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  • Out-of-the-box Eclipse PDT (PHP Development Tool) not capable of debugging PHP, why?

    - by Alex R
    I just finished reinstalling the "All-In-One Eclipse PDT" from zend.com. It's unable to debug even the simplest "Hello World" PHP script. How can such a major open-source app be released in such a bad shape? What am I doing wrong? This is the result of doing a "Debug As...": Problem signature: Problem Event Name: APPCRASH Application Name: php.exe Application Version: 5.2.9.9 Application Timestamp: 49dda267 Fault Module Name: ntdll.dll Fault Module Version: 6.0.6002.18005 Fault Module Timestamp: 49e03824 Exception Code: c0000130 Exception Offset: 0006f04e OS Version: 6.0.6002.2.2.0.768.3 Locale ID: 1033 Additional Information 1: 9d13 Additional Information 2: 1abee00edb3fc1158f9ad6f44f0f6be8 Additional Information 3: 9d13 Additional Information 4: 1abee00edb3fc1158f9ad6f44f0f6be8 Read our privacy statement: http://go.microsoft.com/fwlink/?linkid=50163&clcid=0x0409 I think it wants me to configure some additional stuff, but I have no clue what exactly to do.

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  • ZipArchive php Class - Is it built-in to PHP?

    - by SoLoGHoST
    Ok, just wondering on the versions of PHP that this class is built into. And if they are built into all platforms (OS's). I'm wanting an approach to search through a zip file and place files using file_put_contents in different filepaths within the webroot. In any case, I'm familiar with how to do this with the ZipArchive class, but I'm wondering if using this class would be a good solution and support MOST, if not ALL servers?? I mean, I'd rather not use a method that requires the Server to have it installed. I'm looking for a solution to this that will support at least MOST servers without having to install the class... Thanks :) Also, I'd like to support opening tar.gz and/or .tgz files if possible, but I don't think the ZipArchive class supports this, but perhaps a different built-in php class does??

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  • What to know - for building a form with PHP and MySQL

    - by Tal Galili
    Hello all, I have three weeks to perform the following basic task. I wish to create an online form in PHP that will get 5 numbers and with them: save the numbers to a MySQL DB do a simple computation on the numbers and return them as an output to the visitor I already have a domain, hosting and a MySQL database+user. I don't know PHP, or SQL or databases. I do have prior knowledge in C and R (which means I have some of the basics of programming, and I am not intimidated of a new languages). My question are: Am I missing something? is there some other skill I should have for this task that I don't know of? What is a good way to learn the skills needed for the task I described? Hope the question isn't too basic/general. Thanks!

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  • When to use or not use symbols in PHP

    - by brett
    I'm reading a PHP book where the author says that symbols should be avoided except when it's valid to use them. Very informative stuff, if he could only elaborate or give code examples but he doesn't. Can someone from the experienced PHP bunch give me an example of what these symbols are, and when it makes sense to use them or not. I'm looking for a code example that I can wrap my head around since I don't quite get it in plain English. Code is more plain English to me.

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  • PHP: How To call Standard Library Functions

    - by Andi
    Hi, I'm starting with PHP for dynamic web pages. I have some libaries written in ANSI C for getting/setting parameters and other proprietary stuff. I wonder, is there a simple solution to use a wrapper inside PHP to call this funtions? Is there a already existing class/library? What would be the best practice to do this on my own? I don't want do make calls to external applications and use stdin/stdout! Is there a simple example available? I don't want to dig through the Zend documentation for now, I only need a feeling for the complexity. Thanks, kind regards, Andi

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  • Getting JSON data in PHP

    - by domagoj412
    I have a JSON data like this: { "hello": { "first":"firstvalue", "second":"secondvalue" }, "hello2": { "first2":"firstvalue2", "second2":"secondvalue2" } } I know how to retrieve data from object "first" (firstvalue) and second (secondvalue) but I would like to loop trough this object and as a result get values: "hello" and "hello2"... This is my PHP code: <?php $jsonData='{"hello":{"first":"firstvalue","second":"secondvalue"},""hello2":{"first2":"firstvalue2","second2":"secondvalue2"}}'; $jsonData=stripslashes($jsonData); $obj = json_decode($jsonData); echo $obj->{"hello"}->{"first"}; //result: "firstvalue" ?> Can it be done?

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  • php: ip2long returning negative val

    - by andufo
    hi, function ip_address_to_number($IPaddress) { if(!$IPaddress) { return false; } else { $ips = split('\.',$IPaddress); return($ips[3] + $ips[2]*256 + $ips[1]*65536 + $ips[0]*16777216); } } that function executes the same code as the php bundled function ip2long. however, when i print these 2 values, i get 2 different returns. why? (im using php 5.2.10 on a wamp environment). ip2long('200.117.248.17'); //returns -931792879 ip_address_to_number('200.117.248.17'); // returns 3363174417

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  • Add parameter to PHP

    - by proyb2
    When I sent an image to the code below, uploadImage.php, through a POST method, how do I add a String parameter? <?php $hasError = false; foreach( $_FILES as $i=>$file ) { if ( $file['error'] ) { $hasError = true; } } if ( ! $hasError ) { $myFilePath = '_uploads/'.'_'.$file["name"]; $dta = file_get_contents($file['tmp_name']); file_put_contents($myFilePath, $dta); } else { echo('Stick custom error message here'); } ?>

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  • Php mysqli and stored-procedure

    - by Mneva skoko
    I have a stored procedure: Create procedure news(in dt datetime,in title varchar(10),in desc varchar(200)) Begin Insert into news values (dt,title,desc); End Now my php: $db = new mysqli("","","",""); $dt = $_POST['date']; $ttl = $_POST['title']; $desc = $_POST['descrip']; $sql = $db-query("CALL news('$dt','$ttl','$desc')"); if($sql) { echo "data sent"; }else{ echo "data not sent"; } I'm new with php please help thank you

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  • Creating thumbnails PHP problem

    - by Wayne
    I have this source code where I got it from net tutsplus. I have configured it and made it work in one PHP file. It does work by transferring the original image, but it does not generate to the thumbnails folder. <?php $final_width_of_image = 100; $path_to_image_directory = "../../img/events/" . urldecode($_GET['name']) . "/"; $path_to_thumbs_directory = "../../img/events/" . urldecode($_GET['name']) . "/thumbnails/"; function createThumbnail($filename) { if(preg_match('/[.](jpg)$/', $filename)) { $im = imagecreatefromjpeg($path_to_image_directory . $filename); } elseif(preg_match('/[.](gif)$/', $filename)) { $im = imagecreatefromgif($path_to_image_directory . $filename); } elseif(preg_match('/[.](png)$/', $filename)) { $im = imagecreatefrompng($path_to_image_directory . $filename); } $ox = imagesx($im); $oy = imagesy($im); $nx = $final_width_of_image; $ny = floor($oy * ($final_width_of_image / $ox)); $nm = imagecreatetruecolor($nx, $ny); imagecopyresized($nm, $im, 0,0,0,0,$nx,$ny,$ox,$oy); imagejpeg($nm, $path_to_thumbs_directory . $filename); $tn = '<img src="' . $path_to_thumbs_directory . $filename . '" alt="image" />'; echo $tn; } if(isset($_FILES['fupload'])) { if(preg_match('/[.](jpg)|(gif)|(png)$/', $_FILES['fupload']['name'])) { $filename = $_FILES['fupload']['name']; $source = $_FILES['fupload']['tmp_name']; $target = $path_to_image_directory . $filename; move_uploaded_file($source, $target); createThumbnail($filename); } } ?> Basically it is supposed to generate a thumbnail of the uploaded image and store the original image into a different folder. The paths are correct, it works by getting the folder name in the URL, it does work, but nothing works for the thumbnails folder. BEFORE you ask this related question, yes, thumbnails generation does work on my server by the PHP GD, I have tested it separately. So this is not the problem. :) How do I get this to work? :(

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  • Content-type not working in PHP

    - by Industrial
    Hi everyone, I have some issues with a PHP file that is not working properly. The Content-type does not get recieved by any browser at all. Firebug interprets the file as text/html instead of css. Here's the file : <?php header('Content-Type: text/css; charset=UTF-8'); error_reporting(E_ALL | E_STRICT); ini_set('display_errors', 'On'); /* CSS goes on from here */ I tested to put a row with echo 'TEST'; before the header line, and was expecting to see the classic "headers already sent" error, but nothing appears! What can I do to sort this out?

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  • pdf file creation in php

    - by pavun_cool
    Actually I have used following code , for creating the simple pdf file . It executed fine in the browsers. But I am not able to get the pdf file . But it gives me some output when I am running the code in CLI . my doubt is , where I need specify pdf file name ( creation file ) . <?php require('fpdf.php'); $pdf=new FPDF(); $pdf->AddPage(); $pdf->SetFont('Arial','B',16); $pdf->Cell(40,10,'Hello World!'); $pdf->Output(); ?> CLI output: 2 0 obj << /Type /Page /Parent 1 0 R /Contents 3 0 R endobj 3 0 obj << /Length 4 0 R stream 2.834646 0 0 2.834646 0 841.9 cm 2 J 0.2 w BT /F1 5.64 Tf ET BT 11 -16.692 Td (Hello World!) Tj ET

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  • PHP While() Stop Looping

    - by Axel
    Hi, i have a php loop which displays only one record even if there is hundreds. here is the code: <?php $result1 = mysql_query("SELECT * FROM posts") or die(mysql_error()); $numexem = mysql_num_rows($result1); $s="0"; while($s<$numexem){ $postid=mysql_result($result1,$s,"id"); echo "Post id:".$postid; $result2 = mysql_query("SELECT * FROM pics WHERE postid='$postid'") or die(mysql_error()); $rows = mysql_fetch_array($result2) or die(mysql_error()); $pnum = mysql_num_rows($result2); echo " There is ".$pnum." Attached Pictures"; $s++; } ?> I'm wondering if the loop stop because there is other SQL query inside it or what? and i don't think so. Thanks

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  • Unix tree convert to recursive php array

    - by Fordnox
    I have a response from remote server like this: /home/computer/Downloads |-- /home/computer/Downloads/Apple | `-- /home/computer/Downloads/Apple/Pad |-- /home/computer/Downloads/Empty_Folder `-- /home/computer/Downloads/Subfolder |-- /home/computer/Downloads/Subfolder/Empty `-- /home/computer/Downloads/Subfolder/SubSubFolder `-- /home/computer/Downloads/Subfolder/SubSubFolder/Test this is the output for command computer@athome:$ tree -df --noreport -L 5 /home/computer/Downloads/ I would like to parse this string to recursive php array or object, something like this. I would show only part of result to get the idea. array( 'title' => '/home/computer/Downloads', 'children' => array( 0 => array( 'title' => '/home/computer/Downloads/Apple', 'children' => array( ... ) ) ); Response from server can change according to scanned directory. Can someone help me write this function. Please note that this is response from remote server and php functions can not scan any remote dir.

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  • php : echo"", print(), printf()

    - by marc-andre menard
    Is there a better way to output data to html page with PHP ? if i like to make a div with some var in php i will write something like that print ('<div>'.$var.'</div>); or echo "'<div>'.$var.'</div>'"; what is the PROPER way to do that ? or a better way, fill a $tempvar and print it once? like that: $tempvar = '<div>'.$var.'</div>' print ($tempvar); in fact, in real life, the var will be fill with much more !

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  • What some good PHP jobs?

    - by ggfan
    I am no professional PHP coder or anything, in fact I am fairly new. I can develop sites but nothing too crazy or fancy with PHP,Mysql,CSS,HTML,javascript. Up to now, all I have been doing is practice coding from books and websites. I am now looking for a 'real-life' experience. Besides going to a company and getting an interview, are there any other options in which I can get paid to code? I have posted some ads on craiglists but that's about it. And because this is my first time going to the 'real-word' and can make mistakes, am I liable if...a site I made for someone gets hacked and that person losses information?

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  • Flex / ZendAMF / PHP app, corrupted data with some linux clients problem

    - by Laurent Jégou
    Hello, i'm buiding a survey web application, using Flex for the front-end (nice forms), and a MySQL database for the storage, linked by PHP with the help of ZendAMF. I largely borrowed from this nice tutorial by Alan Gruskoff : http://digitalshowcase.biz/wordpress/?page_id=26 (The only one tutorial i've found to work with the last version of Flex). The app seems to works nicely in my tests, except on certain linux boxes : the data is somehow corrupted : there is no error message, no glitch, but the response of the forms are not what the user selected. I tried to reproduce the error on a fresh installed ubuntu VM, but it works fine. I've asked friends for some tests, and several linux users showed the same problem, on ubuntu and suse machines, all freshly updated and functionnal. The application was targeted to be the survey tool for my doctoral thesis, so i'm quite desperate here, and before i'm dumping it to start anew with php only, i'm asking here in case someone can help, thanks :-) Please excuse my english, by the way. LJ.

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  • PHP Session code work differently on two servers

    - by williamsdb
    I have some code which works fine on one server but is giving a session header warning: Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent on another. I have checked the php.ini settings on the two servers and they are identical. I know that the warning message is supposed to suggest that something has been outputted before the session_start but what I don't understand is why the same code works on one server but not the other. Is there anything else that could be explaining it other than the php.ini settings?

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  • PHP can be exclusively accessed by SWF

    - by brett
    I'm not sure how to describe this, but basically I have a PHP class file: class HelloHello { public function getSomeData($input_parameter){ // code to retrieve data from the database } public function deleteSomeData($input_parameter){ // code to delete data from the database } } This class is on the server and is part of the backend that connects with a database, and it's meant to be accessed by the frontend SWF only (not to be directly accessed). I've setup Flex to read this class and access it. But how do I make sure that someone doesn't develop a script that can call this php file directly and access its methods? For example using a script to add data in a fast automated way, or use the delete method directly, ouch. Is this a legitimate concern, or this can't be done?

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  • php foreach visible on page

    - by Hintswen
    In my PHP code I have this: $filename = 'data.xml'; $xml = file_get_contents($filename); $data = simplexml_load_string($xml); $variable = ""; foreach ($data->file_info as $record) { $id1 = $record['id1']; $id2 = $record['id2']; } And it works perfectly fine on the web server, but when trying to view it locally (using xampp) I get the following output at the top of my pgae: file_info as $record) { $id1 = $record['id1']; $id2 = $record['id2']; } (followed by another 100 or so lines of PHP) Not sure if it would make a difference, the web server it works on is running linux, and I am trying to view it on windows using xampp)

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  • How to strip a GET property from the URL using PHP

    - by James
    I have the following function that get's the current page URL: <?php // get current page url function currentPageUrl() { $pageURL = 'http'; if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";} $pageURL .= "://"; if ($_SERVER["SERVER_PORT"] != "80") { $pageURL .= $_SERVER["SERVER_NAME"].":".$_SERVER["SERVER_PORT"].$_SERVER["REQUEST_URI"]; } else { $pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"]; } echo $pageURL; } ?> Which prints: http://localhost/gallery.php?id=23&type=main I want to remove "&type=main" which is present in the url. So before echoing $pageURL I add the following line: $pageUrl = preg_replace("&type=main", "", $pageURL); But it still returns the full url including type=main. How can I get rid of that from the url?

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