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  • solr range query errors

    - by mquinsland
    http://localhost:8983/solr/select?wt=json&q=lat:[35%20to%2038] results in **org.apache.lucene.queryParser.ParseException: Cannot parse 'lat:[35 to 38]': Encountered " "38 "" at line 1, column 11. Was expecting: "]" This is a pretty basic range query and this error will prevent us from using SOLR for our projects

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  • Error when pushing data to Heroku: time zone displacement out of range

    - by J. Pablo Fernández
    I run the following command to push the contents of my local database to Heroku: heroku db:push --app my-app and from my home computer it works flawlessly but from my work computer I get this error: Taps Server Error: PGError: ERROR: time zone displacement out of range: "2011-11-15 12:00:00.000000+5894114400" I'm not sure where that date is coming from, I can't find it in the data anywhere. Any ideas what's going on and/or how to fix it? Thanks.

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  • jqueryUI Slider: Setting minimum and maximum values in range from DB

    - by alexBrand
    I have a jQueryUI slider on my website that deals with price range. I have a products table in mysql that has various entries. I am using the slider to filter the results, but I need to set the minimum and maximum prices from the records in my database. Should I just generate (with php) hidden fields in my html that contain the minimum and maximum and then use jQuery to obtain them? Or is there a better way of achieving this, maybe using AJAX? Thanks

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  • Mysql - datetime and date-range comparsion

    - by Ockonal
    Hello guys, I have datetime-row in mysql database. I have to check time between now and that date using php. If the range is bigger then 1 month - do somtething. I tried something like this: $dateFromMysql = strtotime($rowData); $currentDate = date("m/d/y g:i A"); And then comparsion by hands. It's ugly.

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  • Unicode Kangxi radicals range 2F00–2FDF not displayed on iphone device, but in simulator

    - by sadfadfasd
    Hi, Kangxi radicals in the range 2F00-2FDF (see link text) are not displayed correctly on the iPhone device. They appear as a crossed-out box. In the simulator they display correctly. I tried the system font and also the [UIFont fontWithName:@"STHeitiTC-Medium" size:24]; ... Is the unicode codepoint coverage limited on the iphone (in my case OS 3.1.3)? How to make those radicals appear??? Thx

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  • Random number from a range in a Bash Script

    - by Jack
    Hi, I need to generate a random port number between 2000-65000 from a shell script. The problem is $RANDOM is only a 16bit number, so im stuck! PORT=$(($RANDOM%63000+2001)) would work nicely if it wasn't for the size limitation. Does anyone have an example of how I can do this, maybe by extracting something from /dev/urandom and getting it within a range? Thanks.

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  • what does "out of range" mean?

    - by user329820
    Hi I have checked these statements with mysql and no error will happen and also the out put will be 0 rows BUT my friend checked it and he found an error for SELECT becaouse it is out of range !! IS he correct? thanks CREATE TABLE T1(A INTEGER NULL); SELECT * FROM T1;

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  • Parsing Range Expressions

    - by sameer karjatkar
    I have a string (R(46 - 9900)) AND ( NOT (R(48 - 9900))) where R denotes Range . If you evaluate the expression it results in R(46-47) , considering the logical operators (AND,NOT). I have a requirement where I need to parse such a string and evaluate it to a correct result . I have to use C++ as a programming tool to achieve this result . Can anyone suggest a few guide lines as to how do I proceed on this ?

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  • MySQL Data Truncation: Out of range value in Performance test

    - by Khaledez
    on a test for Java-MySQL-Restlet application, I write to database at 4reqs/second for 120 seconds. In this write I insert a row that has foreign key which has the same value for all rows, and this exception occurs: Could not recover transaction. Original exception follows. com.mysql.jdbc.MysqlDataTruncation: Data truncation: Out of range value for column 'idPxxx' at row 1 Only 5% of requests fails to this exceptions, others works. Regards

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  • Find closest number in range?

    - by Chris
    What is the best way to find the closes value in a range... for example i have an array with 0, 90, 180, 270, 360.. And a number 46... What is the best way to find 90 in the array? (in actipnscript 3)

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  • Count days within a month from date range

    - by G. Muqtada
    I have three date ranges in mysql table as follow from 2013-09-29 to 2013-10-02 from 2013-10-14 to 2013-10-16 from 2013-10-28 to 2013-11-05 I want to count only days that occur in Month of October, for example from first range (2013-09-29 to 2013-10-02) I should get difference of two days (1st and 2nd October) , and it should ignore days from September month, Finally i want to count total days in a given month from above date ranges. Can it be done from direct mysql query. or any short PHP logic.

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  • PHP number range menu from array

    - by Julious
    Hello people! I'm a bit confused here. I have a php array like this Array(2010,2009,2008 ...1992) and i want to create a loop to print a menu with a four year range counting down like this 2010-2006 2005-2001 2000-1996 etc.. How can i do this Everything i tried end up in an endless loop. THnx in advance. J.

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  • Minimum range of 3 sets

    - by user343882
    We have three sets S1, S2, S3. I need to find x,y,z such that x E S1 y E S2 z E S3 let min denote the minimum value out of x,y,z let max denote the maximum value out of x,y,z The range denoted by max-min should be the MINIMUM possible value

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  • How is starting and ending row number of a Range obtained?

    - by Robert Kerr
    Given a user-selected Range, what is the simplest way to determine the starting row number, and ending row number? Range.Address returns a string containing any number of possible formats. There has to be something simpler. Desired: Dim oRange As Range Dim startRow As Integer Dim endRow As Integer oRange = Range("A1:X50") startRow = oRange.Address.StartRow endRow = oRange.Address.EndRow of course, those properties do not exist. I want to do the same to return column letters.

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  • Slicing a time range into parts

    - by beporter
    First question. Be gentle. I'm working on software that tracks technicians' time spent working on tasks. The software needs to be enhanced to recognize different billable rate multipliers based on the day of the week and the time of day. (For example, "Time and a half after 5 PM on weekdays.") The tech using the software is only required to log the date, his start time and his stop time (in hours and minutes). The software is expected to break the time entry into parts at the boundaries of when the rate multipliers change. A single time entry is not permitted to span multiple days. Here is a partial sample of the rate table. The first-level array keys are the days of the week, obviously. The second-level array keys represent the time of the day when the new multiplier kicks in, and runs until the next sequential entry in the array. The array values are the multiplier for that time range. [rateTable] => Array ( [Monday] => Array ( [00:00:00] => 1.5 [08:00:00] => 1 [17:00:00] => 1.5 [23:59:59] => 1 ) [Tuesday] => Array ( [00:00:00] => 1.5 [08:00:00] => 1 [17:00:00] => 1.5 [23:59:59] => 1 ) ... ) In plain English, this represents a time-and-a-half rate from midnight to 8 am, regular rate from 8 to 5 pm, and time-and-a-half again from 5 till 11:59 pm. The time that these breaks occur may be arbitrary to the second and there can be an arbitrary number of them for each day. (This format is entirely negotiable, but my goal is to make it as easily human-readable as possible.) As an example: a time entry logged on Monday from 15:00:00 (3 PM) to 21:00:00 (9 PM) would consist of 2 hours billed at 1x and 4 hours billed at 1.5x. It is also possible for a single time entry to span multiple breaks. Using the example rateTable above, a time entry from 6 AM to 9 PM would have 3 sub-ranges from 6-8 AM @ 1.5x, 8AM-5PM @ 1x, and 5-9 PM @ 1.5x. By contrast, it's also possible that a time entry may only be from 08:15:00 to 08:30:00 and be entirely encompassed in the range of a single multiplier. I could really use some help coding up some PHP (or at least devising an algorithm) that can take a day of the week, a start time and a stop time and parse into into the required subparts. It would be ideal to have the output be an array that consists of multiple entries for a (start,stop,multiplier) triplet. For the above example, the output would be: [output] => Array ( [0] => Array ( [start] => 15:00:00 [stop] => 17:00:00 [multiplier] => 1 ) [1] => Array ( [start] => 17:00:00 [stop] => 21:00:00 [multiplier] => 1.5 ) ) I just plain can't wrap my head around the logic of splitting a single (start,stop) into (potentially) multiple subparts.

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  • Diamond-square terrain generation problem

    - by kafka
    I've implemented a diamond-square algorithm according to this article: http://www.lighthouse3d.com/opengl/terrain/index.php?mpd2 The problem is that I get these steep cliffs all over the map. It happens on the edges, when the terrain is recursively subdivided: Here is the source: void DiamondSquare(unsigned x1,unsigned y1,unsigned x2,unsigned y2,float range) { int c1 = (int)x2 - (int)x1; int c2 = (int)y2 - (int)y1; unsigned hx = (x2 - x1)/2; unsigned hy = (y2 - y1)/2; if((c1 <= 1) || (c2 <= 1)) return; // Diamond stage float a = m_heightmap[x1][y1]; float b = m_heightmap[x2][y1]; float c = m_heightmap[x1][y2]; float d = m_heightmap[x2][y2]; float e = (a+b+c+d) / 4 + GetRnd() * range; m_heightmap[x1 + hx][y1 + hy] = e; // Square stage float f = (a + c + e + e) / 4 + GetRnd() * range; m_heightmap[x1][y1+hy] = f; float g = (a + b + e + e) / 4 + GetRnd() * range; m_heightmap[x1+hx][y1] = g; float h = (b + d + e + e) / 4 + GetRnd() * range; m_heightmap[x2][y1+hy] = h; float i = (c + d + e + e) / 4 + GetRnd() * range; m_heightmap[x1+hx][y2] = i; DiamondSquare(x1, y1, x1+hx, y1+hy, range / 2.0); // Upper left DiamondSquare(x1+hx, y1, x2, y1+hy, range / 2.0); // Upper right DiamondSquare(x1, y1+hy, x1+hx, y2, range / 2.0); // Lower left DiamondSquare(x1+hx, y1+hy, x2, y2, range / 2.0); // Lower right } Parameters: (x1,y1),(x2,y2) - coordinates that define a region on a heightmap (default (0,0)(128,128)). range - basically max. height. (default 32) Help would be greatly appreciated.

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  • Problem in populating a dictionary using Enumerable.Range()

    - by Newbie
    If I do for (int i = 0; i < appSettings.Count; i++) { string key = appSettings.Keys[i]; euFileDictionary.Add(key, appSettings[i]); } It is working fine. When I am trying the same thing using Enumerable.Range(0, appSettings.Count).Select(i => { string Key = appSettings.Keys[i]; string Value = appSettings[i]; euFileDictionary.Add(Key, Value); }).ToDictionary<string,string>(); I am getting a compile time error The type arguments for method 'System.Linq.Enumerable.Select(System.Collections.Generic.IEnumerable, System.Func)' cannot be inferred from the usage. Try specifying the type arguments explicitly. Any idea? Using C#3.0 Thanks

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