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  • Create bootable partition from image

    - by Carson Darling
    I have a Macbook Pro with a dead CD drive. I don't have easy access to a replacement drive. I'm trying to install Ubuntu, and I can't get the MBP to recognize a USB stick as a bootable media (I believe MBP's have issues with booting from USB in some cases). Is it possible to take a disk image and write it to a partition on the HDD so that I can then boot from that partition and then install the OS onto a third partition? Partition layout: 150GB OS X 50GB Ubuntu destination 5GB Ubuntu install image

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  • Which layer should create DataContext?

    - by Kevin
    I have a problem to decide which layer in my system should create DataContext. I have read a book, saying that if do not pass the same DataContext object for all the database updates, it will sometimes get an exception thrown from the DataContext. That's why i initially create new instance of DataContext in business layer, and pass it into data access layer. So that the same datacontext is used for all the updates. But this lead to one design problem, if i wanna change my DAL to Non-LinqToSQL in future, i need to re-write the code in business layer as well. Please give me some advice on this. Thanks. Example code 'Business Layer Public Sub SaveData(name As String) Using ts AS New TransactionScope() Using db As New MyDataContext() DAL.Insert(db,name) DAL.Insert(db,name) End Using ts.Complete() End Using End Sub 'Data Access Layer Public Sub Insert(db as MyDataContext,name As string) db.TableAInsert(name) End Sub

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  • Programatically Create Controller in Rails

    - by Trey Bean
    What's the best way to dynamically create a controller in Rails. I've got a class that needs to generate a bunch of controller that inherit from it. I could just create a bunch of files in /app/controllers, but they'd all be basically empty files. There's got to be a way to generate these classes dynamically and have them treated like other controllers in Rails, e.g. reloaded correctly in dev mode. I tried putting this in a config/initializer: FL.contact_types.each do |contact_type| controller_name = "#{contact_type.pluralize}Controller" Object.const_set(controller_name.to_sym, Class.new(ContactsController)) unless Object.const_defined?(controller_name.to_sym) end This worked, but I run into the dependency/reload problem and get “A copy of AuthenticatedSystem has been removed from the module tree but is still active” since the ContactsController inherits from ApplicationController which includes AuthenticatedSystem. Is creating a bunch of empty files really the best solution?

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  • [Openfiler] How to create new ftp users?

    - by chrisling106
    Hi there, There's only a default ftp user assigned in openfiler ftp service - openfiler/password. I've been pulling my hairs out for trying to add users to the ftp server but without any luck. I have turned on the local LDAP server within Openfiler and add users there and still no luck. It's for production, so at the end of the day I might have to stick with the default user 'openfiler' and just change its password! Any helps appreciated.

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  • CSS menu broken in Firefox (display:table-cell;)

    - by roman m
    HTML: <td align="center" width="100%"> <a class="Forum_ib_moderate" href="Default.aspx" title="Moderate"></a> <a class="Forum_ib_admin" href="Default.aspx" title="Admin"></a> ... CSS: A.Forum_ib_moderate:link, A.Forum_ib_moderate:visited, A.Forum_ib_moderate:active, A.Forum_ib_moderate:hover { background-image: url(images/ib_moderate.png); background-repeat: no-repeat; background-position: center; padding-left: 2px; padding-right: 2px; padding-top: 8px; padding-bottom: 0px; height: 35px; width: 35px; display:table-cell; } A.Forum_ib_admin:hover { background-image: url(images/ib_admin_hover.png); } the menu looks just fine in IE, shows up vertical in Firefox. If i turn off "display:table-cell;" style in Firebug and then turn it back on, it fixes that menu node. any ideas? p.s.: i don't want to mess with the menu itself, since it's a part of a DNN Forum 4.4.3. I'd rather fix the CSS to make it show correctly.

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  • [VBA] Create a recurrent event in Outlook

    - by CFP
    Hello everyone! I'm trying to create annual, all-day events with VBA in outlook 2007. I use the following code, but no matter which conbination of Start, StartDate, End, etc I use, it won't create a whole-day event. Either it gives it default start/end times, or it remove the all-day attribute... Dim Birthday As Date 'Get the birthday '... Dim BDay As AppointmentItem Dim Pattern As Outlook.RecurrencePattern Set BDay = Application.CreateItem(olAppointmentItem) Set Pattern = BDay.GetRecurrencePattern Pattern.RecurrenceType = olRecursYearly Pattern.DayOfMonth = Day(Birthday) Pattern.MonthOfYear = Month(Birthday) Pattern.PatternStartDate = Birthday Pattern.NoEndDate = True BDay.AllDayEvent = True BDay.Subject = Contact.FullName BDay.Save When created directly in outlook, entries start on the birth day and end 24 hours later. Yet trying to set Start and End this way results in errors. Plus, entries created outlook have no start/end time in the recurrence pattern (well, they are all-day entries...) Ideas, anybody? Thanks!

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  • Django's post_save signal behaves weirdly with models using multi-table inheritance

    - by hekevintran
    Django's post_save signal behaves weirdly with models using multi-table inheritance I am noticing an odd behavior in the way Django's post_save signal works when using a model that has multi-table inheritance. I have these two models: class Animal(models.Model): category = models.CharField(max_length=20) class Dog(Animal): color = models.CharField(max_length=10) I have a post save callback called echo_category: def echo_category(sender, **kwargs): print "category: '%s'" % kwargs['instance'].category post_save.connect(echo_category, sender=Dog) I have this fixture: [ { "pk": 1, "model": "animal.animal", "fields": { "category": "omnivore" } }, { "pk": 1, "model": "animal.dog", "fields": { "color": "brown" } } ] In every part of the program except for in the post_save callback the following is true: from animal.models import Dog Dog.objects.get(pk=1).category == u'omnivore' # True When I run syncdb and the fixture is installed, the echo_category function is run. The output from syncdb is: $ python manage.py syncdb --noinput Installing json fixture 'initial_data' from '~/my_proj/animal/fixtures'. category: '' Installed 2 object(s) from 1 fixture(s) The weird thing here is that the dog object's category attribute is an empty string. Why is it not 'omnivore' like it is everywhere else? As a temporary (hopefully) workaround I reload the object from the database in the post_save callback: def echo_category(sender, **kwargs): instance = kwargs['instance'] instance = sender.objects.get(pk=instance.pk) print "category: '%s'" % instance.category post_save.connect(echo_category, sender=Dog) This works but it is not something I like because I must remember to do it when the model inherits from another model and it must hit the database again. The other weird thing is that I must do instance.pk to get the primary key. The normal 'id' attribute does not work (I cannot use instance.id). I do not know why this is. Maybe this is related to the reason why the category attribute is not doing the right thing?

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  • How to create a rounded title border in Java Swing

    - by Stephane Grenier
    I do understand that to create a title border, you do something like: BorderFactory.createTitledBorder(" Your Title "); However this creates a rectangle border whereas I need a rectangle with curved corners. Now from what I understand you can create your own custom border by: class CustomBorder implements Border { ... } The problem is that I'm not sure how to write the code that overrides the method: public void paintBorder(Component component, Graphics g, int x, int y, int width, int height) Or better yet, is there a way to do it without implementing your own Border class? And if not, how would you write that custom Title Border? I'm ok with drawing a rectangle with rounded corners, but how do you do it so that there's space for the label too?

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  • How do I create a check constraint?

    - by Zack Peterson
    Please imagine this small database... Diagram Tables Volunteer Event Shift EventVolunteer ========= ===== ===== ============== Id Id Id EventId Name Name EventId VolunteerId Email Location VolunteerId Phone Day Description Comment Description Start End Associations Volunteers may sign up for multiple events. Events may be staffed by multiple volunteers. An event may have multiple shifts. A shift belongs to only a single event. A shift may be staffed by only a single volunteer. A volunteer may staff multiple shifts. Check Constraints Can I create a check constraint to enforce that no shift is staffed by a volunteer that's not signed up for that shift's event? Can I create a check constraint to enforce that two overlapping shifts are never staffed by the same volunteer?

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  • Comparing two date ranges within the same table

    - by Danny Herran
    I have a table with sales per store as follows: SQL> select * from sales; ID ID_STORE DATE TOTAL ---------- -------- ---------- -------------------------------------------------- 1 1 2010-01-01 500.00 2 1 2010-01-02 185.00 3 1 2010-01-03 135.00 4 1 2009-01-01 165.00 5 1 2009-01-02 175.00 6 5 2010-01-01 130.00 7 5 2010-01-02 135.00 8 5 2010-01-03 130.00 9 6 2010-01-01 100.00 10 6 2010-01-02 12.00 11 6 2010-01-03 85.00 12 6 2009-01-01 135.00 13 6 2009-01-02 400.00 14 6 2009-01-07 21.00 15 6 2009-01-08 45.00 16 8 2009-01-09 123.00 17 8 2009-01-10 581.00 17 rows selected. What I need to do is to compare two date ranges within that table. Lets say I need to know the differences in sales between 01 Jan 2009 to 10 Jan 2009 AGAINST 01 Jan 2010 to 10 Jan 2010. I'd like to build a query that returns something like this: ID_STORE_A DATE_A TOTAL_A ID_STORE_B DATE_B TOTAL_B ---------- ---------- --------- ---------- ---------- ------------------- 1 2010-01-01 500.00 1 2009-01-01 165.00 1 2010-01-02 185.00 1 2009-01-02 175.00 1 2010-01-03 135.00 1 NULL NULL 5 2010-01-01 130.00 5 NULL NULL 5 2010-01-02 135.00 5 NULL NULL 5 2010-01-03 130.00 5 NULL NULL 6 2010-01-01 100.00 6 2009-01-01 135.00 6 2010-01-02 12.00 6 2009-01-02 400.00 6 2010-01-03 85.00 6 NULL NULL 6 NULL NULL 6 2009-01-07 21.00 6 NULL NULL 6 2009-01-08 45.00 6 NULL NULL 8 2009-01-09 123.00 6 NULL NULL 8 2009-01-10 581.00 So, even if there are no sales in one range or another, it should just fill the empty space with NULL. So far, I've come up with this quick query, but I the "dates" from sales to sales2 sometimes are different in each row: SELECT sales.*, sales2.* FROM sales LEFT JOIN sales AS sales2 ON (sales.id_store=sales2.id_store) WHERE sales.date >= '2010-01-01' AND sales.date <= '2010-01-10' AND sales2.date >= '2009-01-01' AND sales2.date <= '2009-01-10' ORDER BY sales.id_store ASC, sales.date ASC, sales2.date ASC What am I missing?

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  • HAProxy create custom routing logic

    - by kumar
    Is it possible to write a custom routing logic for HAProxy. I need it in such a way that each application server is allocated a max on 1000 TCP connections then only should the loadbalancer try to route next TCP request to next application server. if not with HAProxy if there any other Load balancer that can do it please let me know. Can persistence be applied to TCP connections. There will no HTTP request. thanks

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  • Adding Column While Selecting Table in SQl

    - by kmkperumal
    My First Table is ProjectCustomFields CustomFieldId ProjectId CustomFieldName CustomFieldRequired CustomFieldDataType 69 1 User Name 1 0 72 1 City 1 0 74 1 Email 0 0 82 1 Salary 1 2 My Second Table is ProjectCustomFieldValues CustomFieldValueId ProjectId CustomFieldId CustomFieldValue RecordId 35 1 69 kaliya 1 36 1 72 Bangalore 1 37 1 74 [email protected] 1 41 1 69 Yohesh 2 42 1 72 Delhi 2 43 1 74 2 50 1 69 sss 3 51 1 72 Delhi 3 52 1 74 [email protected] 3 57 1 69 Sunil 4 58 1 72 Mumbai 4 59 1 74 [email protected] 4 60 1 82 20000 4 I tried Below Query Select M.CustomFieldName,N.CustomFieldValue,N.RecordId From (Select G.CustomFieldName,H.RecordId From (Select CustomFieldName From ProjectCustomFields Where ProjectId=1) G Cross Join (Select Distinct RecordId From ProjectCustomFieldValues) H) M Left Join (Select CustFiled.CustomFieldName,CustValue.CustomFieldValue,CustValue.RecordId From ProjectCustomFieldValues CustValue Left Join ProjectCustomFields CustFiled On CustValue.CustomFieldId=CustFiled.CustomFieldId Where CustValue.AuctionId=1 ) N On M.CustomFieldName=N.CustomFieldName And M.RecordId=N.RecordId But I got the result below #CustomFieldName# CustomFieldValue RecordId User Name kaliya 1 City Bangalore 1 Email [email protected] 1 Salary NULL **NULL** User Name Yohesh 2 City Delhi 2 Email 2 Salary NULL **NULL** User Name sss 3 City Delhi 3 Email [email protected] 3 Salary NULL **NULL** User Name NULL **NULL** City NULL **NULL** Email NULL **NULL** Salary NULL **NULL** User Name Sunil 4 City Mumbai 4 Email [email protected] 4 Salary 20000 4 But Expected Result is CustomFieldName CustomFieldValue RecordId User Name kaliya 1 City Bangalore 1 Email [email protected] 1 Salary NULL **1** User Name Yohesh 2 City Delhi 2 Email 2 Salary NULL **2** User Name sss 3 City Delhi 3 Email [email protected] 3 Salary NULL **3** User Name Sunil 4 City Mumbai 4 Email [email protected] 4 Salary 20000 4 Please guide me some one,I tried so much but i got null value in recordId,So I need same recordId above one..

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  • how to update Sr. No. COLUMN after removing a TR from TABLE

    - by user251336
    i have a table like <table> <tr> <td>Sr. No.</td> <td> Name</td> <td>$nbsp;</td> </tr> <tr> <td>1</td> <td>abc</td> <td>remove button</td> </tr> <tr> <td>2</td> <td>xyz</td> <td>remove button</td> </tr> <tr> <td>3</td> <td>def</td> <td>remove button</td> </tr> onclick of ' remove button ' i send ajax request & after successful response i remove the respective TR using $('#id_of_tr').remove();. till here everything goes fine but now i want to update Sr. No.s of each row. Because Initially order is 1 2 3 , when i remove second row then it becames 1 3 which i want to update it to 1 2. I hope this would help.

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  • Java Swing Table questions

    - by Dalton Conley
    Hey guys, working on an event calendar. I'm having some trouble getting my column heads to display.. here is the code private JTable calendarTable; private DefaultTableModel calendarTableModel; final private String [] days = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"}; ////////////////////////////////////////////////////////////////////// /* Setup the actual calendar table */ calendarTableModel = new DefaultTableModel() { public boolean isCellEditable(int row, int col){ return false; } }; // setup columns for(int i = 0; i < 7; i++) calendarTableModel.addColumn(days[i]); calendarTable = new JTable(calendarTableModel); calendarTable.getTableHeader().setResizingAllowed(false); calendarTable.getTableHeader().setReorderingAllowed(false); calendarTable.setColumnSelectionAllowed(true); calendarTable.setRowSelectionAllowed(true); calendarTable.setSelectionMode(ListSelectionModel.SINGLE_SELECTION); calendarTable.setRowHeight(105); calendarTableModel.setColumnCount(7); calendarTableModel.setRowCount(6); Also, Im sort of new with tables.. how can I make the rowHeight split between the max size of the table?

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  • Create date efficiently

    - by Dave Jarvis
    On Pavel's page is the following function: CREATE OR REPLACE FUNCTION makedate(year int, dayofyear int) RETURNS date AS $$ SELECT (date '0001-01-01' + ($1 - 1) * interval '1 year' + ($2 - 1) * interval '1 day'):: date $$ LANGUAGE sql; I have the following code: makedate(y.year,1) What is the fastest way in PostgreSQL to create a date for January 1st of a given year? Pavel's function would lead me to believe it is: date '0001-01-01' + y.year * interval '1 year' + interval '1 day'; My thought would be more like: to_date( y.year||'-1-1', 'YYYY-MM-DD'); Am looking for the fastest way using PostgreSQL 8.4. (The query that uses the date function can select between 100,000 and 1 million records, so it needs speed.) Thank you!

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  • Create Oracle Cursor

    - by Mohammad
    Hi, I create a cursor like this: SQL> CREATE OR REPLACE PROCEDURE Update_STUD_FinAid ( AIDY_CODE IN VARCHAR2 ) IS 2 CURSOR PublicationC IS 3 SELECT SGBSTDN_USER_ID from SGBSTDN 4 WHERE SGBSTDN_TERM_CODE_EFF ='201030'; 5 BEGIN 6 close PublicationC; 7 8 OPEN PublicationC; 9 10 FOR PublicationR IN PublicationC 11 LOOP 12 DBMS_OUTPUT.PUT_LINE( PublicationR.SGBSTDN_USER_ID ); 13 END LOOP; 14 15 close PublicationC; 16 17 END; 18 / Procedure created. And then when I run the Procedure then I get this error: ERROR at line 1: ORA-06512: at line 2 Please advise. Thanks

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  • How to create an "hybrid" usb stick?

    - by rdesign
    Hey guys, I was wondering how to make an hybrid usb stick. That means a usb stick that runs under mac and windows and displays specific content. Example: Plug in on win : index.html opens. Mac os X files are invisible. Plug in on mac: indexMac.html opens. Win files are invisible. I know that every usb stick can be read by both platforms. The Apple Mac os X CD is something which inspired me. thanks a lot.

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  • Why can't I create e-mails on CPanel ?

    - by samantha
    Hello, I have a nasty problem creating e-mails on a cpanel account, the creation form doesn't work (clicking on the buttons does nothing) and the sourcecode of the page has a weird http://petlieutenants.com/css/article1.php in it... The quota for the account is normal, all the other accounts are working fine. What can possibly be causing this ? Thanks for your ideas !

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