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  • How to structure a XML-based order form using ASP.NET

    - by Brendan
    First question here; please help me if I'm doing something wrong. I'm a graphic designer who's trying to teach himself ASP.NET/C#. My server-side background is PHP/WordPress and some ASP Classic, and when I do code I've hand-coded just about everything since I started learning HTML. So, as I've started to learn .NET, my code has been very manual and procedural. I'm now trying to create a really basic order form that pulls from an XML file to populate the form; there's an image, a title, a price, and selectable quantities. If I was making this form as a static HTML file, I'd have each field named manually and so on postback I could query each field to get the values. But I'm trying to do this dynamically so that I can add/remove items from the form and not have to change the code. In terms of displaying the XML, I rolled my own by loading XmlDocument and using XmlNodeList and a bunch of foreach loops to get things displayed. Then, I learned about <asp:XmlDataSource> and <asp:Repeater>, which made displaying the XML simpler by a large margin. However, I've had a really hard time getting the data that's been submitted on postback (it was implied on SO that there are better ways to get data than nested RepeaterItems). So, what I've learned so far is that you can do things a bunch of different ways in .NET. that's why I thought it'd be good to ask for answers regarding the best way to use ASP.NET to display a XML document and dynamically capture the data that's submitted. Any help is appreciated! I'm using Notepad++ to code .NET 2.0.

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  • An XML file or Database?

    - by webnoob
    I am re-writing a section of my site and am trying to decide how much of a rewrite this will be. At the moment I have a web service feed that generates an xml once per day. I then use this xml file on my website to generate the general structure. I am trying to decide if this information should be located in the database or stay in the xml file. The file can range from 4mb - 12mb. The files depth can go on and on so I have to recurse to find the data I want. I use the .NET serializer classes and store the serialized file in a global variable to avoid re-serializing it each time the page is loaded. My reasons for thinking a database would be better are: I would know exactly where I am in the file by using an internal ID so I wouldn't have to recurse the file to get information. I wouldn't have to load / serialize the XML and could just use my already open database connections. Searching for the data in the file would be quicker(?) as I would just perform an SQL query rather than re-cursing the file. Has anyone got any ideas which is better and which option uses more resources on the server or be quicker? EDIT: The file is read every time the web page is loaded (although only serialized once). It isn't written to by standard users (only by an admin task that runs in the middle of the night). This is my initial investigation before mocking up.

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  • Stairway to XML: Level 8 - Deleting Data from an XML Instance

    in order to use the modify() method to delete data from typed and untyped XML instances, you must pass an XML DML expression as an argument to the method. That expression must include the delete keyword, along with an XQuery expression that defines the XML component to be deleted. Robert makes it seem simple, as usual. The best way to version control T-SQLSSMS plug-in SQL Source Control connects SVN, TFS, Git, Hg and all others to SQL Server. Learn more.

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  • Do I need to know servlets and JSP to learn spring or hibernate or any other java web frameworks?

    - by KyelJmD
    I've been asking a lot of people where to start learning java web development, I already know core java (Threading,Generics,Collections, a little experience with (JDBC)) but I do not know JSPs and servlets. I did my fair share of development with several web based applications using PHP for server-side and HTML,CSS,Javascript,HTML5 for client side. Most people that I asked told me to jump right ahead to Hibernate while some told me that I do not need to learn servlets and jsps and I should immediately study the Spring framework. Is this true? do I not need to learn servlets and JSPs to learn hibernate or Spring? All of their answers confused me and now I am completely lost what to learn or study. I feel that if I skipped learning JSP and servlets I would missed a lot of important concepts that will surely help me in the future. So the question, do I need to have foundation/know servlets and JSP to learn spring or hibernate or any other java web frameworks.?

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  • Design for XML mapping scenarios between two different systems [on hold]

    - by deepak_prn
    Mapping XML fields between two systems is a mundane routine in integration scenarios. I am trying to make the design documents look better and provide clear understanding to the developers especially when we do not use XSLT or any other IDE such as jDeveloper or eclipse plugins. I want it to be a high level design but at the same time talk in developer's language. So that there is no requirements that slip under the crack. For example, one of the scenarios goes: the store cashier sells an item, the transaction data is sent to Data management system. Now, I am writing a functional design for the scenario which deals with mapping XML fields between our system and the data management system. Question : I was wondering if some one had to deal with mapping XML fields between two systems? (without XSLT being involved) and if you used a table to represent the fields mapping (example is below) or any other visualization tool which does not break the bank ? I am trying to find out if there is a better way to represent XML mapping in your design documents. The widely accepted and used method seems to be using a simple table such as in the picture to illustrate the mapping. I am wondering if there are alternate ways/ tools to represent such as in Altova:

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  • Stairway to XML: Level 7 - Updating Data in an XML Instance

    You need to provide the necessary keywords and define the XQuery and value expressions in your XML DML expression in order to use the modify() method to update element and attribute values in either typed or untyped XML instances in an XML column. Robert Sheldon explains how. "It really helped us isolate where we were experiencing a bottleneck"- John Q Martin, SQL Server DBA. Get started with SQL Monitor today to solve tricky performance problems - download a free trial

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  • Convience of mySQL over xml

    - by Bonechilla
    Currently I use XML to store specific information to correctly load a few things such as a list of specfied characters, scenes and music, Once more I use JAXB in combination with standard compression/decompression(ZIP) functionality to store a list of extrenous data. This data is called to add functionality to the character, somewhat like Skills in an RPG. Each skill is seperated into its own XML file with a grandlist which contains the names of each file with their extensions omitted and zipped in folder that gets encrypted. At first using xml was working fine however as the skill list grow i worry about its stability. I was wondering if I should begin storing the data in mySQL. Originally I planned to simply convert everything to JSON over xml but i think possibly mySQL would be a better move. Can anyone inform me of the key difference and pros and cons of each I guess i'm looking for the best way to store the data more conviently and would be easier to operate on. The data is mostly primatives and strings and the only arraylist of values i have i can just concat into a single field and parse later

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  • Stairway to XML: Level 5 - The XML exist() and nodes() Methods

    The XML exist() method is used, often in a WHERE clause, to check the existence of an element within an XML document or fragment. The nodes() method lets you shred an XML instance and return the information as relational data. 12 essential tools for database professionalsThe SQL Developer Bundle contains 12 tools designed with the SQL Server developer and DBA in mind. Try it now.

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  • How do you hibernate/suspend Ubuntu like Windows or both at the same time?

    - by All Star Geek
    I'm using an ASUS laptop with Windows 7, and I just installed Ubuntu alongside Windows yesterday, using the no-risk option. I noticed, though, that I can't hibernate Ubuntu the way I did with Windows to save time, and, every time I use Ubuntu, I have to shut down to go into Windows, which has a slow boot. Is there any way that I could have Windows and Ubuntu hibernated at the same time so I can access both easily (preferably without having to hit a function key within seconds). When I try to hibernate or suspend Ubuntu with Windows shut down, the screen just turns blue and doesn't shut the computer off like a Windows hibernate or sleep.

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  • Redirect output logs of javax.xml.ws and com.sun.xml.ws

    - by chrisnfoneur
    I am working on a SOAP based web service, with Sun's Metro. I am facing an annoying bug, each time I send a malformed SOAP object to my web service, sun's api spam the System.out with logs like this: javax.xml.ws.WebServiceException: com.sun.istack.XMLStreamException2: org.xml.sax.SAXParseException: cvc-complex-type.4: Attribute 'type' must appear on element 'object'. at com.sun.xml.ws.util.pipe.AbstractSchemaValidationTube.doProcess(AbstractSchemaValidationTube.java:206) at com.sun.xml.ws.util.pipe.AbstractSchemaValidationTube.processRequest(AbstractSchemaValidationTube.java:175) at com.sun.xml.ws.api.pipe.Fiber.__doRun(Fiber.java:595) at com.sun.xml.ws.api.pipe.Fiber._doRun(Fiber.java:554) at com.sun.xml.ws.api.pipe.Fiber.doRun(Fiber.java:539) at com.sun.xml.ws.api.pipe.Fiber.runSync(Fiber.java:436) at com.sun.xml.ws.server.WSEndpointImpl$2.process(WSEndpointImpl.java:243) at com.sun.xml.ws.transport.http.HttpAdapter$HttpToolkit.handle(HttpAdapter.java:444) at com.sun.xml.ws.transport.http.HttpAdapter.handle(HttpAdapter.java:244) at com.sun.xml.ws.transport.http.server.WSHttpHandler.handleExchange(WSHttpHandler.java:106) at com.sun.xml.ws.transport.http.server.WSHttpHandler.handle(WSHttpHandler.java:91) at com.sun.net.httpserver.Filter$Chain.doFilter(Filter.java:65) at sun.net.httpserver.AuthFilter.doFilter(AuthFilter.java:54) at com.sun.net.httpserver.Filter$Chain.doFilter(Filter.java:68) at sun.net.httpserver.ServerImpl$Exchange$LinkHandler.handle(ServerImpl.java:555) at com.sun.net.httpserver.Filter$Chain.doFilter(Filter.java:65) at sun.net.httpserver.ServerImpl$Exchange.run(ServerImpl.java:527) at sun.net.httpserver.ServerImpl$DefaultExecutor.execute(ServerImpl.java:119) at sun.net.httpserver.ServerImpl$Dispatcher.handle(ServerImpl.java:349) at sun.net.httpserver.ServerImpl$Dispatcher.run(ServerImpl.java:321) at java.lang.Thread.run(Thread.java:619) Caused by: com.sun.istack.XMLStreamException2: org.xml.sax.SAXParseException: cvc-complex-type.4: Attribute 'type' must appear on element 'object'. at com.sun.xml.ws.util.xml.StAXSource$1.parse(StAXSource.java:185) at com.sun.xml.ws.util.xml.StAXSource$1.parse(StAXSource.java:170) at org.apache.xerces.jaxp.validation.ValidatorHandlerImpl.validate(Unknown Source) at org.apache.xerces.jaxp.validation.ValidatorImpl.validate(Unknown Source) at javax.xml.validation.Validator.validate(Validator.java:127) at com.sun.xml.ws.util.pipe.AbstractSchemaValidationTube.doProcess(AbstractSchemaValidationTube.java:204) ... 20 more I would like to switch off this log or redirect it to my error/warn/debug.log files used by log4j. I tried to add a rule in my log4j.xml file : <category name="javax.xml.ws"> <priority value="error" /> </category> It didn't worked. So I tried the following trick: java.util.logging.Logger.getLogger("javax.xml.ws.WebServiceException").setLevel( java.util.logging.Level.OFF); it didn't worked neither. Any ideas ? It is not a big issue but it makes my catalina.log getting bigger & bigger and it's not the appropriate place for this kind of log. Chris

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  • How to include multiple XML files in a single XML file for deserialization by XmlSerializer in .NET

    - by harrydev
    Hi, is it possible to use the XmlSerializer in .NET to load an XML file which includes other XML files? And how? This, in order to share XML state easily in two "parent" XML files, e.g. AB and BC in below. Example: using System; using System.IO; using System.Xml.Serialization; namespace XmlSerializerMultipleFilesTest { [Serializable] public class A { public int Value { get; set; } } [Serializable] public class B { public double Value { get; set; } } [Serializable] public class C { public string Value { get; set; } } [Serializable] public class AB { public A A { get; set; } public B B { get; set; } } [Serializable] public class BC { public B B { get; set; } public C C { get; set; } } class Program { public static void Serialize<T>(T data, string filePath) { using (var writer = new StreamWriter(filePath)) { var xmlSerializer = new XmlSerializer(typeof(T)); xmlSerializer.Serialize(writer, data); } } public static T Deserialize<T>(string filePath) { using (var reader = new StreamReader(filePath)) { var xmlSerializer = new XmlSerializer(typeof(T)); return (T)xmlSerializer.Deserialize(reader); } } static void Main(string[] args) { const string fileNameA = @"A.xml"; const string fileNameB = @"B.xml"; const string fileNameC = @"C.xml"; const string fileNameAB = @"AB.xml"; const string fileNameBC = @"BC.xml"; var a = new A(){ Value = 42 }; var b = new B(){ Value = Math.PI }; var c = new C(){ Value = "Something rotten" }; Serialize(a, fileNameA); Serialize(b, fileNameB); Serialize(c, fileNameC); // How can AB and BC be deserialized from single // files which include two of the A, B or C files. // Using ideally something like: var ab = Deserialize<AB>(fileNameAB); var bc = Deserialize<BC>(fileNameBC); // That is, so that A, B, C xml file // contents are shared across these two } } } Thus, the A, B, C files contain the following: A.xml: <?xml version="1.0" encoding="utf-8"?> <A xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Value>42</Value> </A> B.xml: <?xml version="1.0" encoding="utf-8"?> <B xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Value>3.1415926535897931</Value> </B> C.xml: <?xml version="1.0" encoding="utf-8"?> <C xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Value>Something rotten</Value> </C> And then the "parent" XML files would contain a XML include file of some sort (I have not been able to find anything like this), such as: AB.xml: <?xml version="1.0" encoding="utf-8"?> <AB xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <A include="A.xml"/> <B include="B.xml"/> </AB> BC.xml: <?xml version="1.0" encoding="utf-8"?> <BC xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <B include="B.xml"/> <C include="C.xml"/> </BC> Of course, I guess this can be solved by implementing IXmlSerializer for AB and BC, but I was hoping there was an easier solution or a generic solution with which classes themselves only need the [Serializable] attribute and nothing else. That is, the split into multiple files is XML only and handled by XmlSerializer itself or a custom generic serializer on top of this. I know this should be somewhat possible with app.config (as in http://stackoverflow.com/questions/480538/use-xml-includes-or-config-references-in-app-config-to-include-other-config-files), but I would prefer a solution based on XmlSerializer. Thanks.

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  • JPA 2 and Hibernate 3.5.1 MEMBER OF query doesnt work.

    - by Ed_Zero
    I'm trying the following JPQL and it fails misserably: Query query = em.createQuery("SELECT u FROM User u WHERE 'admin' MEMBER OF u.roles"); List users = query.query.getResultList(); I get the following exception: ERROR [main] PARSER.error(454) | <AST>:0:0: unexpected end of subtree java.lang.IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException: unexpected end of subtree [SELECT u FROM com.online.data.User u WHERE 'admin' MEMBER OF u.roles] ERROR [main] PARSER.error(454) | <AST>:0:0: expecting "from", found '<ASTNULL>' ... ... Caused by: org.hibernate.hql.ast.QuerySyntaxException: unexpected end of subtree [SELECT u FROM com.online.data.User u WHERE 'admin' MEMBER OF u.roles] I have Spring 3.0.1.RELEASE, Hibernate 3.5.1-Final and maven to glue dependencies. User class: @Entity public class User { @Id @Column(name = "USER_ID") @GeneratedValue(strategy = GenerationType.IDENTITY) private long id; @Column(unique = true, nullable = false) private String username; private boolean enabled; @ElementCollection private Set<String> roles = new HashSet<String>(); ... } Spring configuration: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:p="http://www.springframework.org/schema/p" xmlns:aop="http://www.springframework.org/schema/aop" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/tx/spring-context-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd"> <!-- Reading annotation driven configuration --> <tx:annotation-driven transaction-manager="transactionManager" /> <bean class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor" /> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" /> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> <property name="maxActive" value="100" /> <property name="maxWait" value="1000" /> <property name="poolPreparedStatements" value="true" /> <property name="defaultAutoCommit" value="true" /> </bean> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> <property name="dataSource" ref="dataSource" /> </bean> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="showSql" value="true" /> <property name="databasePlatform" value="${hibernate.dialect}" /> </bean> </property> <property name="loadTimeWeaver"> <bean class="org.springframework.instrument.classloading.InstrumentationLoadTimeWeaver" /> </property> <property name="jpaProperties"> <props> <prop key="hibernate.hbm2ddl.auto">update</prop> <prop key="hibernate.current_session_context_class">thread</prop> <prop key="hibernate.cache.provider_class">org.hibernate.cache.NoCacheProvider</prop> <prop key="hibernate.show_sql">true</prop> <prop key="hibernate.format_sql">false</prop> <prop key="hibernate.show_comments">true</prop> </props> </property> <property name="persistenceUnitName" value="punit" /> </bean> <bean id="JpaTemplate" class="org.springframework.orm.jpa.JpaTemplate"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> </beans> Persistence.xml <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence"> <persistence-unit name="punit" transaction-type="RESOURCE_LOCAL" /> </persistence> pom.xml maven dependencies. <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate</artifactId> <version>${hibernate.version}</version> <type>pom</type> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-core</artifactId> <version>${hibernate.version}</version> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-annotations</artifactId> <version>${hibernate.version}</version> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-entitymanager</artifactId> <version>${hibernate.version}</version> </dependency> <dependency> <groupId>commons-dbcp</groupId> <artifactId>commons-dbcp</artifactId> <version>1.2.2</version> <type>jar</type> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-web</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-config</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-taglibs</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-acl</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>javax.annotation</groupId> <artifactId>jsr250-api</artifactId> <version>1.0</version> </dependency> <properties> <!-- Application settings --> <spring.version>3.0.1.RELEASE</spring.version> <hibernate.version>3.5.1-Final</hibernate.version> Im running a unit test to check the configuration and I am able to run other JPQL queries the only ones that I am unable to run are the IS EMPTY, MEMBER OF conditions. The complete unit test is as follows: TestIntegration @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations = { "/spring/dataLayer.xml"}) @Transactional @TransactionConfiguration public class TestUserDaoImplIntegration { @PersistenceContext private EntityManager em; @Test public void shouldTest() throws Exception { try { //WORKS Query query = em.createQuery("SELECT u FROM User u WHERE 'admin' in elements(u.roles)"); List users = query.query.getResultList(); //DOES NOT WORK } catch (Exception e) { e.printStackTrace(); throw e; } try { Query query = em.createQuery("SELECT u FROM User u WHERE 'admin' MEMBER OF u.roles"); List users = query.query.getResultList(); } catch (Exception e) { e.printStackTrace(); throw e; } } }

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  • Optional one-to-one mapping in Hibernate

    - by hibernate
    How do I create an optional one-to-one mapping in the hibernate hbm file? For example, suppose that I have a User and a last_visited_page table. The user may or may not have a last_visited page. Here is my current one-to-one mapping in the hbm file: User Class: <one-to-one name="lastVisitedPage" class="LastVisitedPage" cascade="save-update"> LastVisitedPage Class: <one-to-one name="user" class="user" constrained="true" /> The above example does not allow the creation of a user who does not have a last visited page. A freshly created user has not visited any pages yet. How do I change the hbm mapping to make the userPrefs mapping optional?

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  • XML serialization query

    - by David Neale
    I have the following XML which needs deserializing/serializing: <instance> <dog> <items> <item> <label>Spaniel</label> </item> </items> </dog> <cat> <items> <item> <label>Tabby</label> </item> </items> </cat> </instance> I cannot change the XML structure. I need to map this to the following class: [Serializable, XmlRoot("instance")] public class AnimalInstance { public string Dog { get; set; } public string Cat { get; set; } } I'm not really sure where to start on this one without manually parsing the XML. I'd like to keep the code as brief as possible. Any ideas? (and no, my project doesn't actually involve cats and dogs).

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  • How to set up hibernate to use Glassfish connection pool?

    - by jschoen
    I have set up a connection pool in Glassfish with a jndi resource for it also setup. I am stumped on how to configure hibernate to go get it. I have come across alot of write ups to configure it to use C3P0 connection pool. Well I am lost. I found that I need to set: hibernate.connection.datasource hibernate.jndi.url hibernate.jndi.class hibernate.connection.username hibernate.connection.password Would datasource be the same as the hibernate.connection.datasource set in the connection pool? What would hibernate.jndi.class be? Are hibernate.connection.username and hibernate.connection.password for the connection to the database or to the appserver? I assume this is to the database, but why do I need them since that is all set in the appserver?

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  • XML to Type - Quick way?

    - by MRFerocius
    Team; How are you doing? Im breaking my head trying to do this that seems simple but I can't figure it out... Suppose I have this XML as a string: <calles> <calle> <nombre>CALLAO AV.</nombre> <altura>1500</altura> <longitud>-58.3918617027</longitud> <latitud>-34.5916734896</latitud> <barrio>Recoleta</barrio> </calle> </calles> And and have this Type I created to map that XML: public class Ubicacion { public string Latitud { get; set; } public string Longitud { get; set; } public string Nombre { get; set; } public string Altura { get; set; } public string Barrio { get; set; } public Ubicacion() { } } I need to take that XML file and create an object with those values... Does somebody know a quick way to do it? with C#? I have been trying this but is not working at all... XElement dir = XElement.Parse(text); Ubicacion informacion = from d in dir.Elements("calle"). select new Ubicacion { Longitud = d.Element("longitud").Value, Latitud = d.Element("latitud").Value, Altura = d.Element("altura").Value, Nombre = d.Element("nombre").Value, Barrio = d.Element("barrio").Value, }; return informacion.Cast<Ubicacion>(); } Any ideas? Thanks!!!

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  • How to retain XML string as a string field during XML deserialization

    - by detale
    I got an XML input string and want to deserialize it to an object which partially retain the raw XML. <SetProfile> <sessionId>A81D83BC-09A0-4E32-B440-0000033D7AAD</sessionId> <profileDataXml> <ArrayOfProfileItem> <ProfileItem> <Name>Pulse</Name> <Value>80</Value> </ProfileItem> <ProfileItem> <Name>BloodPresure</Name> <Value>120</Value> </ProfileItem> </ArrayOfProfileItem> </profileDataXml> </SetProfile> The class definition: public class SetProfile { public Guid sessionId; public string profileDataXml; } I hope the deserialization syntax looks like string inputXML = "..."; // the above XML XmlSerializer xs = new XmlSerializer(typeof(SetProfile)); using (TextReader reader = new StringReader(inputXML)) { SetProfile obj = (SetProfile)xs.Deserialize(reader); // use obj .... } but XMLSerializer will throw an exception and won't output < profileDataXml 's descendants to "profileDataXml" field in raw XML string. Is there any way to implement the deserialization like that?

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  • Hibernate unknown entity (not missing @Entity or import javax.persistence.Entity )

    - by david99world
    I've got a really simple class... import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; import javax.persistence.Table; @Entity @Table(name = "users") public class User { @Column(name = "firstName") private String firstName; @Column(name = "lastName") private String lastName; @Column(name = "email") private String email; @Id @GeneratedValue(strategy=GenerationType.AUTO) @Column(name = "id") private long id; public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } public long getId() { return id; } public void setId(long id) { this.id = id; } } I call it using... public class Main { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub HibernateUtil.buildSessionFactory(); Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User u = new User(); u.setEmail("[email protected]"); u.setFirstName("David"); u.setLastName("Gray"); session.save(u); session.getTransaction().commit(); System.out.println("Record committed"); session.close(); } } I keep getting... Exception in thread "main" org.hibernate.MappingException: Unknown entity: org.assessme.com.entity.User at org.hibernate.internal.SessionFactoryImpl.getEntityPersister(SessionFactoryImpl.java:1172) at org.hibernate.internal.SessionImpl.getEntityPersister(SessionImpl.java:1316) at org.hibernate.event.internal.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:117) at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:204) at org.hibernate.event.internal.DefaultSaveEventListener.saveWithGeneratedOrRequestedId(DefaultSaveEventListener.java:55) at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:189) at org.hibernate.event.internal.DefaultSaveEventListener.performSaveOrUpdate(DefaultSaveEventListener.java:49) at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:90) at org.hibernate.internal.SessionImpl.fireSave(SessionImpl.java:670) at org.hibernate.internal.SessionImpl.save(SessionImpl.java:662) at org.hibernate.internal.SessionImpl.save(SessionImpl.java:658) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:601) at org.hibernate.context.internal.ThreadLocalSessionContext$TransactionProtectionWrapper.invoke(ThreadLocalSessionContext.java:352) at $Proxy4.save(Unknown Source) at Main.main(Main.java:20) hibernateUtil is... import org.hibernate.SessionFactory; import org.hibernate.cfg.Configuration; import org.hibernate.service.ServiceRegistry; import org.hibernate.service.ServiceRegistryBuilder; public class HibernateUtil { private static SessionFactory sessionFactory; private static ServiceRegistry serviceRegistry; public static SessionFactory buildSessionFactory() { try { // Create the SessionFactory from hibernate.cfg.xml Configuration configuration = new Configuration(); configuration.configure(); serviceRegistry = new ServiceRegistryBuilder().applySettings(configuration.getProperties()).buildServiceRegistry(); return new Configuration().configure().buildSessionFactory(serviceRegistry); } catch (Throwable ex) { // Make sure you log the exception, as it might be swallowed System.err.println("Initial SessionFactory creation failed." + ex); throw new ExceptionInInitializerError(ex); } } public static SessionFactory getSessionFactory() { sessionFactory = new Configuration().configure().buildSessionFactory(serviceRegistry); return sessionFactory; } } does anyone have any ideas as I've looked at so many duplicates but the resolutions don't appear to work for me. hibernate.cfg.xml shown below... <?xml version='1.0' encoding='utf-8'?> <!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> <hibernate-configuration> <session-factory> <!-- Database connection settings --> <property name="connection.driver_class">com.mysql.jdbc.Driver</property> <property name="connection.url">jdbc:mysql://localhost/ssme</property> <property name="connection.username">root</property> <property name="connection.password">mypassword</property> <!-- JDBC connection pool (use the built-in) --> <property name="connection.pool_size">1</property> <!-- SQL dialect --> <property name="dialect">org.hibernate.dialect.MySQLDialect</property> <!-- Enable Hibernate's automatic session context management --> <property name="current_session_context_class">thread</property> <!-- Disable the second-level cache --> <property name="cache.provider_class">org.hibernate.cache.NoCacheProvider</property> <!-- Echo all executed SQL to stdout --> <property name="show_sql">true</property> <!-- Drop and re-create the database schema on startup --> <property name="hbm2ddl.auto">update</property> </session-factory> </hibernate-configuration>

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  • XML Schema and element with type string

    - by svick
    I'm trying to create an XML Schema and I'm stuck. It seems I can't define an element with string content. What am I doing wrong? Schema: <?xml version="1.0"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://ponderka.wz.cz/MusicLibrary0" targetNamespace="http://ponderka.wz.cz/MusicLibrary0"> <xs:element name="music-library"> <xs:complexType> <xs:sequence> <xs:element name="artist" type="xs:string"/> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> Document: <?xml version="1.0"?> <music-library xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://ponderka.wz.cz/MusicLibrary0 data0.xsd" xmlns="http://ponderka.wz.cz/MusicLibrary0"> <artist>a</artist> </music-library> The validator says: Element <artist> is not allowed under element <music-library>. Reason: The following elements are expected at this location (see below) <artist> Error location: music-library / artist Details cvc-model-group: Element <artist> unexpected by type '{anonymous}' of element <music-library>. cvc-elt.5.2.1: The element <music-library> is not valid with respect to the actual type definition '{anonymous}'.

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  • C# LINQ to XML missing space character.

    - by Fossaw
    I write an XML file "by hand", (i.e. not with LINQ to XML), which sometimes includes an open/close tag containing a single space character. Upon viewing the resulting file, all appears correct, example below... <Item> <ItemNumber>3</ItemNumber> <English> </English> <Translation>Ignore this one. Do not remove.</Translation> </Item> ... the reasons for doing this are various and irrelevent, it is done. Later, I use a C# program with LINQ to XML to read the file back and extract the record... XElement X_EnglishE = null; // This is CRAZY foreach (XElement i in Records) { X_EnglishE = i.Element("English"); // There is only one damned record! } string X_English = X_EnglishE.ToString(); ... and test to make sure it is unchanged from the database record. I detect a change, when processing Items where the field had the single space character... +E+ Text[3] English source has been altered: Was: >>> <<< Now: >>><<< ... the and <<< parts I added to see what was happening, (hard to see space characters). I have fiddled around with this but can't see why this is so. It is not absolutely critical, as the field is not used, (yet), but I cannot trust C# or LINQ or whatever is doing this, if I do not understand why it is so. So what is doing that and why?

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  • HELP with XML to XML transformation using XSLT.

    - by kaniths
    Am a rookie trying XSLT and XML tranformations for the first time. To start off, i tried a simple sample programs. I expected the Output in Tree format (maintaining the hierarchy) instead i just get " KING" in single line... What could be the problem? PS: I use XMLSpy. Any guideline would be great full. Thanks :) Input XML: <ROWSET> <ROW> <EMPNO>7839</EMPNO> <ENAME>KING</ENAME> </ROW> </ROWSET> XSL used for transformation: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" encoding="UTF-8" indent="yes" omit-xml-declaration="no"/> <xsl:template match="/"> <Invitation> <To> <xsl:value-of select="ROWSET/ROW/ENAME"/> </To> </Invitation> </xsl:template>

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  • how to compare the two xml files and update the one xml file in java?

    - by prasad.gai
    I have created two xml files from those xml file i would like to compare one xml file with another xml file and update the xml file. I have created an xml file as follows: main.xml <?xml version="1.0" encoding="utf-8"?> <ScrollView xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="#00BFFF"> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical"> <LinearLayout android:id="@+id/linearLayout1" android:layout_width="fill_parent" android:layout_height="wrap_content" android:gravity="center" android:visibility="visible"> </LinearLayout> <LinearLayout android:id="@+id/linearLayout2" android:layout_width="fill_parent" android:layout_height="wrap_content" android:gravity="center" android:visibility="visible"> </LinearLayout> </LinearLayout> </ScrollView> properties.xml <?xml version='1.0' encoding='utf-8' standalone='yes' ?> <map> <int name="linearLayout1" value="8" /> <int name="linearLayout2" value="0" /> </map> from the above two xml files i would like to compare with LinearLayout android:id ="@id/LinearLayout1" from main.xml with int name ="linearLayout1" from properties.xml. from the above properties.xml file where name ="linearLayout1" and value ="8" then i would like to update the main.xml file where as LinearLayout android:id="@id/linearLayout1" propertie value as android:visibility="gone" From the above xml file how can i update main.xml file by comparing properties.xml? please any body help me.....

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  • How to sett up hibernate to use Glassfish connection pool?

    - by jschoen
    I have set up a connection pool in Glassfish with a jndi resource for it also setup. I am stumped on how to configure hibernate to go get it. I have come across alot of write ups to configure it to use C3P0 connection pool. Well I am lost. I found that I need to set: hibernate.connection.datasource hibernate.jndi.url hibernate.jndi.class hibernate.connection.username hibernate.connection.password Would datasource be the same as the hibernate.connection.datasource set in the connection pool? What would hibernate.jndi.class be? Are hibernate.connection.username and hibernate.connection.password for the connection to the database or to the appserver? I assume this is to the database, but why do I need them since that is all set in the appserver?

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  • How to parse a custom XML-style error code response from a website

    - by user1870127
    I'm developing a program that queries and prints out open data from the local transit authority, which is returned in the form of an XML response. Normally, when there are buses scheduled to run in the next few hours (and in other typical situations), the XML response generated by the page is handled correctly by the java.net.URLConnection.getInputStream() function, and I am able to print the individual results afterwards. The problem is when the buses are NOT running, or when some other problem with my queries develops after it is sent to the transit authority's web server. When the authority developed their service, they came up with their own unique error response codes, which are also sent as XMLs. For example, one of these error messages might look like this: <Error xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <Code>3005</Code> <Message>Sorry, no stop estimates found for given values.</Message> </Error> (This code and similar is all that I receive from the transit authority in such situations.) However, it appears that URLConnection.getInputStream() and some of its siblings are unable to interpret this custom code as a "valid" response that I can handle and print out as an error message. Instead, they give me a more generic HTTP/1.1 404 Not Found error. This problem cascades into my program which then prints out a java.io.FileNotFoundException error pointing to the offending input stream. My question is therefore two-fold: 1. Is there a way to retrieve, parse, and print a custom XML-formatted error code sent by a web service using the plugins that are available in Java? 2. If the above is not possible, what other tools should I use or develop to handle such custom codes as described?

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  • Exporting to XML, including embedded classes

    - by Andy
    I have an object config which has some properties. I can export this ok, however, it also has an ArrayList which relates to embedded classes which I can't get to appear when I export to XML. Any pointers would be helpful. Export Method public String exportXML(config conf, String path) { String success = ""; try { FileOutputStream fstream = new FileOutputStream(path); try { XMLEncoder ostream = new XMLEncoder(fstream); try { ostream.writeObject(conf); ostream.flush(); } finally { ostream.close(); } } finally { fstream.close(); } } catch (Exception ex) { success = ex.getLocalizedMessage(); } return success; } Config Class (some detail stripped to keep size down) public class config { protected String author = ""; protected String website = ""; private ArrayList questions = new ArrayList(); public config(){ } public void addQuestion(String name) { questions.add(new question(questions.size(), name)); } public void removeQuestion(int id) { questions.remove(id); for (int c = 0; c <= questions.size(); c++) { question q = (question) (questions.get(id)); q.setId(c); } questions.trimToSize(); } public config.question getQuestion(int id){ return (question)questions.get(id); } /** * There can be multiple questions per config. * Questions store all the information regarding what questions are * asked of the user, including images, descriptions, and answers. */ public class question { protected int id; protected String title; protected ArrayList answers; public question(int id, String title) { this.id = id; this.title = title; } public int getId() { return id; } public void setId(int id) { this.id = id; } public void addAnswer(String name) { answers.add(new answer(answers.size(), name)); } public void removeAnswer(int id) { answers.remove(id); for (int c = 0; c <= answers.size(); c++) { answer a = (answer) (answers.get(id)); a.setId(c); } answers.trimToSize(); } public config.question.answer getAnswer(int id){ return (answer)answers.get(id); } public class answer { protected int id; protected String title; public answer(int id, String title) { this.id = id; this.title = title; } public int getId() { return id; } public void setId(int id) { this.id = id; } } } } Resultant XML File <?xml version="1.0" encoding="UTF-8"?> <java version="1.6.0_18" class="java.beans.XMLDecoder"> <object class="libConfig.config"> <void property="appName"> <string>xxx</string> </void> <void property="author"> <string>Andy</string> </void> <void property="website"> <string>www.example.com/dsx.xml</string> </void> </object> </java>

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