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  • Java: If vs. Switch

    - by _ande_turner_
    I have a piece of code with a) which I replaced with b) purely for legibility ... a) if ( WORD[ INDEX ] == 'A' ) branch = BRANCH.A; /* B through to Y */ if ( WORD[ INDEX ] == 'Z' ) branch = BRANCH.Z; b) switch ( WORD[ INDEX ] ) { case 'A' : branch = BRANCH.A; break; /* B through to Y */ case 'Z' : branch = BRANCH.Z; break; } ... will the switch version cascade through all the permutations or jump to a case ? EDIT: Some of the answers below regard alternative approaches to the approach above. I have included the following to provide context for its use. The reason I asked, the Question above, was because the speed of adding words empirically improved. This isn't production code by any means, and was hacked together quickly as a PoC. The following seems to be a confirmation of failure for a thought experiment. I may need a much bigger corpus of words than the one I am currently using though. The failure arises from the fact I did not account for the null references still requiring memory. ( doh ! ) public class Dictionary { private static Dictionary ROOT; private boolean terminus; private Dictionary A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z; private static Dictionary instantiate( final Dictionary DICTIONARY ) { return ( DICTIONARY == null ) ? new Dictionary() : DICTIONARY; } private Dictionary() { this.terminus = false; this.A = this.B = this.C = this.D = this.E = this.F = this.G = this.H = this.I = this.J = this.K = this.L = this.M = this.N = this.O = this.P = this.Q = this.R = this.S = this.T = this.U = this.V = this.W = this.X = this.Y = this.Z = null; } public static void add( final String...STRINGS ) { Dictionary.ROOT = Dictionary.instantiate( Dictionary.ROOT ); for ( final String STRING : STRINGS ) Dictionary.add( STRING.toUpperCase().toCharArray(), Dictionary.ROOT , 0, STRING.length() - 1 ); } private static void add( final char[] WORD, final Dictionary BRANCH, final int INDEX, final int INDEX_LIMIT ) { Dictionary branch = null; switch ( WORD[ INDEX ] ) { case 'A' : branch = BRANCH.A = Dictionary.instantiate( BRANCH.A ); break; case 'B' : branch = BRANCH.B = Dictionary.instantiate( BRANCH.B ); break; case 'C' : branch = BRANCH.C = Dictionary.instantiate( BRANCH.C ); break; case 'D' : branch = BRANCH.D = Dictionary.instantiate( BRANCH.D ); break; case 'E' : branch = BRANCH.E = Dictionary.instantiate( BRANCH.E ); break; case 'F' : branch = BRANCH.F = Dictionary.instantiate( BRANCH.F ); break; case 'G' : branch = BRANCH.G = Dictionary.instantiate( BRANCH.G ); break; case 'H' : branch = BRANCH.H = Dictionary.instantiate( BRANCH.H ); break; case 'I' : branch = BRANCH.I = Dictionary.instantiate( BRANCH.I ); break; case 'J' : branch = BRANCH.J = Dictionary.instantiate( BRANCH.J ); break; case 'K' : branch = BRANCH.K = Dictionary.instantiate( BRANCH.K ); break; case 'L' : branch = BRANCH.L = Dictionary.instantiate( BRANCH.L ); break; case 'M' : branch = BRANCH.M = Dictionary.instantiate( BRANCH.M ); break; case 'N' : branch = BRANCH.N = Dictionary.instantiate( BRANCH.N ); break; case 'O' : branch = BRANCH.O = Dictionary.instantiate( BRANCH.O ); break; case 'P' : branch = BRANCH.P = Dictionary.instantiate( BRANCH.P ); break; case 'Q' : branch = BRANCH.Q = Dictionary.instantiate( BRANCH.Q ); break; case 'R' : branch = BRANCH.R = Dictionary.instantiate( BRANCH.R ); break; case 'S' : branch = BRANCH.S = Dictionary.instantiate( BRANCH.S ); break; case 'T' : branch = BRANCH.T = Dictionary.instantiate( BRANCH.T ); break; case 'U' : branch = BRANCH.U = Dictionary.instantiate( BRANCH.U ); break; case 'V' : branch = BRANCH.V = Dictionary.instantiate( BRANCH.V ); break; case 'W' : branch = BRANCH.W = Dictionary.instantiate( BRANCH.W ); break; case 'X' : branch = BRANCH.X = Dictionary.instantiate( BRANCH.X ); break; case 'Y' : branch = BRANCH.Y = Dictionary.instantiate( BRANCH.Y ); break; case 'Z' : branch = BRANCH.Z = Dictionary.instantiate( BRANCH.Z ); break; } if ( INDEX == INDEX_LIMIT ) branch.terminus = true; else Dictionary.add( WORD, branch, INDEX + 1, INDEX_LIMIT ); } public static boolean is( final String STRING ) { Dictionary.ROOT = Dictionary.instantiate( Dictionary.ROOT ); return Dictionary.is( STRING.toUpperCase().toCharArray(), Dictionary.ROOT, 0, STRING.length() - 1 ); } private static boolean is( final char[] WORD, final Dictionary BRANCH, final int INDEX, final int INDEX_LIMIT ) { Dictionary branch = null; switch ( WORD[ INDEX ] ) { case 'A' : branch = BRANCH.A; break; case 'B' : branch = BRANCH.B; break; case 'C' : branch = BRANCH.C; break; case 'D' : branch = BRANCH.D; break; case 'E' : branch = BRANCH.E; break; case 'F' : branch = BRANCH.F; break; case 'G' : branch = BRANCH.G; break; case 'H' : branch = BRANCH.H; break; case 'I' : branch = BRANCH.I; break; case 'J' : branch = BRANCH.J; break; case 'K' : branch = BRANCH.K; break; case 'L' : branch = BRANCH.L; break; case 'M' : branch = BRANCH.M; break; case 'N' : branch = BRANCH.N; break; case 'O' : branch = BRANCH.O; break; case 'P' : branch = BRANCH.P; break; case 'Q' : branch = BRANCH.Q; break; case 'R' : branch = BRANCH.R; break; case 'S' : branch = BRANCH.S; break; case 'T' : branch = BRANCH.T; break; case 'U' : branch = BRANCH.U; break; case 'V' : branch = BRANCH.V; break; case 'W' : branch = BRANCH.W; break; case 'X' : branch = BRANCH.X; break; case 'Y' : branch = BRANCH.Y; break; case 'Z' : branch = BRANCH.Z; break; } if ( branch == null ) return false; if ( INDEX == INDEX_LIMIT ) return branch.terminus; else return Dictionary.is( WORD, branch, INDEX + 1, INDEX_LIMIT ); } }

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  • PHP - XML Feed get print values

    - by danit
    Here is my feed: <entry> <id>http://api.visitmix.com/OData.svc/Sessions(guid'816995df-b09a-447a-9391-019512f643a0')</id> <title type="text">Building Web Applications with Microsoft SQL Azure</title> <summary type="text">SQL Azure provides a highly available and scalable relational database engine in the cloud. In this demo-intensive and interactive session, learn how to quickly build web applications with SQL Azure Databases and familiar web technologies. We demonstrate how you can quickly provision, build and populate a new SQL Azure database directly from your web browser. Also, see firsthand several new enhancements we are adding to SQL Azure based on the feedback we&#x2019;ve received from the community since launching the service earlier this year.</summary> <published>2010-01-25T00:00:00-05:00</published> <updated>2010-03-05T01:07:05-05:00</updated> <author> <name /> </author> <link rel="edit" title="Session" href="Sessions(guid'816995df-b09a-447a-9391-019512f643a0')" /> <link rel="http://schemas.microsoft.com/ado/2007/08/dataservices/related/Speakers" type="application/atom+xml;type=feed" title="Speakers" href="Sessions(guid'816995df-b09a-447a-9391-019512f643a0')/Speakers"> <m:inline> <feed> <title type="text">Speakers</title> <id>http://api.visitmix.com/OData.svc/Sessions(guid'816995df-b09a-447a-9391-019512f643a0')/Speakers</id> <updated>2010-03-25T11:56:06Z</updated> <link rel="self" title="Speakers" href="Sessions(guid'816995df-b09a-447a-9391-019512f643a0')/Speakers" /> <entry> <id>http://api.visitmix.com/OData.svc/Speakers(guid'3395ee85-d994-423c-a726-76b60a896d2a')</id> <title type="text">David-Robinson</title> <summary type="text"></summary> <updated>2010-03-25T11:56:06Z</updated> <author> <name>David Robinson</name> </author> <link rel="edit-media" title="Speaker" href="Speakers(guid'3395ee85-d994-423c-a726-76b60a896d2a')/$value" /> <link rel="edit" title="Speaker" href="Speakers(guid'3395ee85-d994-423c-a726-76b60a896d2a')" /> <link rel="http://schemas.microsoft.com/ado/2007/08/dataservices/related/Sessions" type="application/atom+xml;type=feed" title="Sessions" href="Speakers(guid'3395ee85-d994-423c-a726-76b60a896d2a')/Sessions" /> <category term="EventModel.Speaker" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" /> <content type="image/jpeg" src="http://live.visitmix.com/Content/images/speakers/lrg/default.jpg" /> <m:properties xmlns:m="http://schemas.microsoft.com/ado/2007/08/dataservices/metadata" xmlns:d="http://schemas.microsoft.com/ado/2007/08/dataservices"> <d:SpeakerID m:type="Edm.Guid">3395ee85-d994-423c-a726-76b60a896d2a</d:SpeakerID> <d:SpeakerFirstName>David</d:SpeakerFirstName> <d:SpeakerLastName>Robinson</d:SpeakerLastName> <d:LargeImage m:null="true"></d:LargeImage> <d:SmallImage m:null="true"></d:SmallImage> <d:Twitter m:null="true"></d:Twitter> </m:properties> </entry> </feed> </m:inline> </link> <link rel="http://schemas.microsoft.com/ado/2007/08/dataservices/related/Tags" type="application/atom+xml;type=feed" title="Tags" href="Sessions(guid'816995df-b09a-447a-9391-019512f643a0')/Tags" /> <link rel="http://schemas.microsoft.com/ado/2007/08/dataservices/related/Files" type="application/atom+xml;type=feed" title="Files" href="Sessions(guid'816995df-b09a-447a-9391-019512f643a0')/Files" /> <category term="EventModel.Session" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" /> <content type="application/xml"> <m:properties> <d:SessionID m:type="Edm.Guid">816995df-b09a-447a-9391-019512f643a0</d:SessionID> <d:Location>Breakers L</d:Location> <d:Type>Seminar</d:Type> <d:Code>SVC07</d:Code> <d:StartTime m:type="Edm.DateTime">2010-03-17T12:00:00</d:StartTime> <d:EndTime m:type="Edm.DateTime">2010-03-17T13:00:00</d:EndTime> <d:Slug>SVC07</d:Slug> <d:CreatedDate m:type="Edm.DateTime">2010-01-26T18:14:24.687</d:CreatedDate> <d:SourceID m:type="Edm.Guid">cddca9b7-6830-4d06-af93-5fd87afb67b0</d:SourceID> </m:properties> </content> </entry> I want to print the: Session Title (Building Web Applications with Microsoft SQL Azure) The Author (David Robinson) The Location (Breakers L) And display the speakers image (http://live.visitmix.com/Content/images/speakers/lrg/default.jpg) I presume I can use filegetcontents and then transform to simplexmlstring, but I dont know how to get the deeper items in I want, like Author, and image. Any chance of a bit of coding genius here?

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  • Link List Problem,

    - by david
    OK i have a problem with a Link List program i'm trying to Do, the link List is working fine. Here is my code #include <iostream> using namespace std; struct record { string word; struct record * link; }; typedef struct record node; node * insert_Node( node * head, node * previous, string key ); node * search( node *head, string key, int *found); void displayList(node *head); node * delete_node( node *head, node * previous, string key); int main() { node * previous, * head = NULL; int found = 0; string node1Data,newNodeData, nextData,lastData; //set up first node cout <<"Depature"<<endl; cin >>node1Data; previous = search( head, node1Data, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, node1Data); cout <<"Depature inserted"<<endl; //insert node between first node and head cout <<"Destination"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Destinationinserted"<<endl; //insert node between second node and head cout <<"Cost"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Cost inserted"<<endl; cout <<"Number of Seats Required"<<endl; //place node between new node and first node cin >>nextData; previous = search( head, nextData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, nextData); cout <<"Number of Seats Required inserted"<<endl; //insert node between first node and head cout <<"Name"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Name inserted"<<endl; //insert node between node and head cout <<"Address "<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Address inserted"<<endl; //place node as very last node cin >>lastData; previous = search( head, lastData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, lastData); cout <<"C"<<endl; displayList(head); char Ans = 'y'; //Delete nodes do { cout <<"Enter Keyword to be delete"<<endl; cin >>nextData; previous = search( head, nextData, &found); if (found == 1) head = delete_node( head, previous,nextData); displayList(head); cout <<"Do you want to Delete more y /n "<<endl; cin >> Ans; } while( Ans =='y'); int choice, i=0, counter=0; int fclass[10]; int coach[10]; printf("Welcome to the booking program"); printf("\n-----------------"); do{ printf("\n Please pick one of the following option:"); printf("\n 1) Reserve a first class seat on Flight 101."); printf("\n 2) Reserve a coach seat on Flight 101."); printf("\n 3) Quit "); printf("\n ---------------------------------------------------------------------"); printf("\nYour choice?"); scanf("%d",&choice); switch(choice) { case 1: i++; if (i <10){ printf("Here is your seat: %d " , fclass[i]); } else if (i = 10) { printf("Sorry there is no more seats on First Class. Please wait for the next flight"); } break; case 2: if (i <10){ printf("Here is your Seat Coach: %d " , coach[i]); } else if ( i = 10) { printf("Sorry their is no more Seats on Coach. Please wait for the next flight"); } break; case 3: printf("Thank you and goodbye\n"); //exit(0); } } while (choice != 3); } /******************************************************* search function to return previous position of node ******************************************************/ node * search( node *head, string key, int *found) { node * previous, * current; current = head; previous = current; *found = 0;//not found //if (current->word < key) move through links until the next link //matches or current_word > key while( current !=NULL) { //compare exactly if (key ==current->word ) { *found = 1; break; } //if key is less than word else if ( key < current->word ) break; else { //previous stays one link behind current previous = current; current = previous -> link; } } return previous; } /******************************************************** display function as used with createList ******************************************************/ void displayList(node *head) { node * current; //current now contains the address held of the 1st node similar //to head current = head; cout << "\n\n"; if( current ==NULL) cout << "Empty List\n\n"; else { /*Keep going displaying the contents of the list and set current to the address of the next node. When set to null, there are no more nodes */ while(current !=NULL) { cout << current->word<<endl; current = current ->link; } } } /************************************************************ insert node used to position node (i) empty list head = NULL (ii) to position node before the first node key < head->word (iii) every other position including the end of the list This is done using the following steps (a) Pass in all the details to create the node either details or a whole record (b) Pass the details over to fill the node (C) Use the if statement to add the node to the list **********************************************************/ node * insert_Node( node * head, node * previous, string key ) { node * new_node, * temp; new_node = new node; //create the node new_node ->word = key; new_node -> link = NULL; if (head == NULL || key < head->word ) //empty list { //give address of head to temp temp = head; //head now points to the new_node head = new_node; //new_node now points to what head was pointing at new_node -> link = temp; } else { //pass address held in link to temp temp = previous-> link; //put address of new node to link of previous previous -> link = new_node; //pass address of temp to link of new node new_node -> link = temp; } return head; } node * delete_node( node *head, node * previous, string key) { /* this function will delete a node but will not return its contents */ node * temp; if(key == head->word) //delete node at head of list { temp = head; //point head at the next node head = head -> link; } else { //holds the address of the node after the one // to be deleted temp = previous-> link; /*assign the previous to the address of the present node to be deleted which holds the address of the next node */ previous-> link = previous-> link-> link; } delete temp; return head; }//end delete The problem i have is when i Enter in the Number 2 in the Node(Seats) i like to get a Counter Taken 2 off of 50, some thing like what i have here enter code here int choice, i=0, counter=0; int fclass[10]; int coach[10]; printf("Welcome to the booking program"); printf("\n-----------------"); do{ printf("\n Please pick one of the following option:"); printf("\n 1) Reserve a first class seat on Flight 101."); printf("\n 2) Reserve a coach seat on Flight 101."); printf("\n 3) Quit "); printf("\n ---------------------------------------------------------------------"); printf("\nYour choice?"); scanf("%d",&choice); switch(choice) { case 1: i++; if (i <10){ printf("Here is your seat: %d " , fclass[i]); } else if (i = 10) { printf("Sorry there is no more seats on First Class. Please wait for the next flight"); } break; case 2: if (i <10){ printf("Here is your Seat Coach: %d " , coach[i]); } else if ( i = 10) { printf("Sorry their is no more Seats on Coach. Please wait for the next flight"); } break; case 3: printf("Thank you and goodbye\n"); //exit(0); } } while (choice != 3); How can i get what the User enters into number of Seats into this function

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  • Newbie Python programmer tangling with Lists.

    - by Sergio Tapia
    Here's what I've got so far: # A. match_ends # Given a list of strings, return the count of the number of # strings where the string length is 2 or more and the first # and last chars of the string are the same. # Note: python does not have a ++ operator, but += works. def match_ends(words): counter = 0 for word in words: if len(word) >= 2 and word[0] == word[-1]: counter += counter return counter # +++your code here+++ return I'm following the Google Python Class, so this isn't homework, but me just learning and improving myself; so please no negative comments about 'not doing my homework'. :P What do you guys think I'm doing wrong here? Here's the result: match_ends X got: 0 expected: 3 X got: 0 expected: 2 X got: 0 expected: 1 I'm really loving Python, so I just know that I'll get better at it. :)

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  • Delay On Assembler?

    - by Norm
    Hey, I want to know how i can do delay (Timer) on assembler 16 bit on PC. Thank You for helping, Norm. OS: Windows CODE: delay: inc bx cmp bx,WORD ptr[time] je delay2 jmp delay delay2: inc dx cmp dx,WORD ptr[time2] je delay3 jmp delay mov bx,0 delay3: inc cx cmp cx,WORD ptr[time3] je Finish_delay jmp delay its not work good i need less complicated code

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  • Date Picker Blue

    - by Matt Winters
    I'm successfully setting a date-picker with an initial date from a plist, but I see some unwanted blue values in the month, day, and year components, presumably corresponding to current date. So if today is April 18, 2010 and initial date being set is March 19, 2008, it looks like this (bold represents the blue): January 17 2006 February 18 2007 ------------------------------ March 19 2008 ------------------------------ April 20 2009 May 21 2010 First question is: How do I get rid of the blue? And second question: Ideally, how do I get it to look like this? January 17 2006 February 18 2007 ------------------------------ March 19 2008 ------------------------------ April 20 2009 May 21 2010 Third question, totally unrelated and not as important: How could I have gotten the above to show in blue rather than bold? I see blue in code snippets all the time. Matt

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  • What Algorithm will Find New Longtail Keywords for *keyword* in PPC

    - by Becci
    I am looking for the algorithm (or combo) that would allow someone to find new longtail PPC search phrases based on say one corekeyword. Eg #1 word word corekeyword eg #2 word corekeyword word Google search tool allows a limited number vertically - mostly of eg#1 (https://adwords.google.com.au/select/KeywordToolExternal) I also know of other PPC apps that allow more volume than google adwords keyword tool, But I want to find other combos that mention the corekeyword & then naturally sort for the highest volume searched. Working example of exact match: corekeyword: copywriter (40,500 searches a month) google will serve up: become a copywriter (480 searches globally/month in english) But if I specifically look up: How to become a copywriter (720 searches a month) This exact longtail keyword phrase has 300 more searches than the 3 word version spat out by google. I want the algorithm to find any other highly search exact longtials like: how to become a copywriter Simply because it was save significant $ finding other longtail keywords after your campaign has been running an made google lots of money. I don't want a concantenation algorithm (I already have one of those), because hypothetically, I don't know what keywords will be that I want to find. Any gurus out there? Becci

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  • AS3 Regular Expression Question...

    - by Coltech
    Can someone give me a regular expression that will verify if all the letters in the word "cat" were also in the word "coating" in the proper sequence? So for the word "coating", the RegEx will test true for "cat" but false for "act".

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  • Delphi Phrase Count

    - by Brad
    Does anyone know how to or have some code on counting the number of unique phrases in a document? (Single word, two word phrases, three word phrases). Thanks

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  • Xcode & passing command line arguments

    - by Brisco
    I just started working with C & Xcode and I've run into a little difficulty. All I want to do is read a file from the command line and see the output in the terminal. I think my problem lies with the path to the file that I want to read in. I'm using a Mac and the file is on my desktop, so the path should be Users/myName/Desktop/words.txt. Is this correct? This is my code: #import <Foundation/Foundation.h> int main (int argc, const char* argv[]){ if(argc == 1){ NSLog(@" you must pass at least one arguement"); return 1; } NSLog(@"russ"); FILE* wordFile = fopen(argv[1] , "r"); char word[100]; while (fgets(word,100,wordFile)) { NSLog(@" %s is %d chars long", word,strlen(word)); } fclose(wordFile); return 0; }//main

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  • Order Result in Sqlite

    - by saturngod
    In MySQL , my sql is like following SELECT * , IF( `Word` = 'sim', 1, IF( `Word` LIKE 'sim%', 2, IF( `Word` LIKE '%sim', 4, 3 ) ) ) AS `sort` FROM `dblist` WHERE `Word` LIKE '%sim%' ORDER BY `sort` , `Word` This sql is not working in SQlite. I want to do result order. SELECT * FROM dblist where word like 'sim' or word like 'sim%' or word like '%sim%' or word like '%sim' equal sim is a frist , sim% is second and %sim% is a thrid and then %sim is a last. Currently I can't sort like mysql in sqlite. How to change sql to order the result ?

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  • Counting the number of words in a text area

    - by user1320483
    Hello everyone my first question on stack overflow import javax.swing.*; import java.util.*; import java.awt.event.*; public class TI extends JFrame implements ActionListener { static int count=0; String ct; JTextField word; JTextArea tohide; public static void main(String arg[]) { TI ti=new TI(); } public TI() { JPanel j=new JPanel(); JLabel def=new JLabel("Enter the text to be encrypted"); word=new JTextField("",20); tohide=new JTextArea("",5,20); JButton jb=new JButton("COUNT"); tohide.setBorder(BorderFactory.createLoweredBevelBorder()); j.add(def); j.add(tohide); j.add(word); j.add(jb); add(j); setSize(500,500); setVisible(true); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); setLocationRelativeTo(null); jb.addActionListener(this); } public void actionPerformed(ActionEvent ae) { String txt=tohide.getText(); StringTokenizer stk=new StringTokenizer(txt," "); while(stk.hasMoreTokens()) { String token=stk.nextToken(); count++; } ct=Integer.toString(count);; word.setText(ct); } } I want to count the number of words that are being typed in the textarea.There is a logical error.As I keep clicking the count button the word count increases.

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  • Visio 2010 Reverse Engineer Oracle

    - by digitall
    I have used Visio 2007 in the past to reverse engineer Oracle databases to get a flow scheme. I believe all Office 2007 products were x86 as well which is where I suspect my issue currently lies. I have since upgraded to Visio 2010 x64 and when I go to reverse engineer something from Oracle it shows up under Installed Visio Drivers but I can't seem to create a data source using it. My assumption here is it is because Oracle doesn't play nicely with x64 and with Visio being compiled as x64 I don't even get the option to use it. Has anyone done this with Visio 2010 x64 and Oracle yet? Or are there other tools you would recommend to reverse engineer and get a model such as the one generated by Visio?

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  • $_GET encoding problem with cyrillic text

    - by T1000
    I'm trying this code (on my local web server) <?php echo 'the word is / ?????? ? '.$_GET['word']; ?> but I get corrupted result when enter ?word=????? the word is / ?????? ? ???? The document is saved as 'UTF-8 without BOM' and headers are also UTF-8. I have tried urlencode() and urldecode() but the effect was same. When upload it on web server, works fine...

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  • How can I create a Multiple Value Combo box on an Unbound Form

    - by Jaffal
    Hi I need your help on MS Access 2007. I have a big problem with my MS Access Unbound Form. How can I create a combo box i do not want bound to a table, show a multiple value List? The Combo is named Sector and want these values to be selected in Multiples 9Which should be possible in Access 2007) from the Drop Down List: Fertilizer, Seeds, Pesticides, Veterinary products, Animal Feed, General. Which Select Statement or VBA code can I use. I need a solution to handle this please. Urgent Help needed please!!! Looking forward for your response. Thank you

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  • Highlighting in Solr 1.4 - requireFieldMatch

    - by Mark Redding
    I have an object Title : foo Summary : foo bar Body : this is a published story about a foo and a bar All three are set up as fields with stored=true. The user searches across my system for the word "foo" I would like to highlight foo in all three places. The user searches for the word foo in the title "title:foo" I only want to highlight foo within the title. When I added hl.requireFieldMatch=true and hl.usePhraseHighlighter=true as part of my query over to SOLR I am unable to get the highlighting in all three places when doing a generic non fielded search. Is there a way to get both scenarios to work? I had these two items turned off, but I am adding in some fielded portions of the query that the user does not see which only display Published items for instance. the problem is (foo AND status:published) is causing the word published in the body to highlight when the user only searched for the word "foo".

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  • Using repaint() method.

    - by owca
    I'm still struggling to create this game : http://stackoverflow.com/questions/2844190/choosing-design-method-for-ladder-like-word-game .I've got it almost working but there is a problem though. When I'm inserting a word and it's correct, the whole window should reload, and JButtons containing letters should be repainted with different style. But somehow repaint() method for the game panel (in Main method) doesn't affect it at all. What am I doing wrong ? Here's my code: Main: import java.util.Scanner; import javax.swing.*; import java.awt.*; public class Main { public static void main(String[] args){ final JFrame f = new JFrame("Ladder Game"); Scanner sc = new Scanner(System.in); System.out.println("Creating game data..."); System.out.println("Height: "); //setting height of the grid while (!sc.hasNextInt()) { System.out.println("int, please!"); sc.next(); } final int height = sc.nextInt(); /* * I'm creating Grid[]game. Each row of game contains Grid of Element[]line. * Each row of line contains Elements, which are single letters in the game. */ Grid[]game = new Grid[height]; for(int L = 0; L < height; L++){ Grid row = null; int i = L+1; String s; do { System.out.println("Length "+i+", please!"); s = sc.next(); } while (s.length() != i); Element[] line = new Element[s.length()]; Element single = null; String[] temp = null; String[] temp2 = new String[s.length()]; temp = s.split(""); for( int j = temp2.length; j>0; j--){ temp2[j-1] = temp[j]; } for (int k = 0 ; k < temp2.length ; k++) { if( k == 0 ){ single = new Element(temp2[k], 2); } else{ single = new Element(temp2[k], 1); } line[k] = single; } row = new Grid(line); game[L] = row; } //############################################ //THE GAME STARTS HERE //############################################ //create new game panel with box layout JPanel panel = new JPanel(); panel.setLayout(new BoxLayout(panel, BoxLayout.Y_AXIS)); panel.setBackground(Color.ORANGE); panel.setBorder(BorderFactory.createEmptyBorder(10, 10, 10, 10)); //for each row of the game array add panel containing letters Single panel //is drawn with Grid's paint() method and then returned here to be added for(int i = 0; i < game.length; i++){ panel.add(game[i].paint()); } f.setContentPane(panel); f.pack(); f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); f.setVisible(true); boolean end = false; boolean word = false; String text; /* * Game continues until solved() returns true. First check if given word matches the length, * and then the value of any row. If yes - change state of each letter from EMPTY * to OTHER_LETTER. Then repaint the window. */ while( !end ){ while( !word ){ text = JOptionPane.showInputDialog("Input word: "); for(int i = 1; i< game.length; i++){ if(game[i].equalLength(text)){ if(game[i].equalValue(text)){ game[i].changeState(3); f.repaint(); //simple debug - I'm checking if letter, and //state values for each Element are proper for(int k=0; k<=i; k++){ System.out.print(game[k].e[k].letter()); } System.out.println(); for(int k=0; k<=i; k++){ System.out.print(game[k].e[k].getState()); } System.out.println(); //set word to true and ask for another word word = true; } } } } word = false; //check if the game has ended for(int i = 0; i < game.length; i++){ if(game[i].solved()){ end = true; } else { end = false; } } } } } Element: import javax.swing.*; import java.awt.*; public class Element { final int INVISIBLE = 0; final int EMPTY = 1; final int FIRST_LETTER = 2; final int OTHER_LETTER = 3; private int state; private String letter; public Element(){ } //empty block public Element(int state){ this("", 0); } //filled block public Element(String s, int state){ this.state = state; this.letter = s; } public JButton paint(){ JButton button = null; if( state == EMPTY ){ button = new JButton(" "); button.setBackground(Color.WHITE); } else if ( state == FIRST_LETTER ){ button = new JButton(letter); button.setBackground(Color.red); } else { button = new JButton(letter); button.setBackground(Color.yellow); } return button; } public void changeState(int s){ state = s; } public void setLetter(String s){ letter = s; } public String letter(){ return letter; } public int getState(){ return state; } } Grid: import javax.swing.*; import java.awt.*; public class Grid extends JPanel{ public Element[]e; private Grid[]g; public Grid(){} public Grid( Element[]elements ){ e = new Element[elements.length]; for(int i=0; i< e.length; i++){ e[i] = elements[i]; } } public Grid(Grid[]grid){ g = new Grid[grid.length]; for(int i=0; i<g.length; i++){ g[i] = grid[i]; } Dimension d = new Dimension(600, 600); setMinimumSize(d); setPreferredSize(new Dimension(d)); setMaximumSize(d); } //for Each element in line - change state to i public void changeState(int i){ for(int j=0; j< e.length; j++){ e[j].changeState(3); } } //create panel which will be single row of the game. Add elements to the panel. // return JPanel to be added to grid. public JPanel paint(){ JPanel panel = new JPanel(); panel.setLayout(new GridLayout(1, e.length)); panel.setBorder(BorderFactory.createEmptyBorder(2, 2, 2, 2)); for(int j = 0; j < e.length; j++){ panel.add(e[j].paint()); } return panel; } //check if the length of given string is equal to length of row public boolean equalLength(String s){ int len = s.length(); boolean equal = false; for(int j = 0; j < e.length; j++){ if(e.length == len){ equal = true; } } return equal; } //check if the value of given string is equal to values of elements in row public boolean equalValue(String s){ int len = s.length(); boolean equal = false; String[] temp = null; String[] temp2 = new String[len]; temp = s.split(""); for( int j = len; j>0; j--){ temp2[j-1] = temp[j]; } for(int j = 0; j < e.length; j++){ if( e[j].letter().equals(temp2[j]) ){ equal = true; } else { equal = false; } } if(equal){ for(int i = 0; i < e.length; i++){ e[i].changeState(3); } } return equal; } //check if the game has finished public boolean solved(){ boolean solved = false; for(int j = 0; j < e.length; j++){ if(e[j].getState() == 3){ solved = true; } else { solved = false; } } return solved; } }

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  • Creating a fixed formatted cell in UITableview

    - by Wes
    Hi, I want to have a tableview create rows that look like this: value1 item1 container1 value10 item10 container10 value100 item100 container100 value2 item2 container2 What I am trying to show is that the first word (value) will have a set length of 12 and then the second word (item) will have a set length of 10 and then the last word (container) is just tagged on at the end. I am pulling these from a SQLite database and don't want to use multiple lines, but read in a strictly formatted structure like this.

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  • GNU ld removes section

    - by Jonatan
    I'm writing a boot script for an ARM-Cortex M3 based device. If I compile the assembler boot script and the C application code and then combine the object files and transfer them to my device everything works. However, if I use ar to create an archive (libboot.a) and combine that archive with the C application there is a problem: I've put the boot code in a section: .section .boot, "ax" .global _start _start: .word 0x10000800 /* Initial stack pointer (FIXME!) */ .word start .word nmi_handler .word hard_fault_handler ... etc ... I've found that ld strips this from the final binary (the section "boot" is not available). This is quite natural as there is no dependency on it that ld knows about, but it causes the device to not boot correctly. So my question is: what is the best way to force this code to be included?

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  • Select dynamic string has a different value when referenced in Where clause

    - by David
    I dynamically select a string built using another string. So, if string1='David Banner', then MyDynamicString should be 'DBanne' Select ... , Left( left((select top 1 strval from dbo.SPLIT(string1,' ')) //first word ,1) //first character + (select top 1 strval from dbo.SPLIT(string1,' ') //second word where strval not in (select top 1 strval from dbo.SPLIT(string1,' '))) ,6) //1st character of 1st word, followed by up to 5 characters of second word [MyDynamicString] ,... From table1 Join table2 on table1pkey=table2fkey Where MyDynamicString <> table2.someotherfield I know table2.someotherfield is not equal to the dynamic string. However, when I replace MyDynamicString in the Where clause with the full left(left(etc.. function, it works as expected. Can I not reference this string later in the query? Do I have to build it using the left(left(etc.. function each time in the where clause?

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  • how to read specific number of floats from file in python?

    - by sahel
    I am reading a text file from the web. The file starts with some header lines containing the number of data points, followed the actual vertices (3 coordinates each). The file looks like: # comment HEADER TEXT POINTS 6 float 1.1 2.2 3.3 4.4 5.5 6.6 7.7 8.8 9.9 1.1 2.2 3.3 4.4 5.5 6.6 7.7 8.8 9.9 POLYGONS the line starting with the word POINTS contains the number of vertices (in this case we have 3 vertices per line, but that could change) This is how I am reading it right now: ur=urlopen("http://.../file.dat") j=0 contents = [] while 1: line = ur.readline() if not line: break else: line=line.lower() if 'points' in line : myline=line.strip() word=myline.split() node_number=int(word[1]) node_type=word[2] while 'polygons' not in line : line = ur.readline() line=line.lower() myline=line.split() i=0 while(i<len(myline)): contents[j]=float(myline[i]) i=i+1 j=j+1 How can I read a specified number of floats instead of reading line by line as strings and converting to floating numbers? Instead of ur.readline() I want to read the specified number of elements in the file Any suggestion is welcome..

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  • Getting text at clicked location in an HTML element

    - by Marc
    I have a div element containing some text. When the user clicks a word inside that div I'd like to highlight just that word. In order to do this I need to know what character position in the text the click occurred at, so I can then locate nearby whitespace and insert some formatting around the word. Finding out where the click occurred within the text is the trick here. Is that kind of thing possible?

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  • Path String Concatenation Question in C#.

    - by Nano HE
    Hello. I want to output D:\Learning\CS\Resource\Tutorial\C#LangTutorial But can't work. Compiler error error CS0165: Use of unassigned local variable 'StrPathHead Please give me some advice about how to correct my code or other better solution for my case. Thank you. static void Main(string[] args) { string path = "D:\\Learning\\CS\\Resource\\Book\\C#InDeepth"; int n = 0; string[] words = path.Split('\\'); foreach (string word in words) { string StrPathHead; string StrPath; Console.WriteLine(word); if (word == "Resource") { StrPath = StrPathHead + word + "\\Tutorial\\C#LangTutorial"; } else { StrPathHead += words[n++] + "\\"; } } }

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