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• Working with a list, performing arithmetic logic in Python

  - by haea ohoh

  Suppose I have made a large list of numbers, and I want to make another one which I will add, pairwise, with the first list. Here's the first list, A: [109, 77, 57, 34, 94, 68, 96, 72, 39, 67, 49, 71, 121, 89, 61, 84, 45, 40, 104, 68, 54, 60, 68, 62, 91, 45, 41, 118, 44, 35, 53, 86, 41, 63, 111, 112, 54, 34, 52, 72, 111, 113, 47, 91, 107, 114, 105, 91, 57, 86, 32, 109, 84, 85, 114, 48, 105, 109, 68, 57, 78, 111, 64, 55, 97, 85, 40, 100, 74, 34, 94, 78, 57, 77, 94, 46, 95, 60, 42, 44, 68, 89, 113, 66, 112, 60, 40, 110, 89, 105, 113, 90, 73, 44, 39, 55, 108, 110, 64, 108] And here's B: [35, 106, 55, 61, 81, 109, 82, 85, 71, 55, 59, 38, 112, 92, 59, 37, 46, 55, 89, 63, 73, 119, 70, 76, 100, 49, 117, 77, 37, 62, 65, 115, 93, 34, 107, 102, 91, 58, 82, 119, 75, 117, 34, 112, 121, 58, 79, 69, 68, 72, 110, 43, 111, 51, 102, 39, 52, 62, 75, 118, 62, 46, 74, 77, 82, 81, 36, 87, 80, 56, 47, 41, 92, 102, 101, 66, 109, 108, 97, 49, 72, 74, 93, 114, 55, 116, 66, 93, 56, 56, 93, 99, 96, 115, 93, 111, 57, 105, 35, 99] How might I generate the arithmatic addition logic, processing each pairwise value one by one (A[0] and B[0], through A[99], B[99]) and producing the list C (A[0] + B[0] through A[99]+ B[99])?

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• Creating a dictionary with list of lists in Python

  - by ghbhatt

  I have a huge file (with around 200k inputs). The inputs are in the form: A B C D B E F C A B D D I am reading this file and storing it in a list as follows: text = f.read().split('\n') This splits the file whenever it sees a new line. Hence text is like follows: [[A B C D] [B E F] [C A B D] [D]] I have to now store these values in a dictionary where the key values are the first element from each list. i.e the keys will be A, B, C, D. I am finding it difficult to enter the values as the remaining elements of the list. i.e the dictionary should look like: {A: B C D; B: E F; C: A B D; D: 0} I have done the following: inlinkDict = {} for doc in text: adoc= doc.split(' ') docid = adoc[0] inlinkDict[docid] = inlinkDict.get(docid,0) + {I do not understand what to put in here} Please help as to how should i add the values to my dictionary. It should be 0 if there are no elements in the list except for the one which will be the key value. Like in example for 0.

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• How to update data in the user information list when using FBA

  - by Flo

  I've got to support a SharePoint web application which uses FBA with a custom membership and a custom role provider to authenticate the user against two different LDAPs. The user data are only stored in the user information lists. The SSP user profiles are not used. Now one of the users got married and therefore her surname got changed in the LDAP (the one where her information are stored). But this change doesn't get provisioned into the user information list. I wondering what option I have to provision changes of user data to the user information list. I've already tried to update the last name of the user manually, but it seems as if certain information like surname, first name are not editable in the user information list. I tried to edit them as a site administrator. So what option do I have to solve this problem? Being able to edit the information per hand would also be a solution but of course not the most preferred one.

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• Searching a large list of words in another large list

  - by Christian

  I have a list of 1,000,000 strings with a maximum length of 256 with protein names. Every string has an associated ID. I have another list of 4,000,000,000 strings with a maximum length of 256 with words out of articles and every word has an ID. I want to find all matches between the list of protein names and the list of words of the articles. Which algorithm should I use? Should I use some prebuild API? It would be good if the algorithm runs on a normal PC without special hardware.

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• Make list from two database items

  - by unnamet

  I want to make a list from some data that I have in my database. The first two sets of data in my database are first name and last name. I want my list to show both first and last name instead of now where it only shows the first name. How do I do that? My code looks like this: private void fillData() { Cursor contactCursor = mDbHelper.fetchAllReminders(); startManagingCursor(contactCursor); String[] from = new String[]{DbAdapter.KEY_FIRST}; int[] to = new int[]{R.id.contactlist}; SimpleCursorAdapter contacts = new SimpleCursorAdapter(this, R.layout.list, contactCursor, from, to); setListAdapter(contacts); }

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• Python 3: unpack inner lists in list comprehension

  - by Beau Martínez

  I'm running the following code on a list of strings to return a list of its words: words = [re.split('\\s+', line) for line in lines] However, I end up getting something like: [['import', 're', ''], ['', ''], ['def', 'word_count(filename):', ''], ...] As opposed to the desired: ['import', 're', '', '', '', 'def', 'word_count(filename):', '', ...] How can I unpack the lists re.split('\\s+', line) produces in the above list comprehension? Naïvely, I tried using * but that doesn't work. (I'm looking for a simple and Pythonic way of doing; I was tempted to write a function but I'm sure the language accommodates for this issue.)

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• Converting array to list in Java

  - by Alexandru

  How do I convert an array to a list in Java? I used the Arrays.asList() but the behavior (and signature) somehow changed from 1.4.2 to 1.5.0 and most snippets I found on the web use the 1.4.2 behaviour. For example: int[] spam = new int[] { 1, 2, 3 }; Arrays.asList(spam) on 1.4.2 returns a list containing the elements 1, 2, 3 on 1.5.0 returns a list containing the array spam In many cases it should be easy to detect, but sometimes it can slip unnoticed: Assert.assertTrue(Arrays.asList(spam).indexOf(4) == -1);

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• Comparing two List<MyClass> in C#

  - by Matt

  I have a class called MyClass This class inherits IEquatable and implements equals the way I need it to. (Meaning: when I compare two MyClass tyupe objects individually in code, it works) I then create two List: var ListA = new List<MyClass>(); var ListB = new List<MyClass>(); // Add distinct objects that are equal to one another to // ListA and ListB in such a way that they are not added in the same order. When I go to compare ListA and ListB, should I get true? ListA.Equals(ListB)==true; //???

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• How to set dropdown list by another dropdown list

  - by NewGuy

  I have two dropdown list (let's say there ids are ddl1 and ddl2). How can I set dropdown list 1 (ddl1) equals dropdown list 2 (ddl2) in jQuery? Something like: $('#ddl1').val()=$('#ddl2).val() Thanks in advance.

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• Sorting list of URLs by length in Jython

  - by Eef

  Hi, I am writing a Jython script to sort a list of URLs. I have a list that looks like this: http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 The pipe and the comma separates the path from the amount of files that are under that path. Is it possible some how use Jython to order the URLs by length, so it would end up look like the below list: http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 Hope you guys get what I mean, any help would be appreciated. Cheers

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• Racket list in struct

  - by Tim

  I just started programming with Racket and now I have the following problem. I have a struct with a list and I have to add up all prices in the list. (define-struct item (name category price)) (define some-items (list (make-item "Book1" 'Book 40.97) (make-item "Book2" 'Book 5.99) (make-item "Book3" 'Book 20.60) (make-item "Item" 'KitchenAccessory 2669.90))) I know that I can return the price with: (item-price (first some-items)) or (item-price (car some-items)). The problem is, that I dont know how I can add up all Items prices with this. Answer to Óscar López: May i filled the blanks not correctly, but Racket mark the code black when I press start and don't return anything. (define (add-prices items) (if (null? items) (+ 0 items) ; Here I don't really know what to write for a 0. ; I tried differnt thnigs like null and this version. (+ (item-price (first some-items)) (add-prices (item-price (rest some-items))))))

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• Java anagram recursion List<List<String>> only storing empty lists<Strings>

  - by Riff Rafffer

  Hi In this recursion method i am trying to find all anagrams and add it to a List but what happens when i run this code is it just returns alot of empty Lists. private List<List<String>> findAnagrams(LetterInventory words, ArrayList<String> anagram, int max, Map<String, LetterInventory> smallDict, int level, List<List<String>> result) { ArrayList<String> solvedWord = new ArrayList<String>(); LetterInventory shell; LetterInventory shell2; if (level < max || max == 0) { Iterator<String> it = smallDict.keySet().iterator(); while (it.hasNext()) { String k = it.next(); shell = new LetterInventory(k); shell2 = words; if (shell2.subtract(shell) != null) { anagram.add(k); shell2 = words.subtract(shell); if (shell2.isEmpty()) { //System.out.println(anagram.toString()); it prints off fine here result.add(anagram); // but doesnt add here } else findAnagrams(shell2, anagram, max, smallDict, level + 1, result); anagram.remove(anagram.size()-1); } } } return results; }

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• how to add enum value to list

  - by netmajor

  I have enum: public enum SymbolWejsciowy { K1 , K2 , K3 , K4 , K5 , K6 , K7 , K8 } and I want to create list of this enum public List<SymbolWejsciowy> symbol; but in my way to add enum to List: 1. SymbolWejsciowy symbol ; symbol.Add(symbol = SymbolWejsciowy.K1); 2. symbol.Add(SymbolWejsciowy.K1); I always get Exception Object reference not set to an instance of an object. What i do wrong :/ Please help :)

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• Remove first 'n' elements from list without itterating

  - by Eldhose M Babu

  I need an efficient way of removing items from list. If some condition happens, I need to remove first 'n' elements from a list. Can some one suggest the best way to do this? Please keep in mind: performance is a factor for me, so I need a faster way than itterating. Thanks. I'm thinking of a way through which the 'n'th item can be made as the starting of the list so that the 0-n items will get garbage collected. Is it possible?

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• c# Generic List

  - by user177883

  I m populating data for different entities into set of lists using generic lists as follows : List<Foo> foos .. List<Bar> bars .. I need to write these lists to a file, i do have a util method to get the values of properties etc. using reflection. What i want to do is: using a single method to write these into files such as: void writeToFile(a generic list) { //Which i will write to file here. } How can i do this? I want to be able to call : writeToFile(bars); writeToFile(foos);

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• Python: Indexing list for element in nested list

  - by aquateenfan

  I know what I'm looking for. I want python to tell me which list it's in. Here's some pseudocode: item = "a" nested_list = [["a", "b"], ["c", "d"]] list.index(item) #obviously this doesn't work here I would want python to return 0 (because "a" is an element in the first sub-list in the bigger list). I don't care which sub-element it is. I don't care if there are duplicates, e.g., ["a", "b", "a"] should return the same thing as the above example. Sorry if this is a dumb question. I'm new to programming.

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• Taking a comma separated list and creating a unordered list

  - by mmsa

  I've got a simple list which is generated by a checkbox list. The generated code is simply this white,blue,red,black I need to use jquery to wrap each of these elements in a < li tag. How do you go through the list and use the comma as a separator? I also will need to delete the comma. Sometime there will be 1 item, sometimes 3, etc. Thanks in advance!

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• JSF: how to update the list after delete an item of that list

  - by Harry Pham

  It will take a moment for me to explain this, so please stay with me. I have table COMMENT that has OneToMany relationship with itself. @Entity public class Comment(){ ... @ManyToOne(optional=true, fetch=FetchType.LAZY) @JoinColumn(name="REPLYTO_ID") private Comment replyTo; @OneToMany(mappedBy="replyTo", cascade=CascadeType.ALL) private List<Comment> replies = new ArrayList<Comment>(); public void addReply(NewsFeed reply){ replies.add(reply); reply.setReplyTo(this); } public void removeReply(NewsFeed reply){ replies.remove(reply); } } So you can think like this. Each comment can have a List of replies which are also type Comment. Now it is very easy for me to delete the original comment and get the updated list back. All I need to do after delete is this. allComments = myEJB.getAllComments(); //This will query the db and return updated list But I am having problem when trying to delete replies and getting the updated list back. So here is how I delete the replies. Inside my managed bean I have //Before invoke this method, I have the value of originalFeed, and deletedFeed set. //These original comments are display inside a p:dataTable X, and the replies are //displayed inside p:dataTable Y which is inside X. So when I click the delete button //I know which comment I want to delete, and if it is the replies, I will know //which one is its original post public void deleteFeed(){ if(this.deletedFeed != null){ scholarEJB.deleteFeeds(this.deletedFeed); if(this.originalFeed != null){ //Since the originalFeed is not null, this is the `replies` //that I want to delete scholarEJB.removeReply(this.originalFeed, this.deletedFeed); } feeds = scholarEJB.findAllFeed(); } } Then inside my EJB scholarEJB, I have public void removeReply(NewsFeed comment, NewsFeed reply){ comment = em.merge(comment); comment.removeReply(reply); em.persist(comment); } public void deleteFeeds(NewsFeed e){ e = em.find(NewsFeed.class, e.getId()); em.remove(e); } When I get out, the entity (the reply) get correctly removed from the database, but inside the feeds List, reference of that reply still there. It only until I log out and log back in that the reply disappear. Please help

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• Python: create a function to modify a list by reference not value

  - by Jonathan

  Hey all- I'm doing some performance-critical Python work and want to create a function that removes a few elements from a list if they meet certain criteria. I'd rather not create any copies of the list because it's filled with a lot of really large objects. Functionality I want to implement: def listCleanup(listOfElements): i = 0 for element in listOfElements: if(element.meetsCriteria()): del(listOfElements[i]) i += 1 return listOfElements myList = range(10000) myList = listCleanup(listOfElements) I'm not familiar with the low-level workings of Python. Is myList being passed by value or by reference? How can I make this faster? Is it possible to somehow extend the list class and implement listCleanup() within that? myList = range(10000) myList.listCleanup() Thanks- Jonathan

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• Is it better to use List or Collection?

  - by Vivin Paliath

  I have an object that stores some data in a list. The implementation could change later, and I don't want to expose the internal implementation to the end user. However, the user must have the ability to modify and access this collection of data. Currently I have something like this: public List<SomeDataType> getData() { return this.data; } public void setData(List<SomeDataType> data) { this.data = data; } Does this mean that I have allowed the internal implementation details to leak out? Should I be doing this instead? public Collection<SomeDataType> getData() { return this.data; } public void setData(Collection<SomeDataType> data) { this.data = new ArrayList<SomeDataType>(data); }

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• HTML list wrapping problem

  - by Daniel

  I have a HTML list with this style: font-weight: bold; padding: 0px; margin: 0px; list-style-type: none; display: block; width:700px; font-size: 14px; white-space: pre-wrap; and the cells have this style: display: inline; and I have spacer cells between each cell with this style: padding-right: 20px; display: inline; My problem is that when the list is too long for its 700 pixels, it wraps. I want this, but I dont want the objects to be on two separate lines. I have tried the CSS white-space property, but nothing seems to work. Any ideas?

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• Making a textfile into a list in matlab?

  - by Ben Fossen

  I have a textfile and would like to import it onto Matlab and make it a list Person1 name = steven grade = 11 age= 17 Person2 name = mike grade = 9 age= 15 Person3 name = taylor grade = 11 age= 17 There are a few hundred entries like these above. Each are seperated by a blank line I was thinking I could scan the text and make the information between each blank line into an item in the list. I also would like to be able to look up each person by name once I have a list like the one below. I want something like x = [Person1 Person2 Person3 name = steven name = mike name = taylor grade = 11 grade = 9 grade = 11 age = 17 age = 15 age = 17] This seems very straight forward but I have been having trouble with this so far, I may be overlooking something. anyone have any ideas or advice?

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• Add entry to list and remove first one in Python

  - by wagglewax

  I have a list of about 40 entries. And I frequently want to append an item to the start of the list (with id 0) and want to delete the last entry (with id 40) of the list. how do i do this the best? like: (example with 5 entries) [0] = "herp" [1] = "derp" [2] = "blah" [3] = "what" [4] = "da..." after adding "wuggah" and deleting last it should be like: [0] = "wuggah" [1] = "herp" [2] = "derp" [3] = "blah" [4] = "what" or appending one and deleting first. And I don't want to end up manually moving them one after another all of the entries to the next id.

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• List view and list adapters for displaying json

  - by Rahul Varma

  Hi, I am trying to display the text from json in a list view. I got help for retrieving the json text from the following... http://www.josecgomez.com/2010/04/30/android-accessing-restfull-web-services-using-json/comment-page-1/#comment-498.... But my problem is that i cant figure out how to display them in list view. I also want to get only some of the text from url(for example, alerttext and date). Can anyone help me in declaring the list adapter and list view in order to display the data in the way i want... Plzzzz...

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• To return the list in JSON format

  - by Reshma

  Below is my code, List<string> modified_listofstrings = new List<string>(); string sJSON = ""; System.Web.Script.Serialization.JavaScriptSerializer jSearializer = new System.Web.Script.Serialization.JavaScriptSerializer(); resulted_value = final_resulted_series_name + ":" + period_name + ":" + period_final_value; modified_listofstrings.Add(resulted_value); json_resultedvalue = JsonConvert.SerializeObject(resulted_value); modified_listofstrings.Add(json_resultedvalue); sJSON = jSearializer.Serialize(modified_listofstrings); return sJSON; But on following line , sJSON = jSearializer.Serialize(modified_listofstrings); I am getting an error as Cannot implicitly convert type string to system.collection.generic.list

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