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  • Fetch data from multiple MySQL tables

    - by Jon McIntosh
    My two tables look like this: TABLE1 TABLE2 +--------------------+ +--------------------+ |field1|field2|field3| and |field2|field4|field5| +--------------------+ +--------------------+ I am already running a SELECT query for TABLE1, and assorting all of the data into variables: $query = "SELECT * FROM TABLE1 WHERE field2 = 2"; $result = mysql_query($query); $num_rows = mysql_num_rows($result); if((!is_bool($result) || $result) && $num_rows) { while($row = mysql_fetch_array($result)) { $field1 = $row['field1']; $field2 = $row['field2']; $field3 = $row['field3']; } } What I want to do is get the data from 'field4' on TABLE2 and add it to my variables. I would want to get field4 WHERE field2 = 2

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  • MySQL problem: How to get desired rows.

    - by Joonas Köppä
    I have been trying to solve this problem for 2 hours now but I cant understand the solutions others have given people with a similar problem. Ive seen some answers but can't apply it to my own needs. I have a table of users and their times in different sports events. I need to make a scoretable that shows the user with the best time, second best etc. The table before sorting and retrieving looks as follows: | Name | Time | Date | '''''''''''''''''''''''''''''''''''''''''''''' | Jack | 03:07:13 | 2010-12-01 | | Peter | 05:03:12 | 2010-12-03 | | Jack | 03:53:19 | 2010-12-04 | | Simon | 03:22:59 | 2010-12-02 | | Simon | 04:01:11 | 2010-12-09 | | Peter | 03:19:17 | 2010-12-06 | '''''''''''''''''''''''''''''''''''''''''''''' | Name | Time | Date | '''''''''''''''''''''''''''''''''''''''''' | Jack | 03:07:13 | 2010-12-01 | | Peter | 03:19:17 | 2010-12-06 | | Simon | 03:22:59 | 2010-12-02 | '''''''''''''''''''''''''''''''''''''''''' I know answers to this problem lie in another question asked on this very site: CLICK HERE I just have no idea how to apply it to fullfill my needs. Help is highly appreciated. Thank you -Joonas

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  • fast retrieval from MYSQL DB

    - by trojanwarrior3000
    I have a table of users - It contains around millions of rows (user-id is the primary key). I just want to retrieve user-id and their joining date. using "select user-id,joining date from table user" requires lot of time.Is there a fast way to query/retrieve the same data from this table?

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  • Count Distinct With IF in MySQL?

    - by user1600801
    I need to do a query with count distinct and IF, but the results always are 0. What I need to do, is count the different users from a table in different months, using IF. My individual query, for one month is this: SELECT COUNT(DISTINCT(idUsers)) AS num_usuarios FROM table01 WHERE date1='201207' But I need to get the results by different months in the same query. What I'm trying to do is this: SELECT IF(date1=(201207), count(distinct(idUsers)), 0) as user30, IF(fecha1=(201206), count(distinct(idUsers)), 0) as user60, IF(fecha1=(201205), count(distinct(idUsers)), 0) as user90, IF(fecha1=(201204), count(distinct(idUsers)), 0) as user120, IF(fecha1=(201203), count(distinct(idUsers)), 0) as user150 FROM table01 But the all the results are always 0.

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  • MySQL GROUP BY and JOIN

    - by christian
    Guys what's wrong with this SQL query: $sql = "SELECT res.Age, res.Gender, answer.*, $get_sum, SUM(CASE WHEN res.Gender='Male' THEN 1 else 0 END) AS males, SUM(CASE WHEN res.Gender='Female' THEN 1 else 0 END) AS females FROM Respondents AS res INNER JOIN Answers as answer ON answer.RespondentID=res.RespondentID INNER JOIN Questions as question ON answer.Answer=question.id WHERE answer.Question='Q1' GROUP BY res.Age ORDER BY res.Age ASC"; the $get_sum is an array of sql statement derived from another table: $sum[]= "SUM(CASE WHEN answer.Answer=".$db->f("id")." THEN 1 else 0 END) AS item".$db->f("id"); $get_sum = implode(', ', $sum); the query above return these values: Age: 20 item1 0 item2 1 item3 1 item4 1 item5 0 item6 0 Subtotal for Age 20 3 Age: 24 item1 2 item2 2 item3 2 item4 2 item5 1 item6 0 Subtotal for Age 24 9 It should return: Subtotal for Age 20 1 Subtotal for Age 24 2 In my sample data there are 3 respondents 2 are 24 yrs of age and the other one is 20 years old.

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  • Select and copy to MySQL table PHP

    - by Liju
    Can insert the table1 value to Table2 like the follows.. based on Name Date. Table1 Id Date Name time 1 20/11/2010 Tom 08:00 2 20/11/2010 Tom 08:30 3 20/11/2010 Tom 09:00 4 20/11/2010 Tom 09:30 5 20/11/2010 Tom 10:00 6 20/11/2010 Tom 10:30 7 20/11/2010 Tom 11:30 8 20/11/2010 Tom 14:30 9 20/11/2010 John 08:10 10 20/11/2010 John 09:30 11 20/11/2010 John 11:00 12 20/11/2010 John 13:00 13 20/11/2010 John 14:30 14 20/11/2010 John 16:00 15 20/11/2010 John 17:30 16 20/11/2010 John 19:00 17 20/11/2010 Ram 08:05 18 20/11/2010 Ram 08:30 19 20/11/2010 Ram 09:00 20 20/11/2010 Ram 09:45 21 20/11/2010 Ram 12:00 22 20/11/2010 Ram 13:30 23 20/11/2010 Ram 15:00 Table2 Id Date Name Time In1 Time Out1 Time In1 Time Out1 Time In1 Time Out1 Time In4 Time Out4 1 20/11/2010 Tom 08:00 08:30 09:00 09:30 10:00 10:30 11:30 14:30 2 20/11/2011 John 08:10 09:30 11:00 13:00 14:30 16:00 17:30 19:00 3 20/11/2012 Ram 08:05 08:30 09:00 09:45 12:00 13:30 15:00 Null Help me Please... Liju

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  • Mysql data convert

    - by Sergio
    Is it possible to do DATE_SUB( ".$date." , INTERVAL 100 DAY ) if the type of the column where the date is stored is varchar(255) or I need to convert that column to "DATE" type?

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  • Collaborative filtering in MySQL ?

    - by user281434
    Hi I'm trying to develop a site that recommends items(fx. books) to users based on their preferences. So far, I've read O'Reilly's "Collective Intelligence" and numerous other online articles. They all, however, seem to deal with single instances of recommendation, for example if you like book A then you might like book B. What I'm trying to do is to create a set of 'preference-nodes' for each user on my site. Let's say a user likes book A,B and C. Then, when they add book D, I don't want the system to recommend other books based solely other users experience with book D. I wan't the system to look up similar 'preference-nodes' and recommend books based on that. Here's an example of 4 nodes: User1: 'book A'->'book B'->'book C' User2: 'book A'->'book B'->'book C'->'book D' user3: 'book X'->'book Y'->'book C'->'book Z' user4: 'book W'->'book Q'->'book C'->'book Z' So a recommendation system, as described in the material I've read, would recommend book Z to User 1, because there are two people who recommends Z in conjuction with liking C (ie. Z weighs more than D), even though a user with a similar 'preference-node', User2, would be more qualified to recommend book D because he has a more similar interest-pattern. So does any of you have any experience with this sort of thing? Is there some things I should try to read or does there exist any open source systems for this? Thanks for your time! Small edit: I think last.fm's algorithm is doing exactly what I my system to do. Using the preference-trees of people to recommmend music more personally to people. Instead of just saying "you might like B because you liked A"

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  • MYSQL CASE WHEN PROBLEM

    - by user305270
    SELECT `profiles`.* FROM `profiles` INNER JOIN `friendships` ON `profiles`.id = `friendships`.(CASE WHEN friendships.profile_id = 1 THEN`friend_id` ELSE `profile_id` END) How can i make the inner join like profile.id = friendships.(here will select the one key that is needed) but it doesnt work. please help :P it cant be: `profiles`.id = (CASE WHEN friendships.profile_id = 1 THEN `friendships`.`friend_id` ELSE `friendships`.`profile_id` END)

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  • How to optimize this mysql query - explain output included

    - by Sandeepan Nath
    This is the query (a search query basically, based on tags):- select SUM(DISTINCT(ttagrels.id_tag in (2105,2120,2151,2026,2046) )) as key_1_total_matches, td.*, u.* from Tutors_Tag_Relations AS ttagrels Join Tutor_Details AS td ON td.id_tutor = ttagrels.id_tutor JOIN Users as u on u.id_user = td.id_user where (ttagrels.id_tag in (2105,2120,2151,2026,2046)) group by td.id_tutor HAVING key_1_total_matches = 1 And following is the database dump needed to execute this query:- CREATE TABLE IF NOT EXISTS `Users` ( `id_user` int(10) unsigned NOT NULL auto_increment, `id_group` int(11) NOT NULL default '0', PRIMARY KEY (`id_user`), KEY `Users_FKIndex1` (`id_group`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=730 ; INSERT INTO `Users` (`id_user`, `id_group`) VALUES (303, 1); CREATE TABLE IF NOT EXISTS `Tutor_Details` ( `id_tutor` int(10) unsigned NOT NULL auto_increment, `id_user` int(10) NOT NULL default '0', PRIMARY KEY (`id_tutor`), KEY `Users_FKIndex1` (`id_user`), KEY `id_user` (`id_user`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=58 ; INSERT INTO `Tutor_Details` (`id_tutor`, `id_user`) VALUES (26, 303); CREATE TABLE IF NOT EXISTS `Tags` ( `id_tag` int(10) unsigned NOT NULL auto_increment, `tag` varchar(255) default NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`), KEY `tag_4` (`tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=2957 ; INSERT INTO `Tags` (`id_tag`, `tag`) VALUES (2026, 'Brendan.\nIn'), (2046, 'Brendan.'), (2105, 'Brendan'), (2120, 'Brendan''s'), (2151, 'Brendan)'); CREATE TABLE IF NOT EXISTS `Tutors_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_tutor` int(10) unsigned default NULL, `tutor_field` varchar(255) default NULL, `cdate` timestamp NOT NULL default CURRENT_TIMESTAMP, `udate` timestamp NULL default NULL, KEY `Tutors_Tag_Relations` (`id_tag`), KEY `id_tutor` (`id_tutor`), KEY `id_tag` (`id_tag`), KEY `id_tutor_2` (`id_tutor`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Tutors_Tag_Relations` (`id_tag`, `id_tutor`, `tutor_field`, `cdate`, `udate`) VALUES (2105, 26, 'firstname', '2010-06-17 17:08:45', NULL); ALTER TABLE `Tutors_Tag_Relations` ADD CONSTRAINT `Tutors_Tag_Relations_ibfk_2` FOREIGN KEY (`id_tutor`) REFERENCES `Tutor_Details` (`id_tutor`) ON DELETE NO ACTION ON UPDATE NO ACTION, ADD CONSTRAINT `Tutors_Tag_Relations_ibfk_1` FOREIGN KEY (`id_tag`) REFERENCES `Tags` (`id_tag`) ON DELETE NO ACTION ON UPDATE NO ACTION; What the query does? This query actually searches tutors which contain "Brendan"(as their name or biography or something). The id_tags 2105,2120,2151,2026,2046 are nothing but the tags which are LIKE "%Brendan%". My question is :- 1.In the explain of this query, the reference column shows NULL for ttagrels, but there are possible keys (Tutors_Tag_Relations,id_tutor,id_tag,id_tutor_2). So, why is no key being taken. How to make the query take references. Is it possible at all? 2. The other two tables td and u are using references. Any indexing needed in those? I think not. Check the explain query output here http://www.test.examvillage.com/explain.png

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  • MYSQL Select and group by date

    - by Gil
    I'm not sure how create a right query to get the result I'm looking for. What I have is 2 tables. first has ID, Name columns and second has date and adminID, which is referenced from table 1 column ID. Now, what I want to get is basically number of times each admin loged in per day during the month. From structure like this one I want to get per day and month data so result would be similar to 1, 2, 2 march total 5 for admin 4. ID | Date ------------------ 4 | 2010/03/01 4 | 2010/03/04 4 | 2010/03/04 4 | 2010/03/05 4 | 2010/03/05

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  • MySQL top count({column}) with a limit

    - by Josh K
    I have a table with an ip address column. I would like to find the top five addresses which are listed. Right now I'm planning it out the following: Select all distinct ip addresses Loop through them all saying count(id) where IP='{ip}' and storing the count List the top five counts. Downsides include what if I have 500 ip addresses. That's 500 queries I have to run to figure out what are the top five. I'd like to build a query like so select ip from table where 1 order by count({distinct ip}) asc limit 5

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  • MySQL DATETIME format comparison - is strtotime needed?

    - by Steffan
    I've been doing something along the lines of.. $dt1 = '1000-01-01 00:00:00'; //really some val from db $dt2 = '1000-01-01 00:00:10'; //another val maybe db maybe formatted if(strtotime($dt1) > strtotime($dt2){ //do something } Is the strtotime needed? can i do a more direct comparison on the datetime formatted strings? i.e. if($dt1 > $dt2){ //do something } Will that always work?

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  • mysql table marked as crashed

    - by Phil Jackson
    I recently created a ajax based instant messaging application and after running for a while I got an error [table] is marked as crashed and should be repaired. How could this have happened and how do I go about preventing it happening again?

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  • Special characters in PHP / MySQL

    - by Jonathan
    Hi, I have in the database words that include special character (in Spanish mostly, like tildes). In the database everything is saved and shown correctly with PHPmyAdmin, but when I get the data (using PHP) and display it in a browser, I get a weird character, like a "?" with a square... I need a general fix so I don't need to escape each character every time, and also I would be able to insert special Spanish characters from a PHP form into the database... The HTML is correct: <meta http-equiv="content-type" content="text/html; charset=utf-8" /> All tables and databas are set to utf8_spanish The character I get: ? Any suggestions??? Thanks!!!

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  • MySQL & PHP - Creating Multiple Parent Child Relations

    - by Ashok
    Hi, I'm trying to build a navigation system using categories table with hierarchies. Normally, the table would be defined as follows: id (int) - Primary key name (varchar) - Name of the Category parentid (int) - Parent ID of this Category referenced to same table (Self Join) But the catch is that I require that a category can be child to multiple parent categories.. Just like a Has and Belongs to Many (HABTM) relation. I know that if there are two tables, categories & items, we use a join table categories_items to list the HABTM relations. But here i'm not having two tables but only table but should somehow show HABTM relations to itself. Is this be possible using a single table? If yes, How? If not possible, what rules (table naming, fields) should I follow while creating the additional join table? I'm trying to achieve this using CakePHP, If someone can provide CakePHP solution for this problem, that would be awesome. Even if that's not possible, any solution about creating join table is appreciated. Thanks for your time.

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  • how to atomically claim a row or resource using UPDATE in mysql

    - by Igor
    i have a table of resources (lets say cars) which i want to claim atomically. if there's a limit of one resource per one user, i can do the following trick: UPDATE cars SET user = 'bob' WHERE user IS NULL LIMIT 1 SELECT * FROM cars WHERE user IS bob that way, i claim the resource atomically and then i can see which row i just claimed. this doesn't work when 'bob' can claim multiple cars. i realize i can get a list of cars already claimed by bob, claim another one, and then SELECT again to see what's changed, but that feels hackish. What I'm wondering is, is there some way to see which rows i just updated with my last UPDATE? failing that, is there some other trick to atomically claiming a row? i really want to avoid using SERIALIZABLE isolation level. If I do something like this: 1 SELECT id FROM cars WHERE user IS NULL 2 <here, my PHP or whatever picks a car id> 3 UPDATE cars SET user = 'bob' WHERE id = <the one i picked> would REPEATABLE READ be sufficient here? in other words, could i be guaranteed that some other transactions won't claim the row my software has picked during step 2?

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  • Select from mysql by day with different timezones (php)

    - by Adam
    I'm storing leads in a database, and each lead has a datetime field with a PST timezone based date & time. I want my user to be able to display all leads from a certain date (e.g. today, yseterday), and choose the timezone. E.g. if I want to see all leads that were generated yesterday in EST timezone, I need to first convert (or read) all the datetime values to EST, and then only select those who are in the right range (yesterday). What would be the best way to do that?

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  • Script working with mysql and php into a textarea and back

    - by Tribalcomm
    I am trying to write a custom script that will keep a list of strings in a textarea. Each line of the textarea will be a row from a table. The problem I have is how to work the script to allow for adding, updating, or deleting rows based on a submit. So, for instance, I currently have 3 rows in the database: john sue mark I want to be able to delete sue and add richard and it will delete the row with sue and insert a row for richard. My code so far is as follows: To query the db and list it in the textarea: $basearray = mysql_query("SELECT name FROM mytable ORDER BY name"); <textarea name="names" cols=6 rows=12>'); <?php foreach($basearray as $base){ echo $base->name."\n"; } ?> </textarea> After the submit, I have: <?php $namelist = $_REQUEST[names]; $newarray = explode("\n", $namelist); foreach($newarray as $name) { if (!in_array($name, $basearray)) { mysql_query(DELETE FROM mytable WHERE word='$name'"); } elseif (in_array($name, $basearray)) { ; } else { mysql_query("INSERT INTO mytable (name) VALUES ("$name")"); } } ?> Please tell me what I am doing wrong. I am not getting any functions to work when I edit the contents of the textarea. Thanks!

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  • Mysql SELECT nested query, very complicated?

    - by smartbear
    Okay, first following are my tables: Table house: id | items_id | 1 | 1,5,10,20 | Table items: id | room_name | refer 1 | kitchen | 3 5 | room1 | 10 Table kitchen: id | detail_name | refer 3 | spoon | 4 5 | fork | 10 Table spoon: id | name | color | price | quantity_available | 4 | spoon_a | white | 50 | 100 | 5 | spoon_b | black | 30 | 200 | How to do a nested select statement, where I want to select id, name, color, price and quantity_available column, from the each value inside the 'items_id' column in 'house' table? This is very challenging!! EDIT: after read robin's answer Table house: id | items_id | house1 | 1 | house1 | 5 | house1 | 10 | house2 | 20 | If this it the house table, how to do the nested, join, or whatever select statement??

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