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  • Java multiline string

    - by skiphoppy
    Coming from Perl, I sure am missing the "here-document" means of creating a multi-line string in source code: $string = <<"EOF" # create a three line string text text text EOF In Java I have to have cumbersome quotes and plus signs on every line as I concatenate my multiline string from scratch. What are some better alternatives? Define

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  • How do I truncate a .NET string?

    - by Steve Guidi
    I apologize for such a question that likely has a trivial solution, but I strangely could not find a concise API for this problem. Essentially, I would like to truncate a string such that it its length is not longer than a given value. I am writing to a database table and want to ensure that the values I write meet the constraint of the column's

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  • string manipulation without alloc mem in c

    - by Mike
    I'm wondering if there is another way of getting a sub string without allocating memory. To be more specific, I have a string as: const char *str = "9|0\" 940 Hello"; Currently I'm getting the 940, which is the sub-string I want as, char *a = strstr(str,"9|0\" "); char *b = substr(a+5, 0, 3); // gives me the 940 Where substr is my sub

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  • C++ String manipulation isn't making sense to me...

    - by Andrew Bolster
    I am trying some of the Stanford SEE courses online to learn some new languages; this particular assignment has to do with removing substrings from strings. What I've got so far is below, but if text = "hello hello" and remove ="el", it gets stuck in a loop, but if i change text to text = "hello hllo", it works, making me think I'm doing

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  • About the String#substring() method

    - by alain.janinm
    If we take a look at the String#substring method implementation : new String(offset + beginIndex, endIndex - beginIndex, value); We see that a new String is created with the same original content (parameter char [] value). So the workaround is to use new String(toto.substring(...)) to drop the reference to the original char[]

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  • String intern puzzles

    - by Yob
    On this blog I found interesting String puzzles: --- Quote --- String te = "te", st = "st"; //"test".length(); String username = te + st; username.intern(); System.out.println("String object the same is: " + (username == "test")); prints String object the same is: true but uncomment the "test".length(); line and it

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  • returning correct multiTouch id

    - by Max
    I've spent countless hours on reading tutorials and looking at every question related to multiTouch from here and Stackoverflow. But I just cannot figure out how to do this correctly. I use a loop to get my pointerId, I dont see alot of people doing this but its the only way I've managed to get it somewhat working. I have

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  • Making uppercase of std::string

    - by Daniel K.
    Which implementation do you think is better? std::string ToUpper( const std::string& source ) { std::string result; result.reserve( source.length() ); std::transform( source.begin(), source.end(), result.begin(), std::ptr_fun<int, int>( std::toupper ) ); return result; } and...

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  • string manipulations in C

    - by Vivek27
    Following are some basic questions that I have with respect to strings in C. If string literals are stored in read-only data segment and cannot be changed after initialisation, then what is the difference between the following two initialisations. char *string = "Hello world"; const char

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  • Why is Java String indexOf failing?

    - by Binaryrespawn
    Hi all, this must be quite simple but I am having great difficulty. You see I am trying to find a string within another string as follows. e = input.indexOf("-->"); s = input.indexOf("<!--"); input = input.replace(input.substring(s, e + 3), " "); The integers e and

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  • .NET Format a string with fixed spaces

    - by treant
    Does the .NET String.Format method allow placement of a string at a fixed position within a fixed length string. " String Goes Here" " String Goes Here " "String Goes Here " How is this done using .NET? Edit - I have tried Format/PadLeft/PadRight to death. They do

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