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  • Deploying Qt / MySQL application

    - by canardman
    Hi everyone, I hadn't found a anwser on the web, so i ask to you. I am unable to run my compiled mysql driver on a deployment solution. On the pc A the app work fine when run with QtCreator, but via the .exe in the following working directory, the driver is not loaded : root/ -----/bin --------/app.exe --------/libgcc_s_dw2-1.dll --------/mingwm10.dll --------/QtCore4.dll --------/QtGui4.dll --------/QtSql4.dll -----/sqldrivers --------/libmysql.dll --------/qsqlmysql4.dll Whereas with libmysql.dll under bin/ driver is loaded. Now on the pc B, with no Qt or MySQL lib installation and with any of the 2 last working dir, the driver is not loaded. pc A : Qt 4.7 2010.05, Win 7 pc B : Win 7 Thanks for your help !

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  • PHP/MYSQL Trouble Selecting by Primary Key

    - by djs22
    Hi all, So I have a primary key column called key. I'm trying to select the row with key = 1 via this code: $query ="SELECT * FROM Bowlers WHERE key = '1'"; $result = mysql_query($query) or die(mysql_error()); For some reason, I'm getting this result: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key = '1'' at line 1 The mysql statement works for using other keys, ie WHERE name = 'djs22'. Any ideas?

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  • MySQL insert at end of table

    - by Theopile
    Hello, I am using MySQL and PHP. I am having a problem with inserting a new item at the end of my table. When I insert the new item appears after the last created item, but I want it to be entered at the bottom of the table. Suppose that I have a table id=int,Primary Key and album=string and the table is: Wrath Crack The Skye Enter Shikari What would the MySQL query be if php variable $album=myAlbum was to be inserted next, at the end of the table, and with the appropriate id? Thanks

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  • advance click counter mysql or flat file

    - by jay
    Hi, First of all Thank You for looking. whats the best method for make an advance click counter (eg. order by views [today] | [yesterday] [this week] [last week] [this month] [last month] [all time] ). Is it better to use a flat file or mysql?. This is the MYSQL Structure i came up with. id (type: int(11)) link_id (type: int(11)) date (type: date) counter (type: int(11)) please can you advice me on whats the most effective way of doing this.

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  • Splitting a MySQL DB in two may ease server from "Too many connetions"? I don't think so

    - by Petruza
    I was requested to split a MySQL in two, it's kind of a horizontal partition, in which some rows correspond to one site, and some other correspond to another site. But they want to split it in two DBs in the same MySQL server. I'm no DB expert but I guess keeping them in the same MySQL server with the same amount of memory and processor and the same platform won't improve things. What we're trying to avoid is the "Too many connections" problem.

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  • Preserving indentation when inserting HTML from MySQL

    - by Benjamin
    I am using MySQL and PHP to populate parts of a site, often with HTML stored in a TEXT field. I like to keep my HTML indented so that the source is neat and easy to read, for example: <body> <div> <p>Blahblah</p> </div> </body> However, when the HTML is pulled from MySQL, I end up with: <body> <div> <p>Blahblahblah</p> </div> </body> This is quite ugly when there is a large amount of HTML being inserted into a DIV that is significantly indented. How can I stop this from happening? FYI, I use wordwrap() to keep each line from being too long.

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  • master to slave replication in mysql

    - by vijay
    i need master to slave replication in mysql so i am creating this procedure to change the master dynamically by procedure delimiter // CREATE PROCEDURE change_master( in host_ip varchar(50)) begin stop slave; CHANGE MASTER TO MASTER_HOST = host_ip, MASTER_PORT=3306, MASTER_USER='replication', MASTER_PASSWORD='slave'; start slave; end; // but i am getting a error. ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'host_ip, MASTER_PORT=3306, MASTER_USER='replication', MASTER_PASSWORD='slave'; s' at line 4 if i left it blank then fine eg. CHANGE MASTER TO MASTER_HOST = '', MASTER_PORT=3306, MASTER_USER='replication', MASTER_PASSWORD='slave'; i tried many time but in this query i am not able to use any variable why? if u know help me. thanks .

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  • Using indexes on/through a MySQL view

    - by Peeja
    We've got a MySQL table in which rows are never updated, but instead new rows are added and the old ones marked obsolete. Think Rails' acts_as_paranoid, but for every update. To make working with Rails sane, we've got a view which selects only the rows which are "current". That makes a much better "table" for our ActiveRecord model. The snag: our indexes aren't being used anymore. Queries on the view don't use the underlying tables' indexes. You can't add an index to a view. Without indexes, the app is unbearably slow. The only solution we've come up with is to build a materialized view, but that's a pain in MySQL because they're not natively supported. Is there a better way to do this?

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  • SubSonic isn't generating MySql foreign key tables

    - by keith
    I two tables within a MySql 5.1.34 database. When using SubSonic to generate the DAL, the foreign-key relationship doesn't get scripted, ie; I have no Parent.ChildCollection object. Looking inside the generated DAL Parent class shows the following; //no foreign key tables defined (0) I have tried SubSonic 2.1 and 2.2, and various MySql 5 versions. I must be doing something wrong procedurally - any help would be greatly appreciated. This has always just worked 'out-the-box' when using MS-SQL. TABLE `parent` ( `ParentId` INT(11) NOT NULL AUTO_INCREMENT, `SomeData` VARCHAR(25) DEFAULT NULL, PRIMARY KEY (`ParentId`) ) ENGINE=INNODB DEFAULT CHARSET=latin1; TABLE `child` ( `ChildId` INT(11) NOT NULL AUTO_INCREMENT, `ParentId` INT(11) NOT NULL, `SomeData` VARCHAR(25) DEFAULT NULL, PRIMARY KEY (`ChildId`), KEY `FK_child` (`ParentId`), CONSTRAINT `FK_child` FOREIGN KEY (`ParentId`) REFERENCES `parent` (`ParentId`) ) ENGINE=INNODB DEFAULT CHARSET=latin1;

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  • Question about Radio button/PHP/MySQL

    - by Marcelo
    Hi, I'm an engineering student and I'm developing a simple software based on HTML, PHP and mysql. I learned this topics on w3schools. I know only the basics. I tried to search about this in this website but I found questions about PHP, MySQL and HTML radio buttons which were much more complex than I need and that I could understand. Sorry for the English. (Q1) Ex: $email=$_REQUEST['email'] , in this case the input is text, if it where like a radio button for ex: sex: male or female, how would it be? (Q2) what would be the type of this field (for exemple sex in question 1) in the database: text, int, varchar ? Thanks for the attention

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  • Unable to convert MySQL date/time value to System.DateTime

    - by Sri Kumar
    Hello I am using ibatis and C#. i get a result from a select query that has CreatedDate as one of the field. The Datatype of CreatedDate in Mysql is Date. I assign the result set of the select query to a Ilist< DeliveryClass **. Here the DeliveryClass CreatedDate as DateTime. When i run the application, i get **Unable to convert MySQL date/time value to System.DateTime. What could be the problem?

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  • Unix timestamp and mysql date: birthdate

    - by Mikk
    Hi, I have a really basic question concerning unix timestamp and mysql date. I'm trying to build a small website where users can register and fill in their birthdate. Problem is that unix starts with Jan 01 1970. Now if i calculate age for users, form dates like date('m.d.Y', $unix_from_db) and so on it will fail with users older that 40 years, right? So what would be the rigth way for doing this. Sorry, for basic question like this, but I'm inexperienced with php and mysql.

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  • How to get number of rows deleted from mysql in schell script

    - by simonlord
    Hi all I can't work out how to get the mysql client to return the number of rows deleted to the shell when running a delete. Does anyone know what option will enable this? Or ways around it? Here's what i'm trying, but i get no output: #!/bin/bash deleted=`mysql mydb -e "delete from mytable where insertedtime < '2010-04-01 00:00:00'"|tail -n 1` I was expecting something like this as the output from mysql: deleted 999999 Which is why i have the tail -n 1 so i only pick up the count and not the column name. Any help would be most appreciated.

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  • Organize array in PHP from mysql

    - by Matthew Carter
    Hi i have a social networking website. what i want it to do is pull out my friends status updates. basically what it does is i have a mysql query that pulls out all of my friends and in that while loop there is another mysql query that pulls out the status's from my friends. i want it to be in order of date but since its one while loop in another what it does is pull out all status's from friend 1 then 2 then 3 and not in order by date. i even tried ORDER BY DATE but that just ordered it by date within the friend.. my thought is that i could putt it all in an array and friends is one thing and the values is the stats. then just sort by values would this work and how could i do it. THANKS SO MUCH

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  • MySQL different versions other results.

    - by kuba
    hey, i have 2 version of mysql on windows 5.1.39-community and on linux 5.1.39-log i execute a query: SELECT `o`.`idOffer`, `o`.`offer_date`, `p`.`factory`, `c`.`short` AS `company`, `s`.`name` AS `subcategory`, `ct`.`name` AS `category`, count( (select count(1) from product where idProduct=idOffer group by idOffer) ) as b FROM `Offer` AS `o` LEFT JOIN `Product` AS `p` ON o.idOffer = p.idOffer LEFT JOIN `company` AS `c` ON o.company = c.id LEFT JOIN `Subcategory` AS `s` ON s.idSubcategory = o.idSubcategory LEFT JOIN `Category` AS `ct` ON ct.idCategory = s.idCategory WHERE (o.idOffer = p.idOffer) GROUP BY `o`.`idOffer` on windows it works as it suppose, but on linux it says: ERROR 1242 (21000): Subquery returns more than 1 row is it any way to get it worked on linux without any mysql updates/downgrades ?

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  • mysql_connect randomly hangs up

    - by sergdev
    I install php 5 (more precisely 5.3.1) as apache module. After this one of my application becomes randomly hang up on mysql_connect - sometimes works, sometimes no, sometimes reload of page helps. How can this be fixed? I use Windows Vista, Apache/2.2.14 (Win32) PHP/5.3.1 with php module, MySql 5.0.67-community-nt.

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  • Selecting two field in MySQL with PHP

    - by Crays
    Hi guys, i'm relatively new to php and mysql and would like to know how to select two value in mysql with php. What i have is $query = sprintf("SELECT COUNT(id) FROM table WHERE UPPER(username) = UPPER('%s') AND password='%s'"... in this case, i'm only selecting and count if the id exist and i use list($count) = mysql_fetch_row($result); if($count == 1) and by using cookies, i would like to retrieve two value from the database, namely user (the user's name) and power (which has value of 1,2 or 3, indicating the menu they would be able to see) basically it is to differentiate if you're admin or normal user, but i wonder if i could do SELECT COUNT(id) AND power FROM table WHERE ... is this possible? or is there any other way? Please guide me, thanks.

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  • mysql replace matching but not changing

    - by alex
    I've used mysql's update replace function before, but even though I think I'm following the same syntax, I can't get this to work-it matches the rows, but doesn't replace. Here's what I'm trying to do: mysql> update contained_widgets set preference_values = replace(preference_values, '<li><a_href="/enewsletter"><span class="not-tc">eNewsletter</span></a></li>', '<li><a_href="/enewsletter"><span class="not-tc">eNewsletter</span></a></li> <li> <a_href="/projects"><span class="not-tc">Projects</span></a></li>'); Query OK, 0 rows affected (0.00 sec) Rows matched: 77 Changed: 0 Warnings: 0 I don't see what I'm missing. Any help is appreciated. I edited "a " to "a_" because the site thinks I'm posting spam links otherwise.

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