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• Error with global variable in php not extending to included php file

  - by phileaton

  I have an html file that calls has a php section in the header like so: $page = basename($_SERVER['PHP_SELF']); Now further down in the html file I have a included footer like so: <?php include("footer.php"); ?> In this script I am referencing the $page variable, but it doesn't find it. I tried echoing the variable and nothing happened. When I place the basename() code in the footer.php file though, it handled it fine. I'd like to be efficient with the coding, so how can I get the footer.php file to get that $page variable? Is there a better way to do this than including the $page variable twice?

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• Global Variable problem

  - by riteshkumar1905

  Hi, I am new in iphone.I use a flag variable to play songs in avAudio player all songs are properly handeled with flag variable.we have two tabs in tab bar , i want that if any song playing then on other tab song info show.If we use that flag variable then i syncronize song info with song.But i can't access the value of flag on song info tab.I import the global file in song info file. Please Help me any one through which i define a global integer that var i can access in all project.

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• Rails Variable across all controller actions

  - by bob

  Hello, This should be a very simple rails question. I have a variable like the following. @administration = Administration.first I want this variable to be accessible through every controller action across all my controllers so for example if I have a Product controller and inside of it I have the usual CRUD actions, I want the @administration variable as defined above to be put into all the CRUD actions. (It would not be needed in destroy or create or update). I have many controllers throughout my project and I was wondering if there is an easier way than adding it manually through all of the actions that I want it in. I tried a global variable $administration = Administration.first but I run into an issue where it is not updated when I update the actual content of the Administration.first table. Also, I would like to avoid global variables. Any help would be much appreciated. Thanks! :)

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• Can I use a string variable to reference a class variable?

  - by rson

  Here's the scenario: I have an external swf file with x number of movieclips in its library that I load into a containing swf. Each MC in the external swf is linked with a class name and referenced on frame 1 as such var unique1:lineSequence1 = new lineSequence1(); the unique1 variable name will match a string variable I create in the containing swf: function initLines():void{ lineLoader = new Loader(); lineLoader.load(new URLRequest("theLines.swf")); //load external swf lineLoader.contentLoaderInfo.addEventListener(Event.COMPLETE, linesLoaded); } function linesLoaded(e:Event):void{ var loadedswf:MovieClip = e.target.content as MovieClip; var initialLines = projects[0].pageid; //projects is an xmllist trace("initialLines: "+initialLines); //returns "initialLines: unique1" lines_holder_mc.addChild(loadedswf.[initialLines]); } I would like to use the initialLines variable as the reference to unique1 instead of hardcoding unique1 into loadedswf.unique1 to reference said variable in the loaded swf.

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• update variable after success of ajax function

  - by Scarface

  Hey guys quick question, I am sending a request with the jquery ajax function with a variable. After the request I want that variable updated to match the value of the sent back information, so next time the ajax function executes, it send the value of the new variable. $.ajax({ type: "POST", data: "countusers=" + countusers, url: "tester.php", dataType: 'json', success: function(json) { var countusers=json.rownumber; } } })

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• C++: Declare static variable in function argument list

  - by MDC

  Is there any way at all in C++ to declare a static variable while passing it to a function? I'm looking to use a macro to expand to the expression passed to the function. The expression needs to declare and initialize a static variable on that particular line (based on the filename and line number using FILE and LINE). int foo(int b) { int c = b + 2; return c; } int main() { int a = 3; a = foo(static int h = 2); //<---- see this! cout << a; return 0; } The problem I'm trying to solve is getting the filename and line number with the FILE and LINE macros provided by the preprocessor, but then creating a lookup table with integer keys leading to the FILE, LINE pairs. For example, the key 89 may map to file foo.cpp, line 20. To get this to work, I'm trying to use local static variables, so that they are initialized only once per line execution. The static variable will be initialized by calling a function that calculates the integer key and adds an entry to the lookup table if it is not there. Right now the program uses a message class to send exception information. I'm writing a macro to wrap this class into a new class: WRAPPER_MACRO(old_class_object) will expand to NewClass(old_class_object, key_value). If I add the static variable declaration as a second line right before this, it should work. The problem is that in most places in the code, the old class object is passed as an argument to a function. So the problem becomes declaring and initializing the static variable somehow with the macro, while keeping the existing function calls.

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• Create categorial variable in R based on range

  - by Stedy

  I have a dataframe with a column of integers that I would like to use as a reference to make a new categorical variable. I want to divide the variable into three groups and set the ranges myself (ie 0-5, 6-10, etc). I tried cut but that divides the variable into groups based on a normal distribution and my data is right skewed. I have also tried to use if/then statements but this outputs a true/false value and I would like to keep my original variable. I am sure that there is a simple way to do this but I cannot seem to figure it out. Any advice on a simple way to do this quickly?

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• Static member variable containing object instances

  - by tom

  I have the following: function Preferences() { } Preferences.players = { 'player1': new Player() } players is a static member variable of Preferences and I'm trying to make it an object containing an instance of a Player. However, it doesn't appear to let me do this. It seems like it will allow me to define players if I make it a non-static member variable however. Like so: function Preferences() { var players = { 'player1' : new Player() } } Is it possible to create a static member variable containing instances of an object in JS?

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• Variable Binding Class

  - by Davis

  Hi, I believe this is a tough one... I'm trying to create a collection of variable binding in a class. It is intended to look something like this: Dim x as integer, s as string Dim c as new VBindClass x = 1 s = "Hello" c.Add x, s Debug.Print c.value(x) '= 1 Debug.Print c.value(s) '= "Hello" Is there some function that allow us to retrieve a unique ID for a given variable and also get/set based on variable?

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• Login with Google OAuth api and return url with variable

  - by user2833721

  I am using the Google API for login in my site and I appending my variable with URL and I want that variable in the return URL of OAuth API because of update purpose can I return back that variable For example: <a href="<?php echo($authUrl); ?>&kicker"> I append the kicker in $authUrl and when I return back from Oauth api print $me['displayName']; print $user['email']; print $me['gender']; print $me['id']; with this output I also want my variable "kicker" how can I get it

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• Long variable names

  - by RaouL

  Lets say i have a variable that contains the number of search engine names in a file, what would you name it? number_of_seach_engine_names search_engine_name_count num_search_engines engines engine_names other name? The first name describes what the variable contains precisely, but isn't it too long?, any advice for choosing variable names? especially how to shorten a name that is too long or what kind of abbreviations to use?

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• Getting 'choice' to work in Highline Ruby Gem without error and getting variable from it

  - by The Warm Jets

  I'm having a couple of problems using Highline in Ruby, and trying to get the choice element, detailed here, to work. At the moment the following code produces the error "error: wrong number of arguments (0 for 1). Use --trace to view backtrace" How do I get the variable out of choice? At the moment I have the 'do' setup, but I have no idea about how to get the variable the user has chosen out and into a variable for use elsewhere. Sorry if this is a bit beginner, I'm brand new to ruby and this is my first project, in at the deep end. Thanks in advance. if agree("Are these files going to be part of a set? ") set_title = ask("Title: ") set_desc = ask("Description:") set_genre = ask("Genre: ") set_label = ask("Record Label: ") set_date = ask_for_date("Release Date (yy-mm-dd): ") set_label = ask("EAN/UPC: ") set_buy = ask("Buy this set link: ") set_tags = ask_for_array("Tags (seperated by space): ") # Sort out license choose do |menu| menu.prompt = "Please choose the license for this set? " menu.choices(:all_rights_reserved, :cc_by) do # put the stuff in a variable end end end # End setup set

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• Create a variable of same type?

  - by piemesons

  I want to create a variable of same type of a type-unknown variable.How can I do that? I actually wants to create a variable of same type of cout/cin (as they are objects). I used typedef,but it ERR.

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• PHP: making a copy of a reference variable

  - by gAMBOOKa

  If I make a copy of a reference variable. Is the new variable a pointer or does it hold the value of the variable the pointer was referring to?

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• Access a static variable by $var::$reference

  - by chuckg

  I am trying to access a static variable within a class by using a variable class name. I'm aware that in order to access a function within the class, you use call_user_func(): class foo { function bar() { echo 'hi'; } } $class = "foo"; all_user_func(array($class, 'bar')); // prints hi However, this does not work when trying to access a static variable within the class: class foo { public static $bar = 'hi'; } $class = "foo"; call_user_func(array($class, 'bar')); // nothing echo $foo::$bar; // invalid How do I get at this variable? Is it even possible? I have a bad feeling this is only available in PHP 5.3 going forward and I'm running PHP 5.2.6. Thanks.

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• jQuery/Javascript Cookies and variable returning with value [object Object]

  - by user1706661

  I am attempting to set a cookie to a site using jQuery, ONLY if the user came from a specific site. In this case, lets use -http://referrersite.com- as the site they must come from for the cookie to be created as an example. The cookie value is being stored in a variable and everything up to this point is working fine. There is a conditional statement checking whether the user came from the referred site, if the cookie exists already and if the cookie doesn't exist and the user did not come from the referred site. If the user came from the referred site the cookie is created and stored in a variable. If the cookie already exists, it is then stored in a variable. If the cookie does not exist and the user did not come from the referred site I am assigning the variable a static string of characters - this is where the issue lies. When the variable is alerted from the non referred site and no existing cookie, it returns: [object Object], not the static string of characters. The code I am using is below: $(document).ready(function() { var referrer = document.referrer; if(referrer == "http://referrersite.com") { $.cookie("code","123456", { expires: 90, path: '/' }); cookieContainer = $.cookie("code"); alert(cookieContainer); } else if($.cookie("code")) { cookieContainer = $.cookie("code"); alert(cookieContainer); } else if($.cookie("code") == null && referrer != "http://referrersite.com") { cookieContainer = "67890"; alert(cookieContainer); } }); Please let me know if there is something I am missing as the code to me looks like it should work. Thanks!

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• Accessing initialized variable on different class C++

  - by d0pe

  I'm having some difficulties with this problem. The main idea is, I initialized a variable of class type B in class A, class A.h has the variable Z declared as public, like B *Z; In class A.cpp, I initialized it as Z = new B(); Now, I want to access that variable from class C and I'm unable to do so. C.h includes A.h and B.h

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• Variable pre-fixes, Visual Studio 2010 onwards?

  - by thedixon

  I'm a bit bewildered on this subject, as I relate variable prefixes to being a thing of the past now, but with Visual Studio 2010 onwards (I'm currently using 2012), do people still do this and why? I only ask because, these days, you can hover over any variable and it'll tell you the variable type and scope. There's literally no requirement for pre-fixing being there for readability. By this I mean: string strHello int intHello etc. And I'm being language/tool biased here - as Visual Studio takes a lot of the legwork out for you in terms of seeing exactly what type the variable is, including after conversions in the code. This is not a "general programming" question.

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• Java's equivalence to Python's "Got value: %s" % variable?

  - by Viet

  Java's equivalence to Python's "Got value: %s" % variable?

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• /etc/enviorment not being read into PATH variable

  - by Dan

  In Ubuntu the path variable is stored in /etc/enviorment. This is mine (I've made no changes to it, this is the system default): $ cat /etc/environment PATH="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games" but when I examine my PATH variable: $ echo $PATH /home/dan/bin:/home/dan/bin:/bin:/usr/bin:/usr/local/bin:/usr/bin/X11 You'll notice /usr/games is missing (it was there up until a few days ago). My /etc/profile makes no mention of PATH. My ~/.profile is the default and only has: if [ -d "$HOME/bin" ] ; then PATH="$HOME/bin:$PATH" fi This only happens in gnome, not in tty1-6. This is missing from both gnome terminal and when I try to call applications from the applications dropdown. Anyone know what could be causing this? Thanks.

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• /etc/environment not being read into PATH variable

  - by Dan

  In Ubuntu the path variable is stored in /etc/environment. This is mine (I've made no changes to it, this is the system default): $ cat /etc/environment PATH="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games" but when I examine my PATH variable: $ echo $PATH /home/dan/bin:/home/dan/bin:/bin:/usr/bin:/usr/local/bin:/usr/bin/X11 You'll notice /usr/games is missing (it was there up until a few days ago). My /etc/profile makes no mention of PATH. My ~/.profile is the default and only has: if [ -d "$HOME/bin" ] ; then PATH="$HOME/bin:$PATH" fi This only happens in gnome, not in tty1-6. This is missing from both gnome terminal and when I try to call applications from the applications dropdown. Anyone know what could be causing this? Thanks.

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• Python version priority in OSX/UNIX PATH environment variable

  - by mindthief

  Hi all, I want my system to use /usr/bin/python, but it's currently using /opt/local/bin/python, which points to /usr/bin/python2.6. I tried modifying the PATH variable in my .bashrc as PATH=~/bin:$PATH ...and then set a symbolic link in ~/bin to point to /usr/bin/python. i.e. ~/bin/python --> /usr/bin/python I figured this might prioritize this symlink over the /opt/local version if it came before the other one in the PATH variable, but when I opened a new shell I still found python pointing to /opt/local/bin. Any advice on a good way to get the system to use /usr/bin/python? Also, I usually use ipython as opposed to python directly. I'm assuming that if the system starts to use the correct version of python then ipython would also use that version? If not, how could I also get ipython to use the correct version? Thanks!

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• where.exe does not find OpenSSL libs when %ProgramFiles% variable is used in the PATH environment variable

  - by Piotr Dobrogost

  I installed both 32bit and 64bit version of OpenSSL libs on Vista x64. The 32bit version was installed in c:\Program Files (x86)\OpenSSL and the 64bit version was installed in c:\Program Files\OpenSSL. Then I added the entry %ProgramFiles%\OpenSSL to the PATH environment variable. %ProgramFiles%\OpenSSL is expanded to c:\Program Files (x86)\OpenSSL for 32bit programs and it's expanded to c:\Program Files\OpenSSL for 64bit programs. The idea is to have 32bit programs use 32bit version of OpenSSL libs and 64bit programs use 64bit version. I wanted to check if this works by running 32bit cmd.exe and issuing where ssleay32.dll and then by running 64bit cmd.exe and issuing the same. However in both cases I get the error INFO: Could not find files for the given pattern(s). What's wrong? This is a follow up to Different PATH environment variable for 32bit and 64bit Windows - is it possible?

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• Need to set mailx variable to specify the From address

  - by user256817

  Running Oracle Linux 5.8 (which is just re-branded RedHat EL 5.8) I must change the From address. But we have scripts that use mailx which cannot be re-written to use any extra flags, so I'd like to use internal variables instead, which I see on the linux.die.net manpage on mailx is an alternative to the -r flag: -r address Sets the From address. Overrides any from variable specified in environment or startup files. Tilde escapes are disabled. The -r address options are passed to the mail transfer agent unless SMTP is used. This option exists for compatibility only; it is recommended to set the from variable directly instead. (Source: http://linux.die.net/man/1/mailx) How can we use these mailx variables? I tried adding this to /root/.mailrc, no go: set [email protected] I also added that to /etc/mail.rc with no gold. So I am turning to you, SuperUsers...

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• Modify PATH variable for X11 during log-in

  - by user1028435

  I am working on some lab computers (read: no administrative rights) that, if I log in, I need to change the PATH variable as X11 starts. The reason is that I need to change the PATH variable at this time, as opposed to later, is that the Print Screen command seems to "bind" during login (forgive my bad explanation of this). Currently, I have a .bashrc script as a workaround: #!/bin/bash export PATH=/home/username/bin:$PATH I can make it work by starting a new X, but I was wondering if it is possible to change upon login. cat /etc/redhat-release tells me my distribution is: Red Hat Enterprise Linux Client release 5.8 (Tikanga)

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