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  • This .NET code snippet will NOT actually create a cookie, right?

    - by Ryan
    I just realized that this cookie is not showing up like it should, and I checked the code which was not written by me but I am pretty sure that this is NOT enough to create a cookie right?? public static void CreateSSOCookies(string tokenID) { System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Domain = System.Web.HttpContext.Current.Request.ServerVariables["SERVER_NAME"].ToString().ToLower(); System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Value = tokenID.ToString(); System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Path = "~/"; System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Expires = DateTime.Now.AddDays(7); } If it does work, where is the cookie then? Is the cookie name 'ssocookies' ?

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  • programs hangs during socket interaction

    - by herrturtur
    I have two programs, sendfile.py and recvfile.py that are supposed to interact to send a file across the network. They communicate over TCP sockets. The communication is supposed to go something like this: sender =====filename=====> receiver sender <===== 'ok' ======= receiver or sender <===== 'no' ======= receiver if ok: sender ====== file ======> receiver I've got The sender and receiver code is here: Sender: import sys from jmm_sockets import * if len(sys.argv) != 4: print "Usage:", sys.argv[0], "<host> <port> <filename>" sys.exit(1) s = getClientSocket(sys.argv[1], int(sys.argv[2])) try: f = open(sys.argv[3]) except IOError, msg: print "couldn't open file" sys.exit(1) # send filename s.send(sys.argv[3]) # receive 'ok' buffer = None response = str() while 1: buffer = s.recv(1) if buffer == '': break else: response = response + buffer if response == 'ok': print 'receiver acknowledged receipt of filename' # send file s.send(f.read()) elif response == 'no': print "receiver doesn't want the file" # cleanup f.close() s.close() Receiver: from jmm_sockets import * s = getServerSocket(None, 16001) conn, addr = s.accept() buffer = None filename = str() # receive filename while 1: buffer = conn.recv(1) if buffer == '': break else: filename = filename + buffer print "sender wants to send", filename, "is that ok?" user_choice = raw_input("ok/no: ") if user_choice == 'ok': # send ok conn.send('ok') #receive file data = str() while 1: buffer = conn.recv(1) if buffer=='': break else: data = data + buffer print data else: conn.send('no') conn.close() I'm sure I'm missing something here in the sorts of a deadlock, but don't know what it is.

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  • Send and receive data in same ajax request with jquery

    - by Pedro Esperança
    What is the best way to send data and receive a response dependent on that data? Consider the php file used for the request: $test = $_POST['test']; echo json_encode($test); I have tried unsucessfully to achieve this with: $.ajax({ type: "POST", dataType: "json", data: '{test : worked}', url: 'ajax/getDude.php', success: function(response) { alert(response); } });

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  • xmlhttprequest responsetext coming for Accept header: text/xml , but server error for application/JS

    - by encryptor
    I have to get response text from a resourceindex page as JSON object. When I dont put a Accept header in the request, it shows me the xml response (i see it in an alert).. But I want the response as a JSON object.. What should I do. One solution would have been httpRequest.setRequestHeader('Accept', 'application/JSON'); but this gives me a server error :500 Also it says A message body writer for Java type, class ...., and MIME media type, application/octet-stream, was not found Can someone suggest on what to do to overcome this and get the response as JSON?

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  • how to hide the image? how can i do ?

    - by user309381
    function Psend() { new Ajax.Request('Handler.ashx', { method: 'get', onSuccess: function(transport) { var response = transport.responseText || "no response text"; //alert("Success! \n\n" + response); var obj = response.evalJSON(true); for (i = 0; i < 4; i++) { DeCheBX = $('MyDiv').insert(new Element('input', { 'type': 'checkbox', 'id': "img" + obj[i].Nam, 'value': obj[i].IM, 'onClick': 'SayHi(this)' })); DeImg = $('MyDiv').insert(new Element('img', { 'id': "img" + obj[i].Nam, 'src': obj[i].IM, 'style': 'display = inline', 'onClick': 'Say(this)' })); document.body.appendChild(DeCheBX); document.body.appendChild(DeImg); } }, onFailure: function() { alert('Something went wrong...') } }); SayHi = function(x) { if ($(x).checked == true) { // $('id').hide(); **$('img'+i).style.visibility = "hidden";**// doesnt work } };

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  • Can i create different observables and different corresponding observers in java?

    - by mithun1538
    Hello everyone, Currently, I have one observable and many observers. What i need is different observables, and depending on the observable, different observers. How do I achieve this? ( For understanding, assume I have different apples - say apple1 apple2... I have observer_1 observing apple1, observer_2 observing apple2, observer_3 observing apple 2 and so on..). I tried creating different objects of the Observable class, but since observers are observing the same class of observable, I don't know how to access a particular instance of the Observable. I have included the following servlet code that contains Observer and Observable classes: public class CustomerServlet extends HttpServlet { public String getNextMessage() { // Create a message sink to wait for a new message from the // message source. return new MessageSink().getNextMessage(source); } @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ObjectOutputStream dout = new ObjectOutputStream(response.getOutputStream()); String recMSG = getNextMessage(); dout.writeObject(recMSG); dout.flush(); } public void broadcastMessage(String message) { // Send the message to all the HTTP-connected clients by giving the // message to the message source source.sendMessage(message); } @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { ObjectInputStream din= new ObjectInputStream(request.getInputStream()); String message = (String)din.readObject(); ObjectOutputStream dout = new ObjectOutputStream(response.getOutputStream()); dout.writeObject("1"); dout.flush(); if (message != null) { broadcastMessage(message); } // Set the status code to indicate there will be no response response.setStatus(response.SC_NO_CONTENT); } catch (Exception e) { e.printStackTrace(); } } @Override public String getServletInfo() { return "Short description"; }// </editor-fold> MessageSource source = new MessageSource(); } class MessageSource extends Observable { public void sendMessage(String message) { setChanged(); notifyObservers(message); } } class MessageSource extends Observable { public void sendMessage(String message) { setChanged(); notifyObservers(message); } } class MessageSink implements Observer { String message = null; // set by update() and read by getNextMessage() // Called by the message source when it gets a new message synchronized public void update(Observable o, Object arg) { // Get the new message message = (String)arg; // Wake up our waiting thread notify(); } // Gets the next message sent out from the message source synchronized public String getNextMessage(MessageSource source) { // Tell source we want to be told about new messages source.addObserver(this); // Wait until our update() method receives a message while (message == null) { try { wait(); } catch (Exception e) { System.out.println("Exception has occured! ERR ERR ERR"); } } // Tell source to stop telling us about new messages source.deleteObserver(this); // Now return the message we received // But first set the message instance variable to null // so update() and getNextMessage() can be called again. String messageCopy = message; message = null; return messageCopy; } }

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  • Process is killed without a (obvious) reason and program stops working

    - by Krzysiek Gurniak
    Here's what my program is supposed to do: create 4 child processes: process 0 is reading 1 byte at a time from STDIN, then writing it into FIFO process 1 is reading this 1 byte from fifo and write its value as HEX into shared memory process 2 is reading HEX value from shared memory and writing it into pipe finally process 3 is reading from pipe and writing into STDOUT (in my case: terminal) I can't change communication channels. FIFO, then shared memory, then pipes are the only option. My problem: Program stops at random moments when some file is directed into stdin (for example:./program < /dev/urandom). Sometimes after writing 5 HEX values, sometimes after 100. Weird thing is that when it is working and in another terminal I write "pstree -c" there is 1 main process with 4 children processes (which is what I want), but when I write "pstree -c" after it stopped writing (but still runs) there are only 3 child processes. For some reason 1 is gone even though they all have while(1) in them.. I think I might have problem with synchronization here, but I am unable to spot it (I've tried for many hours). Here's the code: #include <unistd.h> #include <fcntl.h> #include <stdio.h> #include <string.h> #include <stdlib.h> #include <sys/shm.h> #include <sys/sem.h> #include <sys/types.h> #include <sys/wait.h> #include <sys/stat.h> #include <string.h> #include <signal.h> #define BUFSIZE 1 #define R 0 #define W 1 // processes ID pid_t p0, p1, p2, p3; // FIFO variables int fifo_fd; unsigned char bufor[BUFSIZE] = {}; unsigned char bufor1[BUFSIZE] = {}; // Shared memory variables key_t key; int shmid; char * tab; // zmienne do pipes int file_des[2]; char bufor_pipe[BUFSIZE*30] = {}; void proces0() { ssize_t n; while(1) { fifo_fd = open("/tmp/fifo",O_WRONLY); if(fifo_fd == -1) { perror("blad przy otwieraniu kolejki FIFO w p0\n"); exit(1); } n = read(STDIN_FILENO, bufor, BUFSIZE); if(n<0) { perror("read error w p0\n"); exit(1); } if(n > 0) { if(write(fifo_fd, bufor, n) != n) { perror("blad zapisu do kolejki fifo w p0\n"); exit(1); } memset(bufor, 0, n); // czyszczenie bufora } close(fifo_fd); } } void proces1() { ssize_t m, x; char wartosc_hex[30] = {}; while(1) { if(tab[0] == 0) { fifo_fd = open("/tmp/fifo", O_RDONLY); // otwiera plik typu fifo do odczytu if(fifo_fd == -1) { perror("blad przy otwieraniu kolejki FIFO w p1\n"); exit(1); } m = read(fifo_fd, bufor1, BUFSIZE); x = m; if(x < 0) { perror("read error p1\n"); exit(1); } if(x > 0) { // Konwersja na HEX if(bufor1[0] < 16) { if(bufor1[0] == 10) // gdy enter { sprintf(wartosc_hex, "0x0%X\n", bufor1[0]); } else { sprintf(wartosc_hex, "0x0%X ", bufor1[0]); } } else { sprintf(wartosc_hex, "0x%X ", bufor1[0]); } // poczekaj az pamiec bedzie pusta (gotowa do zapisu) strcpy(&tab[0], wartosc_hex); memset(bufor1, 0, sizeof(bufor1)); // czyszczenie bufora memset(wartosc_hex, 0, sizeof(wartosc_hex)); // przygotowanie tablicy na zapis wartosci hex x = 0; } close(fifo_fd); } } } void proces2() { close(file_des[0]); // zablokuj kanal do odczytu while(1) { if(tab[0] != 0) { if(write(file_des[1], tab, strlen(tab)) != strlen(tab)) { perror("blad write w p2"); exit(1); } // wyczysc pamiec dzielona by przyjac kolejny bajt memset(tab, 0, sizeof(tab)); } } } void proces3() { ssize_t n; close(file_des[1]); // zablokuj kanal do zapisu while(1) { if(tab[0] == 0) { if((n = read(file_des[0], bufor_pipe, sizeof(bufor_pipe))) > 0) { if(write(STDOUT_FILENO, bufor_pipe, n) != n) { perror("write error w proces3()"); exit(1); } memset(bufor_pipe, 0, sizeof(bufor_pipe)); } } } } int main(void) { key = 5678; int status; // Tworzenie plikow przechowujacych ID procesow int des_pid[2] = {}; char bufor_proces[50] = {}; mknod("pid0", S_IFREG | 0777, 0); mknod("pid1", S_IFREG | 0777, 0); mknod("pid2", S_IFREG | 0777, 0); mknod("pid3", S_IFREG | 0777, 0); // Tworzenie semaforow key_t klucz; klucz = ftok(".", 'a'); // na podstawie pliku i pojedynczego znaku id wyznacza klucz semafora if(klucz == -1) { perror("blad wyznaczania klucza semafora"); exit(1); } semafor = semget(klucz, 1, IPC_CREAT | 0777); // tworzy na podstawie klucza semafor. 1 - ilosc semaforow if(semafor == -1) { perror("blad przy tworzeniu semafora"); exit(1); } if(semctl(semafor, 0, SETVAL, 0) == -1) // ustawia poczatkowa wartosc semafora (klucz, numer w zbiorze od 0, polecenie, argument 0/1/2) { perror("blad przy ustawianiu wartosci poczatkowej semafora"); exit(1); } // Tworzenie lacza nazwanego FIFO if(access("/tmp/fifo", F_OK) == -1) // sprawdza czy plik istnieje, jesli nie - tworzy go { if(mkfifo("/tmp/fifo", 0777) != 0) { perror("blad tworzenia FIFO w main"); exit(1); } } // Tworzenie pamieci dzielonej // Lista pamieci wspoldzielonych, komenda "ipcs" // usuwanie pamieci wspoldzielonej, komenta "ipcrm -m ID_PAMIECI" shmid = shmget(key, (BUFSIZE*30), 0666 | IPC_CREAT); if(shmid == -1) { perror("shmget"); exit(1); } tab = (char *) shmat(shmid, NULL, 0); if(tab == (char *)(-1)) { perror("shmat"); exit(1); } memset(tab, 0, (BUFSIZE*30)); // Tworzenie lacza nienazwanego pipe if(pipe(file_des) == -1) { perror("pipe"); exit(1); } // Tworzenie procesow potomnych if(!(p0 = fork())) { des_pid[W] = open("pid0", O_WRONLY | O_TRUNC | O_CREAT); // 1 - zapis, 0 - odczyt sprintf(bufor_proces, "Proces0 ma ID: %d\n", getpid()); if(write(des_pid[W], bufor_proces, sizeof(bufor_proces)) != sizeof(bufor_proces)) { perror("blad przy zapisie pid do pliku w p0"); exit(1); } close(des_pid[W]); proces0(); } else if(p0 == -1) { perror("blad przy p0 fork w main"); exit(1); } else { if(!(p1 = fork())) { des_pid[W] = open("pid1", O_WRONLY | O_TRUNC | O_CREAT); // 1 - zapis, 0 - odczyt sprintf(bufor_proces, "Proces1 ma ID: %d\n", getpid()); if(write(des_pid[W], bufor_proces, sizeof(bufor_proces)) != sizeof(bufor_proces)) { perror("blad przy zapisie pid do pliku w p1"); exit(1); } close(des_pid[W]); proces1(); } else if(p1 == -1) { perror("blad przy p1 fork w main"); exit(1); } else { if(!(p2 = fork())) { des_pid[W] = open("pid2", O_WRONLY | O_TRUNC | O_CREAT); // 1 - zapis, 0 - odczyt sprintf(bufor_proces, "Proces2 ma ID: %d\n", getpid()); if(write(des_pid[W], bufor_proces, sizeof(bufor_proces)) != sizeof(bufor_proces)) { perror("blad przy zapisie pid do pliku w p2"); exit(1); } close(des_pid[W]); proces2(); } else if(p2 == -1) { perror("blad przy p2 fork w main"); exit(1); } else { if(!(p3 = fork())) { des_pid[W] = open("pid3", O_WRONLY | O_TRUNC | O_CREAT); // 1 - zapis, 0 - odczyt sprintf(bufor_proces, "Proces3 ma ID: %d\n", getpid()); if(write(des_pid[W], bufor_proces, sizeof(bufor_proces)) != sizeof(bufor_proces)) { perror("blad przy zapisie pid do pliku w p3"); exit(1); } close(des_pid[W]); proces3(); } else if(p3 == -1) { perror("blad przy p3 fork w main"); exit(1); } else { // proces macierzysty waitpid(p0, &status, 0); waitpid(p1, &status, 0); waitpid(p2, &status, 0); waitpid(p3, &status, 0); //wait(NULL); unlink("/tmp/fifo"); shmdt(tab); // odlaczenie pamieci dzielonej shmctl(shmid, IPC_RMID, NULL); // usuwanie pamieci wspoldzielonej printf("\nKONIEC PROGRAMU\n"); } } } } exit(0); }

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  • C++ Stack Overflow

    - by PhilMAN
    Here is some code: void main() { GameEngine ge("phil", "anotherguy"); string response; do { ge.playGame(); cout << endl << "Do you want to (r)eplay the same battle, (s)tart a new battle, or (q)uit? "; cin >> response; } while(response == "r" || response == "R" || response == "s" || response == "S" ); } GameEngine::GameEngine(string name1, string name2) { p1Name = name1; p2Name = name2; } void GameEngine::playGame() { cout << "PLAY GAME" << endl; Army p1, p2; Battlefield testField; RuleSet rs; int xSize = 13; // Number of rows int ySize = 13; // Number of columns loadData(p1, p2, testField, rs, xSize, ySize); ... } void GameEngine::loadData(Army& p1, Army& p2, Battlefield& testField, RuleSet& rs, int& xSize, int& ySize) { string terrain = BattlefieldUtils::pickTerrain(); string armySplit[14];//id index 1 string ruleSplit[19];//in index 7 string armyP1, armyP2, ruleSet; Skill p1Skills[8]; Skill p2Skills[8]; CreatureStack p1Stacks[20]; CreatureStack p2Stacks[20]; ... } CreatureStack(){quantity = 0; isLive = false; id = -1;}; Army(){}; Battlefield(){}; RuleSet(){}; I have posted every line of code that executes until the program crashes. This code ran fine for a long time, I added some stuff that does not even execute until way after the code I have posted here, and bam stack overflow that occurs at GameEngine::loadData() line: CreatureStack p2Stacks[20]; will not go away. What am I doing wrong here? Is that all the stack can handle? I increased the stack size in Visual Studio and got the error to go away, but that slowed things down considerably, so I would rather just get to the source of the issue and fix that.

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  • Path to background in servlet

    - by kapil chhattani
    //the below line is the element of my HTML form which renders the image sent by the servlet written further below. <img style="margin-left:91px; margin-top:-6px;" class="image" src="http://www.abcd.com/captchaServlet"> I generate a captcha code using the following code in java. public class captchaServlet extends HttpServlet { protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { int width = 150; int height = 50; int charsToPrint = 6; String elegibleChars = "ABCDEFGHJKLMPQRSTUVWXYabcdefhjkmnpqrstuvwxy1234567890"; char[] chars = elegibleChars.toCharArray(); StringBuffer finalString = new StringBuffer(); for ( int i = 0; i < charsToPrint; i++ ) { double randomValue = Math.random(); int randomIndex = (int) Math.round(randomValue * (chars.length - 1)); char characterToShow = chars[randomIndex]; finalString.append(characterToShow); } System.out.println(finalString); BufferedImage bufferedImage = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB); Graphics2D g2d = bufferedImage.createGraphics(); Font font = new Font("Georgia", Font.BOLD, 18); g2d.setFont(font); RenderingHints rh = new RenderingHints( RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON); rh.put(RenderingHints.KEY_RENDERING, RenderingHints.VALUE_RENDER_QUALITY); g2d.setRenderingHints(rh); GradientPaint gp = new GradientPaint(0, 0, Color.BLUE, 0, height/2, Color.black, true); g2d.setPaint(gp); g2d.fillRect(0, 0, width, height); g2d.setColor(new Color(255, 255, 0)); Random r = new Random(); int index = Math.abs(r.nextInt()) % 5; char[] data=new String(finalString).toCharArray(); String captcha = String.copyValueOf(data); int x = 0; int y = 0; for (int i=0; i<data.length; i++) { x += 10 + (Math.abs(r.nextInt()) % 15); y = 20 + Math.abs(r.nextInt()) % 20; g2d.drawChars(data, i, 1, x, y); } g2d.dispose(); response.setContentType("image/png"); OutputStream os = response.getOutputStream(); ImageIO.write(bufferedImage, "png", os); os.close(); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { processRequest(request, response); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { processRequest(request, response); } } But in the above code background is also generated using the setPaint menthod I am guessing. I want the background to be some image from my local machine whoz URL i should be able to mention like URL url=this.getClass().getResource("Desktop/images.jpg"); BufferedImage bufferedImage = ImageIO.read(url); I am just writing the above two lines for making the reader understand better what the issue is. Dont want to use the exact same commands. All I want is the the background of the captcha code generated should be an image of my choice.

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  • Access to the path Server.MapPath is denied

    - by Alex
    I created one pdf document var document = new Document(); string path = Server.MapPath("AttachementToMail"); PdfWriter.GetInstance(document, new FileStream(path + "/"+DateTime.Now.ToShortDateString()+".pdf", FileMode.Create)); Now I want to download this document Response.ContentType = "Application/pdf"; Response.AppendHeader("Content-Disposition", "attachment; filename="+ DateTime.Now.ToShortDateString() + ".pdf" + ""); Response.TransmitFile(path); Response.End(); but it gave me error Access to the path '~\AttachementToMail' is denied. read / write access for IIS_IUSRS exists

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  • Why do I need to close fds when reading and writing to the pipe?

    - by valentimsousa
    However, what if one of my processes needs to continuously write to the pipe while the other pipe needs to read? This example seems to work only for one write and one read. I need multi read and write void executarComandoURJTAG(int newSock) { int input[2], output[2], estado, d; pid_t pid; char buffer[256]; char linha[1024]; pipe(input); pipe(output); pid = fork(); if (pid == 0) {// child close(0); close(1); close(2); dup2(input[0], 0); dup2(output[1], 1); dup2(output[1], 2); close(input[1]); close(output[0]); execlp("jtag", "jtag", NULL); } else { // parent close(input[0]); close(output[1]); do { read(newSock, linha, 1024); /* Escreve o buffer no pipe */ write(input[1], linha, strlen(linha)); close(input[1]); while ((d = read(output[0], buffer, 255))) { //buffer[d] = '\0'; write(newSock, buffer, strlen(buffer)); puts(buffer); } write(newSock, "END", 4); } while (strcmp(linha, "quit") != 0); } }

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  • Reading and writing in parallel

    - by Malfist
    I want to be able to read and write a large file in parallel, or if not in parallel, at least in blocks so that I don't use up so much memory. This is my current code: // Define memory stream which will be used to hold encrypted data. MemoryStream memoryStream = new MemoryStream(); // Define cryptographic stream (always use Write mode for encryption). CryptoStream cryptoStream = new CryptoStream(memoryStream, encryptor, CryptoStreamMode.Write); //start encrypting using (BinaryReader reader = new BinaryReader(File.Open(fileIn, FileMode.Open))) { byte[] buffer = new byte[1024 * 1024]; int read = 0; do { read = reader.Read(buffer, 0, buffer.Length); cryptoStream.Write(buffer, 0, read); } while (read == buffer.Length); } // Finish encrypting. cryptoStream.FlushFinalBlock(); // Convert our encrypted data from a memory stream into a byte array. //byte[] cipherTextBytes = memoryStream.ToArray(); //write our memory stream to a file memoryStream.Position = 0; using (BinaryWriter writer = new BinaryWriter(File.Open(fileOut, FileMode.Create))) { byte[] buffer = new byte[1024 * 1024]; int read = 0; do { read = memoryStream.Read(buffer, 0, buffer.Length); writer.Write(buffer, 0, read); } while (read == buffer.Length); } // Close both streams. memoryStream.Close(); cryptoStream.Close(); As you can see, it reads the entire file into memory, encrypts it, then writes it out. If I happen to be encrypting files that are very large (2GB+) it tends not to work, or at the very least, consumes ~97% of my memory. How could I do it in a more effective manner?

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  • How do i close a socket after a timeout in node.js?

    - by rramsden
    I'm trying to close a socket after a connection times out after 1000ms. I am able to set a timeout that gets triggered after a 1000ms but I can't seem to destroy the socket... any ideas? var connection = http.createClient(80, 'localhost'); var request = connection.request('GET', '/somefile.xml', {'host':'localhost'}); var start = new Date().getTime(); request.socket.setTimeout(1000); request.socket.addListener("timeout", function() { request.socket.destroy(); sys.puts("socket timeout connection closed"); }); request.addListener("response", function(response) { var responseBody = []; response.setEncoding("utf8"); response.addListener("data", function(chunk) { sys.puts(chunk); responseBody.push(chunk); }); response.addListener("end", function() { }); }); request.end(); returns socket timeout connection closed node.js:29 if (!x) throw new Error(msg || "assertion error"); ^ Error: assertion error at node.js:29:17 at Timer.callback (net:152:20) at node.js:204:9

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  • JSF: How to forward a request to another page in action?

    - by Satya
    I want to forward request to another page from action class I am using below code in my jsf action : public String submitUserResponse(){ ...... ...... parseResponse(uri,request,response); .... return "nextpage"; } public String parseResponse(String uri,request,response){ if(uri != null){ RequestDispatcher dispatcher = request.getRequestDispatcher(uri); dispatcher.forward(request, response); return null; } ................. .................. return "xxxx"; } "submitUserResponse" method is being called when user clicks the submit button from the jsp and this method returns "nextpage" string here request forwards to next page in normal flow. but in my requirement i will call "submitUserResponse () " which will execute and forwrd request to next page.It is going. but it is displaying some exceptions in server That is : java.lang.IllegalStateException: Cannot forward after response has been committed Here my doubts are: 1.why next lines of code is being executed after forwarding my request using dispatched.forward(uri) . Same thing happening in response.sendRedirect("").

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  • Python HTTPSConnection.close() does not appear to close the connection?

    - by Dave
    I'm not sure if this is a bug or if I'm just doing something wrong. If I were to do an HTTP connection like this: import httplib http_connection = httplib.HTTPConnection("192.168.192.196") http_connection.request("GET", "/") http_connection.sock.settimeout(20) response = http_connection.getresponse() data = response.read() http_connection.close() Then at a DOS prompt, I do this: netstat -ano | find /i "192.168.192.196:80" | find /i "ESTABLISHED" I get nothing. However, if I do the same thing, but change it to an HTTPSConnection: import httplib http_connection = httplib.HTTPSConnection("192.168.192.196") http_connection.request("GET", "/") http_connection.sock.settimeout(20) response = http_connection.getresponse() data = response.read() http_connection.close() Then do this: netstat -ano | find /i "192.168.192.196:443" | find /i "ESTABLISHED" I will actually see that the connection remains established until I actually ^Z out of the Python shell. This is happening in one of the applications I'm responsible for. Python isn't actually hanging there - it's simply leaving the connection open. Am I doing something wrong here? Do I need extra code to close the HTTPS connection? This is Python 2.6.4, btw.

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  • Facebook FB.api post how to specify a target

    - by Laurent Luce
    I am using FB.api OpenGraph to post a message on the user's wall. I would like the link target to be equal to '_blank' so it opens in a new tab. Is it possible ? The Facebook documentation doesn't give much details. var params = {}; params['message'] = 'message'; params['name'] = 'name'; params['link'] = 'http://link'; params['picture'] = 'http://picture'; params['description'] = 'description'; FB.api('/me/feed', 'post', params, function(response) { if (!response || response.error) { alert('Error occured'); } else { alert('Post ID: ' + response); } });

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  • how do i design a high pass filters in matlab without using the builtin function?

    - by noura
    hello everyone, i'm just not sure how to draw the frequency response (H) of the high pass filter? after drawing the frequency response i can get the b coefficient by taking the ifft of (H). so yeah, for a low pass filter, with a cutoff frequency of say pi/2 : the frequency response code will be H = exp(-1*j*w*4).*(((0 <= w) & (w<= pi/2)) | ((2*pi - pi/2 <= w) & (w<=2*pi)); sincr the response is "1" between 0 and pi/2 and between (2*pi - pi/2) and 2*pi. can you help me write H for a high pass filter? thanx in advance.

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  • Organizing development teams

    - by Patrick
    A long time ago, when my company was much smaller, dividing the development work over teams was quite easy: the 'application' team developed the applications-specific logic, often requiring a deep insight of specific industry problems) the 'generic' team developed the parts that were common/generic for all applications (user interface related stuff, database access, low-level Windows stuff, ...) Over the years the boundaries between the teams have become fuzzy: the 'application' teams often write application-specific functionality with a 'generic' part, so instead of asking the 'generic' team to write that part for them, they write it themselves to speed up the developments; then donate it to the 'generic' team the 'generic' team's focus seems to be more 'maintenance oriented'. All of the 'very generic' code has already been written, so no new developments are needed in it, but instead they continuously have to support all the functionality donated by the application teams. All this seems to indicate that it's not a good idea anymore to have this split in teams. Maybe the 'generic' team should evolve into a 'software quality' team (defining and guarding the rules for writing good quality software), or into a 'software deployment' team (defining how software should be deployed, installed, ...). How do you split up the work in different teams if you have different applications? everybody can write generic code and donates it to a central 'generic' team? everybody can write generic code, but nobody 'manages' this generic code (everybody is the owner) generic code is written by a 'generic' team only and the applications have to wait until the 'generic' team delivers the generic part (via a library, via a DLL) there is no overlap in code between the different applications some other way? Notice that thee advantage of having the mix (allowing everybody to write everywhere in the code) is that: code is written in a more flexible way it's easier to debug the code since you can easily step into the 'generic' code in the debugger But the big (and maybe only) disadvantage is that this generic code may become nobody's responsibility if there is no clear team that manages it anymore. What is your vision?

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  • Call an external web service from a servlet

    - by pAkY88
    Hi, I'm developing a servlet that gets a name of a web service and could be forward the request to an external web service, for example: "http://www.webservice.com/..." I have build a response wrapper that intercept response output but I can't forward request to an external web service, it works only if I redirect the request to a servlet that is on same server. Example: request.getRequestDispatcher("aMyServlet").forward(request, response) IT WORKS request.getRequestDispatcher("http://www.webservice.com/...").forward(request, response) IT DON'T WORKS because Tomcat search "http://www.webservice.com/..." on the server as a local resource. How can I do external request? Thanks

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  • Jquery .$.ajax is not working

    - by Saravanan I M
    I am using $.ajax for facebook invite and calling the url (Yii framework controller). The below code is not working. $.ajax is not working. function FacebookInviteFriends() { FB.ui ( { method : 'apprequests', data: '', display: 'dialog', title : 'Invite a Friend', message: 'I just sent you an invitation to play My Game.', filters: ['app_non_users'] }, function(response) { alert("start"); if (response && response.to) { alert("inside if"); $.ajax({ url: 'http://localhost:83/invitechips/createRecord', type: 'POST', data: {id : response.to} }).done(function() { alert( "Data Saved: "); }); } else { alert("inside else"); } } ); }

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  • Backbone.js "model" query

    - by Novice coder
    I'm a learning coder trying to understand this code from a sample MVC framework. The below code is from a "model" file. I've done research on Backbone.js, but I'm still confused as to exactly how this code pull information from the app's database. For example, how are base_url, Model.prototype, and Collection.prototype being used to retrieve information from the backend? Any help would be greatly appreciated. exports.definition = { config : { "defaults": { "title": "-", "description": "-" }, "adapter": { "type": "rest", "collection_name": "schools", "base_url" : "/schools/", } }, extendModel: function(Model) { _.extend(Model.prototype, { // Extend, override or implement Backbone.Model urlRoot: '/school/', name:'school', parse: function(response, options) { response.id = response._id; return response; }, }); return Model; }, extendCollection: function(Collection) { _.extend(Collection.prototype, { // Extend, override or implement Backbone.Collection urlRoot: '/schools/', name: 'schools', }); return Collection; } }

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  • Should I HttpCombine Google Jquery Hosted File?

    - by chobo2
    Hi I am using something called HttpCombiner: http://code.msdn.microsoft.com/HttpCombiner An HTTP handler that combines multiple CSS, Javascript or URL into one response for faster page load. It can combine, compress and cache response which results in faster page load and better scalability of web application It's a good practice to use many small Javascript and CSS files instead of one large Javascript/CSS file for better code maintainability, but bad in terms of website performance. Although you should write your Javascript code in small files and break large CSS files into small chunks but when browser requests those javascript and css files, it makes one Http request per file. Every Http Request results in a network roundtrip form your browser to the server and the delay in reaching the server and coming back to the browser is called latency. So, if you have four javascripts and three css files loaded by a page, you are wasting time in seven network roundtrips. Within USA, latency is average 70ms. So, you waste 7x70 = 490ms, about half a second of delay. Outside USA, average latency is around 200ms. So, that means 1400ms of waiting. Browser cannot show the page properly until Css and Javascripts are fully loaded. So, the more latency you have, the slower page loads. You can reduce the wait time by using a CDN. Read my previous blog post about using CDN. However, a better solution is to deliver multiple files over one request using an HttpHandler that combines several files and delivers as one output. So, instead of putting many or tag, you just put one and one tag, and point them to the HttpHandler. You tell the handler which files to combine and it delivers those files in one response. This saves browser from making many requests and eliminates the latency. This Http Handler reads the file names defined in a configuration and combines all those files and delivers as one response. It delivers the response as gzip compressed to save bandwidth. Moreover, it generates proper cache header to cache the response in browser cache, so that, browser does not request it again on future visit. Now I am wondering since it can handle adding links should I put in it the jquery file? The reason I am not sure is if it gets combined with my other files I think I might close the advantages of it being hosted on googles servers such as caching(my thinking is if it gets combined it will look different so even if a user has it in it's cache I am not sure if it will use the one for the cahce or not). So should I combine it or only the finals that I am using locally?

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  • In node.js slow readable stream attached to a faster pushing message queue eats up memory

    - by Vishal
    In my node.js program I have a response stream attached to a message queue (zeromq) delivering data at a very high rate. Due to slow network connection the response stream and its underlying implementation is unable to consume data at that pace thus occupying a lot of memory. Do you have any suggestion to solve this problem. For reference please see the code snippet below: zmq.on("message", function(data) { res.write(data); // End response on some event });

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  • NSPredicate aggregate function [SIZE] gives 'unsupported function expression' error

    - by jinglesthula
    iOS 4: I have entities in Core Data (using SQLite, which is a requirement) of: Request Response (which has a property personId) Revision Relationships are: Request <-- Revision Request <-- Response Revision <-- Response (e.g. each request may have many responses; each request/response pair may have many revisions) I'm trying to do a predicate to get all Responses with a given personId that have zero Revisions. Using: (personId == %d) && (Request.Revision[SIZE] == 0) in my predicate string gives me a runtime exception "Unsupported function expression Request.Revision[SIZE]" The documentation seems pretty sparse on aggregate functions, only noting that they exist, but with no syntax or examples. Not sure if it's my syntax or if the SIZE function really isn't supported in iOS.

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  • Hiding Url for asp.net page

    - by user204588
    Hello, I'm creating an html page that is posted to another page for processing. I don't want users to see the weird URL they are redirected to and I was using FRAMES but I can't figure out how to add my HTML page dynamically because I need the variables and either add frames or try another way to accomplish this. So, based on how I'm creating the page below, how can I hide the URL and add something that I want. Here is how I'm creating the page. StringBuilder sb = new StringBuilder(); sb.Append("<html><head></head>"); sb.Append("<body onload=\"document.frmLaunch.submit();\">"); sb.Append("<form name=\"frmLaunch\" action=\"" + variableTargetURL + "\" method=\"post\">"); sb.Append("<input type=hidden name=\"testVariable\" value=\"" + variableTest + "\">"); sb.Append("</form>"); sb.Append("</body></html>"); HttpResponse response = HttpContext.Current.Response; response.Clear(); response.Write(sb.ToString()); response.End();

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