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  • Playing craps, asking and printing

    - by Angelo Mejia
    How do I ask the amount of games of craps someone wants to play and print the number of wins as a result of n number of games? Also How do I make a table in the main method using the previous methods I have? A table like this but shows the results: Percent Wins Games Experiment Number 1 2 3 4 5 6 7 8 9 10 100 1000 10000 100000 1000000 public class CrapsAnalysis { public static int rollDie( int n) { return (int)(Math.random()*n) + 1 ; } public static int rollDice( ) { int die1 ; int die2 ; die1 = rollDie(6) ; die2 = rollDie(6) ; return die1 + die2 ; } public static boolean playOneGame( ) { int newDice ; //repeated dice rolls int roll ; //first roll of the dice int playerPoint = 0 ; //player point if no win or loss on first roll newDice = rollDice() ; roll = rollDice() ; if (roll == 7 || roll == 11) return true; else if (roll == 2 || roll == 3 || roll == 12) return false; else { playerPoint = roll; newDice = rollDice(); do { newDice = rollDice(); } while (newDice != playerPoint || newDice != 7) ; if (newDice == 7) return false; else return true; } } public static int playGames ( int n ) { int numWon = 0; for (int i = 1; i <= n; i++) if(playOneGame()) numWon++; return numWon; } public static void main(String[] args) { //Don't know how to ask and print out the results of the number of wins depending on the n number of games played } }

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  • Recursive Iterators

    - by soandos
    I am having some trouble making an iterator that can traverse the following type of data structure. I have a class called Expression, which has one data member, a List<object>. This list can have any number of children, and some of those children might be other Expression objects. I want to traverse this structure, and print out every non-list object (but I do want to print out the elements of the list of course), but before entering a list, I want to return "begin nest" and after I just exited a list, I want to return "end nest". I was able to do this if I ignored the class wherever possible, and just had List<object> objects with List<object> items if I wanted a subExpression, but I would rather do away with this, and instead have an Expressions as the sublists (it would make it easier to do operations on the object. I am aware that I could use extension methods on the List<object> but it would not be appropriate (who wants an Evaluate method on their list that takes no arguments?). The code that I used to generate the origonal iterator (that works) is: public IEnumerator GetEnumerator(){ return theIterator(expr).GetEnumerator(); } private IEnumerable theIterator(object root) { if ((root is List<object>)){ yield return " begin nest "; foreach (var item in (List<object>)root){ foreach (var item2 in theIterator(item)){ yield return item2; } } yield return " end nest "; } else yield return root; } A type swap of List<object> for expression did not work, and lead to a stackOverflow error. How should the iterator be implemented? Update: Here is the swapped code: public IEnumerator GetEnumerator() { return this.GetEnumerator(); } private IEnumerable theIterator(object root) { if ((root is Expression)) { yield return " begin nest "; foreach (var item in (Expression)root) { foreach (var item2 in theIterator(item)) yield return item2; } yield return " end nest "; } else yield return root; }

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  • can bind successfully to the ldap server, but needs to know how to find user w/i AD

    - by Brad
    I create a login form to bind to the ldap server, if successful, it creates a session (which the user's username is stored within), then I go to another page that has session_start(); and it works fine. What I want to do now, is add code to test if that user is a member of a specific group. So in theory, this is what I want to do if(username session is valid) { search ldap for user -> get list of groups user is member of foreach(group they are member of) { switch(group) { case STAFF: print 'they are member of staff group'; $access = true; break; default: print 'not a member of STAFF group'; $access = false; break; } if(group == STAFF) { break; } } if($access == TRUE) { // you have access to the content on this page } else { // you do not have access to this page } } How do I do a ldap_search w/o binding? I don't want to keep asking for their password on each page, and I can't pass their password thru a session. Any help is appreciated.

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  • Cannot Find Symbol Method?

    - by Aaron
    In my driver program, This line gives me cannot find symbol error and I don't know why, the method is clearly defined in the SavingsAccount class, and I can refer to all other methods in my driver program but just not that one, I tried changing the type to double, and etc but still not working. Refer to ** Account acct2 = new SavingsAccount (name); acct2.calculateBalance(); SavingsAccount Class Inherited from Account Class: public class SavingsAccount extends Account { private final short minBalance = 0; private double overdraftFee; private double yearlyInterestRate = 0.02; private double interestAmount; public SavingsAccount (String name) { super(name); } public double withdraw (double amount) { if (accountBalance - amount >= minBalance) { accountBalance -= amount; System.out.print ("Withdraw Successful"); } else { accountBalance -= amount; overdraftFee = accountBalance * (0.10); accountBalance += overdraftFee; System.out.print ("Withdraw Succesful, however overdraft fee of 10% has been applied to your account"); } return accountBalance; } **public void calculateBalance () { interestAmount = (accountBalance * yearlyInterestRate); accountBalance += interestAmount; }** public String toString() { return super.toString() + " Interest Received: " + interestAmount; } } Account class, if needed import java.util.Random; import java.text.NumberFormat; public abstract class Account { protected double accountBalance; protected long accountNumber; protected String accountHolder; public Account (String name) { accountHolder = name; accountBalance = 0; Random accountNo = new Random(); accountNumber = accountNo.nextInt(100000); } public double deposit (double amount) { accountBalance += amount; return accountBalance; } public String toString() { NumberFormat accountBal = NumberFormat.getCurrencyInstance(); return "Account Balance: " + accountBal.format(accountBalance) + "\nAccount Number: " + accountNumber; } public String getAccountHolder() { return accountHolder; } public double getAccountBalance() { return accountBalance; } public abstract double withdraw (double amount); }

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  • can I put my sqlite connection and cursor in a function?

    - by steini
    I was thinking I'd try to make my sqlite db connection a function instead of copy/pasting the ~6 lines needed to connect and execute a query all over the place. I'd like to make it versatile so I can use the same function for create/select/insert/etc... Below is what I have tried. The 'INSERT' and 'CREATE TABLE' queries are working, but if I do a 'SELECT' query, how can I work with the values it fetches outside of the function? Usually I'd like to print the values it fetches and also do other things with them. When I do it like below I get an error Traceback (most recent call last): File "C:\Users\steini\Desktop\py\database\test3.py", line 15, in <module> for row in connection('testdb45.db', "select * from users"): ProgrammingError: Cannot operate on a closed database. So I guess the connection needs to be open so I can get the values from the cursor, but I need to close it so the file isn't always locked. Here's my testing code: import sqlite3 def connection (db, arg): conn = sqlite3.connect(db) conn.execute('pragma foreign_keys = on') cur = conn.cursor() cur.execute(arg) conn.commit() conn.close() return cur connection('testdb.db', "create table users ('user', 'email')") connection('testdb.db', "insert into users ('user', 'email') values ('joey', 'foo@bar')") for row in connection('testdb45.db', "select * from users"): print row How can I make this work?

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  • Why is it that an int in C++ that isnt initialized (then used) doesn't return an error?

    - by omizzle
    I am new to C++ (just starting). I come from a Java background and I was trying out the following piece of code that would sum the numbers between 1 and 10 (inclusive) and then print out the sum: /* * File: main.cpp * Author: omarestrella * * Created on June 7, 2010, 8:02 PM */ #include <cstdlib> #include <iostream> using namespace std; int main() { int sum; for(int x = 1; x <= 10; x++) { sum += x; } cout << "The sum is: " << sum << endl; return 0; } When I ran it it kept printing 32822 for the sum. I knew the answer was supposed to be 55 and realized that its print the max value for a short (32767) plus 55. Changing int sum; to int sum = 0; would work (as it should, since the variable needs to be initialized!). Why does this behavior happen, though? Why doesnt the compiler warn you about something like this? I know Java screams at you when something isnt initialized. Thank you.

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  • Perl: How do I capture Chinese input via SCIM with STDIN?

    - by KCArpe
    Hi, I use SCIM on Linux for Chinese and Japanese language input. Unfortunately, when I try to capture input using Perl's STDIN, the input is crazy. As roman characters are typed, SCIM tries to guess the correct final characters. ^H (backspace) codes are used to delete previously suggested chars on the command line. (As you type, SCIM tries to guess final Asian chars and displays them.) However, these backspace chars are shown literally as ^H and not interpreted correctly. Example one-liner: perl -e 'print "Chinese: "; my $s = <STDIN>; print $s' When I enable SCIM Chinese or Japanese language input, as I type, e.g., nihao = ??, here is the result: ?^H?^H?^H?^H?^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H?? At the very end of this string, you can see "??" (nihao/hello). At a normal bash prompt, if I type nihao (with Chinese enabled), the results is perfect. This has something to do with interpretation of backspace chars (or control chars) during Perl's STDIN. The same thing happens when using command 'read' in Bash. Witness: read -p 'Chinese: ' s && echo $s Cheers, Kevin

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  • How to Implement Backbone Java Logic Code into Android

    - by lord_sneed
    I wrote a program to work from the console in Eclipse and the terminal window in Linux. I am now transforming it into an Android app and I have the basic functionality of the Android UI done up until the point where it needs to use the logic from the Java file of the program I wrote. All of my inputs from the Java file are currently from the keyboard (from Scanners). My question is: how do I transform this to get it work with the user interaction of the app? The only input would be from the built in NumberPicker. Should I copy and paste the code from the Java program to the activity file in the onCreate method and change all of the input methods (Scanners) to work with the Android input? Or do I create variables in the activity file and pass them to the Java program (in the separate class)? (If so, how would I do that? the Java file starts from the main method: public static void main(String[] args) {) Also, will the print statements I have, System.out.println(...);, translate directly into the Android UI and print on the screen or do I have to modify those?

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  • MPI Odd/Even Compare-Split Deadlock

    - by erebel55
    I'm trying to write an MPI version of a program that runs an odd/even compare-split operation on n randomly generated elements. Process 0 should generated the elements and send nlocal of them to the other processes, (keeping the first nlocal for itself). From here, process 0 should print out it's results after running the CompareSplit algorithm. Then, receive the results from the other processes run of the algorithm. Finally, print out the results that it has just received. I have a large chunk of this already done, but I'm getting a deadlock that I can't seem to fix. I would greatly appreciate any hints that people could give me. Here is my code http://pastie.org/3742474 Right now I'm pretty sure that the deadlock is coming from the Send/Recv at lines 134 and 151. I've tried changing the Send to use "tag" instead of myrank for the tag parameter..but when I did that I just keep getting a "MPI_ERR_TAG: invalid tag" for some reason. Obviously I would also run the algorithm within the processors 0 but I took that part out for now, until I figure out what is going wrong. Any help is appreciated.

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  • Drupal: How to Render Results of Form on Same Page as Form

    - by Aaron
    How would I print the results of a form submission on the same page as the form itself? Relevant hook_menu: $items['admin/content/ncbi_subsites/paths'] = array( 'title' => 'Paths', 'description' => 'Paths for a particular subsite', 'page callback' => 'ncbi_subsites_show_path_page', 'access arguments' => array( 'administer site configuration' ), 'type' => MENU_LOCAL_TASK, ); page callback: function ncbi_subsites_show_path_page() { $f = drupal_get_form('_ncbi_subsites_show_paths_form'); return $f; } Form building function: function _ncbi_subsites_show_paths_form() { // bunch of code here $form['subsite'] = array( '#title' => t('Subsites'), '#type' => 'select', '#description' => 'Choose a subsite to get its paths', '#default_value' => 'Choose a subsite', '#options'=> $tmp, ); $form['showthem'] = array( '#type' => 'submit', '#value' => 'Show paths', '#submit' => array( 'ncbi_subsites_show_paths_submit'), ); return $form; } Submit function (skipped validate function for brevity) function ncbi_subsites_show_paths_submit( &$form, &$form_state ) { //dpm ( $form_state ); $subsite_name = $form_state['values']['subsite']; $subsite = new Subsite( $subsite_name ); //y own class that I use internally in this module $paths = $subsite->normalized_paths; // build list $list = theme_item_list( $paths ); } If I print that $list variable, it is exactly what I want, but I am not sure how to get it into the page with the original form page built from 'ncbi_subsites_show_path_page'. Any help is much appreciated!

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  • Show only div of the product hovering in category grid with jQuery

    - by Dane
    On Magento, I'm trying to get avalable attributes per product in a new div (show/ hide onmouseover) as soon as I hover a product. Unfortunately, my jQuery code opens every div with the same name. I think, I need to do it with jQuery(this) but I tried it in a 1000 different ways, and it won't work. Maybe, somebody here can help me with a better code. jQuery(function() { jQuery('.slideDiv').hide().data('over', false); jQuery('#hover').hover(function() { jQuery('.slideDiv').fadeIn(); }, function() { // Check if mouse did not go over .dialog before hiding it again var timeOut = setTimeout(function() { if (!jQuery('.slideDiv').data('over')) { jQuery('.slideDiv').fadeOut(); clearTimeout(timeOut); } }, 100); }); // Set data for filtering on mouse events for #hover-here jQuery('.slideDiv').hover(function() { jQuery(this).data('over', true); }, function() { jQuery(this).fadeOut().data('over', false); }); }); The PHP just prints the attributes needed. <a href="#" id="hover">Custom Attributes</a> <div class="slideDiv"> <?php $attrs = $_product->getTypeInstance(true)->getConfigurableAttributesAsArray($_product); foreach($attrs as $attr) { if(0 == strcmp("shoe_size", $attr['attribute_code'])) { $options = $attr['values']; print "Größen:<br />"; foreach($options as $option) { print "{$option['store_label']}<br />"; } } } ?> </div> I added the script to [new link] http://jsfiddle.net/xsxfr/47/ so you can see there, that it is not working like this right now :(.

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  • How to detect the root recursive call?

    - by ahmadabdolkader
    Say we're writing a simple recursive function fib(n) that calculates the nth Fibonacci number. Now, we want the function to print that nth number. As the same function is being called repeatedly, there has to be a condition that allows only the root call to print. The question is: how to write this condition without passing any additional arguments, or using global/static variables. So, we're dealing with something like this: int fib(int n) { if(n <= 0) return 0; int fn = 1; if(n > 2) fn = fib(n-2) + fib(n-1); if(???) cout << fn << endl; return fn; } int main() { fib(5); return 0; } I thought that the root call differs from all children by returning to a different caller, namely the main method in this example. I wanted to know whether it is possible to use this property to write the condition and how. Update: please note that this is a contrived example that only serves to present the idea. This should be clear from the tags. I'm not looking for standard solutions. Thanks.

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  • Writing a printList method for a Scheme interpreter in C

    - by Rehan Rasool
    I am new to C and working on making an interpreter for Scheme. I am trying to get a suitable printList method to traverse through the structure. The program takes in an input like: (a (b c)) and internally represent it as: [""][ ][ ]--> [""][ ][/] | | ["A"][/][/] [""][ ][ ]--> [""][ ][/] | | ["B"][/][/] ["C"][/][/] Right now, I just want the program to take in the input, make the appropriate cell structure internally and print out the cell structure, thereby getting (a (b c)) at the end. Here is my struct: typedef struct conscell *List; struct conscell { char symbol; struct conscell *first; struct conscell *rest; }; void printList(char token[20]){ List current = S_Expression(token, 0); printf("("); printf("First Value? %c \n", current->first->symbol); printf("Second value? %c \n", current->rest->first->first->symbol); printf("Third value? %c \n", current->rest->first->rest->first->symbol); printf(")"); } In the main method, I get the first token and call: printList(token); I tested the values again for the sublists and I think it is working. However, I will need a method to traverse through the whole structure. Please look at my printList code again. The print calls are what I have to type, to manually get the (a (b c)) list values. So I get this output: First value? a First value? b First value? c It is what I want, but I want a method to do it using a loop, no matter how complex the structure is, also adding brackets where appropriate, so in the end, I should get: (a (b c)) which is the same as the input. Can anyone please help me with this?

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  • how to install a file handle in perl class

    - by Haiyuan Zhang
    please looku up the following code first. #! /usr/bin/perl package foo; sub new { my $pkg = shift; my $self = {}; my $self->{_fd} = undef; bless $self, $pkg; return $self; } sub Setfd { my $self = shift; my $fd = shift; $self_->{_fd} = $fd; } sub write { my $self = shift; print $self->{_fd} "hello word"; } my $foo = new foo; My intention is to store a file handle within a class using hash. the file handle is undefined at first, but can be initilized afterwards by calling Setfd function. then write can be called to actually write string "hello word" to a file indicated by the file handle, supposed that the file handle is the result of a success "write" open. but, perl compiler just complains that there are syntax error in the "print" line. can anyone of you tells me what's wrong here? thanks in advance.

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  • Python - Problems using mechanize to log into a difficult website

    - by user1781599
    × 139886 I am trying to log in to betfair.com by using mechanize. I have tried several ways but it always fail. This is the code I have developed so far, can anyone help me to identify what is wrong with it and how I can improve it to log into my betfair account? Thanks, import cookielib import urllib import urllib2 from BeautifulSoup import BeautifulSoup import mechanize from mechanize import Browser import re bf_username_name = "username" bf_password_name = "password" bf_form_name = "loginForm" bf_username = "xxxxx" bf_password = "yyyyy" urlLogIn = "http://www.betfair.com/" accountUrl = "https://myaccount.betfair.com/account/home?rlhm=0&" # This url I will use to verify if log in has been successful br = mechanize.Browser(factory=mechanize.RobustFactory()) br.addheaders = [("User-Agent","Mozilla/5.0 (Macintosh; Intel Mac OS X 10_5_8) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.90 Safari/537.1")] br.open(urlLogIn) br.select_form(nr=0) print br.form br.form[bf_username_name] = bf_username br.form[bf_password_name] = bf_password print br.form #just to check username and psw have been recorded correctly responseSubmit = br.submit() response = br.open(accountUrl) text_file = open("LogInResponse.html", "w") text_file.write(responseSubmit.read()) #this file should show the home page with me logged in, but it show home page as if I was not logged it text_file.close() text_file = open("Account.html", "w") text_file.write(response.read()) #this file should show my account page, but it should a pop up with an error text_file.close()

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  • Python 2.6 does not like appending to existing archives in zip files

    - by user313661
    Hello, In some Python unit tests of a program I'm working on we use in-memory zipfiles for end to end tests. In SetUp() we create a simple zip file, but in some tests we want to overwrite some archives. For this we do "zip.writestr(archive_name, zip.read(archive_name) + new_content)". Something like import zipfile from StringIO import StringIO def Foo(): zfile = StringIO() zip = zipfile.ZipFile(zfile, 'a') zip.writestr( "foo", "foo content") zip.writestr( "bar", "bar content") zip.writestr( "foo", zip.read("foo") + "some more foo content") print zip.read("bar") Foo() The problem is that this works fine in Python 2.4 and 2.5, but not 2.6. In Python 2.6 this fails on the print line with "BadZipfile: File name in directory "bar" and header "foo" differ." It seems that it is reading the correct file bar, but that it thinks it should be reading foo instead. I'm at a loss. What am I doing wrong? Is this not supported? I tried searching the web but could find no mention of similar problems. I read the zipfile documentation, but could not find anything (that I thought was) relevant, especially since I'm calling read() with the filename string. Any ideas? Thank you in advance!

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  • How do I capture Chinese input via SCIM with STDIN in Perl?

    - by KCArpe
    I use SCIM on Linux for Chinese and Japanese language input. Unfortunately, when I try to capture input using Perl's STDIN, the input is crazy. As roman characters are typed, SCIM tries to guess the correct final characters. ^H (backspace) codes are used to delete previously suggested chars on the command line. (As you type, SCIM tries to guess final Asian chars and displays them.) However, these backspace chars are shown literally as ^H and not interpreted correctly. Example one-liner: perl -e 'print "Chinese: "; my $s = <STDIN>; print $s' When I enable SCIM Chinese or Japanese language input, as I type, e.g., nihao = ??, here is the result: ?^H?^H?^H?^H?^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H?? At the very end of this string, you can see "??" (nihao/hello). At a normal bash prompt, if I type nihao (with Chinese enabled), the results is perfect. This has something to do with interpretation of backspace chars (or control chars) during Perl's STDIN. The same thing happens when using command 'read' in Bash. Witness: read -p 'Chinese: ' s && echo $s

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  • [MSBuild] Problem with setting properties 's values.

    - by Nam Gi VU
    Let's consider the below example. There, I have: target MAIN call target t then call target tt. target t call target ttt, target tt call target tttt. target t define property aa, target ttt modify aa. target tttt try to print property aa 's value. in short we have: MAIN - {t - {ttt-modify aa, define aa}, tt - tttt - print aa} But in target tttt, we can't "see" aa's updated value (by ttt)! Please help me to make that value visible to target tttt. Thank you! The whole script is as below: <Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" DefaultTargets="MAIN" > <Target Name="MAIN" > <CallTarget Targets="t" /> <CallTarget Targets="tt" /> </Target> <Target Name="t"> <Message Text="t" /> <PropertyGroup> <aa>1</aa> </PropertyGroup> <CallTarget Targets="ttt" /> </Target> <Target Name="tt"> <Message Text="tt" /> <CallTarget Targets="tttt" /> </Target> <Target Name="ttt"> <PropertyGroup> <aa>122</aa> </PropertyGroup> <Message Text="ttt" /> </Target> <Target Name="tttt"> <Message Text="tttt" /> <Message Text="tttt:$(aa)" /> </Target> </Project>

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  • How to access the element of a list/vector that passed by reference in C++

    - by bsoundra
    Hi all, The problem is passing lists/vectors by reference int main(){ list<int> arr; //Adding few ints here to arr func1(&arr); return 0; } void func1(list<int> * arr){ // How Can I print the values here ? //I tried all the below , but it is erroring out. cout<<arr[0]; // error cout<<*arr[0];// error cout<<(*arr)[0];//error //How do I modify the value at the index 0 ? func2(arr);// Since it is already a pointer, I am passing just the address } void func2(list<int> *arr){ //How do I print and modify the values here ? I believe it should be the same as above but // just in case. } Is the vectors any different from the lists ? Thanks in advance. Any links where these things are explained elaborately will be of great help. Thanks again.

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  • How can I store and access a filehandle in a Perl class?

    - by Haiyuan Zhang
    please look at the following code first. #! /usr/bin/perl package foo; sub new { my $pkg = shift; my $self = {}; my $self->{_fd} = undef; bless $self, $pkg; return $self; } sub Setfd { my $self = shift; my $fd = shift; $self_->{_fd} = $fd; } sub write { my $self = shift; print $self->{_fd} "hello word"; } my $foo = new foo; My intention is to store a file handle within a class using hash. the file handle is undefined at first, but can be initilized afterwards by calling Setfd function. then write can be called to actually write string "hello word" to a file indicated by the file handle, supposed that the file handle is the result of a success "write" open. but, perl compiler just complains that there are syntax error in the "print" line. can anyone of you tells me what's wrong here? thanks in advance.

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  • Return the exact ID using fetch_assoc

    - by Selom
    Hi, I have a small problem in my code and I need your help. Well Im using fetch_assoc to get data from database and I need to get the ID number of each of returned values. the issue is that my code only return the ID number of the last data. Here's my code: <form method="post" action="action.php"> <select name="album" style="border:1px solid #CCC; font-size:11px; padding:1px"> <?php $sql = "SELECT * FROM table"; $stmt = $dbh -> prepare($sql); $stmt -> execute(); while($row = $stmt -> fetch(PDO::FETCH_ASSOC)) { $album_ID = $row['album_ID']; $value = $row['album_name']; print "<option value ='". $value ."'>". $value. "</option>"; } ?> </select> <input type="hidden" name="album_ID" value="<?php print $album_ID?>"/> </form> I would like the hidden input type holds the selected album id, but it always holds the album id of the last data. Please help.

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  • Insertion sort invariant assertion fails

    - by user1661211
    In the following code at the end of the for loop I use the assert function in order to test that a[i+1] is greater than or equal to a[i] but I get the following error (after the code below). Also in c++ the assert with the following seems to work just fine but in python (the following code) it does not seem to work...anyone know why? import random class Sorting: #Precondition: An array a with values. #Postcondition: Array a[1...n] is sorted. def insertion_sort(self,a): #First loop invariant: Array a[1...i] is sorted. for j in range(1,len(a)): key = a[j] i = j-1 #Second loop invariant: a[i] is the greatest value from a[i...j-1] while i >= 0 and a[i] > key: a[i+1] = a[i] i = i-1 a[i+1] = key assert a[i+1] >= a[i] return a def random_array(self,size): b = [] for i in range(0,size): b.append(random.randint(0,1000)) return b sort = Sorting() print sort.insertion_sort(sort.random_array(10)) The Error: Traceback (most recent call last): File "C:\Users\Albaraa\Desktop\CS253\Programming 1\Insertion_Sort.py", line 27, in <module> print sort.insertion_sort(sort.random_array(10)) File "C:\Users\Albaraa\Desktop\CS253\Programming 1\Insertion_Sort.py", line 16, in insertion_sort assert a[i+1] >= a[i] AssertionError

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  • sed script to remove file name duplicates

    - by dma_k
    Dear community, I hope the below task will be very easy for sed lovers. I am not sed-guru, but I need to express the following task in sed, as sed is more popular on Linux systems. The input text stream is something which is produced by "make depends" and looks like following: pgm2asc.o: pgm2asc.c ../include/config.h amiga.h list.h pgm2asc.h pnm.h \ output.h gocr.h unicode.h ocr1.h ocr0.h otsu.h barcode.h progress.h box.o: box.c gocr.h pnm.h ../include/config.h unicode.h list.h pgm2asc.h \ output.h database.o: database.c gocr.h pnm.h ../include/config.h unicode.h list.h \ pgm2asc.h output.h detect.o: detect.c pgm2asc.h pnm.h ../include/config.h output.h gocr.h \ unicode.h list.h I need to catch only C++ header files (i.e. ending with .h), make the list unique and print as space-separated list prepending src/ as a path-prefix. This is achieved by the following perl script: make libs-depends | perl -e 'while (<>) { while (/ ([\w\.\/]+?\.h)/g) { $a{$1} = 1; } } print join " ", map { "src/$_" } keys %a;' The output is: src/unicode.h src/pnm.h src/progress.h src/amiga.h src/ocr0.h src/ocr1.h src/otsu.h src/barcode.h src/gocr.h src/../include/config.h src/list.h src/pgm2asc.h src/output.h Please, help to express this in sed.

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  • Perl TCP Server handling multiple Client connections

    - by Matt
    I'll preface this by saying I have minimal experience with both Perl and Socket programming, so I appreciate any help I can get. I have a TCP Server which needs to handle multiple Client connections simultaneously and be able to receive data from any one of the Clients at any time and also be able to send data back to the Clients based on information it's received. For example, Client1 and Client2 connect to my Server. Client2 sends "Ready", the server interprets that and sends "Go" to Client1. The following is what I have written so far: my $sock = new IO::Socket::INET { LocalHost => $host, // defined earlier in code LocalPort => $port, // defined earlier in code Proto => 'tcp', Listen => SOMAXCONN, Reuse => 1, }; die "Could not create socket $!\n" unless $sock; while ( my ($new_sock,$c_addr) = $sock->accept() ) { my ($client_port, $c_ip) = sockaddr_in($c_addr); my $client_ipnum = inet_ntoa($c_ip); my $client_host = ""; my @threads; print "got a connection from $client_host", "[$client_ipnum]\n"; my $command; my $data; while ($data = <$new_sock>) { push @threads, async \&Execute, $data; } } sub Execute { my ($command) = @_; // if($command) = "test" { // send "go" to socket1 print "Executing command: $command\n"; system($command); } I know both of my while loops will be blocking and I need a way to implement my accept command as a thread, but I'm not sure the proper way of writing it.

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  • Functions and arrays

    - by Ordo
    Hello! My little program below shall take 5 numbers from the user, store them into an array of integers and use a function to print them out. Sincerly it doesn't work and nothing is printed out. I can't find a mistake, so i would be glad about any advice. Thanks. #include <stdio.h> void printarray(int intarray[], int n) { int i; for(i = 0; i < n; i ++) { printf("%d", intarray[i]); } } int main () { const int n = 5; int temp = 0; int i; int intarray [n]; char check; printf("Please type in your numbers!\n"); for(i = 0; i < n; i ++) { printf(""); scanf("%d", &temp); intarray[i] = temp; } printf("Do you want to print them out? (yes/no): "); scanf("%c", &check); if (check == 'y') printarray(intarray, n); getchar(); getchar(); getchar(); getchar(); return 0; }

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