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  • Using variable for tag in getElementsByTagName() for PHP and XML?

    - by Jared
    See my PHP: $file = "routingConfig.xml"; global $doc; $doc = new DOMDocument(); $doc->load( $file ); $ElTag = "Route"; $tag = $doc->getElementsByTagName($ElTag); XML is: <Routes> <Route></Route> <Route></Route> <Routes> Error returned is: Fatal error: Call to a member function getElementsByTagName() on a non-object I'm not sure how to do this?

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  • What is the correct method to load an XML file and re-write it as a CSV? (C# Only)

    - by codesmack
    I have a XML file that I want to load into an unknown object type. (I say unknown object type because I am not sure what direction to go) Once I have the data loaded I need to do some processing on certain elements that are now loaded into the new object. For sake of example, we can say that the xml file is full of elements named <car> and within the car element I need to process the <mileage> element. Then once this is all done I need to write the file as a CSV file. I would like to do this is the most direct way possible. (The less code the better) I am using VS 2008 C#

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  • Is it possible to define XML schemata with node names specified via regular expressions?

    - by MartyIX
    Hello, I know it is probably a question against XML philosophy but still is it possible to define schemata for XML like this: <Root> <arbitrary-name-of-node> <Name></Name> <Position></Position> <!-- ... --> </arbitrary-name-of-node> <arbitrary-name-of-node> <Name></Name> <Position></Position> <!-- ... --> </arbitrary-name-of-node> </Root> where arbitrary-name-of-node matches regular expression [a-zA-Z0-9]? Thanks for an answer!

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  • SQL SERVER – Understanding XML – Contest Win Joes 2 Pros Combo (USD 198) – Day 5 of 5

    - by pinaldave
    August 2011 we ran a contest where every day we give away one book for an entire month. The contest had extreme success. Lots of people participated and lots of give away. I have received lots of questions if we are doing something similar this month. Absolutely, instead of running a contest a month long we are doing something more interesting. We are giving away USD 198 worth gift every day for this week. We are giving away Joes 2 Pros 5 Volumes (BOOK) SQL 2008 Development Certification Training Kit every day. One copy in India and One in USA. Total 2 of the giveaway (worth USD 198). All the gifts are sponsored from the Koenig Training Solution and Joes 2 Pros. The books are available here Amazon | Flipkart | Indiaplaza How to Win: Read the Question Read the Hints Answer the Quiz in Contact Form in following format Question Answer Name of the country (The contest is open for USA and India residents only) 2 Winners will be randomly selected announced on August 20th. Question of the Day: Is following XML a well formed XML Document? <?xml version=”1.0″?> <address> <firstname>Pinal</firstname> <lastname>Dave</lastname> <title>Founder</title> <company>SQLAuthority.com</company> </address> a) Yes b) No c) I do not know Query Hints: BIG HINT POST A common observation by people seeing an XML file for the first time is that it looks like just a bunch of data inside a text file. XML files are text-based documents, which makes them easy to read.  All of the data is literally spelled out in the document and relies on a just a few characters (<, >, =) to convey relationships and structure of the data.  XML files can be used by any commonly available text editor, like Notepad. Much like a book’s Table of Contents, your first glance at well-formed XML will tell you the subject matter of the data and its general structure. Hints appearing within the data help you to quickly identify the main theme (similar to book’s subject), its headers (similar to chapter titles or sections of a book), data elements (similar to a book’s characters or chief topics), and so forth. We’ll learn to recognize and use the structural “hints,” which are XML’s markup components (e.g., XML tags, root elements). The XML Raw and Auto modes are great for displaying data as all attributes or all elements – but not both at once. If you want your XML stream to have some of its data shown in attributes and some shown as elements, then you can use the XML Path mode. If you are using an XML Path stream, then by default all values will be shown as elements. However, it is possible to pick one or more elements to be shown with an attribute(s) as well. Additional Hints: I have previously discussed various concepts from SQL Server Joes 2 Pros Volume 5. SQL Joes 2 Pros Development Series – OpenXML Options SQL Joes 2 Pros Development Series – Preparing XML in Memory SQL Joes 2 Pros Development Series – Shredding XML SQL Joes 2 Pros Development Series – Using Root With Auto XML Mode SQL Joes 2 Pros Development Series – Using Root With Auto XML Mode SQL Joes 2 Pros Development Series – What is XML? SQL Joes 2 Pros Development Series – What is XML? – 2 Next Step: Answer the Quiz in Contact Form in following format Question - Answer Name of the country (The contest is open for USA and India) Bonus Winner Leave a comment with your favorite article from the “additional hints” section and you may be eligible for surprise gift. There is no country restriction for this Bonus Contest. Do mention why you liked it any particular blog post and I will announce the winner of the same along with the main contest. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Joes 2 Pros, PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Correct XML serialization and deserialization of "mixed" types in .NET

    - by Stefan
    My current task involves writing a class library for processing HL7 CDA files. These HL7 CDA files are XML files with a defined XML schema, so I used xsd.exe to generate .NET classes for XML serialization and deserialization. The XML Schema contains various types which contain the mixed="true" attribute, specifying that an XML node of this type may contain normal text mixed with other XML nodes. The relevant part of the XML schema for one of these types looks like this: <xs:complexType name="StrucDoc.Paragraph" mixed="true"> <xs:sequence> <xs:element name="caption" type="StrucDoc.Caption" minOccurs="0"/> <xs:choice minOccurs="0" maxOccurs="unbounded"> <xs:element name="br" type="StrucDoc.Br"/> <xs:element name="sub" type="StrucDoc.Sub"/> <xs:element name="sup" type="StrucDoc.Sup"/> <!-- ...other possible nodes... --> </xs:choice> </xs:sequence> <xs:attribute name="ID" type="xs:ID"/> <!-- ...other attributes... --> </xs:complexType> The generated code for this type looks like this: /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(TypeName="StrucDoc.Paragraph", Namespace="urn:hl7-org:v3")] public partial class StrucDocParagraph { private StrucDocCaption captionField; private object[] itemsField; private string[] textField; private string idField; // ...fields for other attributes... /// <remarks/> public StrucDocCaption caption { get { return this.captionField; } set { this.captionField = value; } } /// <remarks/> [System.Xml.Serialization.XmlElementAttribute("br", typeof(StrucDocBr))] [System.Xml.Serialization.XmlElementAttribute("sub", typeof(StrucDocSub))] [System.Xml.Serialization.XmlElementAttribute("sup", typeof(StrucDocSup))] // ...other possible nodes... public object[] Items { get { return this.itemsField; } set { this.itemsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlTextAttribute()] public string[] Text { get { return this.textField; } set { this.textField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute(DataType="ID")] public string ID { get { return this.idField; } set { this.idField = value; } } // ...properties for other attributes... } If I deserialize an XML element where the paragraph node looks like this: <paragraph>first line<br /><br />third line</paragraph> The result is that the item and text arrays are read like this: itemsField = new object[] { new StrucDocBr(), new StrucDocBr(), }; textField = new string[] { "first line", "third line", }; From this there is no possible way to determine the exact order of the text and the other nodes. If I serialize this again, the result looks exactly like this: <paragraph> <br /> <br />first linethird line </paragraph> The default serializer just serializes the items first and then the text. I tried implementing IXmlSerializable on the StrucDocParagraph class so that I could control the deserialization and serialization of the content, but it's rather complex since there are so many classes involved and I didn't come to a solution yet because I don't know if the effort pays off. Is there some kind of easy workaround to this problem, or is it even possible by doing custom serialization via IXmlSerializable? Or should I just use XmlDocument or XmlReader/XmlWriter to process these documents?

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  • PHP parsing XML file with and without namespaces

    - by Mike
    I need to get a XML File into a Database. Thats not the problem. Cant read it, parse it and create some Objects to map to the DB. Problem is, that sometimes the XML File can contain namespaces and sometimes not. Furtermore sometimes there is no namespace defined at all. So what i first got was something like this: <?xml version="1.0" encoding="UTF-8"?> <struct xmlns:b="http://www.w3schools.com/test/"> <objects> <object> <node_1>value1</node_1> <node_2>value2</node_2> <node_3 iso_land="AFG"/> <coords lat="12.00" long="13.00"/> </object> </objects> </struct> And the parsing: $t = $xml->xpath('/objects/object'); foreach($nodes AS $node) { if($t[0]->$node) { $obj->$node = (string) $t[0]->$node; } } Thats fine as long as there are no namespaces. Here comes the XML File with namespaces: <?xml version="1.0" encoding="UTF-8"?> <b:struct xmlns:b="http://www.w3schools.com/test/"> <b:objects> <b:object> <b:node_1>value1</b:node_1> <b:node_2>value2</b:node_2> <b:node_3 iso_land="AFG"/> <b:coords lat="12.00" long="13.00"/> </b:object> </b:objects> </b:struct> I now came up with something like this: $xml = simplexml_load_file("test.xml"); $namespaces = $xml->getNamespaces(TRUE); $ns = count($namespaces) ? 'a:' : ''; $xml->registerXPathNamespace("a", "http://www.w3schools.com/test/"); $nodes = array('node_1', 'node_2'); $obj = new stdClass(); foreach($nodes AS $node) { $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.$node); if($t[0]) { $obj->$node = (string) $t[0]; } } $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.'node_3'); if($t[0]) { $obj->iso_land = (string) $t[0]->attributes()->iso_land; } $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.'coords'); if($t[0]) { $obj->lat = (string) $t[0]->attributes()->lat; $obj->long = (string) $t[0]->attributes()->long; } That works with namespaces and without. But i feel that there must be a better way. Before that i could do something like this: $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object'); foreach($nodes AS $node) { if($t[0]->$node) { $obj->$node = (string) $t[0]->$node; } } But that just wont work with namespaces.

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  • How to deserialize an element as an XmlNode?

    - by mackenir
    When using Xml serialization in C#, I want to deserialize a part of my input XML to an XmlNode. So, given this XML: <Thing Name="George"> <Document> <subnode1/> <subnode2/> </Document> </Thing> I want to deserialize the Document element to an XmlNode. Below is my attempt which given the XML above, sets Document to the 'subnode1' element rather than the 'Document' element. How would I get the code to set the Document property to the Document element? using System; using System.IO; using System.Xml; using System.Xml.Serialization; [Serializable] public class Thing { [XmlAttribute] public string Name {get;set;} public XmlNode Document { get; set; } } class Program { static void Main() { const string xml = @" <Thing Name=""George""> <Document> <subnode1/> <subnode2/> </Document> </Thing>"; var s = new XmlSerializer(typeof(Thing)); var thing = s.Deserialize(new StringReader(xml)) as Thing; } } However, when I use an XmlSerializer to deserialize the XML above to an instance of Thing, the Document property contains the child element 'subnode1', rather than the 'doc' element. How can I get the XmlSerializer to set Document to an XmlNode containing the 'doc' element.

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  • Cinema4D XML scene not rendering texture

    - by George Profenza
    I was playing with the Cinema 4D command line options and ran into a problem that might not be specific to the command line options. I saved a basic scene(a textured cube) in two formats: the original .c4d(binary) format and .xml(Cinema 4D XML via File Export). the .c4d file renders with the texture applied, while the .xml file renders without the texture applied. I had a look at the xml file, and there is a node that holds a reference to the image used as texture, and there is another node which seems to store the pixels in xml. When I opened the .xml document in Cinema 4D, the document did store the material with the texture, but it was not applied to the object. Am I missing something when I export to XML ? How can I export a Cinema 4D XML that can render with the texture applied ?

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  • How to use the same element name in different purposes ( in XML and DTD ) ?

    - by BugKiller
    Hi, I Want to create a DTD schema for this xml document: <root> <student> <name> <firstname>S1</firstname> <lastname>S2</lastname> </name> </student> <course> <name>CS101</name> </course> </root> as you can see , the element name in the course contains plain text ,but the element name in the student is complex type ( first-name, last-name ). The following is the DTD: <!ELEMENT root (course|student)*> <!ELEMENT student (name)> <!ELEMENT name (lastname|firstname)> <!ELEMENT firstname (#PCDATA)> <!ELEMENT lastname (#PCDATA)> <!ELEMENT course (name)> When I want to validate it , I get an error because the course's name has different structure then the student's name . My Question: how can I make a work-around solution for this situation without changing the name of element name using DTD not xml schema . Thanks.

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  • XML Catalog in Eclipse is not working

    - by svaret
    Where I work we do not have any internet connection. We still want to have validation and code completion when editing xml files. I have tried the instructions here http://www.helmers.nu/?p=276 However, I try the instructions, restarts eclipse, do reload dependencies. I still cannot get any code completion nor validation. Can anyone point me in the right direction? I have tried both with Eclipse Galileo and Helios. My catalog.xml <?xml version="1.0" encoding="UTF-8" standalone="no"?> <catalog xmlns="urn:oasis:names:tc:entity:xmlns:xml:catalog"> <uri name="http://www.liquibase.org/xml/ns/dbchangelog/1.9" uri="file:///C:/dev/XMLSchemaDefinition/dbchangelog-1.9.xsd"/> </catalog> My xml-file: <?xml version="1.0" encoding="UTF-8" standalone="no"?> <databaseChangeLog xmlns="http://www.liquibase.org/xml/ns/dbchangelog/1.9" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.liquibase.org/xml/ns/dbchangelog/1.9 http://www.liquibase.org/xml/ns/dbchangelog/dbchangelog-1.9.xsd"> </databaseChangeLog>

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  • How to use the same element name for different purposes ( in XML and DTD ) ?

    - by BugKiller
    Hi, I Want to create a DTD schema for this xml document: <root> <student> <name> <firstname>S1</firstname> <lastname>S2</lastname> </name> </student> <course> <name>CS101</name> </course> </root> as you can see , the element name in the course contains plain text ,but the element name in the student is complex type ( first-name, last-name ). The following is the DTD: <!ELEMENT root (course|student)*> <!ELEMENT student (name)> <!ELEMENT name (lastname|firstname)> <!ELEMENT firstname (#PCDATA)> <!ELEMENT lastname (#PCDATA)> <!ELEMENT course (name)> When I want to validate it , I get an error because the course's name has different structure then the student's name . My Question: how can I make a work-around solution for this situation without changing the name of element name using DTD not xml schema . Thanks.

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  • XML Schema: Can I make some of an attribute's values be required but still allow other values?

    - by scrotty
    (Note: I cannot change structure of the XML I receive, I am only able to change how I validate it.) Let's say I can get XML like this: <Address Field="Street" Value="123 Main"/> <Address Field="StreetPartTwo" Value="Unit B"/> <Address Field="State" Value="CO"/> <Address Field="Zip" Value="80020"/> <Address Field="SomeOtherCrazyValue" Value="Foo"/> I need to create an XSD schema that validates that "Street", "State" and "Zip" must be present. But I don't care if "StreetPartTwo" or "SomeOTherCrazyValue" is present. If I knew that only the three I care about could be included, I could do this: <xs:element name="Address" type="addressType" maxOccurs="unbounded" minOccurs="3"/> <xs:complexType name="addressType"> <xs:attribute name="Field" use="required"> <xs:simpleType> <xs:restriction base="xs:string"> <xs:enumeration value="Street"/> <xs:enumeration value="State"/> <xs:enumeration value="Zip"/> </xs:restriction> </xs:simpleType> </xs:attribute> </xs:complexType> But this won't work with my case because I may also receive those other Address elements (that also have "Field" attributes) that I don't care about. Any ideas how I can ensure the stuff I care about is present but let the other stuff in too? TIA! Sean

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  • use multiple xsl files with one xml document

    - by paracaudex
    I have a single xml document (data.xml), which I display as HTML using an XSLT document (transform.xsl) with the following line in data.xml. <?xml-stylesheet type="text/xsl" href="transform.xsl"?> Suppose, however, I want to display this information in two different ways, one at http://www.domain.com/data.xml and one at http://www.domain.com/data2.xml. Both of these displays will use the same xml document but with different xsl's. Is there a way to do this without duplicating the xml file?

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  • Advance: Parsing XML into another XML page using only javascript or jquery; Can't use PhP, Java or MySQL

    - by UrBestFriend
    Current site: http://cardwall.tk/ Example of intended outcome: http://www.shockwave.com/downloadWall.jsp I have an embeded flash object that uses XML/RSS (Picasa) to feed itself pictures. Now I created my own XML/RSS feed so that I can add additional XML tags and values. Now here's my big problem: enabling search. Since I'm not relying on Picasa's API anymore to return custom RSS/XML for the user's search, how can I create xml from another xml based on the user's search queries using only JavaScript and Jquery? Here is the current code: <script type="text/javascript"> var flashvars = { feed : "http%3A%2F%2Frssfeed.ucoz.com%2Frssfeed.xml", backgroundColor : "#FFFFFF", metadataFont : "Arial", wmode : "opaque", iFrameScrolling: "no", numRows : "3", }; var params = { allowFullScreen: "true", allowscriptaccess : "always", wmode: "opaque" }; swfobject.embedSWF("http://apps.cooliris.com/embed/cooliris.swf", "gamewall", "810", "410", "9.0.0", "", flashvars, params); $(document).ready(function() { $("#cooliris input").keydown(function(e) { if(e.keyCode == 13) { $("#cooliris a#searchCooliris").click(); return false; } }); doCoolIrisSearch = function() { cooliris.embed.setFeedContents( '** JAVA STRING OF PARSED RSS/XML based on http%3A%2F%2Frssfeed.ucoz.com%2Frssfeed.xml and USER'S SEARCH INPUT** ' ) }); <form id="searchForm" name="searchForm" class="shockwave"> <input type="text" name="coolIrisSearch" id="coolIrisSearch" value="Search..." class="field text short" onfocus="this.value='';" /> <a id="searchCooliris" href="#" onclick="doCoolIrisSearch();return false;" class="clearLink">Search Cooliris</a> </form> <div id="gamewall"></div> So basically, I want to replace cooliris.embed.setFeedContents's value with a Javastring based on the parsed RSS/XML and user search input. Any code or ideas would be greatly appreciated.

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  • I have problem loading all items from XML with for each

    - by vaha
    Hi all, I'm low level as3 programmer and I need help whit this code: I have gallery XML file: 1 0 Lokacije 1 1.jpg 2 2 Coaching 1 2.jpg 3 0 0 3.jpg And: var loader: URLLoader = new URLLoader(); loader.load(new URLRequest("gallery.xml"); var xml = new XML(evt.target.data); for each(var item in xml..item) { centralniText.htmlText = item.slika; } only shows last item from XML file: 3.jpg I want all. Please help.

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  • Why can't I start XML entity names with 'xml''?

    - by flamey
    <XmlInfo /> I ran into problem using Perl's popular SOAP::Lite module, where it wouldn't accept XML entity names starting with "xml" (regardles letters' case). The author of the module replied to email saying that entity names starting with "xml" are not permitted in XML specification, but I couldn't find it in W3C's documents for 1.0 and 1.1 specs, I also couldn't find it in any of the articles or guidelines docs about XML entity naming. In fact some guideline documents used names starting with xml as an example, and lots of people are using it, as I see via Google Code Search. So are there any restrictions (besides which characters to use as defined in W3C's documents) in Entity naming in XML? Is there a restriction saying you can't name entities starting with "xml"?

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  • format an xml string in Ruby

    - by user1476512
    given an xml string like this : <some><nested><xml>value</xml></nested></some> what's the best option(using ruby) to format it readable like : <some> <nested> <xml>value</xml> </nested> </some> I've found an answer here: what's the best way to format an xml string in ruby?, which is really helpful. But it formats xml like: <some> <nested> <xml> value </xml> </nested> </some> As my xml string is a little big in length. So it is not readable in this format. Thanks in advance!

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  • Oracle 10.1 and 11.2 produce different XML using the same statement

    - by MindFyer
    I am migrating a database from Oracle 10.1 to 11.2 and I have the following problem. The statement SELECT '<?xml version="1.0" encoding="utf-8" ?>' || (Xml).getClobVal() AS XmlClob FROM ( SELECT XmlElement( "Element1", ( SELECT XmlAgg(tpx.Xml) FROM ( SELECT XmlElement("Element3",XmlForest('content' as Element4)) AS Xml FROM dual ) tpx ) AS "Element2" ) AS Xml FROM dual ) On the original 10.1 database produces XML like this... <?xml version="1.0" encoding="utf-8"?> <Element1> <Element2> <Element3> <ELEMENT4>content</ELEMENT4> </Element3> </Element2> </Element1> On the new 11.2 system it looks like this... <?xml version="1.0" encoding="utf-8"?> <Element1> <Element3> <ELEMENT4>content</ELEMENT4> </Element3> </Element1> Is there some environmental variable I am missing that tells Oracle how to format its XML. There are hundreds of thousands of lines of PL/SQL in the database; it would be a mammoth task to rewrite if it turned out they had changed they way Oracle formats XML between versions. Hopefully someone has come accross this before. Thanks

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  • loading an xml in web apps directory from a library dll

    - by Blankman
    my web application has an xml file here: /files/xml/test.xml I need to load a XDocument from within a class library project, how will I reference the xml? I don't want to pass any path parameters to this method. I want to assume the location is fixed at /files/xml/test.xml. How can I load a XDocument know this? I don't seem to have access to server.mappath either.

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  • XML Schema For MBSA Reports

    - by Steve Hawkins
    I'm in the process of creating a script to run the command line version of Microsoft Baseline Security Analyzer (mbsacli.exe) against all of our servers. Since the MBSA reports are provided as XML documents, I should be able to write a script or small program to parse the XML looking for errors / issues. I'm wondering if anyone knows whether or not the XML schema for the MBSA reports is documented anywhere -- I have goggled this, and cant seem to find any trace of it. I've run across a few articles that address bits and pieces, but nothing that addresses the complete schema. Yes, I could just reverse engineer the XML, but I would like to understand a little more about the meaning of some of the tags. Thanks...

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  • IE 7 opens .zip files as XML documents

    - by EdmundG
    When I try clicking on a zip file link on a web page, IE 7 tries to open it as an XML document and displays: The XML page cannot be displayed Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again. I get around this by right-clicking and using Save Target As... Double clicking on a .zip in the file system opens my zip program without problems. How do I fix this problem?

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  • DB2 runstats not working for xml columns

    - by Keshav Prasad
    Hello, I am running runstats command to update the runtime statistics of a particular table called "CUSTOMER" in DB2. The customer has two columns- CID (integer) and INFO (xml column). After running the command, if I look into the SYSCOLDIST table, the information for column CID is populated correctly. But there is nothing filled for the INFO xml column. The same happens with a different table that has xml columns. Please help.. Thanks, -Keshav

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  • How to Create an XML File from an Excel File

    - by nicorellius
    I have an Excel spreadsheet file that has 5 or so columns and hundreds of lines. I need to convert this (export these data) to an XML file. I'm interested in three of the columns and they correspond to these XML tags, where info1 can be followed by info2, info3, etc... <?xml version="1.0" encoding="UTF-8" ?> <list> <info1> <id>111</id> <value>222</value> <des>333</des> </info1> </list> If possible, I would like to avoid building this XML manually. It wouldn't be too much trouble to rearrange the Excel file such that the three columns I'm interested in were in their own file. But then I would need to export those data into an XML file of the above format. Any ideas?

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  • how to recover my xml default icon?

    - by moonway
    My XML files are showing the unknown programs icon, you can see in this picture: i cant revise its icon why? i look it up in the registry i find no error look at the following Windows Registry Editor Version 5.00 [HKEY_CLASSES_ROOT.xml] @="xmlfile" "Content Type"="text/xml" "PerceivedType"="text" [HKEY_CLASSES_ROOT.xml\PersistentHandler] @="{7E9D8D44-6926-426F-AA2B-217A819A5CCE}" Windows Registry Editor Version 5.00 [HKEY_CLASSES_ROOT\xmlfile] @="@C:\Windows\System32\msxml3r.dll,-1" "EditFlags"=hex:00,00,00,00 "FriendlyTypeName"=hex(2):40,00,25,00,53,00,79,00,73,00,74,00,65,00,6d,00,52,\ 00,6f,00,6f,00,74,00,25,00,5c,00,53,00,79,00,73,00,74,00,65,00,6d,00,33,00,\ 32,00,5c,00,6d,00,73,00,78,00,6d,00,6c,00,33,00,72,00,2e,00,64,00,6c,00,6c,\ 00,2c,00,2d,00,31,00,00,00 [HKEY_CLASSES_ROOT\xmlfile\BrowseInPlace] [HKEY_CLASSES_ROOT\xmlfile\CLSID] @="{48123BC4-99D9-11D1-A6B3-00C04FD91555}" [HKEY_CLASSES_ROOT\xmlfile\DefaultIcon] @="C:\Windows\System32\msxml3.dll,0" [HKEY_CLASSES_ROOT\xmlfile\shell] @="open" [HKEY_CLASSES_ROOT\xmlfile\shell\edit] [HKEY_CLASSES_ROOT\xmlfile\shell\edit\command] @="\"C:\Program Files\Common Files\Microsoft Shared\OFFICE11\MSOXMLED.EXE\" /verb edit \"%1\"" [HKEY_CLASSES_ROOT\xmlfile\shell\Open] [HKEY_CLASSES_ROOT\xmlfile\shell\Open\Command] @="\"C:\Program Files\Common Files\Microsoft Shared\OFFICE11\MSOXMLED.EXE\" /verb open \"%1\"" [HKEY_CLASSES_ROOT\xmlfile\shell\Open\ddeexec] @="" [HKEY_CLASSES_ROOT\xmlfile\ShellEx] [HKEY_CLASSES_ROOT\xmlfile\ShellEx\IconHandler] @="{AB968F1E-E20B-403A-9EB8-72EB0EB6797E}" can you find something wrong or you can paste your reg hehe i need default reg about xml which is with default associated exe all right!

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  • Get XML from Server for Use on Windows Phone

    - by psheriff
    When working with mobile devices you always need to take into account bandwidth usage and power consumption. If you are constantly connecting to a server to retrieve data for an input screen, then you might think about moving some of that data down to the phone and cache the data on the phone. An example would be a static list of US State Codes that you are asking the user to select from. Since this is data that does not change very often, this is one set of data that would be great to cache on the phone. Since the Windows Phone does not have an embedded database, you can just use an XML string stored in Isolated Storage. Of course, then you need to figure out how to get data down to the phone. You can either ship it with the application, or connect and retrieve the data from your server one time and thereafter cache it and retrieve it from the cache. In this blog post you will see how to create a WCF service to retrieve data from a Product table in a database and send that data as XML to the phone and store it in Isolated Storage. You will then read that data from Isolated Storage using LINQ to XML and display it in a ListBox. Step 1: Create a Windows Phone Application The first step is to create a Windows Phone application called WP_GetXmlFromDataSet (or whatever you want to call it). On the MainPage.xaml add the following XAML within the “ContentPanel” grid: <StackPanel>  <Button Name="btnGetXml"          Content="Get XML"          Click="btnGetXml_Click" />  <Button Name="btnRead"          Content="Read XML"          IsEnabled="False"          Click="btnRead_Click" />  <ListBox Name="lstData"            Height="430"            ItemsSource="{Binding}"            DisplayMemberPath="ProductName" /></StackPanel> Now it is time to create the WCF Service Application that you will call to get the XML from a table in a SQL Server database. Step 2: Create a WCF Service Application Add a new project to your solution called WP_GetXmlFromDataSet.Services. Delete the IService1.* and Service1.* files and the App_Data folder, as you don’t generally need these items. Add a new WCF Service class called ProductService. In the IProductService class modify the void DoWork() method with the following code: [OperationContract]string GetProductXml(); Open the code behind in the ProductService.svc and create the GetProductXml() method. This method (shown below) will connect up to a database and retrieve data from a Product table. public string GetProductXml(){  string ret = string.Empty;  string sql = string.Empty;  SqlDataAdapter da;  DataSet ds = new DataSet();   sql = "SELECT ProductId, ProductName,";  sql += " IntroductionDate, Price";  sql += " FROM Product";   da = new SqlDataAdapter(sql,    ConfigurationManager.ConnectionStrings["Sandbox"].ConnectionString);   da.Fill(ds);   // Create Attribute based XML  foreach (DataColumn col in ds.Tables[0].Columns)  {    col.ColumnMapping = MappingType.Attribute;  }   ds.DataSetName = "Products";  ds.Tables[0].TableName = "Product";  ret = ds.GetXml();   return ret;} After retrieving the data from the Product table using a DataSet, you will want to set each column’s ColumnMapping property to Attribute. Using attribute based XML will make the data transferred across the wire a little smaller. You then set the DataSetName property to the top-level element name you want to assign to the XML. You then set the TableName property on the DataTable to the name you want each element to be in your XML. The last thing you need to do is to call the GetXml() method on the DataSet object which will return an XML string of the data in your DataSet object. This is the value that you will return from the service call. The XML that is returned from the above call looks like the following: <Products>  <Product ProductId="1"           ProductName="PDSA .NET Productivity Framework"           IntroductionDate="9/3/2010"           Price="5000" />  <Product ProductId="3"           ProductName="Haystack Code Generator for .NET"           IntroductionDate="7/1/2010"           Price="599.00" />  ...  ...  ... </Products> The GetProductXml() method uses a connection string from the Web.Config file, so add a <connectionStrings> element to the Web.Config file in your WCF Service application. Modify the settings shown below as needed for your server and database name. <connectionStrings>  <add name="Sandbox"        connectionString="Server=Localhost;Database=Sandbox;                         Integrated Security=Yes"/></connectionStrings> The Product Table You will need a Product table that you can read data from. I used the following structure for my product table. Add any data you want to this table after you create it in your database. CREATE TABLE Product(  ProductId int PRIMARY KEY IDENTITY(1,1) NOT NULL,  ProductName varchar(50) NOT NULL,  IntroductionDate datetime NULL,  Price money NULL) Step 3: Connect to WCF Service from Windows Phone Application Back in your Windows Phone application you will now need to add a Service Reference to the WCF Service application you just created. Right-mouse click on the Windows Phone Project and choose Add Service Reference… from the context menu. Click on the Discover button. In the Namespace text box enter “ProductServiceRefrence”, then click the OK button. If you entered everything correctly, Visual Studio will generate some code that allows you to connect to your Product service. On the MainPage.xaml designer window double click on the Get XML button to generate the Click event procedure for this button. In the Click event procedure make a call to a GetXmlFromServer() method. This method will also need a “Completed” event procedure to be written since all communication with a WCF Service from Windows Phone must be asynchronous.  Write these two methods as follows: private const string KEY_NAME = "ProductData"; private void GetXmlFromServer(){  ProductServiceClient client = new ProductServiceClient();   client.GetProductXmlCompleted += new     EventHandler<GetProductXmlCompletedEventArgs>      (client_GetProductXmlCompleted);   client.GetProductXmlAsync();  client.CloseAsync();} void client_GetProductXmlCompleted(object sender,                                   GetProductXmlCompletedEventArgs e){  // Store XML data in Isolated Storage  IsolatedStorageSettings.ApplicationSettings[KEY_NAME] = e.Result;   btnRead.IsEnabled = true;} As you can see, this is a fairly standard call to a WCF Service. In the Completed event you get the Result from the event argument, which is the XML, and store it into Isolated Storage using the IsolatedStorageSettings.ApplicationSettings class. Notice the constant that I added to specify the name of the key. You will use this constant later to read the data from Isolated Storage. Step 4: Create a Product Class Even though you stored XML data into Isolated Storage when you read that data out you will want to convert each element in the XML file into an actual Product object. This means that you need to create a Product class in your Windows Phone application. Add a Product class to your project that looks like the code below: public class Product{  public string ProductName{ get; set; }  public int ProductId{ get; set; }  public DateTime IntroductionDate{ get; set; }  public decimal Price{ get; set; }} Step 5: Read Settings from Isolated Storage Now that you have the XML data stored in Isolated Storage, it is time to use it. Go back to the MainPage.xaml design view and double click on the Read XML button to generate the Click event procedure. From the Click event procedure call a method named ReadProductXml().Create this method as shown below: private void ReadProductXml(){  XElement xElem = null;   if (IsolatedStorageSettings.ApplicationSettings.Contains(KEY_NAME))  {    xElem = XElement.Parse(     IsolatedStorageSettings.ApplicationSettings[KEY_NAME].ToString());     // Create a list of Product objects    var products =         from prod in xElem.Descendants("Product")        orderby prod.Attribute("ProductName").Value        select new Product        {          ProductId = Convert.ToInt32(prod.Attribute("ProductId").Value),          ProductName = prod.Attribute("ProductName").Value,          IntroductionDate =             Convert.ToDateTime(prod.Attribute("IntroductionDate").Value),          Price = Convert.ToDecimal(prod.Attribute("Price").Value)        };     lstData.DataContext = products;  }} The ReadProductXml() method checks to make sure that the key name that you saved your XML as exists in Isolated Storage prior to trying to open it. If the key name exists, then you retrieve the value as a string. Use the XElement’s Parse method to convert the XML string to a XElement object. LINQ to XML is used to iterate over each element in the XElement object and create a new Product object from each attribute in your XML file. The LINQ to XML code also orders the XML data by the ProductName. After the LINQ to XML code runs you end up with an IEnumerable collection of Product objects in the variable named “products”. You assign this collection of product data to the DataContext of the ListBox you created in XAML. The DisplayMemberPath property of the ListBox is set to “ProductName” so it will now display the product name for each row in your products collection. Summary In this article you learned how to retrieve an XML string from a table in a database, return that string across a WCF Service and store it into Isolated Storage on your Windows Phone. You then used LINQ to XML to create a collection of Product objects from the data stored and display that data in a Windows Phone list box. This same technique can be used in Silverlight or WPF applications too. NOTE: You can download the complete sample code at my website. http://www.pdsa.com/downloads. Choose Tips & Tricks, then "Get XML From Server for Use on Windows Phone" from the drop-down. Good Luck with your Coding,Paul Sheriff ** SPECIAL OFFER FOR MY BLOG READERS **Visit http://www.pdsa.com/Event/Blog for a free video on Silverlight entitled Silverlight XAML for the Complete Novice - Part 1.  

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