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• Display a MYSQL field using CAKE

  - by adam

  Forgive me if this is a "homework" question. We have a "Rating" table in our mysql db. I want to display this number on our user profile page. JUST BELOW THE GRAVATAR. here is the code in app/views/user/view.ctp <div class="nhplft"> flash(); ? ?d=identicon&s=100" border="0" alt="My Avatar! UID:" / Change Image link("Home",'/items'); ?  |  link('Add',array('controller' = 'items','action'='add')); ?  |  link('Search',array('controller'='items','action'='index')); ?  |  link("Logout",'/users/logout'); } ?

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• php extract data from mysql

  - by florin

  I have this mysql table with the following rows: id_cont suma_lun month year -------------------------------------------- FL28 2133 March 2012 FL28 2144 April 2012 FL28 2155 May 2012 FL28 2166 June 2012 How can i extract suma_lun, month and year foreach id_cont? so that i get an output like this: ID: Month: Monthly Sum: Year: ---------------------------------------------- FL28 March 2133 2012 April 2144 2012 May 2155 2012 June 2166 2012 This is my current code: $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) die ('Could not connect to database: '.mysql_error()); mysql_select_db(DB_DATABASE,$link); $sql="SELECT * FROM test WHERE id_cont = '$cur'"; $result=mysql_query($sql); while ($row=mysql_fetch_array($result)) { $a=$row["id_cont"]; $b=$row["suma_lun"]; $c=$row["month"]; $d=$row["year"]; } I echo the data in a table Thanks!

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• MySql products and categories tables using php and json

  - by Romina Mora

  I have just started learning all this coding language and the teacher is asking us to do the following. I know it may sound really easy for people who do this full time or have more time coding. The teacher is always telling us to GOOGLE everything and I have tried too many sites but I haven't found anything that helps me at all. I need to write two JSON documents (products and categories) using PHP that will dynamically read values from my MySQL database. When each document is called upon, it will return perfectly formatted JSON that will validate using http://jsonlint.com/ Honestly I don't know what to do. I don't understand PHP and now this JSON thing is making it more confusing.

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• How to Practically Split Values from CSV File into MySQL Database

  - by Ryan

  Let's suppose I have the following line in a CSV file (I removed the header row in this example): "500,000",2,50,2,90000 I have a PHP script read the CSV file, break the file into individual lines, and store each line in an array called $linearray. Then, I use a foreach loop to look at each line individually. Within the foreach loop, I break the line into separate variables using the following function: $line = str_replace("'","\'",$line); From here, I insert the values into separate columns within a MySQL database. The script works. The values are inserted into a database, but I run into a problem. I want: "500,000" | 2 | 50 | 2 | 90000 But I get this: "500 | 000" | 2 | 50 | 2 | 90000 The script isn't smart enough to understand it should skip commas within quotation marks. Do you know how I can alter my script to make sure I get the output I'm looking for? Thanks.

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• Approaches for Error Code/Message Management in .NET

  - by WayneC

  Looking for suggestions/best practices on managing error codes and messages in a multi-tiered applications. Specifically things like: Where should error codes be defined? Enum? Class? How are error messages or further details associated with the error codes? resource files? attributes on enum values, etc.? If you have a multi-tier application consisting of DAL, BLL, UI, and Common projects for example, should there be a single giant list of codes for all tiers, or are the codes extensible by project/tier? Update: Important to mention that I can't rely solely on Exceptions and custom Exception types for error reporting, as some clients for this application will be via web services (SOAP & REST) Any suggestions welcome!

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• MySQL Conventions?

  - by Moe

  Hi There, I just moved my website to a new server (Shared to VPS) I expected errors, and the only error that is really puzzling me is this SQL statement. echo mysql_query("SELECT COUNT(*) FROM users_online_now") This returns nothing! And if I try the mysql_num_rows, it returns mysql_num_rows(): supplied argument is not a valid MySQL result resource.. If I query another table though eg: echo mysql_query("SELECT COUNT(*) FROM users") It works fine. I'm guessing it's something to do with the naming of the table? It worked fine on my previous host, is there some setting I should modify?

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• setting codeigniter mysql datetime column to time() always sets it to 0

  - by Jake

  Hi guys. I'm using Codeigniter for a small project, and my model works correctly except for the dates. I have a column defined: created_at datetime not null and my model code includes in its array passed into db-insert: 'created_at' = time() This produces a datetime value of 0000-00-00 00:00:00. When I change it to: 'created_at' = "from_unixtime(" . time() . ")" it still produces the 0 datetime value. What am I doing wrong? How can I set this field to the given unix time? Also, I know mysql sets TIMESTAMP columns automatically for you - I'm not interested in that solution here. So far I can't find a complete example of this on the web.

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• Mysql advanced SELECT, or multiple SELECTS? Movies keywords

  - by Supyxy

  I have a mysql database with movies as follows: MOVIES(id,title) KEYWORDS_TABLE(id,key_id) [id is referenced to movies.id, key_id is refernced to keywords.id] KEYWORDS(id,keyword) //this doesn't matter on my example.. Basically i have movies with their titles and plot keywords for each one, i want to select all movies that have the same keywords with with a given movie id. I tried something like: SELECT key_id FROM keywords_table WHERE id=9 doing that in php and storing all the IDs in an array $key_id.. then i build another select that looks like: SELECT movies.title FROM movies,keywords_table WHERE keywords_table.key_id=$key_id[1] OR keywords_table.key_id=$key_id[2] OR ......... OR keywords_table.key_id=$key_id[n] This kinda works but it takes too much time as we talk about a database with thousands of thousands of records. So, any suggestions?? thanks!

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• MySQL Rank Not Matching High Score in Table

  - by boddie

  While making a game the MySQL call to get the top 10 is as follows: SELECT username, score FROM userinfo ORDER BY score DESC LIMIT 10 This seems to work decently enough, but when paired with a call to get a individual player's rank the numbers may be different if the player has a tied score with other players. The call to get the players rank is as follows: SELECT (SELECT COUNT(*) FROM userinfo ui WHERE (ui.score, ui.username) >= (uo.score, uo.username)) AS rank FROM userinfo uo WHERE username='boddie'; Example results from first call: +------------+-------+ | username | score | +------------+-------+ | admin | 4878 | | test3 | 3456 | | char | 785 | | test2 | 456 | | test1 | 253 | | test4 | 78 | | test7 | 0 | | boddie | 0 | | Lz | 0 | | char1 | 0 | +------------+-------+ Example results from second call +------+ | rank | +------+ | 10 | +------+ As can be seen, the first call ranks the player at number 8 on the list, but the second call puts him at number 10. What changes or what can I do to make these calls give matching results? Thank you in advance for any help!

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• Question about mysql indexes on low to medium cardinality columns

  - by Kevin J

  I have a general question about the way that database indexing works, particularly in mysql. Let's say I have a table with a million rows with a column "ClientID" that is distributed relatively equally among 30 values. Thus, this column is very low cardinality (30) relative to the primary key (1 million). Now, I understand that you shouldn't create indexes on low cardinality fields. However, in this case, queries are only ever done with one of the 30 clientIDs. Thus, wouldn't creating an index on ClientID be helpful, as the search space is automatically reduced to 1/30th what it normally would be? Or is my understanding of how the index works flawed? Thanks

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• searching a mysql database

  - by Bill Parson

  currently i have a database of music that i have db'd in mysql, now i am writing a php frontend for it, and it will list out everything in a table, it works, but if i search "the beatles" it gives me 453 results(correct) however if i just search "beatles" it results in 0 rows, how would i go about making it able to search for something like that? heres my current line: $query2 = "SELECT * From `songs` WHERE `Artist` like '".$_REQUEST['q']."' OR `Album` like '".$_REQUEST['q']."' OR `Genre` like '".$_REQUEST['q']."' OR `Title` like '".$_REQUEST['q']."';";

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• Microsoft Office Access error

  - by CREFLY

  Hi All While I am running on MS Access myapplication.mdb, I am always getting this error "Microsoft Office Access Has encountered a problem and needs to close. We are sorry for the inconvenience, send error to report , don't send...". I tried to create a new application.mdb then to import the database, the form and the modules but I couldn't because I'm getting the same error while I'm importing most of the modules. P.S.: I'm trying to import the modules one by one but for the majority of the modules I encounter this error. I tried to open an old version of myapplication.mdb then to import the updated modules but just when I selected the damaged application to import the updated module I got this famous error directly... Any help will be highly appreciated...

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• Displaying mysql results as an object?

  - by Michael

  If I have a database with the structure: ___id_____|____value____ 1 | value1 2 | value2 3 | value3 How can I pull data from this MySQL database in PHP and have it formatted like this: Array ( [0] => stdClass Object ( [id] => 1 [value] => value1 ) [1] => stdClass Object ( [id] => 2 [value] => value2 ) [2] => stdClass Object ( [id] => 3 [value] => value3 ) )

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• inserting date timestamp value to mysql thru php in godaddy hosting site

  - by Suj

  Hi all, I'm using GoDaddy's Shared Linux hosting. Using php i am inserting or updating the mysql database with create date or modified date using the variables $datestring = "%Y:%m:%d %h:%i:%s"; $time = time(); $createdate= mdate($datestring, $time); In this $createdate will be the variable i use to insert or update the table. But its updating the wrong value. ITs not the server time or localtime. mostly its 30 mins delay with godaddy's server time. Pls help.

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• MySql - only update some rows if the table exists - do not want an error thrown

  - by Pete Oakey

  I want to run an update query. The query will be run against multiple databases - not every database will have the table. I don't want the update to be attempted if the table does not exist. I don't want any error to be thrown - I just want the update to be ignored. Any ideas? EDIT: just to be clear - the query is executed in an automated deployment - no human interaction possible. EDIT2: the logic to say whether the update should run or not will need to be in the MySql query itself. This is not being run through a command prompt or batch or managed code.

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• Inserting records in Mysql with INSERT IGNORE and NULL values

  - by Homer1980ar

  I have a partitioned table InnoDB with several fields. I'm trying to avoid duplicates on insert. Let's say: Field1 int null Field2 int null Field3 int null Field4 int null Field5 int null I have created a UNIQUE index on those fields. I try to insert some records with NULL values and then try to reinsert them with IGNORE feature on MySql. Unfortunately it seems to replicated the records when using NULL values. If I try with zeros instead of NULL cases everything works, but I do need the nulls there. Any idea? Thanks, Leonardo

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• how to insert date in mysql table

  - by mithun1538

  Hello everyone, I have a mysql table called pollOfTheWeek. It has a column "pollDate" of type date. I have two questions regarding this : 1. I declared the column while creating the table as [pollDate date] What I wanted is that this column be set automatically, when the user doesnt enter any value for this column. How do i declare the column to achieve this? Assuming that I have the same declaration as above, how do I enter an empty value. I mean if the column was of type varchar, I would enter empty value as " ". But since it is of type date, I get error when I enter the value as " ". How do I enter empty value for the pollDate column?

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• MySQL Inserting into locked aliased table

  - by Whitey

  I am trying to insert data into a InnoDB MySQL table which is locked using an alias and I cannot for the life of me get it to work! The following works: LOCK TABLES Problems p1 WRITE, Problems p2 WRITE, Server READ; SELECT * FROM Problems p1; UNLOCK TABLES; But try and do an insert and it doesn't work (it claims there is a syntax error round the 'p1' in my INSERT): LOCK TABLES Problems p1 WRITE, Problems p2 WRITE, Server READ; INSERT INTO Problems p1 (SomeCol) VALUES(43534); UNLOCK TABLES; Help please!

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• Mysql query - problem with order by

  - by Sergio

  I'm using two tables for selecting messages between users. Table "messages" for recording the messages and table "members" for checking users data (are they activ or deleted). This query working fine. What I need to do is list the received messsages order by last received. I tried to do with "ORDER BY messages.id DESC" at the end of this query but it didn't work. All messages are listed from first received. This is the mysql join table query that I'm using: sql = "select distinct messages.fromid, messages.readed, messages.fromid, messages.toid, members.id as pid From messages Inner Join members on members.id = messages.fromid Where messages.toid = ".$mid." AND members.status = 7 AND messages.kreaded !='1' AND messages.subject != 'readed' GROUP BY fromid" Is there any way to do this?

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• Automated URL checking from a MySQL table

  - by Rob

  Okay, I have a list of URLs in a MySQL table. I want the script to automatically check each link in the table for 404, and afterward I want it to store whether the URL was 404'd or not, as well as store a time for last checked. Is this even possible to do automatically, even if no one runs the script? ie, no one visits the page for a few days, but even with no one visiting the page, it automatically ran the test. If its possible, how could I go about making a button to do this?

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• MySQL Insert Data Question

  - by Nano HE

  Hi, assume I already created a table in MySQL as below CREATE TABLE IF NOT EXISTS `sales` ( `id` smallint(5) unsigned NOT NULL auto_increment, `client_id` smallint(5) unsigned NOT NULL, `order_time` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, `sub_total` decimal(8,2) NOT NULL, `shipping_cost` decimal(8,2) NOT NULL, `total_cost` decimal(8,2) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=9 ; -- -- Dumping data for table `sales` -- If I added a new field must_fill for the current table. `must_fill` tinyint(1) unsigned NOT NULL, User can insert less than the number of fiels items to the table defaultly, just as the script of below. INSERT INTO `sales` (`id`, `client_id`, `order_time`, `sub_total`, `shipping_cost`, `total_cost`) VALUES (8, 12312, '2007-12-19 01:30:45', 10.75, 3.00, 13.75); It's fine. But How can I configure the field (must_fill) to a MUST INCLUDE Data field when user plan to insert into new data. BTW, The code will be integrated in PHP script.

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• MySQL: Get only count of result set.

  - by Varun

  I am using MVC with PHP/MySQL. Suppose I am using 10 functions with different queries for fetching details from the database. But at other times I may want to get only the count of the result that will be returned by the query. What is the standard way to handle such situation. Should I write 10 more functions which duplicate almost whole query and return only the count. Or Should I always return the count also with the result set Or I can pass a flag to indicate that the function should return count only, and then based on the flag I will dynamically generate the (select part of) query. Or Is there a better way?

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• Table Design in mysql

  - by RIDDHI

  Hi everyone, I need to create one table, Description : i need to create table based on schedule like daily, weekly & monthly, columns are like : sno, startdate, enddate, day, scheduletype For example i ll take weekly data, for my point of view : From sunday to saturday (1 - 7 )Id i create.... So lots of posibilities are creates like (1,2)(1,3) ..(1,2,3)....up to n....this twise posibility only but that will created up to 7 posibility in one. so how can i store this posibility in mysql database? If any one have an issue get back to me... Thanks in advanced!!!! Riddhi

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• Mysql Date formats and url query

  - by jasmine

  I want to make a url query with date. I have confused a little : There is a mysql table: calDate : varchar The query : $sql="select * from calTbl"; $result = mysql_query($sql); while ($row = mysql_fetch_array($result)) { $n = str_replace("/", "",$row['calDate']); echo '<a href="index.php?p='.$n.'">'.$n.'</a>'; } I want to see related event from query. Can I set apart month, day and year from this? Or what is the correct table design here? Thanks in advance

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• Mysql two table query

  - by Sergio

  I'm using two tables. First (friendlist), which contains users who are on the list of friends and the other table (members) that contains the basic data of the users. Friendlist looks like: id | myid | date | user ----------------------------------------- 001 | 50624 | 2010-01-01 | 32009 002 | 41009 | 2010-05-05 | 50624 003 | 50624 | 2010-03-02 | 23007 The column "myid" contains members who added other users (those from column "user") to their frindlist. I want to get the list of all users that I have added to list and those who add me to their friendlist. In this example, if my id is 50624, the list would look like: | allfriends | --------------- 32009 41009 23007 Then I need to check all users from "allfriend" list with data from the table "members". I want to get only the users with status 1. The members table looks like: id | status | photo -------------------------------- 32009 | 0 | 1.jpg 41009 | 1 | 2.jpg 23007 | 1 | 3.jpg How this mysql query should look like? Thanks for any help.

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