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  • Integrating Zend Controller Standalone - without the rest of Zend Framework

    - by ssmusoke
    I am using specific parts of the Zend Framework in my application, and I would like to replace my home grown controller with a Zend Framework controller. My home grown controller is based on an index.php file to which all requests are submitted. A controller is instantiated based on parameters sent within the request After processing the user is forwarded to url which is based on the request information, either a url is specified or some data is analysed I would like ideas on how to integrate the Zend Controller within my application Thanks in advance

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  • Is this safe? Is this OK to do in MYSQL?

    - by alex
    I have always done this: mysqldump -hlocalhost -uuser -ppass MYDATABASE > /home/f/db_backup/MYDATABASE.sql mysql -uuser -ppass MYDATABASE < MYDATABASE.sql But, if I do this instead...is this safe? Is this identical to the above??? mysqldump -hlocalhost -uuser -ppass MYDATABASE | gzip > /home/f/db_backup/MYDATABASE.sql.gz zcat MYDATABASE.sql.gz | mysql -uuser -ppass MYDATABASE

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  • Grails spring security defaultTargetUrl going wrong path

    - by fsi
    Grails 2.4 with Spring security 2 3RC I have this on my Config.groovy grails.plugin.springsecurity.controllerAnnotations.staticRules = [ '/': ['permitAll'], '/index': ['permitAll'], '/index.gsp': ['permitAll'], '/**/js/**': ['permitAll'], '/**/css/**': ['permitAll'], '/**/images/**': ['permitAll'], '/**/favicon.ico': ['permitAll'] ] grails.plugin.springsecurity.successHandler.defaultTargetUrl = "/home/index" But this keeping me redirecting to assets/favicon.ico And my HomeController is like that @Secured(['ROLE_ADMIN', 'ROLE_USER']) def index() { if (SpringSecurityUtils.ifAllGranted('ROLE_ADMIN')) { redirect controller: 'admin', action: 'index' return } } And I modify this in my UrlMapping: "/"(controller: 'home', action:'index') Why it keeps me sending wrong path? Update: using another computer, it redirects me to /asset/grails_logo.png

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  • Ubuntu 9.10 Server (minimal virtual machine) partitioning

    - by John
    I am setting up a generic Ubuntu server and am trying to figure out the (best) way to partition the machine. Again, this is just a generic one: The default drive is 20GB. Some guides show: Separate /home, /usr, /var and /tmp partitions Another one suggested something like this: / 4GB /boot 512MB /tmp 1GB /home 5GB /usr 5GB /var 5GB What is the best way to accomplish this?

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  • Converting my lightweight MySQL DB wrapper into MySQLi. Pesky Problems

    - by Chaplin
    Here is the original code: http://pastebin.com/DNxtmApY. I'm not that interested in prepared statements at the moment, I just want this wrapper updating to MySQLi so once MySQL becomes depreciated I haven't got to update a billion websites. Here is my attempt at converting to MySQLi. <? $database_host = "127.0.0.1"; $database_user = "user"; $database_pass = "pass"; $database_name = "name"; $db = new database($database_host, $database_user, $database_pass, $database_name); class database { var $link, $result; function database($host, $user, $pass, $db) { $this->link = mysqli_connect($host, $user, $pass, $db) or $this->error(); mysqli_select_db($db, $this->link) or $this->error(); } function query($query) { $this->result = mysqli_query($query, $this->link) or $this->error(); $this->_query_count++; return $this->result; } function countRows($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_num_rows($result); } function fetch($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result); } function fetch_num($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result, mysqli_NUM); } function fetch_assoc($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result, mysqli_ASSOC); } function escape($str) { return mysqli_real_escape_string($str); } function error() { if ( $_GET["debug"] == 1 ){ die(mysqi_error()); } else { echo "Error in db code"; } } } function sanitize($data) { //apply stripslashes if magic_quotes_gpc is enabled if(get_magic_quotes_gpc()) $data = stripslashes($data); // a mysqli connection is required before using this function $data = trim(mysqli_real_escape_string($data)); return $data; } However it chucks all sorts of errors: Warning: mysql_query(): Access denied for user 'www-data'@'localhost' (using password: NO) in /home/count/Workspace/lib/classes/user.php on line 7 Warning: mysql_query(): A link to the server could not be established in /home/count/Workspace/lib/classes/user.php on line 7 Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/count/Workspace/lib/classes/user.php on line 8 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, object given in /home/count/Workspace/lib/classes/database.php on line 31

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  • Include a tpl file with variables (Smarty)

    - by user1640660
    I have a "links.tpl" file which contains lines with many variables such as below {assign var=link_main value="index.php"} {assign var=link_login value="?a=login"} but when i include this file in home.tpl using {include file="file.tpl"} the variables {$link_main}, {$link_login} are not included i put the {assign var=link_main value="index.php"} in home.tpl and it works but not from included file i have tried adding scope=global to variable and parent to include but nothing happened I tried the last few hours finding a solution, any help is appreciated

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  • Looking for example projects and "how to create" VB6 Active X EXE's

    - by Clay Nichols
    I'm learning how to create an VB6 Active X EXE. (I need to add the ability for a number of VB6 apps to "phone home" to a server and I'd like centralize this but don't want to do it with a DLL because I'd like to only need Firewall permission for one program (the "phone home ActiveX EXE). I've found a few tutorials but I'm looking for a downloadable project to "play around with".

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  • Add if else function in Ajax Jquery function

    - by Naga Botak
    Is it possible to add other else function in my JS like this: ? if response == success redirect to home if response == failed redirect to failed $.ajax({ type: "POST", url: action, data: form_data, success: function(response) { if(response == 'success') window.location.replace("home"); else $("#message").html("<div class='error_log'><p class='error'>Invalid username and/or password.</p></div>"); } });

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  • Dynamic menu items (change text on click)

    - by Mathijs Delva
    Hello, i need some help with a menu. See the following menu: menu The code for this menu: <div id="menu"> <ul> <li class="home"><a href="#home" class="panel">home / <span class="go">you are here</span></a></li> <li class="about"><a href="#about" class="panel">about / <span class="go">go here</span></a></li> <li class="cases"><a href="#cases" class="panel">cases / <span class="go">go there</span></a></li> <li class="photos"><a href="#photos" class="panel">photos / <span class="go">maybe here</span></a></li> <li class="contact"><a href="#contact" class="panel">contact / <span class="go">or even here<span></span></a></li> </ul> </div> What i want to do: onclick a menu item: 1. change the red text to yellow 'you are here' 2. change the previous menu item back to its original state (eg red and "go here"). The 4 values "go here", "go there", "maybe here", "or even here" are the 4 values that should be assigned to the other menu items (like the example). This is the code i already have: $('#menu ul li.home').addClass('active') $('#menu ul li.active a .go').html("you are here"); $("#menu ul li").click(function () { $('#menu ul li.active').removeClass('active'); $(this).addClass('active'); $('#menu ul li.active a .go').html("you are here"); }); var arr = [ "go here", "go there", "maybe here", "or even here" ]; var obj = { item1: "go here", item2: "go there" ,item3: "maybe here", item4: "or even here"}; $('#menu ul li').click(function () { var str = $('#menu ul li.active a .go').text(); $('#menu ul li.active a .go').html(str); }); As you see, it's incomplete. I don't how to get the values from the array and assign them too a menu item. The replace text works, but not the change-back-to-original-state. Also, right now, for some reason i can't click ONTO the list item itself in order to activate the jquery code. I need to click just a few pixels under it. But i guess that's a css issue. If anyone can help, i'd be super thankful! Regards, Mathijs

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  • How to post data from user control - asp.net mvc

    - by Dharmesh
    Currently i am working on project in which login user control is there in master page. earlier i had seperate login.aspx page and was able to call login method of home controller (with acceptverb = post). now we have changed the idea, want to place login control on master page (home page). Now when i click on login button of login control - it calls login method of controller class with acceptver = get. how can i call login method with acceptverb = post?

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  • Problem carrying Session over to other pages

    - by AAA
    I am able to login a user, but while processing to the next page (memebers area) I can't display any user info let alone print the $_SESSION[email]. I am not sure what's up. Below is the login code and the testing members are page. Login page: session_start(); //also in a real app you would get the id dynamically $sql = "select `email`, `password` from `accounts` where `email` = '$_POST[email]'"; $query = mysql_query($sql) or die ("Error: ".mysql_error()); while ($row = mysql_fetch_array($query)){ $email = $row['email']; $secret = $row['password']; //we will echo these into the proper fields } mysql_free_result($query); // Process the POST variables $email = $_POST["email"]; //Variables $_SESSION["email"] = $_POST["email"]; $secret = $info['password']; //Checks if there is a login cookie if(isset($_COOKIE['ID_my_site'])) //if there is, it logs you in and directes you to the members page { $email = $_COOKIE['ID_my_site']; $pass = $_COOKIE['Key_my_site']; $check = mysql_query("SELECT email, password FROM accounts WHERE email = '$email'")or die(mysql_error()); while($info = mysql_fetch_array( $check )) { if (@ $info['password'] != $pass) { } else { header("Location: home.php"); } } } //if the login form is submitted if (isset($_POST['submit'])) { // if form has been submitted // makes sure they filled it in if(!$_POST['email'] | !$_POST['password']) { die('You did not fill in a required field.'); } // checks it against the database if (!get_magic_quotes_gpc()) { $_POST['email'] = addslashes($_POST['email']); } $check = mysql_query("SELECT email,password FROM accounts WHERE email = '".$_POST['email']."'")or die(mysql_error()); //Gives error if user dosen't exist $check2 = mysql_num_rows($check); if ($check2 == 0) { die('That user does not exist in our database. <a href=add.php>Click Here to Register</a>'); } while($info = mysql_fetch_array( $check )) //gives error if the password is wrong if (@ $_POST['password'] != $info['password']) { die('Incorrect password, please try again'); } else { // if login is ok then we add a cookie $_POST['email'] = stripslashes($_POST['email']); $hour = time() + 3600; setcookie(ID_my_site, $_POST['email'], $hour); setcookie(Key_my_site, $_POST['password'], $hour); //then redirect them to the members area header("Location: home.php"); } } } else { // if they are not logged in ?> <?php } ?> home.php session_start(); if(!isset($_SESSION['email'])) { header('Location: login_test3.php'); die('<a href="login_test3.php">Login first!</a>'); } //Variables $_SESSION["email"] = $email; print $_SESSION['name']; UPDATE Just realized the existing code gets in to the home.php file but will not echo anything. But as soon as you hit refresh the session is gone.

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  • Git as a backup and Version Control System.

    - by gitnoob
    Hi. I want to use Git to backup my home drive, but I also want to use it as a version control system for projects that will be stored in my home drive. How would I go about doing that? Do I .gitignore all the projects root folders and make new repositories for them?

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  • jquery stupid error

    - by user276640
    here is url http://mrhome.ru/Home/MenuPageContent/41?q=??&pid=39 if click search, it not work (quess it because of param q) but on url http://mrhome.ru/Home/main search is work what the problem?

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  • How to fix the open_basedir restriction error?

    - by streetparade
    Hy I have a script called dataface, on a shared host it outputs all the time this warning Warning: file_exists() [function.file-exists]: open_basedir restriction in effect. File(/usr/local/lib/php/Dataface/FormTool/text.php) is not within the allowed path(s): (/home/:/usr/lib/php:/tmp) in /home/a4385243/public_html/dataface/Dataface/FormTool.php on line 654 How can i fix this ?

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  • How to disable current page links in ASP.NET MVC?

    - by rem
    I'm investigating ASP.NET MVC now and noticed that in ASP.NET MVC application, which is created by Visual Studio by default, links "Home" and "About" are staying active when the user is on "Home" and "About" page correspondingly, and after clicking on the current page link page is reloading itself. What is the correct approach to disable link which points to the page, a user is already on? How to do it without violating ASP.NET MVC approach?

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  • iframe creating display problem in ie

    - by jules
    I have just created my first website and am having a problem since adding an iframe to the front page. My home page used to be centered but now it aligns on the left in IE. It displays fine in Firefox, Safari, Opera etc http://www.bignoisechorus.co.uk/home Any ideas?

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  • Run a shell command from Django

    - by Badifunky
    Hello, I'm developing a web page in Django (using apache server) that needs to call a shell command to enable/dissable some daemons. I'm try to do it with os.system(service httpd restart 1>$HOME/out 2>$HOME/error) and this command doesn't return anything. Any idea how can i fix this?

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  • style a navigation link when a particular div is shown

    - by Matt Meadows
    I have JQuery working to show a particular div when a certain link is clicked. I have managed to apply the effect I'm after with the main navigation bar through id'ing the body tag and using css to style when the id is found. However, i'd like to apply the same effect to the sub navigation when a certain div is present. How the main navigation is styled: HTML: <nav> <ul> <li id="nav-home"><a href="index.html">Home</a></li> <li id="nav-showreel"><a href="showreel.html">Showreel</a></li> <li id="nav-portfolio"><a href="portfolio.html">Portfolio</a></li> <li>Contact</li> </ul> </nav> CSS: body#home li#nav-home, body#portfolio li#nav-portfolio { background: url("Images/Nav_Underline.png") no-repeat; background-position: center bottom; color: white; } (Other links havent been added to styling as those pages are still in development) How the sub navigation is structured: <nav id="portfolioNav"> <ul> <li id="portfolio-compositing"><a id="compositingWork" href="#">Compositing</a></li> <li id="portfolio-animation"><a id="animationWork" href="#">Animation</a></li> <li id="portfolio-motionGfx"><a id="GFXWork" href="#">Motion Graphics</a></li> <li id="portfolio-3D"><a id="3DWork" href="#">3D</a></li> </ul> </nav> As you can see, its similar format to the main navigation, however i've tried the same approach and it doesn't work :( The Javascript that switches the divs on the navigation click: <script type="text/javascript"> $(document).ready(function() { $('#3DWork').click(function(){ $('#portfolioWork').load('portfolioContent.html #Portfolio3D'); }); $('#GFXWork').click(function(){ $('#portfolioWork').load('portfolioContent.html #motionGraphics'); }); $('#compositingWork').click(function(){ $('#portfolioWork').load('portfolioContent.html #PortfolioCompositing'); }); $('#animationWork').click(function(){ $('#portfolioWork').load('portfolioContent.html #PortfolioAnimation'); }); }); </script> JSFiddle for full HTML & CSS : JSFiddle File The effect I'm After:

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  • Oracle 9i installation problem

    - by newb
    I can not set my oracle home name "OraHome92". Everytime I do it the destination path is changed to "E:\oracle\ora92" but I am instructed to install "D:\oracle\ora92". How can I sove this problem? FYI Facing this problem I installed the oracle with the home name OraHome9. And installl was successful. But after that when started to upgrde to Oracle 9i (9.2.0.6), it was unsuccessful. Waiting for your reply

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  • Stack overflow in OCaml and F# but not in Haskell

    - by Fernand Pajot
    I've been comparing for fun different languages for speed in execution of the following program: for i from 1 to 1000000 sum the product i*(sqrt i) One of my implementations (not the only one) is constructing a list [1..1000000] and then folding with a specific funtion. The program works fine and fast in Haskell (even when using foldl and not foldl') but stack overflows in OCaml and F#. Here is the Haskell code: test = foldl (\ a b -> a + b * (sqrt b)) 0 create 0 = [] create n = n:(create (n-1)) main = print (test (create 1000000)) And here is the OCaml one: let test = List.fold_left (fun a b -> a +. (float_of_int b) *. (sqrt (float_of_int b))) 0. ;; let rec create = function | 0 -> [] | n -> n::(create (n-1)) ;; print_float (test (create 1000000));; Why does the OCaml/F# implementation stack overflows?

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