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  • How to concatinate text on existing database entry?

    - by Starx
    I am a table, whose structure is somewhat like this id, name, link the link holds the name of the page like "link" = "index.php". Now I want to update this field and add "page=" in front of "index.php". Using this method I would like to update every entry in my table. My desired SQL syntax need to be something like this UPDATE mytable set link= 'page=' + <existing value of link> WHERE 1; I am using Where 1; to denote every other rows Anyone know what to accomplish this?

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  • Evaluate column value into rows

    - by Hugo Palma
    I have a column whose value is a json array. For example: [{"att1": "1", "att2": "2"}, {"att1": "3", "att2": "4"}, {"att1": "5", "att2": "6"}] What i would like is to provide a view where each element of the json array is transformed into a row and the attributes of each json object into columns. Keep in mind that the json array doesn't have a fixed size. Any ideas on how i can achieve this ?

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  • How can this SQL be wrong? What am I not seeing?

    - by ropstah
    Can anybody please spot my error, this should be a legal query in SQL shouldn't it?? Unknown column u.usr_auto_key in the ON clause This is the database schema: User: (usr_auto_key, name, etc...) Setting: (set_auto_key, name etc..) User_Setting: (usr_auto_key, set_auto_key, value) And this is the query... SELECT `u`.`usr_auto_key` AS `u__usr_auto_key`, `s`.`set_auto_key` AS `s__set_auto_key`, `u2`.`usr_auto_key` AS `u2__usr_auto_key`, `u2`.`set_auto_key` AS `u2__set_auto_key`, `u2`.`value` AS `u2__value` FROM `User` `u`, `Setting` `s` LEFT JOIN `User_Setting` `u2` ON `u`.`usr_auto_key` = `u2`.`usr_auto_key` WHERE (`s`.`sct_auto_key` = 1 AND `u`.`usr_auto_key` = 1 AND admin_property is null)

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  • Complex data ordering...

    - by Povylas
    Hi, I have one tables ids in an array and they are ordered in the way I want and I have to select data from another table using those ids and in a order they are listen in the array. Pretty confusing but I was thinking of two solutions giving ORDER BY parameter the array but I do not know if that possible and another is to get all the necessary data and then turn it to array (mysql_fetch_assoc) then compare those two and somehow order the new array using the ids array. But I also do not know how to do this... Any ideas?

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  • one query instead of four - is it possible?

    - by Syom
    i must get data from four tables. i wrote the script with four queries, but i use it in ajax, and i wan't to do it by one query. here is queries... $query1 = "SELECT `id`,`name_ar` FROM `tour_type` ORDER BY `order`"; $query2 = "SELECT `id`,`name_ar` FROM `hotel_type` ORDER BY `order`"; $query3 = "SELECT `id`,`name_ar` FROM `food_type` ORDER BY `order`"; $query4 = "SELECT `id`,`name_ar` FROM `cities` WHERE `id_parrent` = '$id_parrent' ORDER BY `name_ar`"; is it possible to write in one query? thanks

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  • php code is not fetching data from mysql database using wamp server

    - by john
    I want to display a table from database in phpMyAdmin by putting the following conditions that in every different options in drop down menu it displays different table from database by pressing the button of search. But it is not doing so. <p class="h2">Quick Search</p> <div class="sb2_opts"> <p></p> <form method="post" action="" > <p>Enter your source and destination.</p> <p>From:</p> <select name="from"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <p>To:</p> <select name="To"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <input type="submit" value="search" /> </form> </form> </table> <?php $con=mysqli_connect("localhost","root","","test"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } if(isset($_POST['from']) and isset($_POST['To'])) { $from = $_POST['from'] ; $to = $_POST['To'] ; $table = array($from, $to); switch ($table) { case array ("Islamabad", "Lahore") : $result = mysqli_query($con,"SELECT * FROM flights"); echo "</flights>"; //table name is flights break; case array ("Islamabad", "Murree") : $result = mysqli_query($con,"SELECT * FROM isb to murree"); echo "</isb to murree>"; //table name isb to murree ; break; case array ("Islamabad", "Muzaffarabad") : $result = mysqli_query($con,"SELECT * FROM isb to muzz"); echo "</isb to muzz>"; break; //..... //...... default: echo "Your choice is nor valid !!"; } } mysqli_close($con); ?>

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  • Data from two tables without repeating data from the first?

    - by Aran
    I have two tables. Users table and Users Meta Table I am looking for a way to get all the information out of both tables with one query. But without repeating the information from Users table. This is all information relating to the users id number as well. So for example user_id = 1. Is there a way to query the database and collect all the information I from both tables without repeating the information from the first?

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  • How can I improve this SQL to avoid several problems with its results?

    - by Josh Curren
    I am having some problems with trying to search. Currently this will only return results that have at least 1 row in the maintenance_parts table. I would like it to return results even if there are 0 parts rows. My second problem is that when you search for a vehicle and it should return multiple results (multiple maintenance rows) it will only return 1 result for that vehicle. Some Background Info: The user has 2 fields to fill out. The fields are vehicle and keywords. The vehicle field is meant to allow searching based on the make, model, VIN, truck number (often is 2 - 3 digits or a letter prefix followed by 2 digits), and a few other fields that belong to the truck table. The keywords are meant to search most fields in the maintenance and maintenance_parts tables (things like the description of the work, parts name, parts number). The maintenance_parts table can contain 0, 1, or more rows for each maintenance row. The truck table contains exactly 1 row for every maintenance row. A truck can have multiple maintenance records. "SELECT M.maintenance_id, M.some_id, M.type_code, M.service_date, M.mileage, M.mg_id, M.mg_type, M.comments, M.work_done, MATCH( M.comments, M.work_done) AGAINST( '$keywords' ) + MATCH( P.part_num, P.part_desc, P.part_ref) AGAINST( '$keywords' ) + MATCH( T.truck_number, T.make, T.model, T.engine, T.vin_number, T.transmission_number, T.comments) AGAINST( '$vehicle' ) AS score FROM maintenance M, maintenance_parts P, truck T WHERE M.maintenance_id = P.maintenance_id AND M.some_id = T.truck_id AND M.type_code = 'truck' AND ( (MATCH( T.truck_number, T.make, T.model, T.engine, T.vin_number, T.transmission_number, T.comments) AGAINST( '$vehicle' ) OR T.truck_number LIKE '%$vehicle%') OR MATCH( P.part_num, P.part_desc, P.part_ref) AGAINST( '$keywords' ) OR MATCH( M.comments, M.work_done) AGAINST( '$keywords' ) ) AND M.status = 'A' GROUP BY maintenance_id ORDER BY score DESC, maintenance_id DESC LIMIT 0, $limit"

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  • Using INSERT / OUTPUT in a SQL Server Transaction

    Frequently I find myself in situations where I need to insert records into a table in a set-based operation wrapped inside of a transaction where secondarily, and within the same transaction, I spawn-off subsequent inserts into related tables where I need to pass-in key values that were the outcome of the initial INSERT command. Thanks to a Transact/SQL enhancement in SQL Server, this just became much easier and can be done in a single statement... WITHOUT A TRIGGER! Join SQL Backup’s 35,000+ customers to compress and strengthen your backups "SQL Backup will be a REAL boost to any DBA lucky enough to use it." Jonathan Allen. Download a free trial now.

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  • How to concatenate text on existing database entry?

    - by Starx
    I have a table, whose fields are id, name, link the link holds the name of the page like "link" = "index.php". Now I want to update this field and add "page=" in front of "index.php". Using this method I would like to update every entry in my table. My desired SQL syntax need to be something like this UPDATE mytable set link= 'page=' + <existing value of link> WHERE 1; I am using 'WHERE 1;' to denote every row. Anyone know how to accomplish this?

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  • NHibernate and MySql is inserting and Selecting, not updating

    - by Chris Brandsma
    Something strange is going on with NHibernate for me. I can select, and I can insert. But I can't do and update against MySql. Here is my domain class public class UserAccount { public virtual int Id { get; set; } public virtual string UserName { get; set; } public virtual string Password { get; set; } public virtual bool Enabled { get; set; } public virtual string FirstName { get; set; } public virtual string LastName { get; set; } public virtual string Phone { get; set; } public virtual DateTime? DeletedDate { get; set; } public virtual UserAccount DeletedBy { get; set; } } Fluent Mapping public class UserAccountMap : ClassMap<UserAccount> { public UserAccountMap() { Table("UserAccount"); Id(x => x.Id); Map(x => x.UserName); Map(x => x.Password); Map(x => x.FirstName); Map(x => x.LastName); Map(x => x.Phone); Map(x => x.DeletedDate); Map(x => x.Enabled); } } Here is how I'm creating my Session Factory var dbconfig = MySQLConfiguration .Standard .ShowSql() .ConnectionString(a => a.FromAppSetting("MySqlConnStr")); FluentConfiguration config = Fluently.Configure() .Database(dbconfig) .Mappings(m => { var mapping = m.FluentMappings.AddFromAssemblyOf<TransactionDetail>(); mapping.ExportTo(mappingdir); }); and this is my NHibernate code: using (var trans = Session.BeginTransaction()) { var user = GetById(userId); user.Enabled = false; user.DeletedDate = DateTime.Now; user.UserName = "deleted_" + user.UserName; user.Password = "--removed--"; Session.Update(user); trans.Commit(); } No exceptions are being thrown. No queries are being logged. Nothing.

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  • Drupal - db_fetch_array returns NULL for every row

    - by darudude
    I'm using Drupal's db_fetch_array to fetch rows from my db_query. However, every row returned is equal to NULL. Typing the query into PHP myadmin works, so I have no idea whats going on. db_num_rows returns the number of rows as well. Here is the code: if(count($rebuild_ids)) { $ids=implode(",",$rebuild_ids); $type_stmt = "SELECT * from {" . ItemType::$type_table_name . "} where id IN ($ids)"; $new_items=db_query($type_stmt); if(!$new_items || db_num_rows($new_items) == 0) { return; } while($row = db_fetch_array($new_items)); { if ($row!=NULL) { echo "I work!" $game_items[] = $row['id']; ItemInstance::$nid_to_item_type_code[$row['nid']] = $row['id']; } } } However, it never gets into the third if statement (i.e. never echos "I work!") Any ideas?

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  • Similar SQL queries returning different results...

    - by Pablo
    Here are the SQL Queries: $sql1 = "SELECT count(thread) AS total FROM comments WHERE thread=1 AND parent_id=0 "; $sql2 = "SELECT count(thread) AS total FROM comments, users WHERE thread=1 AND parent_id=0 AND users.user_id=comments.user_id "; $sql3 = "SELECT comments.*, users.username AS username FROM comments, users WHERE thread=1 AND parent_id=0 AND users.user_id=comments.user_id ORDER BY date LIMIT 10, 5 "; My question is why would $sql1 and $sql2 would return two different results? $sql1 returns 61 rows $sql2 returns 56 rows The 5th line in $sql2 is just for testing, is not required, is just a variation of $sql1 which gets the total rows for a pagination.

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  • SQL Query to select upcoming events with a start and end date

    - by Chris T
    I need to display upcoming events from a database. The problem is when I use the query I'm currently using any events with a start day that has passed will show up lower on the list of upcoming events regardless of the fact that they are current My table (yaml): columns: title: type: string(255) notnull: true default: Untitled Event start_time: type: time end_time: type: time start_day: type: date notnull: true end_day: type: date description: type: string(500) default: This event has no description category_id: integer My query (doctrine): $results = Doctrine_Query::create() ->from("sfEventItem e, e.Category c") ->select("e.title, e.start_day, e.description, e.category_id, e.slug") ->addSelect("c.title, c.slug") ->orderBy("e.start_day, e.start_time, e.title") ->limit(5) ->execute(array(), Doctrine_Core::HYDRATE_ARRAY); Basically I'd like any events that is currently going on (so if today is in between start_day and end_day) to be at the top of the list. How would I go about doing this if it's even possible? Raw sql queries are good answers too because they're pretty easy to turn into DQL.

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  • How to return null value if the query has no corresponding value?

    - by Holicreature
    Hi i've a query select c.name as companyname, u.name,u.email,u.role,a.date from useraccount u, company c, audittrial a where u.status='active' and u.companyid=c.id and (u.companyid=a.companyID and a.activity like 'User activated%' and a.email=u.email) order by u.companyid desc limit 10 So if the following part doesnt't satisfy, (u.companyid=a.companyID and a.activity like 'User activated%' and a.email=u.email) no rows will be returned.. but i want to return the result of the following query select c.name as companyname, u.name,u.email,u.role,a.date from useraccount u, company c, audittrial a where u.status='active' and u.companyid=c.id order by u.companyid desc limit 10 but to add that, i should return the date if available and return null value if date is not available.. how can i do this?

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  • Create table with PHP and populate from MySQL

    - by typoknig
    Hi all, I am creating a table to display on a web page and that table is populated from data in a MySQL database. I am trying to do a couple of things that are making it difficult for me. First I am trying to have call the PHP code that exists in a separate file in HTML via JavaScript. I think I have that working right but I am not 100% sure (because the table will not display). I think it is working right because some of the code for the table (which is in the PHP file) displays in FireBug. Second I am trying to make it so the rows alternate colors for easy viewing too. My PHP code so far is below. The table does not display at all in any browser. $query = "SELECT * FROM employees"; $result = mysql_query($query); $num = mysql_num_rows($result); echo '<table>'; for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $id = $row['id']; $l_name = $row['l_name']; $f_name = $row['f_name']; $ssn = $row['ssn']; $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr>"; echo "<td class=" . $class . ">$wrap_id</td>"; echo "<td class=" . $class . ">$wrap_l_name</td>"; echo "<td class=" . $class . ">$wrap_f_name</td>"; echo "<td class=" . $class . ">$wrap_ssn</td>"; echo "</tr>"; } echo '</table>'; mysql_close($link); }

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  • Export CSV from Mysql

    - by ss888
    Hi, I'm having a bit of trouble exporting a csv file that is created from one of my mysql tables using php. The code I'm using prints the correct data, but I can't see how to download this data in a csv file, providing a download link to the created file. I thought the browser was supposed to automatically provide the file for download, but it doesn't. (Could it be because the below code is called using ajax?) Any help greatly appreciated - code below, S. include('../config/config.php'); //db connection settings $query = "SELECT * FROM isregistered"; $export = mysql_query ($query ) or die ( "Sql error : " . mysql_error( ) ); $fields = mysql_num_fields ( $export ); for ( $i = 0; $i < $fields; $i++ ) { $header .= mysql_field_name( $export , $i ) . "\t"; } while( $row = mysql_fetch_row( $export ) ) { $line = ''; foreach( $row as $value ) { if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } //header("Content-type: application/octet-stream"); //have tried all of these at sometime //header("Content-type: text/x-csv"); header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=export.csv"); //header("Content-Disposition: attachment; filename=export.xls"); header("Pragma: no-cache"); header("Expires: 0"); echo '<a href="">Download Exported Data</a>'; //want my link to go in here... print "$header\n$data";

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  • Need help with some complex SQL query

    - by Psyche
    Hello guys, I need some help with a complex SQL query. Here's my setup: there are two tables, one with authors, and another with books. The books table contains a field named "author" which holds author's id. If a book has more than one author, then the "author" field will contain all the authors ids separated by ";" (something like 2;34;234). On the website I have to list all the books written by an author. If there's only one author, its simple, but how can I get those books where the author I'm interested in is the second or third author? Many thanks.

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  • MSYQL ~ Why does this query only select a single row?

    - by Joe
    SELECT * FROM tbl_houses WHERE (SELECT HousesList FROM tbl_lists WHERE tbl_lists.ID = '123') LIKE CONCAT('% ', tbl_houses.ID, '#') ^ It only selects the row from tbl_houses of the last occuring "tbl_houses.ID" inside tbl_lists.HousesList I need it to select ALL the rows where any ID from tbl_houses exists within tbl_lists.HousesList

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  • How to insert the recently inserteddata of a table to others DB's Table? See description...

    - by Parth
    I am using MySQL DB and I have created a PHP script for the following, now i need the idea for the below asked question.... please help... I have a table called audit trail whose structure is: id, trackid, table, operation, newvalue, oldvalue, field, changedone I have created triggers for insert/update/delete for every table of same DB, now whenever there is change in ny DB the triggers get activated and updates the Audit trail table accordingly.. I am tracking these changes so that i can use these changes to be done on production DB which is of same structure as of this test DB. Also when the admin finds that he does not need the changes recently he did for production DB then he can rollback it using the Old Data it stored in Ausittrail table of test db. Now here in audit trail table structure, there will be an insert for every single field change like-wise if a table has 4 fields then the change in that tavle will insert 4 rows in audit trail.. Coming to the question now, How can i find the latest change done from the Audit table so that I can insert these changes in Production DB.

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  • login not working when changing from mysql to mysqli

    - by user1438647
    I have a code below where it logs a teacher in by matching it's username and password in the database, if correct, then log in, if incorrect, then display a message. <?php session_start(); $username="xxx"; $password="xxx"; $database="mobile_app"; $link = mysqli_connect('localhost',$username,$password); mysqli_select_db($link, $database) or die( "Unable to select database"); foreach (array('teacherusername','teacherpassword') as $varname) { $$varname = (isset($_POST[$varname])) ? $_POST[$varname] : ''; } ?> <form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" id="teachLoginForm"> <p>Username</p><p><input type="text" name="teacherusername" /></p> <!-- Enter Teacher Username--> <p>Password</p><p><input type="password" name="teacherpassword" /></p> <!-- Enter Teacher Password--> <p><input id="loginSubmit" type="submit" value="Login" name="submit" /></p> </form> <?php if (isset($_POST['submit'])) { $query = " SELECT * FROM Teacher t WHERE (t.TeacherUsername = '".mysqli_real_escape_string($teacherusername)."') AND (t.TeacherPassword = '".mysqli_real_escape_string($teacherpassword)."') "; $result = mysqli_query($link, $query); $num = mysqli_num_rows($result); $loged = false; while($row = mysqli_fetch_array($result)) { if ($_POST['teacherusername'] == ($row['TeacherUsername']) && $_POST['teacherpassword'] == ($row['TeacherPassword'])) { $loged = true; } $_SESSION['teacherforename'] = $row['TeacherForename']; $_SESSION['teachersurname'] = $row['TeacherSurname']; $_SESSION['teacherusername'] = $row['TeacherUsername']; } if ($loged == true){ header( 'Location: menu.php' ) ; }else{ echo "The Username or Password that you Entered is not Valid. Try Entering it Again."; } mysqli_close($link); } ?> Now the problem is that even if the teacher has entered in the correct username and password, it still doesn't let the teacher log in. When the code above was the old mysql() code, it worked fine as teacher was able to login when username and password match, but when trying to change the code into mysqli then it causes login to not work even though username and password match. What am I doing wrong?

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