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  • has_many, belongs_to and comment forms

    - by Koning Baard XIV
    I'm having two models: Snippet and SnippetComment. These also have their own controllers, as well as views. In /app/views/snippets/show.html.erb I have a form that starts like this: <% form_for(@new_snippet_comment) do |form| %> SnippetComment belongs to one Snippet, and a Snippet belongs to one User. This means that I have this routing: map.resources :users do |user| user.resources :snippets do |snippet| snippet.resources :snippet_comments, :as => "comments" end end So when I submit the SnippetComment form in the SnippetController#show view, this request should be made: POST /users/x/snippets/x/comments HTTP/1.1 (where x is the User's or Snippet's id). The problem is that I don't even get the comment submission form, but rahter this: NoMethodError in Snippets#show Showing app/views/snippets/show.html.erb where line #29 raised: undefined method `snippet_comments_path' for Extracted source (around line #29): 26: <% if current_user %> 27: <h2>Schrijf een nieuwe reactie</h2> 28: 29: <% form_for(@new_snippet_comment) do |form| %> 30: 31: <p> 32: <%= form.text_area :body %> RAILS_ROOT: /Users/jeffatwood/Dev/youjustdontneedmyrealname Application Trace | Framework Trace | Full Trace /Users/jeffatwood/.gem/ruby/1.8/gems/actionpack-2.3.5/lib/action_controller/polymorphic_routes.rb:107:in `__send__' /Users/jeffatwood/.gem/ruby/1.8/gems/actionpack-2.3.5/lib/action_controller/polymorphic_routes.rb:107:in `polymorphic_url' /Users/jeffatwood/.gem/ruby/1.8/gems/actionpack-2.3.5/lib/action_controller/polymorphic_routes.rb:114:in `polymorphic_path' /Users/jeffatwood/.gem/ruby/1.8/gems/actionpack-2.3.5/lib/action_view/helpers/form_helper.rb:298:in `apply_form_for_options!' /Users/jeffatwood/.gem/ruby/1.8/gems/actionpack-2.3.5/lib/action_view/helpers/form_helper.rb:277:in `form_for' /Users/jeffatwood/Dev/youjustdontneedmyrealname/app/views/snippets/show.html.erb:29:in `_run_erb_app47views47snippets47show46html46erb' /Users/jeffatwood/Dev/youjustdontneedmyrealname/app/controllers/snippets_controller.rb:19:in `show' Request Parameters: {"id"=>"1", "user_id"=>"2"} Show session dump Response Headers: {"Content-Type"=>"text/html", "Cache-Control"=>"no-cache"} Can anyone help me with this problem? Thanks

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  • How to display a subview loaded from a separate NIB file

    - by Marcus Netter
    I'm developing a Cocoa desktop application that uses a source list in the style of iTunes: different elements in the source list cause the main content area to display different views. The content area is entirely filled with a (vertical) NSSplitView; on the left is an NSOutlineView source list. When the user selects an item on the left, the relevant view appears on the right side of the splitter. I can make it work well enough by putting everything in one NIB file and putting a borderless NSTabView to the right of the splitter; to switch views, I just have to change the selected tab. But putting all the views in one NIB is bad practice, so I'm trying to move each of the subviews into their own NIB files. I have a pretty good idea of most of this process — I've created an NSViewController subclass for each of these views (EntityDetailViewController, GroupDetailViewController, and so on), set the File's Owner of each new NIB to the relevant controller class, set the view connection in each NIB, and reworked the bindings. What I don't know is how to actually change which subview is being shown on screen. I've tried using the default generic NSView on the right side and sending it addSubview: messages; I've tried connecting to it as the first subview and calling NSView *newSubview = /* get subview from the new subview controller */ [[subview superview] replaceSubview:subview with:newSubview]; [self setSubview:newSubview]; But everything just leaves the space blank. How do I display a subview loaded from a separate NIB?

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  • PDO lastInsertId issues, php

    - by Kyle Hudson
    Hi Guys, I have tried lots of ways to get the last inserted ID with the code below (snipplet from larger class) and now I have given up. Does anyone know howto get PDO lastInsertId to work? Thanks in advance. $sql = "INSERT INTO auth (surname, forename, email, mobile, mobilepin, actlink, regdate) VALUES (:surname, :forename, :email, :mobile, :mobpin, :actlink, NOW())"; $stmt = $this->dbh->prepare($sql); if(!$stmt) { return "st"; } $stmt->bindParam(':surname', $this->surname); $stmt->bindParam(':forename', $this->forename); $stmt->bindParam(':email', $this->email); $stmt->bindParam(':mobile', $this->mobile); $stmt->bindParam(':mobpin', $this->mobilePin); $stmt->bindParam(':actlink', $this->actlink); $result = $stmt->execute(); //return var_dump($result); $arr = array(); $arr = $stmt->errorInfo(); $_SESSION['record'] = 'OK' . $dbh->lastInsertId(); $arr .= $_SESSION['record']; return $arr;

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  • A few questions about a Rails model for a simple addressbook app

    - by user284194
    I have a Rails application that lists information about local services. My objectives for this model are as follows: 1. Require the name and tag_list fields. 2. Require one or more of the tollfreephone, phone, phone2, mobile, fax, email or website fields. 3. If the paddress field has a value, then encode it with the Geokit plugin. Here is my entry.rb model: class Entry < ActiveRecord::Base validates_presence_of :name, :tag_list validates_presence_of :tollfreephone or :phone or :phone2 or :mobile or :fax or :email or :website acts_as_taggable_on :tags acts_as_mappable :auto_geocode=>{:field=>:paddress, :error_message=>'Could not geocode physical address'} before_save :geocode_paddress validate :required_info def required_info unless phone or phone2 or tollfreephone or mobile or fax or email or website errors.add_to_base "Please have at least one form of contact information." end end private def geocode_paddress #if paddress_changed? geo=Geokit::Geocoders::MultiGeocoder.geocode (paddress) errors.add(:paddress, "Could not Geocode address") if ! geo.success self.lat, self.lng = geo.lat,geo.lng if geo.success #end end end Requiring name and tag_list work, but requiring one (or more) of the tollfreephone, phone, phone2, mobile, fax, email or website fields does not. As for encoding with Geokit, in order to save a record with the model I have to enter an address. Which is not the behavior I want. I would like it to not require the paddress field, but if the paddress field does have a value, it should encode the geocode. As it stands, it always tries to geocode the incoming entry. The commented out "if paddress_changed?" was not working and I could not find something like "if paddress_exists?" that would work. Help with any of these issues would be greatly appreciated. I posted three questions pertaining to my model because I'm not sure if they are preventing each other from working. Thank you for reading my questions.

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  • problem in split text by php

    - by moustafa
    Hi Team, I need to split the below contents by using the mobile number and email id. If the mobile number and email id found the content is splitted into some blocks. I am using the preg_match_all to check the mobile number and email id. For example : The Given Content: WANTED B'ful Non W'kingEdu Fair Girl for MBA 28/175 H'some Fair Mangal Gotra Boy Well estd. B'ness HI Income Status family Email: [email protected] PQM4 h'some Convent Educated B.techIIT, MS/28/5'9" Wkg in US frm repu fmlyseek b'ful,tall g i r l . Mo:09893029129 Em:[email protected] 5' 2" to 5' 5" b'ful QLFD girl for h a n d s o m e 5' 8" BPT (I) MPT G.Medalist (AUS) wkg in Australia Physiotherapist boy from V.respectable fmly of Surat / DeUli. Tel: 09825147614. EmaU: [email protected] The Desired output should be: 1st block: WANTED B'ful Non W'kingEdu Fair Girl for MBA 28/175 H'some Fair Mangal Gotra Boy Well estd. B'ness HI Income Status family Email: [email protected] 2nd block: PQM4 h'some Convent Educated B.techIIT, MS/28/5'9" Wkg in US frm repu fmlyseek b'ful,tall g i r l . Mo:09893029129 Em:[email protected] 3rd block: 5' 2" to 5' 5" b'ful QLFD girl for h a n d s o m e 5' 8" BPT (I) MPT G.Medalist (AUS) wkg in Australia Physiotherapist boy from V.respectable fmly of Surat / DeUli. Tel: 09825147614. EmaU: [email protected] I do no how to split it.I need some logics. When i am using preg_match_all when ever a mobile number found i inserted a new line and split the blocks.But email id is splitted independently.

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  • How to troubleshoot PHP session file empty issue?

    - by Morgan Cheng
    I have a very simple test page for PHP session. <?php session_start(); if (isset($_SESSIONS['views'])) { $_SESSIONS['views'] = $_SESSIONS['pv'] + 1; } else { $_SESSIONS['views'] = 0; } var_dump($_SESSIONS); ?> After refreshing the page, it always show array 'views' => int 0 The environment is XAMPP 1.7.3. I checked phpInfo(). The session is enabled. Session Support enabled Registered save handlers files user sqlite Registered serializer handlers php php_binary wddx Directive Local Value Master Value session.auto_start Off Off session.bug_compat_42 On On When the page is accessed, there is session file sess_lnrk7ttpai8187v9q6iok74p20 created in my "D:\xampp\tmp" folder. But the content is empty. With Firebug, I can see cookies about the session. Cookie PHPSESSID=lnrk7ttpai8187v9q6iok74p20 It seems session data is not flushed to files. Is there any way or direction to trouble shoot this issue? Thanks.

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  • TeamCity output artifacts not published to IIS7 folder

    - by clausas
    I am trying to set up TeamCity to build and deploy an ASP.NET MVC application. I have the setup running successfully on other servers using TeamCity 4.5, but the new server is running TeamCity 6, and I am having trouble getting it to work as expected. TeamCity manages to get the files from source control, and the project (Visual Studio Solution 2008 set to "Build") builds and outputs the necessary files as expected. The problem seems to be with my artifact paths, as the output files are not copied to the website folder. My solution consists of dozen projects, of which the "Web" project is the interesting one in this case. The build checkout directory is C:\TeamCity\buildAgent\work\7da320cebf0ee541, and the "Web"-project is found in C:\TeamCity\buildAgent\work\7da320cebf0ee541\Web I have set up my build configuration with the following artifact paths (relative from checkout directory to the folder containing the website): Web/bin=>../../../../inetpub/wwwroot/staging/bin Web/Content=>../../../../inetpub/wwwroot/staging/Content Web/Views=>../../../../inetpub/wwwroot/staging/Views Web/Media=>../../../../inetpub/wwwroot/staging/Media Web/*.aspx=>../../../../inetpub/wwwroot/staging Web/*.asax=>../../../../inetpub/wwwroot/staging (I've tried with more ../ just in case, but it didn't make a difference). This is the output I get from the log [19:35:29]: Publishing artifacts (1s) [19:35:29]: [Publishing artifacts] Paths to publish: [Web/bin=../../../../inetpub/wwwroot/staging/bin, Web/Content=../../../../inetpub/wwwroot/staging/Content, Web/obj=../../../../inetpub/wwwroot/staging/obj, Web/Views=../../../../inetpub/wwwroot/staging/Views, Web/Media=../../../../inetpub/wwwroot/staging/Media, Web/.aspx=../../../../inetpub/wwwroot/staging, Web/.asax=../../../../inetpub/wwwroot/staging, teamcity-info.xml] [19:35:30]: [Publishing artifacts] Sending files [19:35:32]: Build finished Logs from some of the other servers running TeamCity 4.5 uses a different format, with a line for each of the artifacts being published, I'm not sure if this is relevant or only due to a different logging format. Everything seems to be working, but no files are put in my website folder after a build, am I missing something here? Any help will be much appreciated :)

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  • Core Data: Overkill for simple, static UITableView-based iPhone App?

    - by David Foster
    Hello! I have a rather simple iPhone app consisting of numerous views containing a single, grouped table view. These views are held together in navigation controllers which are grouped in a tab bar. Simple stuff. My table views do little more than list text (like "Dog", "Cat" and "Weasel") and this data is being served from a collection of plists. It's perhaps worth mentioning too that these tables are 'static' in the sense that their data is pre-determined and will only ever be amended—and if so, very rarely indeed—by the developer (in this case, moi). This rudimentary approach has reached its limits though, and I think I'm going to need something a bit more relational. I have worked a tad with Core Data in the past, but only with apps whose data is determined by user input. I have four closely related questions: Is Core Data overkill for an app consisting mainly of a selection of simple table views? Do you recommend using Core Data to manage data which is predetermine and extremely unlikely to ever change? Can one lock Core Data down so that its data can't change, thereby relinquishing my responsibility as the developer to handle the editing and saving of the managed object context? How do I go about giving Core Data my predetermined data, and in a format I know that it can work with? Thanks a bunch guys.

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  • django: How to make one form from multiple models containing foreignkeys

    - by Tim
    I am trying to make a form on one page that uses multiple models. The models reference each other. I am having trouble getting the form to validate because I cant figure out how to get the id of two of the models used in the form into the form to validate it. I used a hidden key in the template but I cant figure out how to make it work in the views My code is below: views: def the_view(request, a_id,): if request.method == 'POST': b_form= BForm(request.POST) c_form =CForm(request.POST) print "post" if b_form.is_valid() and c_form.is_valid(): print "valid" b_form.save() c_form.save() return HttpResponseRedirect(reverse('myproj.pro.views.this_page')) else: b_form= BForm() c_form = CForm() b_ide = B.objects.get(pk=request.b_id) id_of_a = A.objects.get(pk=a_id) return render_to_response('myproj/a/c.html', {'b_form':b_form, 'c_form':c_form, 'id_of_a':id_of_a, 'b_id':b_ide }) models class A(models.Model): name = models.CharField(max_length=256, null=True, blank=True) classe = models.CharField(max_length=256, null=True, blank=True) def __str__(self): return self.name class B(models.Model): aid = models.ForeignKey(A, null=True, blank=True) number = models.IntegerField(max_length=1000) other_number = models.IntegerField(max_length=1000) class C(models.Model): bid = models.ForeignKey(B, null=False, blank=False) field_name = models.CharField(max_length=15) field_value = models.CharField(max_length=256, null=True, blank=True) forms from mappamundi.mappa.models import A, B, C class BForm(forms.ModelForm): class Meta: model = B exclude = ('aid',) class CForm(forms.ModelForm): class Meta: model = C exclude = ('bid',) B has a foreign key reference to A, C has a foreign key reference to B. Since the models are related, I want to have the forms for them on one page, 1 submit button. Since I need to fill out fields for the forms for B and C & I dont want to select the id of B from a drop down list, I need to somehow get the id of the B form into the form so it will validate. I have a hidden field in the template, I just need to figure how to do it in the views

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  • Webfaction apache + mod_wsgi + django configuration issue

    - by Dmitry Guyvoronsky
    A problem that I stumbled upon recently, and, even though I solved it, I would like to hear your opinion of what correct/simple/adopted solution would be. I'm developing website using Django + python. When I run it on local machine with "python manage.py runserver", local address is http://127.0.0.1:8000/ by default. However, on production server my app has other url, with path - like "http://server.name/myproj/" I need to generate and use permanent urls. If I'm using {% url view params %}, I'm getting paths that are relative to / , since my urls.py contains this urlpatterns = patterns('', (r'^(\d+)?$', 'myproj.myapp.views.index'), (r'^img/(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT + '/img' }), (r'^css/(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT + '/css' }), ) So far, I see 2 solutions: modify urls.py, include '/myproj/' in case of production run use request.build_absolute_uri() for creating link in views.py or pass some variable with 'hostname:port/path' in templates Are there prettier ways to deal with this problem? Thank you. Update: Well, the problem seems to be not in django, but in webfaction way to configure wsgi. Apache configuration for application with URL "hostname.com/myapp" contains the following line WSGIScriptAlias / /home/dreamiurg/webapps/pinfont/myproject.wsgi So, SCRIPT_NAME is empty, and the only solution I see is to get to mod_python or serve my application from root. Any ideas?

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  • Android Hero denies XMLSocket or Socket connection? ....errors #2031, #2048

    - by claudi-ursica
    Hi, I am trying to adapt an existing flash web chat application for the Android mobile phone and I am having this really annoying issue. The server is a custom based solution and can send back both binary messages or XML. So I can use either XMLSocket class or the Socket class to get data from the server. Everything works fine when deployed and I connect from the desktop but when I try it from the android mobile I get the infamous errors #2031, followed by #2048. Now the crossdomain.xml file is rock solid and works well for desktop. When the connect socket method runs I see that the server replies with the crossdomain file but I get the error when running on the mobile. Has anyone bumped into this? Is there some limitation from the mobile phone part. I wasn't able to find anything relevant for this issue, in terms of the phone not allowing Socket or XMLSocket connections. The phone(s) Motorola and HTC run Android 2.1 and indicates the flash FL10,1,123,358 version of flash lite. The issue can be reproduced also on the HTC Desire. Any input on this would be highly appreciated... 10x, Claudiu

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  • error 734 the ppp link control protocal was terminated

    - by satheesh
    Hi, i want to connect my mobile internet to pc using bluetooth device. I installed blue soleil software in my pc. Steps: 1.I can able to pair my cellphone with pc bluetooth device. 2.I selected my device and select bluetooth dialup networking service. 3.It asks an alert "DUN connection with device?" in my mobile. 4.After Clicked "YES", connect bluetooth DUN connection window opens. 5.In that window there was a fields "User Name", "PassWord" which i leave empty and then in "Dial = 99**1#" and click Dial button. 6.After that it say "Registering your computer on the netwok.." and become fails. 7. The Error is as "error 734 the ppp link control protocal was terminated" The same procedure should be followed for Nokia 3110c it works fine.But in my samsung mobile c3053 it not connected also i am tryig with samsung corby pro BT3510 mobile . Is there any settings changes needed for samsung mobiles ? Can anyone help me ? Thanks in advance...........

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  • How can I shared controller logic in ASP.NET MVC for 2 controllers, where they are overriden

    - by AbeP
    Hello, I am trying to implement user-friendly URLS, while keeping the existing routes, and was able to do so using the ActionName tag on top of my controller (http://stackoverflow.com/questions/436866/can-you-overload-controller-methods-in-asp-net-mvc) I have 2 controllers: ActionName("UserFriendlyProjectIndex")] public ActionResult Index(string projectName) { ... } public ActionResult Index(long id) { ... } Basically, what I am trying to do is I store the user-friendly URL in the database for each project. If the user enters the URL /Project/TopSecretProject/, the action UserFriendlyProjectIndex gets called. I do a database lookup and if everything checks out, I want to apply the exact same logic that is used in the Index action. I am basically trying to avoid writing duplicate code. I know I can separate the common logic into another method, but I wanted to see if there is a built-in way of doing this in ASP.NET MVC. Any suggestions? I tried the following and I go the View could not be found error message: [ActionName("UserFriendlyProjectIndex")] public ActionResult Index(string projectName) { var filteredProjectName = projectName.EscapeString().Trim(); if (string.IsNullOrEmpty(filteredProjectName)) return RedirectToAction("PageNotFound", "Error"); using (var db = new PIMPEntities()) { var project = db.Project.Where(p => p.UserFriendlyUrl == filteredProjectName).FirstOrDefault(); if (project == null) return RedirectToAction("PageNotFound", "Error"); return View(Index(project.ProjectId)); } } Here's the error message: The view 'UserFriendlyProjectIndex' or its master could not be found. The following locations were searched: ~/Views/Project/UserFriendlyProjectIndex.aspx ~/Views/Project/UserFriendlyProjectIndex.ascx ~/Views/Shared/UserFriendlyProjectIndex.aspx ~/Views/Shared/UserFriendlyProjectIndex.ascx Project\UserFriendlyProjectIndex.spark Shared\UserFriendlyProjectIndex.spark I am using the SparkViewEngine as the view engine and LINQ-to-Entities, if that helps. thank you!

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  • How to disable server-side caching on IIS 7.5 (asp net mvc3)

    - by troebr
    I'm struggling with my IIS setup regarding caching, here's a brief description of my problem: I'm making a site for mobile and non-mobile, sharing the same controllers. IE: mysite/page will serve either mysite/page.cshtml, or mysite/M/page.cshtml, depending on the device. Here's the catch, it worked fine with my local and integration environment (cassiini and iis 6), but on another machine (2008r2/iis 7.5), apparently there is an aggressive server-side caching policy: If I access the website from a desktop machine, I have the correct pages (desktop version) If now I use my mobile phone to access the site, I will have the desktop version, (which implies a server-side cache, my phone is not using the same network). On the contrary, if I were to restart the server and access the site using my phone first, then I will get the mobile version on my desktop (only for the pages I already visited of course). I tried 2 solutions so far: Disabling OutputCache from my Web.config: <httpModules> [..] <remove name="OutputCache" /> </httpModules> And unchecking "Enable output cache" in "Output Caching" for my site in IIS. What's bugging me is that I do not have this problem with my other server (iis 6.0), although caching is enabled on this one, which leads me to think it is related to iis 7 caching addition. My question is simple: how does one disable server-side caching on IIS 7.5? Thanks in advance for your iis lights!

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  • MySQL Paritioning performance

    - by Imran Pathan
    Measured performance on key partitioned tables and normal tables separately. But we couldn't find any performance improvement with partitioning. Queries are pruned. Using MySQL 5.1.47 on RHEL 4. Table details: UserUsage - Will have entries for user mobile number and data usage for each date. Mobile number and Date as PRI KEY. UserProfile - Queries prev table and stores summary for each mobile number. Mobile number PRI KEY. CREATE TABLE `UserUsage` ( `Msisdn` decimal(20,0) NOT NULL, `Date` date NOT NULL, . . PRIMARY KEY USING BTREE (`Msisdn`,`Date`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 PARTITION BY KEY(Msisdn) PARTITIONS 50; CREATE TABLE `UserProfile` ( `Msisdn` decimal(20,0) NOT NULL, . . PRIMARY KEY (`Msisdn`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 PARTITION BY KEY(Msisdn) PARTITIONS 50; Second table is updated by query select and order by date in first table in a perl program, query is select * from UserUsage where Msisdn=number order by Date desc limit 7 [Process data in perl] update UserProfile values(....) where Msisdn=number explain partition for select, shows row being scanned in a particular partition only. Is something wrong with partition design or queries as partitioning is taking almost same or more time compared to normal tables?

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  • help in selecting a row in a tableview and pushing that row into anotherview? sturgling on this sinc

    - by Madhu
    Hi, I have a list of about 5 items in a tableview which I bought them from a database and now when i am trying to push each of them into different views in DidSelectRow() what I am seeing is it is showing me all the views in all the categories.... here is the code I have written.... Here is the code written in cell for row at indexpath: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } BeautyQuotes *bQuote = (BeautyQuotes*)[mBeautyQ objectAtIndex:indexPath.row]; cell.textLabel.text = bQuote.qBeauty; [cell setAccessoryType:UITableViewCellAccessoryDisclosureIndicator] ; return cell; and in didselectrow() i have written this code: id count1 = [mBeautyQ count]; while (count1--) { object = [mBeautyQ objectAtIndex:count1]; } [mBeautyQ release]; if([[object objectAtIndex:indexPath.row] isEqual : @"Beauty Quotes"]){ [tableView deselectRowAtIndexPath:indexPath animated:NO]; BeautysubViewController *subBeauty = [[BeautysubViewController alloc] initWithNibName:@"BeautysubViewController" bundle:nil]; //subBeauty.selected =[regions objectAtIndex:indexPath.row];(this is not working) [subBeauty setTitle:@"Beauty Quotes"]; NSLog(@"it is about push beauty subview controller"); [self.navigationController pushViewController:subBeauty animated:YES]; [subBeauty release]; } in this way i am pusing all the rows in to different views....but when I am pushing this into beautyquotes it is showing me all other views along with this.... struggling on this a lot please help me in dealing with this....

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  • Correct way to switch between UIView with ARC. My way leads to memory leaks :( (iOS)

    - by Andrei Golubev
    i use xcode 4.4 with ARC on.. I have dynamically created UIViews in the ViewController.m: UIView*myviews[10]; Then in the - (void)viewDidLoad function i fill each of it with pictures i need myviews[viewIndex] = [[UIView alloc]initWithFrame:myrec]; UIImage *testImg; UIImageView * testImgView; testImg = [UIImage imageNamed:[NSString stringWithFormat:@"imgarray%d.png", viewIndex]; testImgView.image = testImg; viewindex++; So all seems to be fine, when i want to jump from one view to another i do with two buttons next: [self.view addSubview:views[viewIndex]]; CATransition *animation = [CATransition animation]; [animation setDelegate:self]; [animation setDuration:1.0f]; [animation setType:@"rippleEffect"]; [animation setSubtype:kCATransitionFromTop]; //[animation setTimingFunction:[CAMediaTimingFunction functionWithName:kCAMediaTimingFunctionEaseInEaseOut]]; [self.view.layer addAnimation:animation forKey:@"transitionViewAnimation"]; Nothing seems to be bad, but the memory consumption grows with huge speed when i switch between views.. and then i get low memory warning or sometimes application will just crash. I have tried to use UIViewController array and was switching between the controllers: nothing changes, the memory low warning is what i end up with.. Maybe i need to clean the memory somehow? But how? ARC does not allow to use release and so on.. last what i have tried (sorry, maybe not very professional) before to add new subview is this NSArray *viewsToRemove = [self.view subviews]; for (UIView *views in viewsToRemove) { [views removeFromSuperview]; } But this does not help either.. Please don't judge too strong, i am still new to iOS and Objective-c..

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  • django multiprocess problem

    - by iKiR
    I have django application, running under lighttpd via fastcgi. FCGI running script looks like: python manage.py runfcgi socket=<path>/main.socket method=prefork \ pidfile=<path>/server.pid \ minspare=5 maxspare=10 maxchildren=10 maxrequests=500 \ I use SQLite. So I have 10 proccess, which all work with the same DB. Next I have 2 views: def view1(request) ... obj = MyModel.objects.get_or_create(id=1) obj.param1 = <some value> obj.save () def view2(request) ... obj = MyModel.objects.get_or_create(id=1) obj.param2 = <some value> obj.save () And If this views are executed in two different threads sometimes I get MyModel instance in DB with id=1 and updated either param1 or param2 (BUT not both) - it depends on which process was the first. (of course in real life id changes, but sometimes 2 processes execute these two views with same id) The question is: What should I do to get instance with updated param1 and param2? I need something for merging changes in different processes. One decision is create interprocess lock object but in this case I will get sequence executing views and they will not be able to be executed simultaneously, so I ask help

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  • Iteratively creating multiple file input fields in Rails

    - by David
    I have a column of product views in a database (e.g. top, bottom, front, back). I'm trying to generate a series of file inputs to allow the user to upload an image for each view. This is the result I'm after: ... <label>Top</label> <input type="file" name="image[Top]"><br> <label>Bottom</label> <input type="file" name="image[Bottom]"><br> <label>Front</label> <input type="file" name="image[Front']"><br> ... This is what I'm trying: <%= views = View.order('name ASC').all.map { |view| [view.name, view.id] } %> <%= views.each { |view| label(view); file_field('image', view) } %> However, all this does is print out the views array a couple of times. Hopefully you Rails experts can point me in the right direction. (I apologize in advance if I'm butchering Ruby.)

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  • Qt: QStackedWidget solution

    - by Martin
    I'm building a Qt application that have about 30 different views (QWidgets). My idea is to use a QStackedWidget to make it easy to switch between the different views in the application. I have two different solutions of how to implement this and use as little memory as possible when the user navigates through the application. Solution 1: Everytime I need to show a view I check if it is already in the stack. (The user might open the same view many times, maybe a view showing an item from a database). If the view is in the stack already it doesn't need to be created again and I can just show the view. The good thing with this solution is that I reuse the views (widgets) so they only need to be created once. This is good as the UI and other stuff should look the same everytime the user show a view, so why not reuse it? The problem with this solution is that every view has childrens. Maybe an object, a QList with objects or other things. A good thing with Qt is that you can use the parent-children mechanism so that the children will be deleted when the parent is deleted. As I never delete the parent (view) I need to handle this myself as the children might need to be deleted from different times when the view is shown. (Maybe the view show a list with objects and the list should be updated from a database each time the view is shown.) Solution 2: Everytime I need to show a QWidget I create a new one and show it. When it is not shown anymore, I delete it from memory. This is a quite easy solution. And as I delete the views when they are not shown both the view and it's children should be deleted from memory so it shouldn't increase memory, am I right? Which one of the solutions do you recommend?

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  • Set bounds for markers generated by jQuery table loop?

    - by abemonkey
    I have some jQuery code that goes through a table of location results and puts corresponding pins on a map. I am having trouble figuring out how to set the bounds so that when it goes through the loop and generates the markers on the map that it zooms and pans to fit the markers in the view. I've tried implementing code from some similar questions on this site but nothing seems to be working. Please let me know what code I should be using and where the heck I should put it in my script: $(function() { var latlng = new google.maps.LatLng(44, 44); var settings = { zoom: 15, center: latlng, disableDefaultUI: false, mapTypeId: google.maps.MapTypeId.ROADMAP }; var map = new google.maps.Map(document.getElementById("map_canvas"), settings); $('tr').each(function(i) { var the_marker = new google.maps.Marker({ title: $(this).find('.views-field-title').text(), map: map, clickable: true, position: new google.maps.LatLng( parseFloat($(this).find('.views-field-latitude').text()), parseFloat($(this).find('.views-field-longitude').text()) ) }); var infowindow = new google.maps.InfoWindow({ content: $(this).find('.views-field-title').text() + $(this).find('.adr').text() }); new google.maps.event.addListener(the_marker, 'click', function() { infowindow.open(map, the_marker); }); }); }); `

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  • How do I use Haml in a view in my new plugin?

    - by Eric
    I'm creating a new plugin for a jruby on rails application that will eventually be turned into a gem. Inside my plugin I have controllers, helpers and views. For my views I'd like to use Haml. The problem is that I can't seem to get it to recognize that they are haml templates. Is it even possible to do this? Is there a way for a plugin to have Haml as a dependency for its view? And by that I mean, I intend for the plugin that I'm creating to have a view created by the plugin, that can be used by the application developer. for example: vendor/ plugins/ my_plugin/ lib/ app/ views/ my_plugin_demo/ index.haml.html controllers/ my_plugin_demo_controller.rb helpers/ In my plugin's init.rb, I tried: require 'my_plugin' require 'haml' #doesn't seem to make a difference :( but that didn't seem to make any difference. Has anybody had any experience with this? I can't seem to find any documentation on how to make this work. Are plugin views restricted to .erb templates?

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  • Android - update widget text

    - by david
    Hi, i have 2 questions about widgets update I have 2 buttons and i need to change one button text when i press the other one, how can i do this? The first time i open the widget it calls the onUpdate method, but it never calls it again. I need to update the widget every 2 seconds and i have this line in the xml. android:updatePeriodMillis="2000" Do i need a service or should it works just with the updatePeriodMillis tag? onUpdate method RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.newswidget); Intent intent = new Intent(context, DetalleConsulta.class); intent.putExtra(DetalleConsulta.CONSULTA_ID_NAME, "3"); PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, intent, 0); views.setOnClickPendingIntent(R.id.btNews, pendingIntent); /* Inicializa variables para llamar el controlador */ this.imei = ((TelephonyManager)context.getSystemService(Context.TELEPHONY_SERVICE)).getDeviceId(); this.controlador = new Controlador(this.imei); try { this.respuestas = this.controlador.recuperarNuevasRespuestas(); if(this.respuestas != null &amp;&amp; this.respuestas.size() &gt; 0){ Iterator&lt;Consulta&gt; iterRespuestas = this.respuestas.iterator(); views.setTextViewText(R.id.btNews, ((Consulta)iterRespuestas.next()).getRespuesta()); } } catch (PersistenciaException e) { //TODO manejar error } appWidgetManager.updateAppWidget(appWidgetIds, views); thx a lot!!!

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  • Refetching a previously visited page

    - by user613665
    All, I am having a field day with page refetching. Any help or pointer will be greatly appreciated!! The behavior is a bit specific to mobile browser. Problem: I have two pages and created a shortcut link to pg#1 in the home page. Through a form submit button, user is taken from pg#1 to pg#2. All that is working fine. Now once I am on pg#2. I will leave the browser and click the shortcut later. The browser will stay on pg#2 and won't go to pg#1 even though the path in URLS is different between the two views. It is almost like Django decides that since I have already visited view#1, it doesn't need to fetch it again. This problem or behavior doesn't happen if I move the same code that handle the two views and the templates to a bare bone test project. Setup: I am using django-registration, context session. I am not using any HTML caching tag. I already have DEBUG turned on in my settings.py. Are there other ways that I can tell what the server is doing. Thanks in advance. pdxMobile Update: Here is the code snippets. def sendmsg(request): if request.method =='POST': messages.add_message(request, messages.INFO, "Hello world") return redirect ('rcvmsg') return render_to_response('sendMsg.html',RequestContext(request)) def rcvmsg(request): '''view that receives the msg.''' printMsg ='Didnt get a message' if messages: thisMsg = messages.get_messages(request) for rcvMsg in thisMsg: printMsg = rcvMsg return render_to_response('rcvMsg.html',{'print_msg':printMsg},RequestContext(request)) URL: url(r'^rcvMsg/','mydomain.mainApp.views.rcvmsg',name='rcvmsg'), (r'^sendMsg/code','mydomain.mainApp.views.sendmsg'),

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  • Dynamically adding custom view to RemoteViews

    - by Naidu
    Could any help me to do this?My code is like: public CustomClass extends View { //uses ondraw() to do something } For displaying my custom view on HomeScreen i created a class to extend Broadcast Receiver public class customAppWidgetProvider extends BroadcastReceiver { public void onReceive(Context context, Intent intent) { String action = intent.getAction(); if (AppWidgetManager.ACTION_APPWIDGET_UPDATE.equals(action)) { RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.main); //Here i want to create my custom view class object and i want to add this view to linear layout in main.xml CustomClass object = new CustomClass(context) ; LinearLayout layout = new LinearLayout(context) ; layout.setLayoutParameters(new LayoutParameters(LayoutParams.WRAP_CONTENT,LayoutParams.WRAP_CONTENT)); layout.addView(object); views.addview(R.id.linearlayout, (ViewGroup) layout) ; views.setOnClickPendingIntent(R.id.analog_appwidget, PendingIntent.getActivity(context, 0, new Intent(context, AlarmClock.class), PendingIntent.FLAG_CANCEL_CURRENT)); int[] appWidgetIds = intent.getIntArrayExtra( AppWidgetManager.EXTRA_APPWIDGET_IDS); AppWidgetManager gm = AppWidgetManager.getInstance(context); gm.updateAppWidget(appWidgetIds, views); } } } But adding viewgroup to RemoteView reference is not working... above main.xml contains only LinearLayout.I want to add custom view object to it.But after running this not showing anything on screen.. please help me to do this.Thanks in Advance.

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