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Search found 447 results on 18 pages for 'ali bozorgkhan'.

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  • Error occurs when I convert NSMutableArray to NSArray

    - by Ali
    Hi All, I want to convert NSMutableArray to NSArray to it gives error following is code ABAddressBookRef addressBook = ABAddressBookCreate(); CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook); CFIndex nPeople = ABAddressBookGetPersonCount(addressBook); tempPeoples=[[NSMutableArray alloc]init]; for(int i=0;i<nPeople;i++){ ABRecordRef i1=CFArrayGetValueAtIndex(allPeople, i); [tempPeoples addObject:i1]; // [peoples addObject:i1]; }// end of the for loop // Peoples is NSArray // peoples=[[NSArray alloc] initWithArray: tempPeoples]; peoples=[NSArray arrayWithArray:tempPeoples]; Please help

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  • Grails unit testing domain classes with Set properties - is this safe?

    - by Ali G
    I've created a domain class in Grails like this: class MyObject { static hasMany = [tags: String] // Have to declare this here, as nullable constraint does not seem to be honoured Set tags = new HashSet() static constraints = { tags(nullable: false) } } Writing unit tests to check the size and content of the MyObject.tags property, I found I had to do the following: assertLength(x, myObject.tags as Object[]) assertEquals(new HashSet([...]), myObject.tags) To make the syntax nicer for writing the tests, I implemented the following methods: void assertEquals(List expected, Set actual) { assertEquals(new HashSet(expected), actual) } void assertLength(int expected, Set set) { assertLength(expected, set as Object[]) } I can now call the assertLength() and assertEquals() methods directly on an instance of Set, e.g. assertLength(x, myObject.tags) assertEquals([...], myObject.tags) I'm new to Groovy and Grails, so unaware how dangerous method overloading like this is. Is it safe? If so, I'm slightly* surprised that these methods (or similar) aren't already available - please let me know if they are. * I can see how these methods could also introduce ambiguity if people weren't expecting them. E.g. assertLength(1, set) always passes, no matter what the content of set

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  • map is not showing correct location in my blackberry applications

    - by Ali
    I am calling blackberry map by converting the real coordinates as you can see public static void showMap(String latitude,String longatude){ try{ int specailLatitude=(int)(Double.parseDouble(latitude))*100000; int specailLongatude=(int)(Double.parseDouble(longatude))*100000; MapView mapView=new MapView(); mapView.setLatitude(specailLatitude); mapView.setLongitude(specailLongatude); mapView.setZoom(07); MapsArguments arg=new MapsArguments(mapView); Invoke.invokeApplication(Invoke.APP_TYPE_MAPS, arg); }catch(Exception e){ CustomUtility.showToast("Map is not available "+e.getMessage()); } }// end of the showMap but problem is this its now showing correct location , it always shows same location in UAE , please help that i am converting correctly ?

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  • How to show login screen only for the first time when app launches

    - by Jaw Ali
    I want to launch the login screen when first time app launches other wise app work simple but problem is that again again it goes to login screen. here is the code which i am using in didFininsh I want the user show go to login screen first time only and next time it should show splitViewController [[NSUserDefaults standardUserDefaults] registerDefaults:[NSDictionary dictionaryWithObjectsAndKeys:[NSNumber numberWithBool:YES],@"firstLaunch",nil]]; if ([[NSUserDefaults standardUserDefaults] boolForKey:@"firstLaunch"]) { [self.window addSubview:[splitViewController view]]; LoginViewController *targetController = [[LoginViewController alloc] initWithNibName:@"LoginViewController" bundle:nil]; targetController.modalPresentationStyle = UIModalPresentationFullScreen; [self.splitViewController presentViewController:targetController animated:YES completion:nil]; } else { [self.window addSubview:[splitViewController view]]; } // my comment[window addSubview:splitViewController.view]; [window makeKeyAndVisible]; return YES;

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  • .ico icons not showing up on Windows

    - by Ali
    I followed the The Qt Resource System guide and the .ico icons appear on Linux. The icons are not showing up on Windows when I try to run the applicaton from Qt Creator. I suspect a plugin issue based on Qt/C++: Icons not showing up when program is run under windows O.S but I failed to figure out what to do from the guide How to Create Qt Plugins. Is it a plugin issue or why aren't the icons showing up on Windows? If it is a plugin issue: How do I tell my applicaton where to find the qico.dll? Details of the environment: Works on: Kubuntu 12.04 LTS, Qt Creator 2.4.1 and Qt 4.7.4 (64 bit) Fails on: Windows XP SP2 32 bit, Qt Creator 2.4.1 and Qt 4.7.4 (32 bit) Everyting is at its default (as installed out of the box), I did not mess with the settings. resources.qrc <!DOCTYPE RCC><RCC version="1.0"> <qresource> <file>images/spreadsheet.ico</file> </qresource> </RCC> Also tried with <qresource prefix="/">. From the applicaton.pro RESOURCES += \ resources.qrc OTHER_FILES += \ images/spreadsheet.ico In the corresponding source file QIcon(":/images/spreadsheet.ico") I repeat: it works on Linux.

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  • #1146 - Table 'phpmyadmin.pma_recent' doesn't exist

    - by Mumin Ali
    Solution Guys... FYI i am using xampp to use phpmyadmin. and this error happens during the process of creating a database on localhost. Below is the code for config.inc file under phpmyadmin directory: <?php /* * This is needed for cookie based authentication to encrypt password in * cookie */ $cfg['blowfish_secret'] = 'xampp'; /* YOU SHOULD CHANGE THIS FOR A MORE SECURE COOKIE AUTH! */ /* * Servers configuration */ $i = 0; /* * First server */ $i++; /* Authentication type and info */ $cfg['Servers'][$i]['auth_type'] = 'HTTP'; $cfg['Servers'][$i]['user'] = 'root'; $cfg['Servers'][$i]['password'] = 'password'; $cfg['Servers'][$i]['extension'] = 'mysql'; $cfg['Servers'][$i]['AllowNoPassword'] = true; $cfg['Lang'] = ''; /* Bind to the localhost ipv4 address and tcp */ $cfg['Servers'][$i]['host'] = 'localhost'; $cfg['Servers'][$i]['connect_type'] = 'tcp'; /* User for advanced features */ $cfg['Servers'][$i]['controluser'] = 'pma'; $cfg['Servers'][$i]['controlpass'] = ''; /* Advanced phpMyAdmin features */ $cfg['Servers'][$i]['pmadb'] = 'phpmyadmin'; $cfg['Servers'][$i]['bookmarktable'] = 'pma_bookmark'; $cfg['Servers'][$i]['relation'] = 'pma_relation'; $cfg['Servers'][$i]['table_info'] = 'pma_table_info'; $cfg['Servers'][$i]['table_coords'] = 'pma_table_coords'; $cfg['Servers'][$i]['pdf_pages'] = 'pma_pdf_pages'; $cfg['Servers'][$i]['column_info'] = 'pma_column_info'; $cfg['Servers'][$i]['history'] = 'pma_history'; $cfg['Servers'][$i]['designer_coords'] = 'pma_designer_coords'; $cfg['Servers'][$i]['tracking'] = 'pma_tracking'; $cfg['Servers'][$i]['userconfig'] = 'pma_userconfig'; $cfg['Servers'][$i]['recent'] = 'pma_recent'; $cfg['Servers'][$i]['table_uiprefs'] = 'pma_table_uiprefs'; /* * End of servers configuration */ ?>

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  • Php code not executing - dies out when trying to refer to member of static class - no error displaye

    - by Ali
    I'm having some problems with this piece of code. I've included a class declaration and trying to create an object of that class but my code dies out. It doesn't seem to be an include issue as all the files are being included even the files called for inclusion within the class file itself. However the object is not created - I tried to put an echo statement in the __construct function but nothing it just doesn't run infact doesn't create the object and the code won't continue from there - plus no error is reported or displayed and I have error reporting set to E_ALL and display errors set to true WHats happening here :( =============EDIT SOrry I checked again the error is prior to teh object creation thing - it dies out when it tries to refer to a constant in a static class like so: $v = Zend_Oauth::REQUEST_SCHEME_HEADER; THis is the class or part of it - it has largely static functions its the Zend Oauth class: class Zend_Oauth { const REQUEST_SCHEME_HEADER = 'header'; const REQUEST_SCHEME_POSTBODY = 'postbody'; const REQUEST_SCHEME_QUERYSTRING = 'querystring'; // continued LIke I said no error is being reported at all :(

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  • C# Type conversion between two similar Datatable objects

    - by Ali
    I have .NET project with sync framework and two separate Datasets for MS SQL and Compact SQL. in my base class I have a generic DataTable object. in my derived classed I assign Typed DataTable to the generic object based on whether the application is operating online or offline: example: if (online) _dataTable = new MSSQLDataSet.Customer; else _dataTable = new CompactSQLDataSet.Customer; Now every where in my code i have to check and do a cast based on the current network mode like this: public void changeCustomerID(int ID) { if (online) (MSSQLDataSet.CustomerDataTable)_dataTable)[i].CustomerID = value; else (CompactMSSQLDataSet.CustomerDataTable)_dataTable)[i].CustomerID = value; } but I don't think this is very efficient and I believe it can be done in a smarter way to only use one line of code by dynamically getting the Type of _dataTable on the run time. my problem is at the design time, in order to acess datatable porperties such as "CustomerID" it has to be casted to either MSSQLDataSet.CustomerDataTable or CompactMSSQLDataSet.CustomerDataTable. Is there a way to have a function or a operator to convert the _datatable to its runtime type but still be able to use it's design time properties which are the same between the two types? something like: ((aType)_dataTable)[i].CustomerID = value; //or GetRuntimeType(_dataTable)[i].CustomerID = value;

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  • getting another website data to manipulate it's value in perl

    - by aun ali
    use CGI qw(:standard); use CGI::Carp qw(fatalsToBrowser warningsToBrowser); our @a=param(src="http://fxrates.forexpros.com/index.php?pairs_ids=1525=last_update"); print header(),start_html('results.pl'); $a=http://fxrates.forexpros.com/index.php?pairs_ids=1525=last_update; '<iframe frameborder="0" scrolling="no" height="95" width="213" allowtransparency="true" marginwidth="0" marginheight="0" src="http://fxrates.forexpros.com/index.php?pairs_ids=1525;&header-text-color=%23FFFFFF&curr-name-color=%230059b0&inner-text-color=%23000000&green-text-color=%232A8215&green-background=%23B7F4C2&red-text-color=%23DC0001&red-background=%23FFE2E2&inner-border-color=%23CBCBCB&border-color=%23cbcbcb&bg1=%23F6F6F6&bg2=%23ffffff&bid=hide&ask=hide&last=hide&high=hide&low=hide&change=hide&change_in_percents=hide&last_update=show"></iframe><br /><div style="width:213"><span style="float:left"><span style="font-size: 11px;color: #333333;text-decoration: none;">The <a href="http://www.forexpros.com/quotes" target="_blank" style="font-size: 11px;color: #06529D; font-weight: bold;" class="underline_link">Forex Quotes</a> are Powered by Forexpros - The Leading Financial Portal.</span></span></div>'; print '<br/>'; print "$a"; print end_html();' getting error: Can't modify constant item in scalar assignment at livedata.pl line 4, near ""http://fxrates.forexpros.com/index.php?pairs_ids=1525=last_update")" syntax error at livedata.pl line 6, near "http:" Execution of livedata.pl aborted due to compilation errors.

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  • UIFileSharingEnabled use folders

    - by Ali Shafai
    I want to allow users add files to the application document folder, so I used the iTunes file sharing. The problem is they can only add single files with a flat structure. I want to drag and drop whole folder (even with sub folders) and keep the structure. Questions I have: is it possible with iTunes file sharing? if not, is there an open source project that helps me with writing a pc side app that talks to the iPhone side app and pushes the files into it?

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  • Does my function right on python?

    - by Ali Ismayilov
    Write a function which takes a string argument, and creates and returns an Employee object containing details of the employee specified by the string. The string should be assumed to have the format 12345 25000 Consultant Bart Simpson The first three items in the line will be the payroll number, salary and job title and the rest of the line will be the name. There will be no spaces in the job title but there may be one or more spaces in the name. My function: def __str__(self): return format(self.payroll, "d") + format(self.salary, "d") + ' ' \ + self.jobtitle + self.name

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  • Query executes with no error but not in trigger

    - by liaqat ali
    I am facing a strange problem in creating trigger in MS SQL. I have a query that executes with out an error but when I place it within trigger body, it gives error Invalid column name 'ScreenName'. I am placing whole trigger code here. Please trace the issue. CREATE TRIGGER [dbo].[tr_tbFieldLabels_FieldLabelLength] ON [dbo].[tbFieldLabels] AFTER INSERT AS Update tbFieldLabels Set TextBoxLength = (SELECT top 1 TextboxLength FROM tbFieldLabelsSource FLS WHERE FLS.ScreenName = Inserted.ScreenName AND tbFieldLabelsSource.SystemName = Inserted.SystemName) FROM tbFieldLabels , Inserted WHERE tbFieldLabels.ID = Inserted.ID GO Please help me ASAP.

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  • PHP class_exists always returns true

    - by Ali
    I have a PHP class that needs some pre-defined globals before the file is included: File: includes/Product.inc.php if (class_exists('Product')) { return; } // This class requires some predefined globals if ( !isset($gLogger) || !isset($db) || !isset($glob) ) { return; } class Product { ... } The above is included in other PHP files that need to use Product using require_once. Anyone who wants to use Product must however ensure those globals are available, at least that's the idea. I recently debugged an issue in a function within the Product class which was caused because $gLogger was null. The code requiring the above Product.inc.php had not bothered to create the $gLogger. So The question is how was this class ever included if $gLogger was null? I tried to debug the code (xdebug in NetBeans), put a breakpoint at the start of Product.inc.php to find out and every time it came to the if (class_exists('Product')) clause it would simply step in and return thus never getting to the global checks. So how was it ever included the first time? This is PHP 5.1+ running under MAMP (Apache/MySQL). I don't have any auto loaders defined.

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  • Angularjs throws TypeError: Cannot read property 'indexOf' of undefined

    - by Ali
    I'm trying to debug the above code which I feel like this is very useful .< I can't even find what is wrong in my code and don't really know where to start since Angularjs still very new to me. I'm trying to localize Angularjs app. I know this is missing a lot of context in order to get a help, but I'm trying to see what information that I should give that would help on this debugging. I've gone through any indexOf in angularjs file and I can see few things is undefined but don't know if that would be helpful. So I've traced the problem here and this is what I have figured is the problem, but still counldn't figure out why... config(['$routeProvider', '$locationProvider', function ($routeProvider, $locationProvider) { $routeProvider.when('/:locale?/:username/badges', { templateUrl: '_partials/badges.html', controller: 'badges' }) .when('/:username/badges', { templateUrl: '_partials/badges.html', controller: 'badges' }) .when('/:username/teaching-resources', { templateUrl: '_partials/teaching-resources.html', controller: 'teachingResources' }) .when('/:username/makes', { templateUrl: '_partials/makes.html', controller: 'makes' }) .when('/:username/likes', { templateUrl: '_partials/likes.html', controller: 'likes' }) .when('/:username/events', { templateUrl: '_partials/events.html', controller: 'events' }) .when('/:username', { templateUrl: '_partials/badges.html', controller: 'badges' }); $routeProvider.otherwise({ redirectTo: '/error/404' }); The URL that I'm visiting for default page is: This will fail and throw the error. http://localhost:1969/en-US/user/someUserName This will work fine http://localhost:1969/user/someUserName UPDATE I figured out! This is the problem: $locationProvider.html5Mode(true); But why!?

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  • Call static properties within another class in php

    - by ali A
    I have problem about calling a static property of a class inside another class. Class A { public $property; public function __construct( $prop ) { $this->property = $prop; } public function returnValue(){ return static::$this->property; } } Class B extends A { public static $property_one = 'This is first property'; public static $property_two = 'This is second property'; } $B = new B( 'property_one' ); $B->returnValue(); I expect to return This is first property But the Output is just the name a parameter input in __construct; When I print_r( static::$this->property ); the output is just property_one

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  • Annonymous functions accessing local variables [ActionScript - Flex 3.5]

    - by Ali
    Hi All, I am having a situation with my actionscript/flex front end. for each (var sym:String in ["A","B","C"]) { const handler = function (data:Object):void { Alert.show(sym); } asyncCallback(handler); } I am expecting to have 3 Alert windows containing A, B and C. But the actual result is 3 alert windows all showing C ! I appreciate your comments. -A

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  • not able to draw image on canvas of surface view in Android

    - by Fayaz Ali
    I am drawing an image using drawbitmap method on a canvas of surface view which is an overlay surface on my camera preview.The image drawn is a portion of captured image to guide the user to capture next image with a proper overlap.Now when I am launching the activity as the application start activity i.e it is my first activity,it works fine and draws the image.But when I launch the same activity from some other activity,the surface view is not show anything. Is there any difference between launching an activity from another activity and from the application launch. Anyone help here please!

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  • Binary Search Tree can't delete the root

    - by Ali Zahr
    Everything is working fine in this function, but the problem is that I can't delete the root, I couldn't figure out what's the bug here.I've traced the "else part" it works fine until the return, it returns the old value I don't know why. Plz Help! node *removeNode(node *Root, int key) { node *tmp = new node; if(key > Root->value) Root->right = removeNode(Root->right,key); else if(key < Root->value) Root->left = removeNode(Root->left, key); else if(Root->left != NULL && Root->right != NULL) { node *minNode = findNode(Root->right); Root->value = minNode->value; Root->right = removeNode(Root->right,Root->value); } else { tmp = Root; if(Root->left == NULL) Root = Root->right; else if(Root->right == NULL) Root = Root->left; delete tmp; } return Root; }

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  • Getting visitors country from their IP

    - by Ali Abdulkarim Salem
    i want to get visitors country via their IP.. right now I'm using this ( http://api.hostip.info/country.php?ip=...... ) here's my code <?php if (isset($_SERVER['HTTP_CLIENT_IP'])) { $real_ip_adress = $_SERVER['HTTP_CLIENT_IP']; } if (isset($_SERVER['HTTP_X_FORWARDED_FOR'])) { $real_ip_adress = $_SERVER['HTTP_X_FORWARDED_FOR']; } else { $real_ip_adress = $_SERVER['REMOTE_ADDR']; } $cip = $real_ip_adress; $iptolocation = 'http://api.hostip.info/country.php?ip=' . $cip; $creatorlocation = file_get_contents($iptolocation); ?> Well, it's working properly, but the thing is, this returns the country code like US or CA., and not the whole country name like United States or Canada So, is there any good alternative to hostip.info offers this? I know that I can just write some code that will eventually turn this two letters to whole country name, but I'm just too lazy to write a code that contains all countries... P.S: For some reason I don't want to use any ready made CSV file or any code that will grab this information for me, something like ip2country ready made code and CSV.

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  • information hiding in python

    - by ali
    in python tutorial added that python cannot hide its attributes from other classes. some thing such as private data in C++ or java..But also i know that we can use _ or __ to set some variables as privated one but it is not enogh. I think it is a week if it is not any thing to do it.

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