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  • How to make a report with count of type of cases in each month in Acess 2010

    - by amir shadaab
    I have a database is access with each record having a date and yes/no type columns for each record which shows which category the record comes under. I want to create a report which shows the types of cases in each month by taking a date range as a parameter through prompts. I have done the prompt part but I'm not sure how the query should be to show values for each month in that date range. Can someone please help me with this?

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  • how do i get name of the month in ruby on Rails?

    - by necker
    so i create in my view: <%=date=Date.today%> How do i get the name of the month out of the date? I was trying to do sth like <%= DATE::ABBR_MONTHNAMES(date.month)%> But without success. I keep getting an error: uninitialized constant ActionView::Base::CompiledTemplates::MONTHNAMES How do i initialise the constant or is there any other way to get the name out of the Date format? would greatly appreciate any answers!

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  • Server load spikes several times a day, load average for the past month is 5 times the load average all year

    - by AMF
    My Munin notifications set up for our (Debian) LAMP cluster have been notifying me continuously that our load on our production machine has been at dangerous levels. While the average load all year typically runs between 2 and 8, the load in the past month and only the past month -- has been skyrocketing to 10, 18, and occasionally even 50-60. The spikes last only 5-10 minutes at a time and occur about every 2-3 hours. The spikes do not effect performance only because I have a script that sends traffic off our server to a mirror CDN when the load goes above 10. I've looked for cron jobs that correlate with this timeframe but there is nothing I can see that would cause this. Site traffic is also normal (we receive about 200K visits per day). I'm also trying to think of anything I've changed around the time this problem began, and I really cannot think of anything. This is probably not much to go on. Maybe there is a clue in the top print-out (below) that I'm not seeing. How do I proceed to find the cause? -- Typical top when the load is NOT spiking: top - 11:13:09 up 472 days, 25 min, 1 user, load average: 6.08, 4.29, 3.80 Tasks: 105 total, 1 running, 104 sleeping, 0 stopped, 0 zombie Cpu(s): 41.2%us, 5.8%sy, 0.0%ni, 49.5%id, 2.7%wa, 0.1%hi, 0.7%si, 0.0%st Mem: 3369592k total, 2166980k used, 1202612k free, 559504k buffers Swap: 2650684k total, 1892k used, 2648792k free, 1129116k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 32046 apache 15 0 36300 12m 9828 S 20 0.4 0:01.97 apache2 32679 apache 15 0 36568 13m 10m S 19 0.4 0:01.69 apache2 31441 apache 15 0 36616 13m 10m S 19 0.4 0:04.13 apache2 31477 apache 15 0 36596 13m 9.8m S 15 0.4 0:01.99 apache2 31993 apache 15 0 36876 16m 12m S 12 0.5 0:02.01 apache2 31782 apache 15 0 36836 14m 10m S 8 0.4 0:02.17 apache2 32198 apache 15 0 36536 13m 10m S 7 0.4 0:01.59 apache2 880 apache 15 0 36508 9708 6236 S 7 0.3 0:00.42 apache2 31945 apache 17 0 36876 16m 13m S 5 0.5 0:03.17 apache2 32197 apache 16 0 36636 10m 7504 S 5 0.3 0:02.70 apache2 32326 apache 15 0 37024 11m 7632 S 5 0.3 0:02.15 apache2 32565 apache 15 0 37280 13m 9.8m S 5 0.4 0:03.75 apache2 32676 apache 15 0 36896 16m 12m S 4 0.5 0:00.95 apache2 32678 apache 15 0 36536 12m 9692 S 4 0.4 0:02.27 apache2 974 apache 16 0 37064 9888 6016 D 4 0.3 0:00.13 apache2 32150 apache 16 0 36832 13m 10m S 3 0.4 0:01.74 apache2 31780 apache 16 0 36848 11m 7660 S 3 0.3 0:02.87 apache2

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  • 4 month old 500 GB SATA HDD making noise?

    - by metal gear solid
    My 4 month old 500 GB SATA HDD making noise sometimes and the PC hangs when it makes noise when the noise stops desktop work fine. It doesn't happen every day but it does happen. Is something wrong with HDD, Data, power cable, or my cabinet's power supply? Should I run scandisk or defragmentation on the disk.

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  • Find out how many DNS Queries/month via WHM or SSH?

    - by Kerry
    Is it possible? We have complete control over our DNS server and the server actually being pointed to. We are interested in how many DNS Queries we are currently getting, as we want to move to Ultra DNS, but we need to know how many queries we're likely to get in a month. Is this possible to figure out? Do I need to start a service before tracking begins? Or use shell to access the data?

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  • How much traffic per month would my site need? [closed]

    - by camran
    HOW MANY GB OF TRAFFIC IS REQUIRED PER MONTH? Any way to calculate this? Webhosting companies have a limit when ordering, so I need to know... A classifieds website using PHP and MYSQL. MYSQL has around 500thousand records. Not much graphics. Pretty advanced search feautures. How much traffic would I need do you think? Thanks

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  • Query to find the data for every month of last year from the given date using mysql?

    - by Salil
    Hi All, I want data for the the last 1 year from the given date For ex:- I have date "2013-06-01" and i want data as follows also data i want is from three table using Group By or something else Month             Amount         Total_Data June 2013     100                5 May 2013       80                  4 -                     100                5 -                     100                5 July 2012       10                  2 I try following query but didn't workout SELECT DATE_FORMAT(rf.period, '%M %Y') as Month , sum(p.amount * ((100-q.amount)/100)) as Amount ,count(distinct q.label_id) as Total Data FROM table1 rf , table2 p , table3 q ,table4 a where rf.period BETWEEN '2013-06-01' AND '2013-06-01' and q.royalty_period BETWEEN '2013-06-01' AND '2013-06-01' and a.id = q.album_id and p.file_id = rf.id and p.upc = a.upc and p.local_revenue is not null GROUP BY Month Thanks in Advance, Salil Gaikwad

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  • Investigation: Can different combinations of components effect Dataflow performance?

    - by jamiet
    Introduction The Dataflow task is one of the core components (if not the core component) of SQL Server Integration Services (SSIS) and often the most misunderstood. This is not surprising, its an incredibly complicated beast and we’re abstracted away from that complexity via some boxes that go yellow red or green and that have some lines drawn between them. Example dataflow In this blog post I intend to look under that facade and get into some of the nuts and bolts of the Dataflow Task by investigating how the decisions we make when building our packages can affect performance. I will do this by comparing the performance of three dataflows that all have the same input, all produce the same output, but which all operate slightly differently by way of having different transformation components. I also want to use this blog post to challenge a common held opinion that I see perpetuated over and over again on the SSIS forum. That is, that people assume adding components to a dataflow will be detrimental to overall performance. Its not surprising that people think this –it is intuitive to think that more components means more work- however this is not a view that I share. I have always been of the opinion that there are many factors affecting dataflow duration and the number of components is actually one of the less important ones; having said that I have never proven that assertion and that is one reason for this investigation. I have actually seen evidence that some people think dataflow duration is simply a function of number of rows and number of components. I’ll happily call that one out as a myth even without any investigation!  The Setup I have a 2GB datafile which is a list of 4731904 (~4.7million) customer records with various attributes against them and it contains 2 columns that I am going to use for categorisation: [YearlyIncome] [BirthDate] The data file is a SSIS raw format file which I chose to use because it is the quickest way of getting data into a dataflow and given that I am testing the transformations, not the source or destination adapters, I want to minimise external influences as much as possible. In the test I will split the customers according to month of birth (12 of those) and whether or not their yearly income is above or below 50000 (2 of those); in other words I will be splitting them into 24 discrete categories and in order to do it I shall be using different combinations of SSIS’ Conditional Split and Derived Column transformation components. The 24 datapaths that occur will each input to a rowcount component, again because this is the least resource intensive means of terminating a datapath. The test is being carried out on a Dell XPS Studio laptop with a quad core (8 logical Procs) Intel Core i7 at 1.73GHz and Samsung SSD hard drive. Its running SQL Server 2008 R2 on Windows 7. The Variables Here are the three combinations of components that I am going to test:     One Conditional Split - A single Conditional Split component CSPL Split by Month of Birth and income category that will use expressions on [YearlyIncome] & [BirthDate] to send each row to one of 24 outputs. This next screenshot displays the expression logic in use: Derived Column & Conditional Split - A Derived Column component DER Income Category that adds a new column [IncomeCategory] which will contain one of two possible text values {“LessThan50000”,”GreaterThan50000”} and uses [YearlyIncome] to determine which value each row should get. A Conditional Split component CSPL Split by Month of Birth and Income Category then uses that new column in conjunction with [BirthDate] to determine which of the same 24 outputs to send each row to. Put more simply, I am separating the Conditional Split of #1 into a Derived Column and a Conditional Split. The next screenshots display the expression logic in use: DER Income Category         CSPL Split by Month of Birth and Income Category       Three Conditional Splits - A Conditional Split component that produces two outputs based on [YearlyIncome], one for each Income Category. Each of those outputs will go to a further Conditional Split that splits the input into 12 outputs, one for each month of birth (identical logic in each). In this case then I am separating the single Conditional Split of #1 into three Conditional Split components. The next screenshots display the expression logic in use: CSPL Split by Income Category         CSPL Split by Month of Birth 1& 2       Each of these combinations will provide an input to one of the 24 rowcount components, just the same as before. For illustration here is a screenshot of the dataflow containing three Conditional Split components: As you can these dataflows have a fair bit of work to do and remember that they’re doing that work for 4.7million rows. I will execute each dataflow 10 times and use the average for comparison. I foresee three possible outcomes: The dataflow containing just one Conditional Split (i.e. #1) will be quicker There is no significant difference between any of them One of the two dataflows containing multiple transformation components will be quicker Regardless of which of those outcomes come to pass we will have learnt something and that makes this an interesting test to carry out. Note that I will be executing the dataflows using dtexec.exe rather than hitting F5 within BIDS. The Results and Analysis The table below shows all of the executions, 10 for each dataflow. It also shows the average for each along with a standard deviation. All durations are in seconds. I’m pasting a screenshot because I frankly can’t be bothered with the faffing about needed to make a presentable HTML table. It is plain to see from the average that the dataflow containing three conditional splits is significantly faster, the other two taking 43% and 52% longer respectively. This seems strange though, right? Why does the dataflow containing the most components outperform the other two by such a big margin? The answer is actually quite logical when you put some thought into it and I’ll explain that below. Before progressing, a side note. The standard deviation for the “Three Conditional Splits” dataflow is orders of magnitude smaller – indicating that performance for this dataflow can be predicted with much greater confidence too. The Explanation I refer you to the screenshot above that shows how CSPL Split by Month of Birth and salary category in the first dataflow is setup. Observe that there is a case for each combination of Month Of Date and Income Category – 24 in total. These expressions get evaluated in the order that they appear and hence if we assume that Month of Date and Income Category are uniformly distributed in the dataset we can deduce that the expected number of expression evaluations for each row is 12.5 i.e. 1 (the minimum) + 24 (the maximum) divided by 2 = 12.5. Now take a look at the screenshots for the second dataflow. We are doing one expression evaluation in DER Income Category and we have the same 24 cases in CSPL Split by Month of Birth and Income Category as we had before, only the expression differs slightly. In this case then we have 1 + 12.5 = 13.5 expected evaluations for each row – that would account for the slightly longer average execution time for this dataflow. Now onto the third dataflow, the quick one. CSPL Split by Income Category does a maximum of 2 expression evaluations thus the expected number of evaluations per row is 1.5. CSPL Split by Month of Birth 1 & CSPL Split by Month of Birth 2 both have less work to do than the previous Conditional Split components because they only have 12 cases to test for thus the expected number of expression evaluations is 6.5 There are two of them so total expected number of expression evaluations for this dataflow is 6.5 + 6.5 + 1.5 = 14.5. 14.5 is still more than 12.5 & 13.5 though so why is the third dataflow so much quicker? Simple, the conditional expressions in the first two dataflows have two boolean predicates to evaluate – one for Income Category and one for Month of Birth; the expressions in the Conditional Split in the third dataflow however only have one predicate thus they are doing a lot less work. To sum up, the difference in execution times can be attributed to the difference between: MONTH(BirthDate) == 1 && YearlyIncome <= 50000 and MONTH(BirthDate) == 1 In the first two dataflows YearlyIncome <= 50000 gets evaluated an average of 12.5 times for every row whereas in the third dataflow it is evaluated once and once only. Multiply those 11.5 extra operations by 4.7million rows and you get a significant amount of extra CPU cycles – that’s where our duration difference comes from. The Wrap-up The obvious point here is that adding new components to a dataflow isn’t necessarily going to make it go any slower, moreover you may be able to achieve significant improvements by splitting logic over multiple components rather than one. Performance tuning is all about reducing the amount of work that needs to be done and that doesn’t necessarily mean use less components, indeed sometimes you may be able to reduce workload in ways that aren’t immediately obvious as I think I have proven here. Of course there are many variables in play here and your mileage will most definitely vary. I encourage you to download the package and see if you get similar results – let me know in the comments. The package contains all three dataflows plus a fourth dataflow that will create the 2GB raw file for you (you will also need the [AdventureWorksDW2008] sample database from which to source the data); simply disable all dataflows except the one you want to test before executing the package and remember, execute using dtexec, not within BIDS. If you want to explore dataflow performance tuning in more detail then here are some links you might want to check out: Inequality joins, Asynchronous transformations and Lookups Destination Adapter Comparison Don’t turn the dataflow into a cursor SSIS Dataflow – Designing for performance (webinar) Any comments? Let me know! @Jamiet

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  • Do you know of a C macro to compute Unix time and date?

    - by Alexis Wilke
    I'm wondering if someone knows/has a C macro to compute a static Unix time from a hard coded date and time as in: time_t t = UNIX_TIMESTAMP(2012, 5, 10, 9, 26, 13); I'm looking into that because I want to have a numeric static timestamp. This will be done hundred of times throughout the software, each time with a different date, and I want to make sure it is fast because it will run hundreds of times every second. Converting dates that many times would definitively slow down things (i.e. calling mktime() is slower than having a static number compiled in place, right?) [made an update to try to render this paragraph clearer, Nov 23, 2012] Update I want to clarify the question with more information about the process being used. As my server receives requests, for each request, it starts a new process. That process is constantly updated with new plugins and quite often such updates require a database update. Those must be run only once. To know whether an update is necessary, I want to use a Unix date (which is better than using a counter because a counter is much more likely to break once in a while.) The plugins will thus receive an update signal and have their on_update() function called. There I want to do something like this: void some_plugin::on_update(time_t last_update) { if(last_update < UNIX_TIMESTAMP(2010, 3, 22, 20, 9, 26)) { ...run update... } if(last_update < UNIX_TIMESTAMP(2012, 5, 10, 9, 26, 13)) { ...run update... } // as many test as required... } As you can see, if I have to compute the unix timestamp each time, this could represent thousands of calls per process and if you receive 100 hits a second x 1000 calls, you wasted 100,000 calls when you could have had the compiler compute those numbers once at compile time. Putting the value in a static variable is of no interest because this code will run once per process run. Note that the last_update variable changes depending on the website being hit (it comes from the database.) Code Okay, I got the code now: // helper (Days in February) #define _SNAP_UNIX_TIMESTAMP_FDAY(year) \ (((year) % 400) == 0 ? 29LL : \ (((year) % 100) == 0 ? 28LL : \ (((year) % 4) == 0 ? 29LL : \ 28LL))) // helper (Days in the year) #define _SNAP_UNIX_TIMESTAMP_YDAY(year, month, day) \ ( \ /* January */ static_cast<qint64>(day) \ /* February */ + ((month) >= 2 ? 31LL : 0LL) \ /* March */ + ((month) >= 3 ? _SNAP_UNIX_TIMESTAMP_FDAY(year) : 0LL) \ /* April */ + ((month) >= 4 ? 31LL : 0LL) \ /* May */ + ((month) >= 5 ? 30LL : 0LL) \ /* June */ + ((month) >= 6 ? 31LL : 0LL) \ /* July */ + ((month) >= 7 ? 30LL : 0LL) \ /* August */ + ((month) >= 8 ? 31LL : 0LL) \ /* September */+ ((month) >= 9 ? 31LL : 0LL) \ /* October */ + ((month) >= 10 ? 30LL : 0LL) \ /* November */ + ((month) >= 11 ? 31LL : 0LL) \ /* December */ + ((month) >= 12 ? 30LL : 0LL) \ ) #define SNAP_UNIX_TIMESTAMP(year, month, day, hour, minute, second) \ ( /* time */ static_cast<qint64>(second) \ + static_cast<qint64>(minute) * 60LL \ + static_cast<qint64>(hour) * 3600LL \ + /* year day (month + day) */ (_SNAP_UNIX_TIMESTAMP_YDAY(year, month, day) - 1) * 86400LL \ + /* year */ (static_cast<qint64>(year) - 1970LL) * 31536000LL \ + ((static_cast<qint64>(year) - 1969LL) / 4LL) * 86400LL \ - ((static_cast<qint64>(year) - 1901LL) / 100LL) * 86400LL \ + ((static_cast<qint64>(year) - 1601LL) / 400LL) * 86400LL ) WARNING: Do not use these macros to dynamically compute a date. It is SLOWER than mktime(). This being said, if you have a hard coded date, then the compiler will compute the time_t value at compile time. Slower to compile, but faster to execute over and over again.

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  • JavaScript date suffix formatting

    - by TexasB
    I have done my due diligence in investigating this and not had any success yet. Being rather green with JavaScript I am seeking some help. I am wanting to display the date NOV2012<br> 2<sup>nd</sup><br> 5:00 PM I have everything working (not my script) except being able to get the date suffix to change to st, nd, rd, or th as the case may be. This is what I have: <pre> <abbr title="Month"> <script type="text/javascript"> var d=new Date(); var month=new Array(12); month[0]="Jan"; month[1]="Feb"; month[2]="Mar"; month[3]="Apr"; month[4]="May"; month[5]="Jun"; month[6]="Jul"; month[7]="Aug"; month[8]="Sep"; month[9]="Oct"; month[10]="Nov"; month[11]="Dec"; document.write(month[d.getMonth()]); </script></abbr> <script type="text/javascript"> var d = new Date() document.write(d.getDate()) ordinal : function (number) { var d = number % 10; return (~~ (number % 100 / 10) === 1) ? 'th' : (d === 1) ? 'st' : (d === 2) ? 'nd' : (d === 3) ? 'rd' : 'th'; } }); </script> <sup>%</sup> <abbr><script type="text/javascript"> var d = new Date() document.write(d.getFullYear()) </script></abbr> <sub> <script type="text/javascript"> <!-- var currentTime = new Date() var hours = currentTime.getHours() var minutes = currentTime.getMinutes() if (minutes < 10){ minutes = "0" + minutes } document.write(hours + ":" + minutes + " ") if(hours > 11){ document.write("PM") } else { document.write("AM") } //--> </script> </sub> </pre> I know the issue is with this part: <pre> <script type="text/javascript"> var d = new Date() document.write(d.getDate()) ordinal : function (number) { var d = number % 10; return (~~ (number % 100 / 10) === 1) ? 'th' : (d === 1) ? 'st' : (d === 2) ? 'nd' : (d === 3) ? 'rd' : 'th'; } }); </script> < sup > % < /sup > </pre> but I can't seem to work out the right fix. This is where it is sitting: http://www.bcreativeservices.com/ Thank you as always. B

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  • Changing DNS - Forgot to change MX records for one month - Is there a way to retrieve emails that we

    - by Chris Altman
    We have our own domain. Our email is hosted by Google Apps. We switched web servers and name servers to a new provider. In the switch, I forgot to move the MX record. When people tried to send emails to our domain, there was no bounce back. We fixed the MX record and now receive email. Is there anyway to retrieve the emails that were sent in the month when there was no MX record? I doubt it because there was no MX record on our name server. Where would the emails have gone since they did not bounce back?

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  • Linux Software Raid runs checkarray on the First Sunday of the Month? Why?

    - by mgjk
    It looks like Debian has a default to run checkarray on the first Sunday of the month. This causes massive performance problems and heavy disk usage for 12 hours on my 2TB mirror. Doing this "just in case" is bizzare to me. Discovering data out of sync between the two disks without quorum would be a failure anyway. This massive checking could only tell me that I have an unrecoverable drive failure and corrupt data. Which is nice, but not all that helpful. Is it necessary? Given I have no disk errors and no reason to believe my disks have failed, why is this check necessary? Should I take it out of my cron? /etc/cron.d# tail -1 /etc/cron.d/mdadm 57 0 * * 0 root [ -x /usr/share/mdadm/checkarray ] && [ $(date +\%d) -le 7 ] && /usr/share/mdadm/checkarray --cron --all --quiet Thanks for any insight,

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  • JQuery:FullCalendar Plugin: Events are not shown in week view and day view but are shown in month vi

    - by bocode
    I've the following code to fetch events: $('#calendar').fullCalendar({ theme: true, slotMinutes: 10, header: { left: 'prev,next today', center: 'title', right: 'month,agendaWeek,agendaDay', }, defaultView: 'agendaDay', allDaySlot: false, editable: false, events: "/cgi-bin/shlk/getshlkruns.pl" }); The output from getshlkruns.pl is fairly simple json feed: [{'title': 'Successful','start': 1266398223,'end': 1266398266,'url': '/shlk/cgi-bin/getshlkrunlog.pl?i=21'}] There are several events like above (i've removed for brevity sake). So the above events show up when am in the month view but mysteriously absent when am in week or day view. What am doing wrong here? Thanks in advance for your answers.

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  • Best way to get record counts grouped by month, adjusted for time zone, using SQL or LINQ to SQL

    - by Jeff Putz
    I'm looking for the most efficient way to suck out a series of monthly counts of records in my database, but adjusting for time zone, since the times are actually stored as UTC. I would like my result set to be a series of objects that include month, year and count. I have LINQ to SQL objects that looks something like this: public class MyRecord { public int ID { get; set; } public DateTime TimeStamp { get; set; } public string Data { get; set; } } I'm not opposed to using straight SQL, but LINQ to SQL would at least keep the code a lot more clean. The time zone adjustment is available as an integer (-5, for example). Again, the result set what I'm looking for is objects containing the month, year and count, all integers. Any suggestions? I can think of several ways to do it straight, but not with a time zone adjustment.

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  • fullcalendar Cannot display the new event when switch month back.

    - by Archer
    Hi guys, I add a new event to fullcalendar, it display well, but when I go to next month and switch back, it disappear! but the old event will display, why? and How can I display all events? thanks a lot! the detail like: I have two events: event1, event2 coming from a database and when FullCalendar initializes, I add them to the Calendar, displays well. Then I add aother event: event3 to calendar, can display well. go to next month switch back, I find only event1 and event2 displayed, and event3 disappeared? does anyone can help me? thanks!

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  • MDX , Calculate Number of days when the cummulative sum of Revenues from end of a month date match with the given debt amount.

    - by Shuchi
    Hi, I have a financial cube and i have to calculate Daily Sales Outstanding as : Number of Days between the selected month last date and the earliest transaction date when cummulative sum of Revenue from last date of the month till the date where sum revenue <= the debt amount for the date . e.g On 31/12/2009 my debt amount = 2,500,000 31-Dec-09 30-Nov-09 15-Oct-09 31-Oct-09 Revenue 1,000,000 1,000,000 500,000 1,0000 Cummulative sum of revenue 1,000,000 2,00,000 2,500,000 4,000,000 No of Days 31 30 16 On 15/Oct/09 cummulative revenue is 2,500,000 which equals my debt amount on that day Count of Days = 31 + 31 + 16 = 76 Days. In other words Sum Revenue from the selected date backwards until sum total equals or exeeds the total to date balance of the debtors. Any help will be highly appreciated . If i haven't explained clearly enough or if you need more information then please let me know. Thanks in advance . Shuchi.

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  • The script not working as expected files dump path

    - by user3319390
    I have a script needs to be dump matching cname from my file contains and then matching scode to dump file to $cname/$year/$month/$day/ into files like access and error logs #!/bin/sh #base_dir="/home/vizion/Desktop" path="/home/vizion/Desktop/adn_DF9D_20140515_0005.log" name=$(basename "$path" ".log") for x in *.log; do year=${x:9:4}; month=${x:13:2}; day=${x:15:2}; done while read -r line do cname=$(echo ${line} | awk '{split($7,c,"/"); print c[3]}') scode=$(echo ${line} | awk -F"[ ]" '{print $9}') [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day/" [[ ( ${scode} -ge 200 ) && ( ${scode} -le 399 ) ]] && { # [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day/" echo ${line} >> /home/vizion/Desktop/$cname/$year/$month/$day/${cname}_${name}_access.log } [[ ( ${scode} -ge 400 ) && ( ${scode} -le 599 ) ]] && { [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day" echo ${line} >> ${cname}_${name}_error.log } done < $path i am able to filter logs but not not dumping the exact location It's going other locations suggest to me correction in script

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  • Possible to set monthCalendar to show current month and previous 2 months?

    - by John M
    In a WinForms (3.5) application there is form with a monthCalendar control. The calendar control has a calendarDimension of 3 columns by 1 row. This means that it currently shows June, July, August of 2010. Is it possible to have the calendar to show April, May, June of 2010 instead? My dataset doesn't have any future dates so the date selection will be for current or older dates.

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