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  • No search data in Goolge Analytics or Webmasters

    - by cjk
    I have a domain that has been registered in Google Webmasters and using Google Analytics for over 4 months. I get lots of analytics data, but am getting no information on Google searches in Webmasters, or Queries in Search Engine Optimisation in Analytics, even though I am getting keywords for traffic coming to my site from search engines. I have a test sub-domain with the same setup (except not HTTPS) that is getting some of this information through, even with much less data and visits. What could be wrong to stop me getting this information?

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  • Oracle Technológia Fórum rendezvény, 2010. május 5. szerda

    - by Fekete Zoltán
    Jövo hét szerdán Oracle Technology Fórum napot tartunk, ahol az adatbázis-kezelési és a fejlesztoi szekciókban hallgathatók meg eloadások illetve kaphatók válaszok a kérdésekre. Jelentkezés a rendezvényre. Az adatbázis szekcióban fogok beszélni a Sun Oracle Database Machine / Exadata megoldások technikai gyöngyszemeirol mind a tranzakciós (OLTP) mind az adattárházas (DW) és adatbázis konszolidáció oldaláról. Emellett kiemelem majd az Oracle Data Mining (adatbányászat) és OLAP újdonságait, érdekességeit. Megemlítem majd az Oracle's Data Warehouse Reference Architecture alkalmazási lehetoségeit is.

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  • Google I/O 2012 - Storing Data in Google Apps Script

    Google I/O 2012 - Storing Data in Google Apps Script Drew Csillag This session covers the different ways in which developers can store data when using Google Script. We'll break things down by use case, and then show examples of how to use the different options: spreadsheet, Script/User Properties, JDBC connector, and distribution. For all I/O 2012 sessions, go to developers.google.com From: GoogleDevelopers Views: 24 1 ratings Time: 41:48 More in Science & Technology

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  • How To Use Regular Expressions for Data Validation and Cleanup

    You need to provide data validation at the server level for complex strings like phone numbers, email addresses, etc. You may also need to do data cleanup / standardization before moving it from source to target. Although SQL Server provides a fair number of string functions, the code developed with these built-in functions can become complex and hard to maintain or reuse. The Future of SQL Server Monitoring "Being web-based, SQL Monitor 2.0 enables you to check on your servers from almost any location" Jonathan Allen.Try SQL Monitor now.

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  • Optimized Integration between Oracle Data Integrator and Oracle GoldenGate

    - by Alex Kotopoulis
    The Journalizing Knowledge Module for Oracle GoldenGate's CDC mechanism has just been released as part of the ODI 10.1.3.6_02 patch, and a very useful post from Mark Rittman gives detailed instructions about how to set it up in a sample environment. This integration combines the best of two worlds, the non-invasive, highly performant data replication from Oracle GoldenGate with the innovative and scalable EL-T concept from ODI to perform complex loads into real-time data warehouses. Please also check out the new datasheet about this integration.

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  • DATE lookup table (1990/01/01:2041/12/31)

    - by Frank Developer
    I use a DATE's master table for looking up dates and other values in order to control several events, intervals and calculations within my app. It has rows for every single day begining from 01/01/1990 to 12/31/2041. One example of how I use this lookup table is: A customer pawned an item on: JAN-31-2010 Customer returns on MAY-03-2010 to make an interest pymt to avoid forfeiting the item. If he pays 1 months interest, the employee enters a "1" and the app looks-up the pawn date (JAN-31-2010) in date master table and puts FEB-28-2010 in the applicable interest pymt date. FEB-28 is returned because FEB-31's dont exist! If 2010 were a leap-year, it would've returned FEB-29. If customer pays 2 months, MAR-31-2010 is returned. 3 months, APR-30... If customer pays more than 3 months or another period not covered by the date lookup table, employee manually enters the applicable date. Here's what the date lookup table looks like: { Copyright 1990:2010, Frank Computer, Inc. } { DBDATE=YMD4- (correctly sorted for faster lookup) } CREATE TABLE datemast ( dm_lookup DATE, {lookup col used for obtaining values below} dm_workday CHAR(2), {NULL=Normal Working Date,} {NW=National Holiday(Working Date),} {NN=National Holiday(Non-Working Date),} {NH=National Holiday(Half-Day Working Date),} {CN=Company Proclamated(Non-Working Date),} {CH=Company Proclamated(Half-Day Working Date)} {several other columns omitted} dm_description CHAR(30), {NULL, holiday description or any comments} dm_day_num SMALLINT, {number of elapsed days since begining of year} dm_days_left SMALLINT, (number of remaining days until end of year} dm_plus1_mth DATE, {plus 1 month from lookup date} dm_plus2_mth DATE, {plus 2 months from lookup date} dm_plus3_mth DATE, {plus 3 months from lookup date} dm_fy_begins DATE, {fiscal year begins on for lookup date} dm_fy_ends DATE, {fiscal year ends on for lookup date} dm_qtr_begins DATE, {quarter begins on for lookup date} dm_qtr_ends DATE, {quarter ends on for lookup date} dm_mth_begins DATE, {month begins on for lookup date} dm_mth_ends DATE, {month ends on for lookup date} dm_wk_begins DATE, {week begins on for lookup date} dm_wk_ends DATE, {week ends on for lookup date} {several other columns omitted} ) IN "S:\PAWNSHOP.DBS\DATEMAST"; Is there a better way of doing this or is it a cool method?

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  • Utilisez WCF Data Services 1.5 avec Silverlight, par Benjamin Roux

    Citation: Cet article vous présentera comment utiliser Silverlight et WCF Data Services 1.5. Premièrement, pourquoi utiliser Data Services 1.5 ? Tout simplement parce que l'intégration avec Silverlight est grandement améliorée (INotifyPropertyChanged et ObservableCollection, Two-way binding.). c'est par ici N'hésitez pas à laisser vos commentaires ici même

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  • Two strange efficiency problems in Mathematica

    - by Jess Riedel
    FIRST PROBLEM I have timed how long it takes to compute the following statements (where V[x] is a time-intensive function call): Alice = Table[V[i],{i,1,300},{1000}]; Bob = Table[Table[V[i],{i,1,300}],{1000}]^tr; Chris_pre = Table[V[i],{i,1,300}]; Chris = Table[Chris_pre,{1000}]^tr; Alice, Bob, and Chris are identical matricies computed 3 slightly different ways. I find that Chris is computed 1000 times faster than Alice and Bob. It is not surprising that Alice is computed 1000 times slower because, naively, the function V must be called 1000 more times than when Chris is computed. But it is very surprising that Bob is so slow, since he is computed identically to Chris except that Chris stores the intermediate step Chris_pre. Why does Bob evaluate so slowly? SECOND PROBLEM Suppose I want to compile a function in Mathematica of the form f(x)=x+y where "y" is a constant fixed at compile time (but which I prefer not to directly replace in the code with its numerical because I want to be able to easily change it). If y's actual value is y=7.3, and I define f1=Compile[{x},x+y] f2=Compile[{x},x+7.3] then f1 runs 50% slower than f2. How do I make Mathematica replace "y" with "7.3" when f1 is compiled, so that f1 runs as fast as f2? Many thanks!

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  • Webcast Replay Available: E-Business Suite Data Protection

    - by BillSawyer
    I am pleased to release the replay and presentation for the latest ATG Live Webcast: E-Business Suite Data Protection (Presentation)   Robert Armstrong, Product Strategy Security Architect and Eric Bing, Senior Director discussed the best practices and recommendations for securing your E-Business Suite data.Finding other recorded ATG webcasts The catalog of ATG Live Webcast replays, presentations, and all ATG training materials is available in this blog's Webcasts and Training section.

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  • Fetching Data from Multiple Tables using Joins

    Applying normalization to relational databases tends to promote better accuracy of queries, but it also leads to queries that take a little more work to develop, as the data may be spread amongst several tables. In today's article, we'll learn how to fetch data from multiple tables by using joins.

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  • How to delete duplicate records in MySQL by retaining those fields with data in the duplicate item b

    - by NJTechGuy
    I have few thousands of records with few 100 fields in a MySQL Table. Some records are duplicates and are marked as such. Now while I can simply delete the dupes, I want to retain any other possible valuable non-null data which is not present in the original version of the record. Hope I made sense. For instance : a b c d e f key dupe -------------------- 1 d c f k l 1 x 2 g h j 1 3 i h u u 2 4 u r t 2 x From the above sample table, the desired output is : a b c d e f key dupe -------------------- 2 g c h k j 1 3 i r h u u 2 If you look at it closely, the duplicate is determined by using the key (it is the same for 2 records, so the one that has an 'x' for dupe field is the one to be deleted by retaining some of the fields from the dupe (like c, e values for key 1). Please let me know if you need more info about this puzzling problem. Thanks a tonne! p.s : If it is not possible using MySQL, a PERL/Python script sample would be awesome! Thanks!

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  • Store a formula in a table and use the formula in a javascript/PHP function

    - by Muhaimin Abdul
    I have a MySql database where part of it handles instrument's depth of water. Each instrument has its own formula of calculation how depth the water when the operator collect the reading I stored the formula for each instrument in database/MySql. Example formula: [55-57] this is the simple minus operation, where the number is actually represent the id of a row. How do I represent those number with id of a row and later convert it to javascript readable code. I simply want to do keyup event where everytime user key in something into text field then the other part of HTML would reflect changes based on formula that I fetched from database FYI, I'm using BackboneJS together with RequireJS

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  • How to reinstall Ubuntu keeping my data intact?

    - by Santosh Linkha
    I want to reinstall Ubuntu keeping my data intact. I have 160 GB hardrive (sata or pata I don't know but it's slim and made in China) with a 40 GB ext3 partition, a 4GB swap memory and 3 other partition with a FAT32 file system. I have around 4GB space on my drive where Linux is installed. I'd like to keep the data intact, especially the Downloads folder, desktop, and /var/www; And I no longer have access to any other machines or external storage devices.

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  • Evaluation of CTEs in SQL Server 2005

    - by Jammer
    I have a question about how MS SQL evaluates functions inside CTEs. A couple of searches didn't turn up any results related to this issue, but I apologize if this is common knowledge and I'm just behind the curve. It wouldn't be the first time :-) This query is a simplified (and obviously less dynamic) version of what I'm actually doing, but it does exhibit the problem I'm experiencing. It looks like this: CREATE TABLE #EmployeePool(EmployeeID int, EmployeeRank int); INSERT INTO #EmployeePool(EmployeeID, EmployeeRank) SELECT 42, 1 UNION ALL SELECT 43, 2; DECLARE @NumEmployees int; SELECT @NumEmployees = COUNT(*) FROM #EmployeePool; WITH RandomizedCustomers AS ( SELECT CAST(c.Criteria AS int) AS CustomerID, dbo.fnUtil_Random(@NumEmployees) AS RandomRank FROM dbo.fnUtil_ParseCriteria(@CustomerIDs, 'int') c) SELECT rc.CustomerID, ep.EmployeeID FROM RandomizedCustomers rc JOIN #EmployeePool ep ON ep.EmployeeRank = rc.RandomRank; DROP TABLE #EmployeePool; The following can be assumed about all executions of the above: The result of dbo.fnUtil_Random() is always an int value greater than zero and less than or equal to the argument passed in. Since it's being called above with @NumEmployees which has the value 2, this function always evaluates to 1 or 2. The result of dbo.fnUtil_ParseCriteria(@CustomerIDs, 'int') produces a one-column, one-row table that contains a sql_variant with a base type of 'int' that has the value 219935. Given the above assumptions, it makes sense (to me, anyway) that the result of the expression above should always produce a two-column table containing one record - CustomerID and an EmployeeID. The CustomerID should always be the int value 219935, and the EmployeeID should be either 42 or 43. However, this is not always the case. Sometimes I get the expected single record. Other times I get two records (one for each EmployeeID), and still others I get no records. However, if I replace the RandomizedCustomers CTE with a true temp table, the problem vanishes completely. Every time I think I have an explanation for this behavior, it turns out to not make sense or be impossible, so I literally cannot explain why this would happen. Since the problem does not happen when I replace the CTE with a temp table, I can only assume it has something to do with the functions inside CTEs are evaluated during joins to that CTE. Do any of you have any theories?

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  • ActiveRecord table inheritence using set_table_names

    - by Jinyoung Kim
    Hi, I'm using ActiveRecord in Ruby on Rails. I have a table named documents(Document class) and I want to have another table data_documents(DataDocument) class which is effectively the same except for having different table name. In other words, I want two tables with the same behavior except for table name. class DataDocument < Document #set_table_name "data_documents" self.table_name = "data_documents" end My solution was to use class inheritance as above, yet this resulted in inconsistent SQL statement for create operation where there are both 'documents' table and 'data_documents' table. Can you figure out why and how I can make it work? >> DataDocument.create(:did=>"dd") ActiveRecord::StatementInvalid: Mysql::Error: Unknown column 'data_documents.did' in 'where clause': SELECT `documents`.id FROM `documents` WHERE (`data_documents`.`did` = BINARY 'dd') LIMIT 1 from /Users/lifidea/.gem/ruby/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract_adapter.rb:212:in `log' from /Users/lifidea/.gem/ruby/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/mysql_adapter.rb:320:in `execute' from /Users/lifidea/.gem/ruby/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/mysql_adapter.rb:595:in `select' from /Users/lifidea/.gem/ruby/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract/database_statements.rb:7:in `select_all_without_query_cache' from /Users/lifidea/.gem/ruby/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract/query_cache.rb:62:in `select_all'

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  • How to programmatically bind to a Core Data model?

    - by Dave Gallagher
    Hello. I have a Core Data model, and was wondering if you know how to create a binding to an Entity, programmatically? Normally you use bind:toObject:withKeyPath:options: to create a binding. But I'm having a little difficulty getting this to work with Core Data, and couldn't find anything in Apple's docs regarding doing this programmatically. The Core Data model is simple: An Entity called Book An Attribute of Book called author (NSString) I have an object called BookController. It looks like so: @interface BookController : NSObject { NSString *anAuthor; } @property (nonatomic, retain) NSString *anAuthor; // @synthesize anAuthor; inside @implementation I'd like to bind anAuthor inside BookController, to author inside a Book entity. This is how I'm attempting to wrongly do it (it partially works): // A custom class I made, providing an interface to the Core Data database CoreData *db = [[CoreData alloc] init]; // Creating a Book entity, saving it [db addMocObject:@"Book"]; [db saveMoc]; // Fetching the Book entity we just created NSArray *books = [db fetchObjectsForEntity:@"Book" withPredicate:nil withSortDescriptors:nil]; NSManagedObject *book = [books objectAtIndex:0]; // Creating the binding BookController *bookController = [[BookController alloc] init]; [bookController bind:@"anAuthor" toObject:book withKeyPath:@"author" options:nil]; // Manipulating the binding [bookController setAnAuthor:@"Bill Gates"]; Now, when updating from the perspective of bookController, things don't work quite right: // Testing the binding from the bookController's perspective [bookController setAnAuthor:@"Bill Gates"]; // Prints: "bookController's anAuthor: Bill Gates" NSLog(@"bookController's anAuthor: %@", [bookController anAuthor]); // OK! // ERROR HERE - Prints: "bookController's anAuthor: (null)" NSLog(@"Book's author: %@", [book valueForKey:@"author"]); // DOES NOT WORK! :( When updating from the perspective of the Book entity, things work fine: // ------------------------------ // Testing the binding from the Book's (Entity) perspective (this works perfect) [book setValue:@"Steve Jobs" forKey:@"author"]; // Prints: "bookController's anAuthor: Steve Jobs" NSLog(@"bookController's anAuthor: %@", [bookController anAuthor]); // OK! // Prints: "bookController's anAuthor: Steve Jobs" NSLog(@"Book's author: %@", [book valueForKey:@"author"]); // OK! It appears that the binding is partially working. I can update it on the side of the Model and it propagates up to the Controller via KVO, but if I update it on the side of the Controller, it doesn't trickle down to the Model via KVC. Any idea on what I'm doing wrong? Thanks so much for looking! :)

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  • This Week on the Green Data Center Management Front

    Among the big news this week in green data center management: APC will demonstrate how to provide energy while addressing energy efficiency legislation; Altruent Systems announced it has completed a new energy efficient data center for one of its key clients; and Voonami is unveiling what it claims is the greenest in Utah.

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  • Using a PivotTable to Count Items in Access

    - by Sandra
    I have a list of text entries and I want to count how often each entry appears in the list. e.g. Berlin Paris London London Paris Paris Paris The result would be Berlin 1 Paris 4 London 2 This result easy do to achieve with an pivot table in MS Excel (see: Count Items in Excel). My data not in spreadsheet in Excel but in a MS Access database table. So in order to avoid constant switching between Access and Excel and I would like to handle everything in Access (either Access 2007 or 2010). I know there are pivot tables in Access and I know how to display one, but I was unable to find out how to count the number of occurrences. Thank you!

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  • MYSQL Merging 2 results into 1 table

    - by AlphaRomeo69
    Im building a c# program and am currently stuck at fetching data from MYSQL database and bind them to a grid view. I had been researching for a few days now but to no avail. I have 4 table in the database. table 1 - alpha table 2 - bravo table 3 - charlie table 4 - delta attributes of alpha (id, type, user, role ) attributes of bravo (id, type, date, user) attributes of charlie (id,type, cat, doneby, comment) atttibutes of delta (id,type, cat, doneby) * the pk of alpha and bravo is (id) * the pk of charlie and delta is (id, type) i did a query1 before by inner joinning alpha, bravo and charlie which leads to the sucessful result of (id, type, date, user, role, cat, doneby, comment) and i also did a query2 before by inner joinning alpha, bravo and delta which leads to the sucessful result of (id, type, date, user, role, cat, doneby) Right now, im trying to built a query3 which will merge the result from query1 and query2 together. the result of my attempts leads to (id, type, date, user, role, cat, doneby, comment,id, type, date, user, role, cat, doneby) As i do not want the repeated columns, I would like to seek advice on how to get the result to become like the one below by placing the records as a new tuple in the result table. (id, type, date, user, role, cat, doneby, comment) Thanks! P.S: the PK would not pose a problem due to (id, type)

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  • what data structure should I use for hash lookup as well as binary search?

    - by zebraman
    I am working on a school homework. I have a list of names. I want to be able to perform binary search on these names (find all names between a lower and upper bound) for first name as well as last name, and perform keyword searches as well (this will be accomplished using hashing. For example, if I have the names Garfield Cat Snoopy Dog Captain Crunch Fat Cat then a binary search of first names (C,H) will return Captain Crunch, Fat Cat, and Garfield Cat. A binary search of last names (Cr,D) will return Captain Crunch. A keyword search of 'cat' will return Fat Cat and Garfield Cat. I understand binary search will only work on a sorted list, but since I am planning on searching two different criteria, I will have to sort the list by last name or first name depending on what I'm searching for. I feel like it will be too inefficient to have to resort the list each time I want to perform a new binary search. Would it just be better for me to set up and maintain two sorted lists (one for sorted by first name, one for sorted by last name)? Also, for hashing, will I have to set up a different table of names for that as well? I understand each keyword will hash to some value determined by a hash function, and this value (or key) is a table address where the corresponding names are stored. So I just want to know what would be the best way to solve this problem? Maintaining separate structures, or is there a way to efficiently do everything I want with just one data structure?

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  • Oracle acquires Pillar Data Systems

    - by nospam(at)example.com (Joerg Moellenkamp)
    So far it was an investment of Larry Ellison, but now it's part of Oracle: Oracle has acquired Pillar Data Systems.. You will find more information in the press release.. As i already smell some of the comments:Pillar Data Systems is majority owned by Oracle CEO Larry Ellison. The evaluation and negotiation of the transaction was led by an independent committee of Oracle's Board of Directors. The transaction is structured as a 100% earn-out with no up-front payment.

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  • SQL Server Geography Data Type

    We are working on the migration to SQL Server 2008 and have geospatial data that we would like to move over as well. As part of our application we house information on locations across the globe. Which data type should we use?

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