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  • Mysql - Grouping the result based on a mathematical operation and SUM() function

    - by SpikETidE
    Hi all... I'm having the following two tables... Table : room_type type_id type_name no_of_rooms max_guests rate 1 Type 1 15 2 1254 2 Type 2 10 1 3025 Table : reservation reservation_id start_date end_date room_type booked_rooms 1 2010-04-12 2010-04-15 1 8 2 2010-04-12 2010-04-15 1 2 Now... I have this query SELECT type_id, type_name FROM room_type WHERE id NOT IN (SELECT room_type FROM reservation WHERE start_date >= '$start_date' AND end_date <= '$end_date') What the query does is it selects the rooms that are not booked between the start date and end date. Also, as you can see from the reservation table, we also have 'number of rooms booked between the two dates' factor also... I need to add this 'no.of booked rooms between the two dates' factor also in to the query... The query should return the type of rooms for which at least one room is free between the two dates. I worked out the logic but just can't represent it as a query....! How will you do this...? Thanks for your suggestions..!

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  • Should I stick only to AWS RDS Automated Backup or DB Snapshots?

    - by James Wise
    I am using AWS RDS for MySQL. With it comes on backup, I understand that amazon provides two types of backup - automated backup and database (DB) snapshot. The difference is explain in here - http://aws.amazon.com/rds/faqs/#23. However, I am still confuse if should I stick to automated backup only or both automated and manual (db snapshots). What do you think guys? What's the setup of your own? I heard to others that automated backup is not reliable due to some unrecoverable database when the DB instance is crashed so the DB snapshots are the way to rescue you. If I will do daily DB snapshots as similar settings to automated backup, I have gonna pay much bunch of bucks. Hope anyone could enlighten me or advise me the right set up. Thanks. James

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  • PHP & MySQL Undefined variable problem

    - by comma
    I keep getting the following error Undefined variable: id on line 91 can some one help me correct this problem? The error is on this line. $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; MySQL database tables. CREATE TABLE tags ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill VARCHAR(255) NOT NULL, experience VARCHAR(255) NOT NULL, years VARCHAR(255) NOT NULL, PRIMARY KEY (id) ); CREATE TABLE users_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill_id INT UNSIGNED NOT NULL, user_id INT UNSIGNED NOT NULL, date_created DATETIME UNSIGNED NOT NULL, PRIMARY KEY (id) ); Here is the PHP & MySQL code. if (isset($_POST['info_submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); return; } $user_id = '5'; $skill = $_POST['skill']; $experience = $_POST['experience']; $years = $_POST['years']; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON users_skills.skill_id = learned_skills.id WHERE users_skills.user_id='$user_id'"); if (mysqli_num_rows($dbc) == 0) { if (isset($_POST['skill']) && trim($_POST['skill'])!=='') { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $skill . "', '" . $experience . "', '" . $years . "')"); if (mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM learned_skills WHERE id='" . $skill . "' AND experience='" . $experience . "' AND years='" . $years . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; } }

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  • MySQL Count If using 4 tables or Perl

    - by user1726133
    Hi I have a relatively convoluted query that relies on 4 different tables, unfortunately I do not have control of this data, but I do have to query it. I ran this simpler query and it works using just table 1 and table 2 SELECT actor, receiver, count(IF(t2.group1 = "anxiety behavior", 1,0)) AS 'anxiety' FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code GROUP BY actor; Below are the 4 tables I need and the query I tried that didn't work Table 1 | Table 2 | Table 3 | Table 4 Actor | Behavior | Behavior | type of Behavior | subject | sex | subject |subject_code er frown | frown anxiety behavior | Eric M | Eric | er Here is the query that is failing SELECT actor, count(IF(t2.group1 = "anxiety behavior", 1,0) AND(t3.sex = "M", 1,0)) AS 'anxiety', FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code JOIN subject_code t3 on t1.actor = t3.behavior_code1 JOIN subjects t4 on t3.subject = t4.yerkes_code GROUP BY actor; Any help would be much appreciated!! Thanks :) P.S. if this is easier to do in Perl tips also much appreciated

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  • MySQL - Selecting the top occurring entries

    - by RC
    Hi, Should be a simple one. Database is mydb. One of the columns is mydata. What SELECT query do I need in order to select the top 3 occurring results from mydata, but sorted alphabetically? For example, if my data is this: mydata ====== kilo (x 1 occurrence) lima (x 9 occurrences) golf (x 5 occurrences) echo (x 9 occurrences) zulu (x 8 occurrences) How do I get it to return "echo, lima, zulu", which are the top three frequently occurring entries sorted alphabetically? Thanks! EDIT: Just to add, they need to be distinct entries. Thanks!

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  • Why is this MySQL Join Statement not Working?

    - by Timmy
    Here is my code: $query2 = mysql_query("SELECT * FROM categories WHERE parent = $id JOIN SELECT * FROM posts WHERE main_nav_page = '$idTwo'"); while ($row2 = mysql_fetch_assoc($query2)) { $id = $row2['id']; $name = $row2['name']; $slug = $row2['slug']; $subMenuOrder = $row2['sub_menu_order']; echo "<tr>\n"; echo "<td>&nbsp; -- $name</td>\n"; echo "</tr>\n"; } Is my syntax wrong? EDIT: the error message is: Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/studentw/public_html/new_nav.php on line 30

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  • Mysql_insert_id with Doctrine

    - by Industrial
    Hi! I have a couple of tables (mySQL) that i would like to update with the help of Doctrine. The products table id is auto-incrementing, and here's a brief description on what I would like to do: $prod = new Products(); $prod->type = '0'; $categ = new CategoriesToProducts(); $categ->cat = '111'; $categ->product = $prod->id; $conn = Doctrine_Manager::connection(); $conn->flush(); How can I do this while using flush? Using a regular save is an alternative, but there will be multiple transactions while doing such. I have tried to find a Mysql_insert_id version for doctrine, but without any luck. Thanks!

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  • mysql - offset problem

    - by Phil Jackson
    Hi, I recently posted a question about getting last 3 results in table in the correct order. I now want the get all comments apart from the last 3 in the correct order. Here is my syntax; SELECT * FROM (SELECT * FROM $table ORDER BY ID DESC OFFSET 3) AS T ORDER BY TIME_STAMP the error i am receiving is; You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'OFFSET, 3) AS T ORDER BY TIME_STAMP' at line 1 I can't seem to get it to work. Any help much appreciated.

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  • mysql - combining columns and tables

    - by Phil Jackson
    Hi, I'm not much of a SQL man so I'm seeking help for this one. I have a site where I have a database for all accounts and whatnot, and another for storing actions that the user has done on the site. Each user has their own table but I want to combine the data of each user group ( all users that are "linked together" ) and order that data in the time the actions took place. Heres what I have; <?php $query = "SELECT `TALKING_TO` FROM `nnn_instant_messaging` WHERE `AUTHOR` = '" . DISPLAY_NAME . "' AND `TALKING_TO` != ''"; $query = mysql_query( $query, $CON ) or die( "_error_ " . mysql_error()); if( mysql_num_rows( $query ) != 0 ) { $table_str = ""; $select_ref_clause = "( "; $select_time_stamp_clause = "( "; while( $row = mysql_fetch_array( $query ) ) { $table_str .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . "`, "; $select_ref_clause .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . ".REF`, "; $select_time_stamp_clause .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . ".TIME_STAMP`, "; } $table_str = $table_str . "`actvbiz_networks`.`" . DISPLAY_NAME . "`"; $select_ref_clause = substr($select_ref_clause, 0, -2) . ") AS `REF`, "; $select_time_stamp_clause = substr($select_time_stamp_clause, 0, -2) . " ) AS `TIME_STAMP`"; }else{ $table_str = "`actvbiz_networks`.`" . DISPLAY_NAME . "`"; $select_ref_clause = "`REF`, "; $select_time_stamp_clause = "`TIME_STAMP`"; } $where_clause = $select_ref_clause . $select_time_stamp_clause; $query = "SELECT " . $where_clause . " FROM " . $table_str . " ORDER BY TIME_STAMP"; die($query); $query = mysql_query( $query, $CON ) or die( "_error_ " . mysql_error()); if( mysql_num_rows( $query ) != 0 ) { }else{ ?> <p>Currently no actions have taken place in your network.</p> <?php } ?> The code above returns the sql statement: SELECT ( `actvbiz_networks`.`john_doe.REF`, `actvbiz_networks`.`Emmalene_Jackson.REF`) AS `REF`, ( `actvbiz_networks`.`john_doe.TIME_STAMP`, `actvbiz_networks`.`Emmalene_Jackson.TIME_STAMP` ) AS `TIME_STAMP` FROM `actvbiz_networks`.`john_doe`, `actvbiz_networks`.`Emmalene_Jackson`, `actvbiz_networks`.`act_web_designs` ORDER BY TIME_STAMP I really am learning on my feet with SQL. Its not the PHP I have a problem with ( I can quite happly code away with PHP ) I'ts just help with the SQL statement. Any help much appreciated, REgards, Phil

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  • MySQL Prepared Statements vs Stored Procedures Performance

    - by amardilo
    Hi there, I have an old MySQL 4.1 database with a table that has a few millions rows and an old Java application that connects to this database and returns several thousand rows from this this table on a frequent basis via a simple SQL query (i.e. SELECT * FROM people WHERE first_name = 'Bob'. I think the Java application uses client side prepared statements but was looking at switching this to the server, and in the example mentioned the value for first_name will vary depending on what the user enters). I would like to speed up performance on the select query and was wondering if I should switch to Prepared Statements or Stored Procedures. Is there a general rule of thumb of what is quicker/less resource intensive (or if a combination of both is better)

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  • mySQL php query - news/ friends feed

    - by rpsep2
    I want to show a user the recent uploads from their friends. I have the users friends id's in an array: $friends A user could have, potentially, thousands of friends. I can select the uploads from 1 of a users friends with: $row = $mysqli->query("SELECT * FROM photos WHERE uploader_id = ".$friend." ORDER BY date_uploaded DESC LIMIT ".$page.", 25"); But I need to find all of a users friends uploads. I thought about doing this in a loop iterating over the $friends array, but then I'd be potentially running thousands of mysql queries. How can I do this most efficiently? so to clarify: search a 'photos' table for photos which are uploaded by specific users(friends), held in $friends variable, sort by date_uploaded and limit to x results so I can have pages 1, 2, 3 etc.

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  • mysql multiple where and inner join query combination

    - by bandhunt
    I'm a little lost as how to run two mysql queries as one(return one result set to be sorted etc). I understand how to do multiple JOINS but need to combine the below which is more than just a multiple join - it would include a multiple where etc. 1st query sql = "SELECT s.id, s.song_name FROM `songs` as s INNER JOIN `artists` as a ON s.artist_id = a.id WHERE ((`a`.id = #{search}))" 2nd query sql = "SELECT s.id, s.song_name FROM `songs` as s INNER JOIN `similarments` as si ON s.artist_id = si.artist_id WHERE ((`si`.similar_id = #{search}))" And then run both queries at once so I can ORDER them etc. Or combine them as one big query (maybe put an OR somewhere)? Thanks!

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  • Validate a date range within MySQL query

    - by fishcracker
    (This question may seem easy or kind of noobish, by that I pardon my ignorance.) I used PDO query to use SELECT then fetch some values, it comes to a point that I need to fetch only some entries that within its start date and end date. My database +----------+-----------------+----------------------+--------------------+ | id (INT) | title (VARCHAR) | start_date (VARCHAR) | end_date (VARCHAR) | +----------+-----------------+----------------------+--------------------+ | 1 | buddy | 2012-11-26 | 2012-11-30 | | 2 | metro | 2012-12-05 | 2012-12-20 | | 3 | justin | 2012-11-28 | 2012-12-01 | +----------+-----------------+----------------------+--------------------+ My query is as follows: $query = "SELECT title, start_date, end_date FROM debts WHERE start_date >= CURDATE() AND end_date >= CURDATE()"; What I want to achieve is whenever the start_date is today or greater but not exceeding the end_date it will be valid. This will return the row for id 1, however if I change the start_date to 2012-11-25, it will fail due to the first condition on AND. I'm really confuse on this since I am new to this, is there any built-in function to handle this kind of situation?

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  • Accessing global variables within functions in PHP

    - by st3
    There are multiple times in one page where I need to connect and subsequently query a MySQL database, yet my code won't let me. I think it might be something to do with how my files are nested but it makes no sense. I am opening the SQL connection in the header file. The top of the offending page looks like the following: <?php $page_title = 'Dashboard'; include('templates/header.inc'); // includes a 'require_once('mysqli_connect.php') and a small query to the database; require_once('includes/functions.php'); require_once('includes/dashboard_sql.php'); // Contains functions which connect to database (which are failing.) ?> I get the PHP error Notice: Undefined variable: dbc in /Library/WebServer/Documents/pediatory_site/includes/dashboard_sql.php Where $dbc is the database connection defined in mysqli_connect.php. If anyone could help me out that would be great.

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  • Improving MySQL Update Query Efficiency

    - by Russell C.
    In our database tables we keep a number of counting columns to help reduce the number of simple lookup queries. For example, in our users table we have columns for the number of reviews written, photos uploaded, friends, followers, etc. To help make sure these stay in sync we have a script that runs periodically to check and update these counting columns. The problem is that now that our database has grown significantly the queries we have been using are taking forever to run since they are totally inefficient. I would appreciate someone with more MySQL knowledge than myself to recommend how we can improve it's efficiency: update users set photos=(select count(*) from photos where photos.status="A" AND photos.user_id=users.id) where users.status="A"; If this were a select statement I would just use a join but I'm not sure if that is possible with update. Thanks in advance for your help!

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  • Optimise & improve performance of this MYSQL query

    - by David
    SELECT u.id, u.honour, COUNT(*) + 1 AS rank FROM user_info u INNER JOIN user_info u2 ON u.honour < u2.honour WHERE u.id = '$id' AND u2.status = 'Alive' AND u2.rank != '14' This query is currently utterly raping my server. It works out based on your honour what rank you are within the 'user_info' table which stores it out of all our users. Screenshot for explain. http://cl.ly/370z0v2Y3v2X1t1r1k2A SELECT u.id, u.honour, COUNT(*)+1 as rank FROM user_info u USE INDEX (prestigeOptimiser) INNER JOIN user_info u2 ON u.honour < u2.honour WHERE u.id='3' AND u2.status='Alive' AND u2.rank!='14'

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  • Duplicate / Copy records in the same MySQL table

    - by Digits
    Hello, I have been looking for a while now but I can not find an easy solution for my problem. I would like to duplicate a record in a table, but of course, the unique primary key needs to be updated. I have this query: INSERT INTO invoices SELECT * FROM invoices AS iv WHERE iv.ID=XXXXX ON DUPLICATE KEY UPDATE ID = (SELECT MAX(ID)+1 FROM invoices) the proble mis that this just changes the ID of the row instead of copying the row. Does anybody know how to fix this ? Thank you verrry much, Digits //edit: I would like to do this without typing all the field names because the field names can change over time.

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  • Escaping quotes twice in PHP

    - by Genadinik
    Hello, I have a complicated form where I first have to take some _GET parameters and obviously I have to do a mysql_real_escape_string() on them since I look stuff up in the database with them. Them problem for me is after the initial db lookup. When the user submits a form, I send them along as a _POST request and obviously have to do this mysql_real_escape_string call again just in case someone tries to hack my site with a faked form submission. Then the problem I have is the arguments are escaped twice and my queries begin to look strange like this: select field1 , field2 , from my_table where some_id = \'.$lookup_id.\' ... So the system seems to be adding \' and it is messing me up :) Also, in my other forms I have not seen such behavior. Any ideas on what may be causing this? One weird thing is that I tried to send unescaped parameters to the post, and the same problem happens. That is a clue, but not a sufficient one for me. :( Thanks, Alex

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  • Mysql Limit column value repetition N times

    - by Paper-bat
    Hi at all, is my first question here, so be patient ^^ I'll go directly to problem, I have two table Customer (idCustomer, ecc.. ecc..) Comment (idCustomer, idComment, ecc.. ecc..) obviosly the two table are joined togheter, for example SELECT * FROM Comment AS co JOIN Customer AS cu ON cu.idCustomer = co.idCustomer With this I select all comment from that table associated with is Customer, but now I wanna limit the number of Comment by 2 max Comment per Customer. The first thing I see is to use 'GROUP BY cu.idCustomer' but it limit only 1 Comment per Customer, but I wanna 2 Comment per Customer.. how now to proceed?

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  • Sum two rows in one - My Sql

    - by user303832
    I have found some similar posts, but I didn't find them useful. But I didn't know how to group them. I would like to Sum 'No' and 'Not Set' to one row, and to lose 'Not Set' row. So : 'No' = 'No' + 'Not Set' I have something like this : TEST TestCount Month 'Yes' 123 March 'No' 432 March 'Not Set' 645 March 'Yes' 13 April 'No' 42 April 'Not Set' 45 April 'Yes' 133 May 'No' 41 May 'Not Set' 35 May .... And I would like something like this : TEST TestCount Month 'Yes' 423 March 'No' 410 March 'Yes' 154 April 'No' 192 April 'Yes' 130 May 'No' 149 May .... Can anybody help me with this, tnx in advance

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  • MySQL - Selecting the top occuring entries

    - by RC
    Hi, Should be a simple one. Database is mydb. One of the columns is mydata. What SELECT query do I need in order to select the top 3 occuring results from mydata, but sorted alphabetically? For example, if my data is this: mydata ====== kilo (x 1 occurrence) lima (x 9 occurrences) golf (x 5 occurrences) echo (x 9 occurrences) zulu (x 8 occurrences) How do I get it to return "echo, lima, zulu", which are the top three frequently occurring entries sorted alphabetically? Thanks! EDIT: Just to add, they need to be distinct entries. Thanks!

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  • Display only latest three results from PHP and MySQL

    - by nogggin1
    <?php $result = @mysql_query('SELECT Article FROM news WHERE ID = (SELECT MAX(ID) FROM News)'); if (!$result) { die('<p>Error performing query: ' . mysql_error() . '</p>'); } while ( $row = mysql_fetch_array($result) ) { echo('<p>' . $row['Article'] . '</p>'); } ?> basically i need to tweak this so that it shows the latest 3 results instead of just the latest one, also i need the order to be: newest 2nd newest 3rd newest any help would be greatly appreciated!

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