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• Easily digestible UI tips for developers

  - by David

  What are some key UI design tips that every developer should know? While there are a number of UI resources for developers (for example, Joel Spolsky's User Interface Design for Programmers), I'm interested in more of a bullet list that can be communicated in 1 to 2 pages. I'm interested in more tactical, day-to-day UI tips, as opposed to overarching UI design goals that would be covered in a UI design meeting (presumably attended by at least one person with a good UI sense). A collection of these tips might cover about 80% of the cases that an everyday programmer would come across.

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• Store data in Ruby on Rails without Database

  - by snowmaninthesun

  I have a few data values that I need to store on my rails app and wanted to know if there are any alternatives to creating a database table just to do this simple task. Background: I'm writing some analytics and dashboard tools for my ruby on rails app and i'm hoping to speed up the dashboard by caching results that will never change. Right now I pull all users for the last 30 days, and re arange them so I can see the number of new users per day. It works great but takes quite a long time, in reality I should only need to calculate the most recent day and just store the rest of the array somewhere else. Where is the best way to store this array? Creating a database table seems a bit overkill, and i'm not sure that global variables are the correct answer. Is there a best practice for persisting data like this? If anyone has done anything like this before let me know what you did and how it turned out.

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• How to to dump JS array... (boommarklet?)

  - by Soulhuntre

  A page on a site I use is holding some of my data hostage. Once I have logged into the site and navigated to the right page, the data I need is in the array eeData[] - it is 720 elements long (once every 2 minutes of a given day). Rather than simulate the requests to the underlying stuff json supplier and since its only once a day, I am happy to simply develop a bookmarklet to grab the data - preferably as a XML or CSV file. Any pointers to sample code or hints would help. I found a bookmarklet here that is based on this script that does part of this - but I am not up to speed on any potential JS file IO to see if it is possible to induce a file "download" of the data, or pop it opn in a new window I can copy / paste.

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• Help me validate these points regarding Ruby

  - by Bragaadeesh

  Hi, I have started learning Ruby for the past 2,3 weeks and I have come up with some findings on the language. Can someone please validate these points. Implemented in many other high level languages such as C, Java, .Net etc., Is slow for the obvious reason that it cannot beat any of the already known high level languages. Should never be compared with any other high level language. Not suitable for large applications. Completely open source and is in a budding state. Has a framework called Rails which claims that it would be good for Agile development Community out there is getting better day by day and finding help immediately should not be a problem as time goes by. Has significant changes between releases which many developers wont welcome right away. Running time cannot be comprehensively estimated since the language has several underlying implementation in several languages. Books are always outdated by the time when you finish them. Thanks.

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• What is the worst gotcha in C# or .NET?

  - by MusiGenesis

  This question is similar to this one, but focused on C# and .NET. I was recently working with a DateTime object, and wrote something like this: DateTime dt = DateTime.Now; dt.AddDays(1); return dt; // still today's date! WTF? The intellisense documentation for AddDays says it adds a day to the date, which it doesn't - it actually returns a date with a day added to it, so you have to write it like: DateTime dt = DateTime.Now; dt = dt.AddDays(1); return dt; // tomorrow's date This one has bitten me a number of times before, so I thought it would be useful to catalog the worst C# gotchas.

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• Dates that intersect

  - by MikeAbyss

  Hi everyone, I've been researching this problem for awhile now and I can't seem to come to a solution, hopefully someone here can help. Currently I'm working with Microsoft SQL server management, I've been trying to do the following: Previously, the old query would just return the results that fit between two dates Heres the previous query: SELECT e.Name, o.StartDate, o.EndDate FROM dbo.Name e, dbo.Date o WHERE where e.Name = o.Name and o.StartDate <= '2010-09-28 23:59:59' and o.EndDate >= '2010-9-28 00:00:00' and e.Name like 'A' Example table that is produced after the query runs (The real table has a lot more rows obviously :P) : Name Start End A 2010-09-28 07:00:00 2010-09-28 17:00:00 A 2010-09-28 13:45:00 2010-09-28 18:00:00 A 2010-09-28 08:00:00 2010-09-28 16:00:00 A 2010-09-28 07:00:00 2010-09-28 15:30:00 However we need to change this, so that the query does the following: find the dates that intersect for a day x find the dates that don't intersect for a day x I've found a real useful site regarding this http://bloggingabout.net/blogs/egiardina/archive/2008/01/30/check-intersection-of-two-date-ranges-in-sql.aspx However the date to compare against is inputted, mine on the other hand has to all dates that intersect/don't intersect. Thanks for the help everyone.

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• PHP - displaying 1 random record for each week

  - by mike

  I want to display 1 random record from a database based on the week. I need to determine if it's a new, and if it is a new week, then select the record and display the new record. I'm thinking I can just use a single day of the week to generate the new record, either way will work. I'm really having a hard time conceptualizing how I'll store the record id and not select a new one when someone visits again the same day or refreshes the page. Any ideas? Let me know if I wasn't clear enough.

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• PHP: Auto Updating subscriptions?

  - by Duncan Palmer

  Hey guys I am currently making a website and I am hopefully going to start a premium service for it. What I am currently looking into right now is how to make an "auto updating" shop which removes 1 day from how many days left the user has left on their premium status. so for example if the users purchases 30 days of premium, each day that 30 with negate 1 so.. 30, 29, 28, 27.. etc and then if the days gets to 0 in will remove premium status. The only way I can think of keeping track of this right now is by manually monitoring each persons premium status but that wouldnt be very practical. What would the best way for me to do this? (hopefully "automatically") Thanks.

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• Basics of html5 and canvas

  - by René Nyffenegger

  As I browse through different questions here, I see that there are a number of questions tagged with html5 and canvas, so I guess they sort of belong together. Now, I have absolutely no idea about the canvas (which is obviously (?) rendered in html5), but it seems that It could be useful one day in the future. So, in order to be prepared when that day comes, I'd like to know the basics about these things. I found a html snippet that is supposed to render such a canvas, but when opened in my browser (firefox) nothing is displayed. So, I guess I need a special plugin or another browser. My question: what are the absolute basic things I need to know and have in order to create a hello world thingy. Please bear in mind that I am completely new with this and don't need no fancy advanced stuff.

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• Display continious dates in Pivot Chart

  - by Douglas

  I have a set of data in a pivot table with date times and events. I've made a pivot chart with this data, and grouped the data by day and year, then display a count of events for each day. So, my horizontal axis goes from 19 March 2007 to 11 May 2010, and my vertical axis is numeric, going from zero to 140. For some days, I have zero events. These days don't seem to be shown on the horizontal axis, so 2008 is narrower than 2009. How do I display a count of zero for days with no events? I'd like my horizontal axis to be continuous, so that it does not miss any days, and every month ends up taking up the same amount of horizontal space. (This question is similar to the unanswered question here, but I'd rather not generate a table of all the days in the last x number of years just to get a smooth plot!)

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• Ubuntu Wired network(ethernet does not work)

  - by badnaam

  It was working just fine, until the other day I yanked it out. The wireless works just fine on the same router. If I login to a windows 7 instance on this dual boot laptop then the ehternet works just fine. So it's not a hardware, cable or router issue. The card even gets an ip, but I can't connect to the internet. Here are the details from route, iptables, ifconfig, ping etc. Any ideas? I have been struggling with this for day, none seems to have an answer. http://pastie.org/954816

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• Drupal: create a node with employee working hours

  - by JMarshall

  I have a bit complicated task. 1. I need to create a node with employee working hours (it's gonna be created for all users with role "employee"), which looks like this: Monday: From __ : __ To __ : __ Tuesday: From __ : __ To __ : __ Wednesday: From __ : __ To __ : __ etc. So, I'll have to create probably 14 CCK fields (monday_from, monday_to, tuesday_from...) or more to store the day of the week and workging hours (hours and minutes). 2. I need to add a view with exposed filters, where visitors can filter employees by day of the week and working hours. What kind of field should I use for working hours? How could views filtering described above be achieved? Any suggestions are greatly appreciated. Thank you!

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• Where Can I get good certification as server admin?

  - by meyosef

  Hi, I programmer without job. Where Can I get good security network certification (online ) as server admin, that will help me to get better Job? Thanks

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• Memcached - how to deal with adding/deploying servers

  - by Industrial

  Hi everybody, How do you handle replacing/adding/removing memcached nodes in your production applications? I will have a number of applications that are cloned and customized due to each customers need running on one and same webserver, so i'll guess that there will be a day when some of the nodes will be changed. Here's how memcached is populated by normal: $m = new Memcached(); $servers = array( array('mem1.domain.com', 11211, 33), array('mem2.domain.com', 11211, 67) ); $m->addServers($servers); My initial idea, is to make the $servers array to be populated from the database, also cached, but file-based, done once a day or something, with the option to force an update on next run of the function that holds the $addservers call. However, I am guessing that this might add some additional overhead since disks are quite slow storage... What do you think?

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• Add Expansion Button to Stackpanel

  - by scientist

  I'd like to add Elements to a StackPanel (or Listbox / Listview if it would make that easier) and automatically add a Button (like "...") to indicate that there are more children than there is space for. Consider a calendar that has appointment items in each day. If there are more appointments than as much as can be displayed a button is displayed to go to a detailed view for that day. Can this be done automatically, or how do I calculate the positions of the stackpanel and its items. It's for windows store development in c#. Thanks in advance.

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• Is there a library in Python that can convert user-dates to timestamp?

  - by alex

  If the month is: "12" Day is: "05" Year is: "2010" Can this be converted into a timestamp somehow, in a very simple way?

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• How do you calculate expanding mean on time series using pandas?

  - by mlo

  How would you create a column(s) in the below pandas DataFrame where the new columns are the expanding mean/median of 'val' for each 'Mod_ID_x'. Imagine this as if were time series data and 'ID' 1-2 was on Day 1 and 'ID' 3-4 was on Day 2. I have tried every way I could think of but just can't seem to get it right. left4 = pd.DataFrame({'ID': [1,2,3,4],'val': [10000, 25000, 20000, 40000],'Mod_ID': [15, 35, 15, 42], 'car': ['ford','honda', 'ford', 'lexus']}) right4 = pd.DataFrame({'ID': [3,1,2,4],'color': ['red', 'green', 'blue', 'grey'], 'wheel': ['4wheel','4wheel', '2wheel', '2wheel'], 'Mod_ID': [15, 15, 35, 42]}) df1 = pd.merge(left4, right4, on='ID').drop('Mod_ID_y', axis=1)

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• Please help me with this Ruby code

  - by Bragaadeesh

  Hi, I am new to Ruby and I know that I am not using the simple and powerful methods available within it. I made my code work but it has to be simple not this huge (especially I feel I am very bad at loop variables) i = 0 j = 0 loop_count = ((to_date-from_date)/(60*60*24)).to_i#diff b/w two dates in days loop_count.times do 48.times do event = Icalendar::Event.new status = get_availability_on_date_and_hour(@templates, @availabilities, from_date+j.days, i).downcase if(status != 'unavailable') #Initialize start and end dates in DateTime's civil format bias_date_time = DateTime.civil(from_date.year, from_date.month, from_date.day) event.dtstart = bias_date_time + j.day + (i/2).to_i.hour + (i%2*30).to_i.minutes event.dtend = event.dtstart + 30.minutes event.summary = status.upcase cal.add_event(event) end i += 1 end i = 0 j += 1 end

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• R graphics plotting a linegraph with date/time horizontally along x-axis

  - by user2978586

  I want to get a linegraph in R which has Time along x and temperature along y. Originally I had the data in dd/mm/yyyy hh:mm format, with a time point every 30 minutes. https://www.dropbox.com/s/q35y1rfila0va1h/Data_logger_S65a_Ania.csv Since I couldn't find a way of reading this into R, I formatted the data to make it into dd/mm/yyyy and added a column 'time' with 1-48 for all the time points for each day https://www.dropbox.com/s/65ogxzyvuzteqxv/temp.csv This is what I have so far: temp<-read.csv("temp.csv",as.is=T) temp$date<-as.Date(temp$date, format="%d/%m/%Y") #inputting date in correct format plot(temperature ~ date, temp, type="n") #drawing a blank plot with axes, but without data lines(temp$date, temp$temperature,type="o") #type o is a line overlaid on top of points. This stacks the points up vertically, which is not what I want, and stacks all the time points (1-48) for each day all together on the same date. Any advice would be much appreciated on how to get this horizontal, and ordered by time as well as date.

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• How to change a DateTime Format

  - by Carlo Adap

  List<DateTime> datetimerange = new List<DateTime>(); DateTime StartDate = Convert.ToDateTime(txtDate.Text); DateTime EndDate = Convert.ToDateTime(TextBox1.Text); foreach (DateTime day in EachDay(StartDate, EndDate)) { datetimerange.Add(day.Date); Session["SelectedDatess"] = datetimerange; } When I displays it to a list box the date looks like 8/28/2012 12:00:00 whereas I just want to display 8/28/2012. How can I change the format of the date to MM/dd/yyyy?

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• Go to the next instruction without pressing enter

  - by louie

  hi guyz my problem is trying to go to the next instruction without pressing enter.. this is my code cout<<"Enter Date Of Birth: "; cin>>day; cout<<"/"; cin>>month; cout<<"/"; cin>>year; by only providing 2 digit number for day, i want the next instruction to get printed without me pressing enter, and so goes to the rest month and year. since year is the last, i can press enter after that.

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• C# Replace two specific commas in a string with many commas

  - by Hal

  I am trying to change the date format in each line from commas to hyphens. The index of the comma separating the month and day day and year varies. lines_in_List[i] = lines_in_List[i].Insert(0, cnt + ","); // Insert Draw # in 1st column string one_line = lines_in_List[i]; // 0,5,1,2012,1,10,19,16,6,36,,, // 1,11,5,2012,49,35,23,37,38,28,,, // 2,12,10,2012,8,52,53,54,47,15,,, // ^-^--^ replace the ',' with a '-'. StringBuilder changed = new StringBuilder(one_line); changed[3] = '-'; changed[5] = '-'; changed[3] = '-'; lines_in_List[i] = changed.ToString(); }

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• PHP: How to get the days of the week?

  - by fwaokda

  I'm wanting to store items in my database with a DATE value for a certain day. I don't know how to get the current Monday, or Tuesday, etc. from the current week. Here is my current database setup. menuentry id int(10) PK menu_item_id int(10) FK day_of_week date message varchar(255) So I have a class setup that holds all the info then I was going to do something like this... foreach ( $menuEntryArray as $item ) { if ( $item->getDate() == [DONT KNOW WHAT TO PUT HERE] ) { // code to display menu_item information } } So I'm just unsure what to put in "[DONT KNOW WHAT TO PUT HERE]" to compare to see if the date is specified for this week's Monday, or Tuesday, etc. The foreach above runs for each day of the week - so it'll look like this... Monday Item 1 Item 2 Item 3 Tuesday Item 1 Wednesday Item 1 Item 2 ... Thanks!

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• Change Text on Landscape mode with Java Code and not XML (Android)

  - by Chowza

  I wrote my layout entirely in java code because it was just more convenient. (I had a lot of textViews and using for statements were more convenient). However, my TextViews require the day of the week and in portrait mode, I would like to cut the day of the week to a short form. For example, I want "Sunday" to show "Sun" for portrait mode, but "Sunday" for landscape mode. I understand how to do this in XML files, but how do I do it in code? I.e. sample code: LinearLayout parent = new LinearLayout(getApplicationContext()); parent.setLayoutParams(new LayoutParams(LayoutParams.MATCH_PARENT,LayoutParams.MATCH_PARENT)); TextView example = new TextView; example.setLayoutParams(mparams); example.setText("Sunday"); //<--make this "Sun" when in portrait but "Sunday" in landscape parent.addView(example);

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• "Passing Go" in a (python) date range

  - by anonymous coward

  The Rules: An employee accrues 8 hours of Paid Time Off on the day after each quarter. Quarters, specifically being: Jan 1 - Mar 31 Apr 1 - Jun 30 Jul 1 - Sep 30 Oct 1 - Dec 31 The Problem Employees will use an automated system to request paid time off, possibly occurring in the past, as well as the future. Requests should only be accepted if the employee has (or will have) that time available. For instance, if an employee only has 1 Day of Paid Time Off currently available (currently being January 20th), but is requesting 2 Days of Paid Time Off, beginning September 20th, the system should take into account that the employee would have accrued enough time off by then and allow the request. (Obviously ignoring that the employee may use up existing time before that date). I'm currently using Python, and wondering what the correct approach to something like this would be. I'm assuming that using DateTime objects, and possibly the dateutil module, would help here, but my brain isn't wrapping around this problem for some reason.

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