Search Results

Search found 94938 results on 3798 pages for 'one man army'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 15/3798 | < Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >

  • One-to-one Mapping issue with NHibernate/Fluent: Foreign Key not updateing

    - by Trevor
    Summary: Parent and Child class. One to one relationship between the Parent and Child. Parent has a FK property which references the primary key of the Child. Code as follows: public class NHTestParent { public virtual Guid NHTestParentId { get; set; } public virtual Guid ChildId { get { return ChildRef.NHTestChildId; } set { } } public virtual string ParentName { get; set; } protected NHTestChild _childRef; public virtual NHTestChild ChildRef { get { if (_childRef == null) _childRef = new NHTestChild(); return _childRef; } set { _childRef = value; } } } public class NHTestChild { public virtual Guid NHTestChildId { get; set; } public virtual string ChildName { get; set; } } With the following Fluent mappings: Parent Mapping Id(x => x.NHTestParentId); Map(x => x.ParentName); Map(x => x.ChildId); References(x => x.ChildRef, "ChildId").Cascade.All(); Child Mapping: Id(x => x.NHTestChildId); Map(x => x.ChildName); If I do something like (pseudo code) ... HTestParent parent = new NHTestParent(); parent.ParentName = "Parent 1"; parent.ChildRef.ChildName = "Child 1"; nhibernateSession.SaveOrUpdate(aParent); Commit; ... I get an error: "Invalid index 3 for this SqlParameterCollection with Count=3" If I change the parent 'References' line as follows (i.e. provide the name of the child property I'm pointing at): References(x => x.ChildRef, "ChildId").PropertyRef("NHTestChildId").Cascade.All(); I get the error: "Unable to resolve property: NHTestChildId" So, I tried the 'HasOne()' reference setting, as follows: HasOne<NHTestChild>(x => x.ChildRef).ForeignKey("ChildId").Cascade.All().Fetch.Join(); This results in the save working, but the load fails to find the child. If I inspect the SQL Nhibernate produces I can see that NHibernate is assuming the Primary key of the parent is the link to the child (i.e. load join condition is "parent.NHTestParentId = child.NHTestChildId). The 'ForeignKey' specified appears to be ignored. I can set any value and no error occurs - the join just always fails and no child is returned. I've tried a number of slight variations on the above. It seems like it should be a simple thing to achieve. Any ideas?

    Read the article

  • Storing Preferences/One-to-One Relationships in Database

    - by LnDCobra
    What is the best way to store settings for certain objects in my database? Method one: Using a single table Table: Company {CompanyID, CompanyName, AutoEmail, AutoEmailAddress, AutoPrint, AutoPrintPrinter} Method two: Using two tables Table Company {CompanyID, COmpanyName} Table2 CompanySettings{CompanyID, utoEmail, AutoEmailAddress, AutoPrint, AutoPrintPrinter}

    Read the article

  • Ruby on Rails: create records for multiple models with one form and one submit

    - by notblakeshelton
    I have a 3 models: quote, customer, and item. Each quote has one customer and one item. I would like to create a new quote, a new customer, and a new item in their respective tables when I press the submit button. I have looked at other questions and railscasts and either they don't work for my situation or I don't know how to implement them. I also want my index page to be the page where I can create everything. quote.rb class Quote < ActiveRecord::Base attr_accessible :quote_number has_one :customer has_one :item end customer.rb class Customer < ActiveRecord::Base #unsure of what to put here #a customer can have multiple quotes, so would i use: has_many :quotes #<----? end item.rb class Item < ActiveRecord::Base #also unsure about this #each item can also be in multiple quotes quotes_controller.rb class QuotesController < ApplicationController def index @quote = Quote.new @customer = Customer.new @item = item.new end def create @quote = Quote.new(params[:quote]) @quote.save @customer = Customer.new(params[:customer]) @customer.save @item = Item.new(params[:item]) @item.save end end items_controller.rb class ItemsController < ApplicationController def index end def new @item = Item.new end def create @item = Item.new(params[:item]) @item.save end end customers_controller.rb class CustomersController < ApplicationController def index end def new @customer = Customer.new end def create @customer = Customer.new(params[:customer]) @customer.save end end quotes/index.html.erb <%= form_for @quote do |f| %> <%= f.fields_for @customer do |builder| %> <%= label_tag :firstname %> <%= builder.text_field :firstname %> <%= label_tag :lastname %> <%= builder.text_field :lastname %> <% end %> <%= f.fields_for @item do |builder| %> <%= label_tag :name %> <%= builder.text_field :name %> <%= label_tag :description %> <%= builder.text_field :description %> <% end %> <%= label_tag :quote_number %> <%= f.text_field :quote_number %> <%= f.submit %> <% end %> When I try submitting that I get an error: Can't mass-assign protected attributes: item, customer So to try and fix it I updated the attr_accessible in quote.rb to include :item, :customer but then I get this error: Item(#) expected, got ActiveSupport::HashWithIndifferentAccess(#) Any help would be greatly appreciated.

    Read the article

  • ROOT_MISMATCH error after following FAQ directions

    - by Adko
    While using Ubuntu One in 11.04 I am unable to change my account info. When I made the switch to 11.04 I forgot that I already had an Ubuntu One account so, I made a new one. However, upon going through one of my email accounts I found my old Ubuntu One login information. I then attempted to switch the account associated with my desktop to my first email. Now, despite following the directions found at https://wiki.ubuntu.com/UbuntuOne/FAQ/WhatToDoWhenSyncdaemonSaysRootMismatch I continue to get the error "File sync error. (local and server roots are different (ROOT_MISMATCH))". Any help would be appreciated.

    Read the article

  • Does a mini PCIe SSD fit into a Acer Aspire One?

    - by Narcolapser
    Question: What, if any, mini PCIe SSDs fit into the mini PCIe slot of the Acer Aspire one AOD250? Info: I have an Aspire One and I've been considering loading it with an SSD. The mini PCIe drives fascinate me and so I want to try that approach. Also they tend to be cheaper and not much slower. (at least not on Read time which matters more for a netbook) But I've heard that some times computers don't support certain mini PCIe cards. And I was wondering if anyone knew about the Aspire One? I tried asking Acer tech support, but they didn't know jack and spent the whole time informing that I would have to support my Ubuntu install on my own, which I was. Anyway. Rant Aside, I'm looking at this drive: http://www.newegg.com/Product/Product.aspx?Item=N82E16820183252 It states it is exclusively for the Eee PC. now does that mean It was designed for the Eee PC but will work in my netbook. or is something going to go wrong? (like right now my concern is it physically not fitting.) Any information would be appreciated. o7

    Read the article

  • Two UIViews, one UIViewController (in one UINavigationController)

    - by jdandrea
    Given an iPhone app with a UITableViewController pushed onto a UINavigationController, I would like to add a right bar button item to toggle between the table view and an "alternate" view of the same data. Let's also say that this other view uses the same data but is not a UITableView. Now, I know variations on this question already exist on Stack Overflow. However, in this case, that alternate view would not be pushed onto the UINavigationController. It would be visually akin to flipping the current UIViewController's table view over and revealing the other view, then being able to flip back. In other words, it's intended to take up a single spot in the UINavigationController hierarchy. Moreover, whatever selection you ultimately make from within either view will push a common UIViewController onto the UINavigationController stack. Still more info: We don't want to use a separate UINavigationController just to handle this pair of views, and we don't want to split these apart via a UITabBarController either. Visually and contextually, the UX is meant to show two sides of the same coin. It's just that those two sides happen to involve their own View Controllers in normal practice. Now … it turns out I have already gone and quickly set this up to see how it might work! However, upon stepping back to examine it, I get the distinct impression that I went about it in a rather non-MVC way, which of course concerns me a bit. Here's what I did at a high level. Right now, I have a UIViewController (not a UITableViewController) that handles all commonalities between the two views, such as fetching the raw data. I also have two NIBs, one for each view, and two UIView objects to go along with them. (One of them is a UITableView, which is a kind of UIView.) I switch between the views using animation (easy enough). Also, in an effort to keep things encapsulated, the now-split-apart UITableView (not the UIViewController!) acts as its own delegate and data source, fetching data from the VC. The VC is set up as a weak, non-retained object in the table view. In parallel, the alternate view gets at the raw data from the VC in the exact same way. So, there are a few things that smell funny here. The weak linking from child to parent, while polite, seems like it might be wrong. Making a UITableView the table's data source and delegate also seems odd to me, thinking that a view controller is where you want to put that per Apple's MVC diagrams. As it stands now, it would appear as if the view knows about the model, which isn't good. Loading up both views in advance also seems odd, because lazy loading is no longer in effect. Losing the benefits of a UITableViewController (like auto-scrolling to cells with text fields) is also a bit frustrating, and I'd rather not reinvent the wheel to work around that as well. Given all of the above, and given we want that "flip effect" in the context of a single spot on a single UINavigationController, and given that both views are two sides of the same coin, is there a better, more obvious way to design this that I'm just happening to miss completely? Clues appreciated!

    Read the article

  • how to get the result query one by one in jsp and mysql

    - by user261002
    I am trying to implement as Online Mock exam in JSP, but I have a problem to get the questions one by one, it get connceted for the first time, and show me the first question and answers, but when I click on "next" again, it still show me the first question, I think by clicking on "next" it start querying again. please help me. this is my bean : database.SQLSelectStatement sqlselect; database.SQLSelectStatement sqlselect2; static ResultSet questions; static ResultSetMetaData rsm; static ResultSet answers; public void setConnection() throws SQLException { if (database.DatabaseManager.getInstance().connectionOK()) { sqlselect = new database.SQLSelectStatement("question", "question", "0"); sqlselect2 = new database.SQLSelectStatement("answers", "question_id", "0"); questions = sqlselect.executeWithNoCondition(); } } public int i=0; public String getQuestions() throws SQLException { String result = ""; rsm = questions.getMetaData(); for (int i = 0; i < rsm.getColumnCount(); i++) { result += "<th>" + rsm.getColumnName(i + 1) + "</th>"; } if (!questions.isLast()) { questions.next(); System.out.println(i+1); result += "<tr>"; result += "<td>" + questions.getInt(1) + "</td>"; result += "<td>" + questions.getString(2) + "</td>"; result += "</tr>"; result += "<tr>"; sqlselect2.setValue(String.valueOf(questions.getInt(1))); answers = sqlselect2.Execute(); while (answers.next()) { result += "<tr> <td colspan='2'><input type='radio' name='answer' value='" + answers.getString(2) + "'> " + answers.getString(2) + "</td></tr>"; } result += "</tr>"; answers.close(); } return result; } this is the HTML: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>JSP Page</title> </head> <body> <h1>JSP Page</h1> <jsp:useBean id="exam" class="exam.ExamQuestions"></jsp:useBean> <% exam.setConnection(); %> <form method="post"> <table > <%=exam.getQuestions()%> </table> <input type="submit" name="action" value="next"/> </form> <% String action = request.getParameter("action"); if ("next".equals(action)) { out.println(request.getParameter("answer")); } %> </body> </html>

    Read the article

  • Does HashMap provide a one to one correspondence?

    - by Roman
    I found the following statement: Map is an object that stores key/volume pairs. Given a key, you can find its value. Keys must be unique, but values may be duplicated. For example I have just one key/value pair (3,4). And now I put a new pair (3,5). It will remove the old pair. Right? But if I put (2,4) instead of (3,4) I will add a new pair of key/value to the HashMap. Right?

    Read the article

  • C++: Most common way to talk to one application from the other one

    - by MInner
    In bare outlines, I've got an application which looks through the directories at startup and creates special files' index - after that it works like daemon. The other application creates such 'special' files and places them in some directory. What way of informing the first application about a new file (to index it) is the most common, simple (the first one is run-time, so it shouldn't slow it too much), and cross-platform if it is possible? I've looked through RPC and IPC but they are too heavy (also non-cross-platform and slow (need a lot of features to work - I need a simple light well-working way), probably).

    Read the article

  • Selecting one object from a one-to-many relationship in Hibernate

    - by Nick Thomson
    I have two tables: Job job_id, <other data> Job_Link job_link_id, job_id, start_timestamp, end_timestamp, <other data> There may be multiple records in Job_Link specifying the same job_id with the start_timestamp and end_timestamps to indicate when those records are considered "current", it is guaranteed that start_timestamp and end_timestamp will not overlap. We have entities for both the Job and Job_Link tables and defining a one-to-many relationship to load all the job_links wouldn't be a problem. However we'd like to avoid that and have a single job_link item in the Job entity that will contain only the "current" Job_Link object. Is there any way to achive that?

    Read the article

  • Are Motherboards for the Acer Aspire One AOA150 Netbook Compatible with the AOA110?

    - by Mindstormscreator
    I have an Acer Aspire One ZG5 AOA110-1588 netbook, and the motherboard doesn't have a port for a SATA 2.5 inch hard drive; it only supports this slow 8GB SSD type drive. Through research I've discovered that the AOA150 motherboards do have a SATA slot, and the bottom plate of these laptops have an appropriate protrusion for the drive to fit in (for example, compare this to this). The AOA110 and AOA150 models are very similar in appearance and specs. I've even seen tutorials that involve soldering a SATA connector onto the AOA110's motherboard, essentially creating an AOA150 motherboard (right?) So, could I just swap out the motherboard in my netbook with the MBS0506001? (I'd post another link to the actual board but can't because of the spam prevention...) I assume I would also need to purchase and replace the bottom cover with a larger one and possibly get a hard drive caddy as well...? Thanks!

    Read the article

  • How to connect to a PEAP GTC wifi network with Android 2.2 on a nexus one?

    - by Glen
    Hi, I recently updated my nexus one to 2.2. Now I can't connect to my uni's wifi. They use PEAP with GTC. I had it working fine on 2.1. Also it works fine on my Ubuntu laptop. I have entered my uni number (user name) in the identity box. I have entered my password in the password box. I have emailed the certificated that works on Ubuntu to my self and installed it on the nexus one. I have enabled secure credentials. What am I doing wrong? Thanks, Glen.

    Read the article

  • Cloud storage services offering one-time download links? [closed]

    - by TARehman
    Is anyone aware of consumer-targeted cloud storage services that allow users to generate a one-time download link for hosted files? Case in point: I have an encrypted container with some documents I need to send to a vendor. I would prefer to give them a one-time download link, so that I know when they have accessed the file, and then inform them of the passphrase by phone. I have heard that MediaFire offers 1-time links, but that they are buried in tons of advertising. At the moment, I'm not sure that I consider MediaFire fully legitimate; I'm more interested in solutions with Google Drive, Box.net, DropBox, etc.

    Read the article

  • Oracle ACE????????

    - by Kazuhiro.Yamaguchi
    ?????????Oracle ACE?????????????????????????????2????????????????,?????????????????????????????????????????????????????????????????????????? ·?????? ·11g R2 for Windows ?????? ?????????????????????????????????????????????????????????????????????????????????50?????????????????????????????????????????????????????????????????????????! ???????????????????????????????????? wmo6hash::blog 2010/05/29(Sat) Iron Man 2 ????????????????(?)?????????????????????????????????????????????????????? ????: ????????????????????????????????????????????????????????????????????????????????????????????????????????2????????????????????????????????????????????????????????????????????CEO ????????????????????????????????????????????????????????????? ????: ?(??????)1?????????????!?????Marvel????????????????????????????·??????????????·???????????????????????????2????????·?????????????????????????????????????????????????(?)???????????????????????????????·???????????????????AI???????????IT??????????CEO????·????????????!?????????????????????????????(?)?????????????????? Oracle ACE???????????????????!(???:??????:????) ??????????????2???????????????????????????????????????????????? ???????2???????? - 3????=3????????! ????????????????????????????????·??????????????????????????????????????????????????????????·????????????SF????·?????????????????????????????????????

    Read the article

  • Entity Framework: insert with one-to-one reference

    - by bomortensen
    Hi 'overflow! I'm having a bit trouble inserting into a mssql database using Entity Framework. There's two tables that I want to insert into, where one of table 1s fields is a foreign key in table2. This is the code I have so far: Media media = null; foreach(POI p in poiList) { media = new Media() { Path = p.ImagePath, Title = p.Title }; if (media != null && !context.Media.Any(me => me.Title == p.ImageTitle)) { context.AddToMedia(media); context.SaveChanges(); } PointOfInterest poi = new PointOfInterest() { Altitude = 2000.0, ID = p.ID, Latitude = p.Latitude, Longitude = p.Longitude, LatitudeRoute = p.LatitudeRoute, LongitudeRoute = p.LongitudeRoute, Description = p.Description, Title = p.Title, DefaultImageID = media.ID, }; context.AddToPointOfInterest(poi); } context.SaveChanges(); The following gives me this error: An object with the same key already exists in the ObjectStateManagerAn object with the same key already exists in the ObjectStateManager I'm still learning how to use the entity framework, so I don't even know if this would be the right approach to insert into two referenced tables. Can anyone enlighten me on this? :) Any help would be greatly appreciated! Thanks!

    Read the article

  • PHP/MySQL - Working with two databases, one shared and one local to an instance of application

    - by Extrakun
    The situation: Using a off-the-shelf PHP application, I have to add in a new module for extra functionality. Today, it is made known that eventually four different instances of the application are to be deployed, but the data from the new functionality is to be shared among those 4 instances. Each instance should still have their own database for users, content and etc. So the data for the new functionality goes into a 'shared' database. The data for the application (user login, content, uploads) go into a 'local' database To make things more complex, the new module I am writing will fetch data from the local DB and the shared DB at the same time. A re-write of the base application will take too long. I only have control over the new module which I am writing. The ideal solution: Is there a way to encapsulate 2 databases into one name using MySQL? I do not wish to switch DB connections or specifically name the DB to query from inside my SQL statements. The application uses a DB wrapper, so I am able to change it somehow so I can invisibly attempt to read/write to two different DB. What is the best way to handle this problem?

    Read the article

  • Entity Framework one-to-one relationship mapping flattened in code

    - by Josh Close
    I have a table structure like so. Address: AddressId int not null primary key identity ...more columns AddressContinental: AddressId int not null primary key identity foreign key to pk of Address County State AddressInternational: AddressId int not null primary key identity foreign key to pk of Address ProvinceRegion I don't have control over schema, this is just the way it is. Now, what I want to do is have a single Address object. public class Address { public int AddressId { get; set; } public County County { get; set; } public State State { get; set } public ProvinceRegion { get; set; } } I want to have EF pull it out of the database as a single entity. When saving, I want to save the single entity and have EF know to split it into the three tables. How would I map this in EF 4.1 Code First? I've been searching around and haven't found anything that meets my case yet. UPDATE An address record will have a record in Address and one in either AddressContinental or AddressInternational, but not both.

    Read the article

  • When destroying one record, another one gets destroyed

    - by normalocity
    Products (like an iPod Classic) :has_many = :listings, :dependent = :destroy Listings (like "My name is Joe, and I have an iPod for sale) :belongs_to = :product So, if I delete a given Product, all the listings that point to it get deleted. That makes sense, and is by design. However, I am writing a "merge" function, where you merge two Products into one, and combine their Listings. So, let's say my two products are "iPod Color" and "iPod Classic", and I want to merge the two. What I want to do is say, "iPod Color, merge into iPod Classic", and result should be that: All the iPod Color Listings are re-pointed to the iPod Classic product After the product_id change, the Listing(s) are saved I then delete the "iPod Color" product Well, that should all work fine, without deleting any Listings. However, I've got this controller, and for whatever reason when I destroy the "iPod Color" Product, even after confirming that the Listings have been moved to "iPod Classic" and saved to the database, the Listings that were previously pointed to "iPod Color" get destroyed as well, and I can't figure out why. It's as if they are retaining some kind of link to the destroyed product, and therefore begin destroyed themselves. What painfully obvious thing am I missing? def merge merging_from = Product.find(params[:id]) merging_to = Product.find_by_model(params[:merging_to]) unless merging_to.nil? unless merging_from.nil? unless merging_from == merging_to # you don't want to merge something with itself merging_from.listings.each do |l| l.product = merging_to l.save end # through some debugging, I've confirmed that my missing Listings are disappearing as a result of the following destroy call merging_from.destroy end end end

    Read the article

  • XSLT, process elements one by one

    - by qui
    Hi I am quite weak at XSLT so this might seem obvious. Here is some sample XML <term> <name>cholecystocolonic fistula</name> <definition>blah blah</definition> <reference>cholecystocolostomy</reference> </term> And here is the XSLT I wrote a while ago to process it <xsl:template name="term"> { "dictitle": "<xsl:value-of select="name" disable-output-escaping="yes" />", "html": "<xsl:value-of select="definition" disable-output-escaping="yes"/>", "referece": "<xsl:value-of select="reference" disable-output-escaping="yes"/> } </xsl:template> Basically I am creating JSON from the XML. The requirements have now changed so that now the XML can have more than one definition tag and reference tag. They can appear in any order, i.e definition, reference, reference, definition, reference. How can I update the XSLT to accommodate this? Probably worth mentioning that because my XSLT processor is using .NET I can only use XSLT 1.0 commands. Many thanks!

    Read the article

  • Vim hanging after parsing .vimrc (even a blank one) file on Solaris 10

    - by Seamus
    Hello all, I am having a problem with vim 7.2 hanging (for about 10 seconds) after it parses the .vimrc file. I had a similar issue in the past with tcsh on linux, but it was resolved by setting TERM to xterm-color. The same does not resolve the issue here. Any idea what may be causing this? $ env USER=redacted LOGNAME=redacted HOME=/home/redacted PATH=redacted MAIL=/var/spool/mail/redacted SHELL=/bin/tcsh TZ=redacted LC_COLLATE=C SSH_CLIENT=redacted SSH_CONNECTION=redacted SSH_TTY=/dev/pts/11 TERM=dtterm HOSTTYPE=sun4 VENDOR=sun OSTYPE=solaris MACHTYPE=sparc SHLVL=1 PWD=/home/redacted GROUP=redacted HOST=redacted REMOTEHOST=redacted QUOTA_CHECKED=1 WHOAMI=redacted HOSTNAME=redacted EDITOR=vim PRINTER=redacted INFOPATH=/software/gnu/gcc/2.8.1/sun4os5.10/info:/software/gnu/sun4os5/info:/software/gnu/emacs/20.3.1/sun4os5/info:/software/gnuish/sun4os5/info:/usr/local/gnu/info MANPATH=/software/gnu/gcc/2.8.1/sun4os5.10/man:/software/gnu/sun4os5/man:/software/gnu/emacs/20.3.1/sun4os5/man:/opt/rational/clearcase/doc/man:/usr/openwin/man:/usr/share/man:/usr/local/man:/usr/dt/man:/software/gnuish/sun4os5/man H_ARCH=sun4 H_ARCHOS=sun4os5 H_ARCHOS_SUB=sun4os5.10 H_OSTYPE=SUNOS H_OSREV=51000 T_ARCH=sun4 T_ARCHOS=sun4os5 T_ARCHOS_SUB=sun4os5.10 T_OSTYPE=SUNOS T_OSREV=51000 X11HOME=/usr/local/x11/sun4os5 OPENWINHOME=/usr/openwin LD_LIBRARY_PATH=/usr/dt/lib:/usr/openwin/lib MOTIFHOME=/usr/dt XINITRC=/usr/openwin/lib/Xinitrc GCC_REV=281

    Read the article

  • how to pass one variable value frm one class to the oder

    - by Arunabha
    i hav two packages one is com.firstBooks.series.db.parser which hav a java file XMLParser.java,i hav another package com.firstBooks.series79 which hav a class called AppMain.NW i want to send the value of a variable called _xmlFileName frm AppMain class to the xmlFile variable in XMLParser class,i am posting the codes for both the class,kindly help me. package com.firstBooks.series.db.parser; import java.io.IOException; import java.io.InputStream; import java.util.Vector; import net.rim.device.api.xml.parsers.DocumentBuilder; import net.rim.device.api.xml.parsers.DocumentBuilderFactory; import net.rim.device.api.xml.parsers.ParserConfigurationException; import org.w3c.dom.Document; import org.w3c.dom.Element; import org.w3c.dom.NodeList; import org.xml.sax.SAXException; import com.firstBooks.series.db.Question; public class XMLParser { private Document document; public static Vector questionList; public static String xmlFile; public XMLParser() { questionList = new Vector(); } public void parseXMl() throws SAXException, IOException, ParserConfigurationException { // Build a document based on the XML file. DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); InputStream inputStream = getClass().getResourceAsStream(xmlFile); document = builder.parse(inputStream); } public void parseDocument() { Element element = document.getDocumentElement(); NodeList nl = element.getElementsByTagName("question"); if (nl != null && nl.getLength() > 0) { for (int i = 0; i < nl.getLength(); i++) { Element ele = (Element) nl.item(i); Question question = getQuestions(ele); questionList.addElement(question); } } } private Question getQuestions(Element element) { String title = getTextValue(element, "title"); String choice1 = getTextValue(element, "choice1"); String choice2 = getTextValue(element, "choice2"); String choice3 = getTextValue(element, "choice3"); String choice4 = getTextValue(element, "choice4"); String answer = getTextValue(element, "answer"); String rationale = getTextValue(element, "rationale"); Question Questions = new Question(title, choice1, choice2, choice3, choice4, answer, rationale); return Questions; } private String getTextValue(Element ele, String tagName) { String textVal = null; NodeList nl = ele.getElementsByTagName(tagName); if (nl != null && nl.getLength() > 0) { Element el = (Element) nl.item(0); textVal = el.getFirstChild().getNodeValue(); } return textVal; } } Nw the code for AppMain class //#preprocess package com.firstBooks.series79; import net.rim.device.api.ui.UiApplication; import com.firstBooks.series.ui.screens.HomeScreen; public class AppMain extends UiApplication { public static String _xmlFileName; public static boolean _Lite; public static int _totalNumofQuestions; public static void initialize(){ //#ifndef FULL /* //#endif _xmlFileName = "/res/Series79_FULL.xml"; _totalNumofQuestions = 50; _Lite = false; //#ifndef FULL */ //#endif //#ifndef LITE /* //#endif _xmlFileName = "/res/Series79_LITE.xml"; _totalNumofQuestions = 10; _Lite = true; //#ifndef LITE */ //#endif } private AppMain() { initialize(); pushScreen(new HomeScreen()); } public static void main(String args[]) { new AppMain().enterEventDispatcher(); } }

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >