Search Results

Search found 5493 results on 220 pages for 'boost regex'.

Page 16/220 | < Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23 | Next Page >

How to create a simple server/client application using boost.asio?

- by the_drow

I was going over the examples of boost.asio and I am wondering why there isn't an example of a simple server/client example that prints a string on the server and then returns a response to the client. I tried to modify the echo server but I can't really figure out what I'm doing at all. Can anyone find me a template of a client and a template of a server? I would like to eventually create a server/client application that receives binary data and just returns an acknowledgment back to the client that the data is received.

Read the article
Using Boost statechart, how can I transition to a state unconditionally?

- by nickb

I have a state A that I would like to transition to its next state B unconditionally, once the constructor of A has completed. Is this possible? I tried posting an event from the constructor, which does not work, even though it compiles. Thanks. Edit: Here is what I've tried so far: struct A : sc::simple_state< A, Active > { public: typedef sc::custom_reaction< EventDoneA > reactions; A() { std::cout << "Inside of A()" << std::endl; post_event( EventDoneA() ); } sc::result react( const EventDoneA & ) { return transit< B >(); } }; This yields the following runtime assertion failure: Assertion failed: get_pointer( pContext_ ) != 0, file /includ e/boost/statechart/simple_state.hpp, line 459

Read the article
Boost in Visual Studio 2010, IntelliSense error

- by Peretz

Hello, I would like to see if you could orient me. It happens that I compiled and referenced the boost libraries in order to use them with Visual Studio 2010. When building my test project I get these two IntelliSense errors 1 IntelliSense: #error directive: "Macro BOOST_LIB_NAME not set (internal error)" c:\boost_1_43_0\boost\config\auto_link.hpp 2 IntelliSense: #error directive: "some required macros where not defined (internal logic error)." c:\boost_1_43_0\boost\config\auto_link.hpp Checking the auto_link.hpp header file the first error is in this line #ifndef BOOST_LIB_NAME # error "Macro BOOST_LIB_NAME not set (internal error)" #endif Tracing the definition of BOOST_LIB_NAME, it seems that is defined in config.hpp by boost_regex, which code I am including below #if !defined(BOOST_REGEX_NO_LIB) && !defined(BOOST_REGEX_SOURCE) && !defined(BOOST_ALL_NO_LIB) && defined(__cplusplus) # define BOOST_LIB_NAME boost_regex # if defined(BOOST_REGEX_DYN_LINK) || defined(BOOST_ALL_DYN_LINK) # define BOOST_DYN_LINK ... more code and strangely when I point to BOOST_LIB_NAME it defines BOOST_LIB_NAME and the IntelliSense errors disappear. My program builds and executes fine using the Boost:Regex library -- with or without the Intellisense errors; however, I do not understand why these IntelliSense errors appear in the first place, and second why pointing the macro in the config.hpp defines BOOST_LIB_NAME. Any guidance will be greatly appreciated. Thanks, Jaime

Read the article
boost::lambda bind expressions can't get bind to string's empty() to work

- by navigator

Hi, I am trying to get the below code snippet to compile. But it fails with: error C2665: 'boost::lambda::function_adaptor::apply' : none of the 8 overloads could convert all the argument types. Sepcifying the return type when calling bind does not help. Any idea what I am doing wrong? Thanks. #include <boost/lambda/lambda.hpp> #include <boost/lambda/bind.hpp> #include <string> #include <map> int main() { namespace bl = boost::lambda; typedef std::map<int, std::string> types; types keys_and_values; keys_and_values[ 0 ] = "zero"; keys_and_values[ 1 ] = "one"; keys_and_values[ 2 ] = "Two"; std::for_each( keys_and_values.begin(), keys_and_values.end(), std::cout << bl::constant("Value empty?: ") << std::boolalpha << bl::bind(&std::string::empty, bl::bind(&types::value_type::second, _1)) << "\n"); return 0; }

Read the article
getting boost::gregorian dates from a string

- by Chris H

I asked a related question yesterday http://stackoverflow.com/questions/2612343/basic-boost-date-time-input-format-question It worked great for posix_time ptime objects. I'm have trouble adapting it to get Gregorian date objects. try { stringstream ss; ss << dateNode->GetText(); using boost::local_time::local_time_input_facet; //using boost::gregorian; ss.imbue(locale(locale::classic(), new local_time_input_facet("%a, %d %b %Y "))); ss.exceptions(ios::failbit); ss>>dayTime; } catch (...) { cout<<"Failed to get a date..."<<endl; //cout<<e.what()<<endl; throw; } The dateNode-GetText() function returns a pointer to a string of the form Sat, 10 Apr 2010 19:30:00 The problem is I keep getting an exception. So concretely the question is, how do I go from const char * of the given format, to a boost::gregorian::date object? Thanks again.

Read the article
Mac OS X and static boost libs -> std::string fail

- by Ionic

Hi all, I'm experiencing some very weird problems with static boost libraries under Mac OS X 10.6.6. The error message is main(78485) malloc: *** error for object 0x1000e0b20: pointer being freed was not allocated *** set a breakpoint in malloc_error_break to debug [1] 78485 abort (core dumped) and a tiny bit of example code which will trigger this problem: #define BOOST_FILESYSTEM_VERSION 3 #include <boost/filesystem.hpp> #include <iostream> int main (int argc, char **argv) { std::cout << boost::filesystem::current_path ().string () << '\n'; } This problem always occurs when linking the static boost libraries into the binary. Linking dynamically will work fine, though. I've seen various reports for quite a similar OS X bug with GCC 4.2 and the _GLIBCXX_DEBUG macro set, but this one seems even more generic, as I'm neither using XCode, nor setting the macro (even undefining it does not help. I tried it just to make sure it's really not related to this problem.) Does anybody have any pointers to why this is happening or even maybe a solution (rather than using the dynamic library workaround)? Best regards, Mihai

Read the article
Boost Asio UDP retrieve last packet in socket buffer

- by Alberto Toglia

I have been messing around Boost Asio for some days now but I got stuck with this weird behavior. Please let me explain. Computer A is sending continuos udp packets every 500 ms to computer B, computer B desires to read A's packets with it own velocity but only wants A's last packet, obviously the most updated one. It has come to my attention that when I do a: mSocket.receive_from(boost::asio::buffer(mBuffer), mEndPoint); I can get OLD packets that were not processed (almost everytime). Does this make any sense? A friend of mine told me that sockets maintain a buffer of packets and therefore If I read with a lower frequency than the sender this could happen. ¡? So, the first question is how is it possible to receive the last packet and discard the ones I missed? Later I tried using the async example of the Boost documentation but found it did not do what I wanted. http://www.boost.org/doc/libs/1_36_0/doc/html/boost_asio/tutorial/tutdaytime6.html From what I could tell the async_receive_from should call the method "handle_receive" when a packet arrives, and that works for the first packet after the service was "run". If I wanted to keep listening the port I should call the async_receive_from again in the handle code. right? BUT what I found is that I start an infinite loop, it doesn't wait till the next packet, it just enters "handle_receive" again and again. I'm not doing a server application, a lot of things are going on (its a game), so my second question is, do I have to use threads to use the async receive method properly, is there some example with threads and async receive? Thanks for you attention.

Read the article
Increasing time resolution of BOOST::progress timer

- by feelfree

BOOST::progress_timer is a very useful class to measure the running time of a function. However, the default implementation of progress_timer is not accurate enough and a possible way of increasing time resolution is to reconstruct a new class as the following codes show: #include <boost/progress.hpp> #include <boost/static_assert.hpp> template<int N=2> class new_progress_timer:public boost::timer { public: new_progress_timer(std::ostream &os=std::cout):m_os(os) { BOOST_STATIC_ASSERT(N>=0 &&N<=10); } ~new_progress_timer(void) { try { std::istream::fmtflags old_flags = m_os.setf(std::istream::fixed,std::istream::floatfield); std::streamsize old_prec = m_os.precision(N); m_os<<elapsed()<<"s\n" <<std::endl; m_os.flags(old_flags); m_os.precison(old_prec); } catch(...) { } } private: std::ostream &m_os; }; However, when I compile the codes with VC10, the following error appear: 'precison' : is not a member of 'std::basic_ostream<_Elem,_Traits>' Any ideas? Thanks.

Read the article
C++ member template for boost ptr_vector

- by Ivan

Hi there, I'm trying to write a container class using boost::ptr_vector. Inside the ptr_vector I would like to include different classes. I'm trying to achieve that using static templates, but so far I'm not able to do that. For example, the container class is class model { private: boost::ptr_vector<elem_type> elements; public: void insert_element(elem_type *a) { element_list.push_back(a); } }; and what I'm trying to achieve is be able to use different elem_type classes. The code below doesn't satisfy my requirements: template <typename T>class model { private: boost::ptr_vector<T> elements; public: void insert_element(T *a) { element_list.push_back(a); } }; because when I initialize the container class I can only use one class as template: model <elem_type_1> model_thing; model_thing.insert_element(new elem_type_1) but not elem_type_2: model_thing.insert_element(new elem_type_2)//error, of course It is possible to do something like using templates only on the member? class model { private: template <typename T> boost::ptr_vector<T> elements; public: void insert_element(T *a) { element_list.push_back(a); } }; //wrong So I can call the insert_element on the specific class that I want to insert? Note that I do not want to use virtual members. Thanks!

Read the article
Vim: how to undo a regex with a new regex?

- by Victor Tihomirov

my I have here a text that has been encrypted in Vi this way: 1,$s/\(.\)\1/&&/g 1,$s/\(.\)\(.\)\2\2\2/\2\2\2\1\2/g 1,$s/\(.\)\(.\)\(.\)\(.\)/\3\1\4\2/g 1,$s/\(...\)\(...\)/\2\1/g The task is to write a new regex for each regex in order to undo the the changes, so-called decrypting of the text. I figured out how to undo the last 2 changes: :1,$s/\(...\)\(...\)/\2\1/g :1,$s/\(.\)\(.\)\(.\)\(.\)/\2\4\1\3/g I'd like you to explain me what do the first two regex do. What does \1 or \2\2\2 mean before the forward slash? I assume that after the slash they change place (but wouldn't it be enough to just write \2\1 instead of \2\2\2\1\2(what does it mean?)? I just don't get it). And what does & or && mean? Thank you

Read the article
codingBat plusOut using regex

- by polygenelubricants

This is similar to my previous efforts (wordEnds and repeatEnd): as a mental exercise, I want to solve this toy problem using regex only. Description from codingbat.com: Given a string and a non-empty word string, return a version of the original string where all chars have been replaced by pluses ("+"), except for appearances of the word string which are preserved unchanged. plusOut("12xy34", "xy") ? "++xy++" plusOut("12xy34", "1") ? "1+++++" plusOut("12xy34xyabcxy", "xy") ? "++xy++xy+++xy" There is no mention whether or not to allow overlap (e.g. what is plusOut("+xAxAx+", "xAx")?), but my non-regex solution doesn't handle overlap and it passes, so I guess we can assume non-overlapping occurrences of word if it makes it simpler. In any case, I'd like to solve this using regex (of the same style that I did before with the other two problems), but I'm absolutely stumped. I don't even have anything to show, because I have nothing that works. So let's see what the stackoverflow community comes up with.

Read the article
Isolate SQL field using regex

- by Das123

I'm trying to isolate a specific field in a SQL dump file so I can edit it but I'm not having any luck. The regex I'm using is: ^(?:(?:'[^\r\n']*'|[^,\r\n]*),){6}('[^\r\n']*'|[^,\r\n]*) Which is supposed to grab the seventh field and place it inside reference 1. The trouble is that this is stumbling when ever it finds a comma inside a text field and counts the partial match as the allowable matches. Eg. (1, 'Title', 1, 3, '2006-09-29', 'Commas, the bane of my regex', 'This is the target', 2, 4) matches " the bane of my regex'" instead of "'This is the target'".

Read the article
Regex for capturing numbered text list

- by crunchyt

I have a test list that I am trying to capture data from using a regex. Here is a sample of the text format: (1) this is a sample string /(2) something strange /(3) another bit of text /(4) the last one/ something!/ I have a Regex that currently captures this correctly, but I am having some difficulty with making it work under outlier conditions. Here is my regex /\(?\d\d?\)([^\)]+)(\/|\z)/ Unfortunately some of the data contains parentheses like this: (1) this is a sample string (1998-1999) /(2) something strange (blah) /(3) another bit of text /(4) the last one/ something!/ The substrings '(1998-1999)' and '(blah)' make it fail! Anyone care to have a crack at this one? Thank you :D

Read the article
bash rename using regex array substitution

- by mulllhausen

hi, i have a very similar question as for this post. i would like to know how to rename occurances within a filename with designated substitutions. for example if the original file is called: 'the quick brown quick brown fox.avi' i would like to rename it to 'the slow red slow red fox.avi'. i tried this: new="(quick=>'slow',brown=>'red')" regex="quick|brown" rename -v "s/($regex)/$new{$1}/g" * but no love :( i also tried with regex="qr/quick|brown/" but this just gives errors. any idea what im doing wrong?

Read the article
Regex to extract link

- by Derin

Hi, I'm looking for a regex to extract links from a url. The url would be as below: /redirecturl?u=http://www.abc.com/&tkn=Ue4uhv&ui=fWrQfyg46CADA&scr=SSTYQFjAA&mk=4D6GHGLfbQwETR I need to extract the link http://www.abc.com from the above url. I tried the regex: redirecturl\\?u=(?<link>[^\"]+)& This works, but the problem is that it does not truncate all the characters after the first occurrence of &. It would be great if you could modify the regex so that I just get the link. Thanks in advance.

Read the article
Problems with matching emails with regex

- by Gandalf StormCrow

Hello, I'm trying to match an email address here is what I've come up with so far : String text = "[email protected]"; String regex = "(\\w+)@{1}(\\w+){2,}\\.{1}\\w{2,4}"; This however works with following cases : [email protected] [email protected] [email protected] So it matches any alphanumeric character repeated once or more that comes before one @ followed by any alphanumeric character repeated at least two times(which is minimal characters for any domain name) followed by one .(dot) and followed by any alphanumeric character repeated at least 2 times and at most 4 times(because there are domains such as .us or .mobi). This expression however does not work with emails such as : [email protected] [email protected] [email protected] [email protected] etc as many subdomains or [email protected] [email protected] [email protected] [email protected] I've just started to learn regex and I found interesting to try to solve problems such as these by using regex .. not partially but for each case, any help would be much appriciated. Thank you

Read the article
Match multiline regex in file object

- by williamx

How can I extract the groups from this regex from a file object (data.txt)? import numpy as np import re import os ifile = open("data.txt",'r') # Regex pattern pattern = re.compile(r""" ^Time:(\d{2}:\d{2}:\d{2}) # Time: 12:34:56 at beginning of line \r{2} # Two carriage return \D+ # 1 or more non-digits storeU=(\d+\.\d+) \s uIx=(\d+) \s storeI=(-?\d+.\d+) \s iIx=(\d+) \s avgCI=(-?\d+.\d+) """, re.VERBOSE | re.MULTILINE) time = []; for line in ifile: match = re.search(pattern, line) if match: time.append(match.group(1)) The problem in the last part of the code, is that I iterate line by line, which obviously doesn't work with multiline regex. I have tried to use pattern.finditer(ifile) like this: for match in pattern.finditer(ifile): print match ... just to see if it works, but the finditer method requires a string or buffer. I have also tried this method, but can't get it to work matches = [m.groups() for m in pattern.finditer(ifile)] Any idea?

Read the article
Regex to match the first file in a rar archive file set in Python

- by mridang

I need to uncompress all the files in a directory and for this I need to find the first file in the set. I'm currently doing this using a bunch of if statements and loops. Can i do this this using regex? Here's a list of files that i need to match: yes.rar yes.part1.rar yes.part01.rar yes.part001.rar yes.r01 yes.r001 These should NOT be matched: no.part2.rar no.part02.rar no.part002.rar no.part011.rar no.r002 no.r02 I found a similar regex on this thread but it seems that Python doesn't support varible length lookarounds. A single line regex would be complicated but I'll document it well and it's not a problem. It's just one of those problems you beat your heap up, over. Thanks in advance guys. :)

Read the article
regex : how to eliminiate urls ending with .dtd

- by dorelal

This is JavaScript regex. regex = /(http:\/\/[^\s]*)/g; text = "I have http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd and I like http://google.com a lot"; matches = text.match(regex); console.log(matches); I get both the urls in the result. However I want to eliminate all the urls ending with .dtd . How do I do that? Note that I am saying ending with .dtd should be removed. It means a url like http://a.dtd.google.com should pass .

Read the article
Regex pattern problem in python

- by mridang

I need to extract parts of a string using regex in Python. I'm good with basic regex but I'm terrible at lookarounds. I've shown two sample records below. The last big is always a currency field e.g. in the first one it is 4,76. In the second one it is 2,00. The second has an account number that is the pattern of \d{6}-\d{6}. Anything after that is the currency. 24.02 24.02VALINTATALO MEGAHERTSI4,76- 24.02 24.02DOE MRIDANG 157235-1234582,00- Could you help me out with this regex? What I've written so far is given below but it considers everything after the 'dash' in the account number to be the currency. .*?(\d\d\.\d\d)(.*?)\s*(?<!\d{6}-\d{6})(\d*,\d\d) Thanks in advance

Read the article
codingBat last2 using regex

- by polygenelubricants

Okay guys, this is similar to my repeatEnd and wordEnds efforts; I want to solve this codingBat Warmup-2 question using only regex-based techniques as a "brain gymnastics" exercise. This solution works for codingBat tests: public int last2(String str) { return str.isEmpty() ? 0 : str.split( str.replaceAll( ".*(.)(.)", "$1(?=$2)" //.replaceAll("(\\$.)", "\\\\\\\\Q$1\\\\\\\\E") ), -1 ).length - 1 - 1; } The monstrous octo-slashes aren't needed to pass codingBat, but is needed for a proper regex-based solution. That is, if I want this (and I do!): assert last2("..+++...++") == 2; I'd have to uncomment the second .replaceAll. I'm just wondering if others can come up with a simpler, more elegant regex solution for this problem. Preferably one that doesn't contain octo-slashes.

Read the article
C# Find and Replace RegEx question

- by fraXis

Hello, I am starting to get a grip on RegEx thanks to all the great help here on SO with my other questions. But I am still suck on this one: My code is: StreamReader reader = new StreamReader(fDialog.FileName.ToString()); string content = reader.ReadToEnd(); reader.Close(); I am reading in a text file and I want to search for this text and change it (the X and Y value always follow each other in my text file): X17.8Y-1. But this text can also be X16.1Y2.3 (the values will always be different after X and Y) I want to change it to this X17.8Y-1.G54 or X(value)Y(value)G54 My RegEx statement follows but it is not working. content = Regex.Replace(content, @"(X(?:\d*\.)?\d+)*(Y(?:\d*\.)?\d+)", "$1$2G54"); Can someone please modify it for me so it works and will search for X(wildcard) Y(Wildcard) and replace it with X(value)Y(value)G54? Thanks, Shawn

Read the article
Regex for tollfree numbers in java

- by arinte

I have this regex to test for telephone # that should be a toll free. public static final Pattern patternTollFree = Pattern.compile("^((877)|(800)|(866)|(888))"); So I only want to get those # where the user may have left the 1 off of the front of the string, but I have tried several things and I can't get java to match. public String changeRingTo( String changedRinger ) { if ( null == changedRinger || changedRinger.length() != 10) return changedRinger; if ( patternTollFree.matcher(changedRinger).region(0, 2).matches() ) changedRinger = '1' + changedRinger; return changedRinger; } I can't get this 2nd test case below to succeed. What am I doing wrong? assertEquals( "Regex not working", "8189091000", of.changeRingTo("8189091000")); assertEquals( "Regex not working", "18769091000", of.changeRingTo("8769091000"));

Read the article
RegEx - Take all numeric characters following a text character

- by Simon

Given a string in the format: XXX999999v99 (where X is any alpha character and v is any numeric character and v is a literal v character) how can I get a regex to match the numeric characters following the v? So far I've got 'v\d\d' which includes the v but ideally I'd like just the numeric part. As an aside does anyone know of a tool in which you can specify a string to match and have the regex generated? Modifying an existing regex is one thing but I find starting from scratch painful! Edit: Re-reading this question I realise it reads like a homework assignment! However I can assure you it's not, the strings I'm trying to match represent product versions appended to product codes. The current code uses all sorts of substring expressions to retrieve the version part.

Read the article
How to use variables with regex?

- by dontoo

This is the input string: 23x^45*y or 2x^2 or y^4*x^3. I am matching ^[0-9]+ after letter x. In other words I am matching x followed by ^ followed by numbers. Problem is that I don't know that I am matching x, it could be any letter that I stored as variable in my char array. For example: foreach (char cEle in myarray) // cEle is letter in char array x, y, z, ... { match CEle in regex(input) //PSEUDOCODE } I am new to regex and I new that this can be done if I define regex variables, but I don't know how.

Read the article

< Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23 | Next Page >