Search Results

Search found 24719 results on 989 pages for 'ajax form'.

Page 162/989 | < Previous Page | 158 159 160 161 162 163 164 165 166 167 168 169  | Next Page >

  • .net Components ... a Custom Form

    - by carlos
    Hi, I've been working in the creation of some custom components adding functionalites to the basic components such as a Datagridview. Now I want to create a custom Form ... I mean, when I choose add new item in the VS menu, there is a Windows form and some varians of it like an about box, or Dialog, that are simple Forms with a custom controls already on it. I want to have a login form for my set of applications, so this login is avialable for all the development team to use it in the different modules. How can I develop the form and then add it to the "Add New Item" screen? Thanks !!!

    Read the article

  • Post ASP.Net Form data to another page

    - by william
    I have an ASP.Net Page, aspx with its default form. I have a Submit Button for it. Upon clicking, it will post the data to itself. In other words, Button Click Event() from code behind will execute the necessary. After that, I would like to post the same data to another ASp.Net Page, aspx from another domain. So, how can I do it? I tried creating a Form in Button Click Event and a javascript to Submit the Form so that it will post. But the Form is not appearing hence there is already aForm` on the page. Is there anyway to do it?

    Read the article

  • change prototype script to jquery one

    - by steve
    I have this form submit code: Event.observe(window, 'load', init, false); function init() { Event.observe('addressForm', 'submit', storeAddress); } function storeAddress(e) { $('response').innerHTML = 'Adding email address...'; var pars = 'address=' + escape($F('address')); var myAjax = new Ajax.Updater('response', 'ajaxServer.php', {method: 'get', parameters: pars}); Event.stop(e); } How can I change it to work with jQuery? Here is the html form: <form id="addressForm" action="index.php" method="get"> <b>Email:</b> <input type="text" name="address" id="address" size="25"><br> <input name="Submit" value="Submit" type="submit" /> <p id="response"><?php echo(storeAddress()); ?></p> </form> and this is php code at start of document: <?php require_once("inc/storeAddress.php"); ?>

    Read the article

  • problem in return value from server to client in ajax useing zend-framework

    - by user1400
    hello i try to use ajax and zend in my application , i could pass variable to server but i can not get data from server , it does not return values, it return all html code page, where is my mistake? $('#myForm').submit(function($e){ $e.preventDefault(); var $paramToServer=$("#myForm").serialize(); $.ajax({ type:'POST', url:'test', data:$paramToServer , success:function(re){ var res = $.evalJSON(re); console.log(res.id); // to see in firebog }, dataType:'json' }); }); public function testAction() { // action body $this->_helper->getHelper('viewRenderer')->setNoRender(); // If you use layout, disable it Zend_Layout::getMvcInstance()->disableLayout(); $name=$this->getRequest()->getParam ( 'name' ); //pass $name to server $return = array( 'id' => '5', 'family' => 'hello ', ); $return = Zend_Json::encode( $return); // Response $this->getResponse()->setBody($return); }

    Read the article

  • Is Form validation and Business validation too much?

    - by Robert Cabri
    I've got this question about form validation and business validation. I see a lot of frameworks that use some sort of form validation library. You submit some values and the library validates the values from the form. If not ok it will show some errors on you screen. If all goes to plan the values will be set into domain objects. Here the values will be or, better said, should validated (again). Most likely the same validation in the validation library. I know 2 PHP frameworks having this kind of construction Zend/Kohana. When I look at programming and some principles like Don't Repeat Yourself (DRY) and single responsibility principle (SRP) this isn't a good way. As you can see it validates twice. Why not create domain objects that do the actual validation. Example: Form with username and email form is submitted. Values of the username field and the email field will be populated in 2 different Domain objects: Username and Email class Username {} class Email {} These objects validate their data and if not valid throw an exception. Do you agree? What do you think about this aproach? Is there a better way to implement validations? I'm confused about a lot of frameworks/developers handling this stuff. Are they all wrong or am I missing a point? Edit: I know there should also be client side kind of validation. This is a different ballgame in my Opinion. If You have some comments on this and a way to deal with this kind of stuff, please provide.

    Read the article

  • rails update whole index of a model with one click

    - by mattherick
    hello! i have a store model, this will handle my leaflet and my shoppingcart for my shop. now i d´like to show all items added from an user to his leaflet in the index of store. in the store an user can change the quantity of the choosen items. and now i want to save that the changes of the different quantities in the database with one click on a button "update store". so how could i implement an update over the whole index with one click? i´d like to do this with ajax and most dynamically. somebody has an idea? i render all items into a form so far, but now i have the problem, when i submit this form only the last quantity and item id are included in the params. further i pushed every quantity into an array and i want to submit this also as a param. but i could not. please give me some tips, will be very fine :) mattherick

    Read the article

  • loading an asp after starting a session

    - by Noam Smadja
    the jQuery $("#loginform").submit(function(){ $.ajax({ type: "POST", url: "loginrespajax.asp", data: $("#loginform").serialize(), success: function(){ $("#loginform").hide("slow"); $("#loginform").load("userheader.asp"); $("#loginform").show("slow"); } }); }); thats userheader.asp <div class="userlinks"> <%if (session("userlevel")) then%> <% select case session("userlevel") case 1 %> <a href="managenews.asp"><%langstring("header_news")%></a> | <a href="managebooks.asp"><%langstring("header_books")%></a> | <a href="manageusers.asp"><%langstring("manage_users")%></a> | <a href="manageorders.asp"><%langstring("manage_orders")%></a> | <a href="managelanguage.asp"><%langstring("manage_language")%></a> | <a href="youthregistration.asp"><%langstring("youthreg_header")%></a> | <a href="manageregistrants.asp"><%langstring("youthlist_header")%></a> | <% case 2 %> <a href="managenews.asp"><%langstring("header_news")%></a> | <a href="managebooks.asp"><%langstring("header_books")%></a> | <a href="youthregistration.asp"><%langstring("youthreg_header")%></a> | <a href="manageregistrants.asp"><%langstring("youthlist_header")%></a> | <% case 3 %> <a href="youthregistration.asp"><%langstring("youthreg_header")%></a> | <a href="manageregistrants.asp"><%langstring("youthlist_header")%></a> | <% End select %> <a href="editprofile.asp"><%langstring("editprofile_header")%></a> | <a href="changepassword.asp"><%langstring("changepassword_header")%></a> | <a href="logout.asp"><%langstring("logout_header")%></a> <%else%> <form action="loginrespajax.asp" method="POST" name="loginform" id="loginform" class="loginform" onSubmit="return false;"> <input type="text" name="username" value="username" class="input inline" onFocus="clearText(this);"> <input type="password" name="password" value="password" class="input inline" onFocus="clearText(this);"> <input type="submit" value="Log In" class="submit inline"> </form> <%End if%> </div> i am submiting the login form using AJAX and the jQuery partially works. it does hide and show again. but it prints the ELSE part of in userheader.asp. the session does start, for sure :)

    Read the article

  • Disable form resizing in delphi

    - by Hendriksen123
    Is there any way to stop the user resizing the form? Currently I am using: When form size changed.... MainForm.Height := 761; MainForm.Width := 777; But this looks horrible as it flickers as the user tries to change the form size.

    Read the article

  • JSF how to temporary disable validators to save draft

    - by Swiety
    I have a pretty complex form with lots of inputs and validators. For the user it takes pretty long time (even over an hour) to complete that, so they would like to be able to save the draft data, even if it violates rules like mandatory fields being not typed in. I believe this problem is common to many web applications, but can't find any well recognised pattern how this should be implemented. Can you please advise how to achieve that? For now I can see the following options: use of immediate=true on "Save draft" button doesn't work, as the UI data would not be stored on the bean, so I wouldn't be able to access it. Technically I could find the data in UI component tree, but traversing that doesn't seem to be a good idea. remove all the fields validation from the page and validate the data programmaticaly in the action listener defined for the form. Again, not a good idea, form is really complex, there are plenty of fields so validation implemented this way would be very messy. implement my own validators, that would be controlled by some request attribute, which would be set for standard form submission (with full validation expected) and would be unset for "save as draft" submission (when validation should be skipped). Again, not a good solution, I would need to provide my own wrappers for all validators I am using. But as you see no one is really reasonable. Is there really no simple solution to the problem?

    Read the article

  • ThreadPool.QueueUserWorkItem new Form CreateHandle Deadlock

    - by bogdanbrudiu
    I have a thread that needs to create a popup Window. I start the thread using ThreadPool.QueueUserWorkItem(new WaitCallback(CreatePopupinThread)) Thew thread creats a new form. The application freases in the new Form constructor at CreateHandle. The Worker Thread is locked... How can I fix this? this is how I create the form var form = new ConfirmationForm { Text = entry.Caption, Label = entry.Text, }; In the constructor the thread enters a deadlock public ConfirmationForm() { InitializeComponent(); }

    Read the article

  • zend session exception on zend_session::start with forms

    - by Grant Collins
    Hi I'm having issues with trying to use Zend_Form_SubForm and sessions. My controller is in essance acting a wizard showing different subforms depending on the stage of the wizard. Using the example I am planning on storing the forms in a session namespace. My controller looks like this. include 'mylib/Form/addTaskWizardForm.php'; class AddtaskController extends Zend_Controller_Action{ private $config = null; private $log = null; private $subFormSession = null; /** * This function is called and initialises the global variables to this object * which is the configuration details and the logger to write to the log file. */ public function init(){ $this->config = Zend_Registry::getInstance()->get('config'); $this->log = Zend_Registry::getInstance()->get('log'); //set layout $this->_helper->layout->setLayout('no-sidemenus'); //we need to get the subforms and $wizardForms = new addTaskWizardForm(); $this->subFormSession = new Zend_Session_Namespace('addTaskWizardForms'); if(!isset($this->subFormSession->subforms)){ $this->subFormSession->subforms = $wizardForms; } } /** * The Landing page controller for the site. */ public function indexAction(){ $form = $this->subFormSession->subforms->getSubForm('start'); $this->view->form = $form; } However this is causing the application session to crash out with Uncaught exception 'Zend_Session_Exception' with message 'Zend_Session::start() Any idea why this is having issues with the Zend Session?? thanks.

    Read the article

  • YUI dialog - what's the equivalent of postdata when using "form" (not ('async")

    - by jamesmoorecode
    I'm creating a dialog with YAHOO.widget.Dialog. The dialog is fired off by clicking on a link, and the function the link uses specifies parameters that finally get added to a postdata option like so: var myDialog = new YAHOO.widget.Dialog("myDialog", { fixedcenter: true, // postmethod: "form", postdata: propString }); This works just fine, but now I need to do the same thing but using "form" instead of "async" - and there's no postdata for form submissions. What's the right way to do this? (YUI 2.7.0)

    Read the article

  • Returning Json object from controller action to jQuery

    - by PsychoCoder
    I'm attempting to get this working properly (2 days now). I'm working on a log in where I'm calling the controller action from jQuery, passing it a JSON object (utilizing json2.js) and returning a Json object from the controller. I'm able to call the action fine, but instead of being able to put the response where I want it it just opens a new window with this printed on the screen: {"Message":"Invalid username/password combination"} And the URL looks like http://localhost:13719/Account/LogOn so instead of calling the action and not reloading the page it's taking the user to the controller, which isn't good. So now for some code, first the controller code [HttpPost] public ActionResult LogOn(LogOnModel model, string returnUrl = "") { if (ModelState.IsValid) { var login = ObjectFactory.GetInstance<IRepository<PhotographerLogin>>(); var user = login.FindOne(x => x.Login == model.Username && x.Pwd == model.Password); if (user == null) return Json(new FailedLoginViewModel { Message = "Invalid username/password combination" }); else { if (!string.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } return RedirectToAction("Index", "Home"); } And the jQuery code $("#signin_submit").click(function () { var login = getLogin(); $.ajax({ type: "POST", url: "../Account/LogOn", data: JSON.stringify(login), dataType: 'json', contentType: 'application/json; charset=utf-8', error: function (xhr) { $("#message").text(xhr.statusText); }, success: function (result) { } }); }); function getLogin() { var un = $("#username").val(); var pwd = $("#password").val(); var rememberMe = $("#rememberme").val(); return (un == "") ? null : { Username: un, Password: pwd, RememberMe: rememberMe }; } In case you need to see the actual login form here that is as well <fieldset id="signin_menu"> <div> <span id="message"></span> </div> <% Html.EnableClientValidation(); %> <% using (Html.BeginForm("LogOn", "Account", FormMethod.Post, new { @id = "signin" })) {%> <% ViewContext.FormContext.ValidationSummaryId = "valLogOnContainer"; %> <%= Html.LabelFor(m => m.Username) %> <%= Html.TextBoxFor(m => m.Username, new { @class = "inputbox", @tabindex = "4", @id = "username" })%><%= Html.ValidationMessageFor(m => m.Username, "*")%> <p> <%= Html.LabelFor(m=>m.Password) %> <%= Html.PasswordFor(m => m.Password, new { @class = "inputbox", @tabindex = "5", @id = "password" })%><%= Html.ValidationMessageFor(m => m.Password, "*")%> </p> <p class="remember"> <input id="signin_submit" value="Sign in" tabindex="6" type="submit"/> <%= Html.CheckBoxFor(m => m.RememberMe, new { @class = "inputbox", @tabindex = "7", @id = "rememberme" })%> <%= Html.LabelFor(m => m.RememberMe) %> <p class="forgot"> <a href="#" id="forgot_password_link" title="Click here to reset your password.">Forgot your password?</a> </p> <p class="forgot-username"> <a href="#" id="forgot_username_link" title="Fogot your login name? We can help with that">Forgot your username?</a> </p> </p> <%= Html.ValidationSummaryJQuery("Please fix the following errors.", new Dictionary<string, object> { { "id", "valLogOnContainer" } })%> <% } %> </fieldset> The login form is loaded on the main page with <% Html.RenderPartial("LogonControl");%> Not sure if that has any bearing on this or not but thought I'd mention it. EDIT: The login form is loaded similar to the Twitter login, click a link and the form loads with the help of jQuery & CSS

    Read the article

  • JSF and Ajax4JSF on WebSphere 6.1 --> Problem with Form Submission

    - by Shamik
    Has anyone setup JSF1.1 with Ajax4JSF on websphere 6.1 ? I followed the instructions as mentioned in the developer guide . The problem that I am facing is that once I use a4j:support on any of my h:inputText item, the form values are not getting set in the backing bean on the submission of the form. I do have <h:messages> tag present just above the form so that all the problems should be reported there but I do not see any error message once I submit the form. But I do see that the values are not getting set. I need to find the solution as early as possible otherwise I probably have to throw the ajax4jsf framework and write javascripts instead :(

    Read the article

  • Codeigniter - form not rendering on live server?

    - by pingu
    hi guys, I've written a small website with CI, which is all working fine on dev. However, when I copy the files over for live, everything works except for my form which is not being rendered. I am using <?php echo form_open('home'); ?> and <?php echo form_close(); ?> The form fields within the form, which I'm generating as follows are being rendered fine, but there is simply no form around them?! <?php $data = array( 'name'=> 'name', 'id'=> 'name', 'class'=>'textfield', 'value' => set_value('name') ); echo form_input($data); ?> Any ideas - I've used CI on a few apps, and this is the first time I've come across this issue. I've got all the helpers etc called correctly, as this is working perfectly in the development environment.

    Read the article

  • Access form elements

    - by shiv09
    Hello Friends......I'm creating a multiform application in c#. I'm storing the values from the user in a List in form 1 and I want to access the same stored values of the same list in form 2...I m not able to access the stored values...The error I'm getting indicates that there are no values in the list which I'm accessing from form 2...Please help me out...

    Read the article

  • PHP Form Validation

    - by JM4
    This question will undoubtedly be difficult to answer and ask in a way that makes sense but I'll try my best: I have a form which uses PHP to display certain sections of the form such as: <?php if ($_SESSION['EnrType'] == "Individual") { display only form information for individual enrollment } ?> and <?php if ($_SESSION['Num_Enrs'] > 6) { display only form information for 7 total members enrollment } ?> In each form piece, unique information is collected about each enrollee but the basic criteria for each enrollee is the same, i.e. All enrollee's must use have a value in the FirstName field. Each field is named according to the enrollee number, i.e. Num1FirstName; Num2FirstName. I have a PHP validation script which is absolutely fantastic and am not looking to change it but the issue I am running into is duplication of the script in order to validate ALL fields in one swoop. On submission, all POSTED items are run through my validation script and based on the rules set return an error if they do not equal true. Sample code: if (isset($_POST['submit'])) { // import the validation library require("validation.php"); $rules = array(); // stores the validation rules //All Enrollee Rules $rules[] = "required,Num1FirstName,Num2FirstName,The First Name field is required."; The script above does the following, $rules[] ="REQUIREMENT,fieldname,error message" where requirement gives criteria (in this case, simply that a value is passed), fieldname is the name of the field being validated, and error message returns the error used. My Goal is to use the same formula above and have $rules[] run through ALL firstnames and return the error posted ONLY if they exist (i.e. dont check for member #7's first name if it doesnt exist on the screen). If I simply put a comma between the 'fieldnames' this only checks for the first, then second, and so on so this wont work. Any ideas?

    Read the article

  • jquery Ajax $.ajaxError

    - by cf_PhillipSenn
    I have a bunch of ajax calls that contain success and error conditions like this one: $.ajax({ url: 'Remote/State.cfc' ,type: "POST" ,data: { 'method': 'UpdateStateName' ,'StateID': StateID ,'StateName': StateName } ,success: function(result){ if (isNaN(result)) { $('#msg').text(result).addClass('err'); } else { $('#' + result + ' input[name="StateName"]').addClass('changed'); }; } ,error: function(msg){ $('#msg').text('Connection error').addClass('err'); } }); All the error conditions are the same. In other words, they all put the phrase "Connection error" in the msg id. Q1: Could I remove all these and replace them with $().ajaxError(function(myEvent, request, settings, thrownError) { $('#msg').text('Connection error').addClass('err'); }); Q2: How would you use myEvent and request to display a more informative error message?

    Read the article

  • Multiple forms using Rails & jQuery & AJAX

    - by biggie8199
    I have multiple coupons on a page and I'm trying to get comments to work on each coupon. So for each coupon i have a comments form. Im using jQuery + Ajax to accomplish this. Here's what my code looks like. Coupon Page <p>Comments:</p> <% form_for(@comment) do |f| %> <%= f.label :body %><br /><%= f.text_field :body, :size => "24" %> <%= f.hidden_field :coupon_id, :value => coupon.id %> <%= f.submit "Save" %> <% end %> Application.js jQuery.ajaxSetup({ 'beforeSend': function(xhr) {xhr.setRequestHeader("Accept", "text/javascript")} }) jQuery.fn.submitWithAjax = function() { this.submit(function() { $.post(this.action, $(this).serialize(), null, "script"); return false; }) return this; }; $(document).ready(function() { $("#new_comment").submitWithAjax(); }) I tried changing the jQuery selector to a class $(".new_comment").submitWithAjax(); Thinking that would work, now all the submit buttons work, however it posts only the first form on the page. What can I change to make it so ajax submits the correct form and not the first one?

    Read the article

< Previous Page | 158 159 160 161 162 163 164 165 166 167 168 169  | Next Page >