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  • Content-type not working in PHP

    - by Industrial
    Hi everyone, I have some issues with a PHP file that is not working properly. The Content-type does not get recieved by any browser at all. Firebug interprets the file as text/html instead of css. Here's the file : <?php header('Content-Type: text/css; charset=UTF-8'); error_reporting(E_ALL | E_STRICT); ini_set('display_errors', 'On'); /* CSS goes on from here */ I tested to put a row with echo 'TEST'; before the header line, and was expecting to see the classic "headers already sent" error, but nothing appears! What can I do to sort this out?

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  • PHP: How To call Standard Library Functions

    - by Andi
    Hi, I'm starting with PHP for dynamic web pages. I have some libaries written in ANSI C for getting/setting parameters and other proprietary stuff. I wonder, is there a simple solution to use a wrapper inside PHP to call this funtions? Is there a already existing class/library? What would be the best practice to do this on my own? I don't want do make calls to external applications and use stdin/stdout! Is there a simple example available? I don't want to dig through the Zend documentation for now, I only need a feeling for the complexity. Thanks, kind regards, Andi

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  • Add parameter to PHP

    - by proyb2
    When I sent an image to the code below, uploadImage.php, through a POST method, how do I add a String parameter? <?php $hasError = false; foreach( $_FILES as $i=>$file ) { if ( $file['error'] ) { $hasError = true; } } if ( ! $hasError ) { $myFilePath = '_uploads/'.'_'.$file["name"]; $dta = file_get_contents($file['tmp_name']); file_put_contents($myFilePath, $dta); } else { echo('Stick custom error message here'); } ?>

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  • Php mysqli and stored-procedure

    - by Mneva skoko
    I have a stored procedure: Create procedure news(in dt datetime,in title varchar(10),in desc varchar(200)) Begin Insert into news values (dt,title,desc); End Now my php: $db = new mysqli("","","",""); $dt = $_POST['date']; $ttl = $_POST['title']; $desc = $_POST['descrip']; $sql = $db-query("CALL news('$dt','$ttl','$desc')"); if($sql) { echo "data sent"; }else{ echo "data not sent"; } I'm new with php please help thank you

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  • pdf file creation in php

    - by pavun_cool
    Actually I have used following code , for creating the simple pdf file . It executed fine in the browsers. But I am not able to get the pdf file . But it gives me some output when I am running the code in CLI . my doubt is , where I need specify pdf file name ( creation file ) . <?php require('fpdf.php'); $pdf=new FPDF(); $pdf->AddPage(); $pdf->SetFont('Arial','B',16); $pdf->Cell(40,10,'Hello World!'); $pdf->Output(); ?> CLI output: 2 0 obj << /Type /Page /Parent 1 0 R /Contents 3 0 R endobj 3 0 obj << /Length 4 0 R stream 2.834646 0 0 2.834646 0 841.9 cm 2 J 0.2 w BT /F1 5.64 Tf ET BT 11 -16.692 Td (Hello World!) Tj ET

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  • Creating thumbnails PHP problem

    - by Wayne
    I have this source code where I got it from net tutsplus. I have configured it and made it work in one PHP file. It does work by transferring the original image, but it does not generate to the thumbnails folder. <?php $final_width_of_image = 100; $path_to_image_directory = "../../img/events/" . urldecode($_GET['name']) . "/"; $path_to_thumbs_directory = "../../img/events/" . urldecode($_GET['name']) . "/thumbnails/"; function createThumbnail($filename) { if(preg_match('/[.](jpg)$/', $filename)) { $im = imagecreatefromjpeg($path_to_image_directory . $filename); } elseif(preg_match('/[.](gif)$/', $filename)) { $im = imagecreatefromgif($path_to_image_directory . $filename); } elseif(preg_match('/[.](png)$/', $filename)) { $im = imagecreatefrompng($path_to_image_directory . $filename); } $ox = imagesx($im); $oy = imagesy($im); $nx = $final_width_of_image; $ny = floor($oy * ($final_width_of_image / $ox)); $nm = imagecreatetruecolor($nx, $ny); imagecopyresized($nm, $im, 0,0,0,0,$nx,$ny,$ox,$oy); imagejpeg($nm, $path_to_thumbs_directory . $filename); $tn = '<img src="' . $path_to_thumbs_directory . $filename . '" alt="image" />'; echo $tn; } if(isset($_FILES['fupload'])) { if(preg_match('/[.](jpg)|(gif)|(png)$/', $_FILES['fupload']['name'])) { $filename = $_FILES['fupload']['name']; $source = $_FILES['fupload']['tmp_name']; $target = $path_to_image_directory . $filename; move_uploaded_file($source, $target); createThumbnail($filename); } } ?> Basically it is supposed to generate a thumbnail of the uploaded image and store the original image into a different folder. The paths are correct, it works by getting the folder name in the URL, it does work, but nothing works for the thumbnails folder. BEFORE you ask this related question, yes, thumbnails generation does work on my server by the PHP GD, I have tested it separately. So this is not the problem. :) How do I get this to work? :(

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  • PHP While() Stop Looping

    - by Axel
    Hi, i have a php loop which displays only one record even if there is hundreds. here is the code: <?php $result1 = mysql_query("SELECT * FROM posts") or die(mysql_error()); $numexem = mysql_num_rows($result1); $s="0"; while($s<$numexem){ $postid=mysql_result($result1,$s,"id"); echo "Post id:".$postid; $result2 = mysql_query("SELECT * FROM pics WHERE postid='$postid'") or die(mysql_error()); $rows = mysql_fetch_array($result2) or die(mysql_error()); $pnum = mysql_num_rows($result2); echo " There is ".$pnum." Attached Pictures"; $s++; } ?> I'm wondering if the loop stop because there is other SQL query inside it or what? and i don't think so. Thanks

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  • php : echo"", print(), printf()

    - by marc-andre menard
    Is there a better way to output data to html page with PHP ? if i like to make a div with some var in php i will write something like that print ('<div>'.$var.'</div>); or echo "'<div>'.$var.'</div>'"; what is the PROPER way to do that ? or a better way, fill a $tempvar and print it once? like that: $tempvar = '<div>'.$var.'</div>' print ($tempvar); in fact, in real life, the var will be fill with much more !

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  • php: ip2long returning negative val

    - by andufo
    hi, function ip_address_to_number($IPaddress) { if(!$IPaddress) { return false; } else { $ips = split('\.',$IPaddress); return($ips[3] + $ips[2]*256 + $ips[1]*65536 + $ips[0]*16777216); } } that function executes the same code as the php bundled function ip2long. however, when i print these 2 values, i get 2 different returns. why? (im using php 5.2.10 on a wamp environment). ip2long('200.117.248.17'); //returns -931792879 ip_address_to_number('200.117.248.17'); // returns 3363174417

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  • Unix tree convert to recursive php array

    - by Fordnox
    I have a response from remote server like this: /home/computer/Downloads |-- /home/computer/Downloads/Apple | `-- /home/computer/Downloads/Apple/Pad |-- /home/computer/Downloads/Empty_Folder `-- /home/computer/Downloads/Subfolder |-- /home/computer/Downloads/Subfolder/Empty `-- /home/computer/Downloads/Subfolder/SubSubFolder `-- /home/computer/Downloads/Subfolder/SubSubFolder/Test this is the output for command computer@athome:$ tree -df --noreport -L 5 /home/computer/Downloads/ I would like to parse this string to recursive php array or object, something like this. I would show only part of result to get the idea. array( 'title' => '/home/computer/Downloads', 'children' => array( 0 => array( 'title' => '/home/computer/Downloads/Apple', 'children' => array( ... ) ) ); Response from server can change according to scanned directory. Can someone help me write this function. Please note that this is response from remote server and php functions can not scan any remote dir.

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  • What some good PHP jobs?

    - by ggfan
    I am no professional PHP coder or anything, in fact I am fairly new. I can develop sites but nothing too crazy or fancy with PHP,Mysql,CSS,HTML,javascript. Up to now, all I have been doing is practice coding from books and websites. I am now looking for a 'real-life' experience. Besides going to a company and getting an interview, are there any other options in which I can get paid to code? I have posted some ads on craiglists but that's about it. And because this is my first time going to the 'real-word' and can make mistakes, am I liable if...a site I made for someone gets hacked and that person losses information?

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  • Flex / ZendAMF / PHP app, corrupted data with some linux clients problem

    - by Laurent Jégou
    Hello, i'm buiding a survey web application, using Flex for the front-end (nice forms), and a MySQL database for the storage, linked by PHP with the help of ZendAMF. I largely borrowed from this nice tutorial by Alan Gruskoff : http://digitalshowcase.biz/wordpress/?page_id=26 (The only one tutorial i've found to work with the last version of Flex). The app seems to works nicely in my tests, except on certain linux boxes : the data is somehow corrupted : there is no error message, no glitch, but the response of the forms are not what the user selected. I tried to reproduce the error on a fresh installed ubuntu VM, but it works fine. I've asked friends for some tests, and several linux users showed the same problem, on ubuntu and suse machines, all freshly updated and functionnal. The application was targeted to be the survey tool for my doctoral thesis, so i'm quite desperate here, and before i'm dumping it to start anew with php only, i'm asking here in case someone can help, thanks :-) Please excuse my english, by the way. LJ.

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  • PHP can be exclusively accessed by SWF

    - by brett
    I'm not sure how to describe this, but basically I have a PHP class file: class HelloHello { public function getSomeData($input_parameter){ // code to retrieve data from the database } public function deleteSomeData($input_parameter){ // code to delete data from the database } } This class is on the server and is part of the backend that connects with a database, and it's meant to be accessed by the frontend SWF only (not to be directly accessed). I've setup Flex to read this class and access it. But how do I make sure that someone doesn't develop a script that can call this php file directly and access its methods? For example using a script to add data in a fast automated way, or use the delete method directly, ouch. Is this a legitimate concern, or this can't be done?

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  • php foreach visible on page

    - by Hintswen
    In my PHP code I have this: $filename = 'data.xml'; $xml = file_get_contents($filename); $data = simplexml_load_string($xml); $variable = ""; foreach ($data->file_info as $record) { $id1 = $record['id1']; $id2 = $record['id2']; } And it works perfectly fine on the web server, but when trying to view it locally (using xampp) I get the following output at the top of my pgae: file_info as $record) { $id1 = $record['id1']; $id2 = $record['id2']; } (followed by another 100 or so lines of PHP) Not sure if it would make a difference, the web server it works on is running linux, and I am trying to view it on windows using xampp)

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  • PHP Session code work differently on two servers

    - by williamsdb
    I have some code which works fine on one server but is giving a session header warning: Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent on another. I have checked the php.ini settings on the two servers and they are identical. I know that the warning message is supposed to suggest that something has been outputted before the session_start but what I don't understand is why the same code works on one server but not the other. Is there anything else that could be explaining it other than the php.ini settings?

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  • How to strip a GET property from the URL using PHP

    - by James
    I have the following function that get's the current page URL: <?php // get current page url function currentPageUrl() { $pageURL = 'http'; if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";} $pageURL .= "://"; if ($_SERVER["SERVER_PORT"] != "80") { $pageURL .= $_SERVER["SERVER_NAME"].":".$_SERVER["SERVER_PORT"].$_SERVER["REQUEST_URI"]; } else { $pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"]; } echo $pageURL; } ?> Which prints: http://localhost/gallery.php?id=23&type=main I want to remove "&type=main" which is present in the url. So before echoing $pageURL I add the following line: $pageUrl = preg_replace("&type=main", "", $pageURL); But it still returns the full url including type=main. How can I get rid of that from the url?

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  • Lightweight PHP library alternative to common MVC frameworks

    - by artarad
    Hi hi, I'm looking for a easy to learn php library to use for my coming web app project. I've recently finished a web app with fully handwritten raw php code and it's absolutely hard to be done again for another project. even though I have the recent project code snippets to be used again, but due to their non-structural arrangement (not object oriented), i have no passion to use 'em again. I have no experience with common frameworks like ZF, CakePhp, CodeIgniter, so I think to get my hands on a multipurpose OO library for my web app and the framework learning will be the next step! any suggestion? UPDATE: Many thanks guys, I have not enough time to get through the depth of every lib or framework you have kindly introduced. Since I'm going one step further I'm going to use ZF as famous framework which could provide me more job opportunities perhaps. thankssss :)

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  • PHP upload file using PUT instead of POST

    - by Marco Demaio
    I read something about this on PHP docs, but it's not celar to me: Do the most widely used browsers (IE, FF, Chrome, Safari, Opera, ...) support this PUT method to uplaod files? What HTML should I write to make the browser call the server via PUT request. I mean do I need to write a FORM with an INPUT file field and just replace the attribute method="POST" with the method="PUT"? On the PHP docs (link above) they say a PUT request is much simplier than a POST request when uploading file, along with this advantage, what other advantages/disadvanatges do the PUT has comapred to teh POST? Thanks!

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  • PHP Linefeeds (\n) Not Working

    - by dosboy
    For some reason I can't use \n to create a linefeed when outputting to a file with PHP. It just writes "\n" to the file. I've tried using "\\n" as well, where it just writes "\n" (as expected). But I can't for the life of me figure out why adding \n to my strings isn't creating new lines. I've also tried \r\n but it just appends "\r\n" to the line in the file. Example: error_log('test\n', 3, 'error.log'); error_log('test2\n', 3, 'error.log'); Outputs: test\ntest2\n Using MAMP on OSX in case that matters (some sort of PHP config thing maybe?). Any suggestions?

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  • ixwebhosting php mail() issues with subject

    - by Dave
    I encounter a very strange problem with ixwebhosting. I am able to send email using the php mail() function with $subject = "test"; But if $subject = "testing of information send"; then i won't be able to receive any email But actually "Mail sent!" was displayed in the php page. if (!mail($email, $subject, $body, $from)) { echo "Error Sending Email!"; } else { echo "Mail sent!"; }

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