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  • how to create english language dictionary application with python (django)?

    - by sintaloo
    Hi All, I would like to create an online dictionary application by using python (or with django). It will be similar to http://dictionary.reference.com/. My question is (1) Are there any existing open source python package or modules or application which implements this functionality that I can use or study from? (2) If the answer to the first question is NO. which algorithm should I follow to create such web application? Can I simply use the python built-in dictionary object for this job? so that the dictionary object's key will be the english word and the value will be the explanation. is this OK in term of performance? OR Do I have to create my own Tree Object to speed up the search? or any existing package which handles this job properly? Thank you very much.

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  • Using Zend_Db and multiple tables

    - by Yacoby
    I have a normalized database that stores locations of files on the internet. A file may have multiple locations spread across different sites. I am storing the urls in two parts (Site.UrlStart, FileLocation.UrlEnd). The UrlEnd is the part unique to that file (for the site). Simplified Db structure: I am using Zend_Db as my ORM (If it is that), with classes for the tables inheriting from Zend_Db_Table_Abstract. The issue is that retrieving the location data (e.g. the url) requires the use of multiple tables and as far as I can make out and I would either have to use both table classes (thereby exposing my table structure) or scatter sql all over my application, neither of which sound appealing. The only solution I can see is to create a façade that acts like Zend_Db_Table_Abstract (Maybe inherits from it?) and hides the fact that the data is actually on two tables. My questions are as follows: Am I going in the right direction in creating a façade class (Are there other alternatives)? Should the facade class inherit from Zend_Db_Table_Abstract?

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  • How do I build (get/download) time.h library?

    - by coffeenet
    I am trying to build a project on Linux via Makefile. I keep getting cannot find <sys/time.h> error. I asked around, and I was told that my project doesn't have access to library folders. Therefore, I am trying to solve this problem by using the time library locally inside my project's folder. I am very new to Linux. So, please forgive my question if it sounds naive. I found this, but I don't know what files I need, and how to build the library. http://sourceware.org/git/?p=glibc.git;a=tree;f=time;h=c950c5d4dd90541e8f3c7e1649fcde4aead989bb;hb=master Where can I find the time.h library/package? How do I build the library?

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  • How to move positions within an array?

    - by Jade Mulholland
    A program that simply moves array elements. Two variables: userInputVariable and blankSpaceVariable. I have a 2D array named table. Defined as table[userInputVariable + 1][6] I am printing out this array in a table format, and the far left column is numbered by whatever number the user entered at the beginning of the program. I then ask the user where they would like to enter a blank space within the array. This blank space acts like a divider for all the other information in the array. For example, if the user enters 10 at the start for the userInputVariable, and then enters 5 for the blank space. Once printed, the numbers should go like this: 1, 2, 3, 4, --, 5, 6, 7, 8, 9, 10. My plan has been to create a for loop and try to move all the numbers in the array back a position starting from the blank space variable. What I currently have, but does not work: for (int i = blankSpaceVariable; i < table.length - 1; i++) { table[i] = table[i + 1]; } table[blankSpaceVariable] = "--"; With my current code, the numbers go like this: 1, 2, 3, 4, 6, 7, 8, 9, 10 Tried completing this a few different ways also, but the other info within my 2D array didn't move with the numbers. So I thought that this approach can hopefully move all the info within my 2D array down, and make way for a blank section. All help is greatly appreciated!

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  • Getting data from the next row in Oracle cursor

    - by Chaotic_one
    Hi, I'm building nested tree and I need to get data for the next row in cursor, using Oracle. And I still need current row, so looping forward is not a solution. Example: OPEN emp_cv FOR sql_stmt; LOOP FETCH emp_cv INTO v_rcod,v_rname,v_level; EXIT WHEN emp_cv%NOTFOUND; /*here lies the code for getting v_next_level*/ if v_next_level > v_level then /*code here*/ elsif v_next_level < v_level then /*code here*/ else /*code here*/ end if; END LOOP; CLOSE emp_cv;

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  • Perl parsing ps fwaux output

    - by Magic Hat
    I am trying to figure out children processes of a given parent from ps fwaux (there may very well be a better way to do this). Basically, I have daemons running that may or may not have a child process running at any given time. In another script I want to check if there are any child processes, and if so do something. If not, error out. ps fwaux|grep will show me the tree, but I'm not exactly sure what to do with it. Any suggestions would be great.

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  • list of all commits SHA1_HASH

    - by dorelal
    git init echo 'I am foo' > foo.txt git add foo.txt # this woould create a git commit object echo ' I am foo2' > foo.txt git add foo.txt # this would create another git commit object git commit -m 'doe' # this would create two git # objects: one commit object and one tree object How do I get a list of all 4 commits SHA1_HASH ? cd .git/objects ls (master)$ ls -al total 0 drwxr-xr-x 8 nsingh staff 272 Mar 27 16:44 . drwxr-xr-x 13 nsingh staff 442 Mar 27 16:44 .. drwxr-xr-x 3 nsingh staff 102 Mar 27 16:44 37 drwxr-xr-x 3 nsingh staff 102 Mar 27 16:43 a2 drwxr-xr-x 3 nsingh staff 102 Mar 27 16:44 e1 drwxr-xr-x 3 nsingh staff 102 Mar 27 16:42 e6 drwxr-xr-x 2 nsingh staff 68 Mar 27 16:42 info drwxr-xr-x 2 nsingh staff 68 Mar 27 16:42 pack I can find the list of all 4 commits by looking at file here but there must be a better way.

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  • Next Identity Key LINQ + SQL Server

    - by user569347
    To represent our course tree structure in our Linq Dataclasses we have 2 columns that could potentially be the same as the PK. My problem is that if I want to Insert a new record and populate 2 other columns with the PK that was generated there is no way I can get the next identity and stop conflict with other administrators who might be doing the same insert at the same time. Case: A Leaf node has right_id and left_id = itself (prereq_id) **dbo.pre_req:** prereq_id left_id right_id op_id course_id is_head is_coreq is_enforced parent_course_id and I basically want to do this: pre_req rec = new pre_req { left_id = prereq_id, right_id = prereq_id, op_id = 3, course_id = query.course_id, is_head = true, is_coreq = false, parent_course_id = curCourse.course_id }; db.courses.InsertOnSubmit(rec); try { db.SubmitChanges(); } Any way to solve my dilemma? Thanks!

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  • Min-Ordered Bionomial Heap Insertion java

    - by Charodd Richardson
    Im writing a java code to make a min-ordered Binomial Heap and I have to Insert and Remove-min. I'm having a very big problem inserting into the Heap. I have been stuck on this for a couple of days now and it is due tomorrow. Whenever I go to insert, It only prints out the item I insert instead of the whole tree (which is in preorder). Such as if I insert 1 it prints (1) and then I go to insert 2 it prints out (2) instead of (1(2)) It keeps printing out only the number I insert last instead of the whole preordered tree. I would be very grateful if someone could help me with this problem. Thank you so much in advance, Here is my code. public class BHeap { int key; int degree;//The degree(Number of children) BHeap parent, leftmostChild, rightmostChild, rightSibling,root,previous,next; public BHeap(){ key =0; degree=0; parent =null; leftmostChild=null; rightmostChild=null; rightSibling=null; root=null; previous=null; next=null; } public BHeap merge(BHeap x, BHeap y){ BHeap newHeap = new BHeap(); y.rightSibling=x.root; BHeap currentHeap = y; BHeap nextHeap = y.rightSibling; while(currentHeap.rightSibling !=null){ if(currentHeap.degree==nextHeap.degree){ if(currentHeap.key<nextHeap.key){ if(currentHeap.degree ==0){ currentHeap.leftmostChild=nextHeap; currentHeap.rightmostChild=nextHeap; currentHeap.rightSibling=nextHeap.rightSibling; nextHeap.rightSibling=null; nextHeap.parent=currentHeap; currentHeap.degree++; } else{ newHeap = currentHeap; newHeap.rightmostChild.rightSibling=nextHeap; newHeap.rightmostChild=nextHeap; nextHeap.parent=newHeap; newHeap.degree++; nextHeap.rightSibling=null; nextHeap=newHeap.rightSibling; } } else{ if(currentHeap.degree==0){ nextHeap.rightmostChild=currentHeap; nextHeap.rightmostChild.root = nextHeap.rightmostChild;//add nextHeap.leftmostChild=currentHeap; nextHeap.leftmostChild.root = nextHeap.leftmostChild;//add currentHeap.parent=nextHeap; currentHeap.rightSibling=null; currentHeap.root=currentHeap;//add nextHeap.degree++; } else{ newHeap=nextHeap; newHeap.rightmostChild.rightSibling=currentHeap; newHeap.rightmostChild=currentHeap; currentHeap.parent= newHeap; newHeap.degree++; currentHeap=newHeap.rightSibling; currentHeap.rightSibling=null; } } } else{ currentHeap=currentHeap.rightSibling; nextHeap=nextHeap.rightSibling; } } return y; } public void Insert(int x){ /*BHeap newHeap = new BHeap(); newHeap.key=x; if(this.root==null){ this.root=newHeap; return; } else{ this.root=merge(newHeap,this.root); }*/ BHeap newHeap= new BHeap(); newHeap.key=x; if(this.root==null){ this.root=newHeap; } else{ this.root = merge(this,newHeap); }} public void RemoveMin(){ BHeap newHeap = new BHeap(); BHeap child = new BHeap(); newHeap=this; BHeap pos = newHeap.next; while(pos !=null){ if(pos.key<newHeap.key){ newHeap=pos; } pos=pos.rightSibling; } pos=this; BHeap B1 = new BHeap(); if(newHeap.previous!=null){ newHeap.previous.rightSibling=newHeap.rightSibling; B1 =pos.leftmostChild; B1.rightSibling=pos; pos.leftmostChild=pos.rightmostChild.leftmostChild; } else{ newHeap=newHeap.rightSibling; newHeap.previous.rightSibling=newHeap.rightSibling; B1 =pos.leftmostChild; B1.rightSibling=pos; pos.leftmostChild=pos.rightmostChild.leftmostChild; } merge(newHeap,B1); } public void Display(){ System.out.print("("); System.out.print(this.root.key); if(this.leftmostChild != null){ this.leftmostChild.Display(); } System.out.print(")"); if(this.rightSibling!=null){ this.rightSibling.Display(); } } }

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  • Multithreaded SDL error in C++

    - by wyatt
    I'm building a program in C++, using SDL, and am occasionally receiving this error: * glibc detected * ./assistant: double free or corruption (!prev) It's difficult to replicate, so I can't find exactly what's causing it, but I just added a second thread to the program, and neither thread run on its own seems to cause the error. The threads don't share any variables, though they both run the functions SDL_BlitSurface and SDL_Flip. Could running these concurrently throw up such an error, or am I barking up the wrong tree? If this is the cause, should I simply throw a mutex around all SDL calls? Thanks

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  • X11, how to detect I’m the last window/application on the display

    - by ts
    I have an x11 display with a windowmanager (sadly not a specific one, could be twm, dtwm, mwm, metacity …) , myApp and other applications with windows. I want to close the display if the other applications are closed and myApp is the only one with windows on the display. I do know the windows of myApp, but how do I distinguish between the windows of the windowmanger and of the other applications. I’m currently polling with xwininfo -tree -root -children and comparing this to what I’m expecting, but this only works in a ‘well defined’ environment. It seems that many of the above mentioned windowmanager don’t support EWMH.

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  • Image Upload with Mootools

    - by notme
    I am creating an ajax uploader with mootools. When I remove the ajax and simply upload the form I get $_FILES with the file data present. But when I use the ajax version, the $_FILES super global is empty. Every other part of the form is present. It acts as if it does not send the image at all but only in the ajax version. Any help is appreciated. Thanks! <form id="uploadphoto_pod" action="upload.php" enctype="multipart/form-data" method="post"> <input type='file' id='uploadphoto' name='uploadphoto'/> <input type="submit" class="submit" name="add_product" value="Upload" /> </form> <div id="response"><!-- Ajax Response --></div> <script type="text/javascript"> window.addEvent('domready', function(){ $('uploadphoto').addEvent('submit', function(e) { //Prevents the default submit event from loading a new page. e.stop(); //("this" refers to the $('uploadphoto') element). this.set('send', {onComplete: function(response) { $('response').set('html', response); }}); //Send the form. this.send(); }); }); </script>

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  • Can the LibreOffice LightProof grammar library be used externally?

    - by Phyxx
    LibreOffice 3.5 includes a grammar checker, called (or maybe based on) LightProof. From what I have read, LightProof seems to be a Python library that can be used to check for custom grammar rules. But I can not for the life of me find a project page for LightProof. The closest I got was http://cgit.freedesktop.org/libreoffice/lightproof/tree/, which seems to be the code for the LibreOffice extension, not LightProof itself. So is LightProof actually a library that can be implemented in other applications, or is it just a code word for a LibreOffice feature?

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  • Navigating sharepoint with a treeview

    - by linqmonkey
    I'm trying to replace the navigation on our sharepoint site with a treeview. It's a large site with up to 4 subsite leves in places. All I need it to do is show a consistent structure from page to page show only sites and pages The default sharepoint treeview seems to do neither of these things (doesn't display items from the parent site, includes document libraries but not pages). Does anyone have any idea how to achieve this? We're using the publishing site template throughout if that makes a difference. I've tried binding the tree to the datasource the quick launch uses but I guess from the error message they expect differently named properties.

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  • Optimal strategy to make a C++ hash table, thread safe

    - by Ajeet
    (I am interested in design of implementation NOT a readymade construct that will do it all.) Suppose we have a class HashTable (not hash-map implemented as a tree but hash-table) and say there are eight threads. Suppose read to write ratio is about 100:1 or even better 1000:1. Case A) Only one thread is a writer and others including writer can read from HashTable(they may simply iterate over entire hash table) Case B) All threads are identical and all could read/write. Can someone suggest best strategy to make the class thread safe with following consideration 1. Top priority to least lock contention 2. Second priority to least number of locks My understanding so far is thus : One BIG reader-writer lock(semaphore). Specialize the semaphore so that there could be eight instances writer-resource for case B, where each each writer resource locks one row(or range for that matter). (so i guess 1+8 mutexes) Please let me know if I am thinking on the correct line, and how could we improve on this solution.

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  • What does it mean for a language to be `interpreted'?

    - by Bubba88
    Hi! A newbie question. Do languages like e.g. Ruby (if running MRI, I mean not compiled to byte-code) run actually parsed everytime when an execution of e.g. method or loop body is needed? I mean, to execute a loop, you need to parse its body N times? I just always thought that all these programs are being parsed one time at the bootstrap - transformed in a 'strongly-typed' statements tree etc.. Is that not true?

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  • Why can't I set a layout for a page in a QStackedWidget in designer?

    - by cppguy
    Steps to reproduce in designer for Qt 4.8.0 I create a new dialog form in Qt Designer I add a QStackedWidget to the dialog I set the layout of the dialog to make the stacked layout size with the dialog I add a few controls to page one in the stacked widget I select the first page in the stacked widget in the right hand tree view of controls The icon next to that page (which is a QWidget) shows the page is missing a layout When I click one of the layout buttons above, it doesn't change the layout of the page QWidget, it changes the layout of the dialog even though I had explicitly selected the page. Is this a bug in designer? Am I missing something? I really don't want to add the layouts programatically as that prevents me from being able to layout the pages in designer in the same .ui file

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  • bounding a sprite in cocos2d

    - by Srinivas
    am making a canon to fire objects. back of the canon the plunger is attached. plunger acts for set speed and angle. canon rotates 0-90 degree and plunger moves front and back for adjust speed. when am rotates the canon by touches moved its working fine. when plunger is pull back by touches moved and it rotates means the plunger is bounds outside of the canon. how to control this:- my code for plunger and canon rotation on touches moved. ( para3 is the canon , para6 is my plunger):- CGPoint touchLocation = [self convertTouchToNodeSpace:touch]; CGPoint oldTouchLocation = [touch previousLocationInView:touch.view]; oldTouchLocation = [[CCDirector sharedDirector] convertToGL:oldTouchLocation]; oldTouchLocation = [self convertToNodeSpace:oldTouchLocation]; if (CGRectContainsPoint(CGRectMake(para6.position.x-para6.contentSize.width/2, para6.position.y-para6.contentSize.height/2, para6.contentSize.width, para6.contentSize.height), touchLocation) && (touchLocation.y-oldTouchLocation.y == 0)) { CGPoint diff = ccpSub(touchLocation, oldTouchLocation); CGPoint currentpos = [para6 position]; NSLog(@"%d",currentpos); CGPoint destination = ccpAdd(currentpos, diff); if (destination.x < 90 && destination.x >70) { [para6 setPosition:destination]; speed = (70 + (90-destination.x))*3.5 ; } } if(CGRectIntersectsRect((CGRectMake(para6.position.x-para6.contentSize.width/8, (para6.position.y+30)-para6.contentSize.height/10, para6.contentSize.width, para6.contentSize.height/10)),(CGRectMake(para3.position.x-para3.contentSize.width/2, para3.position.y-para3.contentSize.height/2, para3.contentSize.width, para3.contentSize.height)))) { [para3 runAction:[CCSequence actions: [CCRotateTo actionWithDuration:rotateDuration angle:rotateDiff], nil]]; CGFloat plungrot = (rotateDiff); CCRotateTo *rot = [CCRotateTo actionWithDuration:rotateDuration angle:plungrot]; [para6 runAction:rot]; } }

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  • Check if an object is order-able in python?

    - by sortfiend
    How can I check if an object is orderable/sortable in Python? I'm trying to implement basic type checking for the __init__ method of my binary tree class, and I want to be able to check if the value of the node is orderable, and throw an error if it isn't. It's similar to checking for hashability in the implementation of a hashtable. I'm trying to accomplish something similar to Haskell's (Ord a) => etc. qualifiers. Is there a similar check in Python?

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  • openvpn WARNING: No server certificate verification method has been enabled

    - by tmedtcom
    I tried to install openvpn on debian squeez (server) and connect from my fedora 17 as (client). Here is my configuration: server configuration ###cat server.conf # Serveur TCP ** proto tcp** port 1194 dev tun # Cles et certificats ca /etc/openvpn/easy-rsa/keys/ca.crt cert /etc/openvpn/easy-rsa/keys/server.crt key /etc/openvpn/easy-rsa/keys/server.key dh /etc/openvpn/easy-rsa/keys/dh1024.pem # Reseau #Adresse virtuel du reseau vpn server 192.170.70.0 255.255.255.0 #Cette ligne ajoute sur le client la route du reseau vers le serveur push "route 192.168.1.0 255.255.255.0" #Creer une route du server vers l'interface tun. #route 192.170.70.0 255.255.255.0 # Securite keepalive 10 120 #type d'encryptage des données **cipher AES-128-CBC** #activation de la compression comp-lzo #nombre maximum de clients autorisés max-clients 10 #pas d'utilisateur et groupe particuliers pour l'utilisation du VPN user nobody group nogroup #pour rendre la connexion persistante persist-key persist-tun #Log d'etat d'OpenVPN status /var/log/openvpn-status.log #logs openvpnlog /var/log/openvpn.log log-append /var/log/openvpn.log #niveau de verbosité verb 5 ###cat client.conf # Client client dev tun [COLOR="Red"]proto tcp-client[/COLOR] remote <my server wan IP> 1194 resolv-retry infinite **cipher AES-128-CBC** # Cles ca ca.crt cert client.crt key client.key # Securite nobind persist-key persist-tun comp-lzo verb 3 Message from the host client (fedora 17) in the log file / var / log / messages: Dec 6 21:56:00 GlobalTIC NetworkManager[691]: <info> Starting VPN service 'openvpn'... Dec 6 21:56:00 GlobalTIC NetworkManager[691]: <info> VPN service 'openvpn' started (org.freedesktop.NetworkManager.openvpn), PID 7470 Dec 6 21:56:00 GlobalTIC NetworkManager[691]: <info> VPN service 'openvpn' appeared; activating connections Dec 6 21:56:00 GlobalTIC NetworkManager[691]: <info> VPN plugin state changed: starting (3) Dec 6 21:56:01 GlobalTIC NetworkManager[691]: <info> VPN connection 'Connexion VPN 1' (Connect) reply received. Dec 6 21:56:01 GlobalTIC nm-openvpn[7472]: OpenVPN 2.2.2 x86_64-redhat-linux-gnu [SSL] [LZO2] [EPOLL] [PKCS11] [eurephia] built on Sep 5 2012 Dec 6 21:56:01 GlobalTIC nm-openvpn[7472]:[COLOR="Red"][U][B] WARNING: No server certificate verification method has been enabled.[/B][/U][/COLOR] See http://openvpn.net/howto.html#mitm for more info. Dec 6 21:56:01 GlobalTIC nm-openvpn[7472]: NOTE: the current --script-security setting may allow this configuration to call user-defined scripts Dec 6 21:56:01 GlobalTIC nm-openvpn[7472]:[COLOR="Red"] WARNING: file '/home/login/client/client.key' is group or others accessible[/COLOR] Dec 6 21:56:01 GlobalTIC nm-openvpn[7472]: UDPv4 link local: [undef] Dec 6 21:56:01 GlobalTIC nm-openvpn[7472]: UDPv4 link remote: [COLOR="Red"]<my server wan IP>[/COLOR]:1194 Dec 6 21:56:01 GlobalTIC nm-openvpn[7472]: [COLOR="Red"]read UDPv4 [ECONNREFUSED]: Connection refused (code=111)[/COLOR] Dec 6 21:56:03 GlobalTIC nm-openvpn[7472]: [COLOR="Red"]read UDPv4[/COLOR] [ECONNREFUSED]: Connection refused (code=111) Dec 6 21:56:07 GlobalTIC nm-openvpn[7472]: read UDPv4 [ECONNREFUSED]: Connection refused (code=111) Dec 6 21:56:15 GlobalTIC nm-openvpn[7472]: read UDPv4 [ECONNREFUSED]: Connection refused (code=111) Dec 6 21:56:31 GlobalTIC nm-openvpn[7472]: read UDPv4 [ECONNREFUSED]: Connection refused (code=111) Dec 6 21:56:41 GlobalTIC NetworkManager[691]: <warn> VPN connection 'Connexion VPN 1' (IP Conf[/CODE] ifconfig on server host(debian): ifconfig eth0 Link encap:Ethernet HWaddr 08:00:27:16:21:ac inet addr:192.168.1.6 Bcast:192.168.1.255 Mask:255.255.255.0 inet6 addr: fe80::a00:27ff:fe16:21ac/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:9059 errors:0 dropped:0 overruns:0 frame:0 TX packets:5660 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:919427 (897.8 KiB) TX bytes:1273891 (1.2 MiB) tun0 Link encap:UNSPEC HWaddr 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 inet addr:192.170.70.1 P-t-P:192.170.70.2 Mask:255.255.255.255 UP POINTOPOINT RUNNING NOARP MULTICAST MTU:1500 Metric:1 RX packets:0 errors:0 dropped:0 overruns:0 frame:0 TX packets:0 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:100 RX bytes:0 (0.0 B) TX bytes:0 (0.0 B) ifconfig on the client host (fedora 17) as0t0: flags=4305<UP,POINTOPOINT,RUNNING,NOARP,MULTICAST> mtu 1500 inet 5.5.0.1 netmask 255.255.252.0 destination 5.5.0.1 unspec 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 txqueuelen 200 (UNSPEC) RX packets 0 bytes 0 (0.0 B) RX errors 0 dropped 0 overruns 0 frame 0 TX packets 2 bytes 321 (321.0 B) TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0 as0t1: flags=4305<UP,POINTOPOINT,RUNNING,NOARP,MULTICAST> mtu 1500 inet 5.5.4.1 netmask 255.255.252.0 destination 5.5.4.1 unspec 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 txqueuelen 200 (UNSPEC) RX packets 0 bytes 0 (0.0 B) RX errors 0 dropped 0 overruns 0 frame 0 TX packets 2 bytes 321 (321.0 B) TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0 as0t2: flags=4305<UP,POINTOPOINT,RUNNING,NOARP,MULTICAST> mtu 1500 inet 5.5.8.1 netmask 255.255.252.0 destination 5.5.8.1 unspec 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 txqueuelen 200 (UNSPEC) RX packets 0 bytes 0 (0.0 B) RX errors 0 dropped 0 overruns 0 frame 0 TX packets 2 bytes 321 (321.0 B) TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0 as0t3: flags=4305<UP,POINTOPOINT,RUNNING,NOARP,MULTICAST> mtu 1500 inet 5.5.12.1 netmask 255.255.252.0 destination 5.5.12.1 unspec 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 txqueuelen 200 (UNSPEC) RX packets 0 bytes 0 (0.0 B) RX errors 0 dropped 0 overruns 0 frame 0 TX packets 2 bytes 321 (321.0 B) TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0 **p255p1**: flags=4163<UP,BROADCAST,RUNNING,MULTICAST> mtu 1500 inet 192.168.1.2 netmask 255.255.255.0 broadcast 192.168.1.255 inet6 fe80::21d:baff:fe20:b7e6 prefixlen 64 scopeid 0x20<link> ether 00:1d:ba:20:b7:e6 txqueuelen 1000 (Ethernet) RX packets 4842070 bytes 3579798184 (3.3 GiB) RX errors 0 dropped 0 overruns 0 frame 0 TX packets 3996158 bytes 2436442882 (2.2 GiB) TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0 device interrupt 16 p255p1 is label for eth0 interface and on the server : root@hoteserver:/etc/openvpn# tree . +-- client ¦** +-- ca.crt ¦** +-- client.conf ¦** +-- client.crt ¦** +-- client.csr ¦** +-- client.key ¦** +-- client.ovpn ¦* ¦** +-- easy-rsa ¦** +-- build-ca ¦** +-- build-dh ¦** +-- build-inter ¦** +-- build-key ¦** +-- build-key-pass ¦** +-- build-key-pkcs12 ¦** +-- build-key-server ¦** +-- build-req ¦** +-- build-req-pass ¦** +-- clean-all ¦** +-- inherit-inter ¦** +-- keys ¦** ¦** +-- 01.pem ¦** ¦** +-- 02.pem ¦** ¦** +-- ca.crt ¦** ¦** +-- ca.key ¦** ¦** +-- client.crt ¦** ¦** +-- client.csr ¦** ¦** +-- client.key ¦** ¦** +-- dh1024.pem ¦** ¦** +-- index.txt ¦** ¦** +-- index.txt.attr ¦** ¦** +-- index.txt.attr.old ¦** ¦** +-- index.txt.old ¦** ¦** +-- serial ¦** ¦** +-- serial.old ¦** ¦** +-- server.crt ¦** ¦** +-- server.csr ¦** ¦** +-- server.key ¦** +-- list-crl ¦** +-- Makefile ¦** +-- openssl-0.9.6.cnf.gz ¦** +-- openssl.cnf ¦** +-- pkitool ¦** +-- README.gz ¦** +-- revoke-full ¦** +-- sign-req ¦** +-- vars ¦** +-- whichopensslcnf +-- openvpn.log +-- openvpn-status.log +-- server.conf +-- update-resolv-conf on the client: [login@hoteclient openvpn]$ tree . |-- easy-rsa | |-- 1.0 | | |-- build-ca | | |-- build-dh | | |-- build-inter | | |-- build-key | | |-- build-key-pass | | |-- build-key-pkcs12 | | |-- build-key-server | | |-- build-req | | |-- build-req-pass | | |-- clean-all | | |-- list-crl | | |-- make-crl | | |-- openssl.cnf | | |-- README | | |-- revoke-crt | | |-- revoke-full | | |-- sign-req | | `-- vars | `-- 2.0 | |-- build-ca | |-- build-dh | |-- build-inter | |-- build-key | |-- build-key-pass | |-- build-key-pkcs12 | |-- build-key-server | |-- build-req | |-- build-req-pass | |-- clean-all | |-- inherit-inter | |-- keys [error opening dir] | |-- list-crl | |-- Makefile | |-- openssl-0.9.6.cnf | |-- openssl-0.9.8.cnf | |-- openssl-1.0.0.cnf | |-- pkitool | |-- README | |-- revoke-full | |-- sign-req | |-- vars | `-- whichopensslcnf |-- keys -> ./easy-rsa/2.0/keys/ `-- server.conf the problem source is cipher AES-128-CBC ,proto tcp-client or UDP or the interface p255p1 on fedora17 or file authentification ta.key is not found ????

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  • Windows Server 2003 Terminal Server does not give out all available licenses

    - by Erwin Blonk
    I installed the Terminal Server role in Windows Server 2003 Standard 64-bits. Still, only 2 connections are allowed. The License Manager says that there are 10 Device CALs available, which is correct, and that none are given out. For good measure I let the server reboot, to no effect. Before this, there was another server (same Windows, except that it is 32 bits) active as a licensing server. I removed the role first and then then added it to the new server. I then removed the Terminal Server Licensing Server component off the old one and added it to the new one. After that, I added to licenses. When that didn't give the required result, I rebooted to new server. Still, the new server, with licenses and all, acts as if it has the 2 license RDP. The server are all stand-alone, there is no active directory been set up. Both servers are in different workgroups. Update (4/12/10): The server has changed the entries in the Terminal Server Licensing a few times. After installing the licenses it added an entry of which the exact phrasing I forgot but it was about temporary Windows 2003 device licenses. Later it added Windows Server 2003 - TS Per Device CAL. The temporary held 2 licenses (standard RDP licenses, I think) and the other 10. At some point, seemingly unrelated from the testing we did, it used a licenses from the new pool. This morning, 2 licenses were used from the pool of 10 and only 1 from the temporary/RDP pool (I wish I had screenshots to show, it changed every few hours oir so it seems). Although I had already activated the server over the internet, and re-activated it, I decided to go through the whole procedure by phone. Long story short, here is what it says now: Existing Windows 2000 Server, type:built-in [no licenses used, I add for for sake of being complete] Windows Server 2003 - Terminal Server Per Device CAL Token, type:open [none of 10 used] Windows Server 2003 - TS Per Device CAL, type:open [3 of 10 used] As I tried to explain, this is the end result after a few changes, most of which I can't directly connect to any action from my part. Only going to the activation procedure by phone seemed to directly effect the TS, resulting in the above configuration. Still, it is impossible to connect with more than 3 people, which is 1 up from the 2 that could connect yesterday. TS does say 7 licenses are avaible. Yet it won't give them out.

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  • Windows Server 2003 Terminal Server does not give out all available licenses (solved)

    - by Erwin Blonk
    I installed the Terminal Server role in Windows Server 2003 Standard 64-bits. Still, only 2 connections are allowed. The License Manager says that there are 10 Device CALs available, which is correct, and that none are given out. For good measure I let the server reboot, to no effect. Before this, there was another server (same Windows, except that it is 32 bits) active as a licensing server. I removed the role first and then then added it to the new server. I then removed the Terminal Server Licensing Server component off the old one and added it to the new one. After that, I added to licenses. When that didn't give the required result, I rebooted to new server. Still, the new server, with licenses and all, acts as if it has the 2 license RDP. The server are all stand-alone, there is no active directory been set up. Both servers are in different workgroups. Update (4/12/10): The server has changed the entries in the Terminal Server Licensing a few times. After installing the licenses it added an entry of which the exact phrasing I forgot but it was about temporary Windows 2003 device licenses. Later it added Windows Server 2003 - TS Per Device CAL. The temporary held 2 licenses (standard RDP licenses, I think) and the other 10. At some point, seemingly unrelated from the testing we did, it used a licenses from the new pool. This morning, 2 licenses were used from the pool of 10 and only 1 from the temporary/RDP pool (I wish I had screenshots to show, it changed every few hours oir so it seems). Although I had already activated the server over the internet, and re-activated it, I decided to go through the whole procedure by phone. Update 2 (4/12/10) The problem has been solved. It seems the activation over the web, while it said to have succeeded, did not work correctly. After activating by phone, it did work. What was different from the old setup and what put me on the wrong foot from that moment, was that I now need to create seperate user account because a session with one user account will be taken over by someone else when that account is used by that person. On the previous server, it was possible to open several sesions with the same account. We now use Per Device licenses, I'm not sure what was used before. Thanks all for the replies.

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  • Sharing Bandwidth and Prioritizing Realtime Traffic via HTB, Which Scenario Works Better?

    - by Mecki
    I would like to add some kind of traffic management to our Internet line. After reading a lot of documentation, I think HFSC is too complicated for me (I don't understand all the curves stuff, I'm afraid I will never get it right), CBQ is not recommend, and basically HTB is the way to go for most people. Our internal network has three "segments" and I'd like to share bandwidth more or less equally between those (at least in the beginning). Further I must prioritize traffic according to at least three kinds of traffic (realtime traffic, standard traffic, and bulk traffic). The bandwidth sharing is not as important as the fact that realtime traffic should always be treated as premium traffic whenever possible, but of course no other traffic class may starve either. The question is, what makes more sense and also guarantees better realtime throughput: Creating one class per segment, each having the same rate (priority doesn't matter for classes that are no leaves according to HTB developer) and each of these classes has three sub-classes (leaves) for the 3 priority levels (with different priorities and different rates). Having one class per priority level on top, each having a different rate (again priority won't matter) and each having 3 sub-classes, one per segment, whereas all 3 in the realtime class have highest prio, lowest prio in the bulk class, and so on. I'll try to make this more clear with the following ASCII art image: Case 1: root --+--> Segment A | +--> High Prio | +--> Normal Prio | +--> Low Prio | +--> Segment B | +--> High Prio | +--> Normal Prio | +--> Low Prio | +--> Segment C +--> High Prio +--> Normal Prio +--> Low Prio Case 2: root --+--> High Prio | +--> Segment A | +--> Segment B | +--> Segment C | +--> Normal Prio | +--> Segment A | +--> Segment B | +--> Segment C | +--> Low Prio +--> Segment A +--> Segment B +--> Segment C Case 1 Seems like the way most people would do it, but unless I don't read the HTB implementation details correctly, Case 2 may offer better prioritizing. The HTB manual says, that if a class has hit its rate, it may borrow from its parent and when borrowing, classes with higher priority always get bandwidth offered first. However, it also says that classes having bandwidth available on a lower tree-level are always preferred to those on a higher tree level, regardless of priority. Let's assume the following situation: Segment C is not sending any traffic. Segment A is only sending realtime traffic, as fast as it can (enough to saturate the link alone) and Segment B is only sending bulk traffic, as fast as it can (again, enough to saturate the full link alone). What will happen? Case 1: Segment A-High Prio and Segment B-Low Prio both have packets to send, since A-High Prio has the higher priority, it will always be scheduled first, till it hits its rate. Now it tries to borrow from Segment A, but since Segment A is on a higher level and Segment B-Low Prio has not yet hit its rate, this class is now served first, till it also hits the rate and wants to borrow from Segment B. Once both have hit their rates, both are on the same level again and now Segment A-High Prio is going to win again, until it hits the rate of Segment A. Now it tries to borrow from root (which has plenty of traffic spare, as Segment C is not using any of its guaranteed traffic), but again, it has to wait for Segment B-Low Prio to also reach the root level. Once that happens, priority is taken into account again and this time Segment A-High Prio will get all the bandwidth left over from Segment C. Case 2: High Prio-Segment A and Low Prio-Segment B both have packets to send, again High Prio-Segment A is going to win as it has the higher priority. Once it hits its rate, it tries to borrow from High Prio, which has bandwidth spare, but being on a higher level, it has to wait for Low Prio-Segment B again to also hit its rate. Once both have hit their rate and both have to borrow, High Prio-Segment A will win again until it hits the rate of the High Prio class. Once that happens, it tries to borrow from root, which has again plenty of bandwidth left (all bandwidth of Normal Prio is unused at the moment), but it has to wait again until Low Prio-Segment B hits the rate limit of the Low Prio class and also tries to borrow from root. Finally both classes try to borrow from root, priority is taken into account, and High Prio-Segment A gets all bandwidth root has left over. Both cases seem sub-optimal, as either way realtime traffic sometimes has to wait for bulk traffic, even though there is plenty of bandwidth left it could borrow. However, in case 2 it seems like the realtime traffic has to wait less than in case 1, since it only has to wait till the bulk traffic rate is hit, which is most likely less than the rate of a whole segment (and in case 1 that is the rate it has to wait for). Or am I totally wrong here? I thought about even simpler setups, using a priority qdisc. But priority queues have the big problem that they cause starvation if they are not somehow limited. Starvation is not acceptable. Of course one can put a TBF (Token Bucket Filter) into each priority class to limit the rate and thus avoid starvation, but when doing so, a single priority class cannot saturate the link on its own any longer, even if all other priority classes are empty, the TBF will prevent that from happening. And this is also sub-optimal, since why wouldn't a class get 100% of the line's bandwidth if no other class needs any of it at the moment? Any comments or ideas regarding this setup? It seems so hard to do using standard tc qdiscs. As a programmer it was such an easy task if I could simply write my own scheduler (which I'm not allowed to do).

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  • Need to increase nginx throughput to an upstream unix socket -- linux kernel tuning?

    - by Ben Lee
    I am running an nginx server that acts as a proxy to an upstream unix socket, like this: upstream app_server { server unix:/tmp/app.sock fail_timeout=0; } server { listen ###.###.###.###; server_name whatever.server; root /web/root; try_files $uri @app; location @app { proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header X-Forwarded-Proto $scheme; proxy_set_header Host $http_host; proxy_redirect off; proxy_pass http://app_server; } } Some app server processes, in turn, pull requests off /tmp/app.sock as they become available. The particular app server in use here is Unicorn, but I don't think that's relevant to this question. The issue is, it just seems that past a certain amount of load, nginx can't get requests through the socket at a fast enough rate. It doesn't matter how many app server processes I set up, it doesn't even matter what the app is (tried it with a dummy app with just a single endpoint that returned an empty page with status 404). The bottleneck seems to be the socket, not the app. I'm getting a flood of these messages in the nginx error log: connect() to unix:/tmp/app.sock failed (11: Resource temporarily unavailable) while connecting to upstream Many requests result in status code 502, and those that don't take a long time to complete. The nginx write queue stat hovers around 1000. Anyway, I feel like I'm missing something obvious here, because this particular configuration of nginx and app server is pretty common, especially with Unicorn (it's the recommended method in fact). Are there any linux kernel options that needs to be set, or something in nginx? Any ideas about how to increase the throughput to the upstream socket? Something that I'm clearly doing wrong? Additional information on the environment: $ uname -a Linux app1 3.2.0-24-generic #39-Ubuntu SMP Mon May 21 16:52:17 UTC 2012 x86_64 x86_64 x86_64 GNU/Linux $ ruby -v ruby 1.9.3p194 (2012-04-20 revision 35410) [x86_64-linux] $ unicorn -v unicorn v4.3.1 $ nginx -V nginx version: nginx/1.2.1 built by gcc 4.6.3 (Ubuntu/Linaro 4.6.3-1ubuntu5) TLS SNI support enabled Current kernel tweaks: net.core.rmem_default = 65536 net.core.wmem_default = 65536 net.core.rmem_max = 16777216 net.core.wmem_max = 16777216 net.ipv4.tcp_rmem = 4096 87380 16777216 net.ipv4.tcp_wmem = 4096 65536 16777216 net.ipv4.tcp_mem = 16777216 16777216 16777216 net.ipv4.tcp_window_scaling = 1 net.ipv4.route.flush = 1 net.ipv4.tcp_no_metrics_save = 1 net.ipv4.tcp_moderate_rcvbuf = 1 net.core.somaxconn = 8192 net.netfilter.nf_conntrack_max = 131072

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  • OpenVPN, Great on Windows, VERY slow on Mac...

    - by Phsion
    Hello, I'm not really an IT Pro, but this seemed like the best place to ask this question... I have setup VPN networks in the past, for fun, and everything was great, but now I've set one up for my boss, and while my computers all work great, his Mac machines are almost too slow to work with. Its pretty much vanilla configs all around, anyone have any ideas? Its a TUN routing setup over UDP. Back Story: My boss travels a lot, and wants to be able to access all his files from the road, and is also pretty paranoid about security (even though knows almost nothing about computers). SO i figured a VPN would be the answer. I went with OpenVPN, but there are some other issues. The only ISP we can get in our area besides Dial-UP is a crappy Satellite provider, that doesn't offer public IPs unless your willing to pay, so while the computers and VPN setup are pretty vanilla, the routing and structure is strange to get around this limitation. Specs: Its OpenVPN2, and there are six machines using it (only three actually use it, the rest are my test machines), one Windows 7 laptop, two XP Desktops, one OS X 10.5 Desktop, one 10.6 Desktop, and one 10.6 Laptop. One XP Desktop sits at my house and acts as the server (6Mbs/2Mbs FIOS connection). One XP desktop sits at the office and hosts a webpage that will wake up the Main Mac Desktop from sleep, and also ping all the machines on the VPN and show their status. The main office mac (10.6) stays in sleep mode until it gets the Wake-On-Lan packet from the Office XP, and then it auto connects to the VPN and opens itself up. The reason for all this is the Satellite private IP crap means i cant directly access the office machines outside of the LAN, so everyone connects to my house first, then they talk to each other from there. The Wake On Lan weirdness is because my boss doesn't want to leave the main Mac on all the time, and making a quick and dirty webpage was the easiest way to send a Magic Packet from inside the LAN without confusing my boss. The VPN uses Client Config files to make static IPs for the client. The only thing i found in google was some changes to the VPN MTU settings (down to 1400) but no real help. Oh, and i forgot...all the windows machines just have OpenVPN start as a service. The Mac laptop uses tunnelblick (an OpenVPN GUI) and the Mac Desktops use OpenVPN in normal command line mode. Server Config: tun-mtu 1500 fragment 1450 mssfix 1450 management localhost #### port #### proto udp dev tun ca ####### cert ####### key ###### dh ###### server 10.8.0.0 255.255.255.0 ifconfig-pool-persist ipp.txt client-config-dir ccd route 10.8.0.0 255.255.255.252 client-to-client keepalive 10 120 comp-lzo persist-key persist-tun status openvpn-status log Client Configs (all are simple variations on this) tun-mtu 1500 fragment 1450 mssfix 1450 client dev tun proto udp remote ######## #### resolv-retry infinite nobind persist-key presist-tun ca ##### cert ##### key ##### ns-cert-type server comp-lzo verb 3

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