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  • Problem with SQL query

    - by William
    Here's the query INSERT INTO test_bans( ip, Expiration ) VALUES ( "0.0.0.0", DateAdd( "d", 1, Date( ) ) ) Here's the table creation query CREATE TABLE test_bans ( ID smallint(6) NOT NULL AUTO_INCREMENT, IP text NOT NULL, Expiration DATETIME NOT NULL, PRIMARY KEY (ID) ) TYPE=MyISAM; And here's the error #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')))' at line 1 Please help.

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  • How to Unselect The Field in select Query using sql

    - by raam
    hi in my database i am store more than 50 field with primarykey (Auto increment) i am not sure about the fields name but i wants to select the entire data in that table , i am using SELECT * FROM tablename i want to select all the fields except that ID but this query populate the entire table so is there is possible to unselect the particular field in the select query. Can anyone have an idea please guide me. Thanks in Advance

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  • Join with table and sub query in oracle

    - by Amandeep
    I dont understand what is wrong with this query it is giving me compile time error of command not ended properly.The inner query is giving me 4 records can any body help me out. select WGN3EVENTPARTICIPANT.EVENTUID from (Select WGN_V_ADDRESS_1.ADDRESSUID1 as add1, WGN_V_ADDRESS_1.ADDRESSUID2 as add2 from WGN3USER inner join WGN_V_ADDRESS_1 on WGN_V_ADDRESS_1.USERID=wgn3user.USERID where WGN3USER.USERNAME='FIRMWIDE\khuraj' ) as ta ,WGN3EVENTPARTICIPANT where (ta.ADDRESSUID1=WGN3EVENTPARTICIPANT.ADDRESSUID1) AND (ta.ADDRESSUID2=WGN3EVENTPARTICIPANT.ADDRESSUID2) I am running it in oracle. Thanks Amandeep

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  • What is the result of this SQL query?

    - by Martin
    I'm working on a mock exam paper at the moment, however I have no set of correct answers and I'm not sure what the correct answer of this SQL query is. Given a table: foo, bar a , 1 b , 3 a , 2 c , 1 and the query: SELECT foo, sum(bar) FROM table GROUP BY foo The two ways I can see this going are either: a 3 a 3 b 3 c 1 or a 3 b 3 c 1 Thanks.

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  • Simple check for SELECT query empty result

    - by den-javamaniac
    Hi. Can anyone point out how to check if a select query returns non empty result set? For example I have next query: SELECT * FROM service s WHERE s.service_id = ?; Should I do something like next: ISNULL(SELECT * FROM service s WHERE s.service_id = ?) to test if result set is not empty?

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  • Simple question on database query.

    - by GK
    I have been asked in an interview, To write a sql query which fetches the first three records with highest value on some column from a table. i had written a query which fetched all the records with highest value, but didnt get how exactly i can get only first three records of those. could you help me in this. thanks.

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  • Error #1064 in mySQL Query

    - by William
    I get the following error in the query below: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')))' at line 1 Code Snippet: INSERT INTO test_bans( ip, Expiration ) VALUES ( "0.0.0.0", DateAdd( "d", 1, Date( ) ) ) Table creation query CREATE TABLE test_bans ( ID smallint(6) NOT NULL AUTO_INCREMENT, IP text NOT NULL, Expiration DATETIME NOT NULL, PRIMARY KEY (ID) ) TYPE=MyISAM; What am I missing?

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  • Solution for this SQL query?

    - by homeWorkBoy
    Suppose you have these tables: Table Name: Salesman Fields: S_ID(Primary Key), Name Table Name: Region_1 Fields: Reg_ID(Primary Key), S_ID(Foreign Key), sales Table Name: Region_2 Fields: Reg_ID(Primary Key), S_ID(Foreign Key), sales Table Name: Region_3 Fields: Reg_ID(Primary Key), S_ID(Foreign Key), sales Table Name: Region_4 Fields: Reg_ID(Primary Key), S_ID(Foreign Key), sales Query 1: Find out total of sales of each salesman in all the regions. Query 2: Find out total of sales of a particual salesman in all the regions. (if the first one is solved I think this will be easy. :-) )

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  • mysql query fails.It gives me invalid result

    - by user2941349
    I have to write mysql query for fetching result from my database with a specified date and code like ABH18 or ABH17 or ABH19.I write the querly like below. select * from tbl_transaction where trans_name like 'ABH19%' or trans_name like 'ABH18%' or trans_name like 'ABH17%' or trans_name like 'ABH15%' and date_of_vazhipad='2013-11-20' and trans_status='Completed successfully.' There are no result in the DB satisfying all above conditions.But i got result with different dates.But i want to ensure the date_of_vazhipad='2013-11-20' so that the query may work properly Thanks in advance

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  • dojo query for checkboxes

    - by mouse
    Hi I want to get all my checked checkboxes from a form and i do like this(and it works) var cbs = dojo.query('input:checked', 'f'); I wand to add another selector(class selector) to get all checked checkboxes from a form with a specified class. I tried this one but it doesn't work var cbs = dojo.query('input:checked .xClass', 'f');

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  • Simple DB2 Query for connection validation

    - by Eric Tuttleman
    I'm looking for a simple DB2 query that can be used to test if a database connection in pool is still valid. It needs to be a generic query that would execute regardless of which databases exist. For other database servers, I've used something like 'SELECT 1' or 'SELECT version();' What would be an equivalent for DB2? Thanks!

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  • Check mysql_query results if DELETE query worked?

    - by Camran
    I have a DELETE query which deletes a record from a mysql db. is there any way to make sure if the delete was performed or not? I mean, for a query to FIND stuff you do $res=mysql_query($var); $nr=mysql_num_rows($res); and you get nr of rows returned. Is there any similiar method for deletion of records? Thanks

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  • PHP inserting Apostrophes where it shouldn't

    - by Jack W-H
    Hi folks Not too sure what's going on here as this doesn't seem like standard practise to me. But basically I have a basic database thingy going on that lets users submit code snippets. They can provide up to 5 tags for their submission. Now I'm still learning so please forgive me if this is obvious! Here's the PHP script that makes it all work (note there may be some CodeIgniter specific functions in there): function submitform() { $this->load->helper(array('form', 'url')); $this->load->library('form_validation'); $this->load->database(); $this->form_validation->set_error_delimiters('<p style="color:#FF0000;">', '</p>'); $this->form_validation->set_rules('title', 'Title', 'trim|required|min_length[5]|max_length[255]|xss_clean'); $this->form_validation->set_rules('summary', 'Summary', 'trim|required|min_length[5]|max_length[255]|xss_clean'); $this->form_validation->set_rules('bbcode', 'Code', 'required|min_length[5]'); // No XSS clean (or <script> tags etc. are gone) $this->form_validation->set_rules('tags', 'Tags', 'trim|xss_clean|required|max_length[254]'); if ($this->form_validation->run() == FALSE) { // Do some stuff if it fails } else { // User's input values $title = $this->db->escape(set_value('title')); $summary = $this->db->escape(set_value('summary')); $code = $this->db->escape(set_value('bbcode')); $tags = $this->db->escape(set_value('tags')); // Stop things like <script> tags working $codesanitised = htmlspecialchars($code); // Other values to be entered $author = $this->tank_auth->get_user_id(); $bi1 = ""; $bi2 = ""; // This long messy bit basically sees which browsers the code is compatible with. if (isset($_POST['IE6'])) {$bi1 .= "IE6, "; $bi2 .= "1, ";} else {$bi1 .= "IE6, "; $bi2 .= "NULL, ";} if (isset($_POST['IE7'])) {$bi1 .= "IE7, "; $bi2 .= "1, ";} else {$bi1 .= "IE7, "; $bi2 .= "NULL, ";} if (isset($_POST['IE8'])) {$bi1 .= "IE8, "; $bi2 .= "1, ";} else {$bi1 .= "IE8, "; $bi2 .= "NULL, ";} if (isset($_POST['FF2'])) {$bi1 .= "FF2, "; $bi2 .= "1, ";} else {$bi1 .= "FF2, "; $bi2 .= "NULL, ";} if (isset($_POST['FF3'])) {$bi1 .= "FF3, "; $bi2 .= "1, ";} else {$bi1 .= "FF3, "; $bi2 .= "NULL, ";} if (isset($_POST['SA3'])) {$bi1 .= "SA3, "; $bi2 .= "1, ";} else {$bi1 .= "SA3, "; $bi2 .= "NULL, ";} if (isset($_POST['SA4'])) {$bi1 .= "SA4, "; $bi2 .= "1, ";} else {$bi1 .= "SA4, "; $bi2 .= "NULL, ";} if (isset($_POST['CHR'])) {$bi1 .= "CHR, "; $bi2 .= "1, ";} else {$bi1 .= "CHR, "; $bi2 .= "NULL, ";} if (isset($_POST['OPE'])) {$bi1 .= "OPE, "; $bi2 .= "1, ";} else {$bi1 .= "OPE, "; $bi2 .= "NULL, ";} if (isset($_POST['OTH'])) {$bi1 .= "OTH, "; $bi2 .= "1, ";} else {$bi1 .= "OTH, "; $bi2 .= "NULL, ";} // $b1 is $bi1 without the last two characters (, ) which would cause a query error $b1 = substr($bi1, 0, -2); $b2 = substr($bi2, 0, -2); // :::::::::::THIS IS WHERE THE IMPORTANT STUFF IS, STACKOVERFLOW READERS:::::::::: // Split up all the words in $tags into individual variables - each tag is seperated with a space $pieces = explode(" ", $tags); // Usage: // echo $pieces[0]; // piece1 etc $ti1 = ""; $ti2 = ""; // Now we'll do similar to what we did with the compatible browsers to generate a bit of a query string if ($pieces[0]!=NULL) {$ti1 .= "tag1, "; $ti2 .= "$pieces[0], ";} else {$ti1 .= "tag1, "; $ti2 .= "NULL, ";} if ($pieces[1]!=NULL) {$ti1 .= "tag2, "; $ti2 .= "$pieces[1], ";} else {$ti1 .= "tag2, "; $ti2 .= "NULL, ";} if ($pieces[2]!=NULL) {$ti1 .= "tag3, "; $ti2 .= "$pieces[2], ";} else {$ti1 .= "tag3, "; $ti2 .= "NULL, ";} if ($pieces[3]!=NULL) {$ti1 .= "tag4, "; $ti2 .= "$pieces[3], ";} else {$ti1 .= "tag4, "; $ti2 .= "NULL, ";} if ($pieces[4]!=NULL) {$ti1 .= "tag5, "; $ti2 .= "$pieces[4], ";} else {$ti1 .= "tag5, "; $ti2 .= "NULL, ";} $t1 = substr($ti1, 0, -2); $t2 = substr($ti2, 0, -2); $sql = "INSERT INTO code (id, title, author, summary, code, date, $t1, $b1) VALUES ('', $title, $author, $summary, $codesanitised, NOW(), $t2, $b2)"; $this->db->query($sql); $this->load->view('subviews/template/headerview'); $this->load->view('subviews/template/menuview'); $this->load->view('subviews/template/sidebar'); $this->load->view('thanksforsubmission'); $this->load->view('subviews/template/footerview'); } } Sorry about that boring drivel of code there. I realise I probably have a few bad practises in there - please point them out if so. This is what the outputted query looks like (it results in an error and isn't queried at all): A Database Error Occurred Error Number: 1136 Column count doesn't match value count at row 1 INSERT INTO code (id, title, author, summary, code, date, tag1, tag2, tag3, tag4, tag5, IE6, IE7, IE8, FF2, FF3, SA3, SA4, CHR, OPE, OTH) VALUES ('', 'test2', 1, 'test2', 'test2 ', NOW(), 'test2, test2, test2, test2, test2', NULL, NULL, 1, 1, 1, 1, 1, 1, 1, NULL) You'll see at the bit after NOW(), 'test2, test2, test2, test2, test2' - I never asked it to put all that in apostrophes. Did I? What I could do is put each of those lines like this: if ($pieces[0]!=NULL) {$ti1 .= "tag1, "; $ti2 .= "'$pieces[0]', ";} else {$ti1 .= "tag1, "; $ti2 .= "NULL, ";} With single quotes around $pieces[0] etc. - but then my problem is that this kinda fails when the user only enters 4 tags, or 3, or whatever. Sorry if that's the worst phrased question in history, I tried, but my brain has turned to mush. Thanks for your help! Jack

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  • Replace dual-XP installs with single-XP install and repartition drive?

    - by caeious
    Hello, The Current Situation I have a hard drive that currently is split up like so: Primary Partition C: 9.77 GB NTFS Healthy (System) with XP Pro (in Polish) installed Extended Partition D: 39.82 GB NTFS Healthy (Boot) with XP Pro (in English) installed 6.30 GB Free space When I start my comuter I get a black and white Windows Boot Manager dual boot screen with 2 choices both being Microsoft Windows XP. The first choice is the English version of XP and the second choice is the Polish version of XP. Images of my Computer Management window and Dual Boot screen The Mission What I need to do is get rid of the entire extended partition (D: 39.82 GB & 6.30 free space) and just have the one primary C: drive which I assume will be somewheres around 55 GB big. So in the end I just want XP Pro in English running on my C: drive and no black and white boot screen to show up when starting up my laptop. The Question How do I go about successfully completing The Mission with out making my computer a useless pile of silicon, plastic and metal? UPDATE: So I went ahead and tried to follow Neal's suggestion but hit a wall. I got to a Windows XP Pro install screen that had the 3 following options as well as my drive data: To set up Windows XP on the selected item, press Enter To create a partition in the unpartitioned space, press C To delete the selected partition, press D 57232 MB Disk 0 at Id 0 on bus 0 on atapi [MBR] C: Partition1 [NTFS] 10001 MB ( 4642 MB free ) Unpartitioned space 6448 MB D: Partition2 [NTFS] 40774 MB ( 26225 MB free ) Unpartitioned space 8 MB I figured I would go with the first choice ((To set up Windows XP on the selected item, press Enter)) because I just wanted to set up Windows XP on C: Partition1 (which was preselected) so I pressed Enter which brought me to a screen displaying this message: You chose to install Windows XP on a partition that contains another operating system. Installing Windows XP on this partition might cause the other operating system to function improperly. CAUTION: Installing multiple operating systems on a single partition is not recommended. So this leads me to 2 new questions: How do I get rid of the Windows XP (Polish language) install on C: Partition 1 so that I can cleanly and safely install Windows XP (English language) on it? Neal, is this what you meant by me possibly having to delete the partition that the Windows XP (Polish language) install was located on? Since I have the option to delete partitions with the 3rd choice ((To delete the selected partition, press D)), should I do that on this screen or wait until I have Windows XP (English language) safely installed on C: Partition 1? I have to ask these questions because I have read that it is possibly dangerous to delete hard drive partitions. Just being cautious.

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  • Windows Vista language text service problem

    - by Azho KG
    Hi, All I'm using English version of Vista and having problems with using programs that display Russian characters somewhere. For example dictionaries doesn't work for me, since they display Russian character. Also I see just "magic" characters in text editor (notepad) when open a Russian text file. I tried to change whole Vista Interface language to Russian, but it still didn't solve the problem. I CAN read any web page from browser, that's not a problem. Also adding "Russian" in "Text Services and Input Languages" doesn't solve this problem. Does anyone know how to solve this? Thanks. My System: 32-bit Windows Vista Home Premium - SP2

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  • Something for the weekend - Whats the most complex query?

    - by simonsabin
    Whenever I teach about SQL Server performance tuning I try can get across the message that there is no such thing as a table. Does that sound odd, well it isn't, trust me. Rather than tables you need to consider structures. You have 1. Heaps 2. Indexes (b-trees) Some people split indexes in two, clustered and non-clustered, this I feel confuses the situation as people associate clustered indexes with sorting, but don't associate non clustered indexes with sorting, this is wrong. Clustered and non-clustered indexes are the same b-tree structure(and even more so with SQL 2005) with the leaf pages sorted in a linked list according to the keys of the index.. The difference is that non clustered indexes include in their structure either, the clustered key(s), or the row identifier for the row in the table (see http://sqlblog.com/blogs/kalen_delaney/archive/2008/03/16/nonclustered-index-keys.aspx for more details). Beyond that they are the same, they have key columns which are stored on the root and intermediary pages, and included columns which are on the leaf level. The reason this is important is that this is how the optimiser sees the world, this means it can use any of these structures to resolve your query. Even if your query only accesses one table, the optimiser can access multiple structures to get your results. One commonly sees this with a non-clustered index scan and then a key lookup (clustered index seek), but importantly it's not restricted to just using one non-clustered index and the clustered index or heap, and that's the challenge for the weekend. So the challenge for the weekend is to produce the most complex single table query. For those clever bods amongst you that are thinking, great I will just use lots of xquery functions, sorry these are the rules. 1. You have to use a table from AdventureWorks (2005 or 2008) 2. You can add whatever indexes you like, but you must document these 3. You cannot use XQuery, Spatial, HierarchyId, Full Text or any open rowset function. 4. You can only reference your table once, i..e a FROM clause with ONE table and no JOINs 5. No Sub queries. The aim of this is to show how the optimiser can use multiple structures to build the results of a query and to also highlight why the optimiser is doing that. How many structures can you get the optimiser to use? As an example create these two indexes on AdventureWorks2008 create index IX_Person_Person on Person.Person (lastName, FirstName,NameStyle,PersonType) create index IX_Person_Person on Person.Person(BusinessentityId,ModifiedDate)with drop_existing    select lastName, ModifiedDate   from Person.Person  where LastName = 'Smith' You will see that the optimiser has decided to not access the underlying clustered index of the table but to use two indexes above to resolve the query. This highlights how the optimiser considers all storage structures, clustered indexes, non clustered indexes and heaps when trying to resolve a query. So are you up to the challenge for the weekend to produce the most complex single table query? The prize is a pdf version of a popular SQL Server book, or a physical book if you live in the UK.  

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  • Windows 7 wont boot from any boot loader except for 'Windows Boot Manager' after partition resize

    - by user2468327
    I have a triple boot system on a single SSD. OSX, Windows 7, and Ubuntu. I use Chimera (basically another version of Chameleon) as my boot loader. Usually I can boot all 3 without any issue, but after using GParted to make my Ubuntu partition 2 Gigs larger, Windows 7 throws me an error when trying to boot to it from either Chimera or Grub. The error is consistently: 0xc000000e "cant find \Boot\BCD" (slightly paraphrased). However, I can still get into Windows by selecting "Windows Boot Manager" from the boot options in my bios. I've already tried several known fixes for similar issues, including bootrec /rebuildbcd (and variations), and BootRec.exe/fixMBR + BootRec.exe/fixBoot. Ive also tried Chkdsk. At best this has made it so Windows 7 boots on it's own by default (making me have to reinstall Chimera and change back my boot settings in the bios). At worst this made it so Windows wont boot period. Now I'm back full circle where I started. A detail that might be useful is that bootrec /rebuildbcd says that the number of found Windows installations is 0. How do I get it back so I can boot Win7 through another boot loader so I don't have to manually select it in the bios? Preferably without a reinstall.

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  • System Rescue CD on multiboot usb not working

    - by darkfeline
    I have a multiboot usb with System Rescue CD and GRUB2 on it. When I try to boot it, it tries to find systemrescuecd/sysrcd.dat, attempts to mount /dev/sr0 and all the partitions on /dev/sda before declaring cannot find systemrescuecd/sysrcd.dat on devices and dumping me onto a primitive shell. The relevant entries in grub.cfg: menuentry "SystemRescueCd 32bit" { linux /systemrescuecd/isolinux/rescuecd rootfs=/systemrescuecd subdir=systemrescuecd dostartx setkmap=us initrd /systemrescuecd/isolinux/initram.igz } menuentry "SystemRescueCd 64bit" { linux /systemrescuecd/isolinux/rescue64 rootfs=/systemrescuecd subdir=systemrescuecd dostartx setkmap=us initrd /systemrescuecd/isolinux/initram.igz } I think the problem is that System Rescue CD cannot see /dev/sdb, which is my usb, but I don't know where to begin to fix it. If it helps, I set up my USB with a utility called MultiSystem, which is like MultiISO for Linux.

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  • Have set Expiration time: Still getting "Query string present but no explicit expiration time"

    - by oligofren
    I have one local Apache instance running with mod_cache (+ disk & mem) enabled, and it seems to cache content from my appserver fine. My app server sets Expiration headers and Last-modified. Yet, when deploying on a production server with the same modules enabled, I am getting the following error in my logs: blablabla not cached. Reason: Query string present but no explicit expiration time Any clues on why Apache is not caching content? The only difference is the Apache version. Locally I am running 2.2. This is from my config CacheRoot "/var/cache/apache2/" CacheEnable disk / This is example output < HTTP/1.1 200 OK < Date: Mon, 19 Nov 2012 16:09:13 GMT < Server: Sun GlassFish Enterprise Server v2.1.1 < X-Powered-By: Servlet/2.5 < Expires: Tue Nov 20 05:00:00 CET 2012 < Last-Modified: Mon Nov 19 17:09:13 CET 2012 < Cache-Control: no-transform < Content-Type: application/x-javascript < Transfer-Encoding: chunked

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