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  • PHP: parse $_FILES[] data in multidimesional array

    - by superUntitled
    Example form here: http://jsfiddle.net/superuntitled/uaTtx/1/ I have a form that allows for dynamic duplication of the form fields. The form allows for file uploads and text input, so the data is sent in both $_POST and $_FILES arrays. The the initial set of inputs look like this: <input type="text" name="question[1][text]" /> <input type="file" name="question[1][file]" /> <input type="text" class="a" name="answer[1][text][]" /> <input type="file" name="answer[1][file][]" /> When duplicated the fields are incremented, they look like this: <input type="text" name="question[2][text]" /> <input type="file" name="question[2][file]" /> <input type="text" class="a" name="answer[2][text][]" /> <input type="file" name="answer[2][file][]" /> To complicate matters, the "answer" form fields can also be duplicated (thus the [] at the end of the 'answer' name array. How can I parse the posted $_FILES array? I have tried something like this: foreach ($_FILES['question'] as $p_num) { echo $p_num['file']['name']; foreach ($_FILES['answer'] as $a_num) { echo $a_num['file']['name']; } } but I get an "Undefined index: file... " error. How can I parse out the posted values.

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  • Reading and writing to files simultaneously?

    - by vipersnake005
    Moved the question here. Suppose, I want to store 1,000,000,000 integers and cannot use my memory. I would use a file(which can easily handle so much data ). How can I let it read and write and the same time. Using fstream file("file.txt', ios::out | ios::in ); doesn't create a file, in the first place. But supposing the file exists, I am unable to use to do reading and writing simultaneously. WHat I mean is this : Let the contents of the file be 111111 Then if I run : - #include <fstream> #include <iostream> using namespace std; int main() { fstream file("file.txt",ios:in|ios::out); char x; while( file>>x) { file<<'0'; } return 0; } Shouldn't the file's contents now be 101010 ? Read one character and then overwrite the next one with 0 ? Or incase the entire contents were read at once into some buffer, should there not be atleast one 0 in the file ? 1111110 ? But the contents remain unaltered. Please explain. Thank you.

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  • Windows 7: Can't see ISO file in C:\

    - by cbp
    I used DVD shrink to create an ISO file and saved it into C:\ The ISO file is visible with some programs but not with others. The file is not hidden as far as I am aware. But it cannot be seen by Windows Explorer, DVD Decrypter or a bunch of other programs. If I search for the file using Windows 7's Start Menu search tool, I can see the file and I can right click and select Properties. The Properties window appears OK, but if I try to change tabs on the property window, I receive an error message as though the file is not there. DVD Shrink can still open the file OK. I can also find the file using Agent Ransack (a file searching tool), but then I cannot open it. What gives?

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  • Permissions won't cascade more than 1 level

    - by Jovin_
    Running Windows Small Business Server 2011 I have a file structure with a lot of sub folders (sometimes 5-6 levels deep). I have created access groups to grant access to my users, and also deny groups to deny access to others. X Access & X Deny. These allow or deny access to a mapped network drive X: On the server I put in the groups with Full Control Allow for X Access and Full Control Deny for X Deny, I also tick the box "Apple these permissions to objects and/or containers within this container only" and have ensured that "Apply to:" is "This folder, subfolders and files". But for some reason the permissions will only apply to the next level of folders & files. ex. structure: X: Folder 1 Folder 1a Folder 2 Folder 2a If I apply the permissions to X: it'll only go to Folder 1 & 2, not 1a and 2a, I then need to manually apply the permissions to these too. Is this working as intended or am I doing something wrong?

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  • optimizing file share performance on Win2k8?

    - by Kirk Marple
    We have a case where we're accessing a RAID array (drive E:) on a Windows Server 2008 SP2 x86 box. (Recently installed, nothing other than SQL Server 2005 on the server.) In one scenario, when directly accessing it (E:\folder\file.xxx) we get 45MBps throughput to a video file. If we access the same file on the same array, but through UNC path (\server\folder\file.xxx) we get about 23MBps throughput with the exact same test. Obviously the second test is going through more layers of the stack, but that's a major performance hit. What tuning should we be looking at for making the UNC path be closer in performance to the direct access case? Thanks, Kirk (corrected: it is CIFS not SMB, but generalized title to 'file share'.) (additional info: this happens during the read from a single file, not an issue across multiple connections. the file is on the local machine, but exposed via file share. so client and file server are both same Windows 2008 server.)

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  • undelete big files - mission impossible?

    - by johnrembo
    Hi, I've accidentaly deleted outlook.pst (6.7GB) file, while there was only 400MB free space left on primary NTFS partition (winxp). I've tried several recovery tools to get this file back. "Ontrack Easy Recovery Pro" found 0 pst files (complete scan mode), while "Recover My Files" in sector scan mode found 5 pst's, but 4 of them of sizes from 3 to 28 KB, while the 5th one - 1Gb. I've managed to succesfuly recover 1Gb pst file, which was 1 year old copy (the one used after the latest windows reinstall). Now, I'm frustrated and confused Why 1 year old file was succesfuly recovered if there were only 400MB left on primary partition? Where's 6.7GB file gone? I did some reading (i.e. here), and it seems that there's almost no probability to retrieve the file I'm looking for, but wait - none of recovery tools i've used found zero-sized pst file, moreover - if due to fragmentation a file might be corrupted - we could use scanpst.exe to fix some errors and survive with 10 or 100 emails missing - whatever. Could you please recommend some more sophisticated recovery tools for this particular task? Appretiate your help - thanks in advance

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  • Is it possible to download extremely large files intelligently or in parts via SSH from Linux to Windows?

    - by Andrew
    I have a ~35 GB file on a remote Linux Ubuntu server. Locally, I am running Windows XP, so I am connecting to the remote Linux server using SSH (specifically, I am using a Windows program called SSH Secure Shell Client version 3.3.2). Although my broadband internet connection is quite good, my download of the large file often fails with a Connection Lost error message. I am not sure, but I think that it fails because perhaps my internet connection goes out for a second or two every several hours. Since the file is so large, downloading it may take 4.5 to 5 hours, and perhaps the internet connection goes out for a second or two during that long time. I think this because I have successfully downloaded files of this size using the same internet connection and the same SSH software on the same computer. In other words, sometimes I get lucky and the download finishes before the internet connection drops for a second. Is there any way that I can download the file in an intelligent way -- whereby the operating system or software "knows" where it left off and can resume from the last point if a break in the internet connection occurs? Perhaps it is possible to download the file in sections? Although I do not know if I can conveniently split my file into multiple files -- I think this would be very difficult, since the file is binary and is not human-readable. As it is now, if the entire ~35 GB file download doesn't finish before the break in the connection, then I have to start the download over and overwrite the ~5-20 GB chunk that was downloaded locally so far. Do you have any advice? Thanks.

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  • Command line switching

    - by Larry
    I have read through some suggestions but I am just not technical enough to get this I think. I am a CAD designer and each file has 5 files associated with it. I have 3 sets of 5 files, and each set needs to go into its own zip file, placed on a separate server. For example: "C:\Program Files\7-zip\7z.exe" a file1.zip "O:\server2\map files\BC\BC.d*"-0 "C:\Program Files\7-zip\7z.exe" a file2.zip "O:\server2\map files\BC\ON.d*"-0 "C:\Program Files\7-zip\7z.exe" a file3.zip "O:\server2\map files\BC\AB.d*"-0 and I am in directory "S:\server\map files\provinces" (for example). These lines run within an existing batch file and by the time it reaches the 3 lines above, it's in the S: directory sample above. So it's looking on my pc for the 7-zip program, creating 3 zip file names which it does, but places those zip files on a separate server which it doesn't and the first zip file also includes all the other 10 files, the second zip file the same plus the first zip file, and the third the same with the other two zip files making me think the code isn't recognizing the part after file1.zip where I am trying to tell it what files to include and where to place the zip files. Ultimately, I want to either have the system create a new zip file if the old one was deleted, or copy the new files into the existing zip and overwrite any older files, and for these zip files to be placed in a separate location which is where we share our files with other personnel from within our company. The S: drive is for all originals, and O: is for sharing. Is there a list of all switching options with many different samples?

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  • how to write or what is the concept behind the file unlocker program

    - by Jach Many
    Recently i was trying to delete a file thinking that i had closed the program which is manipulating the file but it did not delete because the program was still running. I misunderstood that file as an unwanted file. So i used the file unlocker program to find which process is manipulating that file. That program really worked well by showing the process which was handling that file. and that file was http://download.cnet.com/Unlocker/3000-2248_4-10493998.html. What i want to know is i would like to write a program in win32 C or .net to mimic the same process. Just to find which process is handling which file. and if possible to close it. Or i want to know the concept behind that. I know this cannot be explained in a few paragraphs yet if i could get some references or external links to references then that could be nice.

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  • Pass string between two threads in java

    - by geeta
    I have to search a string in a file and write the matched lines to another file. I have a thread to read a file and a thread to write a file. I want to send the stringBuffer from read thread to write thread. Please help me to pass this. I amm getting null value passed. write thread: class OutputThread extends Thread{ /****************** Writes the line with search string to the output file *************/ Thread runner1,runner; File Out_File; public OutputThread() { } public OutputThread(Thread runner,File Out_File) { runner1 = new Thread(this,"writeThread"); // (1) Create a new thread. this.Out_File=Out_File; this.runner=runner; runner1.start(); // (2) Start the thread. } public void run() { try{ BufferedWriter bufferedWriter=new BufferedWriter(new FileWriter(Out_File,true)); System.out.println("inside write"); synchronized(runner){ System.out.println("inside wait"); runner.wait(); } System.out.println("outside wait"); // bufferedWriter.write(line.toString()); Buffer Buf = new Buffer(); bufferedWriter.write(Buf.buffers); System.out.println(Buf.buffers); bufferedWriter.flush(); } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } } Read Thraed: class FileThread extends Thread{ Thread runner; File dir; String search_string,stats; File Out_File,final_output; StringBuffer sb = new StringBuffer(); public FileThread() { } public FileThread(CountDownLatch latch,String threadName,File dir,String search_string,File Out_File,File final_output,String stats) { runner = new Thread(this, threadName); // (1) Create a new thread. this.dir=dir; this.search_string=search_string; this.Out_File=Out_File; this.stats=stats; this.final_output=final_output; this.latch=latch; runner.start(); // (2) Start the thread. } public void run() { try{ Enumeration entries; ZipFile zipFile; String source_file_name = dir.toString(); File Source_file = dir; String extension; OutputThread out = new OutputThread(runner,Out_File); int dotPos = source_file_name.lastIndexOf("."); extension = source_file_name.substring(dotPos+1); if(extension.equals("zip")) { zipFile = new ZipFile(source_file_name); entries = zipFile.entries(); while(entries.hasMoreElements()) { ZipEntry entry = (ZipEntry)entries.nextElement(); if(entry.isDirectory()) { (new File(entry.getName())).mkdir(); continue; } searchString(runner,entry.getName(),new BufferedInputStream(zipFile.getInputStream(entry)),Out_File,final_output,search_string,stats); } zipFile.close(); } else { searchString(runner,Source_file.toString(),new BufferedInputStream(new FileInputStream(Source_file)),Out_File,final_output,search_string,stats); } } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } /********* Reads the Input Files and Searches for the String ******************************/ public void searchString(Thread runner,String Source_File,BufferedInputStream in,File output_file,File final_output,String search,String stats) { int count = 0; int countw = 0; int countl=0; String s; String[] str; String newLine = System.getProperty("line.separator"); try { BufferedReader br2 = new BufferedReader(new InputStreamReader(in)); //OutputFile outfile = new OutputFile(); BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(output_file,true)); Buffer Buf = new Buffer(); //StringBuffer sb = new StringBuffer(); StringBuffer sb1 = new StringBuffer(); while((s = br2.readLine()) != null ) { str = s.split(search); count = str.length-1; countw += count; if(s.contains(search)){ countl++; sb.append(s); sb.append(newLine); } if(countl%100==0) { System.out.println("inside count"); Buf.setBuffers(sb.toString()); sb.delete(0,sb.length()); System.out.println("outside notify"); synchronized(runner) { runner.notify(); } //outfile.WriteFile(sb,bufferedWriter); //sb.delete(0,sb.length()); } } } synchronized(runner) { runner.notify(); } br2.close(); in.close(); if(countw == 0) { System.out.println("Input File : "+Source_File ); System.out.println("Word not found"); System.exit(0); } else { System.out.println("Input File : "+Source_File ); System.out.println("Matched word count : "+countw ); System.out.println("Lines with Search String : "+countl); System.out.println("Output File : "+output_file.toString()); System.out.println(); } } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } }

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  • Java Client-Server problem when sending multiple files

    - by Jim
    Client public void transferImage() { File file = new File(ServerStats.clientFolder); String[] files = file.list(); int numFiles = files.length; boolean done = false; BufferedInputStream bis; BufferedOutputStream bos; int num; byte[] byteArray; long count; long len; Socket socket = null ; while (!done){ try{ socket = new Socket(ServerStats.imgServerName,ServerStats.imgServerPort) ; InputStream inStream = socket.getInputStream() ; OutputStream outStream = socket.getOutputStream() ; System.out.println("Connected to : " + ServerStats.imgServerName); BufferedReader inm = new BufferedReader(new InputStreamReader(inStream)); PrintWriter out = new PrintWriter(outStream, true /* autoFlush */); for (int itor = 0; itor < numFiles; itor++) { String fileName = files[itor]; System.out.println("transfer: " + fileName); File sentFile = new File(fileName); len = sentFile.length(); len++; System.out.println(len); out.println(len); out.println(sentFile); //SENDFILE bis = new BufferedInputStream(new FileInputStream(fileName)); bos = new BufferedOutputStream(socket.getOutputStream( )); byteArray = new byte[1000000]; count = 0; while ( count < len ){ num = bis.read(byteArray); bos.write(byteArray,0,num); count++; } bos.close(); bis.close(); System.out.println("file done: " + itor); } done = true; }catch (Exception e) { System.err.println(e) ; } } } Server public static void main(String[] args) { BufferedInputStream bis; BufferedOutputStream bos; int num; File file = new File(ServerStats.serverFolder); if (!(file.exists())){ file.mkdir(); } try { int i = 1; ServerSocket socket = new ServerSocket(ServerStats.imgServerPort); Socket incoming = socket.accept(); System.out.println("Spawning " + i); try { try{ if (!(file.exists())){ file.mkdir(); } InputStream inStream = incoming.getInputStream(); OutputStream outStream = incoming.getOutputStream(); BufferedReader inm = new BufferedReader(new InputStreamReader(inStream)); PrintWriter out = new PrintWriter(outStream, true /* autoFlush */); String length2 = inm.readLine(); System.out.println(length2); String filename = inm.readLine(); System.out.println("Filename = " + filename); out.println("ACK: Filename received = " + filename); //RECIEVE and WRITE FILE byte[] receivedData = new byte[1000000]; bis = new BufferedInputStream(incoming.getInputStream()); bos = new BufferedOutputStream(new FileOutputStream(ServerStats.serverFolder + "/" + filename)); long length = (long)Integer.parseInt(length2); length++; long counter = 0; while (counter < length){ num = bis.read(receivedData); bos.write(receivedData,0,num); counter ++; } System.out.println(counter); bos.close(); bis.close(); File receivedFile = new File(filename); long receivedLen = receivedFile.length(); out.println("ACK: Length of received file = " + receivedLen); } finally { incoming.close(); } } catch (IOException e){ e.printStackTrace(); } } catch (IOException e1){ e1.printStackTrace(); } } The code is some I found, and I have slightly modified it, but I am having problems transferring multiple images over the server. Output on Client: run ServerQueue.Client Connected to : localhost transfer: Picture 012.jpg 1312743 java.lang.ArrayIndexOutOfBoundsException Connected to : localhost transfer: Picture 012.jpg 1312743 Cant seem to get it to transfer multiple images. But bothsides I think crash or something because the file never finishes transfering

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  • Creando un File Upload

    - by jaullo
    Para iniciar hablaremos un poco sobre el control File Upload, de esta forma daremos una idea general de que es y como trabaja. El File Upload es un control de asp.net que permite que los usuarios seleccionen un archivo de cualquier ubicación en el equipo y lo suban a un directorio predeterminado a traves de una página asp.net. En principio este control esta limitado para no permitir subir archivos de mas de 4 MB. Sin embargo, desde el webconfig de nuestra aplicacón podremos cambiar ese valor, ya sea para aumentarlo o bien para disminuirlo. Nuestro ejemplo, se enfocará en crear un webcontrol que permita seleccionar un archivo y guardarlo, asi que empecemos. Lo primero será agregar a nuestra página un webcontrol que llamaremos Upload.ascx Posteriormente en nuestro webcontrol, agregamos el siguiente código: <table style="width: 100%">         <tr>             <td colspan="3">             <div align="center">                  <asp:Label ID="Label1" runat="server" Text="File Upload"></asp:Label>              </div>             </td>                    </tr>         <tr>             <td style="width: 456px" rowspan="2">                                                             &nbsp;</td>             <td style="width: 386px">                                <div align="center">                         <asp:FileUpload ID="FileUpload1" runat="server" Height="24px" Width="243px" />                         <span id="Span1" runat="server" />                            </div>                      </td>             <td rowspan="2">                                                             </td>         </tr>         <tr>             <td style="width: 386px">                 <div align="center">                      <asp:ImageButton Id="btnupload" runat="server" OnClick="btnupload_Click"                     ImageUrl="~/Styles/img/upload.png" style="text-align: center" />           </div>                  </td>         </tr>         <tr>             <td colspan="3">                 &nbsp;</td>         </tr>     </table>  De esta forma nuestro control deberá verse algo así   Por último en el code behin de nuestro control agregamos el código a nuestro boton, el cual será el encargado de leer el archivo que se encuentra en el File Upload y guardarlo en la ruta especificada.  Protected Sub btnupload_Click(ByVal sender As Object, ByVal e As System.Web.UI.ImageClickEventArgs) Handles btnupload.Click         If FileUpload1.HasFile Then             Dim fileExt As String             fileExt = System.IO.Path.GetExtension(FileUpload1.FileName)             If (fileExt = ".exe") Then                 Label1.Text = "You can´t upload .exe file!"             Else                 Try                     FileUpload1.SaveAs(decrpath & _                        FileUpload1.FileName)                     Label1.Text = "File name: " & _                       FileUpload1.PostedFile.FileName & "<br>" & _                       "File Size: " & _                       FileUpload1.PostedFile.ContentLength & " kb<br>" & _                       "Content type: " & _                       FileUpload1.PostedFile.ContentType                 Catch ex As Exception                     Label1.Text = "ERROR: " & ex.Message.ToString()                 End Try             End If         Else             Label1.Text = "You have not specified a file!"         End If            End Sub   Como vemos en el código anterior tambien hemos agregado otros elementos los cuales nos dirán el nombre del archivo, el tipo de contenido y el tamaño en kb una vez que el archivo ha sido súbido al servidor. Por último deben tomar en cuenta que decrpath es la ruta en donde será subido el archivo, la cual deben variar a su gusto.

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  • How to connect through a proxy using Remote Desktop?

    - by scottmarlowe
    So I've got a home server running Windows Server 2003. I use a dual network card setup and Routing and Remote Access to link the internal, private network to the external connection. The external connection hooks directly to my cable modem (so no routers or other devices sitting between). The problem I'm having is that I can't connect remotely from a location outside the house (so connecting to the server's external connection) to the server using either Remote Desktop or VNC. I have enabled both ports in Routing and Remote Access's firewall to allow access, and I have enabled Remote Desktop in Windows Server 2003. The odd thing is that I can access my home server's SVN repository and I can even ping the server's IP. I am using the IP to attempt to connect, though I use a dyndns.com provided name to connect to my SVN repository, so it shouldn't make a difference (I know the IP is getting resolved correctly). Any ideas on where to start diagnosing this one? I haven't seen anything in my server's event log. If any other info is needed, let me know. Thanks. UPDATE: One last piece of information: We use a proxy server at work, which I'm nearly 100% sure is the culprit. I have a workaround--if I connect to our VPN (even though I'm already inside the building) I am able to connect to my home server. This is with VNC. However, is there a way to connect through a proxy using Remote Desktop? ONE MORE UPDATE: Indeed, it was the http proxy I'm sitting behind at work that was causing the issue. An acceptable workaround is to use my VPN connection to bypass the proxy, and I'm in!

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  • .lnk doesn't open, no errors

    - by MushinNoShin
    I have a shortcut (.LNK) on my desktop to a MS Access database out on a network drive. When I double click that shortcut I get an hour glass for about 10 seconds and then nothing. No errors, no access opening, nothing happens. It appears as if there's not even an MSAccess process running in the background. The file successfully opens from: The Open dialog in Access The commandline "C:\path\to\MSACCESS.EXE C:\path\to\shortcut.lnk" The commandline "C:\path\to\MSACCESS.EXE C:\path\to\whatTheShortcutPointsTo.mdb" The file silently fails to open from: Double clicking the shortcut.lnk Double clicking the mdb file that shortcut.lnk targets At first I thought it had to do with how the link handler operated but the fact that it does the same exact thing when I try to open the mdb directly in explorer makes me think it's an issue with explorer. I've tried restoring, deleting, and recreating the association with the extension. I've tried running MSACCESS.EXE /regserver. I've run out of things to throw at it. In case this is specific to MS Access 2007; I'm trying to use 2007 :)

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    I'm new to ofbiz so try to keep your answer as simple as possibly. If you can give examples that would be kind. My problem is I created a project inside the ofbiz/hot-deploy folder namely productionmgntSystem. Inside the folder ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem I created a file app_details_1.ftl. The following are the code of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server. The file is get from user " tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1". But the file is not uploaded. Give me a good solution for uploading a file to the server.

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  • Security in Software

    The term security has many meanings based on the context and perspective in which it is used. Security from the perspective of software/system development is the continuous process of maintaining confidentiality, integrity, and availability of a system, sub-system, and system data. This definition at a very high level can be restated as the following: Computer security is a continuous process dealing with confidentiality, integrity, and availability on multiple layers of a system. Key Aspects of Software Security Integrity Confidentiality Availability Integrity within a system is the concept of ensuring only authorized users can only manipulate information through authorized methods and procedures. An example of this can be seen in a simple lead management application.  If the business decided to allow each sales member to only update their own leads in the system and sales managers can update all leads in the system then an integrity violation would occur if a sales member attempted to update someone else’s leads. An integrity violation occurs when a team member attempts to update someone else’s lead because it was not entered by the sales member.  This violates the business rule that leads can only be update by the originating sales member. Confidentiality within a system is the concept of preventing unauthorized access to specific information or tools.  In a perfect world the knowledge of the existence of confidential information/tools would be unknown to all those who do not have access. When this this concept is applied within the context of an application only the authorized information/tools will be available. If we look at the sales lead management system again, leads can only be updated by originating sales members. If we look at this rule then we can say that all sales leads are confidential between the system and the sales person who entered the lead in to the system. The other sales team members would not need to know about the leads let alone need to access it. Availability within a system is the concept of authorized users being able to access the system. A real world example can be seen again from the lead management system. If that system was hosted on a web server then IP restriction can be put in place to limit access to the system based on the requesting IP address. If in this example all of the sales members where accessing the system from the 192.168.1.23 IP address then removing access from all other IPs would be need to ensure that improper access to the system is prevented while approved users can access the system from an authorized location. In essence if the requesting user is not coming from an authorized IP address then the system will appear unavailable to them. This is one way of controlling where a system is accessed. Through the years several design principles have been identified as being beneficial when integrating security aspects into a system. These principles in various combinations allow for a system to achieve the previously defined aspects of security based on generic architectural models. Security Design Principles Least Privilege Fail-Safe Defaults Economy of Mechanism Complete Mediation Open Design Separation Privilege Least Common Mechanism Psychological Acceptability Defense in Depth Least Privilege Design PrincipleThe Least Privilege design principle requires a minimalistic approach to granting user access rights to specific information and tools. Additionally, access rights should be time based as to limit resources access bound to the time needed to complete necessary tasks. The implications of granting access beyond this scope will allow for unnecessary access and the potential for data to be updated out of the approved context. The assigning of access rights will limit system damaging attacks from users whether they are intentional or not. This principle attempts to limit data changes and prevents potential damage from occurring by accident or error by reducing the amount of potential interactions with a resource. Fail-Safe Defaults Design PrincipleThe Fail-Safe Defaults design principle pertains to allowing access to resources based on granted access over access exclusion. This principle is a methodology for allowing resources to be accessed only if explicit access is granted to a user. By default users do not have access to any resources until access has been granted. This approach prevents unauthorized users from gaining access to resource until access is given. Economy of Mechanism Design PrincipleThe Economy of mechanism design principle requires that systems should be designed as simple and small as possible. Design and implementation errors result in unauthorized access to resources that would not be noticed during normal use. Complete Mediation Design PrincipleThe Complete Mediation design principle states that every access to every resource must be validated for authorization. Open Design Design PrincipleThe Open Design Design Principle is a concept that the security of a system and its algorithms should not be dependent on secrecy of its design or implementation Separation Privilege Design PrincipleThe separation privilege design principle requires that all resource approved resource access attempts be granted based on more than a single condition. For example a user should be validated for active status and has access to the specific resource. Least Common Mechanism Design PrincipleThe Least Common Mechanism design principle declares that mechanisms used to access resources should not be shared. Psychological Acceptability Design PrincipleThe Psychological Acceptability design principle refers to security mechanisms not make resources more difficult to access than if the security mechanisms were not present Defense in Depth Design PrincipleThe Defense in Depth design principle is a concept of layering resource access authorization verification in a system reduces the chance of a successful attack. This layered approach to resource authorization requires unauthorized users to circumvent each authorization attempt to gain access to a resource. When designing a system that requires meeting a security quality attribute architects need consider the scope of security needs and the minimum required security qualities. Not every system will need to use all of the basic security design principles but will use one or more in combination based on a company’s and architect’s threshold for system security because the existence of security in an application adds an additional layer to the overall system and can affect performance. That is why the definition of minimum security acceptably is need when a system is design because this quality attributes needs to be factored in with the other system quality attributes so that the system in question adheres to all qualities based on the priorities of the qualities. Resources: Barnum, Sean. Gegick, Michael. (2005). Least Privilege. Retrieved on August 28, 2011 from https://buildsecurityin.us-cert.gov/bsi/articles/knowledge/principles/351-BSI.html Saltzer, Jerry. (2011). BASIC PRINCIPLES OF INFORMATION PROTECTION. Retrieved on August 28, 2011 from  http://web.mit.edu/Saltzer/www/publications/protection/Basic.html Barnum, Sean. Gegick, Michael. (2005). Defense in Depth. Retrieved on August 28, 2011 from  https://buildsecurityin.us-cert.gov/bsi/articles/knowledge/principles/347-BSI.html Bertino, Elisa. (2005). Design Principles for Security. Retrieved on August 28, 2011 from  http://homes.cerias.purdue.edu/~bhargav/cs526/security-9.pdf

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  • Mobile Device emulator cannot access localhost

    - by Diana
    I am using Windows Mobile 6 Professional Emulator and Windows Mobile Device Center. I connected and cradled the emulator to my computer. I am trying to connect from the browser of the emulator to a webservice that is deployed in the IIS of my computer (same machine where the emulator is installed). If I connect my computer to the internet, I can access any website, including my local WS (using the IP returned by ipConfig). The problem is when I disconnect the computer from the Internet: I cannot access my local web service using the IP (internal one returned by ipconfig), or machine name. Do you have any ideea what settings am I missing? I am sure this it's possible somehow, I just don't know how... PS: The goal is to access the WS from a mobile application, but until I cannot access it from the browser, I cannot access it from the application either. Thank you!

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  • Access Internet From My Blackberry App

    - by Ankit
    Hi all, This is my first attemp to code a blackberry app so please bear with me. I am developing an app to make it easy to access certain information from certain websites using screenscrapping. Now I am done with the ui part of the application onto the internet access part. My question is how do i access internet from my app ? I see that blackberry offers http, wifi and some other forms to access the internet ... does my app need to be worried about what mode is being used ? or as far as my app is concerned theres a general api to access the net with the logic of connecting to the internet being handled by the device itself ..? any pointers with some sample code would be much appreciated. thank you, ankit

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  • Watchguard box VPN Access X700

    - by Paulio001
    We have a watchguard X700 box that we are trying to get VPN access through. We have had a play with the ports and tried to open the VPN access but still have no joy. Do we need to purchase a special licence to get VPN open on this box?

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  • [Windows 7] Certain Programs cannot access internet

    - by Cindy
    Operating System: Windows 7 (x64) Problem: Certain Programs are unable to access the internet. They claim that there is no connection when you already are connected. Hello, before we start. Just letting you know I'm new here, and I'm very new to Windows 7. I installed it two days ago. I just installed Windows 7 on my laptop and I have a few problems. I play World of Warcraft, as well as a variety of games. And when I first attempt to log into the game, I get a windows error message, but it doesn't stop there. I thought World of Warcraft got corrupted during the upgrade. It seems that I am unable to access the internet from other online games as well. Most say in along the lines of "Cannot connect to patch server, try again later." I cannot use a downloader Also, I have internet explorer. The x32 version of the browser cannot connect to the internet, and when I try to enter "google.com", it says the same thing. I'm only accessing this site through Internet Explorer x64, which I would have been fine with is it's compatible with Adobe Flash. The only thing that seems to connect to the internet are Internet Explorer x64 and Windows Live Messenger. Here are the steps I have taken, but none worked. 1.) Disable Windows Firewall 2.) Have Windows Firewall Enabled, but allow the specific programs to access internet. And allowed all incoming access. 3.) Disabled UAC, Ran the programs as an admin, and set compatibility to Vista. 4.) Uninstalled an anti-virus program. (McAffee Security Suite 2010) 5.) Reinstalled the programs 6.) Reinstalled Windows 7 7.) Retaken the steps on the Administrator account. Please assist me in this problem. I need to get back into the game. Thanks so much in advance.

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  • How to access VMWare localhost from my mac?

    - by Abe Miessler
    I have developed a asp.net application on my VMWare virtual machine that I can access (on my VM) by going to http://localhost:1044 How can I access this from safari on my Mac that is running the VM? I tried running ipconfig on my VM and then using the IP address that was given for "Ethernet adapter Local Area Connection", something like this: http://192.168.179.139:1044/ but this throws a not found error. I am currently using NAT. How can I get to localhost on my VM from my mac?

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  • How to get a Mac Computer Access Service

    - by rfders
    Hi all, do you guys know if exist any services over internet which provide me access to a mac computer, i want to get into iphone programming and dont have a mac, so i want to know if is it possible to get a mac access service, just for training purpose

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