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  • Database INSERT does not take place

    - by reggie
    My code is as follows: <?php include("config.php"); $ip=$_SERVER['REMOTE_ADDR']; if($_POST['id']) { $id=$_POST['id']; $id = mysql_escape_String($id); $ip_sql=mysql_query("select ip_add from Voting_IP where mes_id_fk='$id' and ip_add='$ip'"); $count=mysql_num_rows($ip_sql); if($count==0) { $sql = "update Messages set up=up+1 where mes_id='$id'"; mysql_query($sql); $sql_in = "insert into Voting_IP (mes_id_fk,ip_add) values ('$id','$ip')"; mysql_query($sql_in) or die(mysql_error()); echo "<script>alert('Thanks for the vote');</script>"; } else { echo "<script>alert('You have already voted');</script>"; } $result=mysql_query("select up from Messages where mes_id='$id'"); $row=mysql_fetch_array($result); $up_value=$row['up']; echo "<img src='button.png' width='110' height='90'>"; echo $up_value; } ?> My problem is that the insert process does not take place at all. The script tags echos an alert box. Even the img tag is echoed to the web page. But the insert process does not take place. The config file is fine. Note: This code works on my local machine which has PHP 5.3 but it does not work on the server which has PHP 5.2. Any advice?

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  • Back up a single table in SQL Server

    - by BuckWoody
    SQL Server doesn’t have an easy way to take a table backup, so I often use the bcp (Bulk Copy Program) to accomplish the same goal. I’ve mentioned this before, and someone told me when they tried it they couldn’t restore the table – ah the dangers of telling people half the information! I should have mentioned that you need to have a “format file” ready if the table does not exist at the destination. In my case I already had the table, in this person’s case they did not. The format file can be used to rebuild that table structure before the data is bcp’d in, and you can read more about it here: http://msdn.microsoft.com/en-us/library/ms191516.aspx There’s another way to back up a table, and that’s to create a Filegroup and place the table there. Then you can take a Filegroup backup to back up a single table. Of course, there are other methods of moving a single table’s data in an out, including SQL Server Integration Services and even the older Data Transformation Services, or simply by using hte SQLCMD or PowerShell utilities to run a query and just save the output to a file. In fact, these days I’m using a PowerShell script to build INSERT statements from that query. That could also easily be modified to create the table structure (or modify one if needed) quite easily. Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

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  • how to select the min value using having key word

    - by LOVE_KING
    I have created the table stu_dep_det CREATE TABLE `stu_dept_cs` ( `s_d_id` int(10) unsigned NOT NULL auto_increment, `stu_name` varchar(15) , `gender` varchar(15) , `address` varchar(15),`reg_no` int(10) , `ex_no` varchar(10) , `mark1` varchar(10) , `mark2` varchar(15) , `mark3` varchar(15) , `total` varchar(15) , `avg` double(2,0), PRIMARY KEY (`s_d_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 ROW_FORMAT=DYNAMIC AUTO_INCREMENT=8 ; then Inserted the values INSERT INTO `stu_dept_cs` (`s_d_id`, `stu_name`, `gender`, `address`, `reg_no`, `ex_no`, `mark1`, `mark2`, `mark3`, `total`, `avg`) VALUES (1, 'alex', 'm', 'chennai', 5001, 's1', '70', '90', '95', '255', 85), (2, 'peter', 'm', 'chennai', 5002, 's1', '80', '70', '90', '240', 80), (6, 'parv', 'f', 'mumbai', 5003, 's1', '88', '60', '80', '228', 76), (7, 'basu', 'm', 'kolkatta', 5004, 's1', '85', '95', '56', '236', 79); I want to select the min(avg) using having keyword and I have used the following sql statement SELECT * FROM stu_dept_cs s having min(avg) Is it correct or not plz write the correct ans....

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  • Searching 2 fields at the same time

    - by donpal
    I have a table of first and last names firstname lastname --------- --------- Joe Robertson Sally Robert Jim Green Sandra Jordan I'm trying to search this table based on an input that consists of the full name. For example: input: Joe Robert I thought about using SELECT * FROM tablename WHERE firstname LIKE BUT the table stores the first and last name separately, so I'm not sure how to do the search in this case

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  • Monitor SQL Server Replication Jobs

    - by Yaniv Etrogi
    The Replication infrastructure in SQL Server is implemented using SQL Server Agent to execute the various components involved in the form of a job (e.g. LogReader agent job, Distribution agent job, Merge agent job) SQL Server jobs execute a binary executable file which is basically C++ code. You can download all the scripts for this article here SQL Server Job Schedules By default each of job has only one schedule that is set to Start automatically when SQL Server Agent starts. This schedule ensures that when ever the SQL Server Agent service is started all the replication components are also put into action. This is OK and makes sense but there is one problem with this default configuration that needs improvement  -  if for any reason one of the components fails it remains down in a stopped state.   Unless you monitor the status of each component you will typically get to know about such a failure from a customer complaint as a result of missing data or data that is not up to date at the subscriber level. Furthermore, having any of these components in a stopped state can lead to more severe problems if not corrected within a short time. The action required to improve on this default settings is in fact very simple. Adding a second schedule that is set as a Daily Reoccurring schedule which runs every 1 minute does the trick. SQL Server Agent’s scheduler module knows how to handle overlapping schedules so if the job is already being executed by another schedule it will not get executed again at the same time. So, in the event of a failure the failed job remains down for at most 60 seconds. Many DBAs are not aware of this capability and so search for more complex solutions such as having an additional dedicated job running an external code in VBS or another scripting language that detects replication jobs in a stopped state and starts them but there is no need to seek such external solutions when what is needed can be accomplished by T-SQL code. SQL Server Jobs Status In addition to the 1 minute schedule we also want to ensure that key components in the replication are enabled so I can search for those components by their Category, and set their status to enabled in case they are disabled, by executing the stored procedure MonitorEnableReplicationAgents. The jobs that I typically have handled are listed below but you may want to extend this, so below is the query to return all jobs along with their category. SELECT category_id, name FROM msdb.dbo.syscategories ORDER BY category_id; Distribution Cleanup LogReader Agent Distribution Agent Snapshot Agent Jobs By default when a publication is created, a snapshot agent job also gets created with a daily schedule. I see more organizations where the snapshot agent job does not need to be executed automatically by the SQL Server Agent  scheduler than organizations who   need a new snapshot generated automatically. To assure this setting is in place I created the stored procedure MonitorSnapshotAgentsSchedules which disables snapshot agent jobs and also deletes the job schedule. It is worth mentioning that when the publication property immediate_sync is turned off then the snapshot files are not created when the Snapshot agent is executed by the job. You control this property when the publication is created with a parameter called @immediate_sync passed to sp_addpublication and for an existing publication you can use sp_changepublication. Implementation The scripts assume the existence of a database named PerfDB. Steps: Run the scripts to create the stored procedures in the PerfDB database. Create a job that executes the stored procedures every hour. -- Verify that the 1_Minute schedule exists. EXEC PerfDB.dbo.MonitorReplicationAgentsSchedules @CategoryId = 10; /* Distribution */ EXEC PerfDB.dbo.MonitorReplicationAgentsSchedules @CategoryId = 13; /* LogReader */ -- Verify all replication agents are enabled. EXEC PerfDB.dbo.MonitorEnableReplicationAgents @CategoryId = 10; /* Distribution */ EXEC PerfDB.dbo.MonitorEnableReplicationAgents @CategoryId = 13; /* LogReader */ EXEC PerfDB.dbo.MonitorEnableReplicationAgents @CategoryId = 11; /* Distribution clean up */ -- Verify that Snapshot agents are disabled and have no schedule EXEC PerfDB.dbo.MonitorSnapshotAgentsSchedules; Want to read more of about replication? Check at my replication posts at my blog.

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  • using checkbox yo update MySql table

    - by Martin
    Hi All I have been searching round the internet for days on this matter but I keep coming up against a brick wall. What I have is a table full of checkboxes inside an admin area acting as a monthly "to-do" list. It's essentially a worksheet of 30 or so things to do each month that must be checked off each month and notes added if applicable. I have managed to get the checkboxes to update via mysql and be shown somewhere as a list of ticks. I simply did this my setting the value to 1 and on submission it updates the sql table. I have to cover my bases here and also offer the option to un-tick items if they have been ticked b y mistake. But I cant figure out how this is done. Below is my checking code... any help on this matter would be great. <?php $currentTask = ''; echo "<tr class='tr'>"; while ($seolistRow = mysql_fetch_array($seolistRes)) { $taskValue = $seolistRow["taskValue"]; $worksheetID = $seolistRow["worksheetID"]; $taskName = $seolistRow["taskName"]; $taskInfo = $seolistRow["taskInfo"]; if ($taskValue == 1) { $taskDone = "<input type='checkbox' value='1' class='checkbox' name='checkbox".$worksheetID."' id=checkbox'".$worksheetID."' checked='checked' /><div class='taskinfo'>".$taskInfo."</div>"; } else { $taskDone = "<input type='checkbox' value='0' class='checkbox' name='checkbox".$worksheetID."' id='checkbox".$worksheetID."' />"; } if ($currentTask != $taskName) { echo "</tr>"; echo "<tr class='tr'>"; echo "<td class='task'>".$taskName."</td>"; } echo "<td class='tick'>".$taskDone."</td>"; $currentTask = $taskName; } echo "</tr>"; ?>

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  • using PHP to create multidimensional array from simple JSON array

    - by Michael Robinson
    I have a php query the returns the following JSON format from a table. [{"memberid":"18", "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School", }, It needs the following format: [{"memberid":"18" { "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School",} }, I was told in another question that PHP would work and it looks like "Transversing" might be appropriate, I'm looking to find out what to put in the Php before it returns the JASON. My Array.plist will look like the following: Root: Dictionary V Rows: Array V Item 0: Dictionary Title: String 18 V Children Array V Item 0 Dictionary Title String 30 etc. Thanks in advance.

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  • Problem with ColdFusion communicating with MySQL database

    - by Greg
    Hi, I have been working to migrate a non-profit website from a local server (running Windows XP) to a GoDaddy hosting account (running Linux). Most of the pages are written in ColdFusion. Things have gone smoothly, up until this point. There is a flash form within the site (see this page: http://www.preservenet.cornell.edu/employ/submitjob.cfm) which, when completed, takes the visitor to this page: submitjobaction.cfm . I'm not quite sure what to make of this error, since I copied exactly what had been in the old MySQL database, and the .cfm files are exactly as they had been when they worked on the old server. Am I missing something? Below is the code from the database that the error seems to be referring to. When I change "Positionlat" to some default value in the database as it suggests in the error, it says that another field needs a default value, and it's a neverending chain of errors as I try to correct it. This is probably a stupid error that I'm missing, but I've been working at it for days and can't find what I'm missing. I would really appreciate any help. Thanks! -Greg DROP TABLE IF EXISTS employopp; CREATE TABLE employopp ( POSTID int(10) NOT NULL auto_increment, USERID varchar(10) collate latin1_general_ci default NULL, STATUS varchar(10) collate latin1_general_ci NOT NULL default 'ACTIVE', TYPE varchar(50) collate latin1_general_ci default 'professional', JOBTITLE varchar(70) collate latin1_general_ci default NULL, NUMBER varchar(30) collate latin1_general_ci default NULL, SALARY varchar(40) collate latin1_general_ci default NULL, ORGNAME varchar(70) collate latin1_general_ci default NULL, DEPTNAME varchar(70) collate latin1_general_ci default NULL, ORGDETAILS mediumtext character set utf8 collate utf8_unicode_ci, ORGWEBSITE varchar(200) collate latin1_general_ci default NULL, ADDRESS varchar(60) collate latin1_general_ci default 'none given', ADDRESS2 varchar(60) collate latin1_general_ci default NULL, CITY varchar(30) collate latin1_general_ci default NULL, STATE varchar(30) collate latin1_general_ci default NULL, COUNTRY varchar(3) collate latin1_general_ci default 'USA', POSTALCODE varchar(10) collate latin1_general_ci default NULL, EMAIL varchar(75) collate latin1_general_ci default NULL, NOMAIL varchar(5) collate latin1_general_ci default NULL, PHONE varchar(20) collate latin1_general_ci default NULL, FAX varchar(20) collate latin1_general_ci default NULL, WEBSITE varchar(200) collate latin1_general_ci default NULL, POSTDATE varchar(10) collate latin1_general_ci default NULL, POSTUNTIL varchar(20) collate latin1_general_ci default 'select date', POSTUNTILFILLED varchar(20) collate latin1_general_ci NOT NULL default 'until filled', texteHTML mediumtext character set utf8 collate utf8_unicode_ci, HOWTOAPPLY mediumtext character set utf8 collate utf8_unicode_ci, CONFIRSTNM varchar(30) collate latin1_general_ci default NULL, CONLASTNM varchar(60) collate latin1_general_ci default NULL, POSITIONCITY varchar(30) collate latin1_general_ci default NULL, POSITIONSTATE varchar(30) collate latin1_general_ci default NULL, POSITIONCOUNTRY varchar(3) collate latin1_general_ci default 'USA', POSITIONLAT varchar(50) collate latin1_general_ci NOT NULL, POSITIONLNG varchar(50) collate latin1_general_ci NOT NULL, PRIMARY KEY (POSTID) ) ENGINE=MyISAM AUTO_INCREMENT=2007 DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci;

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  • Do I have to use mysql_real_escape_string if I bind parameters?

    - by Babak
    I have the following code: function dbPublish($status) { global $dbcon, $dbtable; if(isset($_GET['itemId'])) { $sqlQuery = 'UPDATE ' . $dbtable . ' SET active = ? WHERE id = ?'; $stmt = $dbcon->prepare($sqlQuery); $stmt->bind_param('ii', $status, $_GET['itemId']); $stmt->execute(); $stmt->close(); } } Do I need to mysql_real_escape_string in this case or am i okay?

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  • Check if Database Exists

    - by Derek Dieter
    In creating a database you also need to check whether or not the database already exists. In order to do so, simply use the ‘if exists’ method and select the name of the database from sysdatabases.IF NOT EXISTS (SELECT name FROM master.dbo.sysdatabases WHERE name = N'SQLServerPlanet') CREATE DATABASE [SQLServerPlanet]The code below will drop an [...]

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  • How to fix unresolved external symbol due to MySql Connector C++?

    - by Chan
    Hi everyone, I followed this tutorial http://blog.ulf-wendel.de/?p=215#hello. I tried both on Visual C++ 2008 and Visual C++ 2010. Either static or dynamic, the compiler gave me the same exact error messages: error LNK2001: unresolved external symbol _get_driver_instance Has anyone experience this issue before? Update: + Additional Dependencies: mysqlcppconn.lib + Additional Include Directories: C:\Program Files\MySQL\MySQL Connector C++ 1.0.5\include + Additional Libraries Directories: C:\Program Files\MySQL\MySQL Connector C++ 1.0.5\lib\opt Thanks, Chan Nguyen

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  • Manage and Monitor Identity Ranges in SQL Server Transactional Replication

    - by Yaniv Etrogi
    Problem When using transactional replication to replicate data in a one way topology from a publisher to a read-only subscriber(s) there is no need to manage identity ranges. However, when using  transactional replication to replicate data in a two way replication topology - between two or more servers there is a need to manage identity ranges in order to prevent a situation where an INSERT commands fails on a PRIMARY KEY violation error  due to the replicated row being inserted having a value for the identity column which already exists at the destination database. Solution There are two ways to address this situation: Assign a range of identity values per each server. Work with parallel identity values. The first method requires some maintenance while the second method does not and so the scripts provided with this article are very useful for anyone using the first method. I will explore this in more detail later in the article. In the first solution set server1 to work in the range of 1 to 1,000,000,000 and server2 to work in the range of 1,000,000,001 to 2,000,000,000.  The ranges are set and defined using the DBCC CHECKIDENT command and when the ranges in this example are well maintained you meet the goal of preventing the INSERT commands to fall due to a PRIMARY KEY violation. The first insert at server1 will get the identity value of 1, the second insert will get the value of 2 and so on while on server2 the first insert will get the identity value of 1000000001, the second insert 1000000002 and so on thus avoiding a conflict. Be aware that when a row is inserted the identity value (seed) is generated as part of the insert command at each server and the inserted row is replicated. The replicated row includes the identity column’s value so the data remains consistent across all servers but you will be able to tell on what server the original insert took place due the range that  the identity value belongs to. In the second solution you do not manage ranges but enforce a situation in which identity values can never get overlapped by setting the first identity value (seed) and the increment property one time only during the CREATE TABLE command of each table. So a table on server1 looks like this: CREATE TABLE T1 (  c1 int NOT NULL IDENTITY(1, 5) PRIMARY KEY CLUSTERED ,c2 int NOT NULL ); And a table on server2 looks like this: CREATE TABLE T1(  c1 int NOT NULL IDENTITY(2, 5) PRIMARY KEY CLUSTERED ,c2 int NOT NULL ); When these two tables are inserted the results of the identity values look like this: Server1:  1, 6, 11, 16, 21, 26… Server2:  2, 7, 12, 17, 22, 27… This assures no identity values conflicts while leaving a room for 3 additional servers to participate in this same environment. You can go up to 9 servers using this method by setting an increment value of 9 instead of 5 as I used in this example. Continues…

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  • Complex Rails queries across multiple tables, unions, and will_paginate. Solved.

    - by uberllama
    Hi folks. I've been working on a complex "user feed" type of functionality for a while now, and after experimenting with various union plugins, hacking named scopes, and brute force, have arrived at a solution I'm happy with. S.O. has been hugely helpful for me, so I thought I'd post it here in hopes that it might help others and also to get feedback -- it's very possible that I worked on this so long that I walked down an unnecessarily complicated road. For the sake of my example, I'll use users, groups, and articles. A user can follow other users to get a feed of their articles. They can also join groups and get a feed of articles that have been added to those groups. What I needed was a combined, pageable feed of distinct articles from a user's contacts and groups. Let's begin. user.rb has_many :articles has_many :contacts has_many :contacted_users, :through => :contacts has_many :memberships has_many :groups, :through => :memberships contact.rb belongs_to :user belongs_to :contacted_user, :class_name => "User", :foreign_key => "contacted_user_id" article.rb belongs_to :user has_many :submissions has_many :groups, :through => :submissions group.rb has_many :memberships has_many :users, :through => :memberships has_many :submissions has_many :articles, :through => :submissions Those are the basic models that define my relationships. Now, I add two named scopes to the Article model so that I can get separate feeds of both contact articles and group articles should I desire. article.rb # Get all articles by user's contacts named_scope :by_contacts, lambda {|user| {:joins => "inner join contacts on articles.user_id = contacts.contacted_user_id", :conditions => ["articles.published = 1 and contacts.user_id = ?", user.id]} } # Get all articles in user's groups. This does an additional query to get the user's group IDs, then uses those in an IN clause named_scope :by_groups, lambda {|user| {:select => "DISTINCT articles.*", :joins => :submissions, :conditions => {:submissions => {:group_id => user.group_ids}}} } Now I have to create a method that will provide a UNION of these two feeds into one. Since I'm using Rails 2.3.5, I have to use the construct_finder_sql method to render a scope into its base sql. In Rails 3.0, I could use the to_sql method. user.rb def feed "(#{Article.by_groups(self).send(:construct_finder_sql,{})}) UNION (#{Article.by_contacts(self).send(:construct_finder_sql,{})})" end And finally, I can now call this method and paginate it from my controller using will_paginate's paginate_by_sql method. HomeController.rb @articles = Article.paginate_by_sql(current_user.feed, :page => 1) And we're done! It may seem simple now, but it was a lot of work getting there. Feedback is always appreciated. In particular, it would be great to get away from some of the raw sql hacking. Cheers.

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  • Altering a Column Which has a Default Constraint

    - by Dinesh Asanka
    Setting up a default column is a common task for  developers.  But, are we naming those default constraints explicitly? In the below  table creation, for the column, sys_DateTime the default value Getdate() will be allocated. CREATE TABLE SampleTable (ID int identity(1,1), Sys_DateTime Datetime DEFAULT getdate() ) We can check the relevant information from the system catalogs from following query. SELECT sc.name TableName, dc.name DefaultName, dc.definition, OBJECT_NAME(dc.parent_object_id) TableName, dc.is_system_named  FROM sys.default_constraints dc INNER JOIN sys.columns sc ON dc.parent_object_id = sc.object_id AND dc.parent_column_id = sc.column_id and results would be: Most of the above columns are self-explanatory. The last column, is_system_named, is to identify whether the default name was given by the system. As you know, in the above case, since we didn’t provide  any default name, the  system will generate a default name for you. But the problem with these names is that they can differ from environment to environment.  If example if I create this table in different table the default name could be DF__SampleTab__Sys_D__7E6CC920 Now let us create another default and explicitly name it: CREATE TABLE SampleTable2 (ID int identity(1,1), Sys_DateTime Datetime )   ALTER TABLE SampleTable2 ADD CONSTRAINT DF_sys_DateTime_Getdate DEFAULT( Getdate()) FOR Sys_DateTime If we run the previous query again we will be returned the below output. And you can see that last created default name has 0 for is_system_named. Now let us say I want to change the data type of the sys_DateTime column to something else: ALTER TABLE SampleTable2 ALTER COLUMN Sys_DateTime Date This will generate the below error: Msg 5074, Level 16, State 1, Line 1 The object ‘DF_sys_DateTime_Getdate’ is dependent on column ‘Sys_DateTime’. Msg 4922, Level 16, State 9, Line 1 ALTER TABLE ALTER COLUMN Sys_DateTime failed because one or more objects access this column. This means, you need to drop the default constraint before altering it: ALTER TABLE [dbo].[SampleTable2] DROP CONSTRAINT [DF_sys_DateTime_Getdate] ALTER TABLE SampleTable2 ALTER COLUMN Sys_DateTime Date   ALTER TABLE [dbo].[SampleTable2] ADD CONSTRAINT [DF_sys_DateTime_Getdate] DEFAULT (getdate()) FOR [Sys_DateTime] If you have a system named default constraint that can differ from environment to environment and so you cannot drop it as before, you can use the below code template: DECLARE @defaultname VARCHAR(255) DECLARE @executesql VARCHAR(1000)   SELECT @defaultname = dc.name FROM sys.default_constraints dc INNER JOIN sys.columns sc ON dc.parent_object_id = sc.object_id AND dc.parent_column_id = sc.column_id WHERE OBJECT_NAME (parent_object_id) = 'SampleTable' AND sc.name ='Sys_DateTime' SET @executesql = 'ALTER TABLE SampleTable DROP CONSTRAINT ' + @defaultname EXEC( @executesql) ALTER TABLE SampleTable ALTER COLUMN Sys_DateTime Date ALTER TABLE [dbo].[SampleTable] ADD DEFAULT (Getdate()) FOR [Sys_DateTime]

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  • Adding binary checkbox values to MySQL database using PHP

    - by klyv
    I'm new to PHP, and I am creating a basic CMS using PHP and MySQL. I'm struggling to get the checkbox information from my HTML page across into the database. How can I make the values to appear as binary 0 or 1 values? The HTML document is written as follows: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>Create your news page</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> </head> <body> <fieldset> <legend>Checked components will show in the page</legend> <form method="POST" action="http://*********.php"> <span class="label">Header</span> <input type="checkbox" name="header" value="HEADER"> <br> <span class="label">Footer</span> <input type="checkbox" name="footer" value="FOOTER"> <hr> <span class="label">Local news</span> <input type="checkbox" name="local" value="LOCALNEWS"> <br> <span class="label">National news</span> <input type="checkbox" name="national" value="NATIONALNEWS"> <br> <span class="label">International news</span> <input type="checkbox" name="international" value="INTERNATIONALNEWS"> <p> <input type="submit"> </form> </fieldset> </body> </html> And the PHP document is written as follows: <?php $user="user_***"; $password="*********"; $database="dbxyz"; mysql_connect("localhost", $user, $password); mysql_select_db($database, $db_handle); mysql_select_db("dbxyz"); if(isset($_POST['layout'])) { foreach($_POST['layout'] as $value { $insert="INSERT INTO layout (header, footer, local, national, international) VALUES ('$value')"; mysql_query($insert); } } ?>

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  • mysql index optimization for a table with multiple indexes that index some of the same columns

    - by Sean
    I have a table that stores some basic data about visitor sessions on third party web sites. This is its structure: id, site_id, unixtime, unixtime_last, ip_address, uid There are four indexes: id, site_id/unixtime, site_id/ip_address, and site_id/uid There are many different types of ways that we query this table, and all of them are specific to the site_id. The index with unixtime is used to display the list of visitors for a given date or time range. The other two are used to find all visits from an IP address or a "uid" (a unique cookie value created for each visitor), as well as determining if this is a new visitor or a returning visitor. Obviously storing site_id inside 3 indexes is inefficient for both write speed and storage, but I see no way around it, since I need to be able to quickly query this data for a given specific site_id. Any ideas on making this more efficient? I don't really understand B-trees besides some very basic stuff, but it's more efficient to have the left-most column of an index be the one with the least variance - correct? Because I considered having the site_id being the second column of the index for both ip_address and uid but I think that would make the index less efficient since the IP and UID are going to vary more than the site ID will, because we only have about 8000 unique sites per database server, but millions of unique visitors across all ~8000 sites on a daily basis. I've also considered removing site_id from the IP and UID indexes completely, since the chances of the same visitor going to multiple sites that share the same database server are quite small, but in cases where this does happen, I fear it could be quite slow to determine if this is a new visitor to this site_id or not. The query would be something like: select id from sessions where uid = 'value' and site_id = 123 limit 1 ... so if this visitor had visited this site before, it would only need to find one row with this site_id before it stopped. This wouldn't be super fast necessarily, but acceptably fast. But say we have a site that gets 500,000 visitors a day, and a particular visitor loves this site and goes there 10 times a day. Now they happen to hit another site on the same database server for the first time. The above query could take quite a long time to search through all of the potentially thousands of rows for this UID, scattered all over the disk, since it wouldn't be finding one for this site ID. Any insight on making this as efficient as possible would be appreciated :) Update - this is a MyISAM table with MySQL 5.0. My concerns are both with performance as well as storage space. This table is both read and write heavy. If I had to choose between performance and storage, my biggest concern is performance - but both are important. We use memcached heavily in all areas of our service, but that's not an excuse to not care about the database design. I want the database to be as efficient as possible.

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  • Recap - SQL Saturday 151 in Orlando

    - by KKline
    It's always a feel-good experience for me to return to SQL Saturday in Orlando, the place where SQL Saturdays were started by Andy Warren ( Twitter | Blog ). On this trip, I delivered a full-day, pre-conference seminar on Troubleshooting and Performance Tuning SQL Server. I also delivered a session on SQL Server Internals and Architecture to a totally packed house. For those of you who emailed me directly, here's the link for the special SQL Sentry offer . I got to attend the extended events session...(read more)

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  • Query not returning rows in a table that don't have corresponding values in another [associative] ta

    - by Obay
    I have Table: ARTICLES ID | CONTENT --------------- 1 | the quick 2 | brown fox 3 | jumps over 4 | the lazy Table: WRITERS ID | NAME ---------- 1 | paul 2 | mike 3 | andy Table: ARTICLES_TO_WRITERS ARTICLE_ID | WRITER_ID ----------------------- 1 | 1 2 | 2 3 | 3 To summarize, article 4 has no writer. So when I do a "search" for articles with the word "the": SELECT a.id, a.content, w.name FROM articles a, writers w, articles_to_writers atw WHERE a.id=atw.article_id AND w.id=atw.writer_id AND content LIKE '%the%' article 4 does not show up in the result: ID | CONTENT | NAME ----------------------- 1 | the quick | paul How do I make article 4 still appear in the results even though it has no writers?

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  • Optimize GROUP BY&ORDER BY query

    - by Jan Hancic
    I have a web page where users upload&watch videos. Last week I asked what is the best way to track video views so that I could display the most viewed videos this week (videos from all dates). Now I need some help optimizing a query with which I get the videos from the database. The relevant tables are this: video (~239371 rows) VID(int), UID(int), title(varchar), status(enum), type(varchar), is_duplicate(enum), is_adult(enum), channel_id(tinyint) signup (~115440 rows) UID(int), username(varchar) videos_views (~359202 rows after 6 days of collecting data, so this table will grow rapidly) videos_id(int), views_date(date), num_of_views(int) The table video holds the videos, signup hodls users and videos_views holds data about video views (each video can have one row per day in that table). I have this query that does the trick, but takes ~10s to execute, and I imagine this will only get worse over time as the videos_views table grows in size. SELECT v.VID, v.title, v.vkey, v.duration, v.addtime, v.UID, v.viewnumber, v.com_num, v.rate, v.THB, s.username, SUM(vvt.num_of_views) AS tmp_num FROM video v LEFT JOIN videos_views vvt ON v.VID = vvt.videos_id LEFT JOIN signup s on v.UID = s.UID WHERE v.status = 'Converted' AND v.type = 'public' AND v.is_duplicate = '0' AND v.is_adult = '0' AND v.channel_id <> 10 AND vvt.views_date >= '2001-05-11' GROUP BY vvt.videos_id ORDER BY tmp_num DESC LIMIT 8 And here is a screenshot of the EXPLAIN result: So, how can I optimize this?

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  • Delete Job by Name

    - by Derek D.
    When scripting out jobs using ssms (sql server management studio) the default script for a drop statement is to drop the job according to it’s job_id. This is not beneficial however when pushing code to different environments. Job_id’s are specific to the windows environment in which they are created. To get around [...]

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  • using sp_addrolemember

    - by Derek Dieter
    To add a user or group to a role, you need to use sp_addrolemember. This procedure is easy to use as it only accepts two parameters, the role name, and the username (or group). Roles are utilized in order to provide a layer of abstraction from permissions from being applied directly to users. While [...]

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  • fetching rows from mysql table and displaying them as JGROWL notifications

    - by jeansymolanza
    hey guys, i am having problems implementing my php/mysql code into a jgrowl if you are familiar with jgrowl you will know it delivers notifications like Growl does for OS X i am trying to get it read all the records from my table but at the moment it is only displaying one record as a notification and it loops through it 4 times another problem is that if i have 5 rows in the table then jgrowl will only display 4 notifications are going to be viewed how do i get it to view all the records in the table as notifications and how do i display the total number of records (5) as notifications and account for the missing one at the moment thanking you guys in advance... God bless <script type="text/javascript"> // In case you don't have firebug... if (!window.console || !console.firebug) { var names = ["log", "debug", "info", "warn", "error", "assert", "dir", "dirxml", "group", "groupEnd", "time", "timeEnd", "count", "trace", "profile", "profileEnd"]; window.console = {}; for (var i = 0; i < names.length; ++i) window.console[names[i]] = function() {}; } (function($){ $(document).ready(function(){ // This specifies how many messages can be pooled out at any given time. // If there are more notifications raised then the pool, the others are // placed into queue and rendered after the other have disapeared. $.jGrowl.defaults.pool = 5; var i = 1; var y = 1; setInterval( function() { if ( i < <?php echo $totalRows_comment; ?> ) { <?php echo '$.jGrowl("'.$row_comment['comment'].'",'; ?> { sticky: true, log: function() { console.log("Creating message " + i + "..."); }, beforeOpen: function() { console.log("Rendering message " + y + "..."); y++; } }); } i++; } , 1000 ); }); })(jQuery); </script> <p> </span> <p>

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  • SQL query: Delete a entry which is not present in a join table?

    - by Mestika
    Hi, I’m going to delete all users which has no subscription but I seem to run into problems each time I try to detect the users. My schemas look like this: Users = {userid, name} Subscriptionoffering = {userid, subscriptionname} Now, what I’m going to do is to delete all users in the user table there has a count of zero in the subscriptionoffering table. Or said in other words: All users which userid is not present in the subscriptionoffering table. I’ve tried with different queries but with no result. I’ve tried to say where user.userid <> subscriptionoffering.userid, but that doesn’t seem to work. Do anyone know how to create the correct query? Thanks Mestika

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  • Microsoft SQL Server 2008 R2 Administration Cookbook

    - by ssqa.net
    Its one year on my first book released, keeping aside the financial gains from this book I'm more happy to achieve one of the important goals from my career. This is something big in my life to announce, it gives immensive pleasure and happiness to share about my first book (hard paper) and eBook release, titled : Microsoft SQL Server 2008 R2 Administration Cookbook is released and out now. share my experience and task based real-world best practices in a cookbook style. My thanks to the technical...(read more)

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