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  • Total newb having SSH and remote MySQL access problems

    - by kscott
    I don't often work with linux or need to SSH into remote MySQL databases, so pardon my ignorance. For months I had been using the HeidiSQL client application to remotely access a MySQL database. Today two things happened: the DB moved to a new server and I updated HeidiSQL, now I cannot log in to the MySQL server, when attempting I get this message from Heidi: SQL Error (2003) in statement #0: Can't connect to MySQL server on 'localhost' (10061) If I use Putty, I can connect to the server and get MySQL access through command line, including fetching data from the DB. I assume this means my credentials and address are correct, but do not understand why putting those same details into HeidiSQL's SSH tunnel info won't work. I also downloaded the MySQL Workbench and attempted to set up a connection through that client and got this message: Cannot Connect to Database Server Your connection attempt failed for user 'myusername' from your host to server at localhost:3306: Lost connection to MySQL server at 'reading initial communication packet', system error: 0 Please: 1 Check that mysql is running on server localhost 2 Check that mysql is running on port 3306 (note: 3306 is the default, but this can be changed) 3 Check the myusername has rights to connect to localhost from your address (mysql rights define what clients can connect to the server and from which machines) 4 Make sure you are both providing a password if needed and using the correct password for localhost connecting from the host address you're connecting from From Googling around I see that it could be related to the MySQL bind-address, but I am a third party sub-contractor with no access to the MySQL settings of this box and the system admin is assuring me that I'm an idiot and need to figure it out on my end. This is completely possible but I don't know what else to try. Edit 1 - The client settings I am using In Heidi and MySQL Workbench I am using the following: SSH host + port: theHostnameOfTheRemoteServer.com:22 {this is the same host I can Putty to} SSH Username: mySSHusername {the same user name I use for my Putty connection} SSH Password: mySSHpassword {the same password for the Putty connection} Local port: 3307 MySQL host: theHostnameOfTheRemoteServer.com MySQL User: mySQLusername {which I can connect with once in with Putty} MySQL Password: mySQLpassword {which works once in with Putty} Port: 3306

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  • Setting Outlook Web Access as default mail client in Firefox

    - by Barton Chittenden
    The company that I work for is nice enough to let me use Linux for work, but they use Outlook. I've been using Outlook Web Access (OWA) as my mail client, which is more or less acceptable. The only problem is that whenever I click on a mailto link or use the "Send Link" menu option in firefox, I'm prompted to use evolution. Since connecting to an exchange server through evolution seems to be sketchy at best, I would like to set OWA as my default mail client. I'm using Firefox 3.6.13 Here's what I've found so far: Default mail client can be found at Edit Menu -> Preferences -> Applications Tab -> mailto When I click on the drop down menu, one of the options is "Application Details" This shows two options by default: Google Yahoo! Mail Each of these shows how to launch that service. For Gmail: https://mail.google.com/mail/?extsrc=mailto&url=%s For Yahoo!: http://compose.mail.yahoo.com/?To=%s I presume that Outlook Web Access has something similar. Based on the googling that I've done so far, I think that this should look something like this: https://<server name>/owa/?cmd=compose... A little experimentation on my part shows that the following will compose a message: https://<email server>/owa/?ae=Item&a=New&t=IPM.Note but I still don't know how to specify recipient, subject or body of the email to be composed... What I want to know is a) does anyone know the URL parameters to compose a mailto in Outlook Web Access, including subject, recipient and body? else b) can someone give me a decent pointer for where to get this information?

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  • Remote access to phpmyadmin from computer belongs to same LAN

    - by Charles
    OK... I solved it. It is because I have not configured the httpd.conf to allow the centos listen port 80 and 8080. Listen 80 Listen 8080 I have setup the myphpadmin on my CentOS 6.4 recently. I can access and login to the myphpadmin on my localhost. However, when I type http://[hostipaddr]/phpmyadmin on my other computer in the same LAN with the CentOS, the browser simply cannot access the page. Below are some of the current configuration. Anyone can help please......? config.inc.php $i++; /* Authentication type */ $cfg['Servers'][$i]['auth_type'] = 'http'; /* Server parameters */ $cfg['Servers'][$i]['host'] = 'localhost'; $cfg['Servers'][$i]['connect_type'] = 'tcp'; $cfg['Servers'][$i]['compress'] = false; /* Select mysql if your server does not have mysqli */ $cfg['Servers'][$i]['extension'] = 'mysql'; $cfg['Servers'][$i]['AllowNoPassword'] = false; phpmyadmin.conf <Directory /var/www/html/phpmyadmin/> order allow,deny allow from all </Directory> Furthermore, I can access the webpage that stored in the CentOS from my other computer without problems. After using wireshark and tcpdump, I found that the server (the Cent OS) keep resetting the connection. (192.168.1.106 is my other computer, 192.168.1.101 is my CentOS) 23:29:42.281473 IP 192.168.1.106.55999 > 192.168.1.101.webcache: Flags [S], seq 2559409090, win 65535, options [mss 1460,nop,wscale 8,nop,nop,sackOK], length 0 23:29:42.281504 IP 192.168.1.101.webcache > 192.168.1.106.55999: Flags [R.], seq 0, ack 2559409091, win 0, length 0 I have disabled the iptables service on the CentOS already.

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  • Access to CD/DVD Drive is Denied through Windows 7 Explorer (Permission Problem)

    - by Synetech inc.
    A while ago I started having trouble with my optical drives. Both of them keep showing up in Explorer as CD/DVD drives on boot, but as soon as I put a disc in either one, it suddenly turns into a hard-drive—“local disk” is displayed in the Type column, though the File System column remains UDF/CDFS. (I though that maybe it was a permission issue on the registry key in HKLM\System\CurrentControlSet..., but I’m not so certain because of the next test.) When I try to open a disc (of any type), I get an access denied error message. If I open an elevated command-prompt, I am able to access the files. Also, if I kill Explorer and run it from an elevated command-prompt (thus giving Explorer elevated permissions), then I can access the files from Explorer. I’ve tried uninstalling and reinstalling the devices without success. The security dialog indicates that there are none set for the drives (no owner and no permissions). I tried setting the owner, but am only able to do so if there is a disc in it (it complains if it is empty), but the settings do not stick (if I immediately open the security dialog after setting it, it is empty again). I tried setting permissions, but that gives an error. I’ve included a screencap-flowchart of the security dialog of one of the drives below. (Yes, I made sure that there are no upper- or lower-filters, and yes, I ran sfc. I also made sure that in the policy editor, “devices: restrict CD-ROM...” is not set.) Does anyone know what the owner and permissions are supposed to be for optical drives and how to reset them?

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  • Easy Profiling Point Insertion

    - by Geertjan
    One really excellent feature of NetBeans IDE is its Profiler. What's especially cool is that you can analyze code fragments, that is, you can right-click in a Java file and then choose Profiling | Insert Profiling Point. When you do that, you're able to analyze code fragments, i.e., from one statement to another statement, e.g., how long a particular piece of code takes to execute: https://netbeans.org/kb/docs/java/profiler-profilingpoints.html However, right-clicking a Java file and then going all the way down a longish list of menu items, to find "Profiling", and then "Insert Profiling Point" is a lot less easy than right-clicking in the sidebar (known as the glyphgutter) and then setting a profiling point in exactly the same way as a breakpoint: That's much easier and more intuitive and makes it far more likely that I'll use the Profiler at all. Once profiling points have been set then, as always, another menu item is added for managing the profiling point: To achieve this, I added the following to the "layer.xml" file: <folder name="Editors"> <folder name="AnnotationTypes"> <file name="profiler.xml" url="profiler.xml"/> <folder name="ProfilerActions"> <file name="org-netbeans-modules-profiler-ppoints-ui-InsertProfilingPointAction.shadow"> <attr name="originalFile" stringvalue="Actions/Profile/org-netbeans-modules-profiler-ppoints-ui-InsertProfilingPointAction.instance"/> <attr name="position" intvalue="300"/> </file> </folder> </folder> </folder> Notice that a "profiler.xml" file is referred to in the above, in the same location as where the "layer.xml" file is found. Here is the content: <!DOCTYPE type PUBLIC '-//NetBeans//DTD annotation type 1.1//EN' 'http://www.netbeans.org/dtds/annotation-type-1_1.dtd'> <type name='editor-profiler' description_key='HINT_PROFILER' localizing_bundle='org.netbeans.eppi.Bundle' visible='true' type='line' actions='ProfilerActions' severity='ok' browseable='false'/> Only disadvantage is that this registers the profiling point insertion in the glyphgutter for all file types. But that's true for the debugger too, i.e., there's no MIME type specific glyphgutter, instead, it is shared by all MIME types. Little bit confusing that the profiler point insertion can now, in theory, be set for all MIME types, but that's also true for the debugger, even though it doesn't apply to all MIME types. That probably explains why the profiling point insertion can only be done, officially, from the right-click popup menu of Java files, i.e., the developers wanted to avoid confusion and make it available to Java files only. However, I think that, since I'm already aware that I can't set the Java debugger in an HTML file, I'm also aware that the Java profiler can't be set that way as well. If you find this useful too, you can download and install the NBM from here: http://plugins.netbeans.org/plugin/55002

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  • MS Access 2003 - Formatting results in a list box problem.

    - by Justin
    So I have a list box that displays averages in a table like format from a crossyab query. It's just what I need the query is right, there is just one thing. I had to set the field properties in the query as format: standard..decimal:2. Which is exactly what I needed. However..the list box will not pick up on this. First I typed the crosstab sql into the list box's properties....and then I ran into this problem. So then I actually just created the query object, saved it and set that as the rowsource for the list box. Still won't work....when I open the query it is the correct format. So is there a way to further format a text box? Is there a way tell it to limit decimal places to one or two on returned values? Thanks!

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  • In Ruby, how to implement 20 - point and point - 20 using coerce() ?

    - by Jian Lin
    In Ruby, the operation of point - 20 20 - point are to be implemented. But the following code: class Point attr_accessor :x, :y def initialize(x,y) @x, @y = x, y end def -(q) if (q.is_a? Fixnum) return Point.new(@x - q, @y - q) end Point.new(@x - q.x, @y - q.y) end def -@ Point.new(-@x, -@y) end def *(c) Point.new(@x * c, @y * c) end def coerce(something) [self, something] end end p = Point.new(100,100) q = Point.new(80,80) p (-p) p p - q p q - p p p * 3 p 5 * p p p - 30 p 30 - p Output: #<Point:0x2424e54 @x=-100, @y=-100> #<Point:0x2424dc8 @x=20, @y=20> #<Point:0x2424d3c @x=-20, @y=-20> #<Point:0x2424cc4 @x=300, @y=300> #<Point:0x2424c38 @x=500, @y=500> #<Point:0x2424bc0 @x=70, @y=70> #<Point:0x2424b20 @x=70, @y=70> 30 - p will actually be taken as p - 30 by the coerce function. Can it be made to work? I am actually surprise that the - method won't coerce the argument this way: class Fixnum def -(something) if (/* something is unknown class */) a, b = something.coerce(self) return -(a - b) # because we are doing a - b but we wanted b - a, so it is negated end end end that is, the function returns a negated version of a - b instead of just returning a - b.

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  • Using Excel To Read Access Without MS Access On Computer

    - by Tom Clark
    I have written code that joins two table in access, using criteria supplied from drop down lists in excel and then returns the data to a specific location on the spreadsheet (titles already on the sheet). This works fine on my box and others with MS Access on the machine, but the purpose of writing this was to give people (associates) that dont have the MS Access on their machines (which is most of them) to be able to do simple queries to the database. When we try to run this on a machine without MS Access, we are getting the error message "Compile Error: Cant find project or library." Since this works fine on any machine so far that has Access, but not the others I am wondering if this is not possible without the actual Access software. Any help or insight would be appreciated. Tom

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  • Extend and Overload MS and Point Types

    - by dr d b karron
    Do I have make my own Point and Vector types to overload them ? Why does this not work ? namespace System . windows { public partial struct Point : IFormattable { public static Point operator * ( Point P , double D ) { Point Po = new Point ( ); return Po; } } } namespace SilverlightApplication36 { public partial class MainPage : UserControl { public static void ShrinkingRectangle ( WriteableBitmap wBM , int x1 , int y1 , int x2 , int y2 , Color C ) { wBM . DrawRectangle ( x1 , y1 , x2 , y2 , Colors . Red ); Point Center = Mean ( x1 , y1 , x2 , y2 ); wBM . SetPixel ( Center , Colors.Blue , 3 ); Point P1 = new Point ( x1 , y1 ); Point P2 = new Point ( x1 , y2 ); Point P3 = new Point ( x1 , y2 ); Point P4 = new Point ( x2 , y1 ); const int Steps = 10; for ( int i = 0 ; i < Steps ; i++ ) { double iF = (double)(i+1) / (double)Steps; double jF = ( 1.0 - iF ); Point P11 = **P1 * jF;** } }

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  • Access VBA: How to test if recordSet is empty? isNull?

    - by Shubham
    How can you test if a record set is empty? Dim temp_rst1 As Recordset Dim temp_rst2 As Recordset Set temp_rst1 = db.OpenRecordset("SELECT * FROM ORDER_DATA WHERE SKUS_ORDERED = '" & curSKU1 & "' AND [ORDER] = " & curOrder) Set temp_rst2 = db.OpenRecordset("SELECT * FROM ORDER_DATA WHERE SKUS_ORDERED = '" & curSKU2 & "' AND [ORDER] = " & curOrder) If IsNull(temp_rst1) Or IsNull(temp_rst2) Then MsgBox "null" I'm opening up a couple of record sets based on a select statement. If there are no records, will IsNull return true?

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  • MS Access "#Name?" in unbound field on SOME machines

    - by alkorya
    I have a datasheet form bound to table. I added 2 unbound fields and set their Control Source properties to user defined VBA functions: 1. ConcatRelated (http://allenbrowne.com/func-concat.html) 2. Custom function that returns a string: Public Function GetLowestSatatus(LookupField As String, JSAID As Integer) As String On Error Resume Next GetLowestSatatus = DLookup(LookupField, "JsaStatuses", "ID=" & DMin("StatusID", "Tasks", "JSAID =" & JSAID)) End Function It works fine on my and some other machines but there are machines I got "#Name?" in these 2 unbound fields. All machines configured identically. Any ideas? Thank you!

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  • Issue with a point coordinates, which creates an unwanted triangle

    - by Paul
    I would like to connect the points from the red path, to the y-axis in blue. I figured out that the problem with my triangles came from the first point (V0) : it is not located where it should be. In the console, it says its location is at 0,0, but in the emulator, it is not. The code : for(int i = 1; i < 2; i++) { CCLOG(@"_polyVertices[i-1].x : %f, _polyVertices[i-1].y : %f", _polyVertices[i-1].x, _polyVertices[i-1].y); CCLOG(@"_polyVertices[i].x : %f, _polyVertices[i].y : %f", _polyVertices[i].x, _polyVertices[i].y); ccDrawLine(_polyVertices[i-1], _polyVertices[i]); } The output : _polyVertices[i-1].x : 0.000000, _polyVertices[i-1].y : 0.000000 _polyVertices[i].x : 50.000000, _polyVertices[i].y : 0.000000 And the result : (the layer goes up, i could not take the screenshot before the layer started to go up, but the first red point starts at y=0) : Then it creates an unwanted triangle when the code continues : Would you have any idea about this? (So to force the first blue point to start at 0,0, and not at 50,0 as it seems to be now) Here is the code : - (void)generatePath{ float x = 50; //first red point float y = 0; for(int i = 0; i < kMaxKeyPoints+1; i++) { if (i<3){ _hillKeyPoints[i] = CGPointMake(x, y); x = 150 + (random() % (int) 30); y += -40; } else if(i<20){ //going right _hillKeyPoints[i] = CGPointMake(x, y); x += (random() % (int) 30); y += -40; } else if(i<25){ //stabilize _hillKeyPoints[i] = CGPointMake(x, y); x = 150 + (random() % (int) 30); y += -40; } else if(i<30){ //going left _hillKeyPoints[i] = CGPointMake(x, y); //x -= (random() % (int) 10); x = 150 + (random() % (int) 30); y += -40; } else { //back to normal _hillKeyPoints[i] = CGPointMake(x, y); x = 150 + (random() % (int) 30); y += -40; } } } -(void)generatePolygons{ static int prevFromKeyPointI = -1; static int prevToKeyPointI = -1; // key points interval for drawing while (_hillKeyPoints[_fromKeyPointI].y > -_offsetY+winSizeTop) { _fromKeyPointI++; } while (_hillKeyPoints[_toKeyPointI].y > -_offsetY-winSizeBottom) { _toKeyPointI++; } if (prevFromKeyPointI != _fromKeyPointI || prevToKeyPointI != _toKeyPointI) { _nPolyVertices = 0; float x1 = 0; int keyPoints = _fromKeyPointI; for (int i=_fromKeyPointI; i<_toKeyPointI; i++){ //V0: at (0,0) _polyVertices[_nPolyVertices] = CGPointMake(x1, y1); //first blue point _polyTexCoords[_nPolyVertices++] = CGPointMake(x1, y1); //V1: to the first "point" _polyVertices[_nPolyVertices] = CGPointMake(_hillKeyPoints[keyPoints].x, _hillKeyPoints[keyPoints].y); _polyTexCoords[_nPolyVertices++] = CGPointMake(_hillKeyPoints[keyPoints].x, _hillKeyPoints[keyPoints].y); keyPoints++; //from point at index 0 to 1 //V2, same y as point n°2: _polyVertices[_nPolyVertices] = CGPointMake(0, _hillKeyPoints[keyPoints].y); _polyTexCoords[_nPolyVertices++] = CGPointMake(0, _hillKeyPoints[keyPoints].y); //V1 again _polyVertices[_nPolyVertices] = _polyVertices[_nPolyVertices-2]; _polyTexCoords[_nPolyVertices++] = _polyVertices[_nPolyVertices-2]; //V2 again _polyVertices[_nPolyVertices] = _polyVertices[_nPolyVertices-2]; _polyTexCoords[_nPolyVertices++] = _polyVertices[_nPolyVertices-2]; //CCLOG(@"_nPolyVertices V2 again : %i", _nPolyVertices); //V3 = same x,y as point at index 1 _polyVertices[_nPolyVertices] = CGPointMake(_hillKeyPoints[keyPoints].x, _hillKeyPoints[keyPoints].y); _polyTexCoords[_nPolyVertices] = CGPointMake(_hillKeyPoints[keyPoints].x, _hillKeyPoints[keyPoints].y); y1 = _polyVertices[_nPolyVertices].y; _nPolyVertices++; } prevFromKeyPointI = _fromKeyPointI; prevToKeyPointI = _toKeyPointI; } } - (void) draw { //RED glColor4f(1, 1, 1, 1); for(int i = MAX(_fromKeyPointI, 1); i <= _toKeyPointI; ++i) { glColor4f(1.0, 0, 0, 1.0); ccDrawLine(_hillKeyPoints[i-1], _hillKeyPoints[i]); } //BLUE glColor4f(0, 0, 1, 1); for(int i = 1; i < 2; i++) { CCLOG(@"_polyVertices[i-1].x : %f, _polyVertices[i-1].y : %f", _polyVertices[i-1].x, _polyVertices[i-1].y); CCLOG(@"_polyVertices[i].x : %f, _polyVertices[i].y : %f", _polyVertices[i].x, _polyVertices[i].y); ccDrawLine(_polyVertices[i-1], _polyVertices[i]); } } Thanks

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  • Total newb having SSH tunnel and remote MySQL access problems

    - by kscott
    I don't often work with linux or need to SSH tunnel into remote MySQL databases, so pardon my ignorance. I'm using Windows 7 and am needing to connect to a remote MySQL instance on a Linux server. For months I had been using the HeidiSQL client application successfully. Today two things happened: the DB moved to a new server and I updated HeidiSQL, now I cannot log in to the MySQL server, when attempting I get this message from Heidi: SQL Error (2003) in statement #0: Can't connect to MySQL server on 'localhost' (10061) If I use Putty, I can connect to the server and get MySQL access through command line, including fetching data from the DB. I assume this means my credentials and address are correct, but do not understand why putting those same details into HeidiSQL's SSH tunnel info won't work. I also downloaded the MySQL Workbench and attempted to set up a connection through that client and got this message: Cannot Connect to Database Server Your connection attempt failed for user 'myusername' from your host to server at localhost:3306: Lost connection to MySQL server at 'reading initial communication packet', system error: 0 Please: 1 Check that mysql is running on server localhost 2 Check that mysql is running on port 3306 (note: 3306 is the default, but this can be changed) 3 Check the myusername has rights to connect to localhost from your address (mysql rights define what clients can connect to the server and from which machines) 4 Make sure you are both providing a password if needed and using the correct password for localhost connecting from the host address you're connecting from From Googling around I see that it could be related to the MySQL bind-address, but I am a third party sub-contractor with no access to the MySQL settings of this box and the system admin is assuring me that I'm an idiot and need to figure it out on my end. This is completely possible but I don't know what else to try. Edit 1 - The client settings I am using In Heidi and MySQL Workbench I am using the following: SSH host + port: theHostnameOfTheRemoteServer.com:22 {this is the same host I can Putty to} SSH Username: mySSHusername {the same user name I use for my Putty connection} SSH Password: mySSHpassword {the same password for the Putty connection} Local port: 3307 {this is on the SSH settings tab and was defaulted to 3307 by Heidi, changing it to 3306 gives me a different error: SQL Error (1045) in statement #0: Access denied for user 'mySQLusername'@'localhost' (using password: YES)"} MySQL host: theHostnameOfTheRemoteServer.com {consensus seems to be I should use 'localhost' here} MySQL User: mySQLusername {which I can connect with once in with Putty} MySQL Password: mySQLpassword {which works once in with Putty} Port: 3306

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  • Not able to access other machines on network

    - by TheVillageIdiot
    Hi I'm running Windows 7 Enterprise (32bit) on my laptop. For some time I'm not able to access other machines using \\192.168.xxx.xxx. I've installed VM Ware player on my machine few days back but I don't remember if it happened just after that or there is some other reason behind it. EDIT:- I've disabled VMWare Bridge Protocol but still no effect. Please help me. PS:- I've used both wireless and wired networks. Network sharing is enabled and I can ping other machines but cannot access network shares. I get following message: \\xxx.xxx.xxx.xxx You might not have permission to use this network resource. Contact the administrator of this server to find out if you have acess permissions. The request is not supported. EDIT (2):- Network Discovery, File and Printer Sharing, Folder sharing are all on.

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  • [SOLVED]Need help with remote dekstop - Limit the computers you can access server from

    - by stirredo
    I have a windows server 2003 computer that is accessed by remote desktop connection. To access the server all you need to know is the IP address of the computer. I want to limit the computers that can access the windows server computer to authorized computers only. The authorized computers won't have static IPs, so I cannot limit them on basis of IP address. Can I limit them on basis of MAC id perhaps? I won't mind using third party solution like Teamviewer or Logmein etc. So How can I solve this problem? EDIT: Found a possible solution in team viewer. Team viewer creates a unique partner ID for the computer it is installed on. It has an option for allowing only authorized partner IDs to access the computer. Problem solved.

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  • Will I be abled to access 2nd HDD from dual-boot

    - by Ruben
    I'm planning to have a dual-boot on my computer. I have 2 physical hard drives, one 500GB and one 2TB. What I want to do, is have a dual-boot setup (2 partitions, both 50 GB) for Windows 8 and Windows 7. But will I be able to access the 3rd partition on the disk, or the other disk from both OSs? In this case, it would be really useful to access files and install programs, because I could use them on both OSs, as long as I have the same registry keys.

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  • access VPN machine macosx same subnet

    - by matheszabi
    I would like to access the office machine, which has a fixed IP, and is available only in its local LAN. Let say 192.168.1.100. I have a VPN with username/password connection and I am trying to access the office machine from another location, i.e., another LAN, which has the same subnet: 192.168.1.50. I am using MacOSX 10.8. I have checked the "send all trafic over VPN connection, but I think it looks like it doesn't care and is searching in Local. I do not have admin privileges and can't request to make changes to the network settings in both LANs. Is there any way to connect to the desired remote machine?

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  • Cannot write to registry while installing Microsoft Access 2010 - Error 1406

    - by Rillanon
    While installing I get an error: Microsoft Access 2010 encountered an error during setup. Error 1406. Setup cannot write the value to the registry key \Software\Classes\Interface{000C036F-0000-0000-C000-000000000046}\ProxyStubClsid. Verify that have sufficient permissions to access the registry or contact Microsoft Product Support Services (PSS) for assitance. I went to regedit to check on the key that the error was talking about but when I clicked on it it says file not found. I'm using 64bit Windows 7 Ultimate. Any ideas?

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  • Access denied on file system for System Administrator

    - by NLV
    Hello Yesterday I got win32.Saltiy virus and did some damage before my Kaspersky suite caught it. Now I've cleaned all the viruses using Kaspersky but I believe the changes it did to the registry/policies are still there. I'm not able to have write access on the entire file system. It is showing up the access denied the error. I'm in the local system administrators group. I've tried removing and re-adding it (with a reboot). But still no luck. Any ideas on how can I fix this?

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  • Not able to access other machines on network

    - by TheVillageIdiot
    Hi I'm running Windows 7 Enterprise (32bit) on my laptop. For some time I'm not able to access other machines using \\192.168.xxx.xxx. I've installed VM Ware player on my machine few days back but I don't remember if it happened just after that or there is some other reason behind it. EDIT:- I've disabled VMWare Bridge Protocol but still no effect. Please help me. PS:- I've used both wireless and wired networks. Network sharing is enabled and I can ping other machines but cannot access network shares. I get following message: \\xxx.xxx.xxx.xxx You might not have permission to use this network resource. Contact the administrator of this server to find out if you have acess permissions. The request is not supported. EDIT (2):- Network Discovery, File and Printer Sharing, Folder sharing are all on.

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  • ms access template where to find the vb code

    - by tintincutes
    I'm very new to this ms access 2007. I have a copy of a charitable contribution template charitablecontributions.accdb. I would like to know where I can find the code of it? I opened it by holding down the shift button and double click on it and it will open to a normal ms access where you can modify the table and so. But when I just click the file: charitablecontributions.accdb it will open to a formular view where the ribbon bars are gone. I wanted to know how, how is it possible to have this formular view? Because I have a Test.mdb from 2003 and I also would like it to be open like the formular view of charitablecontributions.accdb. I'll appreciate your help. Thanks

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  • MS Access Query Criteria Issue

    - by xxl3ww
    Currently I have a MS Access database query that has a field named FedEXDetTotal that totals 9 FedEX charge fields. I have another field that is from our inhouse system called "Total Charge". This is just a normal number field. I have created another Field in this query Diff: [FedEXDetTotal]-[Total Charge] This tells me the difference between the Fedex charge and what we actually charged. Everything works OK with this, but when I try to put the criteria 5 for the Diff field, when I run the query, I get a prompt saying "Enter Parameter Value FedEXDetTotal". Why is Access doing this? How do I get around this? I'm trying to start out with something simple(5), but what I really want is [Forms]![Dis].[txtbox_Diff].

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  • ms access template where to find the vb code

    - by tintincute
    Hi I'm very new to this ms access 2007. I have a copy of a charitable contribution template charitablecontributions.accdb. I would like to know where I can find the code of it? I opened it by holding down the shift button and double click on it and it will open to a normal ms access where you can modify the table and so. But when I just click the file: charitablecontributions.accdb it will open to a formular view where the ribbon bars are gone. I wanted to know how, how is it possible to have this formular view? Because I have a Test.mdb from 2003 and I also would like it to be open like the formular view of charitablecontributions.accdb. I'll appreciate your help. Thanks

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  • Write permissions denied on linked tables between MS Access 2003 and 2007

    - by STEVE KING
    We are in the process of switching over to Access 2007. We have numerous data tables in Access 2003 files. In one case, the user has 2007 on his PC and opened the front end in 2007. No problems. When the the user is done, he clicks a button that executes a macro full of update queries. The macro reaches the first query and halts. We get a message saying we do not have permissions to write to this linked table (2003 format). There were no security files involved. We re-linked from 2007, same problem. LAN permssions were ok. I wound up having to import the tables to front end in order for the user to be able to do his job.

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