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  • WPF Buttons Style

    - by Polaris
    I have WPF Form which has many buttons with the same code. Appearance of all buttons must be the same For example, code for one of these buttons <Button x:Name="btnAddRelative" Width="120" Click="btnAddRelative_Click" > <Button.Content> <StackPanel Orientation="Horizontal"> <Image Height="26" HorizontalAlignment="Left"> <Image.Source> <BitmapImage UriSource="images/add.png" /> </Image.Source> </Image> <TextBlock Text=" Add Relative" Height="20" VerticalAlignment="Center"/> </StackPanel> </Button.Content> </Button> How can I create one style and use it for all my buttons. All buttons has the same png image, only their text different. How can I do this. I tried to do this with Style object in Resource Section: <UserControl.Resources> <Style TargetType="Button" x:Key="AddStyle"> <Setter Property="Content"> <Setter.Value> <StackPanel Orientation="Horizontal"> <Image Height="26" HorizontalAlignment="Left"> <Image.Source> <BitmapImage UriSource="images/add.png" /> </Image.Source> </Image> <TextBlock Text=" " Height="20" VerticalAlignment="Center"/> </StackPanel> </Setter.Value> </Setter> </Style> </UserControl.Resources> But this code not work. Can any body know how can I do this?

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  • Hiding/blocking tabs using windows forms in c#

    - by Audel
    The thing is that i have a 'log in window' and a 'mainwindow' that is called after pressing the log in button or the "VISITANT" button If pressing the log in button, the whole system will come out, and if i press the VISITANT button, one tab should disappear or be blocked or something. private void visitant(object sender, EventArgs e) { mainwindow menu = new mainwindow(); menu.Show(); //mainwindow.tabPage1.Enabled = false; //attempt1 //mainwindow.tabPage1.Visible = false; //attempt1 //System.Windows.Forms.tabPage1.Enabled = false;//attempt2 //System.Windows.Forms.tabPage1.Visible = false;//attempt2 this.Hide(); } the errors i get for using the attempt1 are Error 1 'System.mainwindow.tabPage1' is inaccessible due to its protection level' Error 2 An object reference is required for the non-static field, method, or property 'System.mainwindow.tabPage1' and the one i get for using the attempt2 is Error 1 The type or namespace name 'tabPage1' does not exist in the namespace 'System.Windows.Forms' (are you missing an assembly reference?) as you probably have guessed "tabPage1" is the tab i need to hide when pressing the visitant button. I can't think of any more details, I will be around to provide any extra information Thanks in advance.

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  • Need to have an aspx page with a Feature in SharePoint 2010

    - by camit90
    I have added a custom button to the server ribbon in SharePoint (I have used a feature with Farm scope, so that the button is visible throughout the various site collections). For the elements of the feature, I have added a CustomUIExtension through which I want to load an aspx page on the click of the button. <CommandUIHandler Command="Test_Button" CommandAction="javascript: function demoCallback(dialogResult, returnValue) { SP.UI.Notify.addNotification('Operation Successful!'); SP.UI.ModalDialog.RefreshPage(SP.UI.DialogResult.OK); } var options = { url: '/_layouts/CustomPage.aspx', tite: 'Custom Page', dialogReturnValueCallback: demoCallback }; SP.UI.ModalDialog.showModalDialog(options);" /> I have added the CustomPage.aspx and its corresponding code behind class to the 14 hive (inside 14/TEMPLATE/LAYOUTS). However when I install the feature and click the button, I get an error saying "Cannot load CustomPage". I understand that I haven't deployed the assembly, but shouldn't the aspx page be compiled Just In Time?

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  • Magento: Customer Comment on order page required field

    - by Shamim Ahmed
    I am using whiteOrderComment module for customer comment on order review page. but in this section text-area field required option not working. I did little bit change on /checkout-onepage-review-button.phtml like this <script type="text/javascript"> function validate(){ if(document.getElementById("whiteOrderComment").value == ""){ alert('Required'); }else{ review.save(); } </script> <button type="submit" title="<?php echo $this->__('Place Order') ?>" class="button btn-checkout" onclick="validate();"><span><span><?php echo $this->__('Place Order') ?></span></span></button> but in this page javascript not working. can you please give any better idea, how can i make this text-area field required. thanks

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  • Using Javascript, How do I bring an already existing open window to the front on top of other window

    - by user268249
    The question was fairly descriptive but I'll describe it further. Basically, I have Window1, clicking a button link opens window2. Clicking a button in window2 opens window3, clicking a button in window3 should bring window2 back to the front of the screen on top of window2. I'm not sure how this is exactly done, however I have used and played around with focus(), opener and other various methods and I cannot seem to get it to work properly. Thanks for any help in advance!

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  • How to limit the number of the same Activity on the stack for an Android application

    - by johnrock
    Is this possible in an Android app? I want to make it so that no matter how many times a user starts activityA, when they hit the back button they will never get more than one occurence of activityA. What I am finding in my current code is that I have only two options: 1. I can call finish() in activityA which will prevent it from being accessible via the back button completely, or 2. I do not call finish(), and then if the user starts activityA (n) times during their usage, there will be (n) instances when hitting the back button. Again, I want to have activityA accessible by hitting the back button, but there is no reason to keep multiple instances of the same activity on the stack. Is there a way to limit the number of instances of an activity in the queue to only 1?

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  • Submit form with POST data in Android app

    - by datguywhowanders
    I've been searching the web for a way to do this for about a week now, and I just can't seem to figure it out. I'm trying to implement an app that my college can use to allow users to log in to various services on the campus with ease. The way it works currently is they go to an online portal, select which service they want, fill in their user name and pwd, and click login. The form data is sent via post (it includes several hidden values as well as just the user name and pwd) to the corresponding login script which then signs them in and loads the service. I've been trying to come at the problem in two ways. I first tried a WebView, but it doesn't seem to want to support all of the html that normally makes this form work. I get all of the elements I need, fields for user and pwd as well as a login button, but clicking the button doesn't do anything. I wondered if I needed to add an onclick handler for it, but I can't see how as the button is implemented in the html of the webview not using a separate android element. The other possibility was using the xml widgets to create the form in a nice relative layout, which seems to load faster and looks better on the android screen. I used EditText fields for the input, a spinner widget for the service select, and the button widget for the login. I know how to make the onclick and item select handlers for the button and spinner, respectively, but I can't figure out how to send that data via POST in an intent that would then launch a browser. I can do an intent with the action url, but can't get the POST data to feed into it. Anyone have any suggestions?

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  • How to find a label in a asp repeater

    - by citrus
    Structure of my asp: repeater repeater updatePanel label1 (rating) button (updates rating) some_picture (thing being rated) /update panel /repeater Imagine the output of the above repeater containing 100 rows. (1 label, and 1 button on each row). Goal: when I click the button, I want the appropriate label to be updated. I dont know how to do this. I can reference a label via: Label myLabel2Update = (Label)Repeater1.Controls[0].Controls[0].FindControl("Label1"); But ofcourse, it will be the same label each time (not necessarily the label that needs to be updated). I need to update the label that is on the same row as the button. Any guidance would be appreciated.

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  • Why is my asp.net mvc form POSTing instead of GETting?

    - by quakkels
    My code is straightforward enough: <% using(Html.BeginForm(FormMethod.Get)) %> <% { %> Search for in Screen Name and Email: <%: Html.TextBox("keyword", Request.QueryString["keyword"]) %> <button type=submit>Search</button> <% } %> The issue I'm running into is that when I submit this form, the values are not added to the querystring. Instead, it appears that the form is submitting by a post request. When I look at the generated HTML, I have this: <form action="/find/AdminMember/MemberList" method="post"> Search for in Screen Name and Email: <input id="keyword" name="keyword" type="text" value="" /> <button type=submit>Search</button> </form> Does anyone know why? This seems pretty simple and straighforward to me.

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  • iphone instance / class method issue

    - by user290031
    Hey All, Okay, so I have a viewController method that has some elements created with interface builder and some I coded myself. I created a view in the IB...lets call it viewOne. I created a loop that creates buttons (through code) and places them on a separate view (viewTwo). This is done in a class method. However, I want the view I made to be opened everytime one of the buttons is clicked. So I did: [button addTarget:self action:@selector(woogoo:) forControlEvents:UIControlEventTouchUpInside]; The woogoo class does the following: +(void) woogoo:(id)sender { //back button [self.view addSubview:viewOne] } However, the program crashes when a button is clicked. I did try making woogoo an instance method but it also crashes in this case too. All I want to do is show viewOne when a button is clicked. Any ideas what I can do?

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  • how to know application is going to destroy/remove?

    - by Bhavesh Jethani
    My requirement is, i want to cancel my alarm manager or services when application going to destroy/closed. if i am in activity A by clicking on button started activity B suddenly user is going to press home button. ---- if application is running in background then don't cancel service. but when he going to remove from recent list of application at that time cancel service. Service/Alarm manager will work even when user has sent application in background by pressing home screen. No of way application can destroy or removed. 1) by clicking back button multiple times if stack have multiple activities. 2) by pressing home button and then remove from recent list. i am facing issue with (2)second option. in that when user press home button at that time service or alarm manager should be work. But when user will be going to remove application from recent list at that time i want to cancel service/alarm manager. Second issue. my service is called at fix interval of time. if i will write code on onCreate(), onDestroy() in each activity. then timer will start from beginning. Is there any listners who talk me application is going to closed?

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  • Is there an easy way to stream a m3u in iPhone?

    - by marty
    I can have a UIWebView with the .m3u file opened, which will go to the webview with a play button displayed, and that automatically goes to the quicktime player and starts playing the stream. But when I press the done button, it goes back to the UIWebView with a little play button in the middle, and from there you can go back to the previous screen (it was selected from a tableview). So I just want it to automatically load the quicktime player in the view. How can I do that?

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  • Pass Value between MDI Child in WinForm using C#

    - by abhilashca
    I have an MDI Parent, containing a MenuStrip. When I click on one of the Menu, two Child Forms are displayed simultaneoulsy. I have a TextBox and a Send Button on one of my ChildForm. When I type-in something in that TextBox and Click the Send Button, I need to show that value in the TextBox of my Second Child Form. What I had done is, I wrote a Public Function in the Second Child Form and tried to invoke it by creating an object of Second Form, on the Send Button click event. When I put break points, in that Public Function, I find that the control is flowing through that Public function on cliking the Send button. But the passed value is not displayed. And, I know that is not the standard way to do that. Any sample script for help? Thanks.

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  • How to Access value of dynamically created control?

    - by sharad
    i have asp.net web application in which i need to create form dynamically depend upon table which user selected.however,i created form dynamically with it's control like text box,drop downlist etc. but not able to access those controls at particular button click event. My form scenario is like this: i have dropdownlist in which i display list of tables,button control say display( on click event which i redirect page with some addition in querystring so that at page init it dynamically genrate controls) and another button control which used to access this controls value say Submit and store in database. This is my code: At Display button Click event: Response.Redirect("dynamic_main.aspx?mode=edit&tablename=" + CMBTableList.SelectedItem.ToString()); This is code For page.Init level if (Request.QueryString["mode"] != null) { if (Request.QueryString["mode"].ToString() == "edit") { Session["tablename"] = Request.QueryString["tablename"].ToString(); // if (Session["tablename"].ToString() == CMBTableList.SelectedItem.ToString()) //{ createcontrol(Session["tablename"].ToString()); // } } } i have used createcontrol() which genrate controls Code For Submit Button: string[] contid=controlid.Value.Split(','); MasterPage ctl00 = FindControl("ctl00") as MasterPage; ContentPlaceHolder cplacehld = ctl00.FindControl("ContentPlaceHolder2") as ContentPlaceHolder; Panel panel1 = cplacehld.FindControl("plnall") as Panel; Table tabl1 = panel1.FindControl("id1") as Table; foreach (string sin in contid) { string splitcvalu = sin.Split('_')[0].ToString(); ControlsAccess contaccess = new ControlsAccess(); if (splitcvalu.ToString() == "txt") { TextBox txt = (TextBox)tabl1.FindControl(sin.ToString()); //TextBox txt = cplacehld.FindControl(sin.ToString()) as TextBox; val = txt.ID; } else { DropDownList DDL = cplacehld.FindControl(sin.ToString()) as DropDownList; } } Here i am no able to access this textbox or drop downlist.i am getting id of particular control from hidden field controlid in which i have stored it during genrating controls. i have used findcontrol() it works in case of finding masterpage,contentplaceholder,table etc. but in case of textbox or other control it doesnt work it shows it returns null. Anyone can help me. Thanks

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  • How can I ignore an http request without clearing the browser?

    - by Timid Developer
    To prevent duplicate requests (i.e. pressing F5 right after clicking a command button), I've setup my page base class to ignore the request if it's detected as a duplicate. When I say 'ignore' I mean Response.End() Now I thought I've seen this work before, where there's an issue, I just Response.End() and the users page just does nothing. I don't know the exact circumstance in which this worked, but I'm unable to repeat it now. Now when I call Response.End(), I just get an empty browser. More specifically, I get this html. <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META http-equiv=Content-Type content="text/html; charset=utf-8"></HEAD> <BODY></BODY></HTML> I setup the following test app to confirm the problem is not elsewhere in my app. Here it is: Add the following to an aspx form <asp:Label ID="lbl" Text="0" runat="server" /><br /> <asp:Button ID="btnAdd1" Text="Add 1" runat="server" /><br /> <asp:Button ID="btnAdd2" Text="Add 2" runat="server" /><br /> <asp:Button ID="btnAdd3" Text="Add 3" runat="server" /><br /> And here's the code behind file using System; namespace TestDupRequestCancellation { public partial class _Default : System.Web.UI.Page { protected void Page_Init(object sender, EventArgs e) { btnAdd1.Click += btnAdd1_Click; btnAdd2.Click += btnAdd2_Click; btnAdd3.Click += btnAdd3_Click; } protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) CurrentValue = 0; else if (Int32.Parse(lbl.Text) != CurrentValue) Response.End(); } protected void Page_PreRender(object sender, EventArgs e) { lbl.Text = CurrentValue.ToString(); } protected int CurrentValue { get { return Int32.Parse(Session["CurrentValue"].ToString()); } set { Session["CurrentValue"] = value.ToString(); } } void btnAdd3_Click(object sender, EventArgs e) { CurrentValue += 3; } void btnAdd2_Click(object sender, EventArgs e) { CurrentValue += 2; } void btnAdd1_Click(object sender, EventArgs e) { CurrentValue += 1; } } } When you load the page, clicking any button does what is expected, but if you press F5 at any time after pressing one of the buttons, it will detect it as a duplicate request and call Response.End() which promptly ends the task. Which leaves the user with an empty browser. Is there anyway to leave the user with the page as it was, so they can just click a button? Also; please note that this code is the simplest code I could come up with to demonstrate my problem. It's not meant to demonstrate how to check for dup requests.

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  • notications pop up in user side

    - by user2931015
    i try to show notification as a pop up. like when admin login and through his account he send notification to user i add this html in admin form like this.. <asp:Button ID="notic" runat="server" Text="Send" onclick="Button1_Click" /> <br /> <input class="add_message" type="text" value="type your message" name="add_message"></input> <input type="button" value="add message" onclick="sNotify.addToQueue($('.add_message').attr('value'))"/> Then when admin click on button then notification send to users account like when any user login then he/she able to see pop ups in user form I call this java script in page load like this .. ClientScript.RegisterStartupScript(GetType(), "Javascript", "javascript:sNotify.addToQueue($('.add_message').attr('value'))();", true); it works like when i login as a admin and click on button then notification in his own page .. but i want to show this notifications in user form. so how to solve it?

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  • How to figure out which key was pressed on a BlackBerry

    - by Skrud
    What I want: To know when the user has pressed the button that has the number '2' on it, for example. I don't care whether "Alt" or "Shift" has been pressed. The user has pressed a button, and I want to evaluate whether this button has '2' printed on it. Naturally, if I switch devices this key will change. On a Bold 9700/9500 this is the 'E' key. On a Pearl, this is the 'T'/'Y' key. I've managed to get this working in what appears to be a roundabout way, by looking up the keycode of the '2' character with the ALT button enabled and using Keypad.key() to get the actual button: // figure out which key the '2' is on: final int BUTTON_2_KEY = Keypad.key(KeypadUtil.getKeyCode('2', KeypadListener.STATUS_ALT, KeypadUtil.MODE_EN_LOCALE)); protected boolean keyDown(int keycode, int time) { int key = Keypad.key(keycode); if ( key == BUTTON_2_KEY ) { // do something return true; } return super.keyDown(keycode,time); } I can't help but wonder if there is a better way to do this. I've looked at the constants defined in KeypadListener and Keypad but I can't find any constants mapped to the actual buttons on the device. Would any more experienced BlackBerry devs care to lend a helping hand? Thanks!

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  • How can I prevent a page to jump to top position after failed validation?

    - by Slauma
    I have a simple aspx page with a few TextBoxes and a submit button. Some fields are required and below the button is a ValidationSummary. The complete form is larger than screen height so one has to scroll down to reach the submit button. If I don't fill all required fields and click on submit validation fails as expected and the validation summary displays some info messages below the button. Validation happens on the client and no postback occurs. So this all works as wished. But disturbing is that the page moves ("jumps") to top position when I click on the submit button. To see the validation summary one has to move down the page again. I've tried to set the ShowSummary property to false (which doesn't make much sense): The validation still works (no postback) but in this case the page does not move to top position. So the problem seems to depend on rendering the validation texts. Is there a way to prevent this page jump? Thank you in advance!

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  • Android Java ArrayList inserting element not working

    - by DavidNg
    I have a simple Android program with one button and one textview. When the button is clicked, a number is inserted in in an ArrayList. However, it does not work. If changing to add, it works fine. package test_ad.com; import java.util.ArrayList; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.TextView; public class Test_adActivity extends Activity { ArrayList<Integer> al = new ArrayList<Integer>(); Button myB; public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); myB = (Button) findViewById(R.id.button1); myTV = (TextView) findViewById(R.id.textView1); myB.setOnClickListener(new OnClickListener() { public void onClick(View arg0) { al.set(i,10*i);//insert an Integer at index i, but not working i++; if (i == 5) myTV.setText(al.toString()); } }); } }

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  • android program crashing (new to platform)

    - by mutio
    So it is my first real Android program (!hello world), but i do have java experience.The program compiles fine, but on running it crashes as soon as it opens (tried debugging, but it crashes before it hits my breakpoint). Was looking for any advice from anyone who is more experienced with android. package org.me.tipcalculator; import android.app.Activity; import android.os.Bundle; import android.widget.TextView; import android.view.View; import android.widget.Button; import android.widget.EditText; import java.text.NumberFormat; import android.util.Log; public class TipCalculator extends Activity { public static final String tag = "TipCalculator"; /** Called when the activity is first created. */ @Override public void onCreate(Bundle icicle) { super.onCreate(icicle); setContentView(R.layout.main); final EditText mealpricefield = (EditText) findViewById(R.id.mealprice); final TextView answerfield = (TextView) findViewById(R.id.answer); final Button button = (Button) findViewById(R.id.calculate); button.setOnClickListener(new Button.OnClickListener() { public void onClick(View v) { try { Log.i(tag, "onClick invoked."); String mealprice = mealpricefield.getText().toString(); Log.i(tag, "mealprice is [" + mealprice + "]"); String answer = ""; if (mealprice.indexOf("$") == -1) { mealprice = "$" + mealprice; } float fmp = 0.0F; NumberFormat nf = java.text.NumberFormat.getCurrencyInstance(); fmp = nf.parse(mealprice).floatValue(); fmp *= 1.2; Log.i(tag, "Total Meal Price (unformatted) is [" + fmp + "]"); answer = "Full Price, including 20% Tip: " + nf.format(fmp); answerfield.setText(answer); Log.i(tag, "onClick Complete"); } catch(java.text.ParseException pe){ Log.i (tag ,"Parse exception caught"); answerfield.setText("Failed to parse amount?"); } catch(Exception e){ Log.e (tag ,"Failed to Calculate Tip:" + e.getMessage()); e.printStackTrace(); answerfield.setText(e.getMessage()); } } } ); } Just in case it helps heres the xml <?xml version="1.0" encoding="UTF-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Android Tip Calculator"/> <EditText android:id="@+id/mealprice" android:layout_width="fill_parent" android:layout_height="wrap_content" android:autoText="true"/> <Button android:id="@+id/calculate" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Calculate Tip"/> <TextView android:id= "@+id/answer" android:layout_width="fill_parent" android:layout_height="wrap_content" android:text=""/> </LinearLayout>

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  • How to show content from contentPlaceholder inline

    - by H4mm3rHead
    Hi, I have a page where i in my masterpage have a toolbar with a "Home" button to the far left. This button is not in a contentplaceholder but on the page. I want to have the opportunity for derived pages to add their own controls or whatever to the toolbar to be whown after the "home" button. But how to do this? I have tried to put in a content placeholder, but it seems that i cannot get it to show inline with the other stuff, it breaks and the content of the contentplaceholder is shown below the button instead. anyone know how to solve this? /Brian

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  • Extjs 4.1 How to call controller action method from form

    - by Omar Faruq
    Extjs 4.1 How to call controller action method from form which is already use in a button action but i want this method reuse from a form field but do not how i can do? // here is my controller code init: function() { this.control({ 'itemsgrid': { removeitem: this.removeUser }, 'salewindow button[action=resetAll]': { click: this.resertform }, 'salewindow button[action=saveOrder]' : { click : this.onsaveOrder }, 'salewindow button[action=PDF]' : { click : this. pdfreport } }); }, resertform : function(button){ var store = Ext.data.StoreManager.get('Items'); store.destroy(); var vatstore = Ext.data.StoreManager.get('Vats'); vatstore.reload(); var rebatestore = Ext.data.StoreManager.get('Rebates'); rebatestore.reload(); Ext.getCmp('calculation-form').getForm().reset(); Ext.getCmp('itemform2').getForm().reset(); Ext.getCmp('itemsgrid').subtotalquantity(p=0); store.reload(); var co=store.getCount(); console.log(co); Ext.getCmp('customerID').setValue('0'); var a = Ext.getCmp('customerID').getValue(); Ext.getCmp('itemform2').customerinfo(a); } //and here is my from field listener { xtype : 'textfield', name : 'BranchId', fieldLabel : 'Branch Id', allowNegative : false, id : 'branchid', value : '1', onBlur: function(){ restoreItem();// i want call this method from here whis is stay in controller } }

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  • Question about the lifecycle of a simple Android application

    - by jul
    Hi, I've got a simple application with 3 activities: -the first contains a search box which calls a web service and show the results (restaurants) below in a listview -when a restaurant is clicked another activity is started showing the description of the restaurant and a button "show map" -when the button "show map" is clicked, guess what, the map is shown in a third activity. All the data is loaded in the first activity by a web service (restaurant descriptions and coordinates), and data required by each activity is passed in a bundle using "intent.putExtra". Now everything seems to run smoothly when clicking on the back button (eg. clicking on the back button from the map resumes the "restaurant description" activity with all data set properly), while I haven't done anything about the lifecycle yet. Why? Are all variables saved automatically? Should I use onSaveInstanceState() and onRestoreInstanceState() anyway? Thanks Jul

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  • JavaScript cookie value can't be retrieved in Django

    - by Boris Rusev
    I am trying to build a web site in both English and Bulgarian using the Django framework. My idea is the user should click on a button, the page will reload and the language will be changed. This is how I am trying to do it: In my html I hava a the button tag <button id='btn' onclick="changeLanguage();" type="button"> ... </button> An excerpt from cookies.js: function changeLanguage() { if (getCookie('language') == 'EN') { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'BG'); } else { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'EN'); } } function setCookie(sName, sValue, oExpires, sPath, sDomain, bSecure) { var sCookie = sName + "=" + encodeURIComponent(sValue); if (oExpires) { sCookie += "; expires=" + oExpires.toGMTString(); } if (sPath) { sCookie += "; path=" + sPath; } if (sDomain) { sCookie += "; domain=" + sDomain; } if (bSecure) { sCookie += "; secure"; } document.cookie = sCookie; } And in my views.py file this is the situation @base def index(request): if request.session['language'] == 'EN': return """<b>%s</b>""" % "Home" else request.session['language'] == 'BG': return """<b>%s</b>""" % "??????" So I know that my JS changes the value of the language cookie but I think Django doesn't get that. On the other hand when I set and get the cookie in my Python code again the cookie is set. My question is whether there is a way to make JS and Django work together - JavaScript sets the cookie value and Python only reads it when asked and takes adequate actions? Thank you.

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