Why first arg to execve() must be path to executable
- by EBM
I understand that execve() and family require the first argument of its argument array to be the same as the executable that is also pointed to by its first argument. That is, in this:
execve(prog, args, env);
args[0] will usually be the same as prog. But I can't seem to find information as to why this is.
I also understand that executables…
