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  • How to check if there is an active session in a JSF page?

    - by Roberto de Santis
    Hi, there is a way to check if there is an active session directly in jsf page? I have try this but it doesn't work: <p:ajaxStatus onerror="#{session == null ? 'idleDialog.show();' : null}" thank you in advance @Update I have see that onerror isn't fired even if viewExpiredException occurr. @Update 1 Ok i have implemented something that may work: <h:form> <p:idleMonitor timeout="10000" idleListener="#{idleMonitorController.idleListener}" onidle="sessionPoll.stop();idleDialog.show();"/> </h:form> <p:dialog header="Sessione scaduta per inattività" widgetVar="idleDialog" modal="true" width="400"> <h:outputText value="Sessione scaduta" /> <h:button value="Ripristina Sessione" onclick="idleDialog.hide();sessionPoll.start();" /> </p:dialog> <h:form prependId="false"> <p:poll widgetVar="sessionPoll" interval="1"/> </h:form> and this is the listner: public void idleListener(IdleEvent event) { System.out.println("aaaa"); final HttpServletRequest request = (HttpServletRequest) FacesContext.getCurrentInstance().getExternalContext().getRequest(); request.getSession(false).invalidate(); } now the only problem is that the session.invalidate doesn't work

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  • Handling 'session expired' in JSF web application, running in JBoss AS 5

    - by Veera
    This question is related to my other question "How to redirect to Login page when Session is expired in Java web application?". Below is what I'm trying to do: I've a JSF web application running on JBoss AS 5 When the user is inactive for, say 15 minutes, I need to log out the user and redirect him to the login page, if he is trying to use the application after the session has expired. So, as suggested in 'JSF Logout and Redirect', I've implemented a filter which checks for the session expired condition and redirects the user to a session-timed-out.jsp page, if the session has expired. I've added SessionExpiryCheckFilter on top of all other filter definitions in web.xml, so that my session expiry check will get the first hit always. Now comes the challenge I'm facing. Since I'm using JBoss AS, when the session expired, JBoss automatically redirects me to the login page (note that the session expiry check filter is not invoked). So, after I log-in, my SessionExpiryCheckFilter intercepts the request, and it sees a session is available. But, it throws the exception javax.faces.application.ViewExpiredException: viewId:/mypage.faces - View /mypage.faces could not be restored. Have anyone faced this issue before? Any ideas to solve this issue?

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  • NHibernate Session per Call in WCF - How to Rollback

    - by Corey Coogan
    I've implemented some components to use WCF with both an IoC Container (StructureMap) and the Session per Call pattern. The NHibernate stuff is most taken from here: http://realfiction.net/Content/Entry/133. It seems to be OK, but I want to open a transaction with each call and commit at the end, rather than just Flush() which how its being done in the article. Here's where I am running into some problems and could use some advice. I haven't figured out a good way to rollback. I realize I can check the CommunicationState and if there's an exception, rollback, like so: public void Detach(InstanceContext owner) { if (Session != null) { try { if(owner.State == CommunicationState.Faulted) RollbackTransaction(); else CommitTransaction(); } finally { Session.Dispose(); } } } void CommitTransaction() { if(Session.Transaction != null && Session.Transaction.IsActive) Session.Transaction.Commit(); } void RollbackTransaction() { if (Session.Transaction != null && Session.Transaction.IsActive) Session.Transaction.Rollback(); } However, I almost never return a faulted state from a service call. I would typically handle the exception and return an appropriate indicator on my response object and rollback the transaction myself. The only way I can think of handling this would be to inject not only repositories into my WCF services, but also an ISession so I can rollback and handle the way I want. That doesn't sit well with me and seems kind of leaky. Anyone else handling the same problem?

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  • Problem connecting to MySQL with zend

    - by wheresrhys
    I've set up a virtual host on my local machine (windows xp with xampp installed), have installed zend there and am now trying to connect to the MySQLdatabase. I get the following error message: Message: SQLSTATE[HY000] [2003] Can't connect to MySQL server on ''myhost.com'' (10060) All the tips I've found via google haven't helped. I use kaspersky antivirus and have added port 3306 to the allowed list for MySQL and Apache. I've also pinged myhost.com:3306 and get a response (with ip address 67.63.50.51), though localhost:3306 and 127.0.0.1:3306 aren't found. I've checked that other apps can still access MySQL if the virtual host is pointed at them instead and my non zend apps do work. I guess I have to do something further to the port, or maybe force the app to use a different port, but am not sure how to do either. Any help appreciated.

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  • Problem connecting to MySQL with zend

    - by wheresrhys
    I've set up a virtual host on my local machine (windows xp with xampp installed), have installed zend there and am now trying to connect to the MySQLdatabase. I get the following error message: Message: SQLSTATE[HY000] [2003] Can't connect to MySQL server on ''myhost.com'' (10060) All the tips I've found via google haven't helped. I use kaspersky antivirus and have added port 3306 to the allowed list for MySQL and Apache. I've also pinged myhost.com:3306 and get a response (with ip address 67.63.50.51), though localhost:3306 and 127.0.0.1:3306 aren't found. I've checked that other apps can still access MySQL if the virtual host is pointed at them instead and my non zend apps do work. I guess I have to do something further to the port, or maybe force the app to use a different port, but am not sure how to do either. Any help appreciated.

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  • phpmyadmin throws a blank page after installing Zend CE server

    - by infotoknowledge
    I installed LAMP on Ubuntu 12.0.4 LTE. Then I installed phpmyadmin. Everything was good. I used phpadmin to do lots of DB administration.... Then I installed Zend CE server. Now, phpmyadmin throws a blank page. No login screen. So, I reinstalled my VPS in the same sequence again. No luck. Same behavior. This time, I installed Apache, Mysql, PHP and Zend server in that order. Then I installed phpmyadmin....Unfortunately, still blank page on phpmyadmin. Any help?...Thanks in advance.

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  • Display subform after validate main form

    - by bahamut100
    Hi, I want to display a new form after the validation of a form. I use Zend_Form_SubForm to do it (I Try to Zend_Form too), but this new form is not displaying. Why ?? This is the code in question : if ($this->_request->isPost()) { $formData = $this->_request->getPost(); if ($form->isValid($formData)) { $subForm = new Zend_Form_SubForm(); $subForm ->setAction('') ->setMethod('post'); $nom=new Zend_Form_Element_Text('nom'); $submit = new Zend_Form_Element_Submit('submit'); $submit->setLabel('OK'); $subForm->addElements(array($nom,$submit)); } else { $form->populate($formData); } }

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  • zend_form ViewScript decorator / passing arguments

    - by timpone
    I have a form that is extend from Zend_Form. I am placing the form into a ViewScript decorator like this: $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml')))); I'd like to pass in a variable to this ViewScript but am not sure how this could be done. Since the partial renders out as a Zend_View (allowing $this-app_store_icon for rendering), it seems like there should be a way to pass variables to be rendered. I tried the following but to no avail. $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml'),array('app_store_picon'=>$current_app_store_picon)))); Any help on how to get this done would be appreciated. thanks

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  • Setting the inner html text of a < span > element using Zend_Form_Decorators

    - by Mallika Iyer
    I'm trying to set the inner html of the < span tag here , so it looks like: Group this is what i have so far: $form->addDisplayGroup( array( ................ ), 'maingroup1', array( 'legend'=>'', 'disableDefaultDecorators'=> true, 'decorators'=> array('FormElements', array('FieldSet',array('class'=>'dashed-outline2')), array(array('SpanTag' => 'HtmlTag'), array('tag'=>'span','class' => 'group',)), array('HtmlTag',array('tag'=>'div','id'=>'group1','class'=>'group','openOnly'=> true)) ) ) ); Is there a setter / property that I can use to set the inner text of the < span element using Zend_form_decorators? Thanks.

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  • How to add CSS classes to Zend_Form_Element_Select option

    - by Jah Selassie
    Hi, I'm trying to add a CSS class to a Zend_Form_Element_Select option, but I just can't find a way to do it. The desired output would be something like this: <select name="hey" id="hey"> <option value="value1" style="parent">label1</option> <option value="value2" style="sibling">sublabel1</option> <option value="value3" style="sibling">sublabel2</option> <option value="value4" style="parent">label2</option> <option value="value5" style="sibling">sublabel3</option> <option value="value6" style="sibling">sublabel4</option> </select> But I'm getting this: <select name="hey" id="hey"> <option value="value1">label1</option> <option value="value2">sublabel1</option> <option value="value3">sublabel2</option> <option value="value4">label2</option> <option value="value5">sublabel3</option> <option value="value6">sublabel4</option> </select> I can't seem to pass a CSS class attribute to any of the options in the select element although I can style the select element itselft. My code: $sel = new Zend_Form_Element_Select('hey'); $sel->setRequired(true)->setLabel('Select an Option:'); $sel->addMultiOption('value1', 'label1', array('class' => 'parent')) ->addMultiOption('value2', 'sublabel1', array('class' => 'sibling')) (etc...); After researching a bit I found out that Element_Select doesn't have a method for adding CSS styles to the options in the select box, only for the select itself. So, how can I add them? Should I extend the form_element_select? Or would a custom decorator suffice? Can anyone give me a hint? I'm baffled with this. Thanks in advance!

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  • Session timeout issue

    - by Kumar
    I have a role based ASP.NET C# web application in which I am putting the menu object inside a session and I have a session timeout configured in the web.config as below: <forms defaultUrl="Home.aspx" loginUrl="Login.aspx" name=".ASPXFORMSAUTH" timeout="10"></forms> I first logged into the system as an employee and waited until the session expires and then when I click a link in the menu I am being rightly redirected to the login page with the ReturnUrl parameter. Now when I try to login to the system as an administrator I am still seeing the employee menu and not the admin menu. The method which loads the menu 1st checks to see if the menu session object is not null if so loads the menu from the session if not then it builds the menu and put it into session. So when the system timesout the menu session object is not being cleared. How can I fix this?

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  • Servlet Session - switch from URL Rewriting to Cookie

    - by lajuette
    Situation: I have a "dumb" Javascript frontend that can contact some kind of SSO middleware (MW). The MW can obtain sessions by issuing requests that contain authentication credentials (username, password). I.e. the session will be created for a certain user. My frontend needs to "restart" the session to gain the user's permissions to the target system. For that i need a valid session cookie. The target system is not under my control (could be a more or less public WFS, WMS, etc.), so i cannot add any SSO mechanism to it. Question: Is it possible to "steal" a Session forging a request which URL contains a valid session ID in the jsessionid parameter? Goal : Issue such a request to a Servlet and make it respond with a Set-Cookie header that contains the same id. That way the frontend joins the session and may do whatever the user, which was used to create the session, is able to do.

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  • How can I append a description to a Zend_Form_Element?

    - by Mallika Iyer
    I have the following Zend_Form_Element: $imginstructions = "Some description"; $img = $this->createElement('select','img'); $img->setAttrib('class', 'image-select'); $imgdecorator = $img->getDecorator('Description'); $imgdecorator->setOption('escape', false); $img->setLabel('Image:') ->setRequired(true) ->addMultiOptions($images) ->setValue('') ->setDescription($imginstructions) ->addErrorMessage('You must select an image'); $img->size = 5; $this->addElement($img); The description should appear next to the select box. The problem is : When an error is thrown, the html rendered changes so the description shows up below the select box, instead of beside it. HTML rendered before error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p></dd> HTML rendered after error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <ul class="errors"><li>You must select an image</li></ul> <p class="description">Some Description</p></dd> Is there a way to force the error message to be appended as the last element in the DOM tree for the dd element? Something like: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p> <ul class="errors"><li>You must select an image</li></ul></dd> so the 'ul' is at the end of the dd DOM tree. Thanks, I appreciate your taking the time to respond to this question!

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  • What's the simplest way to create a Zend_Form tabular display with each row having a radio button?

    - by RenderIn
    I've seen simple examples of rendering a Zend_Form using decorators, but I'm not sure they are able to handle the issue I'm facing very well. I query the database and get an array of user objects. I want to display these users as a form, with a radio button next to each of them and a submit button at the bottom of the page. Here's roughly what the form will look like: [user id] [email] [full name] ( ) 1 [email protected] Test user 1 (*) 2 [email protected] Test user 2 [SUBMIT] Is this something achievable in a reasonably straightforward way or do I need to use the ViewScript partial?

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  • row specific class

    - by stimpie
    How do I create a Zend_Db_Table which returns a different class for each row.? Example UserTable has id,name and type Type contains class names (admin,client,etc...) The classes admin, client are all subclasses of user If I call fetch I need to get a admin or client object depending on the corresponding value in the db.

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  • Inject filter into Zend_View

    - by chelmertz
    Hi! I wish to set some properties in MyFilter with constructor injection but it seems impossible with Zend_View::addFilter(string $filter_class_name) since it loads a new instance upon usage. MyFilter implements Zend_Filter_Interface. Can I somehow inject an instance of a filter to an instance of Zend_View?

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  • Selectively prevent Session from being created

    - by Jean Barmash
    In my app, I have an external monitor that pings the app ever few minutes and measures its uptime / response time Every time the monitor connects, a new server session is created, so when I look at the number of sessions, it's always a minimum of 15, even during times where there are no actual users. I tried to address this with putting the session creation code into a filter, but that doesn't seem to do it - I guess session automatically gets created when the user opens the first page? all() { before = { if (actionName=='signin') { def session = request.session //creates session if not exists } } } I can configure the monitor to pass in a paramter if I need to (i.e. http://servername.com/?nosession, but not sure how to make sure the session isn't created.

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  • What scripts get run on session start and end?

    - by maaartinus
    I want to mount and unmount an encrypted partition just like ecryptfs works with the home partition. Where can I put my commands so that they get executed upon session start and session end (the important part is the unmounting when I log out). UPDATE: For the session start I'm using .gnomerc and it does what I want. For the session end I've found no solution. I had a look at the sources of ecryptfs and it looks quite complicated. It's a pity that nobody thought about creating something analog to .bash_logout.

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  • how to decorate the error message

    - by ulduz114
    this is the decorator code $mydecorate = array( 'ViewHelper', array('Errors', array('placement' => 'append','class' => 'error')), array('Label', array('separator' => '')), array('HtmlTag', array('tag' => 'p', 'class' => 'element-form')) ); html result of two input elements with the above decorator: <p class="element-form"> <label for="firstname" class="required">First Name:</label> <input name="firstname" id="firstname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> <p class="element-form"> <label for="lastname" class="required">Last Name:</label> <input name="lastname" id="lastname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> I'd like the error message to be placed inside the p.element-form tag, any idea pleas? thanks

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  • Rails - session information being cleared?

    - by Jty.tan
    Hi! I'm having a weird issue that I can't track down... For context, I have resources of Users, Registries, and Giftlines. Each User has many Registries. Each Registry has many Giftlines. It's a belongs to association for them in a reverse manner. What is basically happening, is that when I am creating a giftline, the giftline itself is created properly, and linked to its associated Registry properly, but then in the process of being redirected back to the Registry show page, the session[:user_id] variable is cleared and I'm logged out. As far as I can tell, where it goes wrong is here in the registries_controller: def show @registry = Registry.find(params[:id]) @user = User.find(@registry.user_id) if (params[:user_id] && (@user.login != params[:user_id]) ) flash[:notice] = "User #{params[:user_id]} does not have such a registry." redirect_to user_registries_path(session[:user_id]) end end Now, to be clear, I can do a show of the registry normally, and nothing weird happens. It's only when I've added a giftline does the session[:user_id] variable get cleared. I used the debugger and this is what seems to be happening. (rdb:19) list [20, 29] in /Users/kriston/Dropbox/ruby_apps/bee_registered/app/controllers/registries_controller.rb 20 render :action => 'new' 21 end 22 end 23 24 def show => 25 @registry = Registry.find(params[:id]) 26 @user = User.find(@registry.user_id) 27 if (params[:user_id] && (@user.login != params[:user_id]) ) 28 flash[:notice] = "User #{params[:user_id]} does not have such a registry." 29 redirect_to user_registries_path(session[:user_id]) (rdb:19) session[:user_id] "tester" (rdb:19) So from there we can see that the code has gotten back to the show command after the item had been added, and that the session[:user_id] variable is still set. (rdb:19) list [22, 31] in /Users/kriston/Dropbox/ruby_apps/bee_registered/app/controllers/registries_controller.rb 22 end 23 24 def show 25 @registry = Registry.find(params[:id]) 26 @user = User.find(@registry.user_id) => 27 if (params[:user_id] && (@user.login != params[:user_id]) ) 28 flash[:notice] = "User #{params[:user_id]} does not have such a registry." 29 redirect_to user_registries_path(session[:user_id]) 30 end 31 end (rdb:19) session[:user_id] "tester" (rdb:19) Stepping on, we get to this point. And the session[:user_id] is still set. At this point, the URL is of the format localhost:3000/registries/:id, so params[:user_id] fails, and the if condition doesn't occur. (Unless I am completely wrong .<) So then the next bit occurs, which is (rdb:19) list [1327, 1336] in /Library/Ruby/Gems/1.8/gems/actionpack-2.3.5/lib/action_controller/base.rb 1327 end 1328 1329 def perform_action 1330 if action_methods.include?(action_name) 1331 send(action_name) => 1332 default_render unless performed? 1333 elsif respond_to? :method_missing 1334 method_missing action_name 1335 default_render unless performed? 1336 else (rdb:19) session[:user_id] "tester" And then when I hit next... (rdb:19) next 2: session[:user_id] = /Library/Ruby/Gems/1.8/gems/actionpack-2.3.5/lib/action_controller/filters.rb:618 return index if nesting != 0 || aborted (rdb:19) list [613, 622] in /Library/Ruby/Gems/1.8/gems/actionpack-2.3.5/lib/action_controller/filters.rb 613 private 614 def call_filters(chain, index, nesting) 615 index = run_before_filters(chain, index, nesting) 616 aborted = @before_filter_chain_aborted 617 perform_action_without_filters unless performed? || aborted => 618 return index if nesting != 0 || aborted 619 run_after_filters(chain, index) 620 end 621 622 def run_before_filters(chain, index, nesting) (rdb:19) session {:user_id=>nil, :session_id=>"49992cdf2ddc708b441807f998af7ddc", :return_to=>"/registries", "flash"=>{}, :_csrf_token=>"xMDI0oDaOgbzhQhDG7EqOlGlxwIhHlB6c71fWgOIKcs="} The session[:user_id] is cleared, and when the page renders, I'm logged out. .< Sooo.... Any idea why this is occurring? It just occurred to me that I'm not sure if I'm meant to be pasting large chunks of debug output in here... Somebody point out to me if I'm not meant to be doing this. . And yes, this only occurs when I have added a giftitem, and it is sending me back to the registry page. When I'm viewing it, the same code occurs, but the session[:user_id] variable isn't cleared. It's driving me mildly insane. Thanks!

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  • Pass Session data to a Class Library without using a bunch of constructors?

    - by sah302
    Hi all, I've got my application here where literally every object has a lastUpdatedBy property. The information I put into here is the person's username, which is retrieved from the session("username") variable. How can I pass this data to my DAL in the class library? At first I was just passing in the value into each method, but this is ridiculous I thought, there should be no reason to do that every time a method is called. Then I thought well if I just put it in a constructor for each of the DAL related classes, that will make it even easier. However, even still on any given page, I've got a plethora of New() declarations, for which every single line I need to pass in the session username casted as a string. Is there an even still more efficient way of doing this so that I could only declare this in one place, and everything will know what it is and I can pass it to classes in a class library?

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  • XML configuration of Zend_Form: child nodes and attributes not always equal?

    - by Cez
    A set of forms (using Zend_Form) that I have been working on were causing me some headaches trying to figure out what was wrong with my XML configuration, as I kept getting unexpected HTML output for a particular INPUT element. It was supposed to be getting a default value, but nothing appeared. It appears that the following 2 pieces of XML are not equal when used to instantiate Zend_Form: Snippet #1: <form> <elements> <test type="hidden"> <options ignore="true" value="foo"/> </test> </elements> </form> Snippet #2: <form> <elements> <test type="hidden"> <options ignore="true"> <value>foo</value> </options> </test> </elements> </form> The type of the element doesn't appear to make a difference, so it doesn't appear to be related to hidden fields. Is this expected or not?

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  • Prevent Session from being created In some cases

    - by Jean Barmash
    In my app, I have an external monitor that pings the app ever few minutes and measures its uptime / response time Every time the monitor connects, a new server session is created, so when I look at the number of sessions, it's always a minimum of 15, even during times where there are no actual users. I tried to address this with putting the session creation code into a filter, but that doesn't seem to do it - I guess session automatically gets created when the user opens the first page? all() { before = { if (actionName=='signin') { def session = request.session //creates session if not exists } } } I can configure the monitor to pass in a paramter if I need to (i.e. http://servername.com/?nosession, but not sure how to make sure the session isn't created.

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  • Session State ArrayList in Shopping Cart ASP.NET

    - by user330342
    Hi guys, I'm creating a shopping cart application and I'm having some issues with implementing a session state for my arraylist. in my page load i declared if (Session["Cart"] == null) { Session["Cart"] = new ArrayList(); } else { ArrayList cart = (ArrayList)Session["Cart"]; } to create the session if it doesn't exist yet. then i have an event handler for a button to add items to the arraylist protected void onClick_AddBooking(object sender, EventArgs e) { int ClassID = Convert.ToInt32(Request.QueryString.Get("Class_Id")); ArrayList cart1 = new ArrayList(); cart1 = Session["Cart"]; cart1.Add(ClassID); i'm guessing i just don't know how to handle session states yet, thus the confusion. I'm essentially storing the class_ID then when the student confirms i'll store that to the DB and associate that ID with the Class Details. Thanks in advance guys!

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