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  • How do I use a contact's photo in a table view cell?

    - by Andy
    I've got an app that has a table view that displays contact information in each row. I'd like to use the contact's stored image (if there is one available) as the image on the left-hand side of the cell. I've found some sketchy sample code in Apple's documentation, but the address book references some kind of weird data type (CFDataRef) that doesn't appear to correspond to the data types referenced in the table view programming guide (mainly UIImage). This seems like a pretty basic task, but I can't seem to wrap my head around it. Thanks in advance for any help you can offer.

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  • How to put Custom View above built in views in Android?

    - by Lord.F
    Hi All, I am developing a small app for Android. I am creating my own view. I am planning to design the layout to be: <LinearLayout> <MyView> <Button><Button> </LinearLayout> But when I run my program, my custom view will cover the whole screen. Is there anyway to avoid this? I have already tried to add android:layout_width, layout_height to be wrap_content, fill_partent, but no luck.

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  • How to read a complex view model on POST?

    - by Interfector
    Hello, I have an user view model that has the following properties: public User user; public List<Language> Languages; I send the above model to the view and use html helpers to build the form, so I end up with something like: <form action="/Users/Edit/5" method="post"><input id="user_UserId" name="user.UserId" type="hidden" value="5" /> First Name Last Name Email Language - en en Now, I try to read the POST in something that initially was something like : [AcceptVerbs( HttpVerbs.Post )] public ActionResult Edit( int UserId, FormCollection form ) { and cannot get the user.UserId variable, user.FirstName variable etc. Any idea what needs to be done to be able to read this kind of POST request. I'm kind of reluctant to modifying my ViewModel as it is very simple and easy to maintain as it is. Thank you.

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  • How can I embed a flash movie in a zend view programmatically?

    - by curro
    I have tried to embed a flash movie in a zend view using the htmlFlash helper. In theory you only have to pass the movie path to the htmlFlash helper in a phtml view: echo $this-htmlFlash('/path/to/myMovie.swf'); And the framework will generate the html code in the html page: <object data="/path/to/flash.swf" type="application/x-shockwave-flash" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" codebase="http://download.macromedia.com/pub/shockwave/cabs/flash/swflash.cab"> </object> However, I have done so and the code doesn't appear on the source code. Has anyone had this problem? Thank you

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  • How can I construct this file tree based on what files the user is allowed to view?

    - by robert
    I have an array of files that looks like this: Array ( [0] => Array ( [type] => folder [path] => RootFolder ) [1] => Array ( [type] => file [path] => RootFolder\error.log ) [2] => Array ( [type] => folder [path] => RootFolder\test ) [3] => Array ( [type] => file [path] => RootFolder\test\asd.txt ) [4] => Array ( [type] => folder [path] => RootFolder\test\sd ) [5] => Array ( [type] => file [path] => RootFolder\test\sd\testing.txt ) ) I parse this array and create a tree like view based on the depth of the files ('/' count). It looks like this: RootFolder - error.log - test - asd.txt - sd - testing.txt What I have now is an array of filepaths the user is allowed to view. I need to take this array into account when constructing the above tree. That array looks like this: Array ( [0] => Array ( [filePath] => RootFolder\test\sd ) [1] => Array ( [filePath] => RootFolder\error.log ) ) It would be easy to do a if in_array($path, $allowed) but that won't give me the tree. Just a list of files... Another part I'm stumped on is this requirement: If the user has access to view the folder test, they then have access to all children of that folder. My idea was to simply parse the filepaths. For example, I'd confirm that RootFolder\test\sd was a directory and then create a tree based on the '/' count. Like I was doing earlier. Then, since this is a directory, I'd pull out all files within this directory and show them to the user. However, I'm having trouble converting this to working code... Any ideas?

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  • Get the value of a selected java field in a eclipse view.

    - by user325489
    Hi, I making a eclipse view that is working with selected elements from other views. Let say I have opened a java file in the editor that has the following fields in it: private String world = " world!" private String hello = "hello" + world; When I select "hello" in the Outline view I'm able to get IFiled selection and I have access to it's properties, but what i need is the true value of the field ("hello world!"). Any idea how can I do that? Thanks.

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  • How do I show a custom UIImagePicker within a view?

    - by cory ginsberg
    I'm making an app that involves a 'mirror.' Basically, the view should show the UIImagePickerControllerCameraDeviceFront with a custom border around it that I would create. I have looked around the web for days and I can only find a way of putting a subview on the camera view, I want it to be the opposite way. I have seen this happen before, but I have no idea as how to do it as it appears that UIImagePickerController must be a superview and can't be a subview. Please help me anyway you can and thank you in advanced.

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  • How do I put logic in a View a scope or method in a Model?

    - by Angela
    I have the following in the view: <% unless contact_email.statuses.empty?%> (<%= contact_email.statuses.find(:last).status%>) <% end %> contact_email is an instance of a specific model. Could I do something like this? class ContactEmail < ActiveRecord::Base attr_accessible :contact_id, :email_id, :status, :subject, :body, :date_created, :date_sent def status unless contact_email.statuses.empty? contact_email.statuses.find(:last).status end end end is there a better way to do this? is there a way to use the || operator for a default if empty? Basically, I would like to be able to do the following in the View: <%= contact_email.status = IF there is a value, then display it, if not, show nothing.

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  • iOS sdk question: how do I cast a UIView to a UIImage View (alternativly how do I get a UIImageView from a GestureRecognzer?)

    - by user439299
    Desired end result: user taps a UIImageView and the image changes to another image (a subsequent tap returns the image to the original state) Problem: I add a (unique) selector to a bunch of UIImageViews (in an array) and point the action at the same function - let's call this function imageTapped: for now. Here is my code so far: -(void)imageTapped:(UITapGestureRecognizer *)tapGesture { UIImageView *view = tapGesture.view; // rest of code... } This code actually works fine but gets a warning when I run it: "Incompatible objective c types initilizing 'struct UIView *', expected 'struct UIImageView *' Any way to get rid of this? Not sure how casting works in objective c... primitive types seem to work fine such as (int)someFloat works fine but (UIImageView)someUiView doesn't work. Like I said, code works alright when I run it but would like to get ride of the compiler warning. Any help would be awesome.... I am very new to objective c (or any non java language for that matter) so be gentle. Thanks in advance.

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  • How to connect Model through Controller to View using bindings?

    - by Paperflyer
    I have an NSTextField in my view. Its value is bound to an NSNumber *number in my controller. The controller simply calls through to the model (value) to get the appropriate value. // In the controller - (NSNumber *)number { return [NSNumber numberWithFloat:[model value]]; } - (void)setNumber:(NSNumber *)aNumber { [model setValue:[aNumber floatValue]]; } This is fine, only the controller is not notified of model changes and thus, changing the value in the model does not update the NSTextField. The only other option I can think of is to have the model notify the controller and the controller manually update the view through an Outlet. But this circumvents the binding. // In the model, after value change [[NSNotificationCenter defaultCenter] postNotificationName:@"ValueChanged" object:self]; // In the controller, after being notified - (void)updateView:(NSNotification *)aNotification { [myTextField setFloatValue:[model value]]; } Is there a better, binding-aware way to implement this communication?

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  • An efficient way to store view counts for objects?

    - by Nick Brooks
    I maintain an application where users are able to store images, and then share them. The system is powered by MongoDB at the back end. Most of the image depiction pages are cached as flat HTML files, but I can run some code just before loading the file. I've decided to implement a view count for the system. I am wondering what is the best storage place for that. It should be like Memcached but it should save the viewcounts every hour or so, so even if our server has to be restarted we won't lose the view counts. What is the best solution for that (preferably with a PHP extension as a client)?

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  • Rails show view of one model with form for adding one child - nested attributes vs seperate controll

    - by SWR
    I have a basic two tiered model structure: Articles - Comments with one Article having many comments. What is the best way to add a "Add a comment" form to the bottom of the Articles show page? nested_attributes is overkill as I don't want to be able to edit all of the comments on the page, just to add one more. Is the best way even with Rails 2.3 still to make a separate controller and embed a form_for pointing to the other controller into the Articles show view? If so, how do I get validation errors to return to the article display page? I don't want to make a separate comment page/view... thanks

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  • iPhone: increasing size of view frame in a UItabbarcontroller?

    - by dpigera
    I currently have a UITabBarController defined, with the tab bar moved a few pixels down to make it thinner: self.tabBarController = [[UITabBarController alloc] init]; self.tabBarController.tabBar.frame=CGRectMake(0,self.window.bounds.size.height-38.5,self.window.bounds.size.width,50); [self.window addSubview:self.tabBarController.view]; I then have a UIViewController object assigned to the first tab using: Home *home = [[Home alloc] initWithNibName:@"Home" bundle:nil]; UINavigationController *nHome = [[UINavigationController alloc] initWithRootViewController:home]; nHome.tabBarItem.image=[UIImage imageNamed:@"home.png"]; [tabBarController setViewControllers:[NSArray arrayWithObjects:nHome,nil]]; As a result, there is a thin sliver of space between the tabbarcontroller and the view. Can someone please tell me how I can get rid of this space?

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  • how i insert values from list of Data Grid View,current time ,EmployeeID using button click event (C

    - by Six fourty
    hi, it show me this error Incorrect syntax near the keyword 'Select' to make to clear Employee ID in this case is FK in the table (Attendance detail) and the other thing is i am using Data Grid View from another table(Employee information) to Show the list of the staff in my form. then i want to transfer each selected cell value from Data Grid View to attendance detail table. 10q private void time_in_Click(object sender, EventArgs e) { employee_InformationDataGridView.SelectedCells[0].Style.ForeColor = Color.Green; time_in.Enabled = false; time_out.Enabled = true; con = new SqlConnection(GlobalClass.conn); con.Open(); SqlCommand cmd = new SqlCommand("Insert into Attendancedetail Values(" + "Select from EmployeeInformation(EmployeeID)" + ",'" + employee_InformationDataGridView.SelectedCells[0] + "','" + DateTime.Now.ToLongDateString() + "','" + null + "','" + null + "','" + DateTime.Now.ToLongTimeString() + "'," + null + ")", con); int i = cmd.ExecuteNonQuery(); MessageBox.Show(i.ToString() + " record inserted"); }

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  • Android - How can I access a View object instantiated in onCreate in onResume?

    - by Chris
    In my onCreate() method, I'm instantiating an ImageButton View: public void onCreate(Bundle savedInstanceState) { Log.d(AntengoApplication.LOG_TAG, "BrowsePicture onCreate"); super.onCreate(savedInstanceState); setContentView(R.layout.layout_post); final ImageButton ib = (ImageButton) findViewById(R.id.post_image); ... In onResume, I want to be able to change the properties of the ImageButton with something like: @Override protected void onResume() { super.onResume(); ib.setImageURI(selectedImageUri); } //END onResume But onResume doesn't have access to the ib ImageButton object. If this were a variable, I'd simple make it a class variable, but Android does not allow you to define View object in the class. Any suggestions on how to do this?

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  • How to increase Size of PhotoLibrary View in iPad?

    - by Shreedhar
    Folwing code is to pop photoLibrary videoPicker = [[UIImagePickerController alloc] init]; videoPicker.delegate = self; videoPicker.sourceType = UIImagePickerControllerSourceTypePhotoLibrary; videoPicker.mediaTypes = [NSArray arrayWithObjects:(NSString *) kUTTypeImage,(NSString *)kUTTypeMovie,nil]; videoPicker.allowsEditing = YES;; pop = [[UIPopoverController alloc]initWithContentViewController:videoPicker]; pop.popoverContentSize = CGSizeMake(500, 900); [pop setDelegate:self]; [pop presentPopoverFromRect:[sender frame] inView:self.view permittedArrowDirections:UIPopoverArrowDirectionDown animated:YES]; [videoPicker release]; How to increase the photoLibrary view(width X height) on pop?

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  • How do you pass objects between View Controllers in Objective-C?

    - by editor
    I've been trudging through some code for two days trying to figure out why I couldn't fetch a global NSMutableArray variable I declared in the .h and implemented in .m and set in a the viewDidLoad function. It finally dawned on me: there's no such thing as a global variable in Objective-C, at least not in the PHP sense I've come to know. I didn't ever really read the XCode error warnings, but there it was, even if not quite plain English: "Instance variable 'blah' accessed in class method." My question: What am I supposed to do now? I've got two View Controllers that need to access a central NSMutableDictionary I generate from a JSON file via URL. It's basically an extended menu for all my Table View drill downs, and I'd like to have couple other "global" (non-static) variables. Do I have to grab the JSON each time I want to generate this NSMutableDictionary or is there some way to set it once and access it from various classes via #import? Do I have to write data to a file, or is there another way people usually do this?

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  • Can I insert a style tag and contents from a view with CakePHP?

    - by Richard
    From what I can see, CakePHP makes it easy to link to a CSS file in a view with the following: echo $html->css('my-css-filename',null,array(),FALSE); But what if I don't want to exclusively use hardcoded files? How can I get it to create a style tag with some dynamically generated rules in e.g. <style type="text/css" media="all">p {font-size:1.5em}</style> I am trying to do this in a view file, I'd like the CSS to be placed in the head tag, and I'm using CakePHP 1.2.7

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  • What type of data should I send to view?

    - by Vizualni
    Hello, this question I've been asking myself since the day I started programming in MVC way. Should I send to view arrays filled with data or should I send it as on objects I retrieved from database? My model returns me data as objects. What would be the best way to create such a thing? $new_data = $model->find_by_id(1); echo $new_data->name; $new_data->name= "whatever"; $new_data->save(); For example. view.php echo $object->name; or echo $array['name'] Language is php :).

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  • Add a multiple buttons to a view programatically, call the same method, determine which button it wa

    - by just_another_coder
    I want to programatically add multiple UIButtons to a view - the number of buttons is unknown at compile time. I can make one or more UIButton's like so (in a loop, but shorted for simplicity): UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect]; [button addTarget:self action:@selector(buttonClicked:) forControlEvents:UIControlEventTouchDown]; [button setTitle:@"Button x" forState:UIControlStateNormal]; button.frame = CGRectMake(100.0, 100.0, 120.0, 50.0); [view addSubview:button]; Copied/Edited from this link: http://stackoverflow.com/questions/1378765/how-do-i-create-a-basic-uibutton-programmatically But how do I determine in buttonClicked: which button was clicked? I'd like to pass tag data if possible to identify the button.

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  • Developing web apps using ASP.NET MVC 3, Razor and EF Code First - Part 1

    - by shiju
    In this post, I will demonstrate web application development using ASP. NET MVC 3, Razor and EF code First. This post will also cover Dependency Injection using Unity 2.0 and generic Repository and Unit of Work for EF Code First. The following frameworks will be used for this step by step tutorial. ASP.NET MVC 3 EF Code First CTP 5 Unity 2.0 Define Domain Model Let’s create domain model for our simple web application Category class public class Category {     public int CategoryId { get; set; }     [Required(ErrorMessage = "Name Required")]     [StringLength(25, ErrorMessage = "Must be less than 25 characters")]     public string Name { get; set;}     public string Description { get; set; }     public virtual ICollection<Expense> Expenses { get; set; } }   Expense class public class Expense {             public int ExpenseId { get; set; }            public string  Transaction { get; set; }     public DateTime Date { get; set; }     public double Amount { get; set; }     public int CategoryId { get; set; }     public virtual Category Category { get; set; } } We have two domain entities - Category and Expense. A single category contains a list of expense transactions and every expense transaction should have a Category. In this post, we will be focusing on CRUD operations for the entity Category and will be working on the Expense entity with a View Model object in the later post. And the source code for this application will be refactored over time. The above entities are very simple POCO (Plain Old CLR Object) classes and the entity Category is decorated with validation attributes in the System.ComponentModel.DataAnnotations namespace. Now we want to use these entities for defining model objects for the Entity Framework 4. Using the Code First approach of Entity Framework, we can first define the entities by simply writing POCO classes without any coupling with any API or database library. This approach lets you focus on domain model which will enable Domain-Driven Development for applications. EF code first support is currently enabled with a separate API that is runs on top of the Entity Framework 4. EF Code First is reached CTP 5 when I am writing this article. Creating Context Class for Entity Framework We have created our domain model and let’s create a class in order to working with Entity Framework Code First. For this, you have to download EF Code First CTP 5 and add reference to the assembly EntitFramework.dll. You can also use NuGet to download add reference to EEF Code First.    public class MyFinanceContext : DbContext {     public MyFinanceContext() : base("MyFinance") { }     public DbSet<Category> Categories { get; set; }     public DbSet<Expense> Expenses { get; set; }         }   The above class MyFinanceContext is derived from DbContext that can connect your model classes to a database. The MyFinanceContext class is mapping our Category and Expense class into database tables Categories and Expenses using DbSet<TEntity> where TEntity is any POCO class. When we are running the application at first time, it will automatically create the database. EF code-first look for a connection string in web.config or app.config that has the same name as the dbcontext class. If it is not find any connection string with the convention, it will automatically create database in local SQL Express database by default and the name of the database will be same name as the dbcontext class. You can also define the name of database in constructor of the the dbcontext class. Unlike NHibernate, we don’t have to use any XML based mapping files or Fluent interface for mapping between our model and database. The model classes of Code First are working on the basis of conventions and we can also use a fluent API to refine our model. The convention for primary key is ‘Id’ or ‘<class name>Id’.  If primary key properties are detected with type ‘int’, ‘long’ or ‘short’, they will automatically registered as identity columns in the database by default. Primary key detection is not case sensitive. We can define our model classes with validation attributes in the System.ComponentModel.DataAnnotations namespace and it automatically enforces validation rules when a model object is updated or saved. Generic Repository for EF Code First We have created model classes and dbcontext class. Now we have to create generic repository pattern for data persistence with EF code first. If you don’t know about the repository pattern, checkout Martin Fowler’s article on Repository Let’s create a generic repository to working with DbContext and DbSet generics. public interface IRepository<T> where T : class     {         void Add(T entity);         void Delete(T entity);         T GetById(long Id);         IEnumerable<T> All();     }   RepositoryBasse – Generic Repository class public abstract class RepositoryBase<T> where T : class { private MyFinanceContext database; private readonly IDbSet<T> dbset; protected RepositoryBase(IDatabaseFactory databaseFactory) {     DatabaseFactory = databaseFactory;     dbset = Database.Set<T>(); }   protected IDatabaseFactory DatabaseFactory {     get; private set; }   protected MyFinanceContext Database {     get { return database ?? (database = DatabaseFactory.Get()); } } public virtual void Add(T entity) {     dbset.Add(entity);            }        public virtual void Delete(T entity) {     dbset.Remove(entity); }   public virtual T GetById(long id) {     return dbset.Find(id); }   public virtual IEnumerable<T> All() {     return dbset.ToList(); } }   DatabaseFactory class public class DatabaseFactory : Disposable, IDatabaseFactory {     private MyFinanceContext database;     public MyFinanceContext Get()     {         return database ?? (database = new MyFinanceContext());     }     protected override void DisposeCore()     {         if (database != null)             database.Dispose();     } } Unit of Work If you are new to Unit of Work pattern, checkout Fowler’s article on Unit of Work . According to Martin Fowler, the Unit of Work pattern "maintains a list of objects affected by a business transaction and coordinates the writing out of changes and the resolution of concurrency problems." Let’s create a class for handling Unit of Work   public interface IUnitOfWork {     void Commit(); }   UniOfWork class public class UnitOfWork : IUnitOfWork {     private readonly IDatabaseFactory databaseFactory;     private MyFinanceContext dataContext;       public UnitOfWork(IDatabaseFactory databaseFactory)     {         this.databaseFactory = databaseFactory;     }       protected MyFinanceContext DataContext     {         get { return dataContext ?? (dataContext = databaseFactory.Get()); }     }       public void Commit()     {         DataContext.Commit();     } }   The Commit method of the UnitOfWork will call the commit method of MyFinanceContext class and it will execute the SaveChanges method of DbContext class.   Repository class for Category In this post, we will be focusing on the persistence against Category entity and will working on other entities in later post. Let’s create a repository for handling CRUD operations for Category using derive from a generic Repository RepositoryBase<T>.   public class CategoryRepository: RepositoryBase<Category>, ICategoryRepository     {     public CategoryRepository(IDatabaseFactory databaseFactory)         : base(databaseFactory)         {         }                } public interface ICategoryRepository : IRepository<Category> { } If we need additional methods than generic repository for the Category, we can define in the CategoryRepository. Dependency Injection using Unity 2.0 If you are new to Inversion of Control/ Dependency Injection or Unity, please have a look on my articles at http://weblogs.asp.net/shijuvarghese/archive/tags/IoC/default.aspx. I want to create a custom lifetime manager for Unity to store container in the current HttpContext.   public class HttpContextLifetimeManager<T> : LifetimeManager, IDisposable {     public override object GetValue()     {         return HttpContext.Current.Items[typeof(T).AssemblyQualifiedName];     }     public override void RemoveValue()     {         HttpContext.Current.Items.Remove(typeof(T).AssemblyQualifiedName);     }     public override void SetValue(object newValue)     {         HttpContext.Current.Items[typeof(T).AssemblyQualifiedName] = newValue;     }     public void Dispose()     {         RemoveValue();     } }   Let’s create controller factory for Unity in the ASP.NET MVC 3 application. public class UnityControllerFactory : DefaultControllerFactory { IUnityContainer container; public UnityControllerFactory(IUnityContainer container) {     this.container = container; } protected override IController GetControllerInstance(RequestContext reqContext, Type controllerType) {     IController controller;     if (controllerType == null)         throw new HttpException(                 404, String.Format(                     "The controller for path '{0}' could not be found" +     "or it does not implement IController.",                 reqContext.HttpContext.Request.Path));       if (!typeof(IController).IsAssignableFrom(controllerType))         throw new ArgumentException(                 string.Format(                     "Type requested is not a controller: {0}",                     controllerType.Name),                     "controllerType");     try     {         controller= container.Resolve(controllerType) as IController;     }     catch (Exception ex)     {         throw new InvalidOperationException(String.Format(                                 "Error resolving controller {0}",                                 controllerType.Name), ex);     }     return controller; }   }   Configure contract and concrete types in Unity Let’s configure our contract and concrete types in Unity for resolving our dependencies.   private void ConfigureUnity() {     //Create UnityContainer               IUnityContainer container = new UnityContainer()                 .RegisterType<IDatabaseFactory, DatabaseFactory>(new HttpContextLifetimeManager<IDatabaseFactory>())     .RegisterType<IUnitOfWork, UnitOfWork>(new HttpContextLifetimeManager<IUnitOfWork>())     .RegisterType<ICategoryRepository, CategoryRepository>(new HttpContextLifetimeManager<ICategoryRepository>());                 //Set container for Controller Factory                ControllerBuilder.Current.SetControllerFactory(             new UnityControllerFactory(container)); }   In the above ConfigureUnity method, we are registering our types onto Unity container with custom lifetime manager HttpContextLifetimeManager. Let’s call ConfigureUnity method in the Global.asax.cs for set controller factory for Unity and configuring the types with Unity.   protected void Application_Start() {     AreaRegistration.RegisterAllAreas();     RegisterGlobalFilters(GlobalFilters.Filters);     RegisterRoutes(RouteTable.Routes);     ConfigureUnity(); }   Developing web application using ASP.NET MVC 3 We have created our domain model for our web application and also have created repositories and configured dependencies with Unity container. Now we have to create controller classes and views for doing CRUD operations against the Category entity. Let’s create controller class for Category Category Controller   public class CategoryController : Controller {     private readonly ICategoryRepository categoryRepository;     private readonly IUnitOfWork unitOfWork;           public CategoryController(ICategoryRepository categoryRepository, IUnitOfWork unitOfWork)     {         this.categoryRepository = categoryRepository;         this.unitOfWork = unitOfWork;     }       public ActionResult Index()     {         var categories = categoryRepository.All();         return View(categories);     }     [HttpGet]     public ActionResult Edit(int id)     {         var category = categoryRepository.GetById(id);         return View(category);     }       [HttpPost]     public ActionResult Edit(int id, FormCollection collection)     {         var category = categoryRepository.GetById(id);         if (TryUpdateModel(category))         {             unitOfWork.Commit();             return RedirectToAction("Index");         }         else return View(category);                 }       [HttpGet]     public ActionResult Create()     {         var category = new Category();         return View(category);     }           [HttpPost]     public ActionResult Create(Category category)     {         if (!ModelState.IsValid)         {             return View("Create", category);         }                     categoryRepository.Add(category);         unitOfWork.Commit();         return RedirectToAction("Index");     }       [HttpPost]     public ActionResult Delete(int  id)     {         var category = categoryRepository.GetById(id);         categoryRepository.Delete(category);         unitOfWork.Commit();         var categories = categoryRepository.All();         return PartialView("CategoryList", categories);       }        }   Creating Views in Razor Now we are going to create views in Razor for our ASP.NET MVC 3 application.  Let’s create a partial view CategoryList.cshtml for listing category information and providing link for Edit and Delete operations. CategoryList.cshtml @using MyFinance.Helpers; @using MyFinance.Domain; @model IEnumerable<Category>      <table>         <tr>         <th>Actions</th>         <th>Name</th>          <th>Description</th>         </tr>     @foreach (var item in Model) {             <tr>             <td>                 @Html.ActionLink("Edit", "Edit",new { id = item.CategoryId })                 @Ajax.ActionLink("Delete", "Delete", new { id = item.CategoryId }, new AjaxOptions { Confirm = "Delete Expense?", HttpMethod = "Post", UpdateTargetId = "divCategoryList" })                           </td>             <td>                 @item.Name             </td>             <td>                 @item.Description             </td>         </tr>          }       </table>     <p>         @Html.ActionLink("Create New", "Create")     </p> The delete link is providing Ajax functionality using the Ajax.ActionLink. This will call an Ajax request for Delete action method in the CategoryCotroller class. In the Delete action method, it will return Partial View CategoryList after deleting the record. We are using CategoryList view for the Ajax functionality and also for Index view using for displaying list of category information. Let’s create Index view using partial view CategoryList  Index.chtml @model IEnumerable<MyFinance.Domain.Category> @{     ViewBag.Title = "Index"; }    <h2>Category List</h2>    <script src="@Url.Content("~/Scripts/jquery.unobtrusive-ajax.min.js")" type="text/javascript"></script>    <div id="divCategoryList">               @Html.Partial("CategoryList", Model) </div>   We can call the partial views using Html.Partial helper method. Now we are going to create View pages for insert and update functionality for the Category. Both view pages are sharing common user interface for entering the category information. So I want to create an EditorTemplate for the Category information. We have to create the EditorTemplate with the same name of entity object so that we can refer it on view pages using @Html.EditorFor(model => model) . So let’s create template with name Category. Let’s create view page for insert Category information   @model MyFinance.Domain.Category   @{     ViewBag.Title = "Save"; }   <h2>Create</h2>   <script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script>   @using (Html.BeginForm()) {     @Html.ValidationSummary(true)     <fieldset>         <legend>Category</legend>                @Html.EditorFor(model => model)               <p>             <input type="submit" value="Create" />         </p>     </fieldset> }   <div>     @Html.ActionLink("Back to List", "Index") </div> ViewStart file In Razor views, we can add a file named _viewstart.cshtml in the views directory  and this will be shared among the all views with in the Views directory. The below code in the _viewstart.cshtml, sets the Layout page for every Views in the Views folder.      @{     Layout = "~/Views/Shared/_Layout.cshtml"; }   Source Code You can download the source code from http://efmvc.codeplex.com/ . The source will be refactored on over time.   Summary In this post, we have created a simple web application using ASP.NET MVC 3 and EF Code First. We have discussed on technologies and practices such as ASP.NET MVC 3, Razor, EF Code First, Unity 2, generic Repository and Unit of Work. In my later posts, I will modify the application and will be discussed on more things. Stay tuned to my blog  for more posts on step by step application building.

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  • LLBLGen Pro feature highlights: model views

    - by FransBouma
    (This post is part of a series of posts about features of the LLBLGen Pro system) To be able to work with large(r) models, it's key you can view subsets of these models so you can have a better, more focused look at them. For example because you want to display how a subset of entities relate to one another in a different way than the list of entities. LLBLGen Pro offers this in the form of Model Views. Model Views are views on parts of the entity model of a project, and the subsets are displayed in a graphical way. Additionally, one can add documentation to a Model View. As Model Views are displaying parts of the model in a graphical way, they're easier to explain to people who aren't familiar with entity models, e.g. the stakeholders you're interviewing for your project. The documentation can then be used to communicate specifics of the elements on the model view to the developers who have to write the actual code. Below I've included an example. It's a model view on a subset of the entities of AdventureWorks. It displays several entities, their relationships (both relational and inheritance relationships) and also some specifics gathered from the interview with the stakeholder. As the information is inside the actual project the developer will work with, the information doesn't have to be converted back/from e.g .word documents or other intermediate formats, it's the same project. This makes sure there are less errors / misunderstandings. (of course you can hide the docked documentation pane or dock it to another corner). The Model View can contain entities which are placed in different groups. This makes it ideal to group entities together for close examination even though they're stored in different groups. The Model View is a first-class citizen of the code-generator. This means you can write templates which consume Model Views and generate code accordingly. E.g. you can write a template which generates a service per Model View and exposes the entities in the Model View as a single entity graph, fetched through a method. (This template isn't included in the LLBLGen Pro package, but it's easy to write it up yourself with the built-in template editor). Viewing an entity model in different ways is key to fully understand the entity model and Model Views help with that.

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