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  • How can I make the draggable window border thicker, without changing the appearance?

    - by Bruce Connor
    When you want to resize a window in gnome (as well as in other systems) you can click-and-hold at the window's border and than drag it. The problem is (and do correct me if I'm wrong here) that the draggable border is just a couple of pixels thick in gnome. That tends to be a little frustrating, and contributes to my wrist pains from using the mouse, as it requires very careful movement of the mouse. How can I change the thickness of the area I can click in order to resize a window? I don't want to increase the appearance of the window border, I'm not talking about eye candy here. I want to fine tune this functionality where I can resize a window by dragging its border. Is there a setting somewhere that will change this?

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  • CSS : How can I add shadow to a label or box

    - by Rachel
    I have an button just as have Ask Question on SO and here is the CSS for it: .rfs .grey_btn{ float: right; margin: 15px 5px; } Now I have to add border shadow to it and I have tried border-radius and box-shadow but it does not give me proper result. Also other question is that I have a label or box say and now I want to increase size of that box so that I have move the text inside that box to right, currently if I move it to right than it reaches the end limit of box and so I want to increase the size of box so that I can push text more towards right. Hope I have made my question clear. Any guidance would be highly appreciated. Thanks.

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  • Unable to view dialog box in win ce

    - by ame
    I have a win32 application (over 100 source files large) which i need to port to Win CE. I disabled the unsupported functions (such as non client area functions) and compiled the code on a Win CE platform. Now when i run it on my hardware device, I was able to resize the first couple of dialog screens to show up satisfactorily on the LCD. However there is a dialog box that has 2 option buttons and opens a new dialog box based on the choice. I am unable to view the new dialog box. Also, the close (X) button of the parent dialog box is not there and instead shows a question mark (?). I tried resizing the dialog box in the win32 code's resource compiler and it still showed up fine thus telling me that the problem did not lie with the bitmaps. I think there might be some issue with hiding the first dialog box or opening 2 at the same time. please help me. I did not code the win32 version myself and hence i am unable to locate the problem.

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  • Bounding Box Collision Glitching Problem (Pygame)

    - by Ericson Willians
    So far the "Bounding Box" method is the only one that I know. It's efficient enough to deal with simple games. Nevertheless, the game I'm developing is not that simple anymore and for that reason, I've made a simplified example of the problem. (It's worth noticing that I don't have rotating sprites on my game or anything like that. After showing the code, I'll explain better). Here's the whole code: from pygame import * DONE = False screen = display.set_mode((1024,768)) class Thing(): def __init__(self,x,y,w,h,s,c): self.x = x self.y = y self.w = w self.h = h self.s = s self.sur = Surface((64,48)) draw.rect(self.sur,c,(self.x,self.y,w,h),1) self.sur.fill(c) def draw(self): screen.blit(self.sur,(self.x,self.y)) def move(self,x): if key.get_pressed()[K_w] or key.get_pressed()[K_UP]: if x == 1: self.y -= self.s else: self.y += self.s if key.get_pressed()[K_s] or key.get_pressed()[K_DOWN]: if x == 1: self.y += self.s else: self.y -= self.s if key.get_pressed()[K_a] or key.get_pressed()[K_LEFT]: if x == 1: self.x -= self.s else: self.x += self.s if key.get_pressed()[K_d] or key.get_pressed()[K_RIGHT]: if x == 1: self.x += self.s else: self.x -= self.s def warp(self): if self.y < -48: self.y = 768 if self.y > 768 + 48: self.y = 0 if self.x < -64: self.x = 1024 + 64 if self.x > 1024 + 64: self.x = -64 r1 = Thing(0,0,64,48,1,(0,255,0)) r2 = Thing(6*64,6*48,64,48,1,(255,0,0)) while not DONE: screen.fill((0,0,0)) r2.draw() r1.draw() # If not intersecting, then moves, else, it moves in the opposite direction. if not ((((r1.x + r1.w) > (r2.x - r1.s)) and (r1.x < ((r2.x + r2.w) + r1.s))) and (((r1.y + r1.h) > (r2.y - r1.s)) and (r1.y < ((r2.y + r2.h) + r1.s)))): r1.move(1) else: r1.move(0) r1.warp() if key.get_pressed()[K_ESCAPE]: DONE = True for ev in event.get(): if ev.type == QUIT: DONE = True display.update() quit() The problem: In my actual game, the grid is fixed and each tile has 64 by 48 pixels. I know how to deal with collision perfectly if I moved by that size. Nevertheless, obviously, the player moves really fast. In the example, the collision is detected pretty well (Just as I see in many examples throughout the internet). The problem is that if I put the player to move WHEN IS NOT intersecting, then, when it touches the obstacle, it does not move anymore. Giving that problem, I began switching the directions, but then, when it touches and I press the opposite key, it "glitches through". My actual game has many walls, and the player will touch them many times, and I can't afford letting the player go through them. The code-problem illustrated: When the player goes towards the wall (Fine). When the player goes towards the wall and press the opposite direction. (It glitches through). Here is the logic I've designed before implementing it: I don't know any other method, and I really just want to have walls fixed in a grid, but move by 1 or 2 or 3 pixels (Slowly) and have perfect collision without glitching-possibilities. What do you suggest?

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  • Resolving bounding box collision detection

    - by ndg
    I'm working on a simple collision detection and resolution method for a 2d tile-based bounding box system. Collision appears to work correctly, but I'm having issues with resolving a collision after it has happened. Essentially what I'm attempting to do is very similar to this approach. The problem I'm experiencing is that because objects can be traveling with both horizontal and vertical velocity, my resolution code causes the object to jump incorrectly. I've drawn the following annotation to explain my issue. In this example, because my object has both horizontal and vertical velocity, my object (which is heading upwards and collides with the bottom of a tile) has it's position altered twice: To correctly adjust it's vertical position to be beneath the tile. To incorrectly adjust it's horizontal position to be to the left of the tile. Below is my collision/resolution code in full: function intersects(x1, y1, w1, h1, x2, y2, w2, h2) { w2 += x2; w1 += x1; if (x2 > w1 || x1 > w2) return false; h2 += y2; h1 += y1; if (y2 > h1 || y1 > h2) return false; return true; } for(var y = 0; y < this.game.level.tiles.length; y++) { for(var x = 0; x < this.game.level.tiles[y].length; x++) { var tile = this.game.level.getTile(x, y); if(tile) { if( this.velocity.x > 0 && intersects(this.position.x+dx+this.size.w, this.position.y+dy, 1, this.size.h, x*tileSize, y*tileSize, tileSize, tileSize) ) { this.position.x = ((x*tileSize)-this.size.w); hitSomething = true; break; } else if( this.velocity.x < 0 && intersects(this.position.x+dx, this.position.y+dy, 1, this.size.h, x*tileSize, y*tileSize, tileSize, tileSize) ) { this.position.x = ((x*tileSize)+tileSize); hitSomething = true; break; } if( this.velocity.y > 0 && intersects(this.position.x+dx, this.position.y+dy+this.size.h, this.size.w, 1, x*tileSize, y*tileSize, tileSize, tileSize) ) { this.position.y = ((y*tileSize)-this.size.h); hitSomething = true; break; } else if( this.velocity.y < 0 && intersects(this.position.x+dx, this.position.y+dy, this.size.w, 1, x*tileSize, y*tileSize, tileSize, tileSize) ) { this.position.y = ((y*tileSize)+tileSize); hitSomething = true; break; } } } } if(hitSomething) { this.velocity.x = this.velocity.y = 0; dx = dy = 0; this.setJumping(false); }

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  • How TiVo is messing up customer support.

    - by James Fleming
    Ok,  So I've gotten a TiVo and overall, I'm happy, but there have been issues and I suspect I've a defective unit. - Now the nice folks after many service calls were happy to swap it out, and to ensure continuity of service, they sent me a new unit (after a $109 deposit).  That was yesterday. Today, when we go to watch a little TV, and wait for our replacement unit to arrive we find our TiVo service has been suspended. WTF? They have an exchange program, but your unit your waiting to exchange is as dead as a doornail until the replacement arrives. How hard is it to keep the old unit active for an extra week? Here is the exchange w/Tivo below... You are currently number 1 in the queue. We apologize for the delay. We will assign you to an agent as soon as one is available.The average amount of time a customer has to wait is 00:13.  Kaylene (Listening)  Kaylene: Thank you for contacting TiVo! My name is Kaylene. So that I may better assist you, are you an existing customer?  james Fleming: yes I am, but I'm now having second thoughts about being one    Kaylene: Thank you for verifying your information. How may I assist you today James?  james Fleming: I've been having issues w/a tivo box & I'm getting a replacement sent out to me (after paying an additional deposit) and now my current unit is no longer activated  Kaylene: I can help you today!  Kaylene: When we process an exchange we do transfer over the service to the replacement box so it is active and ready to go when you receive it.  james Fleming: which is to say you also make my current box worthless until such time I receive a new box?!?!?  Kaylene: I apologize that your original box was deactivated so we could activate your replacement box.  james Fleming: Why on Earth would I bother to pay in advance for a new box if you were going to kill my existing box.  Kaylene: What features are you needing to use on your current box?  james Fleming: I need to be able to access my netflix subscription (if I'm lucky enough to have it work without rebooting)  Kaylene: Can I have you verify the TiVo Service Number of your TiVo box please?  james Fleming: 7460011906979b4  Kaylene: We have your current box temporary service but not all features are available with temporary service as it is not paid for service.  Kaylene: If you like I can transfer your service back to your current box for now. Then once you receive the new box you will have to call in and have the service transferred back to the new box.  james Fleming: Not paid for? Let's see> one tivo box + 3 year service plan + monthly service + $109 deposit on a second box = what?  Kaylene: Would you like me to transfer your service back to your current box?  james Fleming: Yes - that would be helpful  Kaylene: All you will need to do is contact us again once you receive the new box so we can transfer it back.  Kaylene: I have put your service back on TiVo box 7460011906979b4.  james Fleming: What would also be helpful is your firm informing me to how you'd be cutting service in the interim.  james Fleming: Again - I opted to pay to have a second box delivered BEFORE returning the box I have - thus trying to have a continuity of service..  Kaylene: This is not something we normally do so it is important when you contact us to transfer the service back to the new box when you receive it that you reference this case number: 110622-006089.  Kaylene: I apologize about the inconvenience. You may need  force a few connections for the box to recognize the service again.  james Fleming: If it's not something you normally do than WHY would you have a $109 fee and a term for the service.  james Fleming: I am not mad at you, but your company is not impressing me and I'm blogging about this experience  Kaylene: Again I apologize about the inconvenience but you should be good to go now. Is there anything else I can help you with today?  james Fleming: so I need to go through the re-actviate process or is that somethign you do  Kaylene: When you receive the new TiVo box you need to contact us so we can transfer the service to the new box for you.  james Fleming: sure  Kaylene: Is there anything else I can help you with today James?  james Fleming: Nope - please email this transcript to me  Kaylene: I apologize but we do not have the ability to e-mail you a copy of this transcript. You can view it online at  http://www.tivo.com when you sign into your account or you can copy and paste it now to save it.  Kaylene: Thank you for contacting TiVo today. Your reference number for our conversation is 110622-006089. You can save this for your records, and if necessary, provide this to a later agent to pull up what we discussed. There will be a brief satisfaction survey emailed to you. We would appreciate any feedback on your TiVo Chat Support experience today.  Kaylene: Thank you for using TiVo Chat and have a great day James! Good-bye.  Kaylene has disconnected.

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  • How to display a dependent list box disabled if no child data exist

    - by frank.nimphius
    A requirement on OTN was to disable the dependent list box of a model driven list of value configuration whenever the list is empty. To disable the dependent list, the af:selectOneChoice component needs to be refreshed with every value change of the parent list, which however already is the case as the list boxes are already dependent. When you create model driven list of values as choice lists in an ADF Faces page, two ADF list bindings are implicitly created in the PageDef file of the page that hosts the input form. At runtime, a list binding is an instance of FacesCtrlListBinding, which exposes getItems() as a method to access a list of available child data (java.util.List). Using Expression Language, the list is accessible with #{bindings.list_attribute_name.items} To dynamically set the disabled property on the dependent af:selectOneChoice component, however, you need a managed bean that exposes the following two methods //empty – but required – setter method public void setIsEmpty(boolean isEmpty) {} //the method that returns true/false when the list is empty or //has values public boolean isIsEmpty() {   FacesContext fctx = FacesContext.getCurrentInstance();   ELContext elctx = fctx.getELContext();   ExpressionFactory exprFactory =                          fctx.getApplication().getExpressionFactory();   ValueExpression vexpr =                       exprFactory.createValueExpression(elctx,                         "#{bindings.EmployeeId.items}",                       Object.class);   List employeesList = (List) vexpr.getValue(elctx);                        return employeesList.isEmpty()? true : false;      } If referenced from the dependent choice list, as shown below, the list is disabled whenever it contains no list data <! --  master list --> <af:selectOneChoice value="#{bindings.DepartmentId.inputValue}"                                  label="#{bindings.DepartmentId.label}"                                  required="#{bindings.DepartmentId.hints.mandatory}"                                   shortDesc="#{bindings.DepartmentId.hints.tooltip}"                                   id="soc1" autoSubmit="true">      <f:selectItems value="#{bindings.DepartmentId.items}" id="si1"/> </af:selectOneChoice> <! --  dependent  list --> <af:selectOneChoice value="#{bindings.EmployeeId.inputValue}"                                   label="#{bindings.EmployeeId.label}"                                      required="#{bindings.EmployeeId.hints.mandatory}"                                   shortDesc="#{bindings.EmployeeId.hints.tooltip}"                                   id="soc2" disabled="#{lovTestbean.isEmpty}"                                   partialTriggers="soc1">     <f:selectItems value="#{bindings.EmployeeId.items}" id="si2"/> </af:selectOneChoice>

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  • Vertical Image Border Changes Alignment when Screen is not maximized

    - by Randy
    I have some pretty straightforward HTML code with a few tables to organize various items of text or images. All works fine except that I need to place a vertical border on both the left and right sides of the screen. I am able to do this with a 2x2 pixel image that I stretch out. When the user has their screen maximized, everything looks great. But when the user hits "Restore Down", then the borders stay in place, but the tables get shoved down so that they start below where the borders end, which is off screen. in other words, the relational alignment between the borders and the tables gets all screwed up. Does anybody know how to make this alignment stay consistent on a restore down? I'm pretty much a newbie with html and asp, so speak slowly. If there is a better method to accomplish this, I'm all ears. Thanks. Here is the relevant section of code: <%@ Master Language="C#" AutoEventWireup="true" CodeFile="MasterPage.master.cs" Inherits="MasterPage" % <form id="form1" runat="server"> <asp:Image ID="LeftBorder" src="../Images/Border_Blue.jpg" runat="server" WIDTH="15" HEIGHT="1000" BORDER="0" alt="Image Missing" align="left"/> <asp:Image ID="RightBorder" src="../Images/Border_Blue.jpg" runat="server" WIDTH="15" HEIGHT="1000" BORDER="0" alt="Image Missing" align="right" /> <table id="BannerTable" style="height: 100px"> <tr> <td width="934px"> <img src="../Images/Header.jpg" alt="Image Missing" id="ImgBanner" align="left"/></td> </tr> </table>

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  • How to Use border as an image in android xml

    - by Ethan Hunt
    I have a popup to show in my xml. It should have a border. Following is the code:- <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/rl_parent" android:layout_width="wrap_content" android:layout_height="wrap_content" android:paddingBottom="20dp" > <RelativeLayout android:id="@+id/rl_startpopup" android:layout_width="340dp" android:layout_height="320dp" android:layout_marginLeft="10dp" android:layout_marginRight="10dp" android:background="@drawable/popup_outline" android:orientation="vertical" /> </RelativeLayout> The popup_outline is a shape <?xml version="1.0" encoding="utf-8"?> <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle" > <gradient android:angle="270" android:endColor="#192423" android:startColor="#4a7669" android:type="linear" /> <corners android:radius="8dp" /> <stroke android:width="2dp" android:color="#e4f4d3" /> </shape> here is the image of the popup:- This "popup_outline" is the white border shown. I want to use a repeatable pattern image instead of one color as the border. I have to do this in xml. Please help

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  • nautilus selected item color

    - by shantanu
    See in the image, selected item "build" colour is black as background colour. How can i change the selected item colour gtk3 theme's nautilus.css script Which section colour need to modify: /* desktop mode */ .nautilus-desktop.nautilus-canvas-item { color: @bg_color; text-shadow: 1 1 alpha (#001B33, 0.8); } .nautilus-desktop.nautilus-canvas-item:active { background-image: none; background-color: alpha (@selected_bg_color, 0.84); border-radius: 4; color: @fg_color; } .nautilus-desktop.nautilus-canvas-item:selected { background-image: none; background-color: alpha (@bg_color, 0.84); border-radius: 4; color: @selected_fg_color; } .nautilus-desktop.nautilus-canvas-item:active, .nautilus-desktop.nautilus-canvas-item:prelight, .nautilus-desktop.nautilus-canvas-item:selected { text-shadow: none; } /* browser window */ NautilusTrashBar.info, NautilusXContentBar.info, NautilusSearchBar.info, NautilusQueryEditor.info { /* this background-color controls the symbolic icon in the entry */ background-color: mix (@fg_color, @base_color, 0.3); border-radius: 0; border-style: solid; border-width: 0 1 1 1; } NautilusSearchBar .entry { } .nautilus-cluebar-label { color: @fg_color; font: bold; } #nautilus-search-button *:active, #nautilus-search-button *:active:prelight { color: @dark_fg_color; } NautilusFloatingBar { background-color: @info_bg_color; border-radius: 3 3 0 0; border-style: solid; border-width: 1; border-color: darker (@info_bg_color); -unico-border-gradient: none; } NautilusFloatingBar .button { -GtkButton-image-spacing: 0; -GtkButton-inner-border: 0; } /* sidebar */ NautilusWindow .sidebar, NautilusWindow .sidebar .view { background-color: @bg_color; color: @fg_color; } NautilusWindow .sidebar .frame { } NautilusWindow > GtkTable > .pane-separator { background-color: @bg_color; border-color: @bg_color; border-width: 0 0 0 0; border-style: solid; }

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  • Movement and Collision with AABB

    - by Jeremy Giberson
    I'm having a little difficulty figuring out the following scenarios. http://i.stack.imgur.com/8lM6i.png In scenario A, the moving entity has fallen to (and slightly into the floor). The current position represents the projected position that will occur if I apply the acceleration & velocity as usual without worrying about collision. The Next position, represents the corrected projection position after collision check. The resulting end position is the falling entity now rests ON the floor--that is, in a consistent state of collision by sharing it's bottom X axis with the floor's top X axis. My current update loop looks like the following: // figure out forces & accelerations and project an objects next position // check collision occurrence from current position -> projected position // if a collision occurs, adjust projection position Which seems to be working for the scenario of my object falling to the floor. However, the situation becomes sticky when trying to figure out scenario's B & C. In scenario B, I'm attempt to move along the floor on the X axis (player is pressing right direction button) additionally, gravity is pulling the object into the floor. The problem is, when the object attempts to move the collision detection code is going to recognize that the object is already colliding with the floor to begin with, and auto correct any movement back to where it was before. In scenario C, I'm attempting to jump off the floor. Again, because the object is already in a constant collision with the floor, when the collision routine checks to make sure moving from current position to projected position doesn't result in a collision, it will fail because at the beginning of the motion, the object is already colliding. How do you allow movement along the edge of an object? How do you allow movement away from an object you are already colliding with. Extra Info My collision routine is based on AABB sweeping test from an old gamasutra article, http://www.gamasutra.com/view/feature/3383/simple_intersection_tests_for_games.php?page=3 My bounding box implementation is based on top left/bottom right instead of midpoint/extents, so my min/max functions are adjusted. Otherwise, here is my bounding box class with collision routines: public class BoundingBox { public XYZ topLeft; public XYZ bottomRight; public BoundingBox(float x, float y, float z, float w, float h, float d) { topLeft = new XYZ(); bottomRight = new XYZ(); topLeft.x = x; topLeft.y = y; topLeft.z = z; bottomRight.x = x+w; bottomRight.y = y+h; bottomRight.z = z+d; } public BoundingBox(XYZ position, XYZ dimensions, boolean centered) { topLeft = new XYZ(); bottomRight = new XYZ(); topLeft.x = position.x; topLeft.y = position.y; topLeft.z = position.z; bottomRight.x = position.x + (centered ? dimensions.x/2 : dimensions.x); bottomRight.y = position.y + (centered ? dimensions.y/2 : dimensions.y); bottomRight.z = position.z + (centered ? dimensions.z/2 : dimensions.z); } /** * Check if a point lies inside a bounding box * @param box * @param point * @return */ public static boolean isPointInside(BoundingBox box, XYZ point) { if(box.topLeft.x <= point.x && point.x <= box.bottomRight.x && box.topLeft.y <= point.y && point.y <= box.bottomRight.y && box.topLeft.z <= point.z && point.z <= box.bottomRight.z) return true; return false; } /** * Check for overlap between two bounding boxes using separating axis theorem * if two boxes are separated on any axis, they cannot be overlapping * @param a * @param b * @return */ public static boolean isOverlapping(BoundingBox a, BoundingBox b) { XYZ dxyz = new XYZ(b.topLeft.x - a.topLeft.x, b.topLeft.y - a.topLeft.y, b.topLeft.z - a.topLeft.z); // if b - a is positive, a is first on the axis and we should use its extent // if b -a is negative, b is first on the axis and we should use its extent // check for x axis separation if ((dxyz.x >= 0 && a.bottomRight.x-a.topLeft.x < dxyz.x) // negative scale, reverse extent sum, flip equality ||(dxyz.x < 0 && b.topLeft.x-b.bottomRight.x > dxyz.x)) return false; // check for y axis separation if ((dxyz.y >= 0 && a.bottomRight.y-a.topLeft.y < dxyz.y) // negative scale, reverse extent sum, flip equality ||(dxyz.y < 0 && b.topLeft.y-b.bottomRight.y > dxyz.y)) return false; // check for z axis separation if ((dxyz.z >= 0 && a.bottomRight.z-a.topLeft.z < dxyz.z) // negative scale, reverse extent sum, flip equality ||(dxyz.z < 0 && b.topLeft.z-b.bottomRight.z > dxyz.z)) return false; // not separated on any axis, overlapping return true; } public static boolean isContactEdge(int xyzAxis, BoundingBox a, BoundingBox b) { switch(xyzAxis) { case XYZ.XCOORD: if(a.topLeft.x == b.bottomRight.x || a.bottomRight.x == b.topLeft.x) return true; return false; case XYZ.YCOORD: if(a.topLeft.y == b.bottomRight.y || a.bottomRight.y == b.topLeft.y) return true; return false; case XYZ.ZCOORD: if(a.topLeft.z == b.bottomRight.z || a.bottomRight.z == b.topLeft.z) return true; return false; } return false; } /** * Sweep test min extent value * @param box * @param xyzCoord * @return */ public static float min(BoundingBox box, int xyzCoord) { switch(xyzCoord) { case XYZ.XCOORD: return box.topLeft.x; case XYZ.YCOORD: return box.topLeft.y; case XYZ.ZCOORD: return box.topLeft.z; default: return 0f; } } /** * Sweep test max extent value * @param box * @param xyzCoord * @return */ public static float max(BoundingBox box, int xyzCoord) { switch(xyzCoord) { case XYZ.XCOORD: return box.bottomRight.x; case XYZ.YCOORD: return box.bottomRight.y; case XYZ.ZCOORD: return box.bottomRight.z; default: return 0f; } } /** * Test if bounding box A will overlap bounding box B at any point * when box A moves from position 0 to position 1 and box B moves from position 0 to position 1 * Note, sweep test assumes bounding boxes A and B's dimensions do not change * * @param a0 box a starting position * @param a1 box a ending position * @param b0 box b starting position * @param b1 box b ending position * @param aCollisionOut xyz of box a's position when/if a collision occurs * @param bCollisionOut xyz of box b's position when/if a collision occurs * @return */ public static boolean sweepTest(BoundingBox a0, BoundingBox a1, BoundingBox b0, BoundingBox b1, XYZ aCollisionOut, XYZ bCollisionOut) { // solve in reference to A XYZ va = new XYZ(a1.topLeft.x-a0.topLeft.x, a1.topLeft.y-a0.topLeft.y, a1.topLeft.z-a0.topLeft.z); XYZ vb = new XYZ(b1.topLeft.x-b0.topLeft.x, b1.topLeft.y-b0.topLeft.y, b1.topLeft.z-b0.topLeft.z); XYZ v = new XYZ(vb.x-va.x, vb.y-va.y, vb.z-va.z); // check for initial overlap if(BoundingBox.isOverlapping(a0, b0)) { // java pass by ref/value gotcha, have to modify value can't reassign it aCollisionOut.x = a0.topLeft.x; aCollisionOut.y = a0.topLeft.y; aCollisionOut.z = a0.topLeft.z; bCollisionOut.x = b0.topLeft.x; bCollisionOut.y = b0.topLeft.y; bCollisionOut.z = b0.topLeft.z; return true; } // overlap min/maxs XYZ u0 = new XYZ(); XYZ u1 = new XYZ(1,1,1); float t0, t1; // iterate axis and find overlaps times (x=0, y=1, z=2) for(int i = 0; i < 3; i++) { float aMax = max(a0, i); float aMin = min(a0, i); float bMax = max(b0, i); float bMin = min(b0, i); float vi = XYZ.getCoord(v, i); if(aMax < bMax && vi < 0) XYZ.setCoord(u0, i, (aMax-bMin)/vi); else if(bMax < aMin && vi > 0) XYZ.setCoord(u0, i, (aMin-bMax)/vi); if(bMax > aMin && vi < 0) XYZ.setCoord(u1, i, (aMin-bMax)/vi); else if(aMax > bMin && vi > 0) XYZ.setCoord(u1, i, (aMax-bMin)/vi); } // get times of collision t0 = Math.max(u0.x, Math.max(u0.y, u0.z)); t1 = Math.min(u1.x, Math.min(u1.y, u1.z)); // collision only occurs if t0 < t1 if(t0 <= t1 && t0 != 0) // not t0 because we already tested it! { // t0 is the normalized time of the collision // then the position of the bounding boxes would // be their original position + velocity*time aCollisionOut.x = a0.topLeft.x + va.x*t0; aCollisionOut.y = a0.topLeft.y + va.y*t0; aCollisionOut.z = a0.topLeft.z + va.z*t0; bCollisionOut.x = b0.topLeft.x + vb.x*t0; bCollisionOut.y = b0.topLeft.y + vb.y*t0; bCollisionOut.z = b0.topLeft.z + vb.z*t0; return true; } else return false; } }

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  • Ray-box Intersection Theory

    - by Myx
    Hello: I wish to determine the intersection point between a ray and a box. The box is defined by its min 3D coordinate and max 3D coordinate and the ray is defined by its origin and the direction to which it points. Currently, I am forming a plane for each face of the box and I'm intersecting the ray with the plane. If the ray intersects the plane, then I check whether or not the intersection point is actually on the surface of the box. If so, I check whether it is the closest intersection for this ray and I return the closest intersection. The way I check whether the plane-intersection point is on the box surface itself is through a function bool PointOnBoxFace(R3Point point, R3Point corner1, R3Point corner2) { double min_x = min(corner1.X(), corner2.X()); double max_x = max(corner1.X(), corner2.X()); double min_y = min(corner1.Y(), corner2.Y()); double max_y = max(corner1.Y(), corner2.Y()); double min_z = min(corner1.Z(), corner2.Z()); double max_z = max(corner1.Z(), corner2.Z()); if(point.X() >= min_x && point.X() <= max_x && point.Y() >= min_y && point.Y() <= max_y && point.Z() >= min_z && point.Z() <= max_z) return true; return false; } where corner1 is one corner of the rectangle for that box face and corner2 is the opposite corner. My implementation works most of the time but sometimes it gives me the wrong intersection. I was wondering if the way I'm checking whether the intersection point is on the box is correct or if I should use some other algorithm. Thanks.

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  • Autocomplete or Select box? (design problem)

    - by Craig Whitley
    I'm working on a comparison website, so needless to say the search function is the primary feature of the site. I have two input text boxes and a search button. At the moment, the input text boxes use Ajax to query the database and show a drop-down box, but I'm wondering if it would be more intuitive to use a select box instead? The second box is dependant on the first, as when the first is selected theres another ajax query so only the available options for the first selection appear in the autocomplete box. Autocomplete Pros: - "Feels" right? - Looks more appealing than a select box (css design)? Cons: - the user has to be instructed on how to use the search (made to think?) - Only really works off the bat with javascript enabled. - The user may get confused if they type in what they want and no box appears (i.e., no results) Select Box Pros: - Can bring up the list of options / know whats there from the outset. - We use select boxes every day (locations etc.) so we're used to how they work. (more intuitive?) Cons: - Can look a little unaesthetic when theres too many options to choose from. I'm thinking maybe at most around 100 options for my site over time. Any thoughts on how I could go about this would be appreciated!

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  • How to make the value of one select box drive the options of a second select box

    - by Ben McCormack
    I want to make an HTML form with 2 select boxes. The selected option in the first select box should drive the options in the second select box. I would like to solve this dynamically on the client (using javascript or jQuery) rather than having to submit data to the server. For example, let's say I have the following Menu Categories and Menu Items: Sandwiches Turkey Ham Bacon Sides Mac 'n Cheese Mashed Potatoes Drinks Coca Cola Sprite Sweetwater 420 I would have two select boxes, named Menu Category and Items, respectively. When the user selects Sandwiches in the Menu Category box, the options in the Items box will only show Sandwich options. I'm stuck as how I might approach this. Once I filter out the 2nd list one time, how do I "find" the list options once I change my menu category in the 1st list? Also, if I'm thinking in SQL, I would have a key in the 1st box that would be used to link to the data in the 2nd box. However, I can't see where I have room for a "key" element in the 2nd box. How could this problem be solved with a combination of jQuery or plain javascript?

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  • Open a dialog box in same window on selectOneMenu change

    - by Pravingate
    I have a jsf page where I have a selectOneMenu and , I want to open a dialog box on selectOneMenu changes. As a example if user selects a value ="passive" from jsf selectOneMenu it should open a dialog box or a light box on same page where I want to display a small jsf form like as here done. http://www.primefaces.org/showcase-labs/ui/dialogLogin.jsf and I also want save that submitted data in my backing bean somewhere so I can store it in to database later. I dont know how to open a dialog box or light box from backing bean in same window,as we will identify value change using valueChangeListener event or by using ajax event. I am able to identify which value is selected from selectOneMenu(DropdownMenu), but dont know how to open a dialog box on selecting particular value. <h:outputLabel value="* Country: "/> <h:selectOneMenu id="someSelect" value="#{testController.countryName}" required="true"> <f:selectItem itemLabel="Select Country" itemValue=""/> <f:selectItems value="#{testController.countryNamesSelectItems}"/> </h:selectOneMenu> Supoose we have 2 options in selectItems as India and Austrlia, then If a user choose India a dialog box should open on same page where a user need to fill some information and need to submit if he is from india (like here in example http://www.primefaces.org/showcase-labs/ui/dialogLogin.jsf user will put his username and password and submits data) Hope this helps How can I achieve that by using jsf or javascript or ajax or by any else way?

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  • Browsing Playstation 3 from Ubuntu Box

    - by zfranciscus
    Hi, My Goal here is to be able to transfer files from my Ubuntu 10.04 box to my PS3 over a wireless network. My PS3 and my Ubuntu Box is on the same home network. These are some stuff that I tried: I can't see my PS 3 from 'Places ? Network' nor other computer that is running on windows. I am still puzzled by this fact. I have not tried ping-ing my PS3. I'll try that later today and post the result in the forum I install PS3MediaServer (http://code.google.com/p/ps3mediaserver/). Someone in the PS3 chat forum (http://www.ps3chat.com/playstation-3...lp-please.html) claims that it will enable your ubuntu box to browse PS3. So I downloaded PS3MediaServer, and ran the software. The status tab keep showing "Waiting ...". It seems that PS3MediaServer can't find my PS3. Some how I feel that 1 and 2 are related somehow.Perhaps that there is something wrong with my Ubuntu network settings that is preventing my ubuntu box from looking up other device on the network. I can go to the Internet fine, but I can't see other device on my network. Does anyone have any experience in this area. I would like to hear your experience and perhaps some solution. Any kind of hints or help will be greatly appreciated. Cheers

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  • Updating a staging server (from a CI server) in a Vagrant box with Chef

    - by Tomas Brambora
    I'm using Vagrant + Chef (chef_client provisioner) to create & provision a staging environment for my server. And I have a Jenkins job set up that is run every time I push to my 'develop' branch. In the Jenkins job, I would like to update & rebuild the source code of the server in the staging box and restart it. I have already written the cookbooks that install the dependencies, configure the db etc. But I'm not sure how to run only the update & rebuild & restart stuff from the cookbooks. I understand I could always tear down the whole box and rebuild it, but provisioning the box is a lengthy process so I would like to do that as little as possible. I split my server cookbook into 3 recipes: dependencies, db_setup and server. What I want to run in the my Jenkins job is the "server" recipe only. But I dont' understand how can I do that... If I specify the run_list on my Chef server, then I lose the ability to provision the whole box from scratch. Basically, I would like to be able to tell Vagrant from the command line what recipes Chef should run. Is that possible somehow? Cheers!

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  • Linux Port 80 to redirect to a Windows box

    - by Richard Staehler
    I have 2 servers here at work. One is a Windows 2008 Server R2 (for safety's sake, lets use 192.168.1.100) and the other is a Fedora 14 (192.168.1.101). Currently when you hit our subdomain, x.test.com, our routers tell it to go to our Fedora box, and since Apache is installed and listening to port 80, it displays the Fedora Apache Test Page. It's obvious that I don't use port 80 for this machine, however I do use NAGIOS on it and its always nice to be able to access that from anywhere in the world. So when I want to access it, I just type x.test.com/nagios. Now here comes the dilemma.... On the Windows R2 box, we recently have installed a program that requires us to setup a web server using IIS7. Because of this application, I'm going to be creating a new subdomain called y.test.com, but since we only have 1 WAN/router, it will still get pointed to our Fedora box. That being said, it wants to use port 80 as well (or whatever port I damn well wish to assign it). So my question is: since our router is pointing to the Fedora 14 box (.101), and I want to make sure I can access NAGIOS from anywhere in the world, how do I tell Apache (httpd) to redirect port 80 to the other server (.100)? If not possible, what are my other options? I have rinetd installed on Fedora and have even tried the option 192.168.1.101 80 192.168.1.100 80 and it didn't seem to work "because port 80 was already bound" Thoughts? and Thanks!

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  • Flex Validator -- Show Red Error Border on DataGrid Cell

    - by gmoniey
    I can successfully add a validator on an item in my datagrid, by passing in the particular element in the dataProvider to the validator, but I can't get the red border to show up around the cell if the validation fails. I have stepped through the validator, and confirmed that it is passing back a failure, but I can't figure out why the red error border doesn't show up. I have a feeling its because I am passing the item in my dataProvider as the validator source, rather than the 'cell' item, but I can't find a way to access the cell. Thanks.

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  • Failing to send email on Ubuntu box (Karmic Koala)

    - by user25312
    I have a home network with an XP and Ubuntu (9.10) box. I have created a small test php script for checking that I can send emails from my machine. I am using the same php.ini file with the same [mail settings], yet the file works on my XP box, and fails on the Ubuntu box. I have included the script here, hopefully, someone can spot whats going wrong: <?php // send e-mail to ... $to="[email protected]"; // Your subject $subject="Test Email"; // From //$header="from: test script"; $header='From: host-email-username@hostdomain_here' . "\r\n" . // Your message $message="Hello \r\n"; $message.="This is test\r\n"; $message.="Test again "; // send email $sentmail = mail($to,$subject,$message,$header); // if your email succesfully sent if($sentmail){ echo "Email Has Been Sent ."; } else { echo "Cannot Send Email "; } ?> The emails have been spoofed for obvious reasons, but otherwise, the script is exactly as the one I tested [Edit] I have since installed mailutils package on my Ubuntu box, now the script runs and returns 'Email has been sent'. However, the mail never arrives in my mail inbox (I've waited 1 day so far). Is there something else I need to be looking at?

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  • MSN like box for Ad rotation.

    - by Muhammad Umar Siddique
    Hi Everyone. I want to create a JavaScript based box much like the one found on MSN or AOL with the navigational buttons. Box content must be spider-able by search engines. On MSN you can find the box near top left corner. Note this box contains links and images. Any idea how to implement this ? Thanks.

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  • creating message box as sheets for mac in PyQt

    - by user971306
    I used message box as seperate dialog instead of sheets for mac OS, now i m working on it to spawn a sheet as message box instead of seperate one. I have tried setting the message box as a modal one: (messagebox.setWindowModality(QtCore.Qt.WindoModal)) and setting message box, parent dialog window flags as sheet (parentDialog.setWindowFlags(QtCore.Qt.Sheet) messagebox.setWindowFlags(QtCore.Qt.Sheet)) But the above commands are not working to create a sheet instead of seperate dialog. Does anyone have an idea of how to solve?

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