Search Results

Search found 25418 results on 1017 pages for 'back ache'.

Page 157/1017 | < Previous Page | 153 154 155 156 157 158 159 160 161 162 163 164  | Next Page >

  • Exposing a "dumbed-down", read-only instance of a Model in GAE

    - by Blixt
    Does anyone know a clever way, in Google App Engine, to return a wrapped Model instance that only exposes a few of the original properties, and does not allow saving the instance back to the datastore? I'm not looking for ways of actually enforcing these rules, obviously it'll still be possible to change the instance by digging through its __dict__ etc. I just want a way to avoid accidental exposure/changing of data. My initial thought was to do this (I want to do this for a public version of a User model): class ReadOnlyUser(db.Model): display_name = db.StringProperty() @classmethod def kind(cls): return 'User' def put(self): raise SomeError() Unfortunately, GAE maps the kind to a class early on, so if I do ReadOnlyUser.get_by_id(1) I will actually get a User instance back, not a ReadOnlyUser instance.

    Read the article

  • Convert user title (text) to URL, what instead spaces, #, & and other characters?

    - by Thomas
    I have some form on the website where users can add new pages. I must generate SEO friendly URLs and make this urls unique. What characters can I display in url, I know that spaces I should convert to undescore: " "-"_" and before it - underscores to something else, for example: ""-"()" It is easy make title from url back. But what in my specific title can be all characters from keyboard, even : @#%:"{/\';. Are some contraindications to don't use this characters in URL? Important for me is: -easy generate url and title from url back (without queries to database) -each title are unique, so url must be too -SEO friendly URLs

    Read the article

  • Facebook page linking to external site sign-up process, capture permission to write to wall in process?

    - by steve
    Hi all, Have had a good hunt through the archive but can't find anyone trying to do this... hope someone familiar with the facebook API can confirm if it's possible? Basically I have a client who wants to replicate their membership sign up process in a tab on their facebook page. The form would still submit to their own website to process, we'd just be replicating the form fields. As an additional requirement they want to capture peoples facebook user ID and get permission to post back to a users wall at the same time... The idea being that once the user is a member we can post back to their wall so their friends see that they've signed up... Basically after a sanity check that: 1) these things are possible to do; 2) the best method to build the form in a FB page - I'm guessing using JS to create all fields & ajax to submit to the external site? Thanks Steve

    Read the article

  • Can my tortoise vs. hare race be improved?

    - by FredOverflow
    Here is my code for detecting cycles in a linked list: do { hare = hare.next(); if (hare == back) return; hare = hare.next(); if (hare == back) return; tortoise = tortoise.next(); } while (tortoise != hare); throw new AssertionError("cyclic linkage"); Is there a way to get rid of the code duplication inside the loop? Am I right in assuming that I don't need a check after making the tortoise take a step forward? As I see it, the tortoise can never reach the end of the list before the hare (contrary to the fable). Any other ways to simplify/beautify this code?

    Read the article

  • Creating new context in JSF

    - by Krishna
    HI, We are navigating to for example page A to C. When we are in page C, user clicks the back button of the browser and goes back to the previous application which is used for invoking the page A. Again, when user trying to invoke the page A, he directly navigating to the page C, not page A. Here what I felt the problem was, may the JSF context is taking to the current page. How we can solve this problem. When every user clicks to enter page A, he should be able to see the page A. Anyone has the solution for my problem.

    Read the article

  • Unable to Hide Update Button in GridView Editing

    - by nitinkhanna
    Hi, I am using commandfield edit button to edit the row of the gridview. But unable to perform the basics. This gridview is in update panel. When I press Edit button it shows UPDATE and CANCEL button but when I press UPDATE button it updates the DB but UPDATE button doesn't go back to EDIT one. While Cancel is working as it should. Like on pressing CANCEL it goes back to EDIT button, What I am doing worng. Thanks.

    Read the article

  • Webkit browser jQuery transformations/transitions not working with jSplitSlider

    - by user3689793
    I am helping to build a site and i'm having an issue with the functionality of an add-in called jsplitslider when running it in chrome. Right now, when I navigate between the slides, the div's get stuck on top of each other and never clear the webkit transformations/animations: <div class="sl-content-slice" style="transition: all 800ms ease-in-out; -webkit-transition: all 800ms ease-in-out;"> I think the problem is due to timing of the functions, but I can't seem to figure out where I would need to add a setTimeout(). I only think this because I exhausted a lot of the other options like display: inline-block, notransitions css, etc. I'm desperate to figure out how to make this work in chrome. It works in FF and IE(surprisingly enough). I'm not great at webcoding, so any help will be appreciated! The code on the site isn't minimized. Here is the jQuery where I think the problem lies: var cssStyle = config.orientation === 'horizontal' ? { marginTop : -this.size.height / 2 } : { marginLeft : -this.size.width / 2 }, // default slide's slices style resetStyle = { 'transform' : 'translate(0%,0%) rotate(0deg) scale(1)', opacity : 1 }, // slice1 style slice1Style = config.orientation === 'horizontal' ? { 'transform' : 'translateY(-' + this.options.translateFactor + '%) rotate(' + config.slice1angle + 'deg) scale(' + config.slice1scale + ')' } : { 'transform' : 'translateX(-' + this.options.translateFactor + '%) rotate(' + config.slice1angle + 'deg) scale(' + config.slice1scale + ')' }, // slice2 style slice2Style = config.orientation === 'horizontal' ? { 'transform' : 'translateY(' + this.options.translateFactor + '%) rotate(' + config.slice2angle + 'deg) scale(' + config.slice2scale + ')' } : { 'transform' : 'translateX(' + this.options.translateFactor + '%) rotate(' + config.slice2angle + 'deg) scale(' + config.slice2scale + ')' }; if( this.options.optOpacity ) { slice1Style.opacity = 0; slice2Style.opacity = 0; } // we are adding the classes sl-trans-elems and sl-trans-back-elems to the slide that is either coming "next" // or going "prev" according to the direction. // the idea is to make it more interesting by giving some animations to the respective slide's elements //( dir === 'next' ) ? $nextSlide.addClass( 'sl-trans-elems' ) : $currentSlide.addClass( 'sl-trans-back-elems' ); $currentSlide.removeClass( 'sl-trans-elems' ); var transitionProp = { 'transition' : 'all ' + this.options.speed + 'ms ease-in-out' }; // add the 2 slices and animate them $movingSlide.css( 'z-index', this.slidesCount ) .find( 'div.sl-content-wrapper' ) .wrap( $( '<div class="sl-content-slice" />' ).css( transitionProp ) ) .parent() .cond( dir === 'prev', function() { var slice = this; this.css( slice1Style ); setTimeout( function() { slice.css( resetStyle ); }, 150 ); }, function() { var slice = this; setTimeout( function() { slice.css( slice1Style ); }, 150 ); } ) .clone() .appendTo( $movingSlide ) .cond( dir === 'prev', function() { var slice = this; this.css( slice2Style ); setTimeout( function() { $currentSlide.addClass( 'sl-trans-back-elems' ); if( self.support ) { slice.css( resetStyle ).on( self.transEndEventName, function() { self._onEndNavigate( slice, $currentSlide, dir ); } ); } else { self._onEndNavigate( slice, $currentSlide, dir ); } }, 150 ); }, function() { var slice = this; setTimeout( function() { $nextSlide.addClass( 'sl-trans-elems' ); if( self.support ) { slice.css( slice2Style ).on( self.transEndEventName, function() { self._onEndNavigate( slice, $currentSlide, dir ); } ); } else { self._onEndNavigate( slice, $currentSlide, dir ); } }, 150 ); } ) .find( 'div.sl-content-wrapper' ) .css( cssStyle ); $nextSlide.show(); }, _validateValues : function( config ) { // OK, so we are restricting the angles and scale values here. // This is to avoid the slices wrong sides to be shown. // you can adjust these values as you wish but make sure you also ajust the // paddings of the slides and also the options.translateFactor value and scale data attrs if( config.slice1angle > this.options.maxAngle || config.slice1angle < -this.options.maxAngle ) { config.slice1angle = this.options.maxAngle; } if( config.slice2angle > this.options.maxAngle || config.slice2angle < -this.options.maxAngle ) { config.slice2angle = this.options.maxAngle; } if( config.slice1scale > this.options.maxScale || config.slice1scale <= 0 ) { config.slice1scale = this.options.maxScale; } if( config.slice2scale > this.options.maxScale || config.slice2scale <= 0 ) { config.slice2scale = this.options.maxScale; } if( config.orientation !== 'vertical' && config.orientation !== 'horizontal' ) { config.orientation = 'horizontal' } }, _onEndNavigate : function( $slice, $oldSlide, dir ) { // reset previous slide's style after next slide is shown var $slide = $slice.parent(), removeClasses = 'sl-trans-elems sl-trans-back-elems'; // remove second slide's slice $slice.remove(); // unwrap.. $slide.css( 'z-index', 10 ) .find( 'div.sl-content-wrapper' ) .unwrap(); // hide previous current slide $oldSlide.hide().removeClass( removeClasses ); $slide.removeClass( removeClasses ); // now we can navigate again.. this.isAnimating = false; this.options.onAfterChange( $slide, this.current ); }, Sorry if I missed any conventions when posting, this is my first S.O. post. Thanks in advance for any help.

    Read the article

  • PyGTK: Radiobuttons are still displayed after removal

    - by canavanin
    Hi everyone! I am using PyGTK and the gtk.assistant. On one page I would like to display two radiobuttons in case the user selected a certain option on a previous page. The labels of the buttons - and whether the buttons are to be present at all - are to depend entirely on that earlier selection. Furthermore, if the user goes back and changes that selection, the page containing the radiobuttons is to be updated accordingly. I have got as far as having the radiobuttons displayed when necessary, and with the correct labels. The trouble is that if I go back and change the determining selection, or if I move one page further than the 'radiobutton page' and then move back, the buttons are not only not removed (in case that would have been required), their number has also doubled. To show you what I'm doing, here's part of my code (I've left out bits that do unrelated things, that's why the function name doesn't fit). The function is called when the "prepare" signal is emitted prior to construction of the 'radiobutten page'. def make_class_skills_treestore(self): print self.trained_by_default_hbox.get_children() # PRINT 1 for child in self.trained_by_default_hbox.get_children(): if type(child) == gtk.RadioButton: self.trained_by_default_hbox.remove(child) #child.destroy() # <-- removed the labels, but not the buttons print self.trained_by_default_hbox.get_children() # PRINT 2 class_skills = self.data.data['classes'][selected_class].class_skills.values() default_trained_count = (class_skills.count([True, True]) , class_skills.count([True, False])) num_default_trained_skills = default_trained_count[1] / 2 # you have to pick one of a pair --> don't # count each as trained by default for i in range(default_trained_count[0]): # those are trained by default --> no choice num_default_trained_skills +=1 selected_class = self.get_classes_key_from_class_selection() if default_trained_count[1]: for skill in self.data.data['classes'][selected_class].class_skills.keys(): if self.data.data['classes'][selected_class].class_skills[skill] == [ True, False ] and not self.default_radio: self.default_radio.append(gtk.RadioButton(group=None, label=skill)) elif self.data.data['classes'][selected_class].class_skills[skill] == [ True, False ] and self.default_radio: self.default_radio.append(gtk.RadioButton(group=self.default_radio[0], label=skill)) if self.default_radio: for radio in self.default_radio: self.trained_by_default_hbox.add(radio) self.trained_by_default_hbox.show_all() self.trained_by_default_hbox and self.trained_by_default_label, as well as self.default_radio stem from the above function's class. I have two print statements (PRINT 1 and PRINT 2) in there for debugging. Here's what they give me: PRINT 1: [<gtk.Label object at 0x8fc4c84 (GtkLabel at 0x90a2f20)>, <gtk.RadioButton object at 0x8fc4d4c (GtkRadioButton at 0x90e4018)>, <gtk.RadioButton object at 0x8fc4cac (GtkRadioButton at 0x90ceec0)>] PRINT 2: [<gtk.Label object at 0x8fc4c84 (GtkLabel at 0x90a2f20)>] So the buttons have indeed been removed, yet they still show up on the page. I know the code requires some refactoring, but first I'd like to get it to work at all... If someone could help me out that would be great! Thanks a lot in advance for your replies - any kind of help is highly appreciated.

    Read the article

  • What can cause forms authentication to forget you are logged in?

    - by metanaito
    I have an asp.net web site that uses forms authentication. When users check the "remember me" it will remember the user if they close the browser and come back. I have the timeout set for a day or so. Recently I've noticed that I can be browsing the site and suddenly it forgets I'm logged in. It does not happen after 20 minutes as I can be actively browsing. My question is, what can cause this to happen? If the server recycles the app or app pool will the login be lost? On my local I can restart my machine and when I come back I'm still logged in.

    Read the article

  • Excel Worksheet Index

    - by Ben
    I have the following code that works great but I am trying to modify it so that instead of replacing column 1 of the Index page with a new index I would rather start the range in Cell C11. Right now, the new Index starts in Cell A1 of the Index sheet. Here is the code: Private Sub Worksheet_Activate() Dim wSheet As Worksheet Dim l As Long l = 1 With Me .Columns(1).ClearContents .Cells(1, 1) = "INDEX" .Cells(1, 1).Name = "Index" End With For Each wSheet In Worksheets If wSheet.Name <> Me.Name Then l = l + 1 With wSheet .Range("A1").Name = "Start_" & wSheet.Index .Hyperlinks.Add Anchor:=.Range("A1"), Address:="", _ SubAddress:="Index", TextToDisplay:="Back to Index" End With Me.Hyperlinks.Add Anchor:=Me.Cells(l, 1), Address:="", _ SubAddress:="Start_" & wSheet.Index, TextToDisplay:=wSheet.Name End If Next wSheet End Sub I have successfully modified the code so that the link back to the index on each sheet is in cell A4 without trouble, but I can't figure out how to have the index be replaced starting at Cell C11

    Read the article

  • Is there a method / system / program to keep track of diffirent stages and changes in writing the co

    - by Luay
    forgive me, but I don't know the technical term to know what to search for. I am trying to find a way to keep track of changes in my code during the development of my program. something that would allow me to go back to a section of code that I deleted. I am not talking about "undo". But rather a way that would let me keep track or be able to retrieve a section of my code that I deleted but now want it back. Is there such a way. If there is, then what is this whole system/procedure called? Is there something that integrates with visual studio 2010? Many thanks for your help.

    Read the article

  • Capistrano SSH::AuthenticationFailed, not prompting for password

    - by Sparkmasterflex
    I've been using capistrano successfully for a while now and all of a sudden in every project I've lost the ability to deploy. Environment: os X (Mavericks) ruby 1.9.3p194 rvm (locally, not on server) rails 3.2 and up RubyGems 1.8.25 I'm not using rsa_keys or anything I want capistrano to prompt for user and password. Suddenly it has decided not to ask for a password, but does ask for user. Then it rolls back and gives me the following error. [deploy:update_code] exception while rolling back: Capistrano::ConnectionError, connection failed for: sub.example.com (Net::SSH::AuthenticationFailed: Authentication failed for user [email protected]) connection failed for: sub.example.com (Net::SSH::AuthenticationFailed: Authentication failed for user [email protected]) This has occurred on my personal laptop and my iMac at work. It occurs when deploying to two different servers (both linux) I'm completely at a loss here. Any ideas?

    Read the article

  • Is valgrind crazy or is this is a genuine std map iterator memory leak?

    - by Alberto Toglia
    Well, I'm very new to Valgrind and memory leak profilers in general. And I must say it is a bit scary when you start using them cause you can't stop wondering how many leaks you might have left unsolved before! To the point, as I'm not an experienced in c++ programmer, I would like to check if this is certainly a memory leak or is it that Valgrind is doing a false positive? typedef std::vector<int> Vector; typedef std::vector<Vector> VectorVector; typedef std::map<std::string, Vector*> MapVector; typedef std::pair<std::string, Vector*> PairVector; typedef std::map<std::string, Vector*>::iterator IteratorVector; VectorVector vv; MapVector m1; MapVector m2; vv.push_back(Vector()); m1.insert(PairVector("one", &vv.back())); vv.push_back(Vector()); m2.insert(PairVector("two", &vv.back())); IteratorVector i = m1.find("one"); i->second->push_back(10); m2.insert(PairVector("one", i->second)); m2.clear(); m1.clear(); vv.clear(); Why is that? Shouldn't the clear command call the destructor of every object and every vector? Now after doing some tests I found different solutions to the leak: 1) Deleting the line i-second-push_back(10); 2) adding a delete i-second; after it's been used. 3) Deleting the second vv.push_back(Vector()); and m2.insert(PairVector("two", &vv.back())); statements. Using solution 2) makes Valgring print: 10 allocs, 11 frees Is that OK? As I'm not using new why should I delete? Thanks, for any help!

    Read the article

  • efficiently trimming postgresql tables

    - by agilefall
    I have about 10 tables with over 2 million records and one with 30 million. I would like to efficiently remove older data from each of these tables. My general algorithm is: create a temp table for each large table and populate it with newer data truncate the original tables copy tmp data back to original tables using: "insert into originaltable (select * from tmp_table)" However, the last step of copying the data back is taking longer than I'd like. I thought about deleting the original tables and making the temp tables "permanent", but I lose constraint/foreign key info. If I delete from the tables directly, it takes much longer. Given that I need to preserve all foreign keys and constraints, are there any faster ways of removing the older data? Thanks.

    Read the article

  • Escaping and unescaping a string with single and double quotes in Javascript

    - by Reina
    I have a search box that a user can search for any string including single AND double quotes, once they have searched, the backend is passing the keyword back to me so I can put it back in the box. I don't know what the string is so I can't escape quotes myself, below is an example: var keyword = "hello"; $("#selectionkeywords").val(); The issue I am having is that if the user enters "hello" the keyword becomes ""hello"" and I get this error: missing ) after argument list [Break On This Error] jQuery("#selectionkeywords").val(""hello""); The user could also enter single quotes so that rules it out as well. I tried using escape unescape but I still have the same issue e.g. escape(""hello"") I could get the value in an unescaped format e.g. "hello" but I don't know what to do with it, escape doesn't work on it I end up with this %26%23034%3Bhello%26%23034%3B So I'm pretty much stuck at the moment as I can't do anything to the string, any ideas?

    Read the article

  • RadGrid Ajax PopAlert

    - by user272671
    I have a situation where I need to, based on user selection and some server-side processing, display a message to allow user to choose to continue processing or cancel. I have a RadGrid populated with data from the database. When User adds a new item to the grid,I want to do some processing in the back end and then inform the user of what could result and give him/her the choice to continue and believe that a message box or modal popup/radalert is the best way to do it, but how do I create the message in the back end and then using a popup, display the message and block until user responds. How do I do it please?

    Read the article

  • Potential issue when using memcache session save handler in PHP

    - by Sean
    I have two load balanced web servers, and I'm using the memcache session save handler with the save path pointing to two memcache servers. It's configured with session redundancy set to two (the number of memcache servers). So PHP is writing session data to both memcache servers, and when I take one of the servers down, everything seems to work fine since the session data has been written to both memcache servers. The problem seems to happen when I use the app for a while with only the one memcache server up, and then bring the other one back up. My theory is that the memcache server comes back up, and PHP then starts asking it for session data which isn't there since it was written to the other server while this one was down. Is there any merit to this theory? Should PHP be asking both servers for the session data and maybe there's some other problem?

    Read the article

  • jquery ajax form success callback not being called

    - by Michael Merchant
    I'm trying to upload a file using "AJAX", process data in the file and then return some of that data to the UI so I can dynamically update the screen. I'm using the JQuery Ajax Form Plugin, jquery.form.js found at http://jquery.malsup.com/form/ for the javascript and using Django on the back end. The form is being submitted and the processing on the back end is going through without a problem, but when a response is received from the server, my Firefox browser prompts me to download/open a file of type "application/json". The file has the json content that I've been trying to send to the browser. I don't believe this is an issue with how I'm sending the json as I have a modularized json_wrapper() function that I'm using in multiple places in this same application. Here is what my form looks after Django templates are applied: <form method="POST" enctype="multipart/form-data" action="/test_suites/active/upload_results/805/"> <p> <label for="id_resultfile">Upload File:</label> <input type="file" id="id_resultfile" name="resultfile"> </p> </form> You won't see any submit buttons because I'm calling submit with a button else where and am using ajaxSubmit() from the jquery.form.js plugin. Here is the controlling javascript code: function upload_results($dialog_box){ $form = $dialog_box.find("form"); var options = { type: "POST", success: function(data){ alert("Hello!!"); }, dataType: "json", error: function(){ console.log("errors"); }, beforeSubmit: function(formData, jqForm, options){ console.log(formData, jqForm, options); }, } $form.submit(function(){ $(this).ajaxSubmit(options); return false; }); $form.ajaxSubmit(options); } As you can see, I've gotten desperate to see the success callback function work and simply have an alert message created on success. However, we never reach that call. Also, the error function is not called and the beforeSubmit function is executed. The file that I get back has the following contents: {"count": 18, "failed": 0, "completed": 18, "success": true, "trasaction_id": "SQEID0.231"} I use 'success' here to denote whether or not the server was able to run the post command adequately. If it failed the result would look something like: {"success": false, "message":"<error_message>"} Your time and help is greatly appreciated. I've spent a few days on this now and would love to move on.

    Read the article

  • A web application that uses someone else's mail server?

    - by John
    I'm building a web application, call it http://mywebapp.com, where a user should be able to create a newsletter and email it to everyone in his user account's contact list. So he can check mark all his friends, select an html template, fill in the body content, and send. The only catch to this is that after the user sends the email, the recipient must NOT be allowed to trace the source of the email back to http://mywebapp.com. The reason for this condition is because the user is a "reseller" of my business who wants to appear as if he's an independent business. If liability issues arise due to the reseller's unduly usage, I do not want to be caught up in the legal issues. Hence, I do not want anything about my business or technology to be traceable back to me by newsletter recipients. What's the best way to achieve this?

    Read the article

  • non-blocking socket client connection

    - by Igor
    ALL, I am looking for a simple example of non-blocking socket connection that will run on Windows. I tried to Google, but all samples are either for *nix (POSIX) or blocking sockets on Windows. Looking thru msdn I see that it is easy to make a socket non-blocking and issue a connect(), but then you need some preparation in order to put the socket back. So, all in all I need something on a non-blocking socket that will connect and then put it back to be blocking. The read and write operation should be performed on the blocking socket. The reason for a non-blocking socket is that I need a connection timeout and there is no other way than non-blocking socket. Or is there? Thank you.

    Read the article

  • git push on a remote branch

    - by charlielee
    I have a remote project that have a branch. So I first clone the repo. Then issue the following to the clone to work on a branch: git checkout -b <name> <remote_branch_name> Then I made the changed needed on this branch and want to commit by doing this: git commit -a -m "changed made" However when i want to push back to the remote branch it just say 'Everything is up to date' git push Everything up-to-date I check by clone the remote repo again in a different directory it haven't push the changes over.... So how do i push my changes back to the remote branch Thanks

    Read the article

  • Navigation problem with view controllers.

    - by abdulsamad
    Hi All I have some problem with the my view controllers. When i have about 50 or more records in one of my table view which is below in the stack of view controllers and if i tap the back button quickly the navigation bar on the tap changes but the view does't change. For example: if i have the search controller below in the stack and detail controller up in the stack in this case on tapping the back button quickly the navigation bar comes to the search but the view controller remains on detail page. can any one can give me cause or solution of this problem. your help will be highly appreciated.

    Read the article

< Previous Page | 153 154 155 156 157 158 159 160 161 162 163 164  | Next Page >