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  • Regex to match card code input

    - by kate
    How can I write a regex to match strings following these rules? 1 letter followed by 4 letters or numbers, then 5 letters or numbers, then 3 letters or numbers followed by a number and one of the following signs: ! & @ ? I need to allow input as a 15-character string or as 3 groups of 5 chars separated by one space. I'm implementing this in JavaScript.

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  • Using a regex to match IP addresses in Python

    - by MHibbin
    I'm trying to make a test for checking whether a sys.argv input matches the regex for an IP address... As a simple test, I have the following... import re pat = re.compile("\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}") test = pat.match(hostIP) if test: print "Acceptable ip address" else: print "Unacceptable ip address" However when I pass random values into it, it returns "Acceptable ip address" in most cases, except when I have an "address" that is basically equivalent to \d+ Any thoughts welcome. Cheers Matt

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  • img captions based on src value match

    - by Basho
    I am trying t o create img captions based on src value match. JQUERY : What is the best way to extract "Author-ABC" from an img with src value wwww.abcd.com/images/imagename_Author-ABC_.jpg and replace the alt value with this value. DRUPAL : Is there a way to preprocess this a drupal template function and save the value in img alt attribute? Ideas? Basho

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  • Look for match in a nested list in Python

    - by elfuego1
    Hello everybody, I have two nested lists of different sizes: A = [[1, 7, 3, 5], [5, 5, 14, 10]] B = [[1, 17, 3, 5], [1487, 34, 14, 74], [1487, 34, 3, 87], [141, 25, 14, 10]] I'd like to gather all nested lists from list B if A[2:4] == B[2:4] and put it into list L: L = [[1, 17, 3, 5], [141, 25, 14, 10]] Additionally if the match occurs then I want to change last element of sublist B into first element of sublist A so the final solution would look like this: L1 = [[1, 17, 3, 1], [141, 25, 14, 5]]

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  • Please help on multiple match replacement

    - by duenguyen
    I have a perl code: my $s = "The+quick+brown+fox+jumps+over+the+lazy+dog+that+is+my+dog"; what I want is to replace every + with space and dog with cat i have this regular expression $s =~ s/+(.*)dog/ ${1}cat/g; But it only match first occurrence of + and last dog. Please help

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  • Regular Expression to match IP address + wildcard

    - by Ed Woodcock
    Hey guys I'm trying to use a RegularexpressionValidator to match an IP address (with possible wildcards) for an IP filtering system. I'm using the following Regex: "([0-9]{1,3}\\.|\\*\\.){3}([0-9]{1,3}|\\*){1}" Which works fine when running it in LINQPad with Regex.Matches, but doesn't seem to work when I'm using the validator. Does anyone have a suggestion as to either a better Regex or why it would work in test but not in situ? Cheers, Ed

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  • How can I match a match a null byte (0x00) in the Visual Studio binary editor with a find using a re

    - by Paul K
    Open a file in the Visual Studio binary editor that contains a null byte (0x00), then use the Quick Find feature (Ctrl +F) to find null bytes. I would have thought I could use a regular expression such as \x00 to match null bytes but it doesn't work. Searching for any other hex value using this method works fine. Is this a VS bug, 'feature', or am I just missing something? Is there a work around?

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  • Sed non greedy curly braces match

    - by Cesar
    I have a string in a file a.txt {moslate}alho{/moslate}otra{moslate}a{/moslate} a need to get the string otra using sed. With this regex sed 's|{moslate}.*{/moslate}||g' a.txt a get no output at all but when i add a ? to the regex s|{moslate}.*?{/moslate}||g a.txt (I've read somewhere that it makes the regex non-greedy) i get no match at all, i mean a get the following output {moslate}alho{/moslate}otra{moslate}a{/moslate} How can i get the required output using sed?

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  • Trying to match what is before /../ but after / with regular expressions

    - by tim
    I am trying to match what is before /../ but after / with regular expressions, but i want it to look back and stop at the first / I feel like I am close but it just looks at the first slash and then takes everything after it like... input is this: this/is/a/./path/that/../includes/face/./stuff/../hat and my regular expression is #\/(.*)\.\.\/# matching /is/a/./path/that/../includes/face/./stuff/../ instead of just that/../ and stuff/../ how can i adapt what i'm doing to work?

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  • How to match 2 columns in excel?

    - by abhijithln
    Hi, I have an excel sheet, sheet1 which has 2 cols, A and B. Col A has some values and has corresponding mapping in col B(not all values in A have a mapping in B, some are empty). The sorting is done from Z-A and w.r.to Col A. I have another excel sheet, sheet2 which has similar Col A and Col B. Now, i want to find out whether any match is there between Col A of sheet1 and Col A of sheet2. If matches are found, those values should be copied onto a new column.

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  • check all values match using prototype

    - by snaken
    Using prototype, is there a simple method of checking that a group of values match, for example - can this code be refined to a single line or something otherwise more elegant? var val = ''; var fail = false; $('form').select('.class').each(function(e){ if(!val){ val = $F(e); }else{ if(val != $F(e)) fail = true; } });

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  • Forcing driver to device match

    - by shodanex
    I have a piece of usb hardware, for which I know the driver. However, the vendor id and product id do not match the VID, PID pair registered in the driver. Is there a way in linux to force a driver to be associated with a known device, that do not involve kernel module recompilation to add a PID / VID pair ?

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  • Check exact match of a word in a list of words

    - by Flake
    I want to check if a word is in a list of words. word = "with" word_list = ["without", "bla", "foo", "bar"] I tried if word in set(list), but it is not yielding the wanted result due to the fact in is matching string rather than item. That is to say, "with" is a match in any of the words in the word_list but still if "with" in set(list) will say True. What is a simpler way for doing this check than manually iterate over the list?

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  • match two data.frame

    - by Elb
    I have a situation like this: DF1 COL1 COL2 COL3 ... a b c b d b f e a g m f DF2 COL a b c d e f g h i l m n o I would like to match each column of DF1 with the only one column of DF2 and score how many occurrence of DF2 are in each column of DF1. How this can be done? Thanks in advance, E.

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  • Combine regular expressions for splitting camelCase string into words

    - by stou
    I managed to implement a function that converts camel case to words, by using the solution suggested by @ridgerunner in this question: Split camelCase word into words with php preg_match (Regular Expression) However, I want to also handle embedded abreviations like this: 'hasABREVIATIONEmbedded' translates to 'Has ABREVIATION Embedded' I came up with this solution: <?php function camelCaseToWords($camelCaseStr) { // Convert: "TestASAPTestMore" to "TestASAP TestMore" $abreviationsPattern = '/' . // Match position between UPPERCASE "words" '(?<=[A-Z])' . // Position is after group of uppercase, '(?=[A-Z][a-z])' . // and before group of lowercase letters, except the last upper case letter in the group. '/x'; $arr = preg_split($abreviationsPattern, $camelCaseStr); $str = implode(' ', $arr); // Convert "TestASAP TestMore" to "Test ASAP Test More" $camelCasePattern = '/' . // Match position between camelCase "words". '(?<=[a-z])' . // Position is after a lowercase, '(?=[A-Z])' . // and before an uppercase letter. '/x'; $arr = preg_split($camelCasePattern, $str); $str = implode(' ', $arr); $str = ucfirst(trim($str)); return $str; } $inputs = array( 'oneTwoThreeFour', 'StartsWithCap', 'hasConsecutiveCAPS', 'ALLCAPS', 'ALL_CAPS_AND_UNDERSCORES', 'hasABREVIATIONEmbedded', ); echo "INPUT"; foreach($inputs as $val) { echo "'" . $val . "' translates to '" . camelCaseToWords($val). "'\n"; } The output is: INPUT'oneTwoThreeFour' translates to 'One Two Three Four' 'StartsWithCap' translates to 'Starts With Cap' 'hasConsecutiveCAPS' translates to 'Has Consecutive CAPS' 'ALLCAPS' translates to 'ALLCAPS' 'ALL_CAPS_AND_UNDERSCORES' translates to 'ALL_CAPS_AND_UNDERSCORES' 'hasABREVIATIONEmbedded' translates to 'Has ABREVIATION Embedded' It works as intended. My question is: Can I combine the 2 regular expressions $abreviationsPattern and camelCasePattern so i can avoid running the preg_split() function twice?

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