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  • django crispy-forms inline forms

    - by abolotnov
    I'm trying to adopt crispy-forms and bootstrap and use as much of their functionality as possible instead of inventing something over and over again. Is there a way to have inline forms functionality with crispy-forms/bootstrap like django-admin forms have? Here is an example: class NewProjectForm(forms.Form): name = forms.CharField(required=True, label=_(u'???????? ???????'), widget=forms.TextInput(attrs={'class':'input-block-level'})) group = forms.ModelChoiceField(required=False, queryset=Group.objects.all(), label=_(u'?????? ????????'), widget=forms.Select(attrs={'class':'input-block-level'})) description = forms.CharField(required=False, label=_(u'???????? ???????'), widget=forms.Textarea(attrs={'class':'input-block-level'})) class Meta: model = Project fields = ('name','description','group') def __init__(self, *args, **kwargs): self.helper = FormHelper() self.helper.form_class = 'horizontal-form' self.helper.form_action = 'submit_new_project' self.helper.layout = Layout( Field('name', css_class='input-block-level'), Field('group', css_class='input-block-level'), Field('description',css_class='input-block-level'), ) self.helper.add_input(Submit('submit',_(u'??????? ??????'))) self.helper.add_input(Submit('cancel',_(u'? ?????????'))) super(NewProjectForm, self).__init__(*args, **kwargs) it will display a decent form: How do I go about adding a form that basically represents this model: class Link(models.Model): name = models.CharField(max_length=255, blank=False, null=False, verbose_name=_(u'????????')) url = models.URLField(blank=False, null=False, verbose_name=_(u'??????')) project = models.ForeignKey('Project') So there will be a project and name/url links and way to add many, like same thing is done in django-admin where you are able to add extra 'rows' with data related to your main model. On the sreenshot below you are able to fill out data for 'Question' object and below that you are able to add data for QuestionOption objects -you are able to click the '+' icon to add as many QuestionOptions as you want. I'm not looking for a way to get the forms auto-generated from models (that's nice but not the most important) - is there a way to construct a form that will let you add 'rows' of data like django-admin does?

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  • Problem with Informix JDBC, MONEY and decimal separator in string literals

    - by Michal Niklas
    I have problem with JDBC application that uses MONEY data type. When I insert into MONEY column: insert into _money_test (amt) values ('123.45') I got exception: Character to numeric conversion error The same SQL works from native Windows application using ODBC driver. I live in Poland and have Polish locale and in my country comma separates decimal part of number, so I tried: insert into _money_test (amt) values ('123,45') And it worked. I checked that in PreparedStatement I must use dot separator: 123.45. And of course I can use: insert into _money_test (amt) values (123.45) But some code is "general", it imports data from csv file and it was safe to put number into string literal. How to force JDBC to use DBMONEY (or simply dot) in literals? My workstation is WinXP. I have ODBC and JDBC Informix client in version 3.50 TC5/JC5. I have set DBMONEY to just dot: DBMONEY=. EDIT: Test code in Jython: import sys import traceback from java.sql import DriverManager from java.lang import Class Class.forName("com.informix.jdbc.IfxDriver") QUERY = "insert into _money_test (amt) values ('123.45')" def test_money(driver, db_url, usr, passwd): try: print("\n\n%s\n--------------" % (driver)) db = DriverManager.getConnection(db_url, usr, passwd) c = db.createStatement() c.execute("delete from _money_test") c.execute(QUERY) rs = c.executeQuery("select amt from _money_test") while (rs.next()): print('[%s]' % (rs.getString(1))) rs.close() c.close() db.close() except: print("there were errors!") s = traceback.format_exc() sys.stderr.write("%s\n" % (s)) print(QUERY) test_money("com.informix.jdbc.IfxDriver", 'jdbc:informix-sqli://169.0.1.225:9088/test:informixserver=ol_225;DB_LOCALE=pl_PL.CP1250;CLIENT_LOCALE=pl_PL.CP1250;charSet=CP1250', 'informix', 'passwd') test_money("sun.jdbc.odbc.JdbcOdbcDriver", 'jdbc:odbc:test', 'informix', 'passwd') Results when I run money literal with dot and comma: C:\db_examples>jython ifx_jdbc_money.py insert into _money_test (amt) values ('123,45') com.informix.jdbc.IfxDriver -------------- [123.45] sun.jdbc.odbc.JdbcOdbcDriver -------------- there were errors! Traceback (most recent call last): File "ifx_jdbc_money.py", line 16, in test_money c.execute(QUERY) SQLException: java.sql.SQLException: [Informix][Informix ODBC Driver][Informix]Character to numeric conversion error C:\db_examples>jython ifx_jdbc_money.py insert into _money_test (amt) values ('123.45') com.informix.jdbc.IfxDriver -------------- there were errors! Traceback (most recent call last): File "ifx_jdbc_money.py", line 16, in test_money c.execute(QUERY) SQLException: java.sql.SQLException: Character to numeric conversion error sun.jdbc.odbc.JdbcOdbcDriver -------------- [123.45]

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  • Does Django cache url regex patterns somehow?

    - by Emre Sevinç
    I'm a Django newbie who needs help: Even though I change some urls in my urls.py I keep on getting the same error message from Django. Here is the relevant line from my settings.py: ROOT_URLCONF = 'mydjango.urls' Here is my urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^mydjango/', include('mydjango.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: #(r'^admin/doc/', include(django.contrib.admindocs.urls)), # (r'^polls/', include('mydjango.polls.urls')), (r'^$', 'mydjango.polls.views.homepage'), (r'^polls/$', 'mydjango.polls.views.index'), (r'^polls/(?P<poll_id>\d+)/$', 'mydjango.polls.views.detail'), (r'^polls/(?P<poll_id>\d+)/results/$', 'mydjango.polls.views.results'), (r'^polls/(?P<poll_id>\d+)/vote/$', 'mydjango.polls.views.vote'), (r'^polls/randomTest1/', 'mydjango.polls.views.randomTest1'), (r'^admin/', include(admin.site.urls)), ) So I expect that whenever I visit http://mydjango.yafz.org/polls/randomTest1/ the mydjango.polls.views.randomTest1 function should run because in my polls/views.py I have the relevant function: def randomTest1(request): # mainText = request.POST['mainText'] return HttpResponse("Default random test") However I keep on getting the following error message: Page not found (404) Request Method: GET Request URL: http://mydjango.yafz.org/polls/randomTest1 Using the URLconf defined in mydjango.urls, Django tried these URL patterns, in this order: 1. ^$ 2. ^polls/$ 3. ^polls/(?P<poll_id>\d+)/$ 4. ^polls/(?P<poll_id>\d+)/results/$ 5. ^polls/(?P<poll_id>\d+)/vote/$ 6. ^admin/ 7. ^polls/randomTest/$ The current URL, polls/randomTest1, didn't match any of these. I'm surprised because again and again I check urls.py and there is no ^polls/randomTest/$ in it, but there is ^polls/randomTest1/' It seems like Django is somehow storing the previous contents of urls.py and I just don't know how to make my latest changes effective. Any ideas? Why do I keep on seeing some old version of regexes when I try to load that page even though I changed my urls.py?

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  • Foreign keys in django admin list display

    - by Olivier
    If a django model contains a foreign key field, and if that field is shown in list mode, then it shows up as text, instead of displaying a link to the foreign object. Is it possible to automatically display all foreign keys as links instead of flat text? (of course it is possible to do that on a field by field basis, but is there a general method?) Example: class Author(models.Model): ... class Post(models.Model): author = models.ForeignKey(Author) Now I choose a ModelAdmin such that the author shows up in list mode: class PostAdmin(admin.ModelAdmin): list_display = [..., 'author',...] Now in list mode, the author field will just use the __unicode__ method of the Author class to display the author. On the top of that I would like a link pointing to the url of the corresponding author in the admin site. Is that possible? Manual method: For the sake of completeness, I add the manual method. It would be to add a method author_link in the PostAdmin class: def author_link(self, item): return '<a href="../some/path/%d">%s</a>' % (item.id, unicode(item)) author_link.allow_tags = True That will work for that particular field but that is not what I want. I want a general method to achieve the same effect. (One of the problems is how to figure out automatically the path to an object in the django admin site.)

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  • feedparser - various errors

    - by Eiriks
    I need feedparser (se http://www.feedparser.org) for a project, and want to keep third party modules in a separate folder. I did this by adding a folder to my python path, and putting relevant modules there, among them feedparser. This first attempt to import feedparser resulted in import feedparser Traceback (most recent call last): File "", line 1, in File "/home/users/me/modules/feedparser.py", line 1 ed socket timeout; added support for chardet library ^ SyntaxError: invalid syntax I found the text "socket timeout; added..." in the comments at the bottom of the file, removed these comments, and tried again: import feedparser Traceback (most recent call last): File "", line 1, in File "/home/users/me/modules/feedparser.py", line 1 = [(key, value) for key, value in attrs if key in self.acceptable_attributes] ^ IndentationError: unexpected indent Ok, so some indent error. I made sure the indent in the function in question where ok (moved some line breaks down to no-indent). And tried again: import feedparser Traceback (most recent call last): File "", line 1, in File "/home/users/me/modules/feedparser.py", line 1 , value) for key, value in attrs if key in self.acceptable_attributes] ^ SyntaxError: invalid syntax As much I google, I cannot find anything wrong with the syntax: def unknown_starttag(self, tag, attrs): if not tag in self.acceptable_elements: if tag in self.unacceptable_elements_with_end_tag: self.unacceptablestack += 1 return attrs = self.normalize_attrs(attrs) attrs = [(key, value) for key, value in attrs if key in self.acceptable_attributes] _BaseHTMLProcessor.unknown_starttag(self, tag, attrs) Now what? Is my approach all wrong? Why do I keep producing these errors in a module that seems so well tested and trusted?

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  • Overwrite clean method in Django Custom Forms

    - by John
    Hi I have wrote a custom widget class AutoCompleteWidget(widgets.TextInput): """ widget to show an autocomplete box which returns a list on nodes available to be tagged """ def render(self, name, value, attrs=None): final_attrs = self.build_attrs(attrs, name=name) if not self.attrs.has_key('id'): final_attrs['id'] = 'id_%s' % name if not value: value = '[]' jquery = u""" <script type="text/javascript"> $("#%s").tokenInput('%s', { hintText: "Enter the word", noResultsText: "No results", prePopulate: %s, searchingText: "Searching..." }); $("body").focus(); </script> """ % (final_attrs['id'], reverse('ajax_autocomplete'), value) output = super(AutoTagWidget, self).render(name, "", attrs) return output + mark_safe(jquery) class MyForm(forms.Form): AutoComplete = forms.CharField(widget=AutoCompleteWidget) this widget uses a jquery function which autocompletes a word based on entries from the database. You can preset its initial values by setting prePopulate to a json string in the form ['name': 'some name', 'id': 'some id'] I do this by setting the inital value of the form field to this json string jquery_string = ['name': 'some name', 'id': 'some id'] form = MyForm(initial={'AutoComplete':jquery_string}) When submitting the form the the value of AutoComplete is returned as a comma seperated list of the selected ids e.g. 12,45,43,66 which if what I want. However if there is an error in the form, for example a required field has not been entered the value of the AutoComplete field is now 12,45,43,66 and not the json string which it requires. What is the best way to solve this. I was thinking about overwriting the clean method in the form class but I'm not sure how to find out if any other element has returned an error. e.g. if forms.errors form.cleaned_date['autocomplete'] = json string return form.cleaned_data Thanks

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  • Dynamically create and save image with Django and PIL/Django-Photologue

    - by Travis
    I want to generate a page of html with dynamic content and then save the result as an image as well as display the page to the user. So, user signs up to attend conference and gives their name and org. That data is combined with html/css elements to show what their id badge for the conference will look like (their name and org on top of our conference logo background) for preview. Upon approval, the page is saved on the server to an image format (PNG, PDF or JPG) to be printed onto a physical badge by an admin later. I am using Django and django-photologue powered by PIL. The view might look like this # app/views.py def badgepreview(request, attendee_id): u = User.objects.get(id=attendee_id) name = u.name org = u.org return render_to_response('app/badgepreview.html', {'name':name,'org':org,}, context_instance = RequestContext(request), ) The template could look like this {# templates/app/badgepreview.html #} {% extends "base.html" %} {% block page_body %} <div style='background:url(/site_media/img/logo_bg.png) no-repeat;'> <h4>{{ name }}</h4> <h4>{{ org }}</h4> </div> {% endblock %} simple, but how do I save the result? Or is there a better way to get this done?

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  • ActiveRecordStore ruby

    - by Andy
    I've had two previous questions about active record store that all came down to the same thing. Here's what I want: I want to access the session at any time and see who is online right now and access their session variable from anywhere. I need this because: Users are separated into groups. If one person logs in he receives an api token that I receive from some third party site. If a person from the same group logs in he needs to have that same api token in his session. I cannot regenerate new api tokens on a per call basis. I think active record store is a perfect solution for me, however, I have a problem implementing it!!! InvalidAuthenticityToken keeps getting thrown because I used to use the default cookie store. Thus I made this script to delete cookies but it does not seem to work: In application controller after_filter :delete_cookie def delete_cookie puts "deleting cookies" cookies.to_hash.each_pair do |k, v| puts k cookies.delete(k) end end The only other response I got was to remove protect from forgery. http://stackoverflow.com/questions/2941664/activerecordstore-invalidauthenticitytoken

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  • Populating Models from other Models in Django?

    - by JT
    This is somewhat related to the question posed in this question but I'm trying to do this with an abstract base class. For the purposes of this example lets use these models: class Comic(models.Model): name = models.CharField(max_length=20) desc = models.CharField(max_length=100) volume = models.IntegerField() ... <50 other things that make up a Comic> class Meta: abstract = True class InkedComic(Comic): lines = models.IntegerField() class ColoredComic(Comic): colored = models.BooleanField(default=False) In the view lets say we get a reference to an InkedComic id since the tracer, err I mean, inker is done drawing the lines and it's time to add color. Once the view has added all the color we want to save a ColoredComic to the db. Obviously we could do inked = InkedComic.object.get(pk=ink_id) colored = ColoredComic() colored.name = inked.name etc, etc. But really it'd be nice to do: colored = ColoredComic(inked_comic=inked) colored.colored = True colored.save() I tried to do class ColoredComic(Comic): colored = models.BooleanField(default=False) def __init__(self, inked_comic = False, *args, **kwargs): super(ColoredComic, self).__init__(*args, **kwargs) if inked_comic: self.__dict__.update(inked_comic.__dict__) self.__dict__.update({'id': None}) # Remove pk field value but it turns out the ColoredComic.objects.get(pk=1) call sticks the pk into the inked_comic keyword, which is obviously not intended. (and actually results in a int does not have a dict exception) My brain is fried at this point, am I missing something obvious, or is there a better way to do this?

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  • Why is it so difficult to get a working IDE for Scala?

    - by Alex R
    I recently gave up trying to use Scala in Eclipse (basic stuff like completion doesn't work). So now I'm trying IntelliJ. I'm not getting very far. This was the original error. See below for update: Scala signature Predef has wrong version Expected 5.0 found: 4.1 in .... scala-library.jar I tried both versions 2.7.6 and 2.8 RC1 of scala-*.jar, the result was the same. JDK is 1.6.u20. UPDATE Today I uninstalled IntelliJ 9.0.1, and installed 9.0.2 Early Availability, with the 4/14 stable version of the Scala plug-in. Then I setup a project from scratch through the wizards: new project from scratch JDK is 1.6.u20 accept the default (project) instead of global / module accept the download of Scala 2.8.0beta1 into project's lib folder Created a new class: object hello { def main(args: Array[String]) { println("hello: " + args); } } For my efforts, I now have a brand-new error :) Here it is: Scalac internal error: class java.lang.ClassNotFoundException [java.net.URLClassLoader$1.run(URLClassLoader.java:202), java.security.AccessController.doPrivileged(Native Method), java.net.URLClassLoader.findClass(URLClassLoader.java:190), java.lang.ClassLoader.loadClass(ClassLoader.java:307), sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301), java.lang.ClassLoader.loadClass(ClassLoader.java:248), java.lang.Class.forName0(Native Method), java.lang.Class.forName(Class.java:169), org.jetbrains.plugins.scala.compiler.rt.ScalacRunner.main(ScalacRunner.java:72)] Thanks

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  • Problem with boost::find_format_all, boost::regex_finder and custom regex formatter (bug boost 1.42)

    - by Nikko
    I have a code that has been working for almost 4 years (since boost 1.33) and today I went from boost 1.36 to boost 1.42 and now I have a problem. I'm calling a custom formatter on a string to format parts of the string that match a REGEX. For instance, a string like: "abc;def:" will be changed to "abc\2Cdef\3B" if the REGEX contains "([;:])" boost::find_format_all( mystring, boost::regex_finder( REGEX ), custom_formatter() ); The custom formatter looks like this: struct custom_formatter() { template< typename T > std::string operator()( const T & s ) const { std::string matchStr = s.match_results().str(1); // perform substitutions return matchStr; } } This worked fine but with boost 1.42 I know have "non initialized" s.match_results() which yield to boost::exception_detail::clone_implINS0_::error_info_injectorISt11logic_errorEEEE - Attempt to access an uninitialzed boost::match_results< class. This means that sometimes I am in the functor to format a string but there is no match. Am I doing something wrong? Or is it normal to enter the functor when there is no match and I should check against something? for now my solution is to try{}catch(){} the exception and everything works fine, but somehow that doesn't feel very good. EDIT1 Actually I have a new empty match at the end of each string to parse. EDIT2 : one solution inspired by ablaeul template< typename T > std::string operator()( const T & s ) const { if( s.begin() == s.end() ) return std::string(); std::string matchStr = s.match_results().str(1); // perform substitutions return matchStr; } *EDIT3 Seems to be a bug in (at least) boost 1.42 *

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  • How do I copy a python function to a remote machine and then execute it?

    - by Hugh
    I'm trying to create a construct in Python 3 that will allow me to easily execute a function on a remote machine. Assuming I've already got a python tcp server that will run the functions it receives, running on the remote server, I'm currently looking at using a decorator like @execute_on(address, port) This would create the necessary context required to execute the function it is decorating and then send the function and context to the tcp server on the remote machine, which then executes it. Firstly, is this somewhat sane? And if not could you recommend a better approach? I've done some googling but haven't found anything that meets these needs. I've got a quick and dirty implementation for the tcp server and client so fairly sure that'll work. I can get a string representation the function (e.g. func) being passed to the decorator by import inspect string = inspect.getsource(func) which can then be sent to the server where it can be executed. The problem is, how do I get all of the context information that the function requires to execute? For example, if func is defined as follows, import MyModule def func(): result = MyModule.my_func() MyModule will need to be available to func either in the global context or funcs local context on the remote server. In this case that's relatively trivial but it can get so much more complicated depending on when and how import statements are used. Is there an easy and elegant way to do this in Python? The best I've come up with at the moment is using the ast library to pull out all import statements, using the inspect module to get string representations of those modules and then reconstructing the entire context on the remote server. Not particularly elegant and I can see lots of room for error. Thanks for your time

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  • Combinations into pairs

    - by Will
    I'm working on a directed network problem and trying to compute all valid paths between two points. I need a way to look at paths up to 30 "trips" (represented by an [origin, destination] pair) in length. The full route is then composed of a series of these pairs: route = [[start, city2], [city2, city3], [city3, city4], [city4, city5], [city5, city6], [city6, city7], [city7, city8], [city8, stop]] So far my best solution is as follows: def numRoutes(graph, start, stop, minStops, maxStops): routes = [] route = [[start, stop]] if distance(graph, route) != "NO SUCH ROUTE" and len(route) >= minStops and len(route) <= maxStops: routes.append(route) if maxStops >= 2: for city2 in routesFromCity(graph, start): route = [[start, city2],[city2, stop]] if distance(graph, route) != "NO SUCH ROUTE" and len(route) >= minStops and len(route) <= maxStops: routes.append(route) if maxStops >= 3: for city2 in routesFromCity(graph, start): for city3 in routesFromCity(graph, city2): route = [[start, city2], [city2, city3], [city3, stop]] if distance(graph, route) != "NO SUCH ROUTE" and len(route) >= minStops and len(route) <= maxStops: routes.append(route) if maxStops >= 4: for city2 in routesFromCity(graph, start): for city3 in routesFromCity(graph, city2): for city4 in routesFromCity(graph, city3): route = [[start, city2], [city2, city3], [city3, city4], [city4, stop]] if distance(graph, route) != "NO SUCH ROUTE" and len(route) >= minStops and len(route) <= maxStops: routes.append(route) if maxStops >= 5: for city2 in routesFromCity(graph, start): for city3 in routesFromCity(graph, city2): for city4 in routesFromCity(graph, city3): for city5 in routesFromCity(graph, city4): route = [[start, city2], [city2, city3], [city3, city4], [city4, city5], [city5, stop]] if distance(graph, route) != "NO SUCH ROUTE" and len(route) >= minStops and len(route) <= maxStops: routes.append(route) return routes Where numRoutes is fed my network graph where numbers represent distances: [[0, 5, 0, 5, 7], [0, 0, 4, 0, 0], [0, 0, 0, 8, 2], [0, 0, 8, 0, 6], [0, 3, 0, 0, 0]] a start city, an end city and the parameters for the length of the routes. distance checks if a route is viable and routesFromCity returns the attached nodes to each fed in city. I have a feeling there's a far more efficient way to generate all of the routes especially as I move toward many more steps, but I can't seem to get anything else to work.

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  • Python - multithreading / multiprocessing, very strange problem.

    - by orokusaki
    import uuid import time import multiprocessing def sleep_then_write(content): time.sleep(5) print(content) if __name__ == '__main__': for i in range(15): p = multiprocessing.Process(target=sleep_then_write, args=('Hello World',)) p.start() print('Ah, what a hard day of threading...') This script output the following: Ah, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... AAh, what a hard day of threading.. h, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... Ah, what a hard day of threading... Hello World Hello World Hello World Hello World Hello World Hello World Hello World Hello World Hello World Hello World Hello World Hello World Hello World Hello World Hello World Firstly, why the heck did it print the bottom statement sixteen times (one for each process) instead of just the one time? Second, notice the AAh, and h, about half way down; that was the real output. This makes me wary of using threads ever, now. (Windows XP, Python 2.6.4, Core 2 Duo)

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  • Django | django-socialregistration error

    - by MMRUser
    I'm trying to add the facebook connect feature to my site, I decided to use django socialregistration.All are setup including pyfacebook, here is my source code. settings.py MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'facebook.djangofb.FacebookMiddleware', 'socialregistration.middleware.FacebookMiddleware', ) urls.py (r'^callback/$', 'fbproject.fbapp.views.callback'), views.py def callback(request): return render_to_response('canvas.fbml') Template <html> <body> {% load facebook_tags %} {% facebook_button %} {% facebook_js %} </body> </html> but when I point to the URL, I'm getting this error Traceback (most recent call last): File "C:\Python26\lib\site-packages\django\core\servers\basehttp.py", line 279, in run self.result = application(self.environ, self.start_response) File "C:\Python26\lib\site-packages\django\core\servers\basehttp.py", line 651, in __call__ return self.application(environ, start_response) File "C:\Python26\lib\site-packages\django\core\handlers\wsgi.py", line 241, in __call__ response = self.get_response(request) File "C:\Python26\lib\site-packages\django\core\handlers\base.py", line 73, in get_response response = middleware_method(request) File "build\bdist.win32\egg\socialregistration\middleware.py", line 13, in process_request request.facebook.check_session(request) File "C:\Python26\lib\site-packages\facebook\__init__.py", line 1293, in check_session self.session_key_expires = int(params['expires']) ValueError: invalid literal for int() with base 10: 'None' Django 1.1.1 *Python 2.6.2*

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  • Scrapy issue with iTunes' AppStore

    - by Eric
    I am using Scrapy to fetch some data from iTunes' AppStore database. I start with this list of apps: http://itunes.apple.com/us/genre/mobile-software-applications/id36?mt=8 In the following code I have used the simplest regex which targets all apps in the US store. from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor from scrapy.contrib.spiders import CrawlSpider, Rule class AppStoreSpider(CrawlSpider): domain_name = 'itunes.apple.com' start_urls = ['http://itunes.apple.com/us/genre/mobile-software-applications/id6015?mt=8'] rules = ( Rule(SgmlLinkExtractor(allow='itunes\.apple\.com/us/app'), 'parse_app', follow=True, ), ) def parse_app(self, response): .... SPIDER = AppStoreSpider() When I run it I receive the following: [itunes.apple.com] DEBUG: Crawled (200) <GET http://itunes.apple.com/us/genre/mobile-software-applications/id6015?mt=8> (referer: None) [itunes.apple.com] DEBUG: Filtered offsite request to 'itunes.apple.com': <GET http://itunes.apple.com/us/app/bloomberg/id281941097?mt=8> As you can see, when it starts crawling the first page it says: "Filtered offsite request to 'itunes.apple.com'". and then the spider stops.. it also returns this message: [ScrapyHTTPPageGetter,client] /usr/lib/python2.5/cookielib.py:1577: exceptions.UserWarning: cookielib bug! Traceback (most recent call last): File "/usr/lib/python2.5/cookielib.py", line 1575, in make_cookies parse_ns_headers(ns_hdrs), request) File "/usr/lib/python2.5/cookielib.py", line 1532, in _cookies_from_attrs_set cookie = self._cookie_from_cookie_tuple(tup, request) File "/usr/lib/python2.5/cookielib.py", line 1451, in _cookie_from_cookie_tuple if version is not None: version = int(version) ValueError: invalid literal for int() with base 10: '"1"' I have used the same script for other website and I didn't have this problem. Any suggestion?

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  • Python PyQt Timer Firmata

    - by George Cullins
    Hello. I am pretty new to python and working with firmata I am trying to play around with an arduino . Here is what I want to happen: Set arduino up with an LED as a digital out Set potentiometer to analog 0 Set PyQt timer up to update potentiometer position in application Set a threshold in PyQt to turn LED on (Analog in has 1024bit resolution, so say 800 as the threshold) I am using this firmata library : Link Here is the code that I am having trouble with: import sys from PyQt4 import QtCore, QtGui from firmata import * # Arduino setup self.a = Arduino('COM3') self.a.pin_mode(13, firmata.OUTPUT) # Create timer self.appTimer = QtCore.QTimer(self) self.appTimer.start(100) self.appTimer.event(self.updateAppTimer()) def updateAppTimer(self): self.analogPosition = self.a.analog_read(self, 0) self.ui.lblPositionValue.setNum() I am getting the error message: Traceback (most recent call last): File "D:\Programming\Eclipse\IO Demo\src\control.py", line 138, in myapp = MainWindow() File "D:\Programming\Eclipse\IO Demo\src\control.py", line 56, in init self.appTimer.event(self.updateAppTimer()) File "D:\Programming\Eclipse\IO Demo\src\control.py", line 60, in updateAppTimer self.analogPosition = self.a.analog_read(self, 0) TypeError: analog_read() takes exactly 2 arguments (3 given) If I take 'self' out I get the same error message but that only 1 argument is given What is python doing implicitly that I am not aware of? Blockquote

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  • Python - Help with multiprocessing / threading basics.

    - by orokusaki
    I haven't ever used multi-threading, and I decided to learn it today. I was reluctant to ever use it before, but when I tried it out it seemed way to easy, which makes me wary. Are there any gotchas in my code, or is it really that simple? import uuid import time import multiprocessing def sleep_then_write(content): time.sleep(5) f = open(unicode(uuid.uuid4()), 'w') f.write(content) f.close() if __name__ == '__main__': for i in range(3): p = multiprocessing.Process(target=sleep_then_write, args=('Hello World',)) p.start() My primary purpose of using threading would be to offload multiple images to S3 after re-sizing them, all at the same time. Is that a reasonable task for Python's multiprocessing? I've read a lot about certain types of tasks not really getting any gain from using threading in Python due to the GIL, but it seems that multiprocessing completely removes that worry, yes? I can imagine a case where 50 users hit the system and it spawns 150 Python interpreters. I can also imagine that wouldn't be good on a production server. How can something like that be avoided? Finally (but most important): How can I return control back to the caller of the new processes? I need to be able to continue with returning an HTTP response and content back to the user and then have the processes continue doing there work after the user of my website is done with the transaction.

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  • How to use Scala in IntelliJ IDEA (or: why is it so difficult to get a working IDE for Scala)?

    - by Alex R
    I recently gave up trying to use Scala in Eclipse (basic stuff like completion doesn't work). So now I'm trying IntelliJ. I'm not getting very far. I've been able to edit programs (within syntax highlighting and completion... yay!). But I'm unable to run even the simplest "Hello World". This was the original error: Scala signature Predef has wrong version Expected 5.0 found: 4.1 in .... scala-library.jar But that was yesterday with IDEA 9.0.1. See below... UPDATE Today I uninstalled IntelliJ 9.0.1, and installed 9.0.2 Early Availability, with the 4/14 stable version of the Scala plug-in. Then I setup a project from scratch through the wizards: new project from scratch JDK is 1.6.u20 accept the default (project) instead of global / module accept the download of Scala 2.8.0beta1 into project's lib folder Created a new class: object hello { def main(args: Array[String]) { println("hello: " + args); } } For my efforts, I now have a brand-new error :) Here it is: Scalac internal error: class java.lang.ClassNotFoundException [java.net.URLClassLoader$1.run(URLClassLoader.java:202), java.security.AccessController.doPrivileged(Native Method), java.net.URLClassLoader.findClass(URLClassLoader.java:190), java.lang.ClassLoader.loadClass(ClassLoader.java:307), sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301), java.lang.ClassLoader.loadClass(ClassLoader.java:248), java.lang.Class.forName0(Native Method), java.lang.Class.forName(Class.java:169), org.jetbrains.plugins.scala.compiler.rt.ScalacRunner.main(ScalacRunner.java:72)] FINAL UPDATE I uninstalled 9.0.2 EA and reinstalled 9.0.1, but this time went with the 2.7.3 version of Scala rather than the default 2.7.6, because 2.7.3 is the one shown in the screen-shots at the IntelliJ website (I guess the screen-shots prove that they actually tested this version!). Now everything works!!!

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  • open flash chart rails x-axis issue

    - by Jimmy
    Hey guys, I am using open flash chart 2 in my rails application. Everything is looking smooth except for the range on my x axis. I am creating a line to represent cell phone plan cost over a specific amount of usage and I'm generate 8 values, 1-5 are below the allowed usage while 6-8 are demonstrations of the cost for usage over the limit. The problem I'm encountering is how to set the range of the X axis in ruby on rails to something specific to the data. Right now the values being displayed are the indexes of the array that I'm giving. When I try to hand a hash to the values the chart doesn't even load at all. So basically I need help getting a way to set the data for my line properly so that it displays correctly, right now it is treating every value as if it represents the x value of the index of the array. Here is a screen shot which may be a better description than what I am saying: http://i163.photobucket.com/albums/t286/Xeno56/Screenshot.png Note that those values are correct just the range on the x-axis is incorrect, it should be something like 100, 200, 300, 400, 500, 600, 700 Code: y = YAxis.new y.set_range(0,100, 20) x_legend = XLegend.new("Usage") x_legend.set_style('{font-size: 20px; color: #778877}') y_legend = YLegend.new("Cost") y_legend.set_style('{font-size: 20px; color: #770077}') chart =OpenFlashChart.new chart.set_x_legend(x_legend) chart.set_y_legend(y_legend) chart.y_axis = y line = Line.new line.text = plan.name line.width = 2 line.color = '#006633' line.dot_size = 2 line.values = generate_data(plan) chart.add_element(line) def generate_data(plan) values = [] #generate below threshold numbers 5.times do |x| usage = plan.usage / 5 * x cost = plan.cost * 10 values << cost end #generate above threshold numbers 3.times do |x| usage = plan.usage + ((plan.usage / 5) * x) cost = plan.cost + (usage * plan.overage) values << cost end return values end

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  • Rails PDF Generation with Prawn in IE7

    - by fluid_chelsea
    I'm using Prawn and Prawnto to generate a PDF in a Ruby on Rails app (Rails version 2.2.2) which works great and generates PDFs happily and sends them to the user to download in Firefox. The problem is in IE7. I have a route set up like so: map.invoice_pdf '/invoices.pdf', :controller => 'invoices', :action => 'index', :format => 'pdf' Which I then have a link like so to call: invoice_pdf_path(:year => params[:year], :month => params[:month], :unpaid_only => params[:unpaid_only]) And the following in my controller: def index params[:year] = default params[:year] params[:month] = default params[:month] params[:page] ||= 1 @invoices = Arobl.find_invoices_for_customer(current_customer.strCustomerID, params) respond_to do |format| format.html{ render :action => 'index' } format.pdf{ prawnto :inline => false, :filename => "#{current_customer.strCustomerID}_invoice.pdf" end In FF this works as expected, when the link is clicked the show action is invoked with a format of .pdf, and responds with the correctly named PDF. When it's hit with IE7 it says that the file or website could not be found, and references "invoices.pdf" instead of the expected customer_id_invoice.pdf filename. Any idea what could be causing this behaviour? Thanks!

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  • Django: Unicode Filenames with ASCII headers?

    - by TheLizardKing
    I have a list of strangely encoded files: 02 - Charlie, Woody and You/Study #22.mp3 which I suppose isn't so bad but there are a few particular characters which Django OR nginx seem to be snagging on. >>> test = u'02 - Charlie, Woody and You/Study #22.mp3' >>> test u'02 - Charlie, Woody and You\uff0fStudy #22.mp3' I am using nginx as a reverse proxy to connect to django's built in webserver (still in development stages) and postgresql for my database. My database and tables are all en_US.UTF-8 and I am using pgadmin3 to view my tables outside of django. My issue goes a little beyond my title, firstly how should I be saving possibly whacky filenames in my database? My current method is 'path': smart_unicode(path.lstrip(MUSIC_PATH)), 'filename': smart_unicode(file) and when I pprint out the values they do show u'whateverthecrap' I am not sure if that is how I should be doing it but assuming it is now I have issues trying to spit out the download. My download view looks something like this: def song_download(request, song_id): song = get_object_or_404(Song, pk=song_id) url = u'/static_music/%s/%s' % (song.path, song.filename) print url response = HttpResponse() response['X-Accel-Redirect'] = url response['Content-Type'] = 'audio/mpeg' response['Content-Disposition'] = "attachment; filename=test.mp3" return response and most files will download but when I get to 02 - Charlie, Woody and You/Study #22.mp3 I receive this from django: 'ascii' codec can't encode character u'\uff0f' in position 118: ordinal not in range(128), HTTP response headers must be in US-ASCII format. How can I use an ASCII acceptable string if my filename is out of bounds? 02 - Charlie, Woody and You\uff0fStudy #22.mp3 doesn't seem to work... EDIT 1 I am using Ubuntu for my OS.

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  • Python dictionary formating

    - by None
    I made a python function to convert dictionaries to formatted strings. My goal was to have a function take a dictionary for input and turn it into a string that looked good. For example, something like "{'text':'Hello', 'blah':{'hi':'hello','hello':'hi'}}" would be turned into this: text: Hello blah: hi: hello hello: hi This is the code I wrote: indent = 0 def format_dict(d): global indent res = "" for key in d: res += (" " * indent) + key + ":\n" if not type(d[key]) == type({}): res += (" " * (indent + 1)) + d[key] + "\n" else: indent += 1 res += format_dict(d[key]) indent -= 1 return res #test print format_dict({'key with text content':'some text', 'key with dict content': {'cheese': 'text', 'item':{'Blah': 'Hello'}}}) It works like a charm. It checks if the dictionary item is another dictionary, in which it process that, or something else, in which it would use that as the value. The problem is: I can't have a dictionary and a string together in a dictionary item. For example: if I wanted blah: hi hello: hello again there'd be no way to do it. Is there some way I could have something like a list item in a dictionary. Something like this "{'blah':{'hi', 'hello':'hello again'}}"? And if you provide a solution could you tell me how I would need to change my code (if it did require changes). Note: I am using python 2.5

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  • Iterating through a JSON object.

    - by user327508
    [ { "title": "Baby (Feat. Ludacris) - Justin Bieber", "description": "Baby (Feat. Ludacris) by Justin Bieber on Grooveshark", "link": "http://listen.grooveshark.com/s/Baby+Feat+Ludacris+/2Bqvdq", "pubDate": "Wed, 28 Apr 2010 02:37:53 -0400", "pubTime": 1272436673, "TinyLink": "http://tinysong.com/d3wI", "SongID": "24447862", "SongName": "Baby (Feat. Ludacris)", "ArtistID": "1118876", "ArtistName": "Justin Bieber", "AlbumID": "4104002", "AlbumName": "My World (Part II);\nhttp://tinysong.com/gQsw", "LongLink": "11578982", "GroovesharkLink": "11578982", "Link": "http://tinysong.com/d3wI" }, { "title": "Feel Good Inc - Gorillaz", "description": "Feel Good Inc by Gorillaz on Grooveshark", "link": "http://listen.grooveshark.com/s/Feel+Good+Inc/1UksmI", "pubDate": "Wed, 28 Apr 2010 02:25:30 -0400", "pubTime": 1272435930 } ] That is the current JSON object I have. I am now trying to iterate through it to get the import stuff like title and link. This is where I am having trouble I cant seem to get to the content that is past the ":" i tried doing dictionary way couldn't get it. def getLastSong(user,limit): base_url = 'http://gsuser.com/lastSong/' user_url = base_url + str(user) + '/' + str(limit) + "/" raw = urllib.urlopen(user_url) json_raw= raw.readlines() json_object = json.loads(json_raw[0]) #filtering and making it look good. gsongs = [] print json_object for song in json_object[0]: print song This code prints all the information before ":" Please help. ignore the Justin Bieber track :)

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  • Cannot turn off autocommit in a script using the Django ORM

    - by Wes
    I have a command line script that uses the Django ORM and MySQL backend. I want to turn off autocommit and commit manually. For the life of me, I cannot get this to work. Here is a pared down version of the script. A row is inserted into testtable every time I run this and I get this warning from MySQL: "Some non-transactional changed tables couldn't be rolled back". #!/usr/bin/python import os import sys django_dir = os.path.abspath(os.path.normpath(os.path.join(os.path.dirname(__file__), '..'))) sys.path.append(django_dir) os.environ['DJANGO_DIR'] = django_dir os.environ['DJANGO_SETTINGS_MODULE'] = 'myproject.settings' from django.core.management import setup_environ from myproject import settings setup_environ(settings) from django.db import transaction, connection cursor = connection.cursor() cursor.execute('SET autocommit = 0') cursor.execute('insert into testtable values (\'X\')') cursor.execute('rollback') I also tried placing the insert in a function and adding Django's commit_manually wrapper, like so: @transaction.commit_manually def myfunction(): cursor = connection.cursor() cursor.execute('SET autocommit = 0') cursor.execute('insert into westest values (\'X\')') cursor.execute('rollback') myfunction() I also tried setting DISABLE_TRANSACTION_MANAGEMENT = True in settings.py, with no further luck. I feel like I am missing something obvious. Any help you can give me is greatly appreciated. Thanks!

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