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  • Apache2 VirtualHost Configuration with SSL

    - by Peter
    Hello! I'm new here and I have a strange problem which needs to be solved. Previously I searched in the whole forum and I've read all of related questions but I didn't find solution to my question. We have two servers and a firewall computer. On the Server#1 there is an Apache 2.2 web server and it forwards the incoming traffic to the appropriate ports, to our subdomains by its virtual host configuration (Apache, Tomcat, IIS, Server#2 and so on). We recently bought an SSL certificate to protect one of our subdomain. I successfully installed and configured the certificate into the Apache and it works flawlessly within our local network. Our Kerio Winroute Firewall is configured to permit https traffic and it is translated to Server#1. But all of our subdomains are unavailable from outside (http & https too). Web browser shows "Failed to connect" message. Now, I enclose some parts from our httpd.conf and httpd-vhosts.conf file. httpd.conf ServerRoot "C:/Program Files/Apache Software Foundation/Apache2.2" Listen 80 ServerName dev.mydomain.hu:80 DocumentRoot "C:/Program Files/Apache Software Foundation/Apache2.2/htdocs" LoadModule proxy_module modules/mod_proxy.so LoadModule proxy_connect_module modules/mod_proxy_connect.so LoadModule proxy_http_module modules/mod_proxy_http.so LoadModule rewrite_module modules/mod_rewrite.so LoadModule ssl_module modules/mod_ssl.so Include conf/extra/httpd-vhosts.conf <IfModule ssl_module> SSLMutex default SSLRandomSeed startup builtin SSLRandomSeed connect builtin SSLSessionCache none </IfModule> httpd-vhosts.conf NameVirtualHost *:80 NameVirtualHost *:443 Listen 443 <VirtualHost *:80> DocumentRoot "C:/Program Files/Apache Software Foundation/Apache2.2/htdocs" ServerName localhost </VirtualHost> #-------EXCHANGE SERVER-------- <VirtualHost *:80> ServerName intra.mydomain.hu ProxyRequests Off ProxyVia On ProxyPass / http://myserver:8080/ ProxyPassReverse / http://myserver:8080/ <Proxy *:80> Order deny,allow Allow from all </Proxy> <Location /> Order allow,deny Allow from all </Location> ErrorLog "c:/Program Files/Apache Software Foundation/Apache2.2/logs/exchange.log" CustomLog "c:/Program Files/Apache Software Foundation/Apache2.2/logs/exchange_cust.log" common LogLevel info </VirtualHost> #--------FITNESSE SERVER------- <VirtualHost *:80> ServerName test.mydomain.hu ProxyRequests Off <Proxy *:80> Order deny,allow Allow from all </Proxy> ProxyPass / http://myserver:8004/ ProxyPassReverse / http://myserver:8004/ <Location /> AuthType Basic AuthName "FitNesse" AuthUserFile "C:/Program Files/Apache Software Foundation/Apache2.2/auth/password" AuthGroupFile "C:/Program Files/Apache Software Foundation/Apache2.2/auth/pwgroup" require group Users Order allow,deny Allow from all </Location> ErrorLog "c:/Program Files/Apache Software Foundation/Apache2.2/logs/fitnesse.log" CustomLog "c:/Program Files/Apache Software Foundation/Apache2.2/logs/fitnesse_cust.log" common LogLevel info </VirtualHost> #----WIKI SERVER-----(SSL)- <VirtualHost *:80 *:443> ServerName wiki.mydomain.hu ServerAlias wiki.mydomain.hu SSLEngine On SSLCertificateFile "C:/Program Files/Apache Software Foundation/Apache2.2/cert/certificate.cer" SSLCertificateKeyFile "C:/Program Files/Apache Software Foundation/Apache2.2/cert/wiki.itkodex.hu.key" ProxyRequests Off <Proxy *:80> Order deny,allow Allow from all </Proxy> ProxyPass / http://localhost:8000/ ProxyPassReverse / http://localhost:8000/ ErrorLog "c:/Program Files/Apache Software Foundation/Apache2.2/logs/wiki.log" CustomLog "c:/Program Files/Apache Software Foundation/Apache2.2/logs/wikicust.log" common LogLevel info </VirtualHost> Because this wiki is a JSPWIKI web application, runs on Apache Tomcat therefore there is no "DocumentRoot" parameter in the VirtualHost. Could anybody please help me, to solve this issue, or what should I modify in the configuration? Thanks in advance! Peter

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  • MVC 2 Ajax.Beginform passes returned Html to javascript function

    - by Joe
    Hi, I have a small partial Create Person form in a page above a table of results. I want to be able to post the form to the server, which I can do no problem with ajax.Beginform. <% using (Ajax.BeginForm("Create", new AjaxOptions { OnComplete = "ProcessResponse" })) {%> <fieldset> <legend>Fields</legend> <div class="editor-label"> <%=Html.LabelFor(model => model.FirstName)%> </div> <div class="editor-field"> <%=Html.TextBoxFor(model => model.FirstName)%> <%=Html.ValidationMessageFor(model => model.FirstName)%> </div> <div class="editor-label"> <%=Html.LabelFor(model => model.LastName)%> </div> <div class="editor-field"> <%=Html.TextBoxFor(model => model.LastName)%> <%=Html.ValidationMessageFor(model => model.LastName)%> </div> <p> <input type="submit" /> </p> </fieldset> <% } %> Then in my controller I want to be able to post back a partial which is just a table row if the create is successful and append it to the table, which I can do easily with jquery. $('#personTable tr:last').after(data); However, if server validation fails I want to pass back my partial create person form with the validation errors and replace the existing Create Person form. I have tried returning a Json array Controller: return Json(new { Success = true, Html= this.RenderViewToString("PersonSubform",person) }); Javascript: var json_data = response.get_response().get_object(); with a pass/fail flag and the partial rendered as a string using the solition below but that doesnt render the mvc validation controls when the form fails. SO RenderPartialToString So, is there any way I can hand my javascript the out of the box PartialView("PersonForm") as its returned from my ajax.form? Can I pass some addition info as a Json array so I can tell if its pass or fail and maybe add a message? UPDATE I can now pass the HTML of a PartialView to my javascript but I need to pass some additional data pairs like ServerValidation : true/false and ActionMessage : "you have just created a Person Bill". Ideally I would pass a Json array rather than hidden fields in my partial. function ProcessResponse(response) { var html = response.get_data(); $("#campaignSubform").html(html); } Many thanks in advance

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  • Nginx ssl redirection of images

    - by krishna raj
    Hi. I am trying to set up nginx as reverse proxy for a tomcat server using SSL connection. I want the client's browser to load my tomcat application when nginx reverse proxy's IP is called from client's browser. My tomcat application's address is 192.168.25.25 and nginx proxy's address is 192.168.25.50 In my nginx.conf file i have added these lines # location / { proxy_pass https://192.168.25.25:443/myapp/; proxy_redirect https://192.168.25.25/myapp/ https://192.168.25.25/; } # Some of the images in my application is stored at 192.168.25.25/images/ . Now these directories cant be accessed as the proxy_pass is set to 192.168.25.25:443/myapp. Is there way to access images directory also without changing proxy_pass ? Thanks in advance.

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  • What's the difference between arguments with default values and keyword-arguments?

    - by o_O Tync
    In Python, what's the difference between arguments having default values: def f(a,b,c=1,d=2): pass and keyword arguments: def f(a=1,b=2,c=3): pass ? I guess there's no difference, but the tutorial has two sections: 4.7.1. Default Argument Values 4.7.2. Keyword Arguments which sounds like there are some difference in them. If so, why can't I use this syntax in 2.6: def pyobj_path(*objs, as_list=False): pass ?

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  • iPhone SDK - (void)viewDidLoad { } - Show Progress

    - by Hank Brekke
    I have a long - (void)viewDidLoad { } function that uses the internet to load a page, and whenever the application loads the URL, the screen is black. I have a UIActivityIndicator setup to show that the address is loading, but I don't know how to prevent it from seeming as if the application is not responding, and I don't want to show the network activity indicator [[UIApplication sharedApplication] setNetworkActivityIndicatorVisible:YES]; because the screen will still be black, just with a loader in the top corner. My code is below: - (void)viewDidLoad { NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults]; email.text = [defaults objectForKey:@"mom_email"]; pass.text = [defaults objectForKey:@"mom_pass"]; if (email.text != nil && pass.text != nil) { [self login:loginBtn]; } } - (IBAction)login:(id)sender { [email resignFirstResponder]; [pass resignFirstResponder]; [loader startAnimating]; // Does nothing though NSString *em = (NSString *)CFURLCreateStringByAddingPercentEscapes(NULL,(CFStringRef)email.text,NULL,(CFStringRef)@"!*'();:@&=+$,/?%#[]",kCFStringEncodingUTF8); NSString *ps = (NSString *)CFURLCreateStringByAddingPercentEscapes(NULL,(CFStringRef)pass.text,NULL,(CFStringRef)@"!*'();:@&=+$,/?%#[]",kCFStringEncodingUTF8); NSURL *url = [[NSURL alloc] initWithScheme:@"http" host:@"localhost" path:[[NSString alloc] initWithFormat:@"/app/login.php?email=%@&pass=%@", em, ps]]; NSURLRequest *request = [NSURLRequest requestWithURL:url]; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; NSString *loginResult = [[NSString alloc] initWithData:data encoding:NSASCIIStringEncoding]; [loader stopAnimating]; NSRange range = [loginResult rangeOfString:@"1"]; if (range.location != NSNotFound) { [self dismissModalViewControllerAnimated:YES]; // Doesn't do anything if function called from viewDidLoad } }

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  • Make Apache to listen in multiple IPs

    - by Enrique Becerra
    Hi I'm in a big LAN, which is behind a proxy/firewall I'm working with an apache/php/mysql application, which is hosted in a small server besides my workstation. This server is connected to the LAN also and is behind the proxy: The server has a local IP assigned: 10.64.x.x Also, this server has a public IP assigned (or redirected from within the proxy/firewall) which is: 200.41.x.x I can't access public IP from LAN, but I can ping to the public IP from outside the building How should I configure Apache to listen also for public IP and open the 80 port for people accessing from outside the building?. It is set now to Listen 10.64.x.x:80 Thanks a lot in advance,

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  • Need help trouble shooting Https webserver error - SSL Handshake failed

    - by DerNalia
    I followed this guide: http://hints.macworld.com/article.php?story=20041129143420344 Here is my virtual host definition <VirtualHost *:443> SSLEngine on SSLProxyEngine On RequestHeader set Front-End-Https "On" CacheDisable * SSLCipherSuite ALL:!ADH:!EXPORT56:RC4+RSA:+HIGH:+MEDIUM:+LOW:+SSLv2:+EXP:+eNULL DocumentRoot "/Users/me/projects/myproject/public" ServerName ssl.mydomain.com ServerAlias *.ssl.mydomain.com SSLCertificateKeyFile "/private/etc/apache2/certs/webserver.nopass.key" SSLCertificateFile "/private/etc/apache2/certs/newcert.pem" SSLCACertificateFile "/private/etc/apache2/certs/demoCA/cacert.pem" SSLCARevocationPath "/private/etc/apache2/certs/demoCA/crl" ErrorLog "/Users/me/Desktop/ssl.log" ProxyPass / https://localhost:3002/ ProxyPassReverse / https://localhost:3002 ProxyPreserveHost on </VirtualHost> And when I try connecting to the sevre viov the web browser, I get this error: [Thu Feb 02 16:50:40 2012] [error] (502)Unknown error: 502: proxy: pass request body failed to 127.0.0.1:3002 (localhost) [Thu Feb 02 16:50:40 2012] [error] [client 96.11.81.39] proxy: Error during SSL Handshake with remote server returned by /session/new [Thu Feb 02 16:50:40 2012] [error] proxy: pass request body failed to 127.0.0.1:3002 (localhost) from 96.11.81.39 () how do I debug / fix this?

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  • Data transfer to my own computer from a website host by the same computer

    - by gunbuster363
    Hi all, I have a question about using a web site host in my computer, say Computer A, using any web server hosting application e.g : apache. I connect to my website in my very same computer A, and request to download a file of size 1Mb, in otherwords, I am connecting to my own computer and want to download a file in my computer. In addition, my internet access is bound by a proxy server in a way of gateway. The questions are - does the file transfer really exist? Or is it a local file copying between 2 location? Will my data packet go through the proxy, to the internet, and go back to the proxy and return to me? Thanks everyone who are watching this question.

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  • How to Determine the Size of MSADO Command Parameters

    - by Adam
    I am new to MS ADO and trying to understand how to set the size on command parameters as created by the command.CreateParameter (Name, Type, Direction, Size, Value) The documentation says the following: Size Optional. A Long value that specifies the maximum length for the parameter value in characters or bytes. ... If you specify a variable-length data type in the Type argument, you must either pass a Size argument or set the Size property of the Parameter object before appending it to the Parameters collection; otherwise, an error occurs. 1.) What should one pass for fixed-size parameters? Is it a "don't care"? I was a bit confused by the example found here, in which they set size to 3 for an adInteger parameter with Value set to a variant of type VT_I2 pPrmByRoyalty->Type = adInteger; pPrmByRoyalty->Size = 3; pPrmByRoyalty->Direction = adParamInput; pPrmByRoyalty->Value = vtroyal; VT_I2 implies two bytes. A tagVARIANT struct is 16 bytes. How did they land on three? I see that the enum value for adInteger happens to be three, but I suspect that is just a coincidence. So it's a bit confusing what to pass for fixed-size parameters. The team I'm working with has always passed sizeof(int) for adInteger, and it seems to work. Is that correct? Now, for "variable-length" parameters: we are instructed by the documentation to pass "the maximum length .. in characters or bytes". 2.) For adVarChar, is it sufficient to pass the max width as defined in the database? 3.) What about the Wide types (e.g. adVarWChar)? Is it characters or bytes? 4.) How about adVariant, which could contain fixed- or variable-length data? 5.) Do arrays ever come into play here? (we don't pass them as parameters, just curious) Any references or personal insights are welcome.

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  • VirtualBox networking problem, host XP, guest Debian

    - by Silma
    Hi, I'm trying to set up a development environment in a virtual machine on my laptop, with debian os. I have both lan and wlan available on the host machine, yet I can't connect to the internet using either. As I said the host OS is windows XP and the guest OS will be the latest Debian, we downloaded the business card net install so we need internet access from the beginning, besides we need the virtual machine to be visible on the local network (for my fellow developers). We tried host-only networking, NAT, bridging, with proxy (the local network uses a proxy to connect to the internet) and without proxy, nothing seems to work. What else can we do? Thanks a lot.

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  • ssh all machines behind a router

    - by Luc
    Hello, I have several machines on my lan. One is used as a http proxy to target web sites located on the others (that's working fine now thanks to ServerFault). On my router, Port 22 is NATed to this proxy machine. I would like to be able to access the other machines, within internet, with something like: ssh user@first_machine.my_domain.tld ssh user@second_machine.my_domain.tld Could I use the proxy machine to 'filter' the incoming ssh request and to route them to the correct machine ? (in the same way it's possible to do so for web sites using a mix of mod_proxy and namevirtualhost in Apache) Thanks a lot, Luc

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  • Oracle datetime in VB.net

    - by acadia
    I have a Oracle procedure to which I have to pass a datetime value (2/5/2010 11:46 AM) How do I pass this value from VB.net. When I pass the date as shown below it is not returning any records though there are records. With Cmd .Connection = FactsConn .CommandType = CommandType.StoredProcedure .CommandText = "sp_atas_image_qry" .Parameters.Add(New OracleParameter("vinspectiondatetime", OracleClient.OracleType.DateTime)).Value = "2/5/2010 11:46 AM" .Parameters.Add(New OracleParameter("io_cursor", OracleClient.OracleType.Cursor)).Direction = ParameterDirection.Output End With

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  • Track IP Messenger's chatting by wireshark

    - by Kumar P
    We have Linux server ( RHEL 5 ), and some client machines ( Windows XP ) in local area network. We using server as proxy server. I am using squid proxy. My windows machines using internet by proxy. Now my client machines using IP messenger for chatting and sharing files with in local network. How can i trace what they are doing or chatting by ip messenger, from my server by wireshark packet sniffer ? If i can't do it by wireshark , What will you give idea about it...

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  • multiple valgrind errors: Conditional jump or move depends on uninitialised value(s)

    - by Hristo
    I'm running valgrind and I'm getting the following error (this is not the only one): ==21743== Conditional jump or move depends on uninitialised value(s) ==21743== at 0x4A06509: index (mc_replace_strmem.c:164) ==21743== by 0x33B7CBB3CD: gaih_inet (in /lib64/libc-2.5.so) ==21743== by 0x33B7CBD629: getaddrinfo (in /lib64/libc-2.5.so) ==21743== by 0x401A5F: tunnelURL (proxy.c:336) ==21743== by 0x40142A: client_thread (proxy.c:194) ==21743== by 0x33B8806616: start_thread (in /lib64/libpthread-2.5.so) ==21743== by 0x33B7CD3C2C: clone (in /lib64/libc-2.5.so) My tunnelURL() function looks like this: char * tunnelURL(char *url) { char * a = strstr(url, "//"); a += 2; char * path = strstr(a, "/"); char host[256]; strncpy (host, a, strlen(a)-strlen(path)); /* * The following is courtesy of Beej's Guide */ int status; int proxySocketFD; struct addrinfo hints; struct addrinfo *servinfo; // will point to the results memset(&hints, 0, sizeof(hints)); // make sure the struct is empty hints.ai_family = AF_INET; // don't care IPv4 or IPv6 hints.ai_socktype = SOCK_STREAM; // TCP stream sockets hints.ai_flags = AI_PASSIVE; // fill in my IP for me if ((status = getaddrinfo(host, "80", &hints, &servinfo)) != 0) { perror("getaddrinfo() fail"); exit(1); } // create socket if ((proxySocketFD = socket(servinfo->ai_family, servinfo->ai_socktype, servinfo->ai_protocol)) == -1) { perror("proxy socket() fail"); exit(1); } // connect if (connect(proxySocketFD, servinfo->ai_addr, servinfo->ai_addrlen) != 0) { printf("connect() fail"); exit(1); } // construct request char request[strlen(path) + strlen(host) + 26]; sprintf(request, "GET %s HTTP/1.1\r\nHost: %s\r\n\r\n", path, host); printf("%s", request); // send request send(proxySocketFD, request, strlen(request), 0); // receive response int i = 0; int amntRecvd = 0; char *pageContentBuffer = (char*) malloc(4096 * sizeof(char)); while ((amntRecvd = recv(proxySocketFD, pageContentBuffer + i, 4096, 0)) > 0) { i += amntRecvd; realloc(pageContentBuffer, i * 4096 * sizeof(char)); } // close proxy socket close(proxySocketFD); // deallocate memory freeaddrinfo(servinfo); return pageContentBuffer; } Line 336 corresponds to the if statement with the getaddrinfo() function call. I'm not really sure what I haven't initialized. The string I'm passing in "should" be already set... I'm printing it out just fine. I also get another error corresponding to the same line of code: ==21743== Use of uninitialised value of size 8 ==21743== at 0x33B7D05816: __nscd_cache_search (in /lib64/libc-2.5.so) ==21743== by 0x33B7D0438B: nscd_gethst_r (in /lib64/libc-2.5.so) ==21743== by 0x33B7D04B26: __nscd_gethostbyname2_r (in /lib64/libc-2.5.so) ==21743== by 0x33B7CE9F5E: gethostbyname2_r@@GLIBC_2.2.5 (in /lib64/libc-2.5.so) ==21743== by 0x33B7CBC522: gaih_inet (in /lib64/libc-2.5.so) ==21743== by 0x33B7CBD629: getaddrinfo (in /lib64/libc-2.5.so) ==21743== by 0x401A5F: tunnelURL (proxy.c:336) ==21743== by 0x40142A: client_thread (proxy.c:194) ==21743== by 0x33B8806616: start_thread (in /lib64/libpthread-2.5.so) ==21743== by 0x33B7CD3C2C: clone (in /lib64/libc-2.5.so) Any ideas as to what might becausing this? This is written in C btw... Thanks, Hristo

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  • Reading xml document in firefox

    - by Searock
    I am trying to read customers.xml using javascript. My professor has taught us to read xml using `ActiveXObjectand he has given us an assignment to create a sample login page which checks username and password by reading customers.xml. I am trying to use DOMParser so that it works with firefox. But when I click on Login button I get this error. Error: syntax error Source File: file:///C:/Users/Searock/Desktop/home/project/project/login.html Line: 1, Column: 1 Source Code: customers.xml Here's my code. login.js var xmlDoc = 0; function checkUser() { var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; //xmlDoc = new ActiveXObject("Microsoft.XMLDOM"); /* xmlDoc = document.implementation.createDocument("","",null); xmlDoc.async = "false"; xmlDoc.onreadystatechange = redirectUser; xmlDoc.load("customers.xml"); */ var parser = new DOMParser(); xmlDoc = parser.parseFromString("customers.xml", "text/xml"); alert(xmlDoc.documentElement.nodeName); xmlDoc.async = "false"; xmlDoc.onreadystatechange = redirectUser; } function redirectUser() { alert(''); var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; var log = 0; if(xmlDoc.readyState == 4) { xmlObj = xmlDoc.documentElement; var len = xmlObj.childNodes.length; for(i = 0; i < len; i++) { var nodeElement = xmlObj.childNodes[i]; var userXml = nodeElement.childNodes[0].firstChild.nodeValue; var passXml = nodeElement.childNodes[1].firstChild.nodeValue; var idXML = nodeElement.attributes[0].value if(userXml == user && passXml == pass) { log = 1; document.cookie = escape(idXML); document.login.submit(); } } } if(log == 0) { var divErr = document.getElementById('Error'); divErr.innerHTML = "<b>Login Failed</b>"; } } customers.xml <?xml version="1.0" encoding="UTF-8"?> <customers> <customer custid="CU101"> <user>jack</user> <pwd>PW101</pwd> <email>[email protected]</email> </customer> <customer custid="CU102"> <user>jill</user> <pwd>PW102</pwd> <email>[email protected]</email> </customer> <customer custid="CU103"> <user>john</user> <pwd>PW103</pwd> <email>[email protected]</email> </customer> <customer custid="CU104"> <user>jeff</user> <pwd>PW104</pwd> <email>[email protected]</email> </customer> </customers> I get parsererror message on line alert(xmlDoc.documentElement.nodeName); I don't know what's wrong with my code. Can some one point me in a right direction? Edit : Ok, I found a solution. var xmlDoc = 0; var xhttp = 0; function checkUser() { var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; var err = ""; if(user == "" || pass == "") { if(user == "") { alert("Enter user name"); } if(pass == "") { alert("Enter Password"); } return; } if (window.XMLHttpRequest) { xhttp=new XMLHttpRequest(); } else // IE 5/6 { xhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xhttp.onreadystatechange = redirectUser; xhttp.open("GET","customers.xml",true); xhttp.send(); } function redirectUser() { var log = 2; var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; if (xhttp.readyState == 4) { log = 0; xmlDoc = xhttp.responseXML; var xmlUsers = xmlDoc.getElementsByTagName('user'); var xmlPasswords = xmlDoc.getElementsByTagName('pwd'); var userLen = xmlDoc.getElementsByTagName('customer').length; var xmlCustomers = xmlDoc.getElementsByTagName('customer'); for (var i = 0; i < userLen; i++) { var xmlUser = xmlUsers[i].childNodes[0].nodeValue; var xmlPass = xmlPasswords[i].childNodes[0].nodeValue; var xmlId = xmlCustomers.item(i).attributes[0].nodeValue; if(xmlUser == user && xmlPass == pass) { log = 1; document.cookie = xmlId; document.login.submit(); break; } } } if(log == 0) { alert("Login failed"); } } Thanks.

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  • help with making a password checker in java

    - by Cheesegraterr
    Hello, I am trying to make a program in Java that checks for three specific inputs. It has to be 1. At least 7 characters. 2. Contain both upper and lower case alphabetic characters. 3. Contain at least 1 digit. So far I have been able to make it check if there is 7 characters, but I am having trouble with the last two. What should I put in my loop as an if statement to check for digits and make it upper and lower case. Any help would be greatly appreciated. Here is what I have so far. import java.awt.*; import java.io.*; import java.util.StringTokenizer; public class passCheck { private static String getStrSys () { String myInput = null; //Store the String that is read in from the command line BufferedReader mySystem; //Buffer to store the input mySystem = new BufferedReader (new InputStreamReader (System.in)); //creates a connection to system input try { myInput = mySystem.readLine (); //reads in data from the console myInput = myInput.trim (); } catch (IOException e) //check { System.out.println ("IOException: " + e); return ""; } return myInput; //return the integer to the main program } //**************************************** //main instructions go here //**************************************** static public void main (String[] args) { String pass; //the words the user inputs String temp = ""; //holds temp info int stringLength; //length of string boolean goodPass = false; System.out.print ("Please enter a password: "); //ask for words pass = getStrSys (); //get words from system temp = pass.toLowerCase (); stringLength = pass.length (); //find length of eveyrthing while (goodPass == false) { if (stringLength < 7) { System.out.println ("Your password must consist of at least 7 characters"); System.out.print ("Please enter a password: "); //ask for words pass = getStrSys (); stringLength = pass.length (); goodPass = false; } else if (something to check for digits) { } }

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  • PF, load balanced gateways, and Squid

    - by Santa
    Hi, So I have a FreeBSD router running PF and Squid, and it has three network interfaces: two connected to upstream providers (em0 and em1 respectively), and one for LAN (re0) that we serve. There is some load balancing configured with PF. Basically, it routes all traffic to ports 1-1024 through one interface (em0) and everything else through the other (em1). Now, I have a Squid proxy also running on the box that transparently redirects any HTTP request from LAN to port 3128 in 127.0.0.1. Since Squid redirects this request to HTTP outside, it should follow the load balancing rule through em0, no? The problem is, when we tested it out (by browsing from a computer in the LAN to http://whatismyip.com, it reports the external IP of the em1 interface! When we turn Squid off, the external IP of em0 is reported, as expected. How do I make Squid behave with the load balancing rule that we have set up? Here's the related settings in /etc/pf.conf that I have: ext_if1="em1" # DSL ext_if2="em0" # T1 int_if="re0" ext_gw1="x.x.x.1" ext_gw2="y.y.y.1" int_addr="10.0.0.1" int_net="10.0.0.0/16" dsl_ports = "1024:65535" t1_ports = "1:1023" ... squid=3128 rdr on $int_if inet proto tcp from $int_net \ to any port 80 -> 127.0.0.1 port $squid pass in quick on $int_if route-to lo0 inet proto tcp \ from $int_net to 127.0.0.1 port $squid keep state ... # load balancing pass in on $int_if route-to ($ext_if1 $ext_gw1) \ proto tcp from $int_net to any port $dsl_ports keep state pass in on $int_if route-to ($ext_if1 $ext_gw1) \ proto udp from $int_net to any port $dsl_ports pass in on $int_if route-to ($ext_if2 $ext_gw2) \ proto tcp from $int_net to any port $t1_ports keep state pass in on $int_if route-to ($ext_if2 $ext_gw2) \ proto udp from $int_net to any port $t1_ports Thanks!

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  • Stored procedure strange error when called through php

    - by ravi
    I have been coding a registration page(login system) in php and mysql for a website. I'm using two stored procedures for the same. First stored procedure checks wether the email address already exists in database.Second one inserts the user supplied data into mysql database. User has EXECUTE permission on both the procedures.When is execute them individually from php script they work fine. But when i use them together in script second Stored procedure(insert) not working. Stored procedure 1. DELIMITER $$ CREATE PROCEDURE reg_check_email(email VARCHAR(80)) BEGIN SET @email = email; SET @sql = 'SELECT email FROM user_account WHERE user_account.email=?'; PREPARE stmt FROM @sql; EXECUTE stmt USING @email; END$$ DELIMITER; Stored procedure 2 DELIMITER $$ CREATE PROCEDURE reg_insert_into_db(fname VARCHAR(40), lname VARCHAR(40), email VARCHAR(80), pass VARBINARY(32), licenseno VARCHAR(80), mobileno VARCHAR(10)) BEGIN SET @fname = fname, @lname = lname, @email = email, @pass = pass, @licenseno = licenseno, @mobileno = mobileno; SET @sql = 'INSERT INTO user_account(email,pass,last_name,license_no,phone_no) VALUES(?,?,?,?,?)'; PREPARE stmt FROM @sql; EXECUTE stmt USING @email,@pass,@lname,@licenseno,@mobileno; END$$ DELIMITER; When i test these from php sample script insert is not working , but first stored procedure(reg_check_email()) is working. If i comment off first one(reg_check_email), second stored procedure(reg_insert_into_db) is working fine. <?php require("/wamp/mysql.inc.php"); $r = mysqli_query($dbc,"CALL reg_check_email('[email protected]')"); $rows = mysqli_num_rows($r); if($rows == 0) { $r = mysqli_query($dbc,"CALL reg_insert_into_db('a','b','[email protected]','c','d','e')"); } ?> i'm unable to figure out the mistake. Thanks in advance, ravi.

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  • Cisco IOS PBR - PBRing Skype

    - by Azz
    I've got a very simple question, which seems to be extremely difficult when put into practice. I have a Cisco IOS router with two Internet links (one over a WAN, through a proxy, everywhere, etc.) the other direct Internet. Most traffic destined for the internet goes through the proxy over the WAN. I want Skype traffic (why the client uses skype, I don't know..) to go out of the Internet link, while the rest of the traffic goes over the WAN through the proxy, etc. Apparently skype is very difficult to detect/classify because of it's many adaptations to being blocked. Is there any way to identify Skype on an IOS router (2911), and set it's next hop IP/interface? Thank you, Aaron

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  • Password Protected Wordpress MU

    - by HollerTrain
    I have a MU site related to Doctors and they will be publishing information that I cannot let outside sources and robots view. Is there a way that when you go to the main domain url, it shows a user/pass login for WP. I would set up the user/pass in the backend. Then they would login, then be able to view the website? I can't have it load up for anyone, I need the website to be password protected to even view the website in general. I know I can use .htaccess to have a user/pass, but it would be ideal to use the user/pass generated by WP so I don't have to mess with code when I create a user. Any help would be greatly appreciated.

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  • Parameterized include in Classic ASP with VBScript

    - by Thom Smith
    I want to write a function that will include an external file, much like Server.Execute, but will pass along parameters. I'm aware that Server.Execute will pass along query parameters, but I'd like to pass data more generally. For instance: ' main.asp MyInclude("external.inc", Array("mykey", "myval")) ' external.inc Response.Write mykey I doubt I can get quite that far without reading the external fine, twiddling it, and executing, but I'd like to get as close as reasonably possible. Also, if possible, I'd prefer avoiding using the query passing option for security reasons.

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  • WCF REST based services authentication schemes

    - by FlySwat
    I have a simple authentication scheme for a set of semi-public REST API's we are building: /-----------------------\ | Client POST's ID/Pass | | to an Auth Service | \-----------------------/ [Client] ------------POST----------------------> [Service/Authenticate] | /-------------------------------\ | Service checks credentials | [Client] <---------Session Cookie------- | and generates a session token | | | in a cookie. | | \-------------------------------/ | [Client] -----------GET /w Cookie -------------> [Service/Something] | /----------------------------------\ | Client must pass session cookie | | with each API request | | or will get a 401. | \----------------------------------/ This works well, because the client never needs to do anything except receive a cookie, and then pass it along. For browser applications, this happens automatically by the browser, for non browser applications, it is pretty trivial to save the cookie and send it with each request. However, I have not figured out a good approach for doing the initial handshake from browser applications. For example, if this is all happening using a AJAX technique, what prevents the user from being able to access the ID/Pass the client is using to handshake with the service? It seem's like this is the only stumbling block to this approach and I'm stumped.

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  • Serving static files fails - nginx

    - by Sergei
    Hi, I've been looking and trying around all night, but without success. I configured nginx to serve my static files and proxy all the other traffic: server { listen 80; server_name mydomain.com; access_log /home/boudewijn/www/bbt/brouwers/logs/access.log; error_log /home/boudewijn/www/bbt/brouwers/logs/error.log; location / { proxy_pass http://127.0.0.1:8080; include /etc/nginx/proxy.conf; } location /media/ { root /home/boudewijn/www/bbt/brouwers/; } } The proxy passing is no problem, but when I go to mydomain.com/media/ or try to access any testfile over there, it's without success. I paid attention to the difference between root and alias, my media folder exists, I paid attention to the trailing slashes, but still I get a 404 when trying to access my static media files. Any help?

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  • using iptables to change a destination port but keep the ip the same.

    - by Scott Chamberlain
    I am playing around with transparent proxies, The current way I am doing things is the program makes a request to a computer on port 80, I use iptables -t nat -A OUTPUT -p tcp --destination-port 80 -j REDIRECT --to-port 1234 to redirect to my proxy that I am playing with. the proxy will send out a request to port 81 (as all outbound port 80 are being fed back in to the proxy so I want to do something like iptables -t nat -A OUTPUT -p tcp --destination-port 81 -j DNAT --to-destination xxxx:80 The problem lies with the xxxx part. How do I change the destination port without changing changing the destination ip? Or am I doing this setup completely wrong, I am learning after all and constructive criticism is definitely appreciated.

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