Search Results

Search found 1526 results on 62 pages for 'imperial college london'.

Page 15/62 | < Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >

• How do I get others to see past my prior inexperience?

  - by Kevin

  My core question is how do I proceed from the following predicament. I will be honest with you, I wasted my College Experience. I slacked off and didn't take any of my comp sci classes that seriously, somehow i still got out with a 3.25 GPA. But truth be told I learned nothing. I befriended most of my professors who went pretty lenient on me in terms of grading. However, I basically came out of College knowing how to program a simple calculator in VB.Net. I was (to my great surprise) hired by a very large respected company in Denver as a Junior developer. Well the long and the short of it is that I knew so little about programming that I quickly became the office pariah and was almost fired due to my incompetence. It has been 8 months now and I feel I have learned some basic things and I am not as picked on as I used to be by the other developers. However, everyone hates me and the first few months have given the other developers a horrible perception of me. I am no longer afraid of code or learning, but I have put my self in the precarious position of being the scapegoat of our department. I hate going to work every day because no one there is my friend and pretty much everyone is hostile to me. What should I do? Any advice?

  Read the article

• Google is not treating two Australian schools as separate sites when both are subdomains of qld.edu.au

  - by LuckySpoon

  My question relates to two websites, each of which is a "Calvary Christian College", however in two totally different locations and unrelated to each other entirely (except by name, and thus domain). All schools in the state are issued a <school-name>.qld.edu.au subdomain, in this case calvary.qld.edu.au and calvarycc.qld.edu.au. Now what's interesting is that these domains are crossing each other in sitelinks for searches such as calvary christian college townsville. The green data here is for one school (the Townsville school, as per search term), and the red data is for the other school. I've put a demotion in for this 6 months ago (we control calvary.qld.edu.au), however we're seeing no change on the results page. I have been able to get the owners of calvarycc.qld.edu.au to submit demotions for our domain, which should go in sometime in the next few days. What can we do to tell Google that these websites are not interchangeable, despite both appearing as "subdomains" of qld.edu.au? We can possibly open channels of communication with the administrators of qld.edu.au but will need to tell them what we need to change, and at this point I'm out of ideas.

  Read the article

• Do I expect too much work from an employer? [closed]

  - by Ant

  I recently switched jobs because I was not challenged enough, the work would come in waves, and I HATED the people I worked with. I am a recent college grad, May 2009, and based off the 3 internships I had, and 2 full time jobs I obtained, I am finding that employers can not keep me satisfied with the amount of work. At my new job, I like the people I work with, I am challenged, but I still do not get enough work. I hate down time. I always want to have something to work on AT LEAST 6 out of the 8 hours. I was surprised that my new employer actually hired me because the majority of the technologies they implement, I had minimal exposure to. I never programmed in the technologies they use outside of one class in college. My greatest strength is that I am an extremely fast learner. I can pick up new technologies with relative ease. They gave me a project to work on by myself and I think they assumed it would take me longer to complete. Now that I finished that app, they are struggling to find something for me to do. I am not sure if it is bad timing being close to the holidays, my manager dealing with personal issues at home, how quickly I finished the first project, or that I expect too much out of an employer? If so, what are good things to do on all this downtime?! EDIT: Thanks for all the feedback! EDIT 2: I am going to "unaccept" the answer in an effort to keep the question open. As a few people have mentioned, this is a great discussion on how to grow as a new worker in the programming field. EDIT 3: I am attempting to revive this question so the moderators will see the support to re-open it.

  Read the article

• How to identify web development benchmarking questions? [closed]

  - by GenericJam

  I am in my final year of college and I have to put forward some sort of thesis for my final year project. The project is a web based attendance system that I am building for the college. I have it about 70% complete in Java. After completing it in Java, the plan is for me to rewrite the server bit in Erlang and then release the bitter rivals in a head to head cage match. The idea being that there is some sort of grounds for comparison. There are a few hurdles along the way, such as me learning Erlang. I understand that a performance comparison like this isn't strictly scientific as there are many factors such as the programmer (myself); the hardware it runs on; etc... but it is meant to be a reasonable comparison of the merits of using Java vs. Erlang for web development. I need help in identifying what the relevant questions are that my project could address. Even though the project scope is fixed, I am trying to shoehorn in some worthwhile scientific inquiries.

  Read the article

• Should I make my project free software?

  - by SkyDan

  The story Over the last couple month I have been working on a pretty big project. It's an enterprise-level software, I designed to be used at a local gym, but I believe it can be used in other places, where things like keeping track of clients, attendances, purchases and payments are required. The problem Well recently, I started to think on how to mature this project from being home-made. Not just because I want my project to grow but also because I would like to have some gain from it. The solutions? And here I saw 2 paths: License the software under some restricted license and try to sell the software to other business around. This way I can get some money for college (I am a high school junior right now) License the software under some free license, publish it on GitHub or something, and try to engage other developers to participate in the project. This way I get experience of working in a team and a better chance that the project will keep growing. The latter would be a good + for my resume, when I'll trying to find a job. So far both ways seem pretty exciting and beneficial to me. The first one offers a good college career, while the second one offers some additional experience and the project's growth. The questions Can anyone point to some other +/- of these 2 options? What would the better option in my situation and why? Or are there other options?

  Read the article

• Can I eventually consider myself a professional developer if I don't have a CS degree? [on hold]

  - by heltonbiker

  Question first, context later: If I am a dedicated, self-taught programmer, always seeking top-quality books AND READING THEM, while successfully applying all that new knowledge into my current work, could I call myself (and offer my work as) a PROFESSIONAL developer? How limiting (or how common) that is nowadays? I am afraid that, no matter how hard I study and practice, it could be too difficult to compete with "actual", college graduated developers, and potential employers might have doubts investing in an "undergraduated" person. Now, context: My former profession is from healthcare sector, then I studied mechanical engineering (quit in the middle), then I studied product design (master degree), and I ended up working (very happily) at an engineering company that manufactures medical devices. For more than two years now my main activity in this company is software development. The devices contain software, and we gave up hiring software development (domain knowledge needed, too much communication cost). My current company sees a lot of value in what I do, but I cannot afford the risk of depending on this single company for the rest of my life, you get it. But a lot of job offers require some minimal formal education, usually a CS degree. Fact is that I am sure this is my target profession, I don't plan to go to another area, it is a pleasure to dive into books that normal people would consider unreadable, but I'm 36 years old and can't see going back to college as a viable alternative.

  Read the article

• How to learn to program [on hold]

  - by user94914

  I went to a community college and got a degree in computer science, but I found out I only learn very little about programming. As a result I landed byself a office assistant work (for a year now), I want to study on my own and apply for some internship / very entry level development job. I am wondering how should a person learn to program now? I feel that I might not doing it correctly, I understand everyone has a different approach, but I am really clueless on what to do, as it seems I am 5-10 years away. 1) Read the old college programming textbook cover to cover, learn every single concepts, do all the practice problems and master them (1-2 times until error free). Currently reading this java book 2) Work on any project, keep on googling and reading tutorials (including the books on that specific language). I have been doing 1, but the progress is really slow, about 2-5 pages / hour, over a 1000+ page book, I felt really discouraged. I have a few of them to go through (data struction, analyis algorthim, computer theory, operating system.) I wonder is this the right method to do? I know it is going to take time, but I am hoping to get some advice from current programmers.

  Read the article

• SQL Query - Count column values separately

  - by user575535

  I have a hard time getting a Query to work right. This is the DDL for my Tables CREATE TABLE Agency ( id SERIAL not null, city VARCHAR(200) not null, PRIMARY KEY(id) ); CREATE TABLE Customer ( id SERIAL not null, fullname VARCHAR(200) not null, status VARCHAR(15) not null CHECK(status IN ('new','regular','gold')), agencyID INTEGER not null REFERENCES Agency(id), PRIMARY KEY(id) ); Sample Data from the Tables AGENCY id|'city' 1 |'London' 2 |'Moscow' 3 |'Beijing' CUSTOMER id|'fullname' |'status' |agencyid 1 |'Michael Smith' |'new' |1 2 |'John Doe' |'regular'|1 3 |'Vlad Atanasov' |'new' |2 4 |'Vasili Karasev'|'regular'|2 5 |'Elena Miskova' |'gold' |2 6 |'Kim Yin Lu' |'new' |3 7 |'Hu Jintao' |'regular'|3 8 |'Wen Jiabao' |'regular'|3 I want to produce the following output, but i need to count separately for ('new','regular','gold') 'city' |new_customers|regular_customers|gold_customers 'Moscow' |1 |1 |1 'Beijing'|1 |2 |0 'London' |1 |1 |0

  Read the article

• Tail recursion in Erlang

  - by dagda1

  Hi, I am really struggling to understand tail recursion in Erlang. I have the following eunit test: db_write_many_test() -> Db = db:new(), Db1 = db:write(francesco, london, Db), Db2 = db:write(lelle, stockholm, Db1), ?assertEqual([{lelle, stockholm},{francesco, london}], Db2). And here is my implementation: -module(db) . -include_lib("eunit/include/eunit.hrl"). -export([new/0,write/3]). new() -> []. write(Key, Value, Database) -> Record = {Key, Value}, [Record|append(Database)]. append([H|T]) -> [H|append(T)]; append([]) -> []. Is my implementation tail recursive and if not, how can I make it so? Thanks in advance

  Read the article

• SQL Self Join Query Help

  - by hdoe123

  Hi All, I'm trying to work out a query that self join itself on a table using the eventnumber. I've never done a self join before. What i'm trying to query is when a client has started off in a city which is chester to see what city they moved to. But I dont want to be able to see if they started off in another city. I would also like be only see the move once (So i'd only like to see if they went from chester to london rather then chester to london to wales) The StartTimeDate is the same EndDateTime if they moved to another city. Data example as follows if they started off in the city chester :- clientid EventNumber City StartDateTime EndDateTime 1 1 Chester 10/03/2009 11/04/2010 13:00 1 1 Liverpool 11/04/2010 13:00 30/06/2010 16:00 1 1 Wales 30/07/2010 16:00 the result I would like to see is on the 2nd row - so it only shows me liverpool. Could anyone point in the right direcetion please?

  Read the article

• calling facebox in a google maps balloon

  - by XGreen

  Hi Guys, I have a gmap balloon. var marker = createMarker(point, '<div style="width:240px" id="mapsball"><h2>Splash of London</h2><img src="_assets/images/themes/shop.jpg" id="mapThumb" width="100" align="right" /><p>110-112 Hoxton Street</p><p>London</p><p>N1 6SH</p><\/div>'); map.addOverlay(marker, icon); and a facebox attached to the click event of the image ('#mapsball') which opens it in a facebox $(function() { $("body").delegate("#mapThumb", "click", function(){ jQuery.facebox('<img src="_assets/images/themes/shop.jpg" align="right"/>'); }); }); this works fine in ff and safari and chrome. but doesn't fire in ie. I don't get a js error in ie so I am assuming it just doesn't get binded. any help would be greatly appreciated.

  Read the article

• SQL Count Query with Grouping by multiple Columns

  - by Christian

  I have a table with three filled columns named "Name", "City" and "Occupation". I want to create a new column in the same table that contains the number of people who have the same occupation. "Name" | "City" | "Occupation" ------------------------------ Amy | Berlin | Plumber Bob | Berlin | Plumber Carol | Berlin | Lawyer David | London | Plumber I want to have a table that contains: "Name" | "City" | "Occupation" | "Number" --------------------------------------- Amy | Berlin | Plumber | 2 Bob | Berlin | Plumber | 2 Carol | Berlin | Lawyer | 1 David | London | Plumber | 1 How does the SQL Query that creates the new columns have to look like? I want to actually create a new column in the database that I can access later.

  Read the article

• SQL Count Query with Grouping by multiple Rows

  - by Christian

  I have a table with three filled rows named "Name", "City" and "Occupation". I want to create a new row in the same table that contains the number of people who have the same occupation. "Name" | "City" | "Occupation" ------------------------------ Amy | Berlin | Plumber Bob | Berlin | Plumber Carol | Berlin | Lawyer David | London | Plumber I want to have a table that contains: "Name" | "City" | "Occupation" | "Number" --------------------------------------- Amy | Berlin | Plumber | 2 Bob | Berlin | Plumber | 2 Carol | Berlin | Lawyer | 1 David | London | Plumber | 1 How does the SQL Query that creates the new row have to look like? I want to actually create a new row in the database that I can access later.

  Read the article

• mysql select query problem

  - by Chocho

  i have a form that has a multiple select drop down. a user can select more than one options in the select. the name of the select is array[]; using php i implode(",",$array) in mysql db, it stores the field as a text in this format "places"= "new york, toronto, london" when i want to display these fields i explode the commas. i am trying to run a report to display the places. here is my select: "select * from mytable where db.places .. userSelectedPlaces" how can i check toronto in lists of "places" that user selected? note "places" in the db might be either just "toronto" or it might be comma separated lists of places like "ny, toronto, london, paris, etc".

  Read the article

• Java simple data format british time

  - by DD

  Hi, I am using simple date format to allow users to specify which time zone they are sending data in: DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss,z"); This works fine: e.g. df.parse("2009-05-16 11:07:41,GMT"); However, if someone is always sending time in London time (i.e. taking into account daylight savings), what would be the approriate time zone String to add? e.g. this doesnt work: df.parse("2009-05-16 11:07:41,Europe/London"); Thanks.

  Read the article

• php preg_replace, regexp

  - by Michael

  I'm trying to extract the postal codes from yell.com using php and preg_replace. I successfully extracted the postal code but only along with the address. Here is an example $URL = "http://www.yell.com/ucs/UcsSearchAction.do?scrambleSeed=17824062&keywords=shop&layout=&companyName=&location=London&searchType=advance&broaderLocation=&clarifyIndex=0&clarifyOptions=CLOTHES+SHOPS|CLOTHES+SHOPS+-+LADIES|&ooa=&M=&ssm=1&lCOption32=RES|CLOTHES+SHOPS+-+LADIES&bandedclarifyResults=1"; //get yell.com page in a string $htmlContent = $baseClass-getContent($URL); //get postal code along with the address $result2 = preg_match_all("/(.*)/", $htmlContent, $matches); print_r($matches); The above code ouputs something like Array ( [0] = Array ( [0] = 7, Royal Parade, Chislehurst, Kent BR7 6NR [1] = 55, Monmouth St, London, WC2H 9DG .... the problem that I have is that I don't know how to extract the the postal code because it doesn't have an exact number of digits (sometimes it has 6 digits and sometimes has only 5 times). Basically I should extract the lasted 2 words from each array . Thank you in advance for any help !

  Read the article

• scala 2.8 breakout

  - by oxbow_lakes

  In Scala 2.8, there is an object in scala.collection.package.scala: def breakOut[From, T, To](implicit b : CanBuildFrom[Nothing, T, To]) = new CanBuildFrom[From, T, To] { def apply(from: From) = b.apply() ; def apply() = b.apply() } I have been told that this results in: > import scala.collection.breakOut > val map : Map[Int,String] = List("London", "Paris").map(x => (x.length, x))(breakOut) map: Map[Int,String] = Map(6 -> London, 5 -> Paris) What is going on here? Why is breakOut being called as an argument to my List?

  Read the article

• Getting the correct node

  - by YsoL8

  Hello I have this structure in my dom: <label>London<input type="checkbox" name="London"></label><br> <div class="innerpost"> <label>N1 2AB<input type="checkbox" name="N1 2AB"></label><br> <label>E1 1AB<input type="checkbox" name="E1 1AB"></label><br> </div> I need a way to select the div from the first checkbox. Something like parentNode.parentNode.getElementsByTagName("div"); But I'm not getting it right - that particular line selects all the divs one parent above the one I need.

  Read the article

• Convert Google results object (pure js) to Python object

  - by colwilson

  So I'm trying to use Google Map suggest API to request place name suggestions. Unfortunately I can't find the docs for this bit. Here is an example URI: http://maps.google.com/maps/suggest?q=lon&cp=3&ll=55.0,-3.5&spn=11.9,1.2&hl=en&gl=uk&v=2 which returns: {suggestion:[{query:"London",... I want to use this in python (2.5). Now in proper JSON there would have been quotations around the keys like so: {"suggestion":[{"query":"London",... and I could have used simplejson or something, but as it is I'm a bit stuck. There are two possible solutions here; either I can get to the API code and find an option to return proper JSON, or I do that in python. Any ideas please.

  Read the article

• Finding cities close to one another using longitude and latitude

  - by Jamie

  Each user in my db is associated to a city (with it's longitude and latitude) How would I go about finding out which cities are close to one another? i.e. in England, Cambridge is fairly close to London. So If I have a user who lives in Cambridge. Users close to them would be users living in close surrounding cities, such as London, Hertford etc. Any ideas how I could go about this? And also, how would I define what is close? i.e. in the UK close would be much closer than if it were in the US as the US is far more spread out. Ideas and suggestions. Also, do you know any services that provide this sort of functionality? Thanks

  Read the article

• How do i get a href value from a link within a ul li list

  - by Akk

  I have an unordered list such as: <ul id="cities"> <li><a href="/london/">London<a></li> <li><a href="/new-york/">New York<a></li> <li><a href="/paris/">Paris<a></li> <ul> using jquery how do i get the href value for "New York"? Only the anchor text value is known through the client so i would like to find the matching anchor text and extract the href. Thanks

  Read the article

• Pass data in np.dnarray to Highcharts

  - by F.N.B

  I'm working with python 2.7, jinja2, flask and Highcharts. I create two numpy array (x1 and x2, type = numpy.dnarray) and I pass to Highcharts. My problems is, Highcharts don't recognize the commas in the vector. This is my jinja2 code: <script> $(function () { $('#container').highcharts({ series: [{ name: 'Tokyo', data: {{ x1 }} }, { name: 'London', data: {{ x2 }} }] }); }); And this is the error that I look with network chrome dev tools: series: [{ name: 'Tokyo', data: [1 4 5 2 3] }, { name: 'London', data: [3 6 7 4 1] }] I need change the numpy array to python list to pass to Highcharts or there is a better way to do?? Thanks

  Read the article

• Good way to parse query string

  - by m.edmondson

  I have a String that contains the following: ?workarea=London+&+Home+Counties+Ltd&sub=fs&&&FASh*5 which resembles a URI query string. What is the best way to parse the elements of this string (workarea and sub) without messing about with string manipulation? If I use HttpUtility.ParseQueryString is gets stuck as both elements include &. However if I encode the whole thing first I lose the seperations of the elements. Ideally the output would be: workarea = London & Home Counties Ltd sub = fs&&&FASh*5

  Read the article

• How to get common field in ten tables with different field name

  - by Fero

  Hi all, I am having a common field in ten tables with different field name. example: table1: t1_id     t1_location 1         india 2         china 3         america table2: t2_id     t2_location 4         london 5         australia 6         america Now my o/p should be: location india china america london australia How should i get that using mysql query. thanks in advance

  Read the article

• How to transform latitude and longitude?

  - by Nyla Pareska

  How to calculate from these numbers: 51.501690392607,-0.1263427734375 to latitude and longitude? It should be London, England 51° 32' N 0° 5' W

  Read the article

< Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >