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  • Save gcc compile status to a text file for Java

    - by JohnBore
    I'm making a C Assessment Program through Java, which has a bunch of programming questions for C, and it lets the user input an answer in the form of C code, and then press a "Compile" button, which is linked to a bat file that runs the user input code through gcc. I've got the input and compiling working, but I need to get the output from the compiler and get that to print textarea within the program. I can get a simple "Hello, world" compiling, but I'm having trouble getting programs that require a user input with scanf, for example, to be printed. else if(e.getSource().equals(compile)){ if(questionNumber<1){ JOptionPane.showMessageDialog(programFrame, "Please start the assessment", "Compile Error", JOptionPane.ERROR_MESSAGE); } else{ FileOutputStream fileWrite; try { fileWrite = new FileOutputStream("demo/demo.c"); new PrintStream(fileWrite).println(input.getText());//saves what the user has entered in to a C source file fileWrite.close(); @SuppressWarnings("unused") Process process = Runtime.getRuntime().exec("cmd /c compile.bat");//runs the batch file to compile the source file compileCode(); try{ fileStream = new FileInputStream("demo/output.txt"); inputStream = new DataInputStream(fileStream); bufferRead = new BufferedReader(new InputStreamReader(inputStream)); while((stringLine = bufferRead.readLine())!=null){ compiled.append(stringLine); compiled.append("\n"); } inputStream.close(); } catch(IOException exc){ System.err.println("Unable to read file"); System.exit(-1); } } catch (IOException exc) { JOptionPane.showMessageDialog(programFrame, "Demo file not found", "File Error", JOptionPane.ERROR_MESSAGE); } } This is the actionPerformed method for the "Compile" button, the compileCode() is the JFrame that displays the output and "compiled" is the textArea for the output. My batch file is: C: cd dev-cpp\bin gcc.exe H:\workspace\QuestionProgram\demo\demo.c -o demo > H:\workspace\QuestionProgram\demo\compilestatus.txt demo > H:\workspace\QuestionProgram\demo\output.txt I'm not sure how I can do it, so the frame is created for the output of the code if the code requires a user input as the command prompt doesn't open without adding "START" to .exec(), but then the frame appears before the program has finished running. Also, how would I get the output of the compiler if the compile fails because of an error? The way I've got it in my batch file at the moment doesn't put anything in a text file if it fails.

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  • Android: How to copy a SQLite database from one application to another

    - by mahdaeng
    I have a lite version of an application that uses a SQLite database. I want to copy that database over to the full version of the application when the user installs the full version. I have written some code to perform the file copy, but the lite database file always comes up as unreadable. The file is there and I can point to it, but I can't read it to perform the copy. In the Android documentation, we read: You can save files directly on the device's internal storage. By default, files saved to the internal storage are private to your application and other applications cannot access them (nor can the user). Note the words, "by default". Is there a way that I can override that default and make the SQLite file readable by my other application? Thank you.

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  • Windows Azure: Creation of a file on cloud blob container

    - by veda
    I am writing a program that will be executing on the cloud. The program will generate an output that should be written on to a file and the file should be saved on the blob container. I don't have a idea of how to do that Will this code FileStream fs = new FileStream(file, FileMode.Create); StreamWriter sw = new StreamWriter(fs); generate a file named "file" on the cloud...

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  • Jumbled byte array after using TcpClient and TcpListener

    - by Dylan
    I want to use the TcpClient and TcpListener to send an mp3 file over a network. I implemented a solution of this using sockets, but there were some issues so I am investigating a new/better way to send a file. I create a byte array which looks like this: length_of_filename|filename|file This should then be transmitted using the above mentioned classes, yet on the server side the byte array I read is completely messed up and I'm not sure why. The method I use to send: public static void Send(String filePath) { try { IPEndPoint endPoint = new IPEndPoint(Settings.IpAddress, Settings.Port + 1); Byte[] fileData = File.ReadAllBytes(filePath); FileInfo fi = new FileInfo(filePath); List<byte> dataToSend = new List<byte>(); dataToSend.AddRange(BitConverter.GetBytes(Encoding.Unicode.GetByteCount(fi.Name))); // length of filename dataToSend.AddRange(Encoding.Unicode.GetBytes(fi.Name)); // filename dataToSend.AddRange(fileData); // file binary data using (TcpClient client = new TcpClient()) { client.Connect(Settings.IpAddress, Settings.Port + 1); // Get a client stream for reading and writing. using (NetworkStream stream = client.GetStream()) { // server is ready stream.Write(dataToSend.ToArray(), 0, dataToSend.ToArray().Length); } } } catch (ArgumentNullException e) { Debug.WriteLine(e); } catch (SocketException e) { Debug.WriteLine(e); } } } Then on the server side it looks as follows: private void Listen() { TcpListener server = null; try { // Setup the TcpListener Int32 port = Settings.Port + 1; IPAddress localAddr = IPAddress.Parse("127.0.0.1"); // TcpListener server = new TcpListener(port); server = new TcpListener(localAddr, port); // Start listening for client requests. server.Start(); // Buffer for reading data Byte[] bytes = new Byte[1024]; List<byte> data; // Enter the listening loop. while (true) { Debug.WriteLine("Waiting for a connection... "); string filePath = string.Empty; // Perform a blocking call to accept requests. // You could also user server.AcceptSocket() here. using (TcpClient client = server.AcceptTcpClient()) { Debug.WriteLine("Connected to client!"); data = new List<byte>(); // Get a stream object for reading and writing using (NetworkStream stream = client.GetStream()) { // Loop to receive all the data sent by the client. while ((stream.Read(bytes, 0, bytes.Length)) != 0) { data.AddRange(bytes); } } } int fileNameLength = BitConverter.ToInt32(data.ToArray(), 0); filePath = Encoding.Unicode.GetString(data.ToArray(), 4, fileNameLength); var binary = data.GetRange(4 + fileNameLength, data.Count - 4 - fileNameLength); Debug.WriteLine("File successfully downloaded!"); // write it to disk using (BinaryWriter writer = new BinaryWriter(File.Open(filePath, FileMode.Append))) { writer.Write(binary.ToArray(), 0, binary.Count); } } } catch (Exception ex) { Debug.WriteLine(ex); } finally { // Stop listening for new clients. server.Stop(); } } Can anyone see something that I am missing/doing wrong?

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  • How to read data from keyboard and store it in a file, shellscript

    - by Sunil Kumar Sahoo
    Hi I have a file try.SPEC. This file contains a word "Version: 1.0.0.1" . Now I want to write a shell script which will read the version number from keyboard and insert in the file. eg- if the user enters the version number as 2.1.1.1 then the file will have Version: 2.1.1.1" instead of "Version: 1.0.0.1". like this i want that i must be able to change irrespective of knowing what is the version number present in the spec file Thanks Sunil Kumar Sahoo

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  • Should a HTTP POST'ed file be base64 encoded?

    - by andybee
    I'm currently implementing a client application that POST's a file over HTTP and have implemented base64 encoding on the file's data parameter. However, it appears that when inspecting the traffic between a simple HTML page with a file upload form and the server that no Content-Transfer-Encoding header is sent in the body when describing the file's parameter. Is this the preferred way of POST'ing a file over HTTP?

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  • Sharing a file from Android to Gmail or to Dropbox

    - by Calaf
    To share a simple text file, I started by copying verbatim from FileProvider's manual page: <application android:allowBackup="true" android:icon="@drawable/ic_launcher" android:label="@string/app_name" android:theme="@style/AppTheme" > <provider android:name="android.support.v4.content.FileProvider" android:authorities="com.mycorp.helloworldtxtfileprovider.MainActivity" android:exported="false" android:grantUriPermissions="true" > <meta-data android:name="android.support.FILE_PROVIDER_PATHS" android:resource="@xml/my_paths" /> </provider> <activity android:name="com.mycorp.helloworldtxtfileprovider.MainActivity" ... Then I saved a text file and used, again nearly verbatim, the code under Sending binary content. (Notice that this applies more accurately in this case than "Sending text content" since we are sending a file, which happens to be a text file, rather than just a string of text.) For the convenience of duplication on your side, and since the code is in any case so brief, I'm including it here in full. public class MainActivity extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); String filename = "hellow.txt"; String fileContents = "Hello, World!\n"; byte[] bytes = fileContents.getBytes(); FileOutputStream fos = null; try { fos = this.openFileOutput(filename, MODE_PRIVATE); fos.write(bytes); } catch (IOException e) { e.printStackTrace(); } finally { try { fos.close(); } catch (IOException e) { e.printStackTrace(); } } File file = new File(filename); Intent shareIntent = new Intent(); shareIntent.setAction(Intent.ACTION_SEND); shareIntent.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(file)); shareIntent.setType("application/txt"); startActivity(Intent.createChooser(shareIntent, getResources().getText(R.string.send_to))); file.delete(); } } Aside from adding a value for send_to in res/values/strings.xml, the only other change I did to the generic Hello, World that Eclipse creates is to add the following in res/xml/my_paths.xml (as described on the page previously referenced. <paths xmlns:android="http://schemas.android.com/apk/res/android"> <Files-path name="files" path="." /> </paths> This code runs fine. It shows a list of intent recipients. But sending the text file to either Dropbox or to Gmail fails. Dropbox sends the notification "Uploading to Dropbox" followed by "Upload failed: my_file.txt". After "sending message.." Gmail sends "Couldn't send attachment". What is wrong?

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  • Infinite loop when using fscanf

    - by user1409641
    I wrote this simple program in C, because I'm studying FILES right now at University. I take a txt file with a list of the results of the last race so my program will show the data formatted as I want. Here's my code: /* Esercizio file Motogp */ #include <stdio.h> #define SIZE 20 int main () { int pos, punt, num; float kmh; char nome[SIZE+1], cognome[SIZE+1], moto[SIZE+1]; char naz[SIZE+1], nome_file[SIZE+1]; FILE *fp; printf ("Inserisci il nome del file da aprire: "); gets (nome_file); fp = fopen (nome_file, "r"); if (fopen == NULL) printf ("Errore nell' apertura del file %s\n", nome_file); else { while (fscanf (fp, "%d %d %d %s %s %s %s %.2f", &pos, &punt, &num, nome, cognome, naz, moto, &kmh) != EOF ) { printf ("Posizione di arrivo: %d\n", pos); printf ("Punteggio: %d\n", punt); printf ("Numero pilota: %d\n", num); printf ("Nome pilota: %s\n", nome); printf ("Cognome pilota: %s\n", cognome); printf ("Nazione: %s\n", naz); printf ("Moto: %s\n", moto); printf ("Media Kmh: %d\n\n", kmh); } } fclose(fp); return 0; } and there's my txt file: 1 25 99 Jorge LORENZO SPA Yamaha 164.4 2 20 26 Dani PEDROSA SPA Honda 164.1 3 16 4 Andrea DOVIZIOSO ITA Yamaha 163.8 4 13 1 Casey STONER AUS Honda 163.8 5 11 35 Cal CRUTCHLOW GBR Yamaha 163.6 6 10 19 Alvaro BAUTISTA SPA Honda 163.5 7 9 46 Valentino ROSSI ITA Ducati 163.3 8 8 6 Stefan BRADL GER Honda 162.9 9 7 69 Nicky HAYDEN USA Ducati 162.5 10 6 11 Ben SPIES USA Yamaha 162.3 11 5 8 Hector BARBERA SPA Ducati 162.1 12 4 17 Karel ABRAHAM CZE Ducati 160.9 13 3 41 Aleix ESPARGARO SPA ART 160.2 14 2 51 Michele PIRRO ITA FTR 160.1 15 1 14 Randy DE PUNIET FRA ART 160.0 16 0 77 James ELLISON GBR ART 159.9 17 0 54 Mattia PASINI ITA ART 159.4 18 0 68 Yonny HERNANDEZ COL BQR 159.4 19 0 9 Danilo PETRUCCI ITA Ioda 158.2 20 0 22 Ivan SILVA SPA BQR 158.2 When I run my program, it return me an infinite loop of the first one. Why? Is there another function to read those data?

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  • how to create thumbnail system for MP4 files

    - by Pete Herbert Penito
    Hi everyone! I know I know, why am I using MP4 still?? It's because I have like 100 files already in this format and I need to upload to a website, I have the mp4 file embeded in the site already and the file played changes according to php. but what I really need is a way to dynamically create a thumbnail or take a snapshot of the video file to display on the page. I've read a couple things online but they all require the file type to be in FLV, what would be the best way to accomplish this? Thank you Guys!

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  • stdio's remove() not always deleting on time.

    - by Kyte
    For a particular piece of homework, I'm implementing a basic data storage system using sequential files under standard C, which cannot load more than 1 record at a time. So, the basic part is creating a new file where the results of whatever we do with the original records are stored. The previous file's renamed, and a new one under the working name is created. The code's compiled with MinGW 5.1.6 on Windows 7. Problem is, this particular version of the code (I've got nearly-identical versions of this floating around my functions) doesn't always remove the old file, so the rename fails and hence the stored data gets wiped by the fopen(). FILE *archivo, *antiguo; remove("IndiceNecesidades.old"); // This randomly fails to work in time. rename("IndiceNecesidades.dat", "IndiceNecesidades.old"); // So rename() fails. antiguo = fopen("IndiceNecesidades.old", "rb"); // But apparently it still gets deleted, since this turns out null (and I never find the .old in my working folder after the program's done). archivo = fopen("IndiceNecesidades.dat", "wb"); // And here the data gets wiped. Basically, anytime the .old previously exists, there's a chance it's not removed in time for the rename() to take effect successfully. No possible name conflicts both internally and externally. The weird thing's that it's only with this particular file. Identical snippets except with the name changed to Necesidades.dat (which happen in 3 different functions) work perfectly fine. // I'm yet to see this snippet fail. FILE *antiguo, *archivo; remove("Necesidades.old"); rename("Necesidades.dat", "Necesidades.old"); antiguo = fopen("Necesidades.old", "rb"); archivo = fopen("Necesidades.dat", "wb"); Any ideas on why would this happen, and/or how can I ensure the remove() command has taken effect by the time rename() is executed? (I thought of just using a while loop to force call remove() again so long as fopen() returns a non-null pointer, but that sounds like begging for a crash due to overflowing the OS with delete requests or something.)

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  • Using perl to parse a file and insert specific values into a database

    - by Sean
    Disclaimer: I'm a newbie at scripting in perl, this is partially a learning exercise (but still a project for work). Also, I have a much stronger grasp on shell scripting, so my examples will likely be formatted in that mindset (but I would like to create them in perl). Sorry in advance for my verbosity, I want to make sure I am at least marginally clear in getting my point across I have a text file (a reference guide) that is a Word document converted to text then swapped from Windows to UNIX format in Notepad++. The file is uniform in that each section of the file had the same fields/formatting/tables. What I have planned to do, in a basic way is grab each section, keyed by unique batch job names and place all of the values into a database (or maybe just an excel file) so all the fields can be searched/edited for each job much easier than in the word file and possibly create a web interface later on. So what I want to do is grab each section by doing something like: sed -n '/job_name_1_regex/,/job_name_2_regex/' file.txt --how would this be formatted within a perl script? (grab the section in total, then break it down further from there) To read the file in the script I have open FORMAT_FILE, 'test_format.txt'; and then use foreach $line (<FORMAT_FILE>) to parse the file line by line. --is there a better way? My next problem is that since I converted from a word doc with tables, which looks like: Table Heading 1 Table Heading 2 Heading 1/Value 1 Heading 2/Value 1 Heading 1/Value 2 Heading 2/Value 2 but the text file it looks like: Table Heading 1 Table Heading 2Heading 1/Value 1Heading 1/Value 2Heading 2/Value 1Heading 2/Value 2 So I want to have "Heading 1" and "Heading 2" as a columns name and then put the respective values there. I just am not sure how to get the values in relation to the heading from the text file. The values of Heading 1 will always be the line number of Heading 1 plus 2 (Heading 1, Heading 2, Values for heading 1). I know this can be done in awk/sed pretty easily, just not sure how to address it inside a perl script. After I have all the right values and such, linking it up to a database may be an issue as well, I haven't started looking at the way perl interacts with DBs yet. Sorry if this is a bit scatterbrained...it's still not fully formed in my head.

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  • Java Oracle Installation /usr/bin/java: cannot execute binary file

    - by Dave
    Hi I've been trying for 1 day to get Oracle Java running on Ubuntu. I have a powermac g5 with Ubuntu 12.04 ppc64. uname -a : Linux LK37 3.2.0-53-powerpc64-smp #81-Ubuntu SMP Thu Aug 22 21:17:14 UTC 2013 ppc64 ppc64 ppc64 GNU/Linux lspci: david@LK37:~$ sudo lspc [sudo] password for david: sudo: lspc: command not found david@LK37:~$ sudo lspci 0000:00:0b.0 PCI bridge: Apple Inc. CPC945 PCIe Bridge 0000:0a:00.0 VGA compatible controller: NVIDIA Corporation NV43 [GeForce 6600 LE] (rev a2) 0001:00:00.0 Host bridge: Apple Inc. U4 HT Bridge 0001:00:01.0 PCI bridge: Broadcom BCM5780 [HT2000] PCI-X bridge (rev a3) 0001:00:02.0 PCI bridge: Broadcom BCM5780 [HT2000] PCI-X bridge (rev a3) 0001:00:03.0 PCI bridge: Broadcom BCM5780 [HT2000] PCI-Express Bridge (rev a3) 0001:00:04.0 PCI bridge: Broadcom BCM5780 [HT2000] PCI-Express Bridge (rev a3) 0001:00:05.0 PCI bridge: Broadcom BCM5780 [HT2000] PCI-Express Bridge (rev a3) 0001:00:06.0 PCI bridge: Broadcom BCM5780 [HT2000] PCI-Express Bridge (rev a3) 0001:00:07.0 PCI bridge: Apple Inc. Shasta PCI Bridge 0001:00:08.0 PCI bridge: Apple Inc. Shasta PCI Bridge 0001:00:09.0 PCI bridge: Apple Inc. Shasta PCI Bridge 0001:01:07.0 Unassigned class [ff00]: Apple Inc. Shasta Mac I/O 0001:01:0b.0 USB controller: NEC Corporation OHCI USB Controller (rev 43) 0001:01:0b.1 USB controller: NEC Corporation OHCI USB Controller (rev 43) 0001:01:0b.2 USB controller: NEC Corporation uPD72010x USB 2.0 Controller (rev 04) 0001:03:0c.0 IDE interface: Broadcom K2 SATA 0001:03:0d.0 Unassigned class [ff00]: Apple Inc. Shasta IDE 0001:03:0e.0 FireWire (IEEE 1394): Apple Inc. Shasta Firewire 0001:05:04.0 Ethernet controller: Broadcom Corporation NetXtreme BCM5780 Gigabit Ethernet (rev 03) 0001:05:04.1 Ethernet controller: Broadcom Corporation NetXtreme BCM5780 Gigabit Ethernet (rev 03) david@LK37:~$ I tried various ways to install Oracle Java but I always end up with: bash: /usr/bin/java: cannot execute binary file At the moment I have Installed jdk-7u25-linux-x64.tar.gz in /usr/lib/jvm/jdk1.7.0/bin/ as said in this post I already tried the web install but I get a 404 error. I hope you can help me. I started using Ubuntu yesterday so please give me the complete terminal code, it will be a lot easier for me. For those who care I want to play Minecraft and with the OpenJDK I got a java.lang error. That's why I want to install Oracle Java.

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  • Use $_FILES on a page called by .ajax

    - by RachelD
    I have two .php pages that I'm working with. Index.php has a file upload form that posts back to index.php. I can access the $_FILES no problem on index.php after submitting the form. My issue is that I want (after the form submit and the page loads) to use .ajax (jQuery) to call another .php file so that file can open and process some of the rows and return the results to ajax. The ajax then displays the results and recursively calls itself to process the next batch of rows. Basically I want to process (put in the DB etc) the csv in chunks and display it for the user in between chunks. Im doing it this way because the files are 400,000+ rows and the user doesnt want to wait the 10+ min for them all to be processed. I dont want to move this file (save it) because I just need to process it and throw it away and if a user closes the page while its processing the file wont be thrown away. I could cron script it but I dont want to. What I would really like to do is pass the (single) $_FILES through .ajax OR Save it in a $_POST or $_SESSION to use on the second page. Is there any hope for my cause? Heres the ajax code if that helps: function processCSV(startIndex, length) { $.ajax({ url: "ajax-targets/process-csv.php", dataType: "json", type: "POST", data: { startIndex: startIndex, length: length }, timeout: 60000, // 1000 = 1 sec success: function(data) { // JQuery to display the rows from the CSV var newStart = startIndex+length; if(newStart <= data['csvNumRows']) { processCSV(newStart, length); } } }); } processCSV(1, 2); }); P.S. I did try this Passing $_FILES or $_POST to a new page with PHP but its not working for me :( SOS.

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  • Persist changes in C

    - by Mohit Deshpande
    I am developing a database-like application that stores a a structure containing: struct Dictionary { char *key; char *value; struct Dictionary *next; }; As you can see, I am using a linked list to store information. But the problem begins when the user exits out of the program. I want the information to be stored somewhere. So I was thinking of storing the linked list in a permanent or temporary file using fopen, then, when the user starts the program, retrieve the linked list. Here is the method that prints the linked list to the console: void PrintList() { int count = 0; struct Dictionary *current; current = head; if (current == NULL) { printf("\nThe list is empty!"); return; } printf(" Key \t Value\n"); printf(" ======== \t ========\n"); while (current != NULL) { count++; printf("%d. %s \t %s\n", count, current->key, current->value); current = current->next; } } So I am thinking of modifying this method to print the information through fprintf instead of printf and then the program would just get the infomation from the file. Could someone help me on how I can read and write to this file? What kind of file should it be, temporary or regular? How should I format the file (like I was thinking of just having the key first, then the value, then a newline character)?

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  • VS2008: File creation fails randomly in unit testing?

    - by Tim
    I'm working on implementing a reasonably simple XML serializer/deserializer (log file parser) application in C# .NET with VS 2008. I have about 50 unit tests right now for various parts of the code (mostly for the various serialization operations), and some of them seem to be failing mostly at random when they deal with file I/O. The way the tests are structured is that in the test setup method, I create a new empty file at a certain predetermined location, and close the stream I get back. Then I run some basic tests on the file (varying by what exactly is under test). In the cleanup method, I delete the file again. A large portion (usually 30 or more, though the number varies run to run) of my unit tests will fail at the initialize method, claiming they can't access the file I'm trying to create. I can't pin down the exact reason, since a test that will work one run fails the next; they all succeed when run individually. What's the problem here? Why can't I access this file across multiple unit tests? Relevant methods for a unit test that will fail some of the time: [TestInitialize()] public void LogFileTestInitialize() { this.testFolder = System.Environment.GetFolderPath( System.Environment.SpecialFolder.LocalApplicationData ); this.testPath = this.testFolder + "\\empty.lfp"; System.IO.File.Create(this.testPath); } [TestMethod()] public void LogFileConstructorTest() { string filePath = this.testPath; LogFile target = new LogFile(filePath); Assert.AreNotEqual(null, target); Assert.AreEqual(this.testPath, target.filePath); Assert.AreEqual("empty.lfp", target.fileName); Assert.AreEqual(this.testFolder + "\\empty.lfp.lfpdat", target.metaPath); } [TestCleanup()] public void LogFileTestCleanup() { System.IO.File.Delete(this.testPath); } And the LogFile() constructor: public LogFile(String filePath) { this.entries = new List<Entry>(); this.filePath = filePath; this.metaPath = filePath + ".lfpdat"; this.fileName = filePath.Substring(filePath.LastIndexOf("\\") + 1); } The precise error message: Initialization method LogFileParserTester.LogFileTest.LogFileTestInitialize threw exception. System.IO.IOException: System.IO.IOException: The process cannot access the file 'C:\Users\<user>\AppData\Local\empty.lfp' because it is being used by another process..

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  • MediaElement.js setSrc() Loading The File But Not Changing pluginType

    - by doubleJ
    I'm working on a page that uses mediaelement.js to play mp3/mp4/wmv (yes, we have a lot of wmv). I have a list of links and those links should change the player. My effort is to make the changes to the player through javascript so that the page doesn't refresh. This code is working, but it refreshes every time. See a live demo of the non-ajax version. <?php $file = null; $file = $_GET["file"]; $format = null; if (preg_match("/mp4/i", $file)) $format = "mp4"; if (preg_match("/webm/i", $file)) $format = "webm"; if (preg_match("/wmv/i", $file)) $format = "wmv"; if (preg_match("/mp3/i", $file)) $format = "mp3"; if (preg_match("/ogg/i", $file)) $format = "ogg"; $mime = null; if ($format == "mp4") $mime = "video/mp4"; if ($format == "webm") $mime = "video/webm"; if ($format == "wmv") $mime = "video/wmv"; if ($format == "mp3") $mime = "audio/mp3"; if ($format == "ogg") $mime = "audio/ogg"; $element = "video"; if ($format == "mp3" || $format == "ogg") $element = "audio"; // you have to escape (\) the escape (\) character (hehehe...) $poster = "media\\120701Video.jpg"; $height = "360"; if ($format == "mp3") $height = "30"; ?> <!doctype html> <html> <head> <meta charset="utf-8"> <title>Embed</title> <link rel="stylesheet" href="include/johndyer-mediaelement-b090320/build/mediaelementplayer.min.css"> <style> audio {width:640px; height:30px;} video {width:640px; height:360px;} </style> <script src="include/johndyer-mediaelement-b090320/build/jquery.js"></script> <script src="include/johndyer-mediaelement-b090320/build/mediaelement-and-player.js"></script> </head> <body> <ul> <li><a href="embed.php">Reset</a></li> <li><a href="?file=media/120701Video-AnyVideoConverter.mp4">Alternative (mp4)</a></li> <li><a href="?file=media/120701Video-Ffmpeg-Defaults.webm">Alternative (webm)</a></li> <li><a href="?file=media/AreYouHurting-Death.wmv">Alternative (wmv)</a><li> <li><a href="?file=media/AreYouHurting-Death.mp3">Alternative (mp3)</a></li> </ul> <?php if ($file) { ?> <video src="<?php echo $file; ?>" controls poster="<?php echo $poster; ?>" width="640" height="360"></video> <div id="type"></div> <script> var video = document.getElementsByTagName("video")[0]; var player = new MediaElementPlayer(video, { success: function(player) { $('#type').html(player.pluginType); } }); <?php } ?> </script> </body> </html> This code requires <video> to be loaded, initially and with a file, so that the player mode (pluginType) is set. It will, then, only play formats that the pre-established mode supports (firefox in native mode won't play mp4). See a live demo of the ajax version. <!doctype html> <html> <head> <meta charset="utf-8"> <title>Embed</title> <link rel="stylesheet" href="http://www.mediaelementjs.com/js/mejs-2.9.2/mediaelementplayer.min.css"> <script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script> <script src="http://www.mediaelementjs.com/js/mejs-2.9.2/mediaelement-and-player.js"></script> </head> <body> <ul> <li><a href="javascript:player.pause(); player.setSrc('media/120701Video-AnyVideoConverter.mp4'); player.load(); player.play();">Alternative (mp4)</a></li> <li><a href="javascript:player.pause(); player.setSrc('media/120701Video-Ffmpeg-Defaults.webm'); player.load(); player.play();">Alternative (webm)</a></li> <li><a href="javascript:player.pause(); player.setSrc('media/AreYouHurting-Death.wmv'); player.load(); player.play();">Alternative (wmv)</a></li> <li><a href="javascript:player.pause(); player.setSrc('media/AreYouHurting-Death.mp3'); player.load(); player.play();">Alternative (mp3)</a></li> </ul> <video controls src="media/WordProductionCenter.mp4"></video> <div id="type"></div> <script> var video = document.getElementsByTagName("video")[0]; var player = new MediaElementPlayer(video, { success: function(player) { $('#type').html(player.pluginType); } }); </script> </body> </html> It seems like I need something like setType(), but I see no such option. I've read a couple pages that referenced refreshing the DOM after the javascript runs, but I haven't been able to successfully do it (I know enough about javascript to hack things around and get stuff working, but not enough to create whole new things). It is worth noting that Silverlight doesn't work with Internet Explorer 8 or Safari (not sure if it's my code, mejs, or the browsers). Also, neither Silverlight nor Flash play mp3 or webm (again, not sure where the problem lies). Is there a way to dynamically load different types of files into mediaelement?

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  • question about fgets

    - by user105033
    Is this safe to do? (does fgets terminate the buffer with null) or should I be setting the 20th byte to null after the call to fgets before i call clean. // strip new lines void clean(char *data) { while (*data) { if (*data == '\n' || *data == '\r') *data = '\0'; data++; } } // for this, assume that the file contains 1 line no longer than 19 bytes // buffer is freed elsewhere char *load_latest_info(char *file) { FILE *f; char *buffer = (char*) malloc(20); if (f = fopen(file, "r")) if (fgets(buffer, 20, f)) { clean(buffer); return buffer; } free(buffer); return NULL; }

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  • python: simple example for a python egg with a one-file source file?

    - by Jason S
    I'm not quite sure how to build a really simple one-file source module. Is there a sample module out there one the web somewhere which can be built as a python .egg? From the setuptools page it looks pretty simple, you just have your setup.py file and then at least one other .py file somewhere, and I can build an .egg file OK, and even install it using easy_install, but I can't seem to import the file from within python. (note: using 2.6.4)

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  • Where to put a textfile I want to use in eclipse?

    - by Jayomat
    hi there, I need to read a text file when I start my program. I'm using eclipse and started a new java project. In my project folder I got the "src" folder and the standard "JRE System Library"... I just don't know where to put the text file. I cannot use a "hard coded" path because the text file needs to be included with my app... I also tried to create a new folder like "Files" and use the pathe "Files/staedteliste.txt".. doesn't work too... I use the following code to read the file, but I get this error: Error:java.io.FileNotFoundException:staedteliste.txt(No such file or directory) import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; import java.util.ArrayList; public class Test { ArrayList<String[]> values; public static void main(String[] args) { // TODO Auto-generated method stub loadList(); } public static void loadList() { BufferedReader reader; String zeile = null; try { reader = new BufferedReader(new FileReader("staedteliste.txt")); zeile = reader.readLine(); ArrayList<String[]> values = new ArrayList<String[]>(); while (zeile != null) { values.add(zeile.split(";")); zeile = reader.readLine(); } System.out.println(values.size()); System.out.println(zeile); } catch (IOException e) { System.err.println("Error :"+e); } } } thx for help!

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  • 23warning: assignment makes pointer from integer without a cast

    - by FILIaS
    Im new in programming c with arrays and files. Im just trying to run the following code but i get warnings like that: 23 44 warning: assignment makes pointer from integer without a cast Any help? It might be silly... but I cant find what's wrong. #include<stdio.h> FILE *fp; FILE *cw; char filename_game[40],filename_words[40]; int main() { while(1) { /* Input filenames. */ printf("\n Enter the name of the file with the cryptwords array: \n"); gets(filename_game); printf("\n Give the name of the file with crypted words:\n"); gets(filename_words); /* Try to open the file with the game */ if (fp=fopen("crypt.txt","r")!=NULL) //line23 { printf("\n Successful opening %s \n",filename_game); fclose(fp); puts("\n Enter x to exit,any other to continue! \n "); if ( (getc(stdin))=='x') break; else continue; } else { fprintf(stderr,"ERROR!%s \n",filename_game); puts("\n Enter x to exit,any other to continue! \n"); if (getc(stdin)=='x') break; else continue; } /* Try to open the file with the names. */ if (cw=fopen("words.txt","r")!=NULL) //line 44 { printf("\n Successful opening %s \n",filename_words); fclose(cw); puts("\n Enter x to exit,any other to continue \n "); if ( (getc(stdin))=='x') break; else continue; } else { fprintf(stderr,"ERROR!%s \n",filename_words); puts("\n Enter x to exit,any other to continue! \n"); if (getc(stdin)=='x') break; else continue; } } return 0; }

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  • Alert show when extension of FileUpLoads are not allowed

    - by Vy Clarks
    I have a asp FileUpload control in my aspx page. And the code behind to check file's extension and then insert them into database: private string Write(HttpPostedFile file, string table) { string fileNameMain = Path.GetFileName(file.FileName); // check for the valid file extension string fileExtension = Path.GetExtension(fileNameMain).ToLower(); if (fileExtension.Equals(".pdf") || fileExtension.Equals(".doc")) { ...insert fileupload into database } else { LabelError.Text = "Extension of files are not allowed."; return null; } } With the code above, it checks the extension and then show the message "Extension of files are not allowed." in a LabelError if the fileupload is not allowed. Now, I'm required to do the "check-extension" in the other way: at the moment the client click and choose FileUpload, an alert show "Extension of files are not allowed.". I need a way to make an alert show at the momment the FileUpload choosed in browser. Help!!!!

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  • Easy to get a test file into JUnit

    - by Benju
    Can somebody suggest an easy way to get a reference to a file as a String/InputStream/File/etc type object in a junit test class? Obviously I could paste the file (xml in this case) in as a giant String or read it in as a file but is there a shortcut specific to Junit like this? public class MyTestClass{ @Resource(path="something.xml") File myTestFile; @Test public void toSomeTest(){ ... } }

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  • PHP upload filename

    - by incrediman
    I'd like to have my PHP script upload a file with a certain filename in a directory of my choosing. However, the catch is that I need it to exist there immediately upon upload so I can moniter it on my server. I don't want to use a PHP extension or something - this should be very easy to transfer to any PHP setup. So basically: Is there a way to guarantee that, from the very beginning of the file upload process, the file has a certain name and location on the server?

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  • accessing files after setup.py install

    - by Matthew
    I'm developing a python application and have a question regarding coding it so that it still works after an user has installed it on his or her machine via setup.py install or similar. In one of my files, I use the following: file = "TestParser/View/MainWindow.ui" cwd = os.getcwd() argv_path = os.path.dirname(sys.argv[0]) file_path = os.path.join(cwd, argv_path, file) in order to get the path to MainWindow.ui, when I only know the path relative to the main script's location. This works regardless of from where I call the main script. The issue is that after an user installs the application on his or her machine, the relative path is different, so this doesn't work. I could use __file__, but according to this, py2exe doesn't have __file__. Is there a standard way of achieving this? Or a better way?

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