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  • How to validate Login Details using Google apps API ?

    - by Pari
    Hi, I am using below code to to create Contact Service and to Validate login Details: ContactsService obj_ContactService = new ContactsService(""); obj_ContactService.setUserCredentials(userEmail, password); But even if user enters invalid detail above code does not throw any exception. User get verified only when i call "Insert" query after adding whole contact details. But in my application i want to notify user immediately after user enters login details. Thanx

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  • window form: Adding Emoticons

    - by Emaad Ali
    Hi, i am trying to develop a window form using c# with asp.net 3.5 framework. in that form i want to insert emoticons as we found in yahoo, hotmail etc messenger. can anyone tell me how i can implement that thing as it is done in messenger. please help me.

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  • C# menustrip designer

    - by Iceyoshi
    Hi, I'm not sure when this happened but when I was trying to edit a menustrip in my program (in the VS designer), I noticed that the menu items had be grouped or merged. Like: File Edit Format Insert ... Instead of being able to click each menu item and add sub-items to them in the designer, they all were grouped together so I couldn't edit the menu items separately, it's quite painful. I couldn't find any properties related to this, so how could I ungroup the menu items in the designer?

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  • What is wrong with this trigger in mysql?

    - by Jimit
    Hi all, Below is trigger that I need to create but It is not getting created.Please any buddy can explain me what is wrong with this trigger ? Help me please. DELIMITER $$ CREATE TRIGGER property_history_update AFTER UPDATE ON `properties` FOR EACH ROW BEGIN IF OLD.ListPrice != NEW.ListPrice THEN INSERT INTO `property_history` SET ListingKey=OLD.ListingKey,ListPrice = NEW.ListPrice, ListingStatus = OLD.ListingStatus,LastUpdatedTime = NEW.LocalLastModifiedOn; END IF; END$$ DELIMITER ;

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  • Handling apostrophes, php and pgsql

    - by running4surival
    For my forms, I'm using pg_escape_string on every field before I insert them into the database. So I get something like firstname='O''reilly'. But when I try to print that out, I get O''reily, 2 apostrophes. Shouldn't it only 1 apostrophe, O'reilly? This isnt a debugging problem, im just wondering if you have firstname='O''reilly', how do you print that so it is just O'reilly instead of O''reilly?

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  • How to save byte[] to varbinary(64) field in database

    - by shamim
    I have byte[] a = HashEncrypt("a"); with public byte[] HashEncrypt(string password) { SHA512Managed sha = new SHA512Managed(); byte[] hash = sha.ComputeHash(UnicodeEncoding.Unicode.GetBytes(password)); return hash; } I want to save byte[] a to my database. My database field is a varbinary(64). I'm using SQL Server 2008. I want to know the insert query with C# code. I am using ADO.NET

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  • why save_model method doesn't work in admin.StackedInline?

    - by FurtiveFelon
    Hi all, I have a similar problem as a previously solved problem of mine, except this time solution doesn't seem to work: http://stackoverflow.com/questions/2991365/how-to-auto-insert-the-current-user-when-creating-an-object-in-django-admin Previously i used to override the save_model to stamp the user submitting the article. Now i need to do the same for comments, it doesn't seem to work anymore. Anyone have any ideas? Thanks a lot! Jason

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  • Adding rows to an array in PHP

    - by ChuckO
    I have loaded an associative array of records from a MySQL database table. The array consists of 1 to 7 rows representing one week of entries, which might not have been entered for each day. How can I insert blank rows into the array for the missing days so that I can easily display the data in a table? I don't need to update the database with the blanks.

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  • (mySQL) Unable to query 2 tables properly for data

    - by Devner
    I have 2 tables. One is 'page_links' and the other is 'rpp'. Table page_links is the superset of table rpp. The following is the schema of my tables: -- Table structure for table `page_links` -- CREATE TABLE IF NOT EXISTS `page_links` ( `page` varchar(255) NOT NULL, `page_link` varchar(100) NOT NULL, `heading_id` tinyint(3) unsigned NOT NULL, PRIMARY KEY (`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `page_links` -- INSERT INTO `page_links` (`page`, `page_link`, `heading_id`) VALUES ('a1.php', 'A1', 8), ('b1.php', 'B1', 8), ('c1.php', 'C1', 5), ('d1.php', 'D1', 5), ('e1.php', 'E1', 8), ('f1.php', 'F1', 8), ('g1.php', 'G1', 8), ('h1.php', 'H1', 1), ('i1.php', 'I1', 1), ('j1.php', 'J1', 8), ('k1.php', 'K1', 8), ('l1.php', 'L1', 8), ('m1.php', 'M1', 8), ('n1.php', 'N1', 8), ('o1.php', 'O1', 8), ('p1.php', 'P1', 4), ('q1.php', 'Q1', 5), ('r1.php', 'R1', 4); -- Table structure for table `rpp` -- CREATE TABLE IF NOT EXISTS `rpp` ( `role_id` tinyint(3) unsigned NOT NULL, `page` varchar(255) NOT NULL, `is_allowed` tinyint(1) NOT NULL, PRIMARY KEY (`role_id`,`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `rpp` -- INSERT INTO `rpp` (`role_id`, `page`, `is_allowed`) VALUES (3, 'a1.php', 1), (3, 'b1.php', 1), (3, 'c1.php', 1), (3, 'd1.php', 1), (3, 'e1.php', 1), (3, 'f1.php', 1), (3, 'h1.php', 1), (3, 'i1.php', 1), (3, 'l1.php', 1), (3, 'm1.php', 1), (3, 'n1.php', 1), (4, 'a1.php', 1), (4, 'b1.php', 1), (4, 'q1.php', 1), (5, 'r1.php', 1); WHAT I AM TRYING TO DO: I am trying to query both the above tables (in a single query) in such a way that all the pages from page_links are displayed along with the is_allowed value from rpp for a particular role. For example, I want to get the is_allowed value of all the pages from rpp for role_id = 3 and at the same time, list all the available pages from page_links. A clear example of my expected result would be: page is_allowed role_id ---------------------------------------- a1.php 1 3 b1.php 1 3 c1.php 1 3 d1.php 1 3 e1.php 1 3 f1.php 1 3 g1.php NULL NULL h1.php 1 3 i1.php 1 3 j1.php NULL NULL k1.php NULL NULL l1.php 1 3 m1.php 1 3 n1.php 1 3 o1.php NULL NULL p1.php NULL NULL q1.php NULL NULL r1.php NULL NULL One more example of my desired result could be achieved by doing a LEFT JOIN rpp ON page_links.page = rpp.page but we need to omit using role_id = 3 (or any value) to be able to get that. But I do want to specify the role_id as well and get the results. I need the query to be able to get this result. I would appreciate any replies that could help me with this. If you can suggest me any changes as well to the table(s) design to be able to achieve the desired result, that's good as well. Thanks in advance.

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  • Inserting checkbox values

    - by rabeea
    hey i have registration form that has checkboxes along with other fields. i cant insert the selected checkbox values into the data base. i have made one field in the database for storing all checked values. this is the code for checkbox part in the form: Websites, IT and Software Writing and Content <pre><input type="checkbox" name="expertise[]" value="Design and Media"> Design and Media <input type="checkbox" name="expertise[]" value="Data entry and Admin"> Data entry and Admin </pre> <pre><input type="checkbox" name="expertise[]" value="Engineering and Skills"> Engineering and Science <input type="checkbox" name="expertise[]" value="Seles and Marketing"> Sales and Marketing </pre> <pre><input type="checkbox" name="expertise[]" value="Business and Accounting"> Business and Accounting <input type="checkbox" name="expertise[]" value="Others"> Others </pre> and this is the corresponding php code for inserting data $checkusername=mysql_query("SELECT * FROM freelancer WHERE fusername='{$_POST['username']}'"); if (mysql_num_rows($checkusername)==1) { echo "username already exist"; } else { $query = "insert into freelancer(ffname,flname,fgender,femail,fusername,fpwd,fphone,fadd,facc,facc_name,fbank_details,fcity,fcountry,fexpertise,fprofile,fskills,fhourly_rate,fresume) values ('".$_POST['first_name']."','".$_POST['last_name']."','".$_POST['gender']."','".$_POST['email']."','".$_POST['username']."','".$_POST['password']."','".$_POST['phone']."','".$_POST['address']."','".$_POST['acc_num']."','".$_POST['acc_name']."','".$_POST['bank']."','".$_POST['city']."','".$_POST['country']."','".implode(',',$_POST['expertise'])."','".$_POST['profile']."','".$_POST['skills']."','".$_POST['rate']."','".$_POST['resume']."')"; $result = ($query) or die (mysql_error()); this code inserts data for all fields but the checkbox value field remains empty???

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  • Sort by ranking algorithm using will-paginate

    - by bearwithclaws
    I'm creating a digg-like site using Ruby on Rails that ranks the item (based on this algorithm). I'm using the will-paginate gem list the items in pages. The problem is, will-paginate only allows me to insert ':order =' based on the table data. I would like to make will-paginate to sort by a number which is calculated using a function based on different fields on the table (e.g number of votes, age hours). How can I do that?

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  • Jeditable doubling up on linebreaks every edit

    - by st3
    I'm using var retval = value.replace(/<br[\s\/]?>/gi, '\n'); To strip the <br> tags from the textarea and nl2br('$_POST('newValueHere')') to insert into my database and to return back to jeditable to display the edits. The only problem I'm having is that each click on the editable field seems to make all the <br> tags be written twice? This makes no sense, does anyone have any ideas what could be going on?

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  • find controls from dynamically created table

    - by tina
    hi, i wrote a function to create dynamic table in code behind on selectedindexchanged of checkbox, that is when user will check 2 checkboxex 2 tables will be generated with textboxes, Then on button click i want insert values of these textboxes in database, for that i want to find textbox using findcontrol,but i could not find it, So i called same function of table creation on page load, but then it shows error that textbox is having duplicate id Plz tell me solution for this. thanks

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  • Why Firebug Sucks At Real Time Html Editing?

    - by David
    Hi, i always like to real-time edit a web page source in the browser and updated as i type, but firebug really sucks, i can't insert scripts in the current page, some times the changes i type aren't updated at all, Is there any robust firefox/chrome extension for that? i try to temporarely edit/add code to an existing web page in the internet, not a local one Thanks

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