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  • HTML Doctype Setting / IE Quirks Mode

    - by Frederico
    I'm working within the parameters of an un-reachable developer, whom has created an html generation system for our products.. Whenever a new page is generated he places: <!-- updated page at 05/MAY/2010 02:58.58 --> <!-- You must use the template manager to modify the formatting of this page. --> resulting in my code looking like: <!-- updated page at 05/MAY/2010 02:55.30 --> <!-- You must use the template manager to modify the formatting of this page. --> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en" xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> I don't believe IE read's this doctype at all, as when looking at the developer screen, it renders in Quirks mode... is there any other way to force IE out of this horrible Quirks mode? I've been trying to reach the developer but he has been rather un-available.. Thank you in advance for any help you might have to offer.

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  • Rails 2.3.2 trying to render ERB instead of HAML

    - by c00lryguy
    Rails is suddenly trying to render ERB instead of Haml and I can't figure out why. I've created new rails projects, reinstalled Haml, and reinstalled Rails. Here's exactly the steps I take when making my application (Rails 2.3.2): rails> rails test rails> cd test rails\test> haml --rails . rails\test> ruby script\generate model user email:string password:string rails\test> ruby script\generate controller users index rails\test> rake db:migrate Here's what the UsersController looks like: class UsersController < ApplicationController def index @users = User.all end end My routes: ActionController::Routing::Routes.draw do |map| map.resources :users end I now create views\users\index.html.haml: %table %th(style="text-align: left;") %h1 Users - for user in @users %tr %td= user.email %td= user.password Annnd run the server... I navigate to localhost:3000\users and I get this error message: Template is missing Missing template users/index.erb in view path app/views For some reason Rails is trying to find and render .erb files instead of .haml files. vendor\plugins\haml\init.rb exists, untouched. I've reinstalled Haml (Pretty Penny) multiple times and still get the same results. I've also tried adding config.gem 'haml' to my environment.rb but this also doesn't work. I can't figure out why suddenly rails will not render haml for me.

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  • Silverlight RIA Services - how to do Windows Authentication?

    - by Gustavo Cavalcanti
    I am building my first Silverlight 3 + RI Services application and need some help. It will be deployed in an controlled corporate intranet, 100% windows clients. I have started from the Silverlight Business Application template. These are my requirements: Upon launch the application needs to recognize the currently logged-in user. The application needs to have access to other properties of the user in AD, such as email, full name, and group membership. Group membership is used to grand certain features in the application. A "login as a different user" link is to be always available - Some machines are available throughout the enterprise, logged-in as a certain generic user (verified by the absence of certain membership groups). In this case one can enter credentials and log in (impersonate) to the application as a user different from the one already logged-into the machine. This user is to be used in service calls I have modified the following in the default Business Application template: App.xaml: appsvc:WindowsAuthentication instead of the default FormsAuthentication Web.config: authentication mode="Windows" With these modifications I resolve requirement #1 (get the currently logged-in user). But when I examine RiaContext.Current.User, I don't have access to other properties from AD, such as group memberships. How can I achieve my other requirements? Thanks for your help.

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  • How can I display multiple django modelformset forms in a grouped fieldsets?

    - by JT
    I have a problem with needing to provide multiple model backed forms on the same page. I understand how to do this with single forms, i.e. just create both the forms call them something different then use the appropriate names in the template. Now how exactly do you expand that solution to work with modelformsets? The wrinkle, of course, is that each 'form' must be rendered together in the appropriate fieldset. For example I want my template to produce something like this: <fieldset> <label for="id_base-0-desc">Home Base Description:</label> <input id="id_base-0-desc" type="text" name="base-0-desc" maxlength="100" /> <label for="id_likes-0-icecream">Want ice cream?</label> <input type="checkbox" name="likes-0-icecream" id="id_likes-0-icecream" /> </fieldset> <fieldset> <label for="id_base-1-desc">Home Base Description:</label> <input id="id_base-1-desc" type="text" name="base-1-desc" maxlength="100" /> <label for="id_likes-1-icecream">Want ice cream?</label> <input type="checkbox" name="likes-1-icecream" id="id_likes-1-icecream" /> </fieldset> I am using a loop like this to process the results (after form validation) base_models = base_formset.save(commit=False) like_models = like_formset.save(commit=False) for base_model, likes_model in map(None, base_models, likes_models): which works as I'd expect (I'm using map because the # of forms can be different). The problem is that I can't figure out a way to do the same thing with the templating engine. The system does work if I layout all the base models together then all the likes models after wards, but it doesn't meet the layout requirements. EDIT: Updated the problem statement to be more clear about what exactly I'm processing (I'm processing models not forms in the for loop)

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  • XSLT Pagination

    - by dbomb101
    I have created a xslt document which formats an xml document, but I would like the results from the xslt sheet to be paginated. here is the orginal xlst document <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xsl:for-each select="musicInformation/musicdetails"> <label for="artistname{position()}" id="artistnameLabel{position()}">Artist Name:</label> <span id ="artistname{position()}"><xsl:value-of select="artistname" /></span> <br/> <label for="recordname{position()}" id="recordnameLabel{position()}">Record Name:</label> <span id ="recordname{position()}"><xsl:value-of select="recordname" /></span> <br/> <label for="recordtype{position()}" id="recordtypeLabel{position()}">Record Type:</label> <span id ="recordtype{position()}"><xsl:value-of select="recordtype" /></span> <br/> <label for="format{position()}" id="formatLabel{position()}">Format:</label> <span id ="format{position()}"><xsl:value-of select="format" /></span> <br/> <a href="xmlDetail.php?mid={@m_id}" >See Details</a> <br/><br/> </xsl:for-each> </xsl:template> </xsl:stylesheet>

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  • onmouseover problems with JavaScript (rendered using django and django-imagekit)

    - by Michael Moreno
    I'm using Imagekit. View.py includes: def pics(request): p = Photo.objects.all() return render_to_response('Shots.html', {'p': p}) The following simple code in the template will generate associated images: {% for p in p %} <img src = "{{ p.display.url }}"> <img src = "{{ p.thumbnail_image.url }}"> {% endfor %} I'm attempting to generate a series of thumbnails {{ p.thumbnail_image.url }} which, when mouseover'd, will generate the slightly larger version of the image, {{ p.display.url }} via Javascript. The following code in the template attempts to do so: <html> <head> <HEAD> <script language="Javascript"> { image1 = new Image image2 = new Image image1.src = {{ p.thumbnail_image.url }} image2.src = {{ p.display.url }} </script> </head> <body> {% for p in p %} <a href="" onMouseOver="document.rollover.src= image2.src onMouseOut="document.rollover.src= image1.src"> <img src="{{ p.thumbnail_image.url }}" border=0 name="rollover"></a> {% endfor %} </body> </html> This will display the series of thumbnails, but the larger image will not display when mouseover'd. I believe it has to do with how I'm specifying the variable {{ p.display.url }}.

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  • XSLT: use parameters in xls:sort attributes

    - by fireeyedboy
    How do I apply a parameter to a select and order attribute in a xsl:sort element? I'ld like to do this dynamic with PHP with something like this: $xsl = new XSLTProcessor(); $xslDoc = new DOMDocument(); $xslDoc->load( $this->_xslFilePath ); $xsl->importStyleSheet( $xslDoc ); $xsl->setParameter( '', 'sortBy', 'viewCount' ); $xsl->setParameter( '', 'order', 'descending' ); But I'ld first have to now how to get this to work. I tried the following, but it gives me a 'compilation error' : 'invalid value $order for order'. $sortBy doesn't seem to do anything either: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes"/> <xsl:param name="sortBy" select="viewCount"/> <xsl:param name="order" select="descending"/> <xsl:template match="/"> <media> <xsl:for-each select="media/medium"> <xsl:sort select="$sortBy" order="$order"/> // <someoutput> </xsl:for-each> </media> </xsl:template> </xsl:stylesheet>

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  • How to have a policy class implement a virtual function?

    - by dehmann
    I'm trying to design a policy-based class, where a certain interface is implemented by the policy itself, so the class derives from the policy, which itself is a template (I got this kind of thinking from Alexandrescu's book): #include <iostream> #include <vector> class TestInterface { public: virtual void test() = 0; }; class TestImpl1 { public: void test() {std::cerr << "Impl1" << std::endl;} }; template<class TestPolicy> class Foo : public TestInterface, TestPolicy { }; Then, in the main() function, I call test() on (potentially) various different objects that all implement the same interface: int main() { std::vector<TestInterface*> foos; foos.push_back(new Foo<TestImpl1>()); foos[0]->test(); delete foos[0]; return 0; } It doesn't compile, though, because the following virtual functions are pure within ‘Foo<TestImpl1>’: virtual void TestInterface::test() I thought TestInterface::test() is implemented because we derive from TestImpl1?

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  • WPF: Selecting the Target of an Animation

    - by Phil Sandler
    I am trying to create a simple (I think) animation effect based on a property change in my ViewModel. I would like the target to be a specific textblock in the control template of a custom control, which inherits from Window. From the article examples I've seen, a DataTrigger is the easiest way to accomplish this. It appears that Window.Triggers doesn't support DataTriggers, which led me to try to apply the trigger in the style. The problem I am currently having is that I can't seem to target the TextBlock (or any other child control)--what happens is which the code below is that the animation is applied to the background of the whole window. If I leave off StoryBoard.Target completely, the effect is exactly the same. Is this the right approach with the wrong syntax, or is there an easier way to accomplish this? <Style x:Key="MyWindowStyle" TargetType="{x:Type Window}"> <Setter Property="Template" Value="{StaticResource MyWindowTemplate}"/> <Style.Triggers> <DataTrigger Binding="{Binding ChangeOccurred}" Value="True"> <DataTrigger.EnterActions> <BeginStoryboard> <Storyboard BeginTime="00:00:00" Duration="0:0:2" Storyboard.Target="{Binding RelativeSource={RelativeSource AncestorType=TextBlock}}" Storyboard.TargetProperty="(Background).(SolidColorBrush.Color)"> <ColorAnimation FillBehavior="Stop" From="Black" To="Red" Duration="0:0:0.5" AutoReverse="True"/> </Storyboard> </BeginStoryboard> </DataTrigger.EnterActions> </DataTrigger> </Style.Triggers> </Style>

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  • operator<< cannot output std::endl -- Fix?

    - by dehmann
    The following code gives an error when it's supposed to output just std::endl: #include <iostream> #include <sstream> struct MyStream { std::ostream* out_; MyStream(std::ostream* out) : out_(out) {} std::ostream& operator<<(const std::string& s) { (*out_) << s; return *out_; } }; template<class OutputStream> struct Foo { OutputStream* out_; Foo(OutputStream* out) : out_(out) {} void test() { (*out_) << "OK" << std::endl; (*out_) << std::endl; // ERROR } }; int main(int argc, char** argv){ MyStream out(&std::cout); Foo<MyStream> foo(&out); foo.test(); return EXIT_SUCCESS; } The error is: stream1.cpp:19: error: no match for 'operator<<' in '*((Foo<MyStream>*)this)->Foo<MyStream>::out_ << std::endl' stream1.cpp:7: note: candidates are: std::ostream& MyStream::operator<<(const std::string&) So it can output a string (see line above the error), but not just the std::endl, presumably because std::endl is not a string, but the operator<< definition asks for a string. Templating the operator<< didn't help: template<class T> std::ostream& operator<<(const T& s) { ... } How can I make the code work? Thanks!

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  • Are short tags *that* bad?

    - by Col. Shrapnel
    Everyone here on SO says it's bad, for 3 main reasons: XML is used everywhere You can't control where your script is going to be run short tags are going to be removed in PHP6 But let's see closer at them: Last one is easy - it's just not true. XML is not really a problem. If you want to use short tags, it won't be a problem for you to write a single tag using PHP echo, <?="<?XML...?>"?>. Anyway, why not to leave such a trifle thing for one's own judgment? PHP configuration access. Oh yes, the only thing that can be really considered as a reason. Of course in case you plan to spread your code wide. But if you don't? I think most of scripts being written not for the wide spread, but just for one place. If you can use short tags in that place - why to abandon them? Anyway, it's the only template we are talking about. If you don't like short tags, PHP native template is probably not for you, why not to try Smarty then? Well, the question is: is there any other real reasons to abandon short tags and make it strict recommendation? Or, as it was said, better to leave short tags alone?

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  • Binding DataTemplates (or another aproach)

    - by Bataglião
    Hi all, I'm having some troubles trying to dynamically generate content in WPF and after it bind data. I have the following scenario: TabControl - Dynamically generated TabItems through DataTemplate - inside TabItems, I have dynamic content generated by DataTemplate that I wish to bind (ListBox). The code follows: ::TabControl <TabControl Height="252" HorizontalAlignment="Left" Name="tabControl1" VerticalAlignment="Top" Width="458" Margin="12,12,12,12" ContentTemplate="{StaticResource tabItemContent}"></TabControl> ::The Template for TabControl to generate TabItems <DataTemplate x:Key="tabItemContent"> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition Width="*" /> </Grid.ColumnDefinitions> <Grid.RowDefinitions> <RowDefinition Height="*" /> </Grid.RowDefinitions> <ListBox ItemTemplate="{StaticResource listBoxContent}" ItemsSource="{Binding}"> </ListBox> </Grid> </DataTemplate> ::The template for ListBox Inside each TabItem <DataTemplate x:Key="listBoxContent"> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition Width="22"/> <ColumnDefinition Width="*" /> </Grid.ColumnDefinitions> <Image Grid.Column="0" Source="{Binding Path=PluginIcon}" /> <TextBlock Grid.Column="1" Text="{Binding Path=Text}" /> </Grid> </DataTemplate> So, when I try to do this on code inside a loop to create the tabitems: TabItem tabitem = tabControl1.Items[catIndex] as TabItem; tabitem.DataContext = plugins.ToList(); where 'plugins' is an Enumerable The ListBox is not bounded. I tried also to find the ListBox inside the TabItem to set the ItemSource property but no success at all. Someone have an idea on how to do that? Thanks in advance.

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  • How can I do such a typical unittest?

    - by Malcom.Z
    This is a simple structure in my project: MyAPP--- note--- __init__.py views.py urls.py test.py models.py auth-- ... template--- auth--- login.html register.html note--- noteshow.html media--- css--- ... js--- ... settings.py urls.py __init__.py manage.py I want to make a unittest which can test the noteshow page working propeyly or not. The code: from django.test import TestCase class Note(TestCase): def test_noteshow(self): response = self.client.get('/note/') self.assertEqual(response.status_code, 200) self.assertTemplateUsed(response, '/note/noteshow.html') The problem is that my project include an auth mod, it will force the unlogin user redirecting into the login.html page when they visit the noteshow.html. So, when I run my unittest, in the bash it raise an failure that the response.status_code is always 302 instead of 200. All right though through this result I can check the auth mod is running well, it is not like what I want it to be. OK, the question is that how can I make another unittest to check my noteshow.template is used or not? Thanks for all. django version: 1.1.1 python version: 2.6.4 Use Eclipse for MAC OS

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  • WPF : Multiple views, one DataContext

    - by zapho
    Hi, I'm working on a WPF application which must handle multiple screens (two at this this time). One view can be opened on several screens and user actions must be reflected consistently on all screens. To achieve this, for a given type of view, a single DataContext is instantiated. Then, when a view is displayed on a screen, the unique DataContext is attached to it. So, one DataContext, several views (same type of view/xaml). So far so good. It works quite well in most cases. I do have a problem with a specific view which relies on ItemsControl. These ItemsControl are used to display UIElements dynamically build in the ViewModel/DataContext (C# code). These UIElements are mostly Path objects. Example : <ItemsControl ItemsSource="{Binding WindVectors}"> <ItemsControl.Template> <ControlTemplate TargetType="{x:Type ItemsControl}"> <Canvas IsItemsHost="True" /> </ControlTemplate> </ItemsControl.Template> </ItemsControl> Here, WindVectors is a ObservableCollection<UIElement>. When the view is opened the first time, everything is fine. The problem is that when the view is opened one another screen, all ItemsControl are removed from the first screen and displayed one the second screen. Other WPF components (TextBlock for instance) on this view react normally and are displayed on both screens. Any help would be greatly appreciated. Thanks. Fabrice

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  • WPF Custom ListBox as Buttons Click not firing

    - by Ryan
    I am attempting to have a ListBox of TextBoxes with click events. I have read that one way to achieve this was to have a list of Buttons and call ButtonBase.Click="" on the ListBox. This was not working. Any advice as to how I would hook up a click event to the listbox items? Thanks <Window.Resources> <ControlTemplate x:Key="MouseOverFocusTemplate" > <Grid> <Grid.RowDefinitions> <RowDefinition Height="55*" /> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition Width="Auto" /> <ColumnDefinition Width="*" /> </Grid.ColumnDefinitions> <TextBox Width="290" TextAlignment="Left" VerticalContentAlignment="Center" BorderThickness="0" BorderBrush="Transparent" Foreground="#FF6FB8FD" FontSize="24" TextWrapping="Wrap" Text="{Binding .}" Grid.Column="1" Grid.Row="1" MinHeight="55" Cursor="Hand" IsReadOnly="True" FontFamily="Arial" > <TextBox.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF013B73" Offset="0.501"/> <GradientStop Color="#FF091F34"/> <GradientStop Color="#FF014A8F" Offset="0.5"/> <GradientStop Color="#FF003363" Offset="1"/> </LinearGradientBrush> </TextBox.Background> </TextBox> </Grid> </ControlTemplate> <Style x:Key="MouseOverFocusStyle" TargetType="{x:Type TextBox}"> <Setter Property="Template" Value="{StaticResource MouseOverFocusTemplate}"/> </Style> <ControlTemplate x:Key="LostFocusTemplate" > <Grid> <Grid.RowDefinitions> <RowDefinition Height="55*" /> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition Width="Auto" /> <ColumnDefinition Width="*" /> </Grid.ColumnDefinitions> <TextBox Width="290" TextAlignment="Left" VerticalContentAlignment="Center" BorderThickness="0" BorderBrush="Transparent" Foreground="#FF6FB8FD" FontSize="24" TextWrapping="Wrap" Text="{Binding .}" Grid.Column="1" Grid.Row="1" MinHeight="55" Cursor="Hand" IsReadOnly="True" FontFamily="Arial" > <TextBox.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <LinearGradientBrush.RelativeTransform> <TransformGroup> <ScaleTransform CenterX="0.5" CenterY="0.5"/> <SkewTransform CenterX="0.5" CenterY="0.5"/> <RotateTransform CenterX="0.5" CenterY="0.5"/> <TranslateTransform/> </TransformGroup> </LinearGradientBrush.RelativeTransform> <GradientStop Color="#FF091F34" Offset="1"/> <GradientStop Color="#FF002F5C" Offset="0.4"/> </LinearGradientBrush> </TextBox.Background> </TextBox> </Grid> </ControlTemplate> <Style x:Key="LostFocusStyle" TargetType="{x:Type TextBox}"> <Setter Property="Template" Value="{StaticResource LostFocusTemplate}"/> </Style> <ControlTemplate x:Key="GotFocusTemplate" > <Grid> <Grid.RowDefinitions> <RowDefinition Height="55*" /> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition Width="Auto" /> <ColumnDefinition Width="*" /> </Grid.ColumnDefinitions> <TextBox Width="290" TextAlignment="Left" VerticalContentAlignment="Center" BorderThickness="0" BorderBrush="Transparent" Foreground="#FFE38E27" FontSize="24" TextWrapping="Wrap" Text="{Binding .}" Grid.Column="1" Grid.Row="1" MinHeight="55" Cursor="Hand" IsReadOnly="True" FontFamily="Arial" > <TextBox.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="Black" Offset="0.501"/> <GradientStop Color="#FF091F34"/> <GradientStop Color="#FF002F5C" Offset="0.5"/> </LinearGradientBrush> </TextBox.Background> </TextBox> </Grid> </ControlTemplate> <Style x:Key="GotFocusStyle" TargetType="{x:Type TextBox}"> <Setter Property="Template" Value="{StaticResource GotFocusTemplate}"/> </Style> <Style TargetType="{x:Type Button}" x:Key="listButton"> <Setter Property="Template"> <Setter.Value> <ControlTemplate TargetType="Button"> <Border BorderBrush="Black" BorderThickness="1" Margin="-2,0,0,-1"> <Grid> <Grid.RowDefinitions> <RowDefinition Height="55*" /> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition Width="Auto" /> <ColumnDefinition Width="*" /> </Grid.ColumnDefinitions> <Grid.RenderTransform> <TransformGroup> <ScaleTransform ScaleX="1" ScaleY="1"/> <SkewTransform AngleX="0" AngleY="0"/> <RotateTransform Angle="0"/> <TranslateTransform X="0" Y="0"/> </TransformGroup> </Grid.RenderTransform> <!--<ScrollViewer x:Name="PART_ContentHost" />--> <TextBox Width="290" TextAlignment="Left" VerticalContentAlignment="Center" BorderThickness="0" BorderBrush="Transparent" Foreground="#FF6FB8FD" FontSize="24" Style="{StaticResource LostFocusStyle}" TextWrapping="Wrap" Text="{Binding .}" Grid.Column="1" Grid.Row="1" MinHeight="55" Cursor="Hand" IsReadOnly="True" FontFamily="Arial" Name="bar" > <TextBox.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <LinearGradientBrush.RelativeTransform> <TransformGroup> <ScaleTransform CenterX="0.5" CenterY="0.5"/> <SkewTransform CenterX="0.5" CenterY="0.5"/> <RotateTransform CenterX="0.5" CenterY="0.5"/> <TranslateTransform/> </TransformGroup> </LinearGradientBrush.RelativeTransform> <GradientStop Color="#FF091F34" Offset="1"/> <GradientStop Color="#FF002F5C" Offset="0.4"/> </LinearGradientBrush> </TextBox.Background> </TextBox> </Grid> </Border> <ControlTemplate.Triggers> <Trigger Property="IsMouseOver" Value="true"> <Setter TargetName="bar" Property="Style" Value="{StaticResource MouseOverFocusStyle}" /> </Trigger> </ControlTemplate.Triggers> </ControlTemplate> </Setter.Value> </Setter> </Style> <DataTemplate x:Key="CustomListData" DataType="{x:Type ListBoxItem}"> <Button Style="{StaticResource listButton}" /> </DataTemplate> </Window.Resources> <Window.DataContext> <ObjectDataProvider ObjectType="{x:Type local:ImageLoader}" MethodName="LoadImages" /> </Window.DataContext> <ListBox ItemsSource="{Binding}" Width="320" Background="#FF021422" BorderBrush="#FF1C4B79"> <ListBox.Resources> <SolidColorBrush x:Key="{x:Static SystemColors.HighlightBrushKey}">Transparent</SolidColorBrush> <Style TargetType="{x:Type ListBox}"> <Setter Property="ItemTemplate" Value="{StaticResource CustomListData }" /> <Setter Property="ScrollViewer.HorizontalScrollBarVisibility" Value="Disabled" /> </Style> </ListBox.Resources> </ListBox>

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  • Get nodes value one by one in xslt

    - by Audy
    I am using XSl file in which I am reading values from xml node and creating another xml file. Following is the part of input xml from which I want to read value node one by one. Input Xml: <RoomsInvs> <RoomInv> <ProvisionalId Id="13-0000000007">13-0000000007</ProvisionalId> </RoomInv> <RoomInv> <ProvisionalId Id="13-0000000008">13-0000000008</ProvisionalId> </RoomInv> </RoomsInvs> Xsl Applied: <values> <xsl:apply-templates select="//RoomsInvs/RoomInv" /> </values> <xsl:template match="RoomInv" > <tempID> <xsl:value-of select="ProvisionalId[position()]"/> </tempID> </xsl:template> Output Getting: <values> <tempID>13-0000000007</tempID> <tempID>13-0000000007</tempID> </values> Output I want: <values> <tempID>13-0000000007</tempID> <tempID>13-0000000008</tempID> </values>

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  • What is the rationale to non allow overloading of C++ conversions operator with non-member functio

    - by Vicente Botet Escriba
    C++0x has added explicit conversion operators, but they must always be defined as members of the Source class. The same applies to the assignment operator, it must be defined on the Target class. When the Source and Target classes of the needed conversion are independent of each other, neither the Source can define a conversion operator, neither the Target can define a constructor from a Source. Usually we get it by defining a specific function such as Target ConvertToTarget(Source& v); If C++0x allowed to overload conversion operator by non member functions we could for example define the conversion implicitly or explicitly between unrelated types. template < typename To, typename From operator To(const From& val); For example we could specialize the conversion from chrono::time_point to posix_time::ptime as follows template < class Clock, class Duration operator boost::posix_time::ptime( const boost::chrono::time_point& from) { using namespace boost; typedef chrono::time_point time_point_t; typedef chrono::nanoseconds duration_t; typedef duration_t::rep rep_t; rep_t d = chrono::duration_cast( from.time_since_epoch()).count(); rep_t sec = d/1000000000; rep_t nsec = d%1000000000; return posix_time::from_time_t(0)+ posix_time::seconds(static_cast(sec))+ posix_time::nanoseconds(nsec); } And use the conversion as any other conversion. So the question is: What is the rationale to non allow overloading of C++ conversions operator with non-member functions?

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  • error: expected constructor, destructor, or type conversion before '(' token

    - by jonathanasdf
    include/TestBullet.h:12: error: expected constructor, destructor, or type conver sion before '(' token I hate C++ error messages... lol ^^ Basically, I'm following what was written in this post to try to create a factory class for bullets so they can be instantiated from a string, which will be parsed from an xml file, because I don't want to have a function with a switch for all of the classes because that looks ugly. Here is my TestBullet.h: #pragma once #include "Bullet.h" #include "BulletFactory.h" class TestBullet : public Bullet { public: void init(BulletData& bulletData); void update(); }; REGISTER_BULLET(TestBullet); <-- line 12 And my BulletFactory.h: #pragma once #include <string> #include <map> #include "Bullet.h" #define REGISTER_BULLET(NAME) BulletFactory::reg<NAME>(#NAME) #define REGISTER_BULLET_ALT(NAME, CLASS) BulletFactory::reg<CLASS>(NAME) template<typename T> Bullet * create() { return new T; } struct BulletFactory { typedef std::map<std::string, Bullet*(*)()> bulletMapType; static bulletMapType map; static Bullet * createInstance(char* s) { std::string str(s); bulletMapType::iterator it = map.find(str); if(it == map.end()) return 0; return it->second(); } template<typename T> static void reg(std::string& s) { map.insert(std::make_pair(s, &create<T>)); } }; Thanks in advance.

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  • Dymanic if statement evaluation problem with string comparison

    - by Mani
    I tried the example given in http://forums.sun.com/thread.jspa?threadID=780576&tstart=67605 to create if statement dynamically. But it is not working fine. Instead of using "age" variable as integer, i have used string in the below example. I am getting "fail" as answer instead of "success". Can anyone help me? / To change this template, choose Tools | Templates and open the template in the editor. / import java.lang.reflect.*; import bsh.Interpreter; public class Main { public static String d; public static void main(String args[]) { try { String age = "30"; String cond = "age==30"; Interpreter i = new Interpreter(); i.set("age", age); System.out.println(" sss" + i.get("age")); if((Boolean)i.eval(cond)) { System.out.println("success"); } else { System.out.println("fail"); } } catch (Throwable e) { System.err.println(e); } } } Thanks, Mani

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  • Problems with reading into buffer using boost::asio::async_read

    - by Max
    Good day. I have a Types.hpp file in my project. And within it i have: .... namespace RC { ..... ..... struct ViewSettings { .... }; ..... } In the Server.cpp file I'm including this Types.hpp file, and i have there: class Session { ..... RC::ViewSettings tmp; boost::asio::async_read(socket_, boost::asio::buffer(&tmp, sizeof(RC::ViewSettings)), boost::bind(&Session::Finish_Reading_Data, shared_from_this(), boost::asio::placeholders::error)); ..... } And during the compilation i have an errors: error C2825: 'F': must be a class or namespace when followed by '::' : see reference to class template instantiation 'boost::_bi::result_traits<R,F>' being compiled with [ R=boost::_bi::unspecified, F=void (__thiscall Session::* )(void) ] : see reference to class template instantiation 'boost::_bi::bind_t<R,F,L>' being compiled with [ R=boost::_bi::unspecified, F=void (__thiscall Session::* )(void), L=boost::_bi::list2<boost::_bi::value<boost::shared_ptr<Session>>,boost::arg<1>> ] error C2039: 'result_type' : is not a member of '`global namespace'' And the code like this works in proper way: int w; boost::asio::async_read(socket_, boost::asio::buffer(&w, sizeof(int)), boost::bind(&Session::Handle_Read_Width, shared_from_this(), boost::asio::placeholders::error)); Please, help. What's the problem here? Thanks in advance.

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  • Is MVC 2 client-side validation broken in Visual Studio 2010 RC?

    - by Will
    I can't seem to get client side validation working with the version of MVC released with Visual Studio 2010 RC. I've tried it with two projects -- one upgrade from 1.0, and one using the template that came with VS. I'd think the template version would work, but it doesn't. Added the following scripts: <script type="text/javascript" src="<%= Url.Content("~/Scripts/MicrosoftMvcValidation.js") %>"> </script> <script type="text/javascript" src="<%= Url.Content("~/Scripts/jquery.validate.js")%>"> </script> which are downloaded to the client correctly. Added the following to my form page: <% Html.EnableClientValidation(); %> <%--yes, am aware of the EndForm() bug! --%> <% using (Html.BeginForm()) { %> <%--snip --%> and I can see the client validation scripts have been added to the bottom of the form. But still client validation never happens. What is worse is that in my upgraded project, the client validation scripts are never output in the page! PLEASE NOTE: I am specifically asking about the version of MVC2 that came with VS2010 RC. Also, I do know how to google; please don't waste anybody's time searching and answering if you aren't familiar with this issue in the release candidate of Visual Studio. Thanks.

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  • new Facebook Like button for Blogger

    - by David
    I want to add the new facebook like button to my blogger website. http://developers.facebook.com/docs/reference/plugins/like I have to pass the url to the blog posts in the iframe src tag. I can get the blogger posts url from <data:post.url/> but I can't put that in a src string because Bloggers template system is weird. I want to do this:<iframe allowTransparency='true' frameborder='0' scrolling='no' src='http://www.facebook.com/plugins/like.php?href=<data:post.url/>&amp;layout=standard&amp;show-faces=true&amp;width=450&amp;action=like&amp;colorscheme=light' style='border:none; overflow:hidden; width:450px; height:px'/>but blogger complains: "Your template could not be parsed as it is not well-formed. Please make sure all XML elements are closed properly. XML error message: The value of attribute "src" associated with an element type "null" must not contain the '<' character." Anybody have this working yet?

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  • RSS feed generated by SharePoint has a stylesheet tag and how to remove that

    - by iHeartDucks
    The feed which SharePoint Generates is here (I copied it to pastie because I thought it would be clear there) However, the xml file comes with a style sheet tag. How do I remove that? Does SharePoint always generate that? Due to the presence of that tag, I am unable to apply another style sheet of my own using the XML WebPart. EDIT: I don't think the issue is related to the style sheet. If I copy the xml and paste it in the "Xml Editor" of the Web Part everything works just fine. If I provide the URL, that is when I do not see any data. This is my XSL file <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" exclude-result-prefixes="x d ddwrt xsl msxsl" xmlns:x="http://www.w3.org/2001/XMLSchema" xmlns:d="http://schemas.microsoft.com/sharepoint/dsp" xmlns:ddwrt="http://schemas.microsoft.com/WebParts/v2/DataView/runtime" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt"> <xsl:output method="html" version="1.0" encoding="iso-8859-1" indent="yes"/> <xsl:template match="/"> <xsl:value-of select="count(rss)" /> <xsl:value-of select="count(rss/channel)" /> <xsl:value-of select="count(rss/channel/item)" /> <xsl:for-each select="rss/channel/item"> <xsl:value-of select="title" /> </xsl:for-each> </xsl:template> </xsl:stylesheet> Pastie link

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  • XSLT pass node into CDATA JS

    - by davomarti
    I have the following xml <AAA> <BBB>Total</BBB> </AAA> Transforming it with the following xslt using the xsl:copy-of tag, because I want to use the xml to create a xml doc in js. <xsl:template match="/"> <![CDATA[ function myFunc() { xmlStr = ']]><xsl:copy-of select="/"/><![CDATA['; } ]]> </xsl:template> The output looks like this function myFunc() { xmlStr = '<AAA> <BBB>Total</BBB> </AAA>'; } JS doesn't like this because of the missing semicolons ending the lines. How can I fix my xsl to get the below result: function myFunc() { xmlStr = '<AAA><BBB>Total</BBB></AAA>'; } I've tried normalize-space() and translate() but they strip the tags from the xml. Thanks!

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  • error wordpress, adjusted sidebar.php to show latest 10 posts

    - by Andy
    Hi, I'm trying to edit my sidebar.php file in my current them WP is using to display the last # of posts (only the titles) as links. I tried using the example of http://codex.wordpress.org/Integrating_WordPress_with_Your_Website but I always get the error on the line that states where the file wp-blog-header can be found. the error when opening the index blog page where the sidebar should be shown: // Get the last 3 posts. Warning: require(/blog/folder/wp-blog-header.php) [function.require]: failed to open stream: No such file or directory in /blog/folder/wp-content/themes/default/sidebar.php on line 7 So what is wrong? Is there a way to permanently embed a function in my html template page that retrieves the latest few posts everytime an article is displayed on the template page? the code: <?php require('/the/path/to/your/wp-blog-header.php'); ?> <?php $posts = get_posts('numberposts=10&order=ASC&orderby=post_title'); foreach ($posts as $post) : start_wp(); ?> <?php the_title(); ?> <?php the_excerpt(); ?> <?php endforeach; ?>

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