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  • Using spring:nestedPath tag

    - by Ravi
    Hello All, I have this code, I know I'm missing something but don't know what. It would be great if you help me out. I'm new to Spring MVC. I'm trying out a simple Login application in Spring MVC. This is my web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <listener> <listener-class> org.springframework.web.context.ContextLoaderListener </listener-class> </listener> <servlet> <servlet-name>springapp</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>springapp</servlet-name> <url-pattern>/app/*</url-pattern> </servlet-mapping> <session-config> <session-timeout> 30 </session-timeout> </session-config> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> here is my springapp-servlet.xml file <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <bean name="/login" class="springapp.web.LoginController"/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> This is my applicationContext.xml file <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd"> <beans> <bean id="employee" class="springapp.domain.Employee" /> </beans> Here is my LoginController.java file package springapp.web; import org.springframework.web.servlet.ModelAndView; import org.springframework.web.servlet.mvc.SimpleFormController; import springapp.domain.Employee; public class LoginController extends SimpleFormController{ public LoginController(){ setCommandName("loginEmployee"); setCommandClass(Employee.class); setFormView("login"); setSuccessView("welcome"); } @Override protected ModelAndView onSubmit(Object command) throws Exception { return super.onSubmit(command); } } And finally my login.jsp file <%@ taglib uri="http://www.springframework.org/tags" prefix="spring" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Timesheet Login</title> </head> <body> <spring:nestedPath path="employee"> <form action="" method="POST"> <table width="200" border="1" align="center" cellpadding="10" cellspacing="0"> <tr> <td>Username:</td> <td> <spring:bind path="userName"> <input type="text" name="${status.expression}" id="${status.value}" /> </spring:bind> </td> </tr> <tr> <td>Password</td> <td> <spring:bind path="password"> <input type="password" name="${status.expression}" id="${status.value}" /> </spring:bind> </td> </tr> <tr> <td colspan="2"><input type="submit" value="Login" /></td> </tr> </table> </form> </spring:nestedPath> </body> </html> But when I try to run the code I get this error javax.servlet.ServletException: javax.servlet.jsp.JspTagException: Neither BindingResult nor plain target object for bean name 'employee' available as request attribute

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  • how to design a complex webreport in DevExpress XtraReport?

    - by ahmed
    Hello , I have to design a complex webreport with DevExpress Xtrareport .I have to pull data from 40 different tables on user selection and show on the Report. So I have designed in this way. On the design form I am giving the user to select the department section and project. with three dropdowns A) select the report , B) Sort by , C)Filter By A) Select the report contains different types like family status, insurance type etc ..total 40 types. B) Sort by will contain by employee number, date of birth , Salary , and many more C) Filter by will contain like employee on vacation, or employee terminated etc etc. Now for a single webreport I am first taking a DataSource and binding data to labels. to achieve the above webreport I have to take 40 different Datasource and I have to assign to the labels? Should I be doing this?

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  • XML output from MySQL

    - by NumberFour
    Hi, is there any chance of getting the output from a MySQL query directly to XML? Im referring to something like MSSQL has with SQL-XML plugin, for example: SELECT * FROM table WHERE 1 FOR XML AUTO returns text (or xml data type in MSSQL to be precise) which contains an XML markup structure generated according to the columns in the table. With SQL-XML there is also an option of explicitly defining the output XML structure like this: SELECT 1 AS tag, NULL AS parent, emp_id AS [employee!1!emp_id], cust_id AS [customer!2!cust_id], region AS [customer!2!region] FROM table FOR XML EXPLICIT which generates an XML code as follows: <employee emp_id='129'> <customer cust_id='107' region='Eastern'/> </employee> Do you have any clues how to achieve this in MySQL? Thanks in advance for your answers.

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  • TSQL -- Make it better

    - by user319353
    Hi: -- Very Narrow (all IDs are passed in) IF(@EmpID IS NOT NULL AND @DeptID IS NOT NULL AND @CityID IS NOT NULL) BEGIN SELECT e.EmpName ,d.DeptName ,c.CityName FROM Employee e WITH (NOLOCK) JOIN Department d WITH (NOLOCK) ON e.deptid = d.deptid JOIN City c WITH (NOLOCK) ON e.CityID = c.CityID WHERE e.EmpID = @EmpID END -- Just 2 IDs passed in ELSE IF(@DeptID IS NOT NULL AND @CityID IS NOT NULL) BEGIN SELECT e.EmpName ,d.DeptName ,NULL AS [CityName] FROM Employee e WITH (NOLOCK) JOIN Department d WITH (NOLOCK) ON e.deptid = d.deptid JOIN City c WITH (NOLOCK) ON e.CityID = c.CityID WHERE d.deptID = @DeptID END -- Very Broad (just 1 ID passed in) ELSE IF(@CityID IS NOT NULL) BEGIN SELECT e.EmpName ,NULL AS [DeptName] ,NULL AS [CityName] FROM Employee e WITH (NOLOCK) JOIN Department d WITH (NOLOCK) ON e.deptid = d.deptid JOIN City c WITH (NOLOCK) ON e.CityID = c.CityID WHERE c.CityID = @CityID END -- None (Nothing passed in) ELSE BEGIN SELECT NULL AS [EmpName] ,NULL AS [DeptName] ,NULL AS [CityName] END Question: Is there any better way (OR specifically can I do anything without IF...ELSE condition?

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  • What is Northwind.EmployeesRow

    - by Anthony
    I am doing a tutorial where you use a templatefield in the gridview control to call a function. I don't understand the code for the function. What is the object Northwind.EmployeesRow? This is the tutorial I am doing. http://msdn.microsoft.com/en-us/library/bb288032%28v=MSDN.10%29.aspx#aspnett12ustmpfldsvb_topic5 And this is the code for the function. Protected Function DisplayDaysOnJob(ByVal employee As Northwind.EmployeesRow) As String If employee.IsHireDateNull() Then Return "Unknown" Else ' Returns the number of days between the current ' date/time and HireDate Dim ts As TimeSpan = DateTime.Now.Subtract(employee.HireDate) Return ts.Days.ToString("#,##0") End If End Function

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  • Querying and ordering results of a database in grails using transient fields

    - by Azder
    I'm trying to display paged data out of a grails domain object. For example: I have a domain object Employee with the properties firstName and lastName which are transient, and when invoking their setter/getter methods they encrypt/decrypt the data. The data is saved in the database in encrypted binary format, thus not sortable by those fields. And yet again, not sortable by transient ones either, as noted in: http://www.grails.org/GSP+Tag+-+sortableColumn . So now I'm trying to find a way to use the transients in a way similar to: Employee.withCriteria( max: 10, offset: 30 ){ order 'lastName', 'asc' order 'firstName', 'asc' } The class is: class Employee { byte[] encryptedFirstName byte[] encryptedLastName static transients = [ 'firstName', 'lastName' ] String getFirstName(){ decrypt("encryptedFirstName") } void setFirstName(String item){ encrypt("encryptedFirstName",item) } String getLastName(){ decrypt("encryptedLastName") } void setLastName(String item){ encrypt("encryptedLastName",item) } }

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  • Can't get up with RIA demo: part 2

    - by Budda
    Here is a topic: http://stackoverflow.com/questions/2507734/cant-get-up-with-ria-demo where I've described problem with getting access to DomainContext object on the client. That time problem was resolved himself (without any actions from my side, with Visual Studio restart). At the moment, I had the same problem on another PC (Vista x64, VS2008, Silverlight 3.0, RIA Services Toolkit): ThomasDomainContext class that inherits DomainContext was not visible from the page's codebehind file. Again, it was resolved after VS restart and after that I got another problem: Error 1 'VfmElita.Web.ClientBin.ThomasDomainContext' does not contain a definition for 'employee' and no extension method 'employee' accepting a first argument of type 'VfmElita.Web.ClientBin.ThomasDomainContext' could be found (are you missing a using directive or an assembly reference?) D:\Project\Budda\VFMElita\VfmElitaSilverlightClient\MainPage.xaml.cs for the following lines of code (error is noticed for the 31st line): 30: var context = new ThomasDomainContext(); 31: grid1.ItemsSource = context.employee; 32: context.Load(context.GetEmployeeQuery()); Any help is welcome. P.S. Please note, that source code create on the 1st machine is successfully compilable and launchable

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  • How to force programs out of swap file when a resources-intensive batch finishes?

    - by sharptooth
    We use employees' desktops for CPU-intensive simulation during the night. Desktops run Windows - usually Windows XP. Employees don't log off, they just lock the desktops, switch off their monitors and go. Every employee has a configuration file which he can edit to specify when he is most likely out of office. When that time comes a background program grabs data for simulation from the server, spawns worker processes, watches them, gets results and sends them to the server. When the time specified by the employee elapses simulation stops so that normal desktop usage is not interfered. The problem is that simuation consumes a lot of memory, so when the worker processes run they force other programs into the swap file. So when the employee comes all the programs he left are luggish and slow until he opens them one by one so that they are unswapped. Is there a way the program can force other programs out of swap file when it stops simulation so that they again run smoothly?

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  • how to display the Grid on row click evnt on other jquery grid

    - by kumar
    Hello all, please help me out from this problem which i was facing since from long,, Comming to my applicaiton: Using Asp.net MVC with Jquery stuff, with back end DB2 I have a user controls with jquery grid in it, for the Jquery grid the URL I am assing is something like this. ID EmployeName PHoneNumber Deatils /Employee/Orders/Details /// Deails is my actionresult class.. I am getting the output result exactly what I am expecting... now I have one more action result calls LIST( List for that Deatils).. when User click on any row in the Jquery grid I need to pass ID( for that Employee to the DB2 to get that Employee List) and this Grid I need to show i nthe bottom of the first grid, Like If I click on second row I need to pass the ID to the DB2 to get second user result to display on the second grid. can anybody help me with the code.. Thanks

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  • How to instert child entities in JDO (Google App Engine) ?

    - by Kerem Pekçabuk
    How do i add a record to a child entity in the example below ? For example i have a Employee Record which is name is "Sam". how do i add 2 street adress for sam ? Guess i have a The Parent entity is Employee import java.util.List; // ... @Persistent(mappedBy = "employee") private List contactInfoSets; The Child key is Adress import com.google.appengine.api.datastore.Key; // ... imports ... @PersistenceCapable public class ContactInfo { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private Key key; @Persistent private String streetAddress; // ... }

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  • Help needed in AdventureWorks in a sql query.

    - by vaibhav
    I was just playing with adventureworks database in sqlserver. I got stuck in a query. I wanted to Select all titles from HumanResources.Employee which are either 'Male' or 'Female' but not both. i.e if title Accountant is Male and Female both I want to leave that title. I need only those titles where Gender is either Male or Female. I have done this till yet. select distinct(title) from humanresources.employee where gender='M' select distinct(title) from humanresources.employee where gender='F' Probably a join between these two queries, would work. But If you have any other solution, please let me know. It is not a homework. :) Thanks in advance.

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  • How to configure Hibernate database reverse engineering tool to map database table relation as a ent

    - by Piotr Kochanski
    Is it possible to configure Hibernate reverse engineering and code generation tool in such a way that one-to-many relation between tables is mapped to entities inheritance instead of enrites relation? I have Person table and Employee table, which are related with the foreign key (Person contains basic information, Employee the rest). In my Java code I would like this relation mapped to inheritance Employee extends Person. This can be done by hand, but maybe I missed some custom configuration parameter that I can use. I couldn't find any official documentation - docs link on RedHat Hibernate page (http://www.hibernate.org/5.html#A10) is broken...

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  • how to populate an entity you have extended in the Entity Framework?

    - by user169867
    I have an entity in my EDMX that I've extended with a few fields in a partial class like this: public partial class Employee { public string JobName {get;set;} } These properties are for display only. In the above example say the entity has a JobTypeID property. I wish JobName to be populated w/ the name that belongs to that JobTypeID. Is there anyway to query the employee record in EF including the value for the JobName property w/o explicity assigning each field using select()? The reason I ask is that there are a lot of fields in the Employee entity so I'd like to be able to take advantage of something like: ctx.Employees.Where(e=>e.EmployeeID==employeeID).Single() ...add somehow fill in JobName too Is this possible?

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  • Django: Set foreign key using integer?

    - by User
    Is there a way to set foreign key relationship using the integer id of a model? This would be for optimization purposes. For example, suppose I have an Employee model: class Employee(models.Model): first_name = models.CharField(max_length=100) last_name = models.CharField(max_length=100) type = models.ForeignKey('EmployeeType') and EmployeeType(models.Model): type = models.CharField(max_length=100) I want the flexibility of having unlimited employee types, but in the deployed application there will likely be only a single type so I'm wondering if there is a way to hardcode the id and set the relationship this way. This way I can avoid a db call to get the EmployeeType object first.

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  • How to add EAR files in a java console application

    - by Vibhas
    Hi Friends, I want to know how to add an EAR file into a simple java class i.e a standalone application. Let say i have a class Employee package com.Employee; import com.xyz.Workflow//this library is present in EAR file whose method i need to call public class Employee{ public static void main(String[] args) // Wokflow wf = new Workflow(); // ws.initiateWorkflow(); this method needs to be called but for that i need to include this EAR which is given to me from a 3rd party; } Can any one help me the API is in EAR only. Thanks

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  • Command Query Separation validating for retries

    - by Neil Barnwell
    So I'm comfortable with the basic concept of CQS, where you might have a command that writes to one database, and that updates the query database that you read from. However, consider the scenario where you are entering data, and want to prevent duplicates. Using new employee data entry an employee register as an example, working through a pile of application forms to key in the new employees' details: Take top sheet. Key in employee name and unique payroll number to UI. Submit. Put paper in "completed pile". Repeat. How would you now prevent the user from keying in the same payroll number again, say for instance if they get distracted and can't remember whether they've keyed one in already and the "message" hasn't got all the way back to the query db for the user to search?

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  • ListView GridView and Grid

    - by urema
    Hi, If you have a ListView with its view set as a GridView, which itself contains columns for each month say.....how do I set a template up for the ItemTemplate of the ListView so that each Item will be three rows high, and be inline with the ListView.View's columns? For example different employee recruits over a year.... each month across the top and each employee on the left side, though sub-columned on the employee are three rows "Name", "Address" and "Job Type" say. I know you have to use the IsSharedSizeScope attached property. January February ... Employee1 Name E1 Address E1 Street Job Type Cleaner Employee2 Name ... Address ... Job Type ... Thanks greatly in advance, U.

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  • Arrange 0's & 1's in a array

    - by Ganesh M
    This is one of an interview question which I had recently. I would like to know others perception of approach for this problem. Question: You are given a structure which holds an employee details with two elements as int Deptartment and string Name. struct Employee { string Name; int Dept; } You are given details of N Employees among which there are N/2 employees Dept are 0's and N/2 employees dept are 1's arranged in some random order. You need to sort the employee details based on their Dept value and it should be stable i.e., the order of 1s and 0s in the original record should be maintained. For example, given the following sample data: Name Dept X1 0 X2 1 X3 0 X4 1 X5 0 after sorting the result should be: Name Dept X2 1 X4 1 X1 0 X3 0 X5 0 The algorithm should be stable and the complexity should be o(N), with constant space for additional variables (which means sorting should be done in-place).

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  • Expand <div> tag to bottom of page with CSS

    - by typoknig
    Hi all, I know this question gets asked a lot because I have looked at many "solutions" trying to get this to work for me. I can get it to work if I hack up the html but I want to use all CSS. All I want is a header with two columns below it, and I want these three items to fill the entire page/screen, and I want to do it with CSS and without frames or tables. The XAMPP user interface looks exactly how I want my page to look, but again, I do not want to use frames. I cannot get the two orangeish colored columns to extend to the bottom of the screen. I do have it so it looks like the right column extends to the bottom of the screen just by changing the body background color to the same color as the background color of the right column, but I would like both columns to extend to the bottom so I didn't have to do that. Here is what I have so far: HTML <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html dir="ltr" xmlns="http://www.w3.org/1999/xhtml"> <head> <title>MY SITE</title> <meta content="text/html; charset=utf-8" http-equiv="Content-Type" /> <link href="stylesheet.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="container"> <div id="masthead"> MY SITE</div> <div id="left_col"> Employee Management<br /> <a href="Employee%20Management.php">Add New Employee</a><br /> <a href="Employee%20Management.php">Edit Existing Employee</a><br /> <br/> Load Management<br /> <a href="Load%20Management.php">Log New Load</a><br /> <a href="Load%20Management.php">Edit Existing Load</a><br /> <br/> Report Management<br /> <a href="Report%20Management.php">Employee Report</a><br /> <a href="Report%20Management.php">Load Report</a></div> <div id="page_content"> <div id="page_content_heading">Welcome!</div> Lots of words</div> </div> </body> </html> CSS #masthead { background-color:#FFFFFF; font-family:Arial,Helvetica,sans-serif; font-size:xx-large; font-weight:bold; padding:30px; text-align:center; } #container { min-width: 600px; min-height: 100%; } #left_col { padding: 10px; background-color: #339933; float: left; font-family: Arial,Helvetica,sans-serif; font-size: large; font-weight: bold; width: 210px; } #page_content { background-color: #CCCCCC; margin-left: 230px; padding: 20px; } #page_content_heading { font-family:Arial,Helvetica,sans-serif; font-size:large; font-weight:bold; padding-bottom:10px; padding-top:10px; } a { color:#0000FF; font-family:Arial,Helvetica,sans-serif; font-size:medium; font-weight:normal; } a:hover { color:#FF0000; } html, body { height: 100%; padding: 0; margin: 0; background-color: #CCCCCC; }

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  • Error in PHP with Mysql

    - by maltad
    Hello, Im starting to learn PHP. When I run the script it had an error that said: "Assigned Employee:resource(6) of type (mysql result)" . Please help me and sorry for my bad English Here is the code: include_once 'rnheader.php'; include_once 'rnfunctions.php'; echo ''; echo ' Assigned Employee:'; $query = "SELECT UserName FROM employee where Classification_ClassificationID = '2'"; $result = queryMysql($query); if (!queryMysql($query)) { echo "Query fail: $query" . mysql_error() . ""; } else { var_dump($result); exit; echo ''; // or name="toinsert[]" while ($row = mysqli_fetch_array($result)) { echo '' . htmlspecialchars($row['UserName']) . ''; } } echo ''; ?

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  • Strange SQL problem selecting multiple values for same column

    - by Nubber
    Hello there, Been at this for a few hours now and I can't make any sense of it. I've used this way of selecting multiple values for same column a few times, but there is something weird with this one. SELECT * FROM employee as s INNER JOIN works AS w1 ON w1.name = s.name INNER JOIN employee AS w2 ON w2.name = s.name INNER JOIN employee AS w3 ON w3.name = s.name WHERE w2.city = 'Washington' Basically what I want to do is find all companies which have people in all the cities. The company name is under 'works'. The problem is however that if I have the WHERE w2.city='Washington' it will make ALL the cities match Washington when it should only touch w2 and leave w3 alone so I could match it with another value. Anyone know why its doing this? Or know a better way to do it. Thank you very much in advance.

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  • printing reverse in singly link list using pointers

    - by theoneabhinav
    i have been trying this code. i think the logic is ok but the program terminates abruptly when the display_rev function is called here is code of display_rev void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } } here is my whole code #include<stdio.h> #include<stdlib.h> #include<ctype.h> #include<string.h> //Declarations=============================================================== typedef struct //employee record { int emp_id; char name[150]; char mob_no[11]; float salary; int proj[5]; struct emp_node *next; } emp_node; emp_node* add_rec(emp_node*); emp_node* create_db(emp_node*); emp_node* search_db(emp_node*, int); emp_node* delete_rec(emp_node*, int); void read_name(emp_node*); void read_mob(emp_node*); void display_db(emp_node*); void display_rec(emp_node*); void display_rev(emp_node*); void modify_rec(emp_node*); void swtch(emp_node*); //=========================================================================== int main() { char ans; emp_node *head = NULL; head = create_db(head); display_db(head); do { swtch(head); printf("\n\n\tDo you want to continue (y/n) : "); getchar(); scanf("%c", &ans); } while (ans == 'y' || ans == 'Y'); return 0; } //Definitions================================================================ emp_node* create_db(emp_node *head) //database creation { int i = 1, no; emp_node *p; printf("Enter number of employees:"); scanf("%d", &no); printf("\n\n"); head = (emp_node *) malloc(sizeof(emp_node)); head = add_rec(head); head->next = NULL; p = head; while (i < no) { p->next = (emp_node *) malloc(sizeof(emp_node)); p = p->next; p = add_rec(p); p->next = NULL; i++; } return head; } emp_node* add_rec(emp_node *p) //new record { int j; printf("\n\tEmployee ID : "); scanf("%d", &(p->emp_id)); printf("\n\tFirst Name:"); read_name(p); printf("\n\tMobile No.:"); read_mob(p); printf("\n\tSalary :"); scanf("%f", &(p->salary)); printf( "\n\tEnter \"1\" for the projects employee is working on, otherwise enter \"0\": \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1 && p->proj[j] != 0) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } printf("\n\n\n"); return p; } void read_name(emp_node *p) //validation for name { int j, len; scanf("%s", p->name); len = strlen(p->name); for (j = 0; j < len; j++) { if (!isalpha(p->name[j])) { printf( "\n\n\tInvalid name!!Can contain only characters. Please Re-enter.\n"); printf("\n\tName : "); read_name(p); } } } void read_mob(emp_node *p) //validation for mobile no. { int j; scanf("%s", p->mob_no); while (strlen(p->mob_no) != 10) { printf("\n\nInvalid Mobile No!!Please Re-enter"); printf("\n\n\tMobile No.:"); read_mob(p); } for (j = 0; j < 10; j++) { if (!(48 <= p->mob_no[j] && p->mob_no[j] <= 57)) { printf( "\n\nInvalid Mobile No!!Can contain only digits. Please Re-enter."); printf("\n\n\tMobile No.:"); read_mob(p); } } } void display_db(emp_node *head) //displaying whole database { emp_node *p; p = head; printf("\n\n\t\t****** EMPLOYEE DATABASE ******\n"); printf( "\n=============================================================================="); printf("\n Id.\t Name\t\t Mobile No\t Salary\t Projects\n"); while (p != NULL) { display_rec(p); p = p->next; printf("\n\n\n"); } printf( "\n=============================================================================="); } void swtch(emp_node *head) //function for menu and switch case { int cho, x; emp_node *p; printf("\n\n\t\t****** MENU ******"); printf( "\n\n\t1. insert Record\n\t2. Search Record\n\t3. Modify Record\n\t4. Delete Record\n\t5. Display Reverse\n\t6. Exit"); printf("\n\tWhich operation do you want to perform? "); scanf("%d", &cho); switch (cho) { case 1: p=head; while(p->next != NULL) p=p->next; p->next = (emp_node *) malloc(sizeof(emp_node)); p=p->next; p = add_rec(p); p->next = NULL; display_db(head); break; case 2: printf("\n\n\tEnter employee ID whose record is to be Searched :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else display_rec(p); break; case 3: printf("\n\n\tEnter employee ID whose record is to be modified :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else modify_rec(p); display_db(head); break; case 4: printf("\n\n\tEnter employee ID whose record is to be deleted :"); scanf("%d", &x); head = delete_rec(head, x); display_db(head); break; case 5: display_rev(head); case 6: exit(0); default: printf("Invalid Choice!! Please try again."); } } emp_node* search_db(emp_node *head, int id) //search database { emp_node *p = head; while (p != NULL) { if (p->emp_id == id) return p; p = p->next; } return NULL; } void display_rec(emp_node *p) //display a single record { int j; printf("\n %d", p->emp_id); printf("\t %10s", p->name); printf("\t %10s", p->mob_no); printf("\t %05.2f", p->salary); printf("\t "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } } void modify_rec(emp_node *p) //modifying a record { int j, cho; char ch1, edt; do { printf( "\n\t1. Name\n\t2. Email Address\n\t3. Mobile No.\n\t4. Salary\n\t5. Date of birth\n\t6. Projects\n"); printf("Enter your choice : "); scanf("%d", &cho); switch (cho) { case 1: printf("\n\tPrevious name:%s", p->name); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Name:"); read_name(p); } break; case 2: printf("\n\tPrevious Mobile No. : %s", p->mob_no); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Mobile No. :"); read_mob(p); } break; case 3: printf("\n\tPrevious salary is : %f", p->salary); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New salary:"); scanf("%f", &(p->salary)); } break; case 4: printf("the employee is currently working on project no. "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf( "\n\tEnter \"1\" for the projects employee is working on : \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } } break; default: printf("\n\nInvalid Choice!! Please Try again."); } printf("\n\nDo you want to edit any other fields ?(y/n)"); getchar(); scanf("%c", &edt); } while (edt == 'y' || edt == 'Y'); } emp_node* delete_rec(emp_node *head, int id) //physical deletion of record { emp_node *p = head, *q; if (head->emp_id == id) { head = head->next; free(p); return head; } else { q = p->next; while (q->emp_id != id) { p = p->next; q = q->next; } if (q->next == NULL) p->next = NULL; else p->next = q->next; free(q); return head; } } void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } }

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  • WPF Databinding- Not your fathers databinding Part 1-3

    - by Shervin Shakibi
    As Promised here is my advanced databinding presentation from South Florida Code camp and also Orlando Code camp. you can find the demo files here. http://ssccinc.com/wpfdatabinding.zip Here is a quick description of the first demos, there will be 2 other Blogposting in the next few days getting into more advance databinding topics.   Example00 Here we have 3 textboxes, The first textbox mySourceElement Second textbox has a binding to mySourceElement and Path= Text <Binding ElementName="mySourceElement" Path="Text"  />   Third textbox is also bound to the Text property but we use inline Binding <TextBlock Text="{Binding ElementName=mySourceElement,Path=Text }" Grid.Row="2" /> Here is the entire XAML     <Grid  >           <Grid.RowDefinitions >             <RowDefinition Height="*" />             <RowDefinition Height="*" />             <RowDefinition Height="*" />         </Grid.RowDefinitions>         <TextBox Name="mySourceElement" Grid.Row="0"                  TextChanged="mySourceElement_TextChanged">Hello Orlnado</TextBox>         <TextBlock Grid.Row="1">                        <TextBlock.Text>                 <Binding ElementName="mySourceElement" Path="Text"  />             </TextBlock.Text>         </TextBlock>         <TextBlock Text="{Binding ElementName=mySourceElement,Path=Text }" Grid.Row="2" />     </Grid> </Window> Example01 we have a slider control, then we have two textboxes bound to the value property of the slider. one has its text property bound, the second has its fontsize property bound. <Grid>      <Grid.RowDefinitions >          <RowDefinition Height="40px" />          <RowDefinition Height="40px" />          <RowDefinition Height="*" />      </Grid.RowDefinitions>      <Slider Name="fontSizeSlider" Minimum="5" Maximum="100"              Value="10" Grid.Row="0" />      <TextBox Name="SizeTextBox"                    Text="{Binding ElementName=fontSizeSlider, Path=Value}" Grid.Row="1"/>      <TextBlock Text="Example 01"                 FontSize="{Binding ElementName=SizeTextBox,  Path=Text}"  Grid.Row="2"/> </Grid> Example02 very much like the previous example but it also has a font dropdown <Grid>      <Grid.RowDefinitions >          <RowDefinition Height="20px" />          <RowDefinition Height="40px" />          <RowDefinition Height="40px" />          <RowDefinition Height="*" />      </Grid.RowDefinitions>      <ComboBox Name="FontNameList" SelectedIndex="0" Grid.Row="0">          <ComboBoxItem Content="Arial" />          <ComboBoxItem Content="Calibri" />          <ComboBoxItem Content="Times New Roman" />          <ComboBoxItem Content="Verdana" />      </ComboBox>      <Slider Name="fontSizeSlider" Minimum="5" Maximum="100" Value="10" Grid.Row="1" />      <TextBox Name="SizeTextBox"      Text="{Binding ElementName=fontSizeSlider, Path=Value}" Grid.Row="2"/>      <TextBlock Text="Example 01" FontFamily="{Binding ElementName=FontNameList, Path=Text}"                 FontSize="{Binding ElementName=SizeTextBox,  Path=Text}"  Grid.Row="3"/> </Grid> Example03 In this example we bind to an object Employee.cs Notice we added a directive to our xaml which is clr-namespace and the namespace for our employee Class xmlns:local="clr-namespace:Example03" In Our windows Resources we create an instance of our object <Window.Resources>     <local:Employee x:Key="MyEmployee" EmployeeNumber="145"                     FirstName="John"                     LastName="Doe"                     Department="Product Development"                     Title="QA Manager" /> </Window.Resources> then we bind our container to the that instance of the data <Grid DataContext="{StaticResource MyEmployee}">         <Grid.RowDefinitions>             <RowDefinition Height="*" />             <RowDefinition Height="*" />             <RowDefinition Height="*" />             <RowDefinition Height="*" />             <RowDefinition Height="*" />         </Grid.RowDefinitions>         <Grid.ColumnDefinitions >             <ColumnDefinition Width="130px" />             <ColumnDefinition Width="178*" />         </Grid.ColumnDefinitions>     </Grid> and Finally we have textboxes that will bind to that textbox         <Label Grid.Row="0" Grid.Column="0">Employee Number</Label>         <TextBox Grid.Row="0" Grid.Column="1" Text="{Binding Path=EmployeeNumber}"></TextBox>         <Label Grid.Row="1" Grid.Column="0">First Name</Label>         <TextBox Grid.Row="1" Grid.Column="1" Text="{Binding Path=FirstName}"></TextBox>         <Label Grid.Row="2" Grid.Column="0">Last Name</Label>         <TextBox Grid.Row="2" Grid.Column="1" Text="{Binding Path=LastName}" />         <Label Grid.Row="3" Grid.Column="0">Title</Label>         <TextBox Grid.Row="3" Grid.Column="1" Text="{Binding Path=Title}"></TextBox>         <Label Grid.Row="4" Grid.Column="0">Department</Label>         <TextBox Grid.Row="4" Grid.Column="1" Text="{Binding Path=Department}" />

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  • SQL SERVER – Convert IN to EXISTS – Performance Talk

    - by pinaldave
    In recent training one of the attendee asked if I can show simple method to convert IN clause to EXISTS clause. Here is the simple example. USE AdventureWorks GO -- use of = SELECT * FROM HumanResources.Employee E WHERE E.EmployeeID = ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA WHERE EA.EmployeeID = E.EmployeeID) GO -- use of exists SELECT * FROM HumanResources.Employee E WHERE EXISTS ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA WHERE EA.EmployeeID = E.EmployeeID) GO It is NOT necessary that every time when IN is replaced by EXISTS it gives better performance. However, in our case listed above it does for sure give better performance. Click on below image to see the execution plan. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: SQL, SQL Authority, SQL Optimization, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – Weekly Series – Memory Lane – #033

    - by Pinal Dave
    Here is the list of selected articles of SQLAuthority.com across all these years. Instead of just listing all the articles I have selected a few of my most favorite articles and have listed them here with additional notes below it. Let me know which one of the following is your favorite article from memory lane. 2007 Spatial Database Definition and Research Documents Here is the definition from Wikipedia about spatial database : A spatial database is a database that is optimized to store and query data related to objects in space, including points, lines and polygons. While typical databases can understand various numeric and character types of data, additional functionality needs to be added for databases to process spatial data types. Select Only Date Part From DateTime – Best Practice A very common question which I receive is how to only get Date or Time part from datetime value. In this blog post I explain the same in very simple words. T-SQL Paging Query Technique Comparison (OVER and ROW_NUMBER()) – CTE vs. Derived Table I have received few emails and comments about my post SQL SERVER – T-SQL Paging Query Technique Comparison – SQL 2000 vs SQL 2005. The main question was is this can be done using CTE? Absolutely! What about Performance? It is identical! Please refer above mentioned article for the history of paging. SQL SERVER – Cannot resolve collation conflict for equal to operation One of the very first error I ever encountered in my career was to resolve this conflict. I have blogged about it and I have realized that many others like me who are facing this error. LEN and DATALENGTH of NULL Simple Example Here is the question for you what is the LEN of NULL value? Well it is very easy – just read the blog. Recovery Models and Selection Very simple and easy explanation of the Database Backup Recovery Model and how to select the best option for you. Explanation SQL SERVER Hash Join Hash join gives best performance when two more join tables are joined and at-least one of them have no index or is not sorted. It is also expected that smaller of the either of table can be read in memory completely (though not necessary). Easy Sequence of SELECT FROM JOIN WHERE GROUP BY HAVING ORDER BY SELECT yourcolumns FROM tablenames JOIN tablenames WHERE condition GROUP BY yourcolumns HAVING aggregatecolumn condition ORDER BY yourcolumns NorthWind Database or AdventureWorks Database – Samples Databases In this blog post we learn how to install Northwind database. I also shared the source where one can download this database as that is used in many examples on MSDN help files. sp_HelpText for sp_HelpText – Puzzle A simple quick puzzle – do you know the answer of it? If not, go ahead and read the blog. 2008 SQL SERVER – 2008 – Step By Step Installation Guide With Images When SQL Server 2008 was newly introduced lots of people had no clue how to install SQL Server 2008 and the amount of the question which I used to receive were so much. I wrote this blog post with the spirit that this will help all the newbies to install SQL Server 2008 with the help of images. Still today this blog post has been bible for all of the people who are confused with SQL Server installation. Inline Variable Assignment I loved this feature. I have always wanted this feature to be present in SQL Server. The last time when I met developers from Microsoft SQL Server, I had talked about this feature. I think this feature saves some time but make the code more readable. Introduction to Policy Management – Enforcing Rules on SQL Server If our company policy is to create all the Stored Procedure with prefix ‘usp’ that developers should be just prevented to create Stored Procedure with any other prefix. Let us see a small tutorial how to create conditions and policy which will prevent any future SP to be created with any other prefix. 2009 Performance Counters from System Views – By Kevin Mckenna Many of you are not aware of this fact that access to performance information is readily available in SQL Server and that too without querying performance counters using a custom application or via perfmon. Till now, this fact has remained undisclosed but through this post I would like to explain you can easily access SQL Server performance counter information. Without putting much effort you will come across the system viewsys.dm_os_performance_counters. As the name suggests, this provides you easy access to the SQL Server performance counter information that is passed on to perfmon, but you can get at it via tsql. Customize Toolbar – Remove Debug Button from Toolbar I was fond of SQL Server Debugger feature in SQL Server 2000. To my utter disappointment, this feature was withdrawn from SQL Server 2005. The button of the debugger is similar to a play button and is used to run debugging commands of Visual Studio. Because of this reason, it gets very much infuriating for developers when they are developing on both – Visual Studio and SSMS. Let us now see how we can remove debugging button from SQL Server Management Studio. Effect of Normalization on Index and Performance A very interesting conversation which started from twitter. If you want to read one link this is the link I encourage you to read it. SSMS Feature – Multi-server Queries Using SQL Server Management Studio (SSMS) DBAs can now query multiple servers from one window. It is quite common for DBAs with large amount of servers to maintain and gather information from multiple SQL Servers and create report. This feature is a blessing for the DBAs, as they can now assemble all the information instantaneously without going anywhere. Query Optimizer Hint ROBUST PLAN – Question to You “ROBUST PLAN” is a kind of query hint which works quite differently than other hints. It does not improve join or force any indexes to use; it just makes sure that a query does not crash due to over the limit size of row. Let me elaborate upon it in the blog post. 2010 Do you really know the difference between various date functions available in SQL Server 2012? Here is a three part story where we explored the same with examples: Fastest Way to Restore the Database Difference Between DATETIME and DATETIME2 Difference Between DATETIME and DATETIME2 – WITH GETDATE Shrinking NDF and MDF Files – Readers’ Opinion Shrinking Database always creates performance degradation and increases fragmentation in the database. I suggest that you keep that in mind before you start reading the following comment. If you are going to say Shrinking Database is bad and evil, here I am saying it first and loud. Now, the comment of Imran is written while keeping in mind only the process showing how the Shrinking Database Operation works. Imran has already explained his understanding and requests further explanation. I have removed the Best Practices section from Imran’s comments, as there are a few corrections. 2011 Solution – Puzzle – SELECT * vs SELECT COUNT(*) This is very interesting question and I am very confident that not every one knows the answer to this question. Let me ask you again – Which will be faster SELECT* or SELECT COUNT (*) or do you think this is apples and oranges comparison. 2012 Service Broker and CAP_CPU_PERCENT – Limiting SQL Server Instances to CPU Usage In SQL Server 2012 there are a few enhancements with regards to SQL Server Resource Governor. One of the enhancement is how the resources are allocated. Let me explain you with examples. Let us understand the entire discussion with the help of three different examples. Finding Size of a Columnstore Index Using DMVs One of the very common question I often see is need of the list of columnstore index along with their size and corresponding table name. I quickly re-wrote a script using DMVs sys.indexes and sys.dm_db_partition_stats. This script gives the size of the columnstore index on disk only. I am sure there will be advanced script to retrieve details related to components associated with the columnstore index. However, I believe following script is sufficient to start getting an idea of columnstore index size. Developer Training Resources and Summary Roundup Developer Training - Importance and Significance - Part 1 In this part we discussed the importance of training in the real world. The most important and valuable resource any company is its employee. Employees who have been well-trained will be better at their jobs and produce a better product.  An employee who is well trained obviously knows more about their job and all the technical aspects. I have a very high opinion about training employees and it is the most important task. Developer Training – Employee Morals and Ethics – Part 2 In this part we discussed the most crucial components of training. Often employees are expecting the company to pay for their training and the company expresses no interest in training the employee. Quite often training expenses are the real issue for both the employee and employer. Developer Training – Difficult Questions and Alternative Perspective - Part 3 This part was the most difficult to write as I tried to address a few difficult questions and answers. Training is such a sensitive issue that many developers when not receiving chance for training think about leaving the organization. Developer Training – Various Options for Developer Training – Part 4 In this part I tried to explore a few methods and options for training. The generic feedback I received on this blog post was short and I should have explored each of the subject of the training in details. I believe there are two big buckets of training 1) Instructor Lead Training and 2) Self Lead Training. Developer Training – A Conclusive Summary- Part 5 There is no better motivation than a personal desire to learn new technology. Honestly there is nothing more personal learning. That “change is the only constant” and “adapt & overcome” are the essential lessons of life. One cannot stop the learning and resist the change. In the IT industry “ego of knowing all” and the “resistance to change” are the most challenging issues. A Quick Look at Logging and Ideas around Logging Question: What is the first thing comes to your mind when you hear the word “Logging”? Strange enough I got a different answer every single time. Let me just list what answer I got from my friends. Let us go over them one by one. Beginning Performance Tuning with SQL Server Execution Plan Solution of Puzzle – Swap Value of Column Without Case Statement Earlier this week I asked a question where I asked how to Swap Values of the column without using CASE Statement. Read here: SQL SERVER – A Puzzle – Swap Value of Column Without Case Statement. I have proposed 3 different solutions in the blog posts itself. I had requested the help of the community to come up with alternate solutions and honestly I am stunned and amazed by the qualified entries. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Memory Lane, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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