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  • IRM Item Codes &ndash; what are they for?

    - by martin.abrahams
    A number of colleagues have been asking about IRM item codes recently – what are they for, when are they useful, how can you control them to meet some customer requirements? This is quite a big topic, but this article provides a few answers. An item code is part of the metadata of every sealed document – unless you define a custom metadata model. The item code is defined when a file is sealed, and usually defaults to a timestamp/filename combination. This time/name combo tends to make item codes unique for each new document, but actually item codes are not necessarily unique, as will become clear shortly. In most scenarios, item codes are not relevant to the evaluation of a user’s rights - the context name is the critical piece of metadata, as a user typically has a role that grants access to an entire classification of information regardless of item code. This is key to the simplicity and manageability of the Oracle IRM solution. Item codes are occasionally exposed to users in the UI, but most users probably never notice and never care. Nevertheless, here is one example of where you can see an item code – when you hover the mouse pointer over a sealed file. As you see, the item code for this freshly created file combines a timestamp with the file name. But what are item codes for? The first benefit of item codes is that they enable you to manage exceptions to the policy defined for a context. Thus, I might have access to all oracle – internal files - except for 2011_03_11 13:33:29 Board Minutes.sdocx. This simple mechanism enables Oracle IRM to provide file-by-file control where appropriate, whilst offering the scalability and manageability of classification-based control for the majority of users and content. You really don’t want to be managing each file individually, but never say never. Item codes can also be used for the opposite effect – to include a file in a user’s rights when their role would ordinarily deny access. So, you can assign a role that allows access only to specified item codes. For example, my role might say that I have access to precisely one file – the one shown above. So how are item codes set? In the vast majority of scenarios, item codes are set automatically as part of the sealing process. The sealing API uses the timestamp and filename as shown, and the user need not even realise that this has happened. This automatically creates item codes that are for all practical purposes unique - and that are also intelligible to users who might want to refer to them when viewing or assigning rights in the management UI. It is also possible for suitably authorised users and applications to set the item code manually or programmatically if required. Setting the item code manually using the IRM Desktop The manual process is a simple extension of the sealing task. An authorised user can select the Advanced… sealing option, and will see a dialog that offers the option to specify the item code. To see this option, the user’s role needs the Set Item Code right – you don’t want most users to give any thought at all to item codes, so by default the option is hidden. Setting the item code programmatically A more common scenario is that an application controls the item code programmatically. For example, a document management system that seals documents as part of a workflow might set the item code to match the document’s unique identifier in its repository. This offers the option to tie IRM rights evaluation directly to the security model defined in the document management system. Again, the sealing application needs to be authorised to Set Item Code. The Payslip Scenario To give a concrete example of how item codes might be used in a real world scenario, consider a Human Resources workflow such as a payslips. The goal might be to allow the HR team to have access to all payslips, but each employee to have access only to their own payslips. To enable this, you might have an IRM classification called Payslips. The HR team have a role in the normal way that allows access to all payslips. However, each employee would have an Item Reader role that only allows them to access files that have a particular item code – and that item code might match the employee’s payroll number. So, employee number 123123123 would have access to items with that code. This shows why item codes are not necessarily unique – you can deliberately set the same code on many files for ease of administration. The employees might have the right to unseal or print their payslip, so the solution acts as a secure delivery mechanism that allows payslips to be distributed via corporate email without any fear that they might be accessed by IT administrators, or forwarded accidentally to anyone other than the intended recipient. All that remains is to ensure that as each user’s payslip is sealed, it is assigned the correct item code – something that is easily managed by a simple IRM sealing application. Each month, an employee’s payslip is sealed with the same item code, so you do not need to keep amending the list of items that the user has access to – they have access to all documents that carry their employee code.

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  • What is the point of the prototype method?

    - by Mild Fuzz
    I am reading through Javascript: The Good Parts, and struggled to get my head around the section on prototypes. After a little google, I came to the conclusion that it is to add properties to objects after the objects declaration. Using this script gleamed from w3schools, I noticed that removing the line adding the prototype property had no effect. So what is the point? //Prototyping function employee(name,jobtitle,born) { this.name=name; this.jobtitle=jobtitle; this.born=born; } var fred=new employee("Fred Flintstone","Caveman",1970); employee.prototype.salary=null; // <--- try removing this line fred.salary=20000; document.write(fred.salary);

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  • Repositories and the Save Method

    One of the questions I've been getting lately goes like this: Should a Repository class have a Save method? And the standard answer: It depends. It's hard to keep track of all the different approaches to implementing the repository pattern these days, but I assume when someone asks me this type of question they are thinking of using code like this: var employee = new Employee(); employeeRepository.Save(employee); var account = new Account(); accountRepository.Save(account); This...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Installing Midnight Commander from sources (no root privileges)

    - by ouroboros
    I tried to configure ./configure --prefix=/localfolder glib-2.26.1/ make make install but it fails at make stage. trying to configure mc-4.6.1/ and make doesn't obviously work. What are the steps I need to make in order to install midnight comander for my local user in a custom folder? Make for glib gives me these errors /usr/bin/msgfmt: found 2 fatal errors cp: cannot stat `test.mo': No such file or directory gmake[4]: *** [test.mo] Error 1 gmake[4]: Leaving directory `/remote/folder/mc/glib-2.26.1/gio/tests' gmake[3]: *** [all-recursive] Error 1 gmake[3]: Leaving directory `/remote/folder/mc/glib-2.26.1/gio' gmake[2]: *** [all] Error 2 gmake[2]: Leaving directory `/remote/folder/mc/glib-2.26.1/gio' gmake[1]: *** [all-recursive] Error 1 gmake[1]: Leaving directory `/remote/folder/mc/glib-2.26.1' gmake: *** [all] Error 2

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  • No rule to make target libmysql.c', needed bylibmysql.lo'. Stop

    - by user1711008
    I install mysql5.1.53, run #./configure is well, but run #make have this error. My system is centos5.8, gcc version 4.1.2 20080704 (Red Hat 4.1.2-52) make[2]: Leaving directory /root/soft/mysql-5.1.53/libmysql' make[1]: Leaving directory/root/soft/mysql-5.1.53/libmysql' Making all in libmysql_r make[1]: Entering directory /root/soft/mysql-5.1.53/libmysql_r' make all-am make[2]: Entering directory/root/soft/mysql-5.1.53/libmysql_r' make[2]: * No rule to make target libmysql.c', needed bylibmysql.lo'. Stop. make[2]: Leaving directory /root/soft/mysql-5.1.53/libmysql_r' make[1]: *** [all] Error 2 make[1]: Leaving directory/root/soft/mysql-5.1.53/libmysql_r' make: * [all-recursive] Error 1

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  • xecvp: ./chk: Permission denied

    - by Hiranth
    I'm trying to install Xen 4.0.1 on Ubuntu 10.10. When i run the "make world" it gives the following error at the end.... make -C check clean make[4]: Entering directory `/home/hirantha/xen-4.0.1/tools/check' ./chk clean make[4]: execvp: ./chk: Permission denied make[4]: * [clean] Error 127 make[4]: Leaving directory `/home/hirantha/xen-4.0.1/tools/check' make[3]: * [subdir-clean-check] Error 2 make[3]: Leaving directory `/home/hirantha/xen-4.0.1/tools' make[2]: * [subdirs-clean] Error 2 make[2]: Leaving directory `/home/hirantha/xen-4.0.1/tools' make[1]: * [clean] Error 2 make[1]: Leaving directory `/home/hirantha/xen-4.0.1' make: * [world] Error 2 Why is that? Please help me to solve this....

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  • apt-get install fails due to dependency issues but apt-get -f install won't fix it

    - by user71941
    I've just installed Ubuntu 12.04 and was about to manually install Rawstudio with the packages from SourceForge repo, but I've been stuck with dependency issues and I am short on apt command lines to sort this out. Here's the report I'v got : installArchives() failed: dpkg: dependency problems prevent configuration of libgphoto2-2: libgphoto2-2 depends on libjpeg62; however: Package libjpeg62 is not installed. libgphoto2-l10n (2.4.13-1ubuntu1) breaks libgphoto2-2 (<= 2.4.10.1-4) and is installed. Version of libgphoto2-2 to be configured is 2.4.10.1-0ubuntu3~maverick. dpkg: error processing libgphoto2-2 (--configure): dependency problems - leaving unconfigured No apport report written because MaxReports is reached already dpkg: dependency problems prevent configuration of libgphoto2-2-dev: libgphoto2-2-dev depends on libgphoto2-2 (= 2.4.10.1-0ubuntu3~maverick); however: Package libgphoto2-2 is not configured yet. dpkg: error processing libgphoto2-2-dev (--configure): dependency problems - leaving unconfigured No apport report written because MaxReports is reached already Errors were encountered while processing: libgphoto2-2 libgphoto2-2-dev Error in function: SystemError: E:Sub-process /usr/bin/dpkg returned an error code (1) dpkg: dependency problems prevent configuration of libgphoto2-2: libgphoto2-2 depends on libjpeg62; however: Package libjpeg62 is not installed. libgphoto2-l10n (2.4.13-1ubuntu1) breaks libgphoto2-2 (<= 2.4.10.1-4) and is installed. Version of libgphoto2-2 to be configured is 2.4.10.1-0ubuntu3~maverick. dpkg: error processing libgphoto2-2 (--configure): dependency problems - leaving unconfigured dpkg: dependency problems prevent configuration of libgphoto2-2-dev: libgphoto2-2-dev depends on libgphoto2-2 (= 2.4.10.1-0ubuntu3~maverick); however: Package libgphoto2-2 is not configured yet. dpkg: error processing libgphoto2-2-dev (--configure): dependency problems - leaving unconfigured I've tried "apt-get -f install" but without success. What is the mahick command line that will unblock the situation ? Thanks Seb

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  • Challenge 19 – An Explanation of a Query

    - by Dave Ballantyne
    I have received a number of requests for an explanation of my winning query of TSQL Challenge 19. This involved traversing a hierarchy of employees and rolling a count of orders from subordinates up to superiors. The first concept I shall address is the hierarchyId , which is constructed within the CTE called cteTree.   cteTree is a recursive cte that will expand the parent-child hierarchy of the personnel in the table @emp.  One useful feature with a recursive cte is that data can be ‘passed’ from the parent to the child data.  The hierarchyId column is similar to the hierarchyId data type that was introduced in SQL Server 2008 and represents the position of the person within the organisation. Let us start with a simplistic example Albert manages Bob and Eddie.  Bob manages Carl and Dave. The hierarchyId will represent each person’s position in this relationship in a single field.  In this simple example we could append the userID together into a varchar field as detailed below. This will enable us to select a branch of the tree by filtering using Where hierarchyId  ‘1,2%’ to select Bob and all his subordinates.  Naturally, this is not comprehensive enough to provide a full solution, but as opposed to concatenating the Id’s together into a varchar datatyped column, we can apply the same theory to a varbinary.  By CASTing the ID’s into a datatype of varbinary(4) ,4 is used as 4 bytes of data are used to store an integer and building a hierarchyId  from those.  For example: The important point to bear in mind for later in the query is that the binary data generated is 'byte order comparable'. ie We can ORDER a dataset with it and the resulting data, will be in the order required. Now, would probably be a good time to download the example file and, after the cte ‘cteTree’, uncomment the line ‘select * from cteTree’.  Mark this and all prior code and execute.  This will show you how this theory directly relates to the actual challenge data.  The only deviation from the above, is that instead of using the ID of an employee, I have used the row_number() ranking function to order each level by LastName,Firstname.  This enables me to order by the HierarchyId in the final result set so that the result set is in the required order. Your output should be something like the below.  Notice also the ‘Level’ Column that contains the depth that the employee is within the tree.  I would encourage you to ‘play’ with the query, change the order in the row_number() or the length of the cast in the hierarchyId to see how that effects the outcome.  The next cte, ‘cteTreeWithOrderCount’, is a join between cteTree and the @ord table, and COUNT’s the number of orders per employee.  A LEFT JOIN is employed here to account for the occasion where an employee has made no sales.   Executing a ‘Select * from cteTreeWithOrderCount’ will return the result set as below.  The order here is unimportant as this is only a staging point of the data and only the final result set in a cte chain needs an Order by clause, unless TOP is utilised. cteExplode joins the above result set to the tally table (Nums) for Level Occurances.  So, if level is 2 then 2 rows are required.  This is done to expand the dataset, to create a new column (PathInc), which is the (n+1) integers contained within the heirarchyid.  For example, with the data for Robert King as given above, the below 3 rows will be returned. From this you can see that the pathinc column now contains the values for Andrew Fuller and Steven Buchanan who are Robert King’s superiors within the tree.    Finally cteSumUp, sums the orders for each person and their subordinates using the PathInc generated above, and the final select does the final simple mathematics and filters to restrict the result set to only the ‘original’ row per employee.

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  • ubuntu software center not working after update

    - by HOS
    today I'm updated my Ubuntu (I have KDE Desktop installed on it before) & After update , my Ubuntu software center said : items cannot be installed or removed until the package catalog is repaired .do you want to repair it ? and when I'm clicked on Repair ,after 2 seconds it says : the installation or removal of software package Failed , with this details : installArchives() failed: dpkg: dependency problems prevent configuration of kdm: kdm depends on libkworkspace4abi1 (= 4:4.8.5-0ubuntu0.1); however: Version of libkworkspace4abi1 on system is 4:4.8.5-0ubuntu0.2. kdm depends on kde-workspace-kgreet-plugins (= 4:4.8.5-0ubuntu0.1); however: Version of kde-workspace-kgreet-plugins on system is 4:4.8.5-0ubuntu0.2. dpkg: error processing kdm (--configure): dependency problems - leaving unconfigured dpkg: dependency problems prevent configuration of kubuntu-desktop: kubuntu-desktop depends on kdm; however: Package kdm is not configured yet. dpkg: error processing kubuntu-desktop (--configure): No apport report written because the error message indicates its a followup error from a previous failure. No apport report written because the error message indicates its a followup error from a previous failure. dependency problems - leaving unconfigured Errors were encountered while processing: kdm kubuntu-desktop Error in function: dpkg: dependency problems prevent configuration of kdm: kdm depends on libkworkspace4abi1 (= 4:4.8.5-0ubuntu0.1); however: Version of libkworkspace4abi1 on system is 4:4.8.5-0ubuntu0.2. kdm depends on kde-workspace-kgreet-plugins (= 4:4.8.5-0ubuntu0.1); however: Version of kde-workspace-kgreet-plugins on system is 4:4.8.5-0ubuntu0.2. dpkg: error processing kdm (--configure): dependency problems - leaving unconfigured dpkg: dependency problems prevent configuration of kubuntu-desktop: kubuntu-desktop depends on kdm; however: Package kdm is not configured yet. dpkg: error processing kubuntu-desktop (--configure): dependency problems - leaving unconfigured please help me i love Ubuntu & i want to repair it . Thanks

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  • Oracle Announces Release of PeopleSoft HCM 9.1 Feature Pack 2

    - by Jay Zuckert
    Big things sometimes come in small packages.  Today Oracle announced the availability of PeopleSoft HCM 9.1 Feature Pack 2 which delivers a new HR self service user experience that fundamentally changes the way managers and employees interact with the HCM system.  Earlier this year we reviewed a number of new concept designs with our Customer Advisory Boards.  With the accelerated feature pack development cycle we have adopted, these innovations are  now available to all 9.1 customers without the need for an upgrade.   There are no new products that need to be licensed for the capabilities below. For more details on Feature Pack 2, please see the Oracle press release. Included in Feature Pack 2 is a new search-based menu-free navigation that allows managers to search for employees by name and take actions directly from the secure search results.  For example, a manager can now simply type in part of an employee’s first or last name and receive meaningful results from documents related to performance, compensation, learning, recruiting, career planning and more.   Delivered actions can be initiated directly from these search results and the actions are securely tied to HCM security and user role.  The feature pack also includes new pages that will enable managers to be more productive by aggregating key employee data into a single page.  The new Manager Dashboard and Talent Summary provide a consolidated view of data related to a manager’s team and individual team members, respectively.   The Manager Dashboard displays information relevant to their direct reports including team learning, objective alignment, alerts, and pending approvals requiring their attention.  The Talent Summary provides managers with an aggregated view of talent management-related data for an individual employee including performance history, salary history, succession options, total rewards, and competencies.   The information displayed in both the Manager Dashboard and Talent Summary is configurable by system administrators and can be personalized by each of your managers. Other Feature Pack 2 enhancements allow organizations to administer Matrix or Dotted-Line Relationship Management, which addresses the challenge of tracking and maintaining project-based organizations that cut across the enterprise and geographic regions.  From within the Company Directory and Org Viewer organization charts, managers now have access to manager self-service transactions from related actions.  More than 70 manager and employee self-service transactions have been tied into the related action framework accessible from Org Viewer, Manager Dashboard, Talent Summary and Secure Enterprise Search (SES) results.  In addition to making it easier to access manager self-service transactions, the feature pack delivers streamlined transaction pages making everyday tasks such as promoting an employee faster and more efficient. With the delivery of PeopleSoft HCM 9.1 Feature Pack 2, Oracle continues to deliver on its commitment to our PeopleSoft customers.  With this feature pack, HCM 9.1 customers will be able to deploy the newest functionality quickly, without a major release upgrade, and realize added value from their existing PeopleSoft investment.    For customers newly deploying 9.1, a new download with all of Feature Pack 2  will be available early next year.   This will aslo include recertified upgrade paths from 8.8, 8.9 and 9.0, for customers in the upgrade process.

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  • Validation and authorization in layered architecture

    - by SonOfPirate
    I know you are thinking (or maybe yelling), "not another question asking where validation belongs in a layered architecture?!?" Well, yes, but hopefully this will be a little bit of a different take on the subject. I am a firm believer that validation takes many forms, is context-based and varies at each level of the architecture. That is the basis for the post - helping to identify what type of validation should be performed in each layer. In addition, a question that often comes up is where authorization checks belong. The example scenario comes from an application for a catering business. Periodically during the day, a driver may turn in to the office any excess cash they've accumulated while taking the truck from site to site. The application allows a user to record the 'cash drop' by collecting the driver's ID, and the amount. Here's some skeleton code to illustrate the layers involved: public class CashDropApi // This is in the Service Facade Layer { [WebInvoke(Method = "POST")] public void AddCashDrop(NewCashDropContract contract) { // 1 Service.AddCashDrop(contract.Amount, contract.DriverId); } } public class CashDropService // This is the Application Service in the Domain Layer { public void AddCashDrop(Decimal amount, Int32 driverId) { // 2 CommandBus.Send(new AddCashDropCommand(amount, driverId)); } } internal class AddCashDropCommand // This is a command object in Domain Layer { public AddCashDropCommand(Decimal amount, Int32 driverId) { // 3 Amount = amount; DriverId = driverId; } public Decimal Amount { get; private set; } public Int32 DriverId { get; private set; } } internal class AddCashDropCommandHandler : IHandle<AddCashDropCommand> { internal ICashDropFactory Factory { get; set; } // Set by IoC container internal ICashDropRepository CashDrops { get; set; } // Set by IoC container internal IEmployeeRepository Employees { get; set; } // Set by IoC container public void Handle(AddCashDropCommand command) { // 4 var driver = Employees.GetById(command.DriverId); // 5 var authorizedBy = CurrentUser as Employee; // 6 var cashDrop = Factory.CreateCashDrop(command.Amount, driver, authorizedBy); // 7 CashDrops.Add(cashDrop); } } public class CashDropFactory { public CashDrop CreateCashDrop(Decimal amount, Employee driver, Employee authorizedBy) { // 8 return new CashDrop(amount, driver, authorizedBy, DateTime.Now); } } public class CashDrop // The domain object (entity) { public CashDrop(Decimal amount, Employee driver, Employee authorizedBy, DateTime at) { // 9 ... } } public class CashDropRepository // The implementation is in the Data Access Layer { public void Add(CashDrop item) { // 10 ... } } I've indicated 10 locations where I've seen validation checks placed in code. My question is what checks you would, if any, be performing at each given the following business rules (along with standard checks for length, range, format, type, etc): The amount of the cash drop must be greater than zero. The cash drop must have a valid Driver. The current user must be authorized to add cash drops (current user is not the driver). Please share your thoughts, how you have or would approach this scenario and the reasons for your choices.

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  • Advice on database design / SQL for retrieving data with chronological order

    - by Remnant
    I am creating a database that will help keep track of which employees have been on a certain training course. I would like to get some guidance on the best way to design the database. Specifically, each employee must attend the training course each year and my database needs to keep a history of all the dates on which they have attend the course in the past. The end user will use the software as a planning tool to help them book future course dates for employees. When they select a given employee they will see: (a) Last attendance date (b) Projected future attendance date(i.e. last attendance date + 1 calendar year) In terms of my database, any given employee may have multiple past course attendance dates: EmpName AttandanceDate Joe Bloggs 1st Jan 2007 Joe Bloggs 4th Jan 2008 Joe Bloggs 3rd Jan 2009 Joe Bloggs 8th Jan 2010 My question is what is the best way to set up the database to make it easy to retrieve the most recent course attendance date? In the example above, the most recent would be 8th Jan 2010. Is there a good way to use SQL to sort by date and pick the MAX date? My other idea was to add a column called ‘MostRecent’ and just set this to TRUE. EmpName AttandanceDate MostRecent Joe Bloggs 1st Jan 2007 False Joe Bloggs 4th Jan 2008 False Joe Bloggs 3rd Jan 2009 False Joe Bloggs 8th Jan 2010 True I wondered if this would simplify the SQL i.e. SELECT Joe Bloggs WHERE MostRecent = ‘TRUE’ Also, when the user updates a given employee’s attendance record (i.e. with latest attendance date) I could use SQL to: Search for the employee and set the MostRecent value to FALSE Add a new record with MostRecent set to TRUE? Would anybody recommended either method over the other? Or do you have a completely different way of solving this problem?

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  • Paging through records (json data) using jQuery...

    - by Pandiya Chendur
    I have a JSON result that contains numerous records. I'd like to show the first five records in one page and create pager links which have to move to that page with five record so on. I don't want the page to refresh which is why I'm hoping for a combination of JavaScript and jQuery. My json data looks like this: {"Table" : [ {"Emp_Id" : "3","Identity_No" : "","Emp_Name" : "Jerome","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Supervisior","Desig_Description" : "Supervisior of the Construction","SalaryBasis" : "Monthly","FixedSalary" : "25000.00"}, {"Emp_Id" : "4","Identity_No" : "","Emp_Name" : "Mohan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Acc ","Desig_Description" : "Accountant","SalaryBasis" : "Monthly","FixedSalary" : "200.00"}, {"Emp_Id" : "5","Identity_No" : "","Emp_Name" : "Murugan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "150.00"}, {"Emp_Id" : "6","Identity_No" : "","Emp_Name" : "Ram","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "120.00"}, {"Emp_Id" : "7","Identity_No" : "","Emp_Name" : "Raja","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "135.00"}, {"Emp_Id" : "8","Identity_No" : "","Emp_Name" : "Raja kumar","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason Helper","Desig_Description" : "Mason Helper","SalaryBasis" : "Weekly","FixedSalary" : "105.00"}, {"Emp_Id" : "9","Identity_No" : "","Emp_Name" : "Lakshmi","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason Helper","Desig_Description" : "Mason Helper","SalaryBasis" : "Weekly","FixedSalary" : "100.00"}, {"Emp_Id" : "10","Identity_No" : "","Emp_Name" : "Palani","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Carpenter","Desig_Description" : "Carpenter","SalaryBasis" : "Weekly","FixedSalary" : "200.00"}, {"Emp_Id" : "11","Identity_No" : "","Emp_Name" : "Annamalai","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Carpenter","Desig_Description" : "Carpenter","SalaryBasis" : "Weekly","FixedSalary" : "220.00"}, {"Emp_Id" : "12","Identity_No" : "","Emp_Name" : "David","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Fixer","Desig_Description" : "Steel Fixer","SalaryBasis" : "Weekly","FixedSalary" : "220.00"}, {"Emp_Id" : "13","Identity_No" : "","Emp_Name" : "Chandru","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Fixer","Desig_Description" : "Steel Fixer","SalaryBasis" : "Weekly","FixedSalary" : "220.00"}, {"Emp_Id" : "14","Identity_No" : "","Emp_Name" : "Mani","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Helper","Desig_Description" : "Steel Helper","SalaryBasis" : "Weekly","FixedSalary" : "175.00"}, {"Emp_Id" : "15","Identity_No" : "","Emp_Name" : "Karthik","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Fixer","Desig_Description" : "Wood Fixer","SalaryBasis" : "Weekly","FixedSalary" : "195.00"}, {"Emp_Id" : "16","Identity_No" : "","Emp_Name" : "Bala","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Fixer","Desig_Description" : "Wood Fixer","SalaryBasis" : "Weekly","FixedSalary" : "185.00"}, {"Emp_Id" : "17","Identity_No" : "","Emp_Name" : "Tamil arasi","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Helper","Desig_Description" : "Wood Helper","SalaryBasis" : "Weekly","FixedSalary" : "185.00"}, {"Emp_Id" : "18","Identity_No" : "","Emp_Name" : "Perumal","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Cook","Desig_Description" : "Cook","SalaryBasis" : "Weekly","FixedSalary" : "105.00"}, {"Emp_Id" : "19","Identity_No" : "","Emp_Name" : "Andiappan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Watchman","Desig_Description" : "Watchman","SalaryBasis" : "Weekly","FixedSalary" : "150.00"} ] } And as of now my result looks like this, http://img401.imageshack.us/img401/2500/yuidtsum.jpg I have used jQuery for this: var jsonObj = JSON.parse(HfJsonValue); for (var i = jsonObj.Table.length - 1; i >= 0; i--) { var employee = jsonObj.Table[i]; $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>') .insertAfter('#ResultsDiv'); } My image contains only 6 records as of now. Any suggestions?

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  • Sharp architecture; Accessing Validation Results

    - by nabeelfarid
    I am exploring Sharp Architecture and I would like to know how to access the validation results after calling Entity.IsValid(). I have two scenarios e.g. 1) If the entity.IsValid() return false, I would like to add the errors to ModelState.AddModelError() collection in my controller. E.g. in the Northwind sample we have an EmployeesController.Create() action when we do employee.IsValid(), how can I get access to the errors? public ActionResult Create(Employee employee) { if (ViewData.ModelState.IsValid && employee.IsValid()) { employeeRepository.SaveOrUpdate(employee); } // .... } [I already know that when an Action method is called, modelbinder enforces validation rules(nhibernate validator attributes) as it parses incoming values and tries to assign them to the model object and if it can't parse the incoming values  then it register those as errors in modelstate for each model object property. But what if i have some custom validation. Thats why we do ModelState.IsValid first.] 2) In my test methods I would like to test the nhibernate validation rules as well. I can do entity.IsValid() but that only returns true/ false. I would like to Assert against the actual error not just true/ false. In my previous projects, I normally use a wrapper Service Layer for Repositories, and instead of calling Repositories method directly from controller, controllers call service layer methods which in turn call repository methods. In my Service Layer all my custom validation rules resides and Service Layer methods throws a custom exception with a NameValueCollection of errors which I can easily add to ModelState in my controller. This way I can also easily implement sophisticated business rules in my service layer as well. I kow sharp architecture also provides a Service Layer project. But what I am interested in and my next question is: How I can use NHibernate Vaidators to implement sophisticated custom business rules (not just null,empty, range etc.) and make Entity.IsValid() to verify those rules too ?

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  • Paging Through Records(json data) Using jQuery...

    - by Pandiya Chendur
    I have a JSON result that contains numerous records. I'd like to show the first five records in one page and create pager links which have to move to that page with five record so on. I don't want the page to refresh which is why I'm hoping a combination of JavaScript and jQuery... My json Data looks like this... {"Table" : [{"Emp_Id" : "3","Identity_No" : "","Emp_Name" : "Jerome","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Supervisior","Desig_Description" : "Supervisior of the Construction","SalaryBasis" : "Monthly","FixedSalary" : "25000.00"},{"Emp_Id" : "4","Identity_No" : "","Emp_Name" : "Mohan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Acc ","Desig_Description" : "Accountant","SalaryBasis" : "Monthly","FixedSalary" : "200.00"},{"Emp_Id" : "5","Identity_No" : "","Emp_Name" : "Murugan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "150.00"},{"Emp_Id" : "6","Identity_No" : "","Emp_Name" : "Ram","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "120.00"},{"Emp_Id" : "7","Identity_No" : "","Emp_Name" : "Raja","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "135.00"},{"Emp_Id" : "8","Identity_No" : "","Emp_Name" : "Raja kumar","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason Helper","Desig_Description" : "Mason Helper","SalaryBasis" : "Weekly","FixedSalary" : "105.00"},{"Emp_Id" : "9","Identity_No" : "","Emp_Name" : "Lakshmi","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason Helper","Desig_Description" : "Mason Helper","SalaryBasis" : "Weekly","FixedSalary" : "100.00"},{"Emp_Id" : "10","Identity_No" : "","Emp_Name" : "Palani","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Carpenter","Desig_Description" : "Carpenter","SalaryBasis" : "Weekly","FixedSalary" : "200.00"},{"Emp_Id" : "11","Identity_No" : "","Emp_Name" : "Annamalai","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Carpenter","Desig_Description" : "Carpenter","SalaryBasis" : "Weekly","FixedSalary" : "220.00"},{"Emp_Id" : "12","Identity_No" : "","Emp_Name" : "David","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Fixer","Desig_Description" : "Steel Fixer","SalaryBasis" : "Weekly","FixedSalary" : "220.00"},{"Emp_Id" : "13","Identity_No" : "","Emp_Name" : "Chandru","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Fixer","Desig_Description" : "Steel Fixer","SalaryBasis" : "Weekly","FixedSalary" : "220.00"},{"Emp_Id" : "14","Identity_No" : "","Emp_Name" : "Mani","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Helper","Desig_Description" : "Steel Helper","SalaryBasis" : "Weekly","FixedSalary" : "175.00"},{"Emp_Id" : "15","Identity_No" : "","Emp_Name" : "Karthik","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Fixer","Desig_Description" : "Wood Fixer","SalaryBasis" : "Weekly","FixedSalary" : "195.00"},{"Emp_Id" : "16","Identity_No" : "","Emp_Name" : "Bala","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Fixer","Desig_Description" : "Wood Fixer","SalaryBasis" : "Weekly","FixedSalary" : "185.00"},{"Emp_Id" : "17","Identity_No" : "","Emp_Name" : "Tamil arasi","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Helper","Desig_Description" : "Wood Helper","SalaryBasis" : "Weekly","FixedSalary" : "185.00"},{"Emp_Id" : "18","Identity_No" : "","Emp_Name" : "Perumal","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Cook","Desig_Description" : "Cook","SalaryBasis" : "Weekly","FixedSalary" : "105.00"},{"Emp_Id" : "19","Identity_No" : "","Emp_Name" : "Andiappan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Watchman","Desig_Description" : "Watchman","SalaryBasis" : "Weekly","FixedSalary" : "150.00"}]} And as of now my result looks like this, http://img401.imageshack.us/img401/2500/yuidtsum.jpg I have used jquery for this, var jsonObj = JSON.parse(HfJsonValue); for (var i = jsonObj.Table.length - 1; i >= 0; i--) { var employee = jsonObj.Table[i]; $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>').insertAfter('#ResultsDiv'); } My image contains only 6 records as of now.. Any suggestions?

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  • Sorting in SSRS Reports overriding Group sorting

    - by Siva
    I am new to SSRS (2005) and am creating my first report. I need to create a group-based running value but is sorted or some other field. For example, from the data below |Employee| Day |Hours|Salary| |E1 | 1.1 | 5 | 5 | |E2 | 1.2 | 6 | 6 | |E3 | 1.3 | 7 | 7 | |E2 | 2.1 | 6 | 12 | |E1 | 2.2 | 5 | 10 | |E3 | 2.3 | 7 | 14 | |E3 | 3.1 | 7 | 21 | |E2 | 3.2 | 6 | 18 | I am calculating the salary to be a running value on hours grouped by employee, which works fine. The problem is I want the report to be sorted on the Day column. If I use the Day as a sorting criteria in the employee group, the report is grouped on the employee, but within the group, the data is sorted on the Day column. Is there a way to build the report and then finally sort the report on the day column ? Please let me know in case I am unclear. Thanks a lot! Siva.

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  • Good jquery pagination plugin to use with json Data...

    - by bala3569
    I am looking for a good jquery pagination plugin to use in my aspx page.... I have the following parameters currentpage,pagesize,TotalRecords,NumberofPages... I would like my plugin to same as stackoverflow paging .... EDIT: It should paginate through json data.... similar to this I use my json data and iterating with jquery var jsonObj = jQuery.parseJSON(HfJsonValue); for (var i = jsonObj.Table.length - 1; i >= 0; i--) { var employee = jsonObj.Table[i]; $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>').insertAfter('#ResultsDiv'); } There are 25 divs in my page as a result i want to show first five divs in page 1 and so on... Any suggestion... My HfJsonValue contains the following json data {"Table" : [{"Emp_Id" : "3","Identity_No" : "","Emp_Name" : "Jerome","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Supervisior","Desig_Description" : "Supervisior of the Construction","SalaryBasis" : "Monthly","FixedSalary" : "25000.00"},{"Emp_Id" : "4","Identity_No" : "","Emp_Name" : "Mohan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Acc ","Desig_Description" : "Accountant","SalaryBasis" : "Monthly","FixedSalary" : "200.00"},{"Emp_Id" : "5","Identity_No" : "","Emp_Name" : "Murugan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "150.00"},{"Emp_Id" : "6","Identity_No" : "","Emp_Name" : "Ram","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "120.00"},{"Emp_Id" : "7","Identity_No" : "","Emp_Name" : "Raja","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "135.00"},{"Emp_Id" : "8","Identity_No" : "","Emp_Name" : "Raja kumar","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason Helper","Desig_Description" : "Mason Helper","SalaryBasis" : "Weekly","FixedSalary" : "105.00"},{"Emp_Id" : "9","Identity_No" : "","Emp_Name" : "Lakshmi","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason Helper","Desig_Description" : "Mason Helper","SalaryBasis" : "Weekly","FixedSalary" : "100.00"},{"Emp_Id" : "10","Identity_No" : "","Emp_Name" : "Palani","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Carpenter","Desig_Description" : "Carpenter","SalaryBasis" : "Weekly","FixedSalary" : "200.00"},{"Emp_Id" : "11","Identity_No" : "","Emp_Name" : "Annamalai","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Carpenter","Desig_Description" : "Carpenter","SalaryBasis" : "Weekly","FixedSalary" : "220.00"},{"Emp_Id" : "12","Identity_No" : "","Emp_Name" : "David","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Fixer","Desig_Description" : "Steel Fixer","SalaryBasis" : "Weekly","FixedSalary" : "220.00"},{"Emp_Id" : "13","Identity_No" : "","Emp_Name" : "Chandru","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Fixer","Desig_Description" : "Steel Fixer","SalaryBasis" : "Weekly","FixedSalary" : "220.00"},{"Emp_Id" : "14","Identity_No" : "","Emp_Name" : "Mani","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Helper","Desig_Description" : "Steel Helper","SalaryBasis" : "Weekly","FixedSalary" : "175.00"},{"Emp_Id" : "15","Identity_No" : "","Emp_Name" : "Karthik","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Fixer","Desig_Description" : "Wood Fixer","SalaryBasis" : "Weekly","FixedSalary" : "195.00"},{"Emp_Id" : "16","Identity_No" : "","Emp_Name" : "Bala","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Fixer","Desig_Description" : "Wood Fixer","SalaryBasis" : "Weekly","FixedSalary" : "185.00"},{"Emp_Id" : "17","Identity_No" : "","Emp_Name" : "Tamil arasi","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Helper","Desig_Description" : "Wood Helper","SalaryBasis" : "Weekly","FixedSalary" : "185.00"},{"Emp_Id" : "18","Identity_No" : "","Emp_Name" : "Perumal","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Cook","Desig_Description" : "Cook","SalaryBasis" : "Weekly","FixedSalary" : "105.00"},{"Emp_Id" : "19","Identity_No" : "","Emp_Name" : "Andiappan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Watchman","Desig_Description" : "Watchman","SalaryBasis" : "Weekly","FixedSalary" : "150.00"}]}

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  • Using XMLDecoder to cast Encoded XML to List<>

    - by Ender
    I am writing an application that reads in a large number of basic user details in the following format; once read in it then allows the user to search for a user's details using their email: NAME ROLE EMAIL --------------------------------------------------- Joe Bloggs Manager [email protected] John Smith Consultant [email protected] Alan Wright Tester [email protected] ... The problem I am suffering is that I need to store a large number of details of all people that have worked at the company. The file containing these details will be written on a yearly basis simply for reporting purposes, but the program will need to be able to access these details quickly. The way I aim to access these files is to have a program that asks the user for the name of the unique email of the member of staff and for the program to then return the name and the role from that line of the file. I've played around with text files, but am struggling with how I would handle multiple columns of data when it comes to searching this large file. What is the best format to store such data in? A text file? XML? The size doesn't bother me, but I'd like to be able to search it as quickly as possible. The file will need to contain a lot of entries, probably over the 10K mark over time. EDIT: I've decided to go with the XML serialisation method. I've managed to get the code for Encoding working perfectly, but the Decoding code below does not work. XMLDecoder d = new XMLDecoder( new BufferedInputStream(new FileInputStream("data.xml"))); List<Employee> list = (List<Employee>) d.readObject(); d.close(); for(Employee x : list) { if(x.getEmail().equals(userInput)) { // do stuff } } When the program hits List<Employee> list = (List<Employee>) d.readObject(); an exception is thrown claiming that "Employee cannot be cast to java.util.List". I've added a bounty to this and anyone that can help me solve this problem once and for all will get lots of lovely points. EDIT 2: I've looked a bit more into the problem and have come across Serialization as a potential answer. If anyone can look into this for me as I've no experience with Serialization or Deserialization I'd be very grateful. It can provide an Object with no problems whatsoever, but I really need to return it in the same format as it went in (List). EDIT 3: Ugh, this problem is really starting to drive me crazy and to be honest I'm starting to think that it's an unsolvable problem. If possible, could someone take a look at the code and help provide a solution for me?

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  • Binding custom property in Entity Framework

    - by deverop
    I have an employee entity in my EF model. I then added a class to the project to add a custom property public partial class Employee { public string Name { get { return string.Format("{0} {1}", this.FirstName, this.LastName); } } } On a aspx form (inside a FormView), I want to bind a DropDownList to the employee collection: <asp:Label runat="server" AssociatedControlID="ddlManagerId" Text="ManagerId" /> <asp:DropDownList ID="ddlManagerId" runat="server" DataSourceID="edsManagerId" DataValueField="Id" DataTextField="Name" AppendDataBoundItems="true" SelectedValue='<%# Bind("ManagerId") %>'> <asp:ListItem Text="-- Select --" Value="0" /> </asp:DropDownList> <asp:EntityDataSource ID="edsManagerId" runat="server" ConnectionString="name=Entities" DefaultContainerName="Entities" EntitySetName="Employees" EntityTypeFilter="Employee" EnableFlattening="true"> </asp:EntityDataSource> Unfortunately, when I fire up the page, I get an error: DataBinding: 'System.Web.UI.WebControls.EntityDataSourceWrapper' does not contain a property with the name 'Name'. Any ideas what I'm doing wrong?

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  • Nested forms and automatic creation of parent, children

    - by Karen
    Guys, I was wondering if it was possible to create new parent, children in a has many relationship, using rails nested forms. Rails documentation clearly says that this works in a one to one relationship. Not sure if its the same in has many relationship. For example: If params = { :employee => { :name => "Tester", :account_attributes => {:login => 'tester'} } } works as one to one relationship. So Employee.new(params) works fine. New employee, account are created. Supposing I had params = { :employee => { :name => "Tester", :account_attributes => { "0" => {:login => 'tester'}, "1" => {:login => 'tester2'} } } } Employee.new(params) doesnt work. It fails on child validations saying parent cant be blank. Any help is appreciated. Thanks Karen

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  • how to merge xml string to main xml document object

    - by CliffC
    how can i merge the following xml string <employee> <name>cliff</name> </employee> to my existing xml document object XmlDocument xmlDoc = new XmlDocument(); XmlElement xmlCompany = xmlDoc.CreateElement("Company"); the final output should look like <Company> <employee> <name>cliff</name> </employee> </Company> thanks

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  • Using datetime float representation as primary key

    - by devanalyst
    From my experience I have learn that using an surrogate INT data type column as primary key esp. an IDENTITY key column offers better performance than using GUID or char/varchar data type column as primary key. I try to use IDENTITY key as primary key wherever possible. But recently I came across a schema where the tables were horizontally partitioned and were managed via a Partitioned view. So the tables could not have an IDENTITY column since that would make the Partitioned View non updatable. One work around for this was to create a dummy 'keygenerator' table with an identity column to generate IDs for primary key. But this would mean having a 'keygenerator' table for each of the Partitioned View. My next thought was to use float as a primary key. The reason is the following key algorithm that I devised DECLARE @KEY FLOAT SET @KEY = CONVERT(FLOAT,GETDATE())/100000.0 SET @KEY = @EMP_ID + @KEY Heres how it works. CONVERT(FLOAT,GETDATE()) gives float representation of current datetime since internally all datetime are represented by SQL as a float value. CONVERT(FLOAT,GETDATE())/100000.0 converts the float representation into complete decimal value i.e. all digits are pushed to right side of ".". @KEY = @EMP_ID + @KEY adds the Employee ID which is an integer to this decimal value. The logic is that the Employee ID is guaranteed to be unique across sessions since an employee cannot connect to an application more than once at the same time. And for the same employee each time a key will be generated the current datetime will be unique. In all an unique key across all employee sessions and across time. So for Emp Ids 11 and 12, I have key values like 12.40046693321566357, 11.40046693542361111 But my concern whether float data type as primary key offer benefits compared to choosing GUID or char/varchar as primary keys. Also important thing is because of partitioning the float column is going to be part of a composite key.

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  • Synchronizing a collection of wrapped objects with a collection of unwrapped objects

    - by Kenneth Cochran
    I have two classes: Employee and EmployeeGridViewAdapter. Employee is composed of several complex types. EmployeeGridViewAdapter wraps a single Employee and exposes its members as a flattened set of system types so a DataGridView can handle displaying, editing, etc. I'm using VS's builtin support for turning a POCO into a data source, which I then attach to a BindingSource object. When I attach the DataGridView to the BindingSource it creates the expected columns and at runtime I can perform the expected CRUD operations. All is good so far. The problem is the collection of adapters and the collection of employees aren't being synchronized. So all the employees I create an runtime never get persisted. Here's a snippet of the code that generates the collection of EmployeeGridViewAdapter's: var employeeCollection = new List<EmployeeGridViewAdapter>(); foreach (var employee in this.employees) { employeeCollection.Add(new EmployeeGridViewAdapter(employee)); } this.view.Employees = employeeCollection; Pretty straight forward but I can't figure out how to synchronize changes back to the original collection. I imagine edits are already handled because both collections reference the same objects but creating new employees and deleting employees aren't happening so I can't be sure.

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  • getting the list of all functions executed like call stack in asp.net

    - by sridhar
    Hi, I am having trouble with debugging one of the problems that I am having in our website. This is the problem. I have a webpage that contains the photo of an employee and information related to the employee. When the user logins to our website, we are storing the details of the employee in session. I am setting the image url for the photo of an employee as follows. imgEEPhoto.ImageUrl = imgPhoto.aspx?Company=XXXX&Empno=YYYY. Inside the page imgPhoto.aspx, I am checking if the session is alive for that user. when I login to the page that has the employee photo sometimes the photo is not displayed. It is because I am checking whether the session is alive inside the imgPhoto.aspx page. sometimes the session is alive and sometimes the session is not alive. It looks like there is some function that is setting the session to null asynchronously. I am not knowing how to track that function. so I am thinking that inside the imgPhoto.aspx page, if I can get the list of all functions that have been executed so far, I could track the function that is resetting the session. Is there a way to find this? If there is no another way to debug this problem, please let me know. Thanks, sridhar.

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  • Serializing a part of object graph

    - by Felix
    Hi all, I have a problem regarding Java custom serialization. I have a graph of objects and want to configure where to stop when I serialize a root object from client to server. Let's make it a bit concrete, clear by giving a sample scenario. I have Classes of type Company Employee (abstract) Manager extends Employee Secretary extends Employee Analyst extends Employee Project Here are the relations: Company(1)---(n)Employee Manager(1)---(n)Project Analyst(1)---(n)Project Imagine, I'm on the client side and I want to create a new company, assign it 10 employees (new or some existing) and send this new company to the server. What I expect in this scenario is to serialize the company and all bounding employees to the server side, because I'll save the relations on the database. So far no problem, since the default Java serialization mechanism serializes the whole object graph, excluding the field which are static or transient. My goal is about the following scenario. Imagine, I loaded a company and its 1000 employees from the server to the client side. Now I only want to rename the company's name (or some other field, that directly belongs to the company) and update this record. This time, I want to send only the company object to the server side and not the whole list of employees (I just update the name, the employees are in this use case irrelevant). My aim also includes the configurability of saying, transfer the company AND the employees but not the Project-Relations, you must stop there. Do you know any possibility of achieving this in a generic way, without implementing the writeObject, readObject for every single Entity-Object? What would be your suggestions? I would really appreciate your answers. I'm open to any ideas and am ready to answer your questions in case something is not clear.

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