Search Results

Search found 13075 results on 523 pages for 'bounding box'.

Page 15/523 | < Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >

  • run ubuntu from virtual box in an external hard drive

    - by Bhavan
    I would like to run ubuntu on my external hard drive. I have got virtual box installed in the external hard drive and made a machine named ubuntu and installed the latest ubuntu version which i got from the .iso download. Now after much juggling around i got ubuntu running on the machine which i did the whole installation. When i move it to another machine the virtual box just woudnt open. What is the reason for this and how can i get the ubuntu run from whichever machine i plug in the external usb hard disk. Thanks a lot for your answers in advance. Best regards Bhavan

    Read the article

  • Transfer values from one selection box to another

    - by Tonya Cash
    I need to populate the first box with the items from a db table. Users would choose from the first box, and either drag value(items) to the second for selection, or would select items, and then click a button to move them over to the 2nd box. After that I need to update the db with the selected values/items.

    Read the article

  • Picture Box and Form Transparency

    - by Qu1nncunxIV
    Maybe I am missing something, but is it the case that when you set a pictureboxes background to transparent, all it really does is set it to the same color as the forms background? What I am trying to do is draw an animation for the benefit of this, a bouncing ball - which I paint on the form, then overlay that with a picture frame. End result should be a bouncing ball in a picture frame, I should mention that the picture frame does not have a straight edge, so it is not possible to arrange 4 picture boxes in a frame. The ball needs to vanish behind the frame to change color and then magically bounce back out. I have tried: 1.Setting the picture box background to pink and then key out the same pink, this basically cuts away everything, including that which is behind the picture box 2.Setting the picture box to transparent, this just displays the picture box background as the same color as the forms background. 3.I have tried painting the image in a rectangle, this had the same effect as drawing it in a picture box. I am not sure what I am doing wrong, I am wondering if there is any other ways I could try or if someone has made a custom control or library that supports transparency?

    Read the article

  • jquery animate boxshadow

    - by mstef
    http://jsfiddle.net/mstefanko/w5aAn/877/ Below, i'm achieving the effect I wanted, but with a pending issue. Since i'm using a separate span and positioning it absolute over-top of a box with relative position. I can not access the inputs until after the animation is finished. I'm guessing the only way to alleviate this would be do something similar with just animating the border of the outer box? But nothing I was doing to animate box-shadow:inset was working. HTML <div id="wow"> <span id="pulse"></span> <input id="form-input"/> <input id="form-input"/> </div>? CSS #wow { width: 500px; height: 200px; display: inline-block; position: relative; border: 1px solid black; } #pulse { width: 100%; height: 100%; box-shadow:inset 0 0 20px #6c95c3; -moz-box-shadow:inset 0 0 10px #6c95c3; position: absolute; z-index: 20000; } JS $('#pulse').stop().animate({"opacity": 0}, "fast"); $('#pulse').effect("pulsate", { times:4 }, 500, function() { $(this).remove(); });

    Read the article

  • C++ Edit Box Text Change

    - by user1218395
    Is their any cases in C++ Like these case WM_COMMAND: switch(LOWORD(wParam)) That happen when you change the text of a edit Box, I need to call a function when i change in edit box and store the value of the edit box into a Integer. case EditCD: //ID of your edit { if (HIWORD(wParam) == EN_CHANGE) MessageBox(hwnd, "Text!", "Test!", MB_OK); return TRUE; } Doesnt work did i do it wrong?

    Read the article

  • Transforming a primitive tetrahedron into a primitive icosahedron?

    - by Djentleman
    I've created a tetrahedron by creating a BoundingBox and building the faces of the tetrahedron within the bounding box as follows (see image as well): VertexPositionNormalTexture[] vertices = new VertexPositionNormalTexture[12]; BoundingBox box = new BoundingBox(new Vector3(-1f, 1f, 1f), new Vector3(1f, -1f, -1f)); vertices[0].Position = box.GetCorners()[0]; vertices[1].Position = box.GetCorners()[2]; vertices[2].Position = box.GetCorners()[7]; vertices[3].Position = box.GetCorners()[0]; vertices[4].Position = box.GetCorners()[5]; vertices[5].Position = box.GetCorners()[2]; vertices[6].Position = box.GetCorners()[5]; vertices[7].Position = box.GetCorners()[7]; vertices[8].Position = box.GetCorners()[2]; vertices[9].Position = box.GetCorners()[5]; vertices[10].Position = box.GetCorners()[0]; vertices[11].Position = box.GetCorners()[7]; What would I then have to do to transform this tetrahedron into an icosahedron? Similar to this image: I understand the concept but applying it is another thing entirely for me.

    Read the article

  • How do I make a dialog box? [on hold]

    - by bill
    By dialog box I mean when player talks to someone, a box shows up with text on it. I haven't found much about this topic online, so I created a basic dialog box: //in dialog box i have only two methods public void createBox(int x, int y, int width, int height, String txt) { this.x = x; this.y = y; this.width = width; this.height = height; this.txt = txt; } //draw dialog box public void draw(Graphics2D g) { if (txt != null) { g.setColor(Color.red); g.drawRect(x,y,width,height); g.setColor(Color.black); g.fillRect(x, y, width, height); g.setColor(Color.white); g.drawString(txt, x + 10, y + 10); } } I wanted to now can I make this better?

    Read the article

  • Login box not shown on Ubuntu

    - by Alexandre
    I've installed Ubuntu 10.04 (64bit) as a guest OS in VirtualBox, using Windows7 Professional (64bit) as host. After Ubuntu install, I did installed Xfce4 (sudo apt-get install xfce4). Logged in using a Xfce session, and when I logged out, I couldn't see the login box anymore, only the regular gnome background from login screen. Then I restarted the virtual machine, and now I'm not able to see the login box anymore, only the gnome background. Does someone knows how to solve this? Thanks in advance Update: I've tried to use Xubuntu, that comes with Xfce. And I'm facing the same problem. As a common denominator from the two cases, now I see the problem arises after I've updated the system, and then installed curl (via apt-get), zlib (make process), git (make process). But I'm not sure this can be the cause for this ... Update: I isolated the problem. The bad guy is zlib, but I don't have a clue why. In fact, it does crash not only ubuntu and xubuntu, but also Debian (Yes, I've tested all). I'll keep this question in case someone have the same problem, but I think my initial question is not valid anymore.

    Read the article

  • Intel Atom overheating in ASUS EEE Box 1501P

    - by Sergey L.
    I have had an ASUS EEE Box 1501P for just a little bit over a year. Of course it breaks 2 months after the warranty runs out. http://www.asus.com/Eee/EeeBox_PC/EeeBox_PC_EB1501P/ I have been using the box as a Home Media Center. Running mostly 24/7 often pausing a video overnight. Since last week the fan started running extremely loud. After some digging I found that the Intel Atom CPU in it is overheating and the built-in sensor is reporting temperatures way over 105°C. This got me worried, so I took the unit apart. Completely vacuumed the heat sink, oiled the fan, but the unit is still showing the same behaviour. After turning it on and just observing the hardware monitor in the BIOS the temperature slowly rises from 40°C to over 95°C in appx 5 min. I am running the newest BIOS and a lightweight Linux OPENELEC OS with XBMC on it. Now I am wondering if it could be a faulty heat sensor in the Atom. Recommended running temperature is up to 85°C, but I have not detected any performance hits when running at the above mentioned 105°C and there seem to be no software faults. How can an Atom with an attached heat sink and a fan running at full capacity even get this hot in the first place at 0 load? Aren't those things designed to generate virtually no heat? Could it be a faulty heat sensor? What shall I try to fix this? I would prefer not to damage the CPU, since it is hard fused into the motherboard and cannot be replaced. I could remove the heat pipe/heat sink, but it is getting hot, so heat is properly transferring from the CPU to the heat pipe, the fan is running at full capacity, is recently oiled and warm air is making it out of the exhaust. Edit: One more note: The North-bridge (or whatever it is called nowadays) is on the same heat pipe.

    Read the article

  • Xen domU passwd file overwritten with console log output

    - by malfy
    I was setting up a Debian Xen domU and after booting it fine, I added basic configuration to /etc/network/interfaces and ran /etc/init.d/networking restart. This failed so I decided to reboot. After the reboot I also ran xm shutdown box. When dropped to a shell prompt it wouldn't let me login. Upon further inspection, I now have garbage in some critical files in /etc: root@box:/# tail +1 mnt/etc/{passwd-,shadow} tail: cannot open `+1' for reading: No such file or directory ==> mnt/etc/passwd- <== 0000000000100000 (reserved) Nov 23 02:02:39 box kernel: [ 0.000000] Xen: 0000000000100000 - 0000000004000000 (usable) Nov 23 02:02:39 box kernel: [ 0.000000] DMI not present or invalid. Nov 23 02:02:39 box kernel: [ 0.000000] last_pfn = 0x4000 max_arch_pfn = 0x1000000 Nov 23 02:02:39 box kernel: [ 0.000000] initial memory mapped : 0 - 033ff000 Nov 23 02:02:39 box kernel: [ 0.000000] init_memory_mapping: 0000000000000000-0000000004000000 Nov 23 02:02:39 box kernel: [ 0.000000] NX (Execute Disable) protection: active Nov 23 02:02:39 box kernel: [ 0.000000] 0000000000 - 0004000000 page 4k Nov 23 02:02:39 box kernel: [ 0.000000] kernel direct mapping tables up to 4000000 @ 7000-2c000 Nov 23 02:02:3 ==> mnt/etc/shadow <== 32 nr_cpumask_bits:32 nr_cpu_ids:1 nr_node_ids:1 Nov 23 02:02:39 box kernel: [ 0.000000] PERCPU: Embedded 15 pages/cpu @c15b0000 s37688 r0 d23752 u65536 Nov 23 02:02:39 box kernel: [ 0.000000] pcpu-alloc: s37688 r0 d23752 u65536 alloc=16*4096 Nov 23 02:02:39 box kernel: [ 0.000000] pcpu-alloc: [0] 0 Nov 23 02:02:39 box kernel: [ 0.000000] Xen: using vcpu_info placement Nov 23 02:02:39 box kernel: [ 0.000000] Built 1 zonelists in Zone order, mobility grouping on. Total pages: 16160 Nov 23 02:02:39 box kernel: [ 0.000000] Kernel command line: root=/dev/mapper/xen-guest_root ro quiet root=/dev/xvda1 ro Nov 23 02:02:39 box kernel: [ 0.000000] PID hash table entries: The garbage is also present in the passwd file and the group file (although I didn't paste that above since I have since ran debootstrap on the filesystem again). Does anyone have any insight into what happened and why?

    Read the article

  • Creating Active Directory on an EC2 box

    - by Chiggins
    So I have Active Directory set up on a Windows Server 2008 Amazon EC2 server. Its set up correctly I think, I never got any errors with it. Just to test that I got it all set up correctly, I have a Windows 7 Professional virtual machine set up on my network to join to AD. I set the VM to use the Active Directory box as its DNS server. I type in my domain to join it, but I get the following error: DNS was successfully queried for the service location (SRV) resource record used to locate a domain controller for domain "ad.win.chigs.me": The query was for the SRV record for _ldap._tcp.dc._msdcs.ad.win.chigs.me The following domain controllers were identified by the query: ip-0af92ac4.ad.win.chigs.me However no domain controllers could be contacted. Common causes of this error include: - Host (A) or (AAAA) records that map the names of the domain controllers to their IP addresses are missing or contain incorrect addresses. - Domain controllers registered in DNS are not connected to the network or are not running. It seems that I can talk to Active Directory, but when I'm trying to contact the Domain Controller, its giving a private IP to connect to, at least thats what I can make out of it. Here are some nslookup results. > win.chigs.me Server: ec2-184-73-35-150.compute-1.amazonaws.com Address: 184.73.35.150 Non-authoritative answer: Name: ec2-184-73-35-150.compute-1.amazonaws.com Address: 10.249.42.196 Aliases: win.chigs.me > ad.win.chigs.me Server: ec2-184-73-35-150.compute-1.amazonaws.com Address: 184.73.35.150 Name: ad.win.chigs.me Address: 10.249.42.196 win.chigs.me and ad.win.chigs.me are CNAME's pointing to my EC2 box. Any idea what I need to do so that I can join my virtual machine to the EC2 Active Directory set up I have? Thanks!

    Read the article

  • Linux: Send mail to external mail box from a server with that user's hostname

    - by dtbarne
    I've got sendmail running on a linux box. Let's say the hostname of the box is bar.com. If I run the following command, I don't receive the email (which is hosted with a third party), presumably due to the hostname pointing to the local machine. echo "Test Body" | mail -s "Test Subject" [email protected] Is there any way to get this to work so that I can receive emails at my third party email address even though it has the same hostname? Do I have to change the hostname of this server (not preferred)? It may be worth noting that I created a user "foo" on my machine and noticed that the mailbox for that account is empty. I noticed these log entries, which may or may not be relevant: Jun 28 01:09:48 bar sendmail[14338]: p5S59min014338: from=apache, size=80, class=0, nrcpts=1, msgid=<[email protected]>, relay=apache@localhost Jun 28 01:09:48 bar sendmail[14339]: p5S59mIA014339: from=<[email protected]>, size=293, class=0, nrcpts=1, msgid=<[email protected]>, proto=ESMTP, daemon=MTA, relay=localhost.localdomain [127.0.$ Jun 28 01:09:48 bar sendmail[14338]: p5S59min014338: [email protected], ctladdr=apache (48/48), delay=00:00:00, xdelay=00:00:00, mailer=relay, pri=30080, relay=[127.0.0.1] [127.0.0.1], dsn=2.0.0, stat=Sent (p5S59mIA$ Jun 28 01:09:48 bar sendmail[14340]: p5S59mIA014339: to=<[email protected]>, ctladdr=<[email protected]> (48/48), delay=00:00:00, xdelay=00:00:00, mailer=local, pri=30495, dsn=2.0.0, stat=Sent

    Read the article

  • Linux: Send mail to external mail box from a server with that user's hostname

    - by dtbarne
    I've got sendmail running on a linux box. Let's say the hostname of the box is bar.com. If I run the following command, I don't receive the email (which is hosted with a third party), presumably due to the hostname pointing to the local machine. echo "Test Body" | mail -s "Test Subject" [email protected] Is there any way to get this to work so that I can receive emails at my third party email address even though it has the same hostname? Do I have to change the hostname of this server (not preferred)? It may be worth noting that I created a user "foo" on my machine and noticed that the mailbox for that account is empty. I noticed these log entries, which may or may not be relevant: Jun 28 01:09:48 bar sendmail[14338]: p5S59min014338: from=apache, size=80, class=0, nrcpts=1, msgid=<[email protected]>, relay=apache@localhost Jun 28 01:09:48 bar sendmail[14339]: p5S59mIA014339: from=<[email protected]>, size=293, class=0, nrcpts=1, msgid=<[email protected]>, proto=ESMTP, daemon=MTA, relay=localhost.localdomain [127.0.$ Jun 28 01:09:48 bar sendmail[14338]: p5S59min014338: [email protected], ctladdr=apache (48/48), delay=00:00:00, xdelay=00:00:00, mailer=relay, pri=30080, relay=[127.0.0.1] [127.0.0.1], dsn=2.0.0, stat=Sent (p5S59mIA$ Jun 28 01:09:48 bar sendmail[14340]: p5S59mIA014339: to=<[email protected]>, ctladdr=<[email protected]> (48/48), delay=00:00:00, xdelay=00:00:00, mailer=local, pri=30495, dsn=2.0.0, stat=Sent

    Read the article

  • VBA - Access 03 - Iterating through a list box, with an if statement to evaluate

    - by Justin
    So I have a one list box with values like DeptA, DeptB, DeptC & DeptD. I have a method that causes these to automatically populate in this list box if they are applicable. So in other words, if they populate in this list box, I want the resulting logic to say they are "Yes" in a boolean field in the table. So to accomplish this I am trying to use this example of iteration to cycle through the list box first of all, and it works great: dim i as integer dim myval as string For i = o to me.lstResults.listcount - 1 myVal = lstResults.itemdata(i) Next i if i debug.print myval, i get the list of data items that i want from the list box. so now i am trying to evaluate that list so that I can have an UPDATE SQL statement to update the table as i need it to be done. so, i know this is a mistake, but this is what i tried to do (giving it as an example so that you can see what i am trying to get to here) dim sql as string dim i as integer dim myval as string dim db as database sql = "UPDATE tblMain SET " for i = 0 to me.lstResults.listcount - 1 myval = lstResults.itemdata(i) If MyVal = "DeptA" Then sql = sql & "DeptA = Yes" ElseIF myval = "DeptB" Then sql = sql & "DeptB = Yes" ElseIf MyVal = "DeptC" Then sql = sql & "DeptC = Yes" ElseIf MyVal = "DeptD" Then sql = sql & "DeptD = Yes" End If Next i debug.print (sql) sql = sql & ";" set db= currentdb db.execute(sql) msgbox "Good Luck!" So you can see why this is going to cause problems because the listbox that these values (DeptA, DeptB, etc) automatically populate in are dynamic....there is rarely one value in the listbox, and the list of values changes per OrderID (what the form I am using this on populates information for in the first place; unique instance). I am looking for something that will evaluate this list one at a time (i.e. iterate through the list of values, and look for "DeptA", and if it is found add yes to the SQL string, and if it not add no to the SQL string, then march on to the next iteration). Even though the listbox populates values dynamically, they are set values, meaning i know what could end up in it. Thanks for any help, Justin

    Read the article

  • Ruby on Rails check box not updating on form submission

    - by user284194
    I have an entries controller that allows users to add contact information the website. The user-submitted information isn't visible to users until the administrator checks a check box and submits the form. So basically my problem is that if I check the check box as an administrator while initially creating an entry (entries#new) the entry will be publicly visible as expected, but if a non-admin user creates an entry (the normal user view doesn't include the 'live' check box, only the admin one does) then that entry is stuck in limbo because the entries#edit view for some reason doesn't update the boolean check box value when logged in as an admin. entries#new view: <% form_for(@entry) do |f| %> <%= f.error_messages %> Name<br /> <%= f.text_field :name %> Mailing Address<br /> <%= f.text_field :address %> #... <%- if current_user -%> <%= f.label :live %><br /> <%= f.check_box :live %> <%- end -%> <%= f.submit 'Create' %> <% end %> entries#edit (only accessible by admin) view: <% form_for(@entry) do |f| %> <%= f.error_messages %> <%= f.label :name %><br /> <%= f.text_field :name %> Mailing Address<br /> <%= f.text_field :address %> <%= f.label :live %><br /> <%= f.check_box :live %> <%= f.submit 'Update' %> <% end %> Any ideas as to why an administrator can't update the :live check box from the edit view? I would greatly appreciate any suggestions. I'm new to rails. I can post more code if it's needed. Thanks for reading my question.

    Read the article

  • actionscript 2.0 input text box

    - by user1769760
    So, here's what I'm trying to do, and I, frankly, believe it should be obvious, but I can't figure it out. I am creating a very simple Artificial Intelligence simulation. And in this simulation there's an input box at the bottom of the screen (called "input" exactly). "input" has a variable in its properties that is called "inbox" (exactly). Using a key listener the script calls up a function when the enter button is pressed. This function has 2 if statements and an else statement which dictate the responses of the AI (named "nistra"). The problem is this, When I type in what I want to say, and hit enter, it always uses the second response ("lockpick" in the code below). I have tried variations on the code but I still don't see the solution. I believe the problem is that the "typein" variable holds all the format information from the text box as well as the variable, but I could be wrong, that information is in here as well, underneath the code itself. Any help I can get would be greatly appreciated. var typein = ""; //copies the text from inbox into here, this is what nistra responds to var inbox = ""; //this is where the text from the input text box goes var respond = ""; //nistra's responses go here my_listener = new Object(); // key listener my_listener.onKeyDown = function() { if(Key.isDown(13)) //enter button pressed { typein = inbox; // moves inbox into typein nistraresponse(); // calles nistra's responses } //code = Key.getCode(); //trace ("Key pressed = " + code); } Key.addListener(my_listener); // key listener ends here nistraresponse = function() // nistra's responses { trace(typein); // trace out what "typein" holds if(typein = "Hello") // if you type in "Hello" { respond = "Hello, How are you?"; } if(typein = "lockpick") // if you type in "lockpick" { respond = "Affirmative"; } else // anything else { respond = "I do not understand the command, please rephrase"; } cntxtID = setInterval(clearnistra, 5000); // calls the function that clears out nistra's response box so that her responses don't just sit there } clearnistra = function() // clears her respond box { respond = ""; clearInterval(cntxtID); } // "typein" traces out the following <TEXTFORMAT LEADING="2"><P ALIGN="CENTER"><FONT FACE="Times New Roman" SIZE="20" COLOR="#FF0000" LETTERSPACING="0" KERNING="0">test</FONT></P></TEXTFORMAT>

    Read the article

  • How to avoid the configuring ms office dialog box

    - by user23950
    I always see the configuring ms office with a an endless progress bar, 2 or more weeks after I installed ms office(2000, 2003, 2010 beta). I'm not exactly sure what it is called but it is trying to configure ms office.Or maybe repairing the installation. And it sucks because when I need to access ms word NOW, I can only see that box with the progress bar. And when I press cancel, it won't open ms word, or maybe the whole suite(ms word, powerpoint, excel) What might be a possible solution to this?anyone here who has encountered it before

    Read the article

  • way to access Win networked folder on Mac like one can with Run box on Win

    - by Nik
    I was wondering if there is a way to access a deeply nested shared networked Windows folder on Mac (Lion) like you can on windows with the Run box. say I know the folder I want is on the computer Homer-PC, the G drive, the folder ABC/234/CDE on Windows I can Win+R then \Homer-PC\G\ABC\234\CDE return and it should open that folder directly, Is there something similar on the Mac? Or is there some tiny apps that I can use to do that? Thank You

    Read the article

  • Virtual Box state not saving upon restart/reset/shutdown - reverting to an earlier state

    - by user638756
    Every time I restart/shut down my VM in VirtualBox (image is Ubuntu 10.02), whenever I start it back up, it reverts to the state it was in after I installed Guest Additions. This is extremely frustrating as every time I make progress on a project, whenever it restarts (mostly from crashing), I have to redo mostly everything. Is this a known problem with Guest Additions or with Virtual Box in general, and if so is there some solution?

    Read the article

  • Ubuntu resolution on Virtual Box(Mac OSX)

    - by idealflip
    Ubuntu can't detect my monitor type. What driver shall I update Ubuntu with? Or how can I go about increasing the resolution past 800x600, if no higher resolution is visibly available? I'm running Ubuntu 9.1 on Virtual Box 3.1.6 on Mac OSX 10.6.3 Thanks in advance!

    Read the article

  • openSUSE on Virtual Box : Guest Additions

    - by Arkapravo
    I am using openSUSE 11.0 guest in Ubuntu 9.10 host on Virtual Box. When I try to install Guest-Additions it doesn't really work as expected, the screen is not sized to fit the correct resolution, seamless working between 2 OS doesn't happen ! Has anyone tried installing Guest-Additions in openSUSE ?

    Read the article

< Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >