Search Results

Search found 1657 results on 67 pages for 'jeff mc'.

Page 16/67 | < Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23  | Next Page >

  • Hashtable/Dictionary but with key composed of multiple values?

    - by MC
    Lets say I have an object that has stringProp1, stringProp2. I wish to store each combination of stringProp1, stringProp2 in a Dictionary. Initially I was storing the key as key = stringProp1+stringProp2 but this can actually cause a bug depending on the 2 values. Is the best solution for this problem to create a custom dictionary class or is there a better way using built-in .NET classes?

    Read the article

  • Android multiple screen sizes and density problems

    - by Ben Mc
    I'm having a real problem with my drawables that I just can't seem to figure out. The problem is this: There are screen sizes at approximately 320x480, 480x800, 480x854 Then there are most commonly densities at 1.0 (160) and 1.5 (240) Now, on a Droid, the screen size is 480x800 and the density is reporting using DisplayMetrics as 1.5 On the G1, it's 320x480 and reporting back at a density of 1.0 BUT tablet devices are reporting back at 480x800 with a density of 1.0 (160) So, I'm going mad because I can put 320x480 images in the drawables-mdpi folder and 480x800 images in the drawables-hdpi folder, but on Tablet computers, no matter what it's not resizing up anything to a full screen. Any help would be greatly appreciated. I just want all of my 320x480 images to scale up regardless of the device.

    Read the article

  • Showing a loading spinner only if the data has not been cached.

    - by Aaron Mc Adam
    Hi guys, Currently, my code shows a loading spinner gif, returns the data and caches it. However, once the data has been cached, there is a flicker of the loading gif for a split second before the data gets loaded in. It's distracting and I'd like to get rid of it. I think I'm using the wrong method in the beforeSend function here: $.ajax({ type : "GET", cache : false, url : "book_data.php", data : { keywords : keywords, page : page }, beforeSend : function() { $('.jPag-pages li:not(.cached)').each(function (i) { $('#searchResults').html('<p id="loader">Loading...<img src="../assets/images/ajax-loader.gif" alt="Loading..." /></p>'); }); }, success : function(data) { $('.jPag-current').parent().addClass('cached'); $('#searchResults').replaceWith($(data).find('#searchResults')).find('table.sortable tbody tr:odd').addClass('odd'); detailPage(); selectForm(); } });

    Read the article

  • Drawing bitmaps faster on Android canvas or OpenGL

    - by Ben Mc
    I currently have a game written using the Android canvas. It is completely 2D, and I draw bitmaps as sprites on the canvas, and it technically works, but I have a few features that I need to add that will require drawing many more bitmaps on the screen, and there will be a lot more movement. The app needs more power. What is the best way to go from this method of drawing Bitmaps on a canvas to using OpenGL so I can draw them faster?

    Read the article

  • List of objects plus a tag

    - by MC
    I want to store a list of objects, lets say of type Car, but with an additional 'tag' property eg a boolean True/False which does not belong on the Car class. What is the best way to accomplish this? I need to pass the result between methods.

    Read the article

  • Configuring a Context specific Tomcat Security Realm

    - by Andy Mc
    I am trying to get a context specific security Realm in Tomcat 6.0, but when I start Tomcat I get the following error: 09-Dec-2010 16:12:40 org.apache.catalina.startup.ContextConfig validateSecurityRoles INFO: WARNING: Security role name myrole used in an <auth-constraint> without being defined in a <security-role> I have created the following context.xml file: <Context debug="0" reloadable="true"> <Resource name="MyUserDatabase" type="org.apache.catalina.UserDatabase" description="User database that can be updated and saved" factory="org.apache.catalina.users.MemoryUserDatabaseFactory" pathname="conf/my-users.xml" /> <Realm className="org.apache.catalina.realm.UserDatabaseRealm" resourceName="MyUserDatabase"/> </Context> Created a file: my-users.xml which I have placed under WEB-INF/conf which contains the following: <tomcat-users> <role rolename="myrole"/> <user username="test" password="changeit" roles="myrole" /> </tomcat-users> Added the following lines to my web.xml file: <web-app ...> ... <security-constraint> <web-resource-collection> <web-resource-name>Entire Application</web-resource-name> <url-pattern>/*</url-pattern> </web-resource-collection> <auth-constraint> <role-name>myrole</role-name> </auth-constraint> </security-constraint> <login-config> <auth-method>BASIC</auth-method> </login-config> ... </web-app> But seem to get the error wherever I put conf/my-users.xml. Do I have to specify an explicit PATH in the pathname or is it relative to somewhere? Ideally I would like to have it packaged up as part of my WAR file. Any ideas?

    Read the article

  • Which Android platform and API to target?

    - by Ben Mc
    I'm just about to launch my first Android app, and it runs on the Android 1.1 platform, API Level 2, but is this what I should officially sign and launch the app as? Does it affect performance at all or is it simply for Android to know which devices it works on? The only problem I see is that I can't specify <supports-screens> in the Manifest, which I would like to do, but it appears I'd have to launch at 1.6 at least for this to work. Would I be missing a huge number of phones by launching at 1.6 instead of 1.1? Thank you!

    Read the article

  • Class design when working with dataset

    - by MC
    If you have to retrieve data from a database and bring this dataset to the client, and then allow the user to manipulate the data in various ways before updating the database again, what is a good class design for this if the data tables will not have a 1:1 relationship with the class objects? Here are some I came up with: Just manipulate the DataSet itself on the client and then send it back to the database as is. This will work though obviously the code will be very dirty and not well-structured. Same as #1, but wrap the dataset code around classes. What I mean is that you may have a class that takes a dataset or a datatable in its constructor, and then provides public methods and properties to simplify the code. Inside these methods and properties it will be reading or manipulating the dataset. To update the database afterwards will be easy because you already have the updated dataset. Get rid of the dataset entirely on the client, convert to objects, then convert back to a dataset when needing to update the database. Is there any good resources where I can find information on this?

    Read the article

  • jQuery pagination without all the rows of data before hand

    - by Aaron Mc Adam
    Hi guys, I'm trying to find a solution for paginating my search results. I have a built the links and everything works without jQuery. I've also got AJAX working for the links, but I just need a way of tidying up the list of links, as some search results return up to 60 pages and the links spread to two rows in my template. I am searching the Amazon API, and can only return 10 results at a time. Upon clicking the pagination links, the next 10 results are returned. I have access to the total results number from the XML, but not all the data at once, so I can't put all the data into a "hiddenResults" div that the jQuery Pagination plugin needs. Here is the jQuery I have for the pagination: var $pagination = $("#pagination ul"); $pagination.delegate('.pagenumbers', 'click', function() { var $$this = $(this); $$this.closest('li').addClass('cached'); $pagination.find("#currentPage").removeAttr('id').wrapInner($('<a>', {'class':'pagenumbers', 'href':'book_data.php?keywords='+keywords})); $$this.closest('li').attr('id','currentPage').html( $$this.text() ); $.ajax({ type : "GET", cache : false, url : "book_data.php", data : { keywords : keywords, page : $$this.text() }, success : show_results }); return false; }); function show_results(res) { $("#searchResults").replaceWith($(res).find('#searchResults')).find('table.sortable tbody tr:odd').addClass('odd'); detailPage(); selectForm(); if ( ! ( $pagination.find('li').hasClass('cached') ) ) { $.get("book_data.php", { keywords : keywords, page : ( $pagination.find("#currentPage").text() + 1 ) } ); } }

    Read the article

  • Excel, VBA Vlookup, multiple returns into rows

    - by Sean Mc
    Very new to VBA, so please excuse my ignorance. How would you alter the code below to return the result into rows as opposed to a string? Thanks in advance.... data Acct No CropType ------- --------- 0001 Grain 0001 OilSeed 0001 Hay 0002 Grain function =vlookupall("0001", A:A, 1, " ") Here is the code: Function VLookupAll(ByVal lookup_value As String, _ ByVal lookup_column As range, _ ByVal return_value_column As Long, _ Optional seperator As String = ", ") As String Application.ScreenUpdating = False Dim i As Long Dim result As String For i = 1 To lookup_column.Rows.count If Len(lookup_column(i, 1).text) <> 0 Then If lookup_column(i, 1).text = lookup_value Then result = result & (lookup_column(i).offset(0, return_value_column).text & seperator) End If End If Next If Len(result) <> 0 Then result = Left(result, Len(result) - Len(seperator)) End If VLookupAll = result Application.ScreenUpdating = True End FunctionNotes:

    Read the article

  • UITextView cut problem !

    - by Mc.Lover
    Hi , i have problem with cut some text from UITextView , i idon't understand how can implement Cut , for example copy or paste it's like this : -(IBAction)copy { NSString *copyString = [[NSString alloc] initWithFormat:@"%@",[textPad text]]; UIPasteboard *pb = [UIPasteboard generalPasteboard]; [pb setString:copyString]; } -(IBAction)paste { UIPasteboard *pb = [UIPasteboard generalPasteboard]; textPad.text = [pb string]; } but about cut ! thank you ,

    Read the article

  • UITextView cut problem ! (iPhone sdk)

    - by Mc.Lover
    Hi , i have problem with cut some text from UITextView , i idon't understand how can implement Cut , for example copy or paste it's like this : -(IBAction)copy { NSString *copyString = [[NSString alloc] initWithFormat:@"%@",[textPad text]]; UIPasteboard *pb = [UIPasteboard generalPasteboard]; [pb setString:copyString]; } -(IBAction)paste { UIPasteboard *pb = [UIPasteboard generalPasteboard]; textPad.text = [pb string]; } but about cut ! thank you ,

    Read the article

  • Calculate angle of moving ball after collision with angled or sloped wall that is a 2D line segment

    - by Ben Mc
    If you have a "ball" inside a 2D polygon, made up of say, 4 line segments that act as bounding walls, how do you calculate the angle of the ball after the collision with the irregularly sloped wall? I know how to make the ball bounce if the wall is horizontal, vertical, or at a 45 degree angle. I also have my code setup to detect a collision with the wall. I've read about dot products and normals, but I cannot figure out how to implement these in Java / Android. I'm completely stumped and feel like I've looked up everything 10 pages deep in Google 10 times now. I'm burned out trying to figure this out, I hope someone can help.

    Read the article

  • How do I restrict foreign keys choices to related objects only in django

    - by Jeff Mc
    I have a two way foreign relation similar to the following class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True) class Child(models.Model): name = models.CharField(max_length=255) myparent = models.ForeignKey(Parent) How do I restrict the choices for Parent.favoritechild to only children whose parent is itself? I tried class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True, limit_choices_to = {"myparent": "self"}) but that causes the admin interface to not list any children.

    Read the article

  • Database concurrency issue in .NET application

    - by MC.
    If userA deleted OrderA while userB is modifying OrderA, then userB saves OrderA then there is no order in the database to be updated. My problem is there is no error! The SqlDataAdapter.Update succeeds and returns a "1" indicating a record was modified when this is not true. Does anybody know how this is supposed to work, thanks.

    Read the article

  • Violation of primary key constraint, multiple users

    - by MC.
    Lets say UserA and UserB both have an application open and are working with the same type of data. UserA inserts a record into the table with value 10 (PrimaryKey='A'), UserB does not currently see the value UserA entered and attempts to insert a new value of 20 (PrimaryKey='A'). What I wanted in this situation was a DBConcurrencyException, but instead what I have is a primary key violation. I understand why, but I have no idea how to resolve this. What is a good practice to deal with such a circumstance? I do not want to merge before updating the database because I want an error to inform the user that multiple users updated this data.

    Read the article

  • The program fails to display `cout` when it is run

    - by Jeff - FL
    Hello, I justed started a C++ course & I wrote, compiled, debugged & ran my first program: // This program calculates how much a little league team spent last year to purchase new baseballs. #include <iostream> using namespace std; int baseballs; int cost; int total; int main() { baseballs, cost, total; // Get the number of baseballs were purchased. cout << "How many baseballs were purchased? "; cin >> baseballs; // Get the cost of baseballs purchased. cout << "What was the cost of each baseball purchased? "; cin >> cost; // Calculate the total. total = baseballs * cost; // Display the total. cout << "The total amount spent $" << total << endl; return 0; } The only probelm that I encountered was that when I ran the program it failed to display the total amount spent (cout). Could someone please explain why? Thanks Jeff H - Sarasota, FL

    Read the article

  • Tools for displaying text, powerpoint style, in linux

    - by Will Mc
    I have a problem where I need a way to display a repeating series of "images" on a computer monitor. Specifically, given a series of text files, I'd like a way to display the contents of said files on a screen in a way much like a powerpoint would. My current thoughts are to find some tool that will take in a text file of some format, and then output an image which contains the text from the file. Then I'd put it in a directory and have some Slideshow program continuously go between the images in that directory. It's a very hacky solution, obviously. So, does anyone know of tools that would do such a thing? Or is there a better way to do this? I've looked into the library libgd2, but it doesn't seem to support text-wrapping for images, which is something I'd need. Thanks!

    Read the article

  • Kerberos & signle-sign-on for website

    - by Dylan Klomparens
    I have a website running on a Linux computer using Apache. I've employed mod_auth_kerb for single-sign-on Kerberos authentication against a Windows Active Directory server. In order for Kerberos to work correctly, I've created a service account in Active Directory called dummy. I've generated a keytab for the Linux web server using ktpass.exe on the Windows AD server using this command: ktpass /out C:\krb5.keytab /princ HTTP/[email protected] /mapuser [email protected] /crypto RC4-HMAC-NT /ptype KRB5_NT_PRINCIPAL /pass xxxxxxxxx I can successfully get a ticket from the Linux web server using this command: kinit -k -t /path/to/keytab HTTP/[email protected] ... and view the ticket with klist. I have also configured my web server with these Kerberos properties: <Directory /> AuthType Kerberos AuthName "Example.com Kerberos domain" KrbMethodK5Passwd Off KrbAuthRealms EXAMPLE.COM KrbServiceName HTTP/[email protected] Krb5KeyTab /path/to/keytab Require valid-user SSLRequireSSL <Files wsgi.py> Order deny,allow Allow from all </Files> </Directory> However, when I attempt to log in to the website (from another Desktop with username 'Jeff') my Kerberos credentials are not automatically accepted by the web server. It should grant me access immediately after that, but it does not. The only information I get from the mod_auth_kerb logs is: kerb_authenticate_user entered with user (NULL) and auth_type Kerberos However, more information is revealed when I change the mod_auth_kerb setting KrbMethodK5Passwd to On: [Fri Oct 18 17:26:44 2013] [debug] src/mod_auth_kerb.c(1939): [client xxx.xxx.xxx.xxx] kerb_authenticate_user entered with user (NULL) and auth_type Kerberos [Fri Oct 18 17:26:44 2013] [debug] src/mod_auth_kerb.c(1031): [client xxx.xxx.xxx.xxx] Using HTTP/[email protected] as server principal for password verification [Fri Oct 18 17:26:44 2013] [debug] src/mod_auth_kerb.c(735): [client xxx.xxx.xxx.xxx] Trying to get TGT for user [email protected] [Fri Oct 18 17:26:44 2013] [debug] src/mod_auth_kerb.c(645): [client xxx.xxx.xxx.xxx] Trying to verify authenticity of KDC using principal HTTP/[email protected] [Fri Oct 18 17:26:44 2013] [debug] src/mod_auth_kerb.c(1110): [client xxx.xxx.xxx.xxx] kerb_authenticate_user_krb5pwd ret=0 [email protected] authtype=Basic What am I missing? I've studied a lot of online tutorials and cannot find a reason why the Kerberos credentials are not allowing access.

    Read the article

  • SendMail not working in CentOs 6.4

    - by Kane
    I am trying to send e-mails from my CentOS 6.4 but it does not work. My knowledge about servers is quite limited, so I hope someone can help me. Here is what I did: First i tried to send an email using the "mail" command, but it was not in the OS so I installed it. # yum install mailx After that, I tried sending an email using the "mail" command, but it did not send anything. I checked it on the internet and I realized I needed an e-mail server like sendmail, so I installed it. # yum install sendmail sendmail-cf sendmail-doc sendmail-devel After that, I configured it following some tutorials. First, sendmail.mc file. # vi /etc/mail/sendmail.mc Commented out the next line: BEFORE # DAEMON_OPTIONS('Port=smtp, Name=MTA') dnl AFTER # dnl DAEMON_OPTIONS('Port=smtp, Name=MTA') dnl Check that the next lines are correct: # FEATURE(`virtusertable', `hash -o /etc/mail/virtusertable.db')dnl # ... # FEATURE(use_cw_file)dnl # ... # FEATURE(`access_db', `hash -T<TMPF> -o /etc/mail/access.db')dnl Update sendmail.cf # m4 /etc/mail/sendmail.mc > /etc/mail/sendmail.cf Open the port 25 adding the proper line in the iptables file # vi /etc/sysconfig/iptables # -A INPUT -m state --state NEW -m tcp --dport 25 -j ACCEPT restart iptables and sendmail # service iptables restart # service sendmail restart So i thought that would be ok, but when i tried: # mail '[email protected]' # Subject: test subject # test content #. I checked the mail log: # vi /var/log/maillog And that is what I found: Aug 14 17:36:24 dev-admin-test sendmail[20682]: r7D8RItS019578: to=<[email protected]>, ctladdr=<[email protected]> (0/0), delay=1+00:09:06, xdelay=00:00:00, mailer=esmtp, pri=2460500, relay=alt4.gmail- smtp-in.l.google.com., dsn=4.0.0, stat=Deferred: Connection timed out with alt4.gmail-smtp-in.l.google.com. I do not understand why there is a connection time out. Am I missing something? Can anyone help me, please? Thank you.

    Read the article

  • ensime scala errors (class scala.Array not found, object scala not found)

    - by Jeff Bowman
    I've installed ensime according to the README.md file, however, I get errors in the inferior-ensime-server buffer with the following: INFO: Fatal Error: scala.tools.nsc.MissingRequirementError: object scala not found. scala.tools.nsc.MissingRequirementError: object scala not found. at scala.tools.nsc.symtab.Definitions$definitions$.getModuleOrClass(Definitions.scala:516) at scala.tools.nsc.symtab.Definitions$definitions$.ScalaPackage(Definitions.scala:43) at scala.tools.nsc.symtab.Definitions$definitions$.ScalaPackageClass(Definitions.scala:44) at scala.tools.nsc.symtab.Definitions$definitions$.UnitClass(Definitions.scala:89) at scala.tools.nsc.symtab.Definitions$definitions$.init(Definitions.scala:786) at scala.tools.nsc.Global$Run.(Global.scala:593) at scala.tools.nsc.interactive.Global$TyperRun.(Global.scala:473) at scala.tools.nsc.interactive.Global.newTyperRun(Global.scala:535) at scala.tools.nsc.interactive.Global.reloadSources(Global.scala:289) at scala.tools.nsc.interactive.Global$$anonfun$reload$1.apply(Global.scala:300) at scala.tools.nsc.interactive.Global$$anonfun$reload$1.apply(Global.scala:300) at scala.tools.nsc.interactive.Global.respond(Global.scala:276) at scala.tools.nsc.interactive.Global.reload(Global.scala:300) at scala.tools.nsc.interactive.CompilerControl$$anon$1.apply$mcV$sp(CompilerControl.scala:81) at scala.tools.nsc.interactive.Global.pollForWork(Global.scala:132) at scala.tools.nsc.interactive.Global$$anon$2.run(Global.scala:192) also: INFO: Fatal Error: scala.tools.nsc.MissingRequirementError: class scala.Array not found. scala.tools.nsc.MissingRequirementError: class scala.Array not found. at scala.tools.nsc.symtab.Definitions$definitions$.getModuleOrClass(Definitions.scala:516) at scala.tools.nsc.symtab.Definitions$definitions$.getClass(Definitions.scala:474) at scala.tools.nsc.symtab.Definitions$definitions$.ArrayClass(Definitions.scala:217) at scala.tools.nsc.backend.icode.TypeKinds$REFERENCE.(TypeKinds.scala:258) at scala.tools.nsc.backend.icode.GenICode$ICodePhase.(GenICode.scala:55) at scala.tools.nsc.backend.icode.GenICode.newPhase(GenICode.scala:43) at scala.tools.nsc.backend.icode.GenICode.newPhase(GenICode.scala:25) at scala.tools.nsc.Global$Run$$anonfun$4.apply(Global.scala:606) at scala.tools.nsc.Global$Run$$anonfun$4.apply(Global.scala:605) at scala.collection.LinearSeqOptimized$class.foreach(LinearSeqOptimized.scala:62) at scala.collection.immutable.List.foreach(List.scala:46) at scala.tools.nsc.Global$Run.(Global.scala:605) at scala.tools.nsc.interactive.Global$TyperRun.(Global.scala:473) at scala.tools.nsc.interactive.Global.newTyperRun(Global.scala:535) at scala.tools.nsc.interactive.Global.reloadSources(Global.scala:289) at scala.tools.nsc.interactive.Global.typedTreeAt(Global.scala:309) at scala.tools.nsc.interactive.Global$$anonfun$getTypedTreeAt$1.apply(Global.scala:326) at scala.tools.nsc.interactive.Global$$anonfun$getTypedTreeAt$1.apply(Global.scala:326) at scala.tools.nsc.interactive.Global.respond(Global.scala:276) at scala.tools.nsc.interactive.Global.getTypedTreeAt(Global.scala:326) at scala.tools.nsc.interactive.CompilerControl$$anon$2.apply$mcV$sp(CompilerControl.scala:89) at scala.tools.nsc.interactive.Global.pollForWork(Global.scala:132) at scala.tools.nsc.interactive.Global$$anon$2.run(Global.scala:192) Also none of the type identification works for me, I get 'NA' if I get anything at all. C-c t causes emacs to lock up. I'm running: Ubuntu 10.04 (64bit version) emacs 23.1.50.1 ensime from git (as of 3 May 2010) scala is version 2.8.0.RC1 java is 1.6.0_20 (from sun) here is a copy of the log: http://dl.dropbox.com/u/5309017/ensime.log Thanks! Jeff

    Read the article

  • Design-time failure: WPF, Usercontrols and Namespaces

    - by Simon Woods
    Hi I have a very simple WPF project comprising a Window and Usercontrol. I'm very much in a learning phase. It works fine when I run it. However, I am unable to see the form in design time. The problem, I believe is something to do with namespaces, but I don't understand where. It may well be a simple error Main Window XML <Window xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:views="clr-namespace:UserLogin" x:Class="UserLogin.MainView" x:Name="MainViewWindow" mc:Ignorable="d" Title="Login" Height="141" Width="347" > <Grid> <views:LoginView /> </Grid> </Window> Main Window CodeBehind Imports Microsoft.VisualBasic Imports System Imports System.Windows Imports UserLogin Namespace UserLogin Partial Public Class MainView Inherits System.Windows.Window Public Sub New() InitializeComponent() End Sub End Class End Namespace Usercontrol XAML <UserControl xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" x:Class="UserLogin.LoginView" x:Name="LoginViewControl" mc:Ignorable="d" d:DesignHeight="96" d:DesignWidth="298"> <Grid Height="96" Width="298"> <Button Command="{Binding OKCommand}" Height="21" Margin="0,0,90,16" Name="btnOK" VerticalAlignment="Bottom" HorizontalAlignment="Right" Width="76">OK</Button> <Button Command="{Binding CancelCommand}" Height="21" HorizontalAlignment="Right" Margin="0,0,9,16" Name="btnCancel" VerticalAlignment="Bottom" Width="75">Cancel</Button> <Label Height="23" HorizontalAlignment="Left" Margin="10,5,0,0" Name="Label1" VerticalAlignment="Top" Width="85">Name:</Label> <Label HorizontalAlignment="Left" Margin="10,32,0,0" Name="Label2" Width="85" Height="29" VerticalAlignment="Top">Password:</Label> <TextBox Margin="0,31,6,0" Name="txtPassword" Height="22" VerticalAlignment="Top" HorizontalAlignment="Right" Width="182" /> <ComboBox Height="22" Margin="110,6,6,0" Name="cboNames" VerticalAlignment="Top" /> </Grid> </UserControl> Usercontrol CodeBehind Imports Microsoft.VisualBasic Imports System Imports UserLogin Namespace UserLogin Partial Public Class LoginView Inherits System.Windows.Controls.UserControl Public Sub New() InitializeComponent() End Sub End Class End Namespace I think I'm missing something this namespace xmlns:views="clr-namespace:UserLogin" since intellisense doesn't give me the usercontrol declared within it in the XAML designer but rather reports the error "Unable to load the metadata for the assembly ... etc etc" Thx for any suggestions Simon

    Read the article

< Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23  | Next Page >