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  • how to control the width and height of default alert dialog in Android?

    - by sat
    AlertDialog.Builder builder = new AlertDialog.Builder(this); builder.setTitle("Title"); builder.setItems(items, new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int item) { Toast.makeText(getApplicationContext(), items[item], Toast.LENGTH_SHORT).show(); } }); AlertDialog alert = builder.create(); I am using above code to show alert dialog , By default it fills the screen in width and wrap_content in height. How to control the width and height of default alert dialog ? I tried , alert.getWindow().setLayout(100,100); // It dint work. How to get the layout params on the alert window and set manually the width and height ?

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  • SQL Server Querying An XML Field

    - by Gavin Draper
    I have a table that contains some meta data in an XML field. For example <Meta> <From>[email protected]</From> <To> <Address>[email protected]</Address> <Address>[email protected]</Address> </To> <Subject>ESubject Goes Here</Subject> </Meta> I want to then be able to query this field to return the following results From To Subject [email protected] [email protected] Subject Goes Here [email protected] [email protected] Subject Goes Here I've written the following query SELECT MetaData.query('data(/Meta/From)') AS [From], MetaData.query('data(/Meta/To/Address)') AS [To], MetaData.query('data(/Meta/Subject)') AS [Subject] FROM Documents However this only returns one record for that XML field. It combines both the 2 addresses into one result. Is it possible for split these on to separate records? The result I'm getting is From To Subject [email protected] [email protected] [email protected] Subject Goes Here Thanks Gav

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  • How to send XML data through socket InputStream

    - by THeK3nger
    Hi, I'm trying to write a client-server application in Java with an XML-based protocol. But I have a great problem! See this part of client code: InputStream incoming = skt.getInputStream(); //I get Stream from Socket. OutputStream out = skt.getOutputStream(); [...] XMLSerializer serializer = new XMLSerializer(); //This create an XML document. tosend = WUTPClientWriter.createMessage100(projectid, cpuclock, cpunumber); serializer.setOutputByteStream(out); serializer.serialize(tosend); At this point server fall in deadlock. It wait for EOF but I can't send it because if I use out.close(); or skt.shutdownOutput(); I close Socket and I must keep alive this connection. I can't send '\0' becouse I get Parse Error in the server. How can I do? Can I "close" output stream without close socket? RESOLVED I've created new class XMLStreamOutput and XMLStreamInput with advanced Stream gesture.

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  • Switch XML value for another in google maps

    - by JeffP
    all thanks for taking a look. Problem: Using Google maps I need to switch catid value to another value. How would I approach this and display it in a the window. E.G var catid = { 2: { newcatid: 'london' }, 4: { newcatid: 'newyork' } }; function load() { var map = new google.maps.Map(document.getElementById("map"), { center: new google.maps.LatLng(47.6145, -122.3418), zoom: 5, mapTypeId: 'roadmap' }); var infoWindow = new google.maps.InfoWindow; // Change this depending on the name of your PHP file downloadUrl("index_xml.php", function(data) { var xml = data.responseXML; var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("title"); var address = markers[i].getAttribute("address"); var catid = markers[i].getAttribute("catid"); var point = new google.maps.LatLng( parseFloat(markers[i].getAttribute("latitude")), parseFloat(markers[i].getAttribute("langtitude"))); var html = "<b>" + name + "</b> <br/>" + address + "<br/>" + **catid** + "<br/> <a href='@'>Info</a>" ;

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  • C# XML Documentation Compiler Warning

    - by ImperialLion
    I am curious as to why I get a compiler warning in the following situation. /// <summary>This is class A /// </summary> public class A { /// <summary>This is the documentation for Method A /// </summary> public void MethodA() { //Do something } } /// <summary>This is class B /// </summary> public class B : A { /// <summary>This does something that I want to /// reference <see cref="MethodA"/> /// </summary> public void MethodB() { //Do something } } The warning states that "XML comment on 'B.MethodB()' has cref attribute 'MethodA' that could not be resolved." If B inherits from A shouldn't the compiler be able to see that method when generating the documentation without me specifying the parent class in the cref? If I change the cref to be cref="A.MethodA()" it works fine, but it seems like that's unnecessary and is a pain to do, especially if I have to go up more than one level. As a note to anyone testing this you have to be sure to "XML documentation file" checked in the Properties - Build in order to see the warning.

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  • Query decendants in XML to Linq

    - by Gordon
    I have the following xml data: <portfolio> <item> <title>Site</title> <description>Site.com is a </description> <url>http://www.site.com</url> <photos> <photo url="http://www.site.com/site/thumbnail.png" thumbnail="true" description="Main" /> <photo url="http://www.site.com/site/1.png" thumbnail="false" description="Main" /> </photos> </item> </portfolio> In c# I am using the following link query: List list = new List(); XDocument xmlDoc = XDocument.Load(HttpContext.Current.Server.MapPath("~/app_data/portfolio.xml")); list = (from portfolio in xmlDoc.Descendants("item") select new PortfolioItem() { Title = portfolio.Element("title").Value, Description = portfolio.Element("description").Value, Url = portfolio.Element("url").Value }).ToList(); How do I go about querying the photos node? In the PortfolioItem class I have a property: List Photos {get;set;} Any ideas would be greatly appreciated!

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  • ImageView place at center on click in gallery view

    - by TGMCians
    i used gallery view in which i place multiple imageview dynamically but on click imageview place at center and second question how to start first imageview from left of screen. I do not want to change the place until user scroll horizontally by finger . Is there any way to achieve this. Please help for this.. private class ImageAdapter extends BaseAdapter{ public ImageAdapter() { //To set blank at bottom and make visible TextView textView = (TextView)findViewById(R.id.textView2); textView.setVisibility(View.VISIBLE); //To set the visibility visible of gallery myGallery.setVisibility(View.VISIBLE); } public int getCount() { return ProductItemArray.Image_URL.length; } public Object getItem(int position) { return null; } public long getItemId(int position) { return 0; } public View getView(int position, View arg1, ViewGroup arg2) { ImageView bottomImageView = new ImageView(context); if(Helper.isTablet(context)) bottomImageView.setLayoutParams(new Gallery.LayoutParams(VirtualMirrorActivity.convertDpToPixel(100, context), VirtualMirrorActivity.convertDpToPixel(100, context))); else bottomImageView.setLayoutParams(new Gallery.LayoutParams(VirtualMirrorActivity.convertDpToPixel(80, context), VirtualMirrorActivity.convertDpToPixel(80, context))); UrlImageViewHelper.setUrlDrawable(bottomImageView, ProductItemArray.Image_URL[position]); bottomImageView.setBackgroundResource(R.layout.border); return bottomImageView; } } myGallery.setAdapter(new ImageAdapter()); myGallery.setSelection(1); myGallery.setOnItemClickListener(new OnItemClickListener() { @Override public void onItemClick(AdapterView<?> parent, View view, final int position, long arg3) { linearLayout.removeView(frameImageView); Thread newThread = new Thread(new Runnable() { public void run() { URL url_1 = null; try { isAlreadyExistInWishlist = false; VMProductListPaging.productUrl = ProductItemArray.Image_small_URL[position]; VMProductListPaging.productId = ProductItemArray.productId[position]; VMProductListPaging.productName = ProductItemArray.product_Name[position]; url_1 = new URL(ProductItemArray.Image_small_URL[position]); bmp = BitmapFactory.decodeStream(url_1.openConnection().getInputStream()); isExecuted = true; bitmapHandler.sendMessage(bitmapHandler.obtainMessage()); } catch (Exception e) { //Toast.makeText(context,"Sorry!! This link appears to be broken",Toast.LENGTH_LONG).show(); } } }); newThread.start(); } }); Layout.xml <Gallery android:id="@+id/galleryView" android:layout_width="fill_parent" android:layout_height="wrap_content" android:spacing="5dp" android:layout_below="@+id/sendPhoto" android:layout_marginTop="10dp" android:visibility="gone"/>

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  • ANDROID SAX Parser issue

    - by Chris Watson
    Since I am new to java programming, I need a bit of help with this. I stuck on this one issue and can't continue until I get this to work. I am trying to make a string from that includes a preference int. I saved the data and can display the int (just sample code): SharedPreferences prefs=PreferenceManager .getDefaultSharedPreferences(this); list.setText(prefs.getString("list", "22")); now, I have a xml parser that is pulling a url correctly as a static string: public static String feedUrl = String.format("http://www.freshpointmarketing.com/iphone/objects/XML/AND.php?ID=%d", 22); Works great... now my issue...... I need to have the preference "int" become the variable in the string, thus making it not static. static SharedPreferences prefs=PreferenceManager.getDefaultSharedPreferences(this); static int myVariable = prefs.getInt("list1", 22); public static String feedUrl = String.format("http://www.freshpointmarketing.com/iphone/objects/XML/AND.php?ID=%d", myVariable); If I take out all static references, I get an error on this: private void loadFeed(ParserType type){ try{ FeedParser parser = FeedParserFactory.getParser(type); long start = System.currentTimeMillis(); messages = parser.parse(); long duration = System.currentTimeMillis() - start; Log.i("AndroidNews", "Parser duration=" + duration); String xml = writeXml(); Log.i("AndroidNews", xml); List<String> titles = new ArrayList<String>(messages.size()); for (Message msg : messages){ titles.add(msg.getTitle()); } ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, R.layout.row,titles); this.setListAdapter(adapter); } catch (Throwable t){ Log.e("AndroidNews",t.getMessage(),t); } } thanks

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  • Linq Return node level of hierarchical xml

    - by Ryan
    In a treeview you can retrieve the level of an item. I am trying to accomplish the same thing with the given input being an object. The XML data I will use for this example would be something like the following <?xml version="1.0" encoding="utf-8" ?> <Testing> <Numbers> <Number val="1"> <Number val="1.1"> <Number val="1.1.1"> <Number val="1.1.2" /> <Number val="1.1.3" /> <Number val="1.1.4" /> </Number> </Number> <Number val="1.2" /> <Number val="1.3" /> <Number val="1.4" /> </Number> <Number val="2" /> <Number val="3" /> <Number val="4" /> </Numbers> <Numbers> <Number val="5" /> <Number val="6" /> <Number val="7" /> <Number val="8" /> </Numbers> </Testing> This one is kicking my butt!

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  • Is it possible to create the following XML using Xdocument(C#3.0)

    - by Newbie
    <?xml version='1.0' encoding='UTF-8'?> <StockMarket> <StockDate Day = "02" Month="06" Year="2010"> <Stock> <Symbol>ABC</Symbol> <Amount>110.45</Amount> </Stock> <Stock> <Symbol>XYZ</Symbol> <Amount>366.25</Amount> </Stock> </StockDate> <StockDate Day = "03" Month="06" Year="2010"> <Stock> <Symbol>ABC</Symbol> <Amount>110.35</Amount> </Stock> <Stock> <Symbol>XYZ</Symbol> <Amount>369.70</Amount> </Stock> </StockDate> </StockMarket> My approach so far is XDocument doc = new XDocument( new XElement("StockMarket", new XElement("StockDate", new XAttribute("Day", "02"),new XAttribute("Month","06"),new XAttribute("Year","2010")), new XElement("Stock") ) ); Since I am new to Linq to XML, I am presently struggling a lot and henceforth seeking for help. Using C#3.0 . Thanks

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  • Deleting items from datagrid (xml)

    - by Tonz
    Hello, I have a datagrid buttoncolumn which acts as delete buttons for my xml nodes. The elements are simply displayed in a boundcolumn, so there names get displayed. Each item generated gets a unique id (each time one is made id+++). My question his how can i remove a item (the entire element node with that certain id) when i click on one of the buttons in the bound column? <root> <element id="0"> <name>One</name> </element> <element id="1"> <name>Two</name> </element> </root> protected void dg_DeleteCommand(object sender, DataGridCommandEventArgs e) { XmlFunctions.Remove(index); }/*dg_DeleteCommand*/ (function on other class, where all my xml methods are written) public static void Remove(string index) { XmlDocument XMLDoc = new XmlDocument(); XMLDoc.Load(XMLFile); XPathNavigator nav = XMLDoc.CreateNavigator(); var node = nav.SelectSingleNode("/test/one[@id='" +???+ "']"); node.DeleteSelf(); XMLDoc.Save(XMLFile); } Edit: added datagrid <asp:View ID="viewDelete" runat="server"> <asp:DataGrid ID="dgDelete runat="server" AutoGenerateColumns="False" OnDeleteCommand="dg_DeleteCommand"> <Columns> <asp:BoundColumn DataField="name" HeaderText="names" /> <asp:ButtonColumn ButtonType="PushButton" Text="Delete" CommandName="Delete" ></asp:ButtonColumn> </Columns> </asp:DataGrid> </asp:View>

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  • Properly obsoleting old members in an XML Serializable class in C# VB .NET

    - by George
    Hi! Some time ago I defined a class that was serialized using XML. That class contained a serializable propertyA of integer type. Now I have extended and updated this class, whereby a new propertyB was added, whose type is another class that also has several serializable properties. The new propertyB is now supposed to play the role of propertyA, that is since type of propertyB is another class, one of its members would contain the value that previously propertyA contained, thus making peroptyA obsolete. What I am trying to figure out is how do I make sure that when I desireliaze the OLD version of this class (without propertyB in it), I make sure that the desreializer would take the value of propertyA from the old calss and set it as a value of one of the members of propertyB in a new class? Private WithEvents _Position As Position = New Position(Alignment.MiddleMiddle, 0, True, 0, True) Public Property Position() As Position 'NEW composite property that holds the value of the obsolted property, i.e. Alignment Get Return _Position End Get Set(ByVal value As Position) _Position = value End Set End Property Private _Alignment As Alignment = Alignment.MiddleMiddle <Xml.Serialization.XmlIgnore(), Obsolete("Use Position property instead.")> _ Public Property Alignment() As Alignment'The old, obsoleted property that I guess must be left for compliance with deserializing the old version of this class Get Return _Alignment End Get Set(ByVal value As Alignment) _Alignment = value End Set End Property Can you help me, please?

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  • Copy existing XML, duplicate element and modify

    - by Robert
    Hi, I have a tricky XSL problem at the moment. I need to copy the existing XML, copy a certain element (plus its child elements) and modify the value of two child-elements. The modifications are: divide value of the 'value' element by 110 and edit the value of the 'type' element from 'normal' to 'discount'. This is currently what I have: Current XML: <dataset> <data> <prices> <price> <value>50.00</value> <type>normal</type> </price> </prices> </data> </dataset> Expected result <dataset> <data> <prices> <price> <value>50.00</value> <type>normal</type> </price> <price> <value>45.00</value> <type>discount</type> </price> </prices> </data> </dataset> Any takers? I've gotten as far as copying the desired 'price' element using copy-of, but I'm stuck as to how to modify it next.

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  • Is there a way to automatically update application on Android?

    - by Levara
    Hi, I'm developing an application that will most likely be preinstalled on devices. It will be also available on Market. Is there a way to update those instances that are not downloaded through Market, since Market won't notify users about an update. I was thinking about, as suggested here, trying to contact my site periodically, and when update is available, download it. I'm wondering if there is a way to do this update automatically, so that user doesn't have to do anything (like running the package manually). Or, when my site shows update is available, to offer users an update through Market, even though it's not installed through Market. Thanks!

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  • creating xml from database

    - by Prady
    hi, I am creating an xml from salesforce database, Everything works fine except when there is a & in the data which is been fetched. <apex:page contenttype="text/xml" > controller="Test2ab" > <data > wiki-section="Timeline"> <apex:repeat > value="{!lsttask}" var="e" > <event > start="{!e.ActivityDate}" title= > "{!e.Subject}"> <apex:outputText > value="{!e.Subject}" /> </event> > </apex:repeat> </data></apex:page> and in the controller i am just querying > lsttask =[Select OwnerId,WhoId,Status,Subject,ActivityDate from Task where Status = 'Completed' Order By ActivityDate Desc]; How can i use an escape for the value retrieved from the database Thanks Prady

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  • Cannot get list of elements using Linq to XML

    - by Blackator
    Sample XML: <CONFIGURATION> <Files> <File>D:\Test\TestFolder\TestFolder1\TestFile.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile01.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile02.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile03.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile04.txt</File> </Files> <SizeMB>3</SizeMB> <BackupLocation>D:\Log backups\File backups</BackupLocation> </CONFIGURATION> I've been doing some tutorials but I am unable to get all the list of file inside the files element. It only shows the first element and doesn't display the rest. This is my code: var fileFolders = from file in XDocument.Load(@"D:\Hello\backupconfig1.xml").Descendants("Files") select new { File = file.Element("File").Value }; foreach (var fileFolder in fileFolders) { Console.WriteLine("File = " + fileFolder.File); } How do I display all the File in the Files element, the SizeMB and BackupLocation? Thanks

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  • Retrieving XML node from a path specified in an attribute value of another node

    - by Olivier PAYEN
    From this XML source : <?xml version="1.0" encoding="utf-8" ?> <ROOT> <STRUCT> <COL order="1" nodeName="FOO/BAR" colName="Foo Bar" /> <COL order="2" nodeName="FIZZ" colName="Fizz" /> </STRUCT> <DATASET> <DATA> <FIZZ>testFizz</FIZZ> <FOO> <BAR>testBar</BAR> <LIB>testLib</LIB> </FOO> </DATA> <DATA> <FIZZ>testFizz2</FIZZ> <FOO> <BAR>testBar2</BAR> <LIB>testLib2</LIB> </FOO> </DATA> </DATASET> </ROOT> I want to generate this HTML : <html> <head> <title>Test</title> </head> <body> <table border="1"> <tr> <td>Foo Bar</td> <td>Fizz</td> </tr> <tr> <td>testBar</td> <td>testFizz</td> </tr> <tr> <td>testBar2</td> <td>testFizz2</td> </tr> </table> </body> </html> Here is the XSLT I currently have : <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"> <xsl:output method="html" indent="yes"/> <xsl:template match="/ROOT"> <html> <head> <title>Test</title> </head> <body> <table border="1"> <tr> <!--Generate the table header--> <xsl:apply-templates select="STRUCT/COL"> <xsl:sort data-type="number" select="@order"/> </xsl:apply-templates> </tr> <xsl:apply-templates select="DATASET/DATA" /> </table> </body> </html> </xsl:template> <xsl:template match="COL"> <!--Template for generating the table header--> <td> <xsl:value-of select="@colName"/> </td> </xsl:template> <xsl:template match="DATA"> <xsl:variable name="pos" select="position()" /> <tr> <xsl:for-each select="/ROOT/STRUCT/COL"> <xsl:sort data-type="number" select="@order"/> <xsl:variable name="elementName" select="@nodeName" /> <td> <xsl:value-of select="/ROOT/DATASET/DATA[$pos]/*[name() = $elementName]" /> </td> </xsl:for-each> </tr> </xsl:template> </xsl:stylesheet> It almost works, the problem I have is to retrieve the correct DATA node from the path specified in the "nodeName" attribute value of the STRUCT block.

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  • placing the matched 2 different child elements xml values in a single line from xslt2.0

    - by Girikumar Mathivanan
    I have the below input xml, <GSKProductHierarchy> <GlobalBusinessIdentifier>ZGB001</GlobalBusinessIdentifier> <Hierarchy> <Material>335165140779</Material> <Level1>02</Level1> <Level2>02AQ</Level2> <Level3>02AQ006</Level3> <Level4>02AQ006309</Level4> <Level5>02AQ006309</Level5> <Level6>02AQ006309</Level6> <Level7>02AQ006309</Level7> <Level8>02AQ006309</Level8> </Hierarchy> <Hierarchy> <Material>335165140780</Material> <Level1>02</Level1> <Level2>02AQ</Level2> <Level3>02AQ006</Level3> <Level4>02AQ006309</Level4> <Level5>02AQ006309</Level5> <Level6>02AQ006309</Level6> <Level7>02AQ006309</Level7> <Level8>02AQ006310</Level8> </Hierarchy> <Texts> <ProductHierarchy>02AQ006310</ProductHierarchy> <Language>A</Language> <Description>CREAM</Description> </Texts> <Texts> <ProductHierarchy>02AQ006309</ProductHierarchy> <Language>B</Language> <Description>CREAM</Description> </Texts> as per the requirement, xsl should check the matched value of GSKProductHierarchy/Hierarchy/Level8 in the GSKProductHierarchy/Texts/ProductHierarchy elements...and its should result as below flat file. 335165140779|02|02AQ|02AQ006|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006309|A|CREAM| 335165140780|02|02AQ|02AQ006|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006310|02AQ006310|B|CREAM| Right now I have the below xslt, <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exsl="http://exslt.org/common" xmlns:set="http://exslt.org/sets" xmlns:str="http://exslt.org/strings" xmlns:java="http://xml.apache.org/xslt/java" xmlns:saxon="http://saxon.sf.net/" exclude-result-prefixes="exsl set str java saxon"> <xsl:output method="text" indent="yes"/> <xsl:variable name="VarPipe" select="'|'"/> <xsl:variable name="VarBreak" select="'&#xa;'"/> <xsl:template match="/"> <xsl:for-each select="GSKProductHierarchy/Hierarchy"> <xsl:variable name="currentIndex" select="position()"/> <xsl:variable name="Level8" select="Level8"/> <xsl:variable name="ProductHierarchy" select="../Texts[$currentIndex]/ProductHierarchy"/> <xsl:if test="$Level8=$ProductHierarchy"> <xsl:value-of select="Material"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level1"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level2"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level3"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level4"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level5"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level6"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level7"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level8"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/ProductHierarchy"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/Language"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/Description"/> <xsl:value-of select="$VarPipe"/> <xsl:if test="not(position() = last())"> <xsl:value-of select="$VarBreak"/> </xsl:if> </xsl:if> </xsl:for-each> </xsl:template> can anyone please suggest what function should i need to use to get the desired result. Regards, Giri

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  • "ant" is not recognized as command in Windows

    - by user1294663
    This is my first time developing Android applications. I'm developing an Android app on Eclipse on Windows 7. I would like to run the Android app from the Windows 7 command line interface. I have my Android device connected to the PC. The workspace directory that I use to store the Android project is C:\Users\Guest\Desktop\Software Applications Development\Java\Android Moblie Applications Projects\Eclipse Indigo for Java EE x64-bit\project workspace I opened the command line interface and I changed the working directory to the Android workspace directory. cd C:\Users\Guest\Desktop\Software Applications Development\Java\Android Moblie Applications Projects\Eclipse Indigo for Java EE x64-bit\project workspace I included Android sdk platform tools directory into the PATH environment variable. c:\Users\admin\Android-sdks\platform-tools Then I entered this into the Windows 7 command line interface: ant debug I have this error message on the cmd: ant is not recognised as an internal or external command, operatable program or batch file. What is the solution to this problem?

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  • Can I make Windows to open Excel XML files with Excel without opening Explorer?

    - by Sorin Sbarnea
    I want to be able to open Excel XML files in Excel but without assigning XML directly to Excel. There are lots of XML files that are not Excel files and I don't want to open all of them in Excel. The file has proper header for opening in Excel but currently it does open Internet Explorer that asks me if I want to open the file with Excel, save or cancel. I just want to open it without two another annoying windows.

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  • What is a good XML Editor for Mac OS X?

    - by g.
    I am looking for a good lightweight XML viewer/editor for Mac OS X. It would only be for occasional use, so free options are preferable though paid options aren't out of the question. It would be used primarily for reviewing and making small changes to XML files and would require the following basic features. easily create a new file from clipboard (copy/paste) re-format (pretty print) xml syntax highlighting validation find

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