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  • Google appEngine: 404 when accesing /_ah/api

    - by jfu
    I try to build a very simple GAE application, using eclipse and the Google Plugin for Eclipse. I've generated some Endpoint from an @Entity class, then I've generated Cloud Endpoint Client library. After that I've started the appEngine project (within eclipse, on the embedded jetty server). When I try to access /_ah/api I get the following issue: HTTP ERROR 500 Problem accessing /_ah/api/. Reason: Failed to retrieve API configs with status: 404 Caused by: java.io.IOException: Failed to retrieve API configs with status: 404 at com.google.api.server.spi.tools.devserver.ApiServlet.getApiConfigSources(ApiServlet.java:102) at com.google.api.server.spi.tools.devserver.ApiServlet.initConfigsIfNecessary(ApiServlet.java:67) at com.google.api.server.spi.tools.devserver.RestApiServlet.service(RestApiServlet.java:117) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:511) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1166) at com.google.appengine.api.socket.dev.DevSocketFilter.doFilter(DevSocketFilter.java:74) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1157) at com.google.appengine.tools.development.ResponseRewriterFilter.doFilter(ResponseRewriterFilter.java:123) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1157) at com.google.appengine.tools.development.HeaderVerificationFilter.doFilter(HeaderVerificationFilter.java:34) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1157) at com.google.appengine.api.blobstore.dev.ServeBlobFilter.doFilter(ServeBlobFilter.java:63) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1157) at com.google.apphosting.utils.servlet.TransactionCleanupFilter.doFilter(TransactionCleanupFilter.java:43) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1157) at com.google.appengine.tools.development.StaticFileFilter.doFilter(StaticFileFilter.java:125) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1157) at com.google.appengine.tools.development.DevAppServerModulesFilter.doDirectRequest(DevAppServerModulesFilter.java:368) at com.google.appengine.tools.development.DevAppServerModulesFilter.doDirectModuleRequest(DevAppServerModulesFilter.java:351) at com.google.appengine.tools.development.DevAppServerModulesFilter.doFilter(DevAppServerModulesFilter.java:116) at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1157) at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:388) at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:182) at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:765) at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:418) What am I doing wrong?

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  • Rails dealing with blank params at controller level

    - by stephenmurdoch
    I have a User model: class User < ActiveRecord::Base has_secure_password # validation lets users update accounts without entering password validates :password, presence: { on: :create }, allow_blank: { on: :update } validates :password_confirmation, presence: { if: :password_digest_changed? } end I also have a password_reset_controller: def update # this is emailed to the user by the create action - not shown @user=User.find_by_password_reset_token!(params[:id]) if @user.update_attributes(params[:user]) # user is signed in if password and confirmation pass validations sign_in @user redirect_to root_url, :notice => "Password has been reset." else flash.now[:error] = "Something went wrong, please try again." render :edit end end Can you see the problem here? A user can submit a blank a password/confirmation and rails will sign them in, because the User model allows blank on update. It's not a security concern, since an attacker would still need access to a user's email account before they could get anywhere near this action, but my problem is that a user submitting 6 blank chars would be signed in, and their password would not be changed for them, which could lead to confusion later on. So, I've come up with the following solution, and I'd like to check if there's a better way of doing it, before I push to production: def update @user=User.find_by_password_reset_token!(params[:id]) # if user submits blank password, add an error, and render edit action if params[:user][:password].blank? @user.errors.add(:password_digest, "can't be blank.") render :edit elsif @user.update_attributes(params[:user]) sign_in @user redirect_to root_url, :notice => "Password has been reset." else flash.now[:error] = "Something went wrong, please try again." render :edit end end Should I be checking for nil as well as blank? Are there any rails patterns or idiomatic ruby techniques for solving this? [Fwiw, I've got required: true on the html inputs, but want this handled server side too.]

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  • How to build Open JavaFX for Android.

    - by PictureCo
    Here's a short recipe for baking JavaFX for Android dalvik. We will need just a few ingredients but each one requires special care. So let's get down to the business.  SourcesThe first ingredient is an open JavaFX repository. This should be piece of cake. As always there's a catch. You probably know that dalvik is jdk6 compatible  and also that certain APIs are missing comparing to good old java vm from Oracle.  Fortunately there is a repository which is a backport of regular OpenJFX to jdk7 and going from jdk7 to jdk6 is possible. The first thing to do is to clone or download the repository from https://bitbucket.org/narya/jfx78. Main page of the project says "It works in some cases" so we will presume that it will work in most cases As I've said dalvik vm misses some APIs which would lead to a build failures. To get them use another compatibility repository which is available on GitHub https://github.com/robovm/robovm-jfx78-compat. Download the zip and unzip sources into jfx78/modules/base.We need also a javafx binary stubs. Use jfxrt.jar from jdk8.The last thing to download are freetype sources from http://freetype.org. These will be necessary for native font rendering. Toolchain setup I have to point out that these instructions were tested only on linux. I suppose they will work with minimal changes also on Mac OS. I also presume that you were able to build open JavaFX. That means all tools like ant, gradle, gcc and jdk8 have been installed and are working all right. In addition to this you will need to download and install jdk7, Android SDK and Android NDK for native code compilation.  Installing all of them will take some time. Don't forget to put them in your path. export ANDROID_SDK=/opt/android-sdk-linux export ANDROID_NDK=/opt/android-ndk-r9b export JAVA_HOME=/opt/jdk1.7.0 export PATH=$JAVA_HOME/bin:$ANDROID_SDK/tools:$ANDROID_SDK/platform-tools:$ANDROID_NDK FreetypeUnzip freetype release sources first. We will have to cross compile them for arm. Firstly we will create a standalone toolchain for cross compiling installed in ~/work/ndk-standalone-19. $ANDROID_NDK/build/tools/make-standalone-toolchain.sh  --platform=android-19 --install-dir=~/work/ndk-standalone-19 After the standalone toolchain has been created cross compile freetype with following script: export TOOLCHAIN=~/work/freetype/ndk-standalone-19 export PATH=$TOOLCHAIN/bin:$PATH export FREETYPE=`pwd` ./configure --host=arm-linux-androideabi --prefix=$FREETYPE/install --without-png --without-zlib --enable-shared sed -i 's/\-version\-info \$(version_info)/-avoid-version/' builds/unix/unix-cc.mk make make install It will compile and install freetype library into $FREETYPE/install. We will link to this install dir later on. It would be possible also to link openjfx font support dynamically against skia library available on Android which already contains freetype. It creates smaller result but can have compatibility problems. Patching Download patches javafx-android-compat.patch + android-tools.patch and patch jfx78 repository. I recommend to have look at patches. First one android-compat.patch updates openjfx build script, removes dependency on SharedSecret classes and updates LensLogger to remove dependency on jdk specific PlatformLogger. Second one android-tools.patch creates helper script in android-tools. The script helps to setup javaFX Android projects. Building Now is time to try the build. Run following script: JAVA_HOME=/opt/jdk1.7.0 JDK_HOME=/opt/jdk1.7.0 ANDROID_SDK=/opt/android-sdk-linux ANDROID_NDK=/opt/android-ndk-r9b PATH=$JAVA_HOME/bin:$ANDROID_SDK/tools:$ANDROID_SDK/platform-tools:$ANDROID_NDK:$PATH gradle -PDEBUG -PDALVIK_VM=true -PBINARY_STUB=~/work/binary_stub/linux/rt/lib/ext/jfxrt.jar \ -PFREETYPE_DIR=~/work/freetype/install -PCOMPILE_TARGETS=android If everything went all right the output is in build/android-sdk Create first JavaFX Android project Use gradle script int android-tools. The script sets the project structure for you.   Following command creates Android HelloWorld project which links to a freshly built javafx runtime and to a HelloWorld application. NAME is a name of Android project. DIR where to create our first project. PACKAGE is package name required by Android. It has nothing to do with a packaging of javafx application. JFX_SDK points to our recently built runtime. JFX_APP points to dist directory of javafx application. (where all application jars sit) JFX_MAIN is fully qualified name of a main class. gradle -PDEBUG -PDIR=/home/user/work -PNAME=HelloWorld -PPACKAGE=com.helloworld \ -PJFX_SDK=/home/user/work/jfx78/build/android-sdk -PJFX_APP=/home/user/NetBeansProjects/HelloWorld/dist \ -PJFX_MAIN=com.helloworld.HelloWorld createProject Now cd to the created project and use it like any other android project. ant clean, debug, uninstall, installd will work. I haven't tried it from any IDE Eclipse nor Netbeans. Special thanks to Stefan Fuchs and Daniel Zwolenski for the repositories used in this blog post.

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  • Mpd as pppoe server with authorisation by freeradius2

    - by Korjavin Ivan
    I install freeradius2, add to raddb/users: test Cleartext-Password := "test1" Service-Type = Framed-User, Framed-Protocol = PPP, Framed-IP-Address = 10.36.0.2, Framed-IP-Netmask = 255.255.255.0, start radiusd, and check auth: radtest test test1 127.0.0.1 1002 testing123 Sending Access-Request of id 199 to 127.0.0.1 port 1812 User-Name = "test" User-Password = "test1" NAS-IP-Address = 127.0.0.1 NAS-Port = 1002 Message-Authenticator = 0x00000000000000000000000000000000 rad_recv: Access-Accept packet from host 127.0.0.1 port 1812, id=199, length=44 Service-Type = Framed-User Framed-Protocol = PPP Framed-IP-Address = 10.36.0.2 Framed-IP-Netmask = 255.255.255.0 Works fine. Next step. Add to mpd.conf: radius: set auth disable internal set auth max-logins 1 CI set auth enable radius-auth set radius timeout 90 set radius retries 2 set radius server 127.0.0.1 testing123 1812 1813 set radius me 127.0.0.1 create link template L pppoe set link action bundle B set link max-children 1000 set link no multilink set link no shortseq set link no pap chap-md5 chap-msv1 chap-msv2 set link enable chap set pppoe acname Internet load radius create link template em1 L set pppoe iface em1 set link enable incoming And trying to connect, auth failed, here is mpd log: mpd: [em1-2] LCP: auth: peer wants nothing, I want CHAP mpd: [em1-2] CHAP: sending CHALLENGE #1 len: 21 mpd: [em1-2] LCP: LayerUp mpd: [em1-2] CHAP: rec'd RESPONSE #1 len: 58 mpd: [em1-2] Name: "test" mpd: [em1-2] AUTH: Trying RADIUS mpd: [em1-2] RADIUS: Authenticating user 'test' mpd: [em1-2] RADIUS: Rec'd RAD_ACCESS_REJECT for user 'test' mpd: [em1-2] AUTH: RADIUS returned: failed mpd: [em1-2] AUTH: ran out of backends mpd: [em1-2] CHAP: Auth return status: failed mpd: [em1-2] CHAP: Reply message: ^AE=691 R=1 mpd: [em1-2] CHAP: sending FAILURE #1 len: 14 mpd: [em1-2] LCP: authorization failed Then i start freeradius as radiusd -fX, and get this log: rad_recv: Access-Request packet from host 127.0.0.1 port 46400, id=223, length=282 NAS-Identifier = "rubin.svyaz-nt.ru" NAS-IP-Address = 127.0.0.1 Message-Authenticator = 0x14d36639bed8074ec2988118125367ea Acct-Session-Id = "815965-em1-2" NAS-Port = 2 NAS-Port-Type = Ethernet Service-Type = Framed-User Framed-Protocol = PPP Calling-Station-Id = "00e05290b3e3 / 00:e0:52:90:b3:e3 / em1" NAS-Port-Id = "em1" Vendor-12341-Attr-12 = 0x656d312d32 Tunnel-Medium-Type:0 = IEEE-802 Tunnel-Client-Endpoint:0 = "00:e0:52:90:b3:e3" User-Name = "test" MS-CHAP-Challenge = 0xbb1e68d5bbc30f228725a133877de83e MS-CHAP2-Response = 0x010088746ae65b68e435e9d045ad6f9569b60000000000000000b56991b4f20704cb6c68e5982eec5e98a7f4b470c109c1b9 # Executing section authorize from file /usr/local/etc/raddb/sites-enabled/default +- entering group authorize {...} ++[preprocess] returns ok ++[chap] returns noop [mschap] Found MS-CHAP attributes. Setting 'Auth-Type = mschap' ++[mschap] returns ok [eap] No EAP-Message, not doing EAP ++[eap] returns noop [files] users: Matched entry DEFAULT at line 172 ++[files] returns ok Found Auth-Type = MSCHAP # Executing group from file /usr/local/etc/raddb/sites-enabled/default +- entering group MS-CHAP {...} [mschap] No Cleartext-Password configured. Cannot create LM-Password. [mschap] No Cleartext-Password configured. Cannot create NT-Password. [mschap] Creating challenge hash with username: test [mschap] Client is using MS-CHAPv2 for test, we need NT-Password [mschap] FAILED: No NT/LM-Password. Cannot perform authentication. [mschap] FAILED: MS-CHAP2-Response is incorrect ++[mschap] returns reject Failed to authenticate the user. Login incorrect: [test] (from client localhost port 2 cli 00e05290b3e3 / 00:e0:52:90:b3:e3 / em1) Using Post-Auth-Type REJECT # Executing group from file /usr/local/etc/raddb/sites-enabled/default +- entering group REJECT {...} [attr_filter.access_reject] expand: %{User-Name} -> test attr_filter: Matched entry DEFAULT at line 11 ++[attr_filter.access_reject] returns updated Delaying reject of request 2 for 1 seconds Going to the next request Waking up in 0.9 seconds. Sending delayed reject for request 2 Sending Access-Reject of id 223 to 127.0.0.1 port 46400 MS-CHAP-Error = "\001E=691 R=1" Why i have error "[mschap] No Cleartext-Password configured. Cannot create LM-Password." ? I define cleartext-password in users. I check raddb/sites-enabled/default authorize { chap mschap eap { ok = return } files } looks ok for me. Whats wrong with mpd/chap/radius ?

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  • SSH error: Permission denied, please try again

    - by Kamal
    I am new to ubuntu. Hence please forgive me if the question is too simple. I have a ubuntu server setup using amazon ec2 instance. I need to connect my desktop (which is also a ubuntu machine) to the ubuntu server using SSH. I have installed open-ssh in ubuntu server. I need all systems of my network to connect the ubuntu server using SSH (no need to connect through pem or pub keys). Hence opened SSH port 22 for my static IP in security groups (AWS). My SSHD-CONFIG file is: # Package generated configuration file # See the sshd_config(5) manpage for details # What ports, IPs and protocols we listen for Port 22 # Use these options to restrict which interfaces/protocols sshd will bind to #ListenAddress :: #ListenAddress 0.0.0.0 Protocol 2 # HostKeys for protocol version 2 HostKey /etc/ssh/ssh_host_rsa_key HostKey /etc/ssh/ssh_host_dsa_key HostKey /etc/ssh/ssh_host_ecdsa_key #Privilege Separation is turned on for security UsePrivilegeSeparation yes # Lifetime and size of ephemeral version 1 server key KeyRegenerationInterval 3600 ServerKeyBits 768 # Logging SyslogFacility AUTH LogLevel INFO # Authentication: LoginGraceTime 120 PermitRootLogin yes StrictModes yes RSAAuthentication yes PubkeyAuthentication yes #AuthorizedKeysFile %h/.ssh/authorized_keys # Don't read the user's ~/.rhosts and ~/.shosts files IgnoreRhosts yes # For this to work you will also need host keys in /etc/ssh_known_hosts RhostsRSAAuthentication no # similar for protocol version 2 HostbasedAuthentication no # Uncomment if you don't trust ~/.ssh/known_hosts for RhostsRSAAuthentication #IgnoreUserKnownHosts yes # To enable empty passwords, change to yes (NOT RECOMMENDED) PermitEmptyPasswords no # Change to yes to enable challenge-response passwords (beware issues with # some PAM modules and threads) ChallengeResponseAuthentication no # Change to no to disable tunnelled clear text passwords #PasswordAuthentication yes # Kerberos options #KerberosAuthentication no #KerberosGetAFSToken no #KerberosOrLocalPasswd yes #KerberosTicketCleanup yes # GSSAPI options #GSSAPIAuthentication no #GSSAPICleanupCredentials yes X11Forwarding yes X11DisplayOffset 10 PrintMotd no PrintLastLog yes TCPKeepAlive yes #UseLogin no #MaxStartups 10:30:60 #Banner /etc/issue.net # Allow client to pass locale environment variables AcceptEnv LANG LC_* Subsystem sftp /usr/lib/openssh/sftp-server # Set this to 'yes' to enable PAM authentication, account processing, # and session processing. If this is enabled, PAM authentication will # be allowed through the ChallengeResponseAuthentication and # PasswordAuthentication. Depending on your PAM configuration, # PAM authentication via ChallengeResponseAuthentication may bypass # the setting of "PermitRootLogin without-password". # If you just want the PAM account and session checks to run without # PAM authentication, then enable this but set PasswordAuthentication # and ChallengeResponseAuthentication to 'no'. UsePAM yes Through webmin (Command shell), I have created a new user named 'senthil' and added this new user to 'sudo' group. sudo adduser -y senthil sudo adduser senthil sudo I tried to login using this new user 'senthil' in 'webmin'. I was able to login successfully. When I tried to connect ubuntu server from my terminal through SSH, ssh senthil@SERVER_IP It asked me to enter password. After the password entry, it displayed: Permission denied, please try again. On some research I realized that, I need to monitor my server's auth log for this. I got the following error in my auth log (/var/log/auth.log) Jul 2 09:38:07 ip-192-xx-xx-xxx sshd[3037]: pam_unix(sshd:auth): authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=MY_CLIENT_IP user=senthil Jul 2 09:38:09 ip-192-xx-xx-xxx sshd[3037]: Failed password for senthil from MY_CLIENT_IP port 39116 ssh2 When I tried to debug using: ssh -v senthil@SERVER_IP OpenSSH_5.9p1 Debian-5ubuntu1, OpenSSL 1.0.1 14 Mar 2012 debug1: Reading configuration data /etc/ssh/ssh_config debug1: /etc/ssh/ssh_config line 19: Applying options for * debug1: Connecting to SERVER_IP [SERVER_IP] port 22. debug1: Connection established. debug1: identity file {MY-WORKSPACE}/.ssh/id_rsa type 1 debug1: Checking blacklist file /usr/share/ssh/blacklist.RSA-2048 debug1: Checking blacklist file /etc/ssh/blacklist.RSA-2048 debug1: identity file {MY-WORKSPACE}/.ssh/id_rsa-cert type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_dsa type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_dsa-cert type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_ecdsa type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_ecdsa-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.8p1 Debian-7ubuntu1 debug1: match: OpenSSH_5.8p1 Debian-7ubuntu1 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.9p1 Debian-5ubuntu1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: sending SSH2_MSG_KEX_ECDH_INIT debug1: expecting SSH2_MSG_KEX_ECDH_REPLY debug1: Server host key: ECDSA {SERVER_HOST_KEY} debug1: Host 'SERVER_IP' is known and matches the ECDSA host key. debug1: Found key in {MY-WORKSPACE}/.ssh/known_hosts:1 debug1: ssh_ecdsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: password debug1: Next authentication method: password senthil@SERVER_IP's password: debug1: Authentications that can continue: password Permission denied, please try again. senthil@SERVER_IP's password: For password, I have entered the same value which I normally use for 'ubuntu' user. Can anyone please guide me where the issue is and suggest some solution for this issue?

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  • ifconfig : Command 'ifconfig' is available in '/sbin/ifconfig'

    - by Sahil Grover
    My question is related to another open question. My echo $PATH gives me an output which is like /home/sahil/.rvm/gems/ruby-1.9.3-p125/bin:/home/sahil/.rvm/gems/ruby-1.9.3-p125@global/bin:/home/sahil/.rvm/rubies/ruby-1.9.3-p125/bin:/home/sahil/.rvm/bin:/usr/local/bin:/usr/bin:/bin:/usr/games:/home/sahil/.rvm/bin{}:/home/android-sdks/{}:/home/android-sdks/platform-tools/{}:/home/android-sdks/tools/{}:/home/sahil/android-sdks/tools{}:/home/sahil/android-sdks/tools:/home/sahil/android-sdks/platform-tools/ But running ifconfig gives me an output like Command 'ifconfig' is available in '/sbin/ifconfig' The command could not be located because '/sbin' is not included in the PATH environment variable. This is most likely caused by the lack of administrative privileges associated with your user account. ifconfig: command not found after running command like given in other question export PATH="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games" it runs ifconfig but blocks other commands of ruby rails or rvm. Seeking help how to resolve this. Also why this happens?

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  • Creating a secure SQL server login - CHECK_EXPIRATION & CHECK_POLICY

    - by cabhilash
    In SQL Server you can create users using T-SQL or using the options provided by SQL Server Management Studio.   CREATE LOGIN sql_user WITH PASSWORD ='sql_user_password' MUST_CHANGE, DEFAULT_DATABASE = defDB, CHECK_EXPIRATION = ON, CHECK_POLICY = ONAs mentioned in the previous article (http://weblogs.asp.net/cabhilash/archive/2010/04/07/login-failed-for-user-sa-because-the-account-is-currently-locked-out-the-system-administrator-can-unlock-it.aspx) when CHECK_POLICY = ON user account follows the password rules provided in the system on which the SQL server is installed. When MUST_CHANGE keyword is used user is forced to change the password when he/she tries to login for the first time. CHECK_EXPIRATION and CHECK_POLICY are only enforced on Windows Server 2003 and later. If you want to turn off the password expiration enforcement or security policy enforcement, you can do by using the following statements. (But these wont work if you have created your login with MUST_CHANGE and user didn't change the default password) ALTER LOGIN sql_login WITH CHECK_EXPIRATION = OFF go ALTER LOGIN sql_login WITH CHECK_POLICY = OFF

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  • Authentication failure!

    - by veera
    At the time of installation i gave login password and that was the login keyring password and authentication password.. then once in user accounts-login options in dat for password options i set as none and then i locked.. after that the passwd which i gave at the time of installation remained as login keyring passwd but wen i entered that passwd for authentication while installing some packages it's showing authentication failure.pls try again.. so i couldnt download any packages or updates.. is there any possibilities to change/reset the authentication password.. pls help me..

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  • Would you consider using training/mentoring from LearnersParadise.com?

    - by HK1
    My initial question deserves some explanation. I signed up for an account at learnersparadise.com. After signing up I couldn't login so I opted to use their "send password" feature. Upon receiving my password in my email I confirmed two things A) They trimmed off 2 of the last digits of my 10-digit password without informing me and saved it that way in their database B) my password is not saved in their database using a one-way hash since they were able to email me my password. I'm quite certain that both of these are perfectly awful programming practices. I suspect that the mentors/trainers at learnersparadise are not necessarily affiliated with the website and it's design since they are basically people like you and me (hopefully more skill than me) who have signed up to become mentors. However, I'm still uncertain about signing up for training/mentoring at a site that uses such poor programming practices themselves? Would you let learnersparadise poor programming practices affect your opinion of their trainers/mentors?

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  • tomcat6 manager

    - by Bary W Pollack
    I've just installed Ubuntu 10.04 LTS Server with LAMP support. Tomcat6 seems to run ok. But, I am unable to get into the manager-webapp... I've updated the tomcat-users.xml file: <?xml version='1.0' encoding='utf-8'?> <tomcat-users> <role rolename="tomcat"/> <role rolename="role1"/> <role rolename="manager"/> <role rolename="admin"/> <user username="tomcat" password="tomcat" roles="tomcat,manager,admin"/> <user username="both" password="tomcat" roles="tomcat,role1"/> <user username="role1" password="tomcat" roles="role1"/> <user username="admin" password="admin" roles="manager,admin"/> </tomcat-users> But, no matter what I try, it keeps rejecting my username/password combo. What might I be missing?

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  • PeopleTools 8.54 Pre-Release Notes Available

    - by Matthew Haavisto
    PeopleSoft's PeopleTools recently published pre-release notes for PeopleTools 8.54.  Pre-release notes provide more functional and technical details than the release value proposition. This document describes how enhancements function within the context of the greater business process. This added level of detail should enable project teams to answer the following questions: What delivered functionality will change? How will an upgrade or new implementation affect other systems? How will these changes affect the organization? After the project team has reviewed and analyzed the pre-release notes, business decision makers should be able to determine whether to allocate budget and initiate implementation plans. This document covers the following subjects: Platform support enhancements Development tools enhancements System administration tools enhancements Reporting and analytic tools enhancements Integration tools enhancements Lifecycle management tools enhancements Accessibility PeopleSoft Interaction Hub enhancements.

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  • How to execute? [closed]

    - by Viswa
    Possible Duplicate: how to read the password from variable? I did the below code in my python script,but its not work. #! /usr/bin/python import os address = "rsync -avrz [email protected]:/opt/script/python/data/ /opt/script/python/data/" passwd ="my server password" os.system('%(address)s "echo %(passwd)s"' %locals()) it throws below error. If arg is a remote file/dir, prefix it with a colon (:). rsync error: syntax or usage error (code 1) at main.c(1236) [Receiver=3.0.7] If i run os.system('%(address)s' %locals()) means it work without any error but it ask password. I need that password should be read from my passwd variable. How to write python script to read server password from my variable.

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  • The imported project "C:\Program Files (x86)\MSBuild\Microsoft\VisualStudio\v10.0\SSDT\Microsoft.Data.Tools.Schema.SqlTasks.targets" was not found. Confirm that the path in the <Import> declaration is correct, and that the file exists on di

    - by simonsabin
    Are you trying to build a SQL Server database project and getting   The imported project "C:\Program Files (x86)\MSBuild\Microsoft\VisualStudio\v10.0\SSDT\Microsoft.Data.Tools.Schema.SqlTasks.targets" was not found. Confirm that the path in the <Import> declaration is correct, and that the file exists on disk. We had this recently when trying to build one SSDT solution but not when building another.   Checking the build agent the error was correct that file didn’t exist...(read more)

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  • Chrome Mobile: The Mobile Web Developers Toolkit (Part 1)

    Chrome Mobile: The Mobile Web Developers Toolkit (Part 1) Building for mobile web requires a different mindset than desktop web development, and a different set of tools. The tools we're used to using often aren't available or would take up too much screen real estate. And going back to the dark ages of tweak/save/deploy/test/repeat isn't exactly optimal, so what can we do? Thankfully there are a number of great options - from remote debugging to emulation, mobile browsers are offering more and more tools to make our lives easier. We'll take a look at a couple of tools that you can use today to make cross platform mobile web development easier and then peer into the crystal ball to see what tools may bring in the future. Join us for Part 1 - as we take a look at a few boiler plates, frameworks and helpful libraries for building the mobile web. From: GoogleDevelopers Views: 0 0 ratings Time: 01:00:00 More in Science & Technology

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  • Problem while running the j2me application

    - by Paru
    I am not able to view any content in the emulator while running the application. The Build is not failed and i am able run the application successfully. While i am closing the emulator i am getting an error. i can provide both code and log here. import javax.microedition.lcdui.; import javax.microedition.midlet.; import java.io.; import java.lang.; import javax.microedition.io.; import javax.microedition.rms.; public class Login extends MIDlet implements CommandListener { TextField ItemName=null; TextField ItemNo=null; TextField UserName=null; TextField Password=null; Form authForm,mainscreen; TextBox t = null; StringBuffer b = new StringBuffer(); private Display myDisplay = null; private Command okCommand = new Command("Login", Command.OK, 1); private Command exitCommand = new Command("Exit", Command.EXIT, 2); private Command sendCommand = new Command("Send", Command.OK, 1); private Command backCommand = new Command("Back", Command.BACK, 2); private Alert alert = null; public Login() { ItemName=new TextField("Item Name","",10,TextField.ANY); ItemNo=new TextField("Item No","",10,TextField.ANY); myDisplay = Display.getDisplay(this); UserName=new TextField("Your Name","",10,TextField.ANY); Password=new TextField("Password","",10,TextField.PASSWORD); authForm=new Form("Identification"); mainscreen=new Form("Logging IN"); mainscreen.addCommand(sendCommand); mainscreen.addCommand(backCommand); authForm.append(UserName); authForm.append(Password); authForm.addCommand(okCommand); authForm.addCommand(exitCommand); authForm.setCommandListener(this); myDisplay.setCurrent(authForm); } public void startApp() throws MIDletStateChangeException { } public void pauseApp() { } protected void destroyApp(boolean unconditional) throws MIDletStateChangeException { } public void commandAction(Command c, Displayable d) { if ((c == okCommand) && (d == authForm)) { if (UserName.getString().equals("") || Password.getString().equals("")){ alert = new Alert("Error", "You should enter Username and Password", null, AlertType.ERROR); alert.setTimeout(Alert.FOREVER); myDisplay.setCurrent(alert); } else{ //myDisplay.setCurrent(mainscreen); login(UserName.getString(),Password.getString()); } } if ((c == backCommand) && (d == mainscreen)) { myDisplay.setCurrent(authForm); } if ((c == exitCommand) && (d == authForm)) { notifyDestroyed(); } if ((c == sendCommand) && (d == mainscreen)) { if(ItemName.getString().equals("") || ItemNo.getString().equals("")){ } else{ sendItem(ItemName.getString(),ItemNo.getString()); } } } public void login(String UserName,String PassWord) { HttpConnection connection=null; DataInputStream in=null; String url="http://olario.net/submitpost/submitpost/login.php"; OutputStream out=null; try { connection=(HttpConnection)Connector.open(url); connection.setRequestMethod(HttpConnection.POST); connection.setRequestProperty("IF-Modified-Since", "2 Oct 2002 15:10:15 GMT"); connection.setRequestProperty("User-Agent","Profile/MIDP-1.0 Configuration/CLDC-1.0"); connection.setRequestProperty("Content-Language", "en-CA"); connection.setRequestProperty("Content-Length",""+ (UserName.length()+PassWord.length())); connection.setRequestProperty("username",UserName); connection.setRequestProperty("password",PassWord); out = connection.openDataOutputStream(); out.flush(); in = connection.openDataInputStream(); int ch; while((ch = in.read()) != -1) { b.append((char) ch); //System.out.println((char)ch); } //t = new TextBox("Reply",b.toString(),1024,0); //mainscreen.append(b.toString()); String auth=b.toString(); if(in!=null) in.close(); if(out!=null) out.close(); if(connection!=null) connection.close(); if(auth.equals("ok")){ mainscreen.setCommandListener(this); myDisplay.setCurrent(mainscreen); } } catch(IOException x){ } } public void sendItem(String itemname,String itemno){ HttpConnection connection=null; DataInputStream in=null; String url="http://www.olario.net/submitpost/submitpost/submitPost.php"; OutputStream out=null; try { connection=(HttpConnection)Connector.open(url); connection.setRequestMethod(HttpConnection.POST); connection.setRequestProperty("IF-Modified-Since", "2 Oct 2002 15:10:15 GMT"); connection.setRequestProperty("User-Agent","Profile/MIDP-1.0 Configuration/CLDC-1.0"); connection.setRequestProperty("Content-Language", "en-CA"); connection.setRequestProperty("Content-Length",""+ (itemname.length()+itemno.length())); connection.setRequestProperty("itemCode",itemname); connection.setRequestProperty("qty",itemno); out = connection.openDataOutputStream(); out.flush(); in = connection.openDataInputStream(); int ch; while((ch = in.read()) != -1) { b.append((char) ch); //System.out.println((char)ch); } //t = new TextBox("Reply",b.toString(),1024,0); //mainscreen.append(b.toString()); String send=b.toString(); if(in!=null) in.close(); if(out!=null) out.close(); if(connection!=null) connection.close(); if(send.equals("added")){ alert = new Alert("Error", "Send Successfully", null, AlertType.INFO); alert.setTimeout(Alert.FOREVER); myDisplay.setCurrent(alert); } } catch(IOException x){ } } } and the log is pre-init: pre-load-properties: exists.config.active: exists.netbeans.user: exists.user.properties.file: load-properties: exists.platform.active: exists.platform.configuration: exists.platform.profile: basic-init: cldc-pre-init: cldc-init: cdc-init: ricoh-pre-init: ricoh-init: semc-pre-init: semc-init: savaje-pre-init: savaje-init: sjmc-pre-init: sjmc-init: ojec-pre-init: ojec-init: cdc-hi-pre-init: cdc-hi-init: nokiaS80-pre-init: nokiaS80-init: nsicom-pre-init: nsicom-init: post-init: init: conditional-clean-init: conditional-clean: deps-jar: pre-preprocess: do-preprocess: Pre-processing 0 file(s) into /home/sreekumar/NetBeansProjects/Login/build/preprocessed directory. post-preprocess: preprocess: pre-compile: extract-libs: do-compile: post-compile: compile: pre-obfuscate: proguard-init: skip-obfuscation: proguard: post-obfuscate: obfuscate: lwuit-build: pre-preverify: do-preverify: post-preverify: preverify: pre-jar: set-password-init: set-keystore-password: set-alias-password: set-password: create-jad: add-configuration: add-profile: do-extra-libs: nokiaS80-prepare-j9: nokiaS80-prepare-manifest: nokiaS80-prepare-manifest-no-icon: nokiaS80-create-manifest: jad-jsr211-properties.check: jad-jsr211-properties: semc-build-j9: do-jar: nsicom-create-manifest: do-jar-no-manifest: update-jad: Updating application descriptor: /home/sreekumar/NetBeansProjects/Login/dist/Login.jad Generated "/home/sreekumar/NetBeansProjects/Login/dist/Login.jar" is 3501 bytes. sign-jar: ricoh-init-dalp: ricoh-add-app-icon: ricoh-build-dalp-with-icon: ricoh-build-dalp-without-icon: ricoh-build-dalp: savaje-prepare-icon: savaje-build-jnlp: post-jar: jar: pre-run: netmon.check: open-netmon: cldc-run: Copying 1 file to /home/sreekumar/NetBeansProjects/Login/dist/nbrun4244989945642509378 Copying 1 file to /home/sreekumar/NetBeansProjects/Login/dist/nbrun4244989945642509378 Jad URL for OTA execution: http://localhost:8082/servlet/org.netbeans.modules.mobility.project.jam.JAMServlet//home/sreekumar/NetBeansProjects/Login/dist//Login.jad Starting emulator in execution mode Running with storage root /home/sreekumar/j2mewtk/2.5.2/appdb/temp.DefaultColorPhone1 /home/sreekumar/NetBeansProjects/Login/nbproject/build-impl.xml:915: Execution failed with error code 143. BUILD FAILED (total time: 35 seconds)

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  • Using AES encryption in .NET - CryptographicException saying the padding is invalid and cannot be removed

    - by Jake Petroules
    I wrote some AES encryption code in C# and I am having trouble getting it to encrypt and decrypt properly. If I enter "test" as the passphrase and "This data must be kept secret from everyone!" I receive the following exception: System.Security.Cryptography.CryptographicException: Padding is invalid and cannot be removed. at System.Security.Cryptography.RijndaelManagedTransform.DecryptData(Byte[] inputBuffer, Int32 inputOffset, Int32 inputCount, Byte[]& outputBuffer, Int32 outputOffset, PaddingMode paddingMode, Boolean fLast) at System.Security.Cryptography.RijndaelManagedTransform.TransformFinalBlock(Byte[] inputBuffer, Int32 inputOffset, Int32 inputCount) at System.Security.Cryptography.CryptoStream.FlushFinalBlock() at System.Security.Cryptography.CryptoStream.Dispose(Boolean disposing) at System.IO.Stream.Close() at System.IO.Stream.Dispose() ... And if I enter something less than 16 characters I get no output. I believe I need some special handling in the encryption since AES is a block cipher, but I'm not sure exactly what that is, and I wasn't able to find any examples on the web showing how. Here is my code: using System; using System.IO; using System.Security.Cryptography; using System.Text; public static class DatabaseCrypto { public static EncryptedData Encrypt(string password, string data) { return DatabaseCrypto.Transform(true, password, data, null, null) as EncryptedData; } public static string Decrypt(string password, EncryptedData data) { return DatabaseCrypto.Transform(false, password, data.DataString, data.SaltString, data.MACString) as string; } private static object Transform(bool encrypt, string password, string data, string saltString, string macString) { using (AesManaged aes = new AesManaged()) { aes.Mode = CipherMode.CBC; aes.Padding = PaddingMode.PKCS7; int key_len = aes.KeySize / 8; int iv_len = aes.BlockSize / 8; const int salt_size = 8; const int iterations = 8192; byte[] salt = encrypt ? new Rfc2898DeriveBytes(string.Empty, salt_size).Salt : Convert.FromBase64String(saltString); byte[] bc_key = new Rfc2898DeriveBytes("BLK" + password, salt, iterations).GetBytes(key_len); byte[] iv = new Rfc2898DeriveBytes("IV" + password, salt, iterations).GetBytes(iv_len); byte[] mac_key = new Rfc2898DeriveBytes("MAC" + password, salt, iterations).GetBytes(16); aes.Key = bc_key; aes.IV = iv; byte[] rawData = encrypt ? Encoding.UTF8.GetBytes(data) : Convert.FromBase64String(data); using (ICryptoTransform transform = encrypt ? aes.CreateEncryptor() : aes.CreateDecryptor()) using (MemoryStream memoryStream = encrypt ? new MemoryStream() : new MemoryStream(rawData)) using (CryptoStream cryptoStream = new CryptoStream(memoryStream, transform, encrypt ? CryptoStreamMode.Write : CryptoStreamMode.Read)) { if (encrypt) { cryptoStream.Write(rawData, 0, rawData.Length); return new EncryptedData(salt, mac_key, memoryStream.ToArray()); } else { byte[] originalData = new byte[rawData.Length]; int count = cryptoStream.Read(originalData, 0, originalData.Length); return Encoding.UTF8.GetString(originalData, 0, count); } } } } } public class EncryptedData { public EncryptedData() { } public EncryptedData(byte[] salt, byte[] mac, byte[] data) { this.Salt = salt; this.MAC = mac; this.Data = data; } public EncryptedData(string salt, string mac, string data) { this.SaltString = salt; this.MACString = mac; this.DataString = data; } public byte[] Salt { get; set; } public string SaltString { get { return Convert.ToBase64String(this.Salt); } set { this.Salt = Convert.FromBase64String(value); } } public byte[] MAC { get; set; } public string MACString { get { return Convert.ToBase64String(this.MAC); } set { this.MAC = Convert.FromBase64String(value); } } public byte[] Data { get; set; } public string DataString { get { return Convert.ToBase64String(this.Data); } set { this.Data = Convert.FromBase64String(value); } } } static void ReadTest() { Console.WriteLine("Enter password: "); string password = Console.ReadLine(); using (StreamReader reader = new StreamReader("aes.cs.txt")) { EncryptedData enc = new EncryptedData(); enc.SaltString = reader.ReadLine(); enc.MACString = reader.ReadLine(); enc.DataString = reader.ReadLine(); Console.WriteLine("The decrypted data was: " + DatabaseCrypto.Decrypt(password, enc)); } } static void WriteTest() { Console.WriteLine("Enter data: "); string data = Console.ReadLine(); Console.WriteLine("Enter password: "); string password = Console.ReadLine(); EncryptedData enc = DatabaseCrypto.Encrypt(password, data); using (StreamWriter stream = new StreamWriter("aes.cs.txt")) { stream.WriteLine(enc.SaltString); stream.WriteLine(enc.MACString); stream.WriteLine(enc.DataString); Console.WriteLine("The encrypted data was: " + enc.DataString); } }

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  • Integer Linear Programming Java: Multiple Open Source and Commercial tools are available. Which one

    - by Sandeep Jindal
    Hi, I need to use Integer Linear Programming API/Tool for my application. Though my application is in Java but I don’t mind calling an EXE (Tool) from Java providing input using file (MPS, etc). My search analysis is as follows: There are multiple Open Source and Commercial tools available to solve ILP Following I found and think are useful for my needs. 1. Gnu LP Kit(GLPK): I think this is the oldest and probably most stable and efficient 2. IP_Solve: Has good reviews about it. 3. JavaILP: Found this, but not much reviews about it 4. Apache Common-Math: Supports LP but not ILP, so ruled out. 5. Coin-OR Can you please suggest which one shall be the best in terms of stability, efficiency, acceptance, etc Regards Sandeep Jindal

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  • How to use the md5 hash?

    - by Ken
    Okay, so I'm learning php, html, and mysql to learn website development (for fun). One thing I still don't get is how to use md5 of sha1 hashes. I know how to hash the plain text, but say I want to make a login page. Since the password is hashed and can't be reversed, how would mysql know that the user-inserted password matches the hashed password in the database? Here is what I mean: $password = md5($_POST['password']); $query = ("INSERT INTO `users`.`data` (`password`) VALUES ('$password')"); I know that this snippet of script hashes the password, but how would I use this piece of code and make a login page? Any working examples would be great.

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  • i am facing some problem while passing parameter to crystal report? it is asking for the password of

    - by Gaurav Sharma
    protected void Page_Load(object sender, EventArgs e) { ConnectionInfo myConnectionInfo = new ConnectionInfo(); myConnectionInfo.UserID = "sa"; myConnectionInfo.Password = "********"; setDBLOGONforREPORT(myConnectionInfo); //When i don't write this code it does not ask for the passowrd //but doesn't take Parameter as value int recpt_no = Convert.ToInt32(Request.QueryString["recpt_no"]); ReportDocument report1 = new ReportDocument(); //report1.SetDatabaseLogon("sa", "********"); report1.Load(Server.MapPath("purchase.rpt")); report1.FileName = Server.MapPath("purchase.rpt"); report1.SetParameterValue("recpt_no", recpt_no); CrystalReportViewer1.ReportSource = report1; } private void setDBLOGONforREPORT(ConnectionInfo myconnectioninfo) { TableLogOnInfos mytableloginfos = new TableLogOnInfos(); mytableloginfos = CrystalReportViewer1.LogOnInfo; foreach (TableLogOnInfo myTableLogOnInfo in mytableloginfos) { myTableLogOnInfo.ConnectionInfo = myconnectioninfo; } } kindly Help me as soon as possible respt_no is passed as querysting Gaurav Sharma

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  • python-pam & pam_time module -- possible to check a user without password?

    - by medigeek
    I've looked at the example script of python-pam and linux pam pages, but it's a bit confusing, at least for a beginner in PAM (that I am): http://www.kernel.org/pub/linux/libs/pam/Linux-PAM-html/Linux-PAM_ADG.html http://packages.ubuntu.com/python-pam Is it possible to check if a user has or does not have access to login, without entering password? I would like to create a script that root can use to check if a user is allowed or not to login to the system. If so, can someone post an example that checks if the user is allowed against pam_time? Thanks in advance!

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  • How do I fix JavaHL (JNI) Not available after I have changed the logon password on my Mac?

    - by INeedHelp
    I have installed Eclipse 3.5.2 and the plugin Subversion JavaHL Native Library Adapter 1.6.9.2 and this worked without any problems. However, this morning I was forced to change the password to logon to my Mac and since then I get the message that "Subversion native library not available" when I try to save any changes. Can anyone help? I have tried to add this line (-Djava.library.path=/usr/lib/jni) to the eclipse.ini file but this didn´t seem to make any difference. Can anyone help?

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  • mercurial: less duplication in hgrc file

    - by zaharpopov
    Hi there. I have using Hg for some projects on my google code hosting. For each projects I set in [auth] section of .hgrc the username/password to push without every asking for password. But it is lots of duplication like: [auth] proj1.prefix = ... 111 proj1.username = google code username proj1.password = google code password proj2.prefix = ... 222 proj2.username = google code username proj2.password = google code password Can this somehow be doing with less duplications? Maybe set variable in hgrc and refer to it from all username/password lines? Thanks in advance for your help

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  • Do Eclipse's Refactoring Tools Violate The Java Language Specification?

    - by Tom Tresansky
    In Eclipse 3.5, say I have a package structure like this: tom.package1 tom.package1.packageA tom.package1.packageB if I right click on an the tom.package1 package and go to Refactor-Rename, an option "Rename subpackages" appears as a checkbox. If I select it, and then rename tom.package1 to tom.red my package structure ends up like this: tom.red tom.red.packageA tom.red.packageB Yet I hear that Java's packages are not hierarchical. The Java Tutorials back that up (see the section on Apparent Hierarchies of Packages). It certainly seems like Eclipse is treating packages as hierarchical in this case. I was curious why access specifiers couldn't allow/restrict access to "sub-packages" in a previous question because I KNEW I had seen "sub-packages" referenced somewhere before. So are Eclipse's refactoring tools intentionally misleading impressionable young minds by furthering the "sub-package" myth? Or am I misinterpreting something here?

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  • Why Shouldn't I Programmatically Submit Username/Password to Facebook/Twitter/Amazon/etc?

    - by viatropos
    I wish there was a central, fully customizable, open source, universal login system that allowed you to login and manage all of your online accounts (maybe there is?)... I just found RPXNow today after starting to build a Sinatra app to login to Google, Facebook, Twitter, Amazon, OpenID, and EventBrite, and it looks like it might save some time. But I keep wondering, not being an authentication guru, why couldn't I just have a sleek login page saying "Enter username and password, and check your login service", and then in the background either scrape the login page from say EventBrite and programmatically submit the form with Mechanize, or use an API if there was one? It would be so much cleaner and such a better user experience if they didn't have to go through popups and redirects and they could use any previously existing accounts. My question is: What are the reasons why I shouldn't do something like that? I don't know much about the serious details of cookies/sessions/security, so if you could be descriptive or point me to some helpful links that would be awesome. Thanks!

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  • Tools and ways to generate HTML help for built-in help system (QtHelp)?

    - by BastiBense
    Hello, I'm in the progress of implementing a built-in help system based on QtHelp into my application. Since QtHelp is based on Qt's help collection files, I need to produce a set of HTML pages. Since I won't be writing the documentation alone (a few of my colleagues will write, too), I am looking for the best way to produce these files. We are internally using a Wiki, and I know that the documentation should be written in some kind of markup language instead of giving all authors a WYSIWYG HTML editor. So my question is, are there tools out there which help with the process of generating documentation that can be exported as a set of HTML files, and possibly, as PDFs, too?. Thanks in advance! Update: I'm already using Doxygen for C++ documentation generation. But I'm not exactly looking for an API-Documentation generator, but something like LaTeX, which allows you to format the documentation contents like a markup document (much like a Wiki).

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